4.2· 103 questions · 763 marks · 916 min · 2006–2025· Structured questions
Every Cambridge IGCSE Physics Paper 3 question on electrical quantities, laid out as 122 A4 pages with the mark scheme below. Nothing is left out. Free to read, no account.
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122 / 122Answers below. Sit the paper first if you are practising.
Pastlit
Physics 0625 · Electrical quantities — Paper 3
IGCSE · topical answer key — answer key (teacher use)
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| 8 | see sheet | 8 | 0625/31 May/June 2010 |
| 9 | see sheet | 9 | 0625/32 May/June 2010 |
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8 Fig. 8.1 shows an electrical circuit. For 12.0 V d.c. Examiner’s Use R A C B 4.0 Ω one metre resistance wire sliding contact Fig. 8.1 The resistance of the lamp is 4.0 Ω when it is at its normal brightness. (a) The lamp is rated at 6.0 V, 9.0 W. Calculate the current in the lamp when it is at its normal brightness. current = … [2] (b) The sliding contact C is moved to A. The lamp lights at its normal brightness. Calculate (i) the total circuit resistance, resistance = … [1] (ii) the potential difference across the 4.0 Ω resistor R. potential difference = … [1] (c) The sliding contact C is moved from A to B. (i) Describe any change that occurs in the brightness of the lamp. … [1] (ii) Explain your answer to (i). … … [2] (d) The 1 m wire between A and B, as shown in Fig. 8.1, has a resistance of 2.0 Ω. Calculate the resistance between A and B when (i) the 1 m length is replaced by a 2 m length of the same wire, resistance = … [1] (ii) the 1 m length is replaced by a 1 m length of a wire of the same material but of only half the cross-sectional area. resistance = … [1]
9 marks
Mark scheme: 8 (a) I = W/V or 9/6 C1 I = 1.5 A A1 2 (b) (i) 8 ohm A1 (ii) 6 V A1 2 (c) (i) brightness decreases/dimmer B1 (ii) resistance of circuit greater B1 current through lamp falls B1 3 (d) (i) 4 ohm A1 (ii) 4 ohm A1 2 [9] IGCSE – May/June 2006 0625 03
10 (a) Fig. 10.1 shows a positively charged plastic rod, a metal plate resting on an insulator, For and a lead connected to earth. Examiner’s Use positively charged plastic rod metal plate lead connected insulator to earth Fig. 10.1 Describe how the metal plate may be charged by induction. … … … [3] (b) An electrostatic generator sets up a current of 20 mA in a circuit. Calculate (i) the charge flowing through the circuit in 15 s, charge = … (ii) the potential difference across a 10 kΩ resistor in the circuit. potential difference = … [3]
6 marks
Mark scheme: 10 (a) bring rod close but not touching plate M1 touch metal plate with earth lead M1 remove lead and then rod A1 3 (b) (i) Q = 20 (mA) x 15 (s) C1 = 0.30 C A1 (ii) V = 20 (ma) x 10 (kΩ) C1 = 200 V A1 M3 [6]
8 Fig. 8.1 shows part of a low-voltage lighting circuit containing five identical lamps. 12 V d.c. supply A B C D E Fig. 8.1 (a) Complete the circuit, by the addition of components as necessary, so that (i) the total current from the supply can be measured, (ii) the brightness of lamp E only can be varied, (iii) lamps C and D may be switched on and off together whilst lamps A, B and E remain on. [4] (b) All five lamps are marked 12 V, 36 W. Assume that the resistance of each lamp is the same fixed value regardless of how it is connected in the circuit. Calculate (i) the current in one lamp when operating at normal brightness, current = … [1] (ii) the resistance of one lamp when operating at normal brightness, resistance = … [1] (iii) the combined resistance of two lamps connected in parallel with the 12 V supply, resistance = … [1] (iv) the energy used by one lamp in 30 s when operating at normal brightness. energy = … [1] Examiner’s Use (c) The whole circuit is switched on. Explain why the brightness of lamps A and B is much less than that of one lamp operating at normal brightness. … … … [2] [Total: 10]
10 marks
Mark scheme: 8 (a) connections such that all lamps will light B1 ammeter in correct position B1 variable resistor in correct position (condone poor symbol) B1 switch in appropriate position (could be 2 switches) B1 [4] (b) (i) 3 A B1 [1] (ii) 4Ω OR 12/his(i) correctly evaluated B1 [1] (iii) 2Ω OR ½ × his(ii) correctly evaluated B1 [1] (iv) 1080 J e.c.f. from (i) & (ii) if working shown B1 [1] (c) lamps in series M1 less current/less p.d. (across 1 lamp)/voltage shared/higher resistance A1 [2] NOT current shared [Total: 10] IGCSE – May/June 2007 0625 03
7 Three wires and a meter are used to construct a thermocouple for measuring the surface For temperature of a pipe carrying hot liquid, as shown in Fig. 7.1. Examiner’s Use meter wire 1 wire 2 cold junction wire 3 hot junction hot liquid in pipe Fig. 7.1 (a) Copper wire and constantan wire are used in the construction of the thermocouple. State which metal might be used for wire 1 … wire 2 … wire 3 … [1] (b) State what type of meter is used. … [1] (c) State one particular advantage of thermocouples for measuring temperature. … [1] [Total: 3]
3 marks
Mark scheme: 7 (a) EITHER OR copper constantan copper constantan constantan copper B1 (b) galvanometer OR millivoltmeter OR milliammeter OR digital ammeter OR digital voltmeter B1 (c) rapid response ) small area ) can measure high / low temperatures ) small thermal capacity (idea of) ) any 1 B1 remote reading ) large range ) data logging / continuous monitoring possible ) takes temperature of a surface ) N.B. (very) sensitive not accepted [3]
10 Alternating current electricity is delivered at 22 000 V to a pair of transmission lines. For The transmission lines carry the electricity to the customer at the receiving end, where Examiner’s the potential difference is V. This is shown in Fig. 10.1. Each transmission line has a Use resistance of 3 Ω. 22 000 V 3 Ω V 3 Ω Fig. 10.1 (a) The a.c. generator actually generates at a much lower voltage than 22 000 V. (i) Suggest how the voltage is increased to 22 000 V. … [1] (ii) State one advantage of delivering electrical energy at high voltage. … [1] (b) The power delivered by the generator is 55 kW. Calculate the current in the transmission lines. current = … [2] (c) Calculate the rate of loss of energy from one of the 3 Ω transmission lines. rate of energy loss = … [2] (d) Calculate the voltage drop across one of the transmission lines. For Examiner’s Use voltage drop = … [2] (e) Calculate the potential difference V at the receiving end of the transmission lines. V = … [2] [Total: 10] Question 11 is on the next page.
10 marks
Mark scheme: 10 (a) (i) step-up transformer B1 (ii) less heat/energy/power loss (from lines) / thinner wires (possible) B1 OR lower current NOT more efficient (b) P = V × I in any form, figures or symbols / (P =) VI C1 2.5 A A1 (c) P = I2R in any form, figures or symbols / (P =) I2R C1 18.75 W e.c.f. from (b) A1 (d) V = IR in any form, figures or symbols OR (V =) IR OR P = V2 / R in any form, figures or symbols OR (P =) V2 / R OR V = (PR)1/2 C1 7.5 V e.c.f. from (b) or (c) A1 IGCSE – October/November 2009 0625 31 (e) 22,000 – 7.5 – 7.5 OR 22,000 – 7.5 ecf C1 21,985 V e.c.f. (minimum 4 s.f.in this case) A1 OR 55,000 – 37.5 = 54962.5 (C1) 54962.5 / 2.5 = 21985 V (minimum 4 s.f. in this case) (A1) [10]
7 Three wires and a meter are used to construct a thermocouple for measuring the surface For temperature of a pipe carrying hot liquid, as shown in Fig. 7.1. Examiner’s Use meter wire 1 wire 2 cold junction wire 3 hot junction hot liquid in pipe Fig. 7.1 (a) Copper wire and constantan wire are used in the construction of the thermocouple. State which metal might be used for wire 1 … wire 2 … wire 3 … [1] (b) State what type of meter is used. … [1] (c) State one particular advantage of thermocouples for measuring temperature. … [1] [Total: 3]
3 marks
Mark scheme: 7 (a) EITHER OR copper constantan copper constantan constantan copper B1 (b) galvanometer OR millivoltmeter OR milliammeter OR digital ammeter OR digital voltmeter B1 (c) rapid response ) small area ) can measure high / low temperatures ) small thermal capacity (idea of) ) any 1 B1 remote reading ) large range ) data logging / continuous monitoring possible ) takes temperature of a surface ) N.B. very sensitive or wtte not accepted [3]
10 Alternating current electricity is delivered at 22 000 V to a pair of transmission lines. The For transmission lines carry the electricity to the customer at the receiving end, where the Examiner’s potential difference is V. This is shown in Fig. 10.1. Each transmission line has a resistance Use of 3 . 22 000 V 3 X V 3 X Fig. 10.1 (a) The a.c. generator actually generates at a much lower voltage than 22 000 V. (i) Suggest how the voltage is increased to 22 000 V. … [1] (ii) State one advantage of delivering electrical energy at high voltage. … [1] (b) The power delivered by the generator is 55 kW. Calculate the current in the transmission lines. current = … [2] (c) Calculate the rate of loss of energy from one of the 3 transmission lines. rate of energy loss = … [2] (d) Calculate the voltage drop across one of the transmission lines. For Examiner’s Use voltage drop = … [2] (e) Calculate the potential difference V at the receiving end of the transmission lines. V = … [2] [Total: 10] Question 11 is on the next page.
10 marks
Mark scheme: 10 (a) (i) step-up transformer B1 (ii) less heat/energy/power loss (from lines) / thinner wires (possible) B1 OR lower current NOT more efficient (b) P = V × I in any form, figures or symbols / (P =) VI C1 2.5 A A1 (c) P = I2R in any form, figures or symbols / (P =) I2R C1 18.75 W e.c.f. from (b) A1 (d) V = IR in any form, figures or symbols OR (V =) IR OR P = V2 / R in any form, figures or symbols OR (P =) V2 / R OR V = (PR)1/2 C1 7.5 V e.c.f. from (b) or (c) A1 (e) 22,000 – 7.5 – 7.5 OR 22,000 – 7.5 ecf C1 21,985 V e.c.f. (minimum 4 s.f.in this case) A1 OR 55,000 – 37.5 = 54962.5 (C1) 54962.5 / 2.5 = 21985 V (minimum 4 s.f. in this case) (A1) [10] IGCSE – October/November 2009 0625 32
11 (a) A coil of wire is connected into a circuit containing a variable resistor and a battery. For Examiner’s The variable resistor is adjusted until the potential difference across the coil is 1.8 V. Use In this condition, the current in the circuit is 0.45 A. Calculate (i) the resistance of the coil, resistance = … [1] (ii) the thermal energy released from this coil in 9 minutes. energy released = … [3] (b) The coil in part (a) is replaced by one made of wire which has half the diameter of that in (a). When the potential difference across the coil is again adjusted to 1.8 V, the current is only 0.30 A. Calculate how the length of wire in the second coil compares with the length of wire in the first coil. length of wire in second coil is ………………………… the length of wire in first coil [4]
8 marks
Mark scheme: 11 (a) (i) 4 Ω B1 (ii) IVt OR I2Rt OR V2t/R in any form or words or numbers Condone t = 9 if substituted possible ecf from (i) C1 540 (s) C1 437.4 J possible ecf if 4 Ω from (i) used A1 (b) R = ρL/A OR R ∝ L/A OR R ∝ L and R ∝ 1/A or 1/d2 or 1/r2 C1 A2 = ¼A1 OR A2 = 0.25A1 C1 R2 = (0.45/0.3) × R1 OR (3/2) x R1 C1 ⅜ OR 0.375 OR 37.5 % A1 OR R = ρL/A OR R ∝ L/A OR R ∝ L and R ∝ 1/A or 1/d2 or 1/r2 C1 Resistance of thinner wire with same length as thicker wire = 4 × 4 = 16 Ω C1 Actual resistance of thinner wire = 1.8 /0.3 = 6.0 Ω C1 Ratio: L of thinner wire / L of thicker wire = 6.0 / 16 = 3/8 = 0.375 = 37.5 % A1 [8]
8 (a) State the law of attraction and repulsion between electrostatic charges. For Examiner’s … Use … … [2] (b) Sometimes, when people have been riding in a car, they get an electric shock from the door handle as they get out of the car. Suggest why this happens. … … … [2] (c) A plastic rod is rubbed with a cloth and becomes positively charged. After charging, the rod is held close to the suspended table-tennis ball shown in Fig. 8.1. The table-tennis ball is covered with metal paint and is initially uncharged. nylon thread light table-tennis ball covered with metal paint positively charged rod Fig. 8.1 (i) Describe what happens to the charges on the metal-painted table-tennis ball as the positively-charged rod is brought close to the ball. … … … [1] (ii) The ball is attracted towards the charged rod. For Examiner’s Explain why this happens. Use … … … [2] (iii) When it is a few centimetres away from the rod, the ball is briefly touched by a wire connected to earth. In terms of the movement of charges, describe what happens to the charge on the ball. … … [2] [Total: 9]
9 marks
Mark scheme: 8 (a) same/like/similar charges repel (ignore poles repel) B1 unlike/opposite/different charges attract (ignore poles attract) B1 (b) idea of car/person (being) charged (by friction) B1 idea of charge/electrons going to/from/through person B1 (c) (i) electrons / -ve charges move towards the rod / to R (ignore just “attracted”) ignore any mention of +ve charges moving any mention of +ve electrons gets B0 B1 (ii) opposite charges attract OR electrons / -ve charges attracted to +ve / rod B1 attraction between opposite charges > repulsion between like charges OR – ve charges (are) close(r) (to the rod) B1 (iii) electrons / -ve charges flow (up) from earth/wire no e.c.f. from (i) ignore +ve charges moving, NOT +ve electrons B1 ball becomes –vely charged B1 [9]
10 A student is using a cathode-ray oscilloscope to display the waveform of an alternating For current supply. The arrangement is shown in Fig. 10.1. Examiner’s Use cathode-ray oscilloscope switch S (open) a.c. R Y-input supply Fig. 10.1 When switch S is closed, the trace seen on the screen is as shown in Fig. 10.2. To get this trace, the settings of the oscilloscope controls are volts / cm: 5 V / cm time-base: 10 ms / cm 1 cm Fig. 10.2 (a) On Fig. 10.2, carefully draw what is seen on the screen when the frequency of the supply is increased to 1.5 times its previous value. [3] (b) What change, if any, must be made to the oscilloscope volts / cm and time-base controls For in order to reduce the peak-to-peak height of the trace to half that shown in Fig. 10.2? Examiner’s Use volts / cm setting … [2] time-base setting … [1] [Total: 6]
6 marks
Mark scheme: 10 (a) waves clearly more bunched condone poor accuracy / shape or waves not filling screen C1 3 waves drawn, with first 4 half-wavelengths having 2.0 (±0.2) cm interval A1 all waves drawn same amplitude (±0.2) cm as original AND at least 1 peak and 1 trough drawn B1 (b) volts/cm: increased / any value > 5 (V / cm) B1 factor of 2, increase or decrease / 10 (V / cm) / 2.5 (V / cm) B1 N.B. 10 (V / cm) scores B1, B1 time base: no change / 10 ms / cm B1 [6]
10 A student is using a cathode-ray oscilloscope to display the waveform of an alternating For current supply. The arrangement is shown in Fig. 10.1. Examiner’s Use cathode-ray oscilloscope switch S (open) a.c. R Y-input supply Fig. 10.1 When switch S is closed, the trace seen on the screen is as shown in Fig. 10.2. To get this trace, the settings of the oscilloscope controls are volts / cm: 5 V / cm time-base: 10 ms / cm 1 cm Fig. 10.2 (a) On Fig. 10.2, carefully draw what is seen on the screen when the frequency of the supply is increased to 1.5 times its previous value. [3] (b) What change, if any, must be made to the oscilloscope volts / cm and time-base controls For in order to reduce the peak-to-peak height of the trace to half that shown in Fig. 10.2? Examiner’s Use volts / cm setting … [2] time-base setting … [1] [Total: 6]
6 marks
Mark scheme: 10 (a) waves clearly more bunched condone poor accuracy / shape or waves not filling screen C1 3 waves drawn, with first 4 half-wavelengths having 2.0 (±0.2) cm interval A1 all waves drawn same amplitude (±0.2) cm as original AND at least 1 peak and 1 trough drawn B1 (b) volts/cm: increased / any value > 5 (V / cm) B1 factor of 2, increase or decrease / 10 (V / cm) / 2.5 (V / cm) B1 N.B. 10 (V / cm) scores B1, B1 time base: no change / 10 ms / cm B1 [6]
9 In Fig. 9.1, A and B are two conductors on insulating stands. Both A and B were initially uncharged. X Y A B Fig. 9.1 (a) Conductor A is given the positive charge shown on Fig. 9.1. (i) On Fig. 9.1, mark the signs of the charges induced at end X and at end Y of conductor B. [1] (ii) Explain how these charges are induced. … … … [3] (iii) Explain why the charges at X and at Y are equal in magnitude. … … … [1] (b) B is now connected to earth by a length of wire. Explain what happens, if anything, to (i) the charge at X, … … [1] (ii) the charge at Y. … … [2] [Total: 8]
8 marks
Mark scheme: 9 (a) (i) negative at LH end and positive at RH end B1 (ii) (+ve) charge on A attracts electrons/-ve charges/-ve ions OR unlike charges attract (ignore reference to + charges) B1 electrons move to end X/towards A B1 (unbalanced) +ve charges (left) at end Y NOT repelled to Y B1 (iii) idea that each electron leaves behind an equal unbalanced proton in nucleus/B has no net charge/B is neutral/idea that B has not gained or lost any charges B1 (b) (i) nothing OR nothing implied B1 (ii) +ve charge cancelled/neutralised B1 by electrons/negative charges flowing up from earth B1 [Total: 8] IGCSE – October/November 2010 0625 31
7 When he leaves work at 6.30 p.m. (18:30) one evening, a caretaker forgets to switch off the 100 W lamp in his office. He doesn’t discover this until he returns at 7.30 a.m. (07:30) the next morning. The mains electricity supply is 250 V. (a) Calculate how much energy the caretaker has wasted. energy wasted = … [2] (b) Calculate the charge that passed through the lamp during this time. charge = … [3] (c) What happened to the energy wasted by the lamp? … … [1] [Total: 6]
6 marks
Mark scheme: 7 (a) (E =) Pt symbols or numbers OR 100 × 13 × 3600 OR 0.1 × 13 OR 3 960 000 OR 4 320 000 C1 4 680 000 J OR 4.68 MJ OR 1.3 kWh OR 1300 Wh A1 (b) EITHER I = P/V in any form OR P/V OR 100/250 OR 0.4 A C1 Q = It OR 0.4 × 13 × 3600 OR candidate’s current × 13 × 3600 OR candidate’s current × candidate’s time in s C1 18 720 C e.c.f A1 OR volts = joules/coulombs in any form C1 4680000/250 OR candidate’s E/250 C1 18 720 C e.c.f A1 (c) (lost as/changed to) heat/light OR lost to air/surroundings B1 [Total: 6] IGCSE – October/November 2010 0625 32
5 The manufacturer’s label on an electric heater is as shown in Fig. 5.1. C.I.E. Electrical Company Suitable for use on 110 V, 60 Hz supply 1 kW/ 2 kW This appliance must be earthed when in use Fig. 5.1 (a) State what electrical quantity is represented by (i) 110 V, … (ii) 60 Hz, … (iii) 1 kW. … [1] (b) (i) Which part of the electric heater must be earthed? … [1] (ii) Explain what the hazard might be if the heater is not earthed. … … … [2] (c) The heater has two 110 V heating elements, with two switches, so that either one or both elements may be switched on. In the space below, draw a circuit diagram showing how the heating elements and switches are connected to the mains supply. Use the symbol for each heating element. [2] [Total: 6]
6 marks
Mark scheme: 5 (a) (i) potential difference OR e.m.f. OR voltage ignore volts (ii) frequency accept cycles/s ignore waves/s all 3 B1 (iii) power accept energy/s (b) (i) case/frame/outside/base/parts that can be touched ignore metal parts B1 (ii) electric shock/electrocution/death by electricity o.w.t.t.e. ignore anything else B1 live wire touches case B1 (c) heaters in parallel with any supply (M0 if no supply, clear break in circuit, short across supply or heater) M1 one switch controlling both heaters and one switch controlling one heater OR one switch in series with each element A1 special case: heaters in series with supply and one switch shorting out one resistor AND another switch in series with supply B2 [6]
10 (a) A cathode-ray oscilloscope makes use of the process known as thermionic emission. Describe what happens during this process. … … … [1] (b) In the space below, draw a labelled diagram of a cathode-ray oscilloscope. Include in your diagram the tube, the cathode, the accelerating anode, the focusing anode and both X- and Y-plates. Do not attempt to show any external circuits. [3] (c) A cathode ray is a beam of electrons. Suggest one way of controlling the number of electrons in the beam. … … [1] (d) One cathode-ray tube has 5000 V between the accelerating anode and the cathode. The beam of electrons carries a total charge of 0.0095 C in 5.0 s. Calculate (i) the current caused by the beam, current = … [2] (ii) the energy transferred by the beam in 20 s. energy = … [2] [Total: 9] Question 11 is on the next page.
9 marks
Mark scheme: 10 (a) release of electrons due to heating/high temperature/heater B1 (b) X- and Y-plates labelled B1 anodes either order, labelled, either plates/cylinders with holes B1 closed tube of sensible shape AND cathode AND anode(s) AND X- & Y- plates, all three features in correct order labels not needed for last mark but if given must be correct B1 (c) change current in filament/cathode/heater IGNORE limit OR change temperature/heat/power/energy of filament/cathode/heater OR change cathode-anode p.d./voltage OR change charge/voltage of grid B1 (d) (i) (I=)Q/t in any form C1 0.0019 A OR 1.9 × 10-3 A OR 1.9 mA A1 (ii) (E=) VIt OR VQ in any form, words, symbols, numbers (accept t=5s) C1 190 J OR candidate’s I × 100 000 correctly evaluated A1 [9]
8 (a) What is meant by the electromotive force (e.m.f.) of an electric power supply? … … [2] (b) When connected to a 240 V supply, a desk lamp has a power rating of 60 W. Calculate (i) the current in the lamp, current = … [2] (ii) the resistance of the lamp’s filament. resistance = … [2] (c) A torch lamp is normally connected to a 3.0 V battery and carries a current of 0.25 A. The resistance of its filament is 12 Ω. The desk lamp in (b) and the torch lamp are connected in series. Students X and Y plan to connect the lamp combination to a 240 V supply. Student X says that the filament of the torch lamp will melt and the circuit will no longer work. Student Y says that both lamps will light up and stay on. Show, with a suitable calculation, whether student X or student Y is correct. … … [2] [Total: 8]
8 marks
Mark scheme: 8 (a) energy supplied / work done (per unit charge) to B1 drive charge round a (complete) circuit B1 OR p.d. / voltage across battery / power source B1 (b) (i) P = IV OR (I =) P/V OR (I =) 60/240 C1 = 0.25 A OR ¼ A A1 (ii) I = V/R OR other version OR (R = )V/I C1 OR (R = )240/0.25 OR P=V2/R or other version e.g. (R=) V2/P OR (R=) 2402/60 R= 960 Ω A1 (c) current in series circuit = 240 / 972 =0.247 A B1 current suits both bulbs, (so both light up so Y is correct) B1 OR p.d. across bulb A = 240 × (960/972) = 237 V p.d. across bulb B = 240 × 12/972 = 2.96 V B1 p.d. suits both bulbs, (so both light up so Y correct) B1 [8]
8 (a) What is meant by the electromotive force (e.m.f.) of an electric power supply? … … [2] (b) When connected to a 240 V supply, a desk lamp has a power rating of 60 W. Calculate (i) the current in the lamp, current = … [2] (ii) the resistance of the lamp’s filament. resistance = … [2] (c) A torch lamp is normally connected to a 3.0 V battery and carries a current of 0.25 A. The resistance of its filament is 12 Ω. The desk lamp in (b) and the torch lamp are connected in series. Students X and Y plan to connect the lamp combination to a 240 V supply. Student X says that the filament of the torch lamp will melt and the circuit will no longer work. Student Y says that both lamps will light up and stay on. Show, with a suitable calculation, whether student X or student Y is correct. … … [2] [Total: 8]
8 marks
Mark scheme: 8 (a) energy supplied / work done (per unit charge) to B1 drive charge round a (complete) circuit B1 OR p.d. / voltage across battery / power source B1 (b) (i) P = IV OR (I =) P/V OR (I =) 60/240 C1 = 0.25 A OR ¼ A A1 (ii) I = V/R OR other version OR (R = )V/I C1 OR (R = )240/0.25 OR P=V2/R or other version e.g. (R=) V2/P OR (R=) 2402/60 R= 960 Ω A1 (c) current in series circuit = 240 / 972 =0.247 A B1 current suits both bulbs, (so both light up so Y is correct) B1 OR p.d. across bulb A = 240 × (960/972) = 237 V p.d. across bulb B = 240 × 12/972 = 2.96 V B1 p.d. suits both bulbs, (so both light up so Y correct) B1 [8]
9 The graphs in Fig. 9.1 show the relation between the current I and the potential difference V for a resistor and a lamp. 6 5 I / A 4 lamp 3 2 resistor 1 0 0 1 2 3 4 5 6 7 8 9 V / V Fig. 9.1 (a) (i) Describe how, if at all, the resistance varies as the current increases in 1. the resistor, … 2. the lamp. … [2] (ii) State the value of the potential difference when the resistor and the lamp have the same resistance. potential difference = … [1] (b) The two components are connected in parallel to a supply of e.m.f. 4.0 V. Calculate the total resistance of the circuit. total resistance = … [4] [Total: 7]
7 marks
Mark scheme: 9 (a) (i) 1. resistance is constant / doesn’t vary B1 2. resistance increases B1 (ii) 7 V B1 (b) resistance of resistor = 4/2.6 (= 1.54 Ω) C1 resistance of lamp = 4/3.6 (= 1.11 Ω) C1 1/R = 1/R1 + 1/R2 OR (R =) R1R2/(R1 + R2) OR either eq. with numbers C1 0.645 or 0.65 Ω A1 OR current through resistor = 2.6 A (C1) current through lamp = 3.6 A (C1) total current = 2.6 + 3.6 = 6.2 A (C1) 0.645 Ω OR 0.65 Ω OR R = 4/sum of candidate’s currents (A1) [7] accept R value based on no. of sig. figs. for resistors used by candidate
7 The solar charger shown in Fig. 7.1 is used to charge portable electronic devices in a part of For the world without any other electricity supply. Examiner’s Use solar panels Fig. 7.1 The dimensions of each of the solar panels are 0.25 m × 0.20 m. The solar power incident on 1.0 m2 of flat ground in this part of the world is 260 W. (a) Calculate the total solar power incident on the two panels of the charger. solar power = … [2] (b) The output of the charger is 0.95 A at 20 V. Calculate the efficiency of the charger. efficiency = … [3] (c) Three devices A, B and C are connected together and then connected to the 20 V For charger. The potential difference (p.d.) across A is measured as 14 V, across B it is 14 V Examiner’s and across C it is 6 V. Use Complete Fig. 7.2 to show the arrangement of the devices connected to the charger. Draw devices B and C as similar boxes to the box shown for device A. output from charger 20 V device A Fig. 7.2 [2] (d) Two other devices, D and E, have resistances of 20 Ω and 30 Ω. Calculate the total resistance of D and E when they are connected in parallel. total resistance = … [2] [Total: 9]
9 marks
Mark scheme: 7 (a) (Pi =) 260 (× 2) × length × breadth (= 260 × 0.1), words, symbols or numbers C1 note: gets this mark if omits factor of 2 (Pi = 2 × 260 × 0.25 × 0.2 =) 26 W A1 [2] (b) (Po = 0.95 × 20 =) 19 (W) B1 efficiency = output (energy) / input (energy) accept power for energy E = candidate’s Po/candidate’s Pi evaluated (= 0.73 or 73%), accept fraction (19/26) C1 0.73% or bald 73 gets unit penalty A1 [3] (c) A OR B in series with C connected across 20 V M1 parallel combination of A and B only A1 [2] (d) 1 / R = 1 / R1 + 1 / R2 OR R = R1R2 / (R1 + R2) in any form OR R1R2 / (R1 + R2) C1 words, symbols or numbers 12 Ω A1 [2] [Total: 9]
11 Fig. 11.1 shows the main components of a cathode-ray oscilloscope. For Examiner’s Use IOXRUHVFHQW VFUHHQ KHDWHU EHDP FDWKRGH DQRGH < SODWHV ; SODWHV YDFXXP V\VWHP JULG Fig. 11.1 (a) (i) Name the particles that are in the beam. … [1] (ii) Explain the purpose of the heater. … [1] (iii) Explain why there is a vacuum in the tube. … … [1] (b) When no potential difference (p.d.) is applied across either the X-plates or the Y-plates, a spot is seen in the centre of the fluorescent screen. Describe the p.d.s applied to the X-plates and to the Y-plates when the spot moves up and down in the centre of the screen. X-plates … Y-plates … [2] [Total: 5]
5 marks
Mark scheme: 11 (a) (i) electrons B1 [1] ignore β (ii) to heat cathode or produce thermionic emission o.w.t.t.e. i.e. any mention of heating/providing energy and production/emission of electrons B1 [1] NOT heater/filament emits electrons (iii) air would stop/weaken (electron) beam OR electrons have no collisions B1 [1] (b) X-plates B1 zero (p.d.)/off NOT zero current Y-plates B1 [2] alternating (p.d.) OR description condone a.c. [Total: 5]
8 Fig. 8.1 shows a small, uncharged copper sphere suspended from a nylon thread, and a For plastic rod being rubbed with a woollen cloth. Examiner’s Use nylon plastic rod thread woollen cloth copper sphere Fig. 8.1 The rod becomes negatively charged as it is rubbed. (a) Explain, in terms of electrons, why copper is a conductor but nylon is an insulator. … … … [2] (b) Describe how the negatively charged rod may be used to induce a positive charge on the copper sphere. … … … … [3] (c) The copper sphere is given a positive charge, as shown in Fig. 8.2. + Fig. 8.2 On Fig. 8.2, draw arrows to indicate the direction and pattern of the electric field that surrounds the positively charged sphere. [2] [Total: 7]
7 marks
Mark scheme: 8 (a) in copper/metals/conductors, electrons (free to move) B1 in nylon/insulators electrons fixed/not free (to move) B1 (b) (negatively charged nylon) rod near to sphere B1 earth/touch (with hand) the sphere B1 remove earth/hand (and remove rod) B1 (c) at least four equally spaced, radial lines from surface M1 at least one outward arrow AND none wrong A1 [7]
11 A remote ski lodge receives 18 kW of electric power from a 120 V supply. For Examiner’s (a) Calculate Use (i) the current that the ski lodge draws from the supply, current = … [2] (ii) the electrical energy supplied to the ski lodge in 30 minutes. energy = … [2] (b) The power supply to the ski lodge is from a nearby transformer that is connected to long-distance transmission cables. The voltage of the transmission cables is very much larger than 120 V. Explain why energy losses in the transmission cables are lower when the voltage is high. … … … … … [3] [Total: 7]
7 marks
Mark scheme: 11 (a) (i) (I = )P/V OR 18 000/120 OR 18/120 C1 150 A A1 (ii) (E = )Pt OR 18 000 × 30 × 60 OR 18 000 × 1800 OR 18 000 × 30 OR 5.4 × 105 C1 3.2 × 107 J OR 9.0 kW h A1 (b) any three of: (high voltage means) low(er) current for given supply power (low(er) current means) less heat/thermal energy (generated in cables) OR P = I2R for given resistance (of cables) cables heated by current B3 [7]
9 (a) State the relationship between For Examiner’s (i) the resistance R and the length L of a wire of constant cross-sectional area, Use … (ii) the resistance R and the cross-sectional area A of a wire of constant length. … [1] (b) A 60 W filament lamp X is connected to a 230 V supply, as shown in Fig. 9.1. 230 V X Fig. 9.1 Calculate the current in the filament. current = … [2] (c) Lamp Y has a filament made of the same metal as the filament of lamp X in (b). For Examiner’s This filament has half the length and one-third of the cross-sectional area of the filament Use of X. Lamp Y is also connected to a 230 V supply. current in filament of Y Calculate the ratio Show your working. current in filament of X. ratio = … [4] [Total: 7]
7 marks
Mark scheme: 9 (a)(i)(ii) R ∝ L in words or symbols (ii) AND R ∝ 1 / A in words or symbols B1 (b) P = IV OR (I =) P / V OR 60 / 230 C1 0.26 A A1 IGCSE – October/November 2013 0625 31 (c) length change divides resistance by 2 / multiplies current by 2 C1 cross-section change multiplies resistance by 3 / divides current by 3 C1 (overall) resistance of Y is 3/2 times bigger / 3/2 × 885 Ω / 1327 Ω OR current in Y 2/3 of 0.26 A = 0.17 A C1 current in Y / Current in X = 2/3 A1 [Total: 7]
10 (a) Fig. 10.1 shows an electron beam travelling, in a vacuum, towards the space between a For pair of oppositely-charged parallel plates. Examiner’s Use + + + + + + + + + + electron beam – – – – – – – – – – Fig. 10.1 On Fig. 10.1, draw carefully the path of the beam between the plates and in the space to the right of the plates. [2] (b) The screen of a cathode-ray oscilloscope (c.r.o.) has a grid of 1 cm squares. Fig. 10.2 shows the trace of an alternating voltage on this screen. 1 cm 1 cm Fig. 10.2 (i) A potential difference of 5.0 V across the Y-plates of the oscilloscope moves the spot on the screen a vertical distance of 1.0 cm. Use Fig. 10.2 to determine the maximum p.d. across the Y-plates. maximum p.d. = … [1] (ii) The spot on the screen takes 1.0 ms to move 1.0 cm horizontally. For Examiner’s From Fig. 10.2, determine the time for 1 cycle of the waveform on the screen, and Use use this time to find the frequency of the alternating voltage. frequency = … [3] [Total: 6]
6 marks
Mark scheme: 10 (a) between plates path curves upwards continuously B1 continuation in straight line in space beyond plates B1 (b) (i) in range 7.0 to 7.5 V B1 (ii) use of the number 4 (as a distance or a time) C1 f = 1/T OR ¼ OR 1/0.004 but NOT if f = v/λ used C1 250 Hz A1 [Total: 6]
9 In the circuit shown in Fig. 9.1, resistors can be connected between terminals P and Q. The e.m.f. of the battery is 6.0 V. 6.0 V A P Q Fig. 9.1 (a) Calculate the current shown by the ammeter when a 12.0 Ω resistor and a 4.0 Ω resistor are (i) connected in series between P and Q, current = … [2] (ii) connected in parallel between P and Q. current = … [3] (b) State the relationship between (i) the resistance R and the length l of a wire of constant cross-sectional area, … (ii) the resistance R and the cross-sectional area A of a wire of constant length. … [2] (c) The 12.0 Ω and 4.0 Ω resistors in (a) are wires of the same length and are made of the same alloy. cross-sectional area of 12.0 Ω resistor Calculate the ratio: cross-sectional area of 4.0 Ω resistor ratio = … [1] [Total: 8]
8 marks
Mark scheme: 9 (a) (i) (I =) V / R OR 6 / (12 + 4) OR 6 / 16 C1 0.38 A / 0.37 A A1 IGCSE – May/June 2014 0625 31 (ii) 1 / R = 1 / R1 + 1 / R2 OR (R =) R1 R2 / (R1 + R2) OR above with numbers substituted C1 R = 3 (Ω) C1 (I = 6 / 3 =) 2(.0) A A1 OR ALTERNATIVE METHOD: 6 / 12 (C1) + 6 / 4 (C1) 2(.0) A (A1) (b) (i) R ∝ l (in words or symbols) OR directly proportional OR e.g. R doubles when l doubles B1 (ii) R ∝1 / A (or with words) OR inversely proportional OR e.g. R doubles when A halves B1 (c) 4 / 12 OR 4:12 OR 1 / 3 OR 1:3 OR 0.33 B1 [Total: 8]
8 Fig. 8.1 shows three cells each with e.m.f. 1.5 V connected in series. 1.5 V 1.5 V 1.5 V 4.0 1 1.0 1 1.0 1 Fig. 8.1 (a) Calculate the combined e.m.f. of the cells. e.m.f. = … [1] (b) Calculate the combined resistance of the three resistors shown in Fig. 8.1. resistance = … [2] (c) Calculate the current in the 4.0 Ω resistor in Fig. 8.1. current = … [3] (d) Calculate the combined e.m.f. of the cells if one cell is reversed. e.m.f. = … [1] [Total: 7]
7 marks
Mark scheme: 8 (a) 4.5 V ignore sign B1 (b) 1 / Rp = 1 / R1 + 1 / R2 OR (Rp =) R1R2 / (R1 + R2) words, symbols or numbers C1 R = (1 / (1 / 1 + 1 / 5)) = 0.83 Ω A1 (c) V= IR in any form OR V / R words, symbols or numbers C1 use of total e.m.f. as V AND series resistance as R OR 4 / 5 of total emf seen OR 1 / 6 of total current seen C1 (I = 4.5 / 5 =) 0.90 A accept 0.9 e.c.f. from (a) A1 (d) 1.5 V ignore sign B1 [Total: 7]
9 Fig. 9.1 shows a positively charged plastic rod, a metal block resting on an insulator, and a wire connected to earth. positively charged plastic rod metal block wire connected insulator to earth Fig. 9.1 (a) On Fig. 9.1, draw the charge distribution in the metal block. [2] (b) The earth wire is held against the metal block, as shown in Fig. 9.2. positively charged plastic rod metal block wire connected insulator to earth Fig. 9.2 On Fig. 9.2, draw the new charge distribution. [1] (c) The charged rod and the earth wire are removed and the metal block is left charged. State the order in which the rod and the wire were removed. Explain your answer. … … … … [2] (d) Name this charging process. … [1] [Total: 6]
6 marks
Mark scheme: 9 (a) more negatives in top half than bottom half M1 roughly same no of positives as negatives A1 (b) clearly more negatives than positives, anywhere in / on block B1 (c) wire removed first M1 charges kept in block OR so no charge can flow to or from block NOT any mention of positive charges moving accept reverse argument A1 (d) (charging by) induction NOT e.m. induction OR earthing B1 [Total: 6]
9 Fig. 9.1 represents two identical metal plates, positioned horizontally, one above the other in a vacuum. Fig. 9.1 A negative charge of 0.000 000 042 C (4.2 × 10−8 C) is transferred to the upper plate, leaving the lower plate with a positive charge of the same size. (a) On Fig. 9.1, draw the pattern of the electric field between the two plates and indicate the direction of the lines of force. [3] (b) (i) A conducting copper wire is used to connect the two plates and this leaves the plates uncharged. Charge flows in the wire for 0.000 000 035 s (3.5 × 10−8 s). Calculate the average current in the wire during this time. current = … [3] (ii) State, in terms of its atomic structure, why the copper wire is an electrical conductor. … … … [2] [Total: 8]
8 marks
Mark scheme: 9 (a) at least three vertical lines between the plates B1 equally spaced OR some curvature at the ends B1 at least one correct (upwards) arrow AND none wrong B1 (b) (i) (I=) Q / t OR 0.000 000 042 / 0.000 000 035 OR 4.2 × 10–8 / 3.5 × 10–8 C1 1.2 × 10n for any n C1 1.2 A A1 (ii) contains electrons C1 electrons are free to move A1 [Total: 8]
8 A charger for a cellphone (mobile phone) is marked: input: a.c. 240 V, 50 Hz, 80 mA. output: d.c. 5.3 V, 500 mA. (a) State (i) the component in the charger that converts a.c. to d.c., … (ii) the quantity that has the value 50 Hz. … [2] (b) Calculate (i) the output power of the charger, output power = … [2] (ii) the energy transferred in the output circuit when the cellphone is charged for 1.5 hours. energy = … [2] (c) In the following list, underline the quantity that is stored in the battery of the cellphone. voltage current power energy [1] [Total: 7]
7 marks
Mark scheme: 8 (a) (i) rectifier / diode B1 (ii) frequency (of A.C. supply) B1 (b) (i) (P =) IV OR 0.5 × 5.3 OR 500 × 5.3 C1 2.6 W OR 2600 mW A1 (ii) (E =) Pt OR IVt OR 2.65 × 1.5 × 3600 OR 0.5 × 5.3 × 1.5 × 3600 C1 14000 J A1 (c) energy only underlined B1 [Total: 7]
8 (a) Fig. 8.1 shows two resistors X and Y in series. X Y I R 2R Fig. 8.1 Complete the table below, using only the symbols I and R, alone or in combination. resistor resistance current potential power difference X R I I2R Y 2R 2IR [3] (b) Fig. 8.2 represents the system used to transmit electricity from a power station to a factory. power line 750 A power 11 000 V factory station power line Fig. 8.2 The power station generates 11 000 V and supplies a current of 750 A. The total resistance of the power lines between the power station and the factory is 1.5 Ω. Calculate (i) the power output of the power station, power = … [1] (ii) the potential difference across the 1.5 Ω of the power lines, potential difference = … [1] (iii) the power supplied to the factory. power = … [3] [Total: 8]
8 marks
Mark scheme: 8 (a) one mark for each correct entry in table: B3 resistor resistance current potential power difference IR I 2I2R (b) (i) (P = IV = 750 × 11000 =) 8.3 × 106 W (8300 kW) B1 (ii) (V = IR =750 × 1.5 =) 1100 V B1 (iii) (voltage to factory = 11 000 – 1125 =) 9875 V C1 (power supplied to factory =) 9875 × 750 A1 7.4 × 106 W OR 7400 kW A1 OR power loss in cables = I 2R OR 7502 × 1.5 (C1) (=) 8.44 × 105 (W) (A1) (power to factory = 8.25 × 106 – 8.44 × 105 =) 7.4 × 106 W OR 7400 kW (A1) [Total: 8]
8 A student sets up a circuit containing three identical cells. Each cell has an e.m.f. (electromotive force) of 2.0 V. Fig. 8.1 shows the cells in series with a length of uniform metal wire connected between two terminals K and L, an ammeter and a resistor X. uniform metal wire K A L X Fig. 8.1 (a) State the total e.m.f. of the three cells in series. total e.m.f. = … [1] (b) The ammeter reading is 0.25 A. (i) State the name of the unit in which electric charge is measured. … [1] (ii) Calculate the charge that flows through the circuit in twelve minutes. charge = … [2] (iii) The metal wire has a resistance of 16 Ω. Calculate the resistance of resistor X. resistance = … [2] (c) The student removes the 16 Ω wire from the circuit and cuts it into two equal lengths. He then connects the two lengths in parallel between K and L, as shown in Fig. 8.2. uniform metal K wire A L X Fig. 8.2 Calculate the resistance of the two lengths of wire in parallel. resistance = … [3] [Total: 9]
9 marks
Mark scheme: 8 (a) 6.0 V B1 (b) (i) coulomb (IGNORE C) B1 (ii) (Q =) I t OR 0.25 × 12 × 60 OR 0.25 × 720 OR 0.25 × 12 OR 3.0 OR 0.25 × 60 OR 15 C1 180 (C) A1 (iii) (R =) V / I or 6.0 / 0.25 or 24.0 e.c.f. from (a) OR (V =) IR OR 0.25 × 16 OR 4.0 e.c.f. from (a) C1 8.0 Ω A1 (c) R ∝ l OR 8.0 OR 16 / 2 C1 R1R2 / (R1 + R2) OR 1 / R = 1 / R1 + 1 / R2 OR 64 / 16 OR 1 / R = 1 / 8 + 1 / 8 C1 4.0 Ω A1 [Total: 9]
7 (a) (i) State what is meant by an electric field. … … [1] (ii) Fig. 7.1 shows a small, positively charged sphere. + Fig. 7.1 On Fig. 7.1, sketch the pattern of the electric field in the space around the sphere. [2] (b) Fig. 7.2 shows a metal sphere on an insulating support. Fig. 7.2 A student has available two rods, one charged positively and one charged negatively. Using one of these rods, she gives the sphere a uniform negative charge by induction. State which rod she chooses, and describe the procedure she follows. … … . … … … … [4] [Total: 7]
7 marks
Mark scheme: 7 (a) (i) A region in which a force acts upon an (electric) charge/charged object B1 (ii) At least 4 radial straight lines with lines evenly spaced B1 Arrows on lines pointing away from + charge B1 (b) Use positively charged rod B1 Place rod close to surface of sphere B1 Touch sphere (briefly) with finger OR Connect sphere to earth and remove earth connection OR Briefly connect sphere to earth B1 Remove charged rod B1 [Total: 7]
10 Fig. 10.1 shows two parallel conducting plates connected to a very high voltage supply. + – + – conducting plate + – + – + – + – + – + – + – + – + – + – + – voltage supply Fig. 10.1 The left-hand plate is positively charged and the right-hand plate is negatively charged. (a) On Fig. 10.1, draw the electric field pattern produced between the charged plates. Use arrows to show the direction of the field. [2] (b) A light, conducting ball is suspended by an insulating string. Fig. 10.2 shows the ball in the middle of the gap between the plates. + – + – + – + – + – + – + – + – + – + – + – + – + – voltage supply Fig. 10.2 On Fig. 10.2, show the distribution of charge on the ball. [2] (c) The ball is displaced to the left and then oscillates backwards and forwards between the two plates. The ball touches a plate once every 0.05 s. Every time it touches a plate, a charge of 2.8 × 10−8 C (0.000 000 028 C) is transferred. Calculate the average current produced by the repeated transfer of charge. current = … [2] [Total: 6] Question 11 is on the next page.
6 marks
Mark scheme: 10 (a) (i) at least three horizontal, parallel lines evenly spaced (ignore edge effects) B1 arrows pointing left to right B1 (b) right hand half of ball has more + signs than – signs AND left hand half of ball has more – signs than + signs M1 equal numbers of + and – signs A1 (c) Q = I t in any form OR (I =) Q ÷ t OR 2.8 × 10–8 ÷ 0.05 C1 5.6 × 10–7 A OR C/s A1 [Total: 6]
4 (a) Fig. 4.1 shows a device used as a thermocouple thermometer. meter Z wire of material X wire of material X wire of material Y Fig. 4.1 In the table put three ticks against the correct statements about the thermocouple thermometer. Meter Z measures energy. Meter Z measures potential difference. Meter Z measures power. Materials X and Y are different materials. Materials X and Y are the same material. Materials X and Y are electrical conductors. Materials X and Y are electrical insulators. [3] (b) A liquid-in-glass thermometer is replaced by a similar thermometer with a larger bulb. No other change is made. State and explain the effect on the sensitivity. … … … [2] (c) The capillary of a liquid-in-glass thermometer should have a constant diameter. Fig. 4.2 shows the capillary of a thermometer made with a manufacturing fault. walls of glass non-uniform capillary bulb capillary Fig. 4.2 (not to scale) State and explain the effect of this fault on the linearity of the thermometer. … … … [2] [Total: 7]
7 marks
Mark scheme: 4 (a) box 2: Z measures p. d. B1 box 4: X and Y are different materials. B1 box 6: X and Y are electrical conductors. B1 (b) more sensitive OR thread moves more M1 more (greater volume of) expansion A1 (c) not linear OR linearity worse/less B1 correctly relates movement of thread to diameter of capillary B1
8 Fig. 8.1 shows a circuit containing a battery of electromotive force (e.m.f.) 12 V and a heater of resistance 6.0 Ω. 12 V A 6.0 1 Fig. 8.1 (a) State what is meant by electromotive force (e.m.f.). … … [1] (b) (i) Calculate the current in the heater. current = … [2] (ii) State the name of the particles that flow through the heater. … [1] (iii) On Fig. 8.1, draw an arrow next to the heater symbol to show the direction of flow of these particles through the heater. [1] (c) Calculate the thermal energy produced in the heater in 10 minutes. thermal energy = … [2] [Total: 7]
7 marks
Mark scheme: 8 (a) energy transferred per coulomb/unit charge OR energy supplied in driving coulomb/unit charge around a circuit ACCEPT p.d./voltage across battery/power supply B1 (b) (i) V = IR in any form OR (I =) V ÷ R C1 2.0 A OR 2 A A1 (ii) electrons B1 (iii) arrow right to left by heater OR indication of clockwise B1 (c) (E =) VIt OR V 2t/R OR I 2Rt in any form C1 14 000 J A1
9 An extremely violent nuclear reaction is taking place at the centre of the Sun. It is this reaction that enables the Sun to emit both a very large quantity of energy and an extremely large number of charged particles. (a) Name the type of nuclear reaction taking place in the Sun. … [1] (b) Many of the charged particles produced by the Sun are emitted from its surface at high speeds and travel out into space. (i) Explain why these particles constitute an electric current. … … [1] (ii) State the equation that relates the electric current I to the charge Q that is flowing. Define any other terms in the equation. … … [1] (c) Some of the particles emitted by the Sun travel straight towards the Earth until they enter the Earth’s magnetic field. Because they constitute a current, they experience a force and are deflected. (i) Describe the relationship between the direction of the force and 1. the direction of the current, … [1] 2. the direction of the magnetic field. … [1] (ii) A negatively charged particle is travelling in a magnetic field. This is represented in Fig. 9.1. The direction of the magnetic field is into the page. direction of travel of particle magnetic field into page negative particle Fig. 9.1 On Fig. 9.1, draw an arrow, labelled F, to show the direction of the force that acts on the particle. [1] [Total: 6]
6 marks
Mark scheme: 9 (a) (nuclear) fusion B1 (b) (i) charges are moving (and current is the (rate of) flow of charge) B1 (ii) Q = It AND t is time B1 (c) (i) 1. (they are) perpendicular OR at right angles OR at 90° B1 2. (they are) perpendicular OR at right angles OR at 90° B1 (ii) arrow (labelled F) perpendicular to direction AND pointing towards the bottom right of the page B1 [Total: 6]
8 A digital watch is powered by a 1.3 V cell. The cell supplies a current of 4.1 × 10–5 A (0.000041 A) for 1.6 × 107 s. Calculate (a) the charge that passes through the cell in this time, charge = … [2] (b) the resistance of the electrical circuit in the watch, resistance = … [2] (c) the output power of the cell. power = … [2] [Total: 6]
6 marks
Mark scheme: 8 (a) (Q =) It OR 4.1 x10–5 × 1.6 × 107 C1 = 660 C A1 (b) (R =) V / I OR 1.3 / 4.1 × 10–5 C1 = 32 000 Ω OR 32 kΩ A1 (c) 1st method: (P =) IV OR 4.1 × 10–5 × 1.3 OR 2nd method: (P =) I2R OR (4.1 × 10–5)2 × 32 000 OR 3rd method: (P =) V2 / R OR 1.32 / 32 000 OR 4th method: (P =) QV / t OR 660 × 1.3 / 1.6 × 107 C1 1st and 3rd methods: 5.3 × 10–5 W / 0.000053 W 2nd and 4th methods: 5.4 × 10–5 W / 0.000054 W A1 [Total: 6]
8 A metal sphere, mounted on an insulating plastic stand, is positively charged. (a) State the name of the unit in which electric charge is measured. … [1] (b) A smaller metal sphere, also mounted on an insulating plastic stand, is uncharged. This smaller sphere is moved close to the positively charged sphere. Fig. 8.1 shows the two spheres. positively charged sphere smaller sphere plastic stands Fig. 8.1 (i) On Fig. 8.1, draw the distribution of charge on the smaller sphere. [2] (ii) An earthed metal wire is touched against the smaller metal sphere. State and explain what happens to the charge on the smaller sphere. … … … [2] (c) Explain, in terms of their structures, why the metal wire is an electrical conductor but the plastic stand is an electrical insulator. … … … [2] [Total: 7]
7 marks
Mark scheme: 8 (a) coulomb B1 (b) (i) negative charge(s) on left AND positive charge(s) on right M1 equal number of positive and negative charges AND number of each ≤ 7 A1 (ii) electrons / negative charges flow from Earth / on to sphere (NOT protons / positive charges / positive electrons move) B1 total charge negative OR (some) protons / positive charges cancelled B1 (c) metal contains free (delocalised) electrons OR electrons can move about B1 electrons in plastic not free to move / fixed B1 [Total: 7]
9 (a) The resistance of a long piece of wire is 6.0 Ω. The potential difference across the wire is 2.0 V. Calculate the current in the wire. current = … A [3] (b) A force acts on a wire carrying a current in a magnetic field. Fig. 9.1 shows the direction of the current in the wire and the direction of the force acting on the wire. wire current N S direction of force Fig. 9.1 (i) On Fig. 9.1, draw arrows to indicate the direction of the magnetic field. [1] (ii) The magnetic field is reversed. State what happens, if anything, to the direction of the force on the wire. … [1] (c) Fig. 9.2 shows a current-carrying coil in a magnetic field. magnet axle N N coil to + magnet S S – battery axle Fig. 9.2 The coil starts to turn about its axle. (i) State two ways of increasing the turning effect on the coil. 1. … 2. … [2] (ii) Describe and explain the effect of reversing the connections to the battery. … … … … [2] [Total: 9]
9 marks
Mark scheme: 9(a) V = I × R OR V ÷ R in words, numbers or symbols 2.0 ÷ 6.0 0.33 (A) B1 B1 B1 9(b)(i) arrows indicating field drawn from N to S B1 9(b)(ii) force upwards / reverses B1 9(c)(i) any two from: increase current in the coil increase the strength of the magnets or magnetic field increase the number of turns in the coil B2 9(c)(ii) force on (each side of) coil or turning effect is in opposite direction or coil turns in opposite direction (because) current (through motor) is in opposite direction B1 B1 Total: 9
10 Fig. 10.1 shows the charger for a laptop computer. charger Fig. 10.1 The charger contains a transformer. (a) The voltage across the primary coil of the transformer is 230 V. The primary coil has 4995 turns and the secondary coil has 555 turns. Calculate the output voltage of the transformer. output voltage = … V [3] (b) State the term used to describe this type of transformer. … [1] [Total: 4]
4 marks
Mark scheme: 10(a) 230 / V s = 4995 ÷ 555 or Vs = 230 ÷ 9 Vs = (555 ÷ 4995) × 230 25.6 (V) C1 C1 A1 10(b) step-down (transformer) B1 Total: 4
9 (a) The resistance of a long piece of wire is 6.0 Ω. The potential difference across the wire is 2.0 V. Calculate the current in the wire. current = … A [3] (b) A force acts on a wire carrying a current in a magnetic field. Fig. 9.1 shows the direction of the current in the wire and the direction of the force acting on the wire. wire current N S direction of force Fig. 9.1 (i) On Fig. 9.1, draw arrows to indicate the direction of the magnetic field. [1] (ii) The magnetic field is reversed. State what happens, if anything, to the direction of the force on the wire. … [1] (c) Fig. 9.2 shows a current-carrying coil in a magnetic field. magnet axle N N coil to + magnet S S – battery axle Fig. 9.2 The coil starts to turn about its axle. (i) State two ways of increasing the turning effect on the coil. 1. … 2. … [2] (ii) Describe and explain the effect of reversing the connections to the battery. … … … … [2] [Total: 9]
9 marks
Mark scheme: 9(a) V = I × R OR V ÷ R in words, numbers or symbols 2.0 ÷ 6.0 0.33 (A) B1 B1 B1 9(b)(i) arrows indicating field drawn from N to S B1 9(b)(ii) force upwards / reverses B1 9(c)(i) any two from: increase current in the coil increase the strength of the magnets or magnetic field increase the number of turns in the coil B2 9(c)(ii) force on (each side of) coil or turning effect is in opposite direction or coil turns in opposite direction (because) current (through motor) is in opposite direction B1 B1 Total: 9
9 Fig. 9.1 shows the electric circuit for a fan heater. 24 V motor for fan P M heater Fig. 9.1 The fan blows air over the heater. The fan is driven by a motor connected to a 24 V d.c. supply. (a) Explain the difference between an a.c. supply and a d.c. supply. … … [1] (b) The circuit includes a component labelled P. (i) Name this component. … [1] (ii) Explain the function of this component in the circuit. … … [2] (c) (i) The heater has a resistance of 8.5 Ω and the potential difference across it is 24 V. Calculate the current in the heater. Include the unit. current = … [4] (ii) Suggest the rating of the fuse needed for the heater. … [1] (d) A different fan heater for use in a house is connected to a 110 V supply. This heater has a metal case. Explain the benefit of earthing the metal case. … … … … [1] [Total: 10]
10 marks
Mark scheme: 9(a) a.c. current changes direction OR d.c. one direction only B1 9(b)(i) variable resistor B1 9(b)(ii) changes the amount of current B1 changes speed of motor fan B1 9(c)(i) V = IR in any form C1 24/8.5 C1 2.82 A1 A OR amps B1 9(c)(ii) 5 (A) B1 9(d) protect user from electric shock B1 Total: 10
11 An electrical conductor is placed between the poles of a magnet as shown in Fig. 11.1. 0 electrical conductor S pole N pole Fig. 11.1 (a) State a material from which an electrical conductor can be made. … [1] (b) (i) A centre-zero meter measures the electromotive force (e.m.f.) across the conductor. State the unit of e.m.f. unit = … [1] (ii) State what, if anything, is shown by the centre-zero meter when the conductor is moved. • horizontally, from side-to-side, between the poles of the magnet, … • vertically, up-and-down, between the poles of the magnet. … [3] (c) State two factors that affect the size of the e.m.f. across the conductor. 1 … 2 … [2] [Total: 7]
7 marks
Mark scheme: 11(a) metal B1 11(b)(i) volt OR V OR mV B1 11(b)(ii) 1 Nothing owtte B1 2 pointer deflects / moves B1 backwards and forwards owtte B1 11(c) 1 strength of magnet B1 2 rate of (relative) movement B1 Total: 7
11 Fig. 11.1 shows a power supply in series with a resistance wire and a switch. power supply thin resistance wire Fig. 11.1 (a) When the switch is closed, energy is transferred from the power supply. Explain what happens to this energy. … … [2] (b) A student wants to determine the resistance of the wire. He adds components to the circuit shown in Fig. 11.1. (i) He measures the current in the circuit. State the name of the component that he uses. … [1] (ii) The student measures the potential difference (p.d.) across the resistance wire. On Fig. 11.1, draw the correct symbol for the component he uses and show how he connects it. [2] (iii) Fig. 11.2 shows the symbol for another component that the student adds to the circuit. Fig. 11.2 State the name and function of this component. name … function … … [2] [Total: 7]
7 marks
Mark scheme: 11(a) thermal B1 lost to surroundings/air owtte B1 11(b)(i) ammeter B1 11(b)(ii) correct symbol for voltmeter B1 connected in parallel with the resistance wire B1 11(b)(iii) variable resistor B1 varies/changes current/resistance/voltage (in resistance wire) B1 Total: 7
9 Fig. 9.1 shows a current-carrying coil in a magnetic field. coil B C current N S A D F connections to battery + – battery Fig. 9.1 The direction of the current in side AB of the coil is labelled. The force F on side AB is also labelled. (a) On Fig. 9.1, draw • an arrow labelled X, on side CD, to show the direction of the current in this side of the coil, • an arrow labelled P, to show the direction of the force on CD. [2] (b) Give two ways of increasing the forces F and P on the sides of the coil. 1. … … 2. … … [2] (c) (i) Name the particles that flow in the metal wire of the coil. … [1] (ii) The wire of the coil is replaced by a thinner wire. This wire is the same length and is made of the same metal. State and explain how this changes the current in the coil. … … … [2] [Total: 7]
7 marks
Mark scheme: 9(a) arrow drawn pointing from C to D B1 arrow on /near side CD pointing upwards B1 9(b) any 2 from: increase (size of) current increase strength of magnet increase number of turns in coil B2 9(c)(i) electrons B1 9(c)(ii) current is smaller B1 (as) resistance of coil/wire is greater B1 Total: 7
11 Fig. 11.1 shows a charger for a mobile (cell) phone. The charger contains a transformer. Fig. 11.1 (a) The primary coil of the transformer has 900 turns and the secondary coil has 49 turns. The input voltage to the transformer is 220 V. Calculate the output voltage. output voltage = … V [3] (b) State the name of the metal used to make the coils of the transformer. … [1] (c) A transformer uses an alternating current (a.c.). Describe the difference between alternating current (a.c.) and direct current (d.c.). … … … [1] [Total: 5]
5 marks
Mark scheme: 11(a) N1/ N2 = V1 / V2 C1 (49 / 900) × 220 OR use of ratios seen C1 11.98 OR 12 (V) A1 11(b) copper B1 11(c) d.c. is in one direction only / a.c. changes direction B1
11 A student wants to find the resistance of a wire. He connects the circuit shown in Fig. 11.1. V wire A Fig. 11.1 (a) A teacher checks the circuit and identifies three errors. Using the components given in Fig. 11.1, carefully draw the correct circuit diagram in the space below. [3] (b) The student uses the correct circuit. The student finds that the current is 0.3 A when the potential difference across the wire is 2.7 V. Calculate the resistance of the wire. resistance = … Ω [3] (c) The student tests two other pieces of wire made of the same metal. He compares each resistance value with that of the first wire. State how the resistance compares with the first wire (i) for a wire that is longer, but of the same thickness, … [1] (ii) for a wire that is thicker, but of the same length. … [1] [Total: 8]
8 marks
Mark scheme: 11(a) ammeter in series B3 voltmeter across wire two cells correctly linked positive to negative 11(b) V = IR in any recognised form C1 R = 2.7 ÷ 0.3 C1 9 (Ω) A1 11(c) 1 higher / more B1 2. lower / less B1
10 Fig. 10.1 shows a circuit for determining the resistance of a component. A V Fig. 10.1 (a) On Fig. 10.1, label the fixed resistor, by writing the letter R. [1] (b) Two components in Fig. 10.1 measure electrical quantities. Identify the quantity that each component measures. Write each quantity and the unit of each quantity in the correct place in Table 10.1. component quantity unit A V Table 10.1 [4] (c) A student uses the circuit in Fig. 10.1 to determine the resistance of wires made from the same material. State how the resistance of a wire is related to its length and its diameter. length … … diameter … … [2] [Total: 7]
7 marks
Mark scheme: 10(a) resistor identified 1 10(b) quantity unit current NOT amps ignore ammeter A/amps/amperes 2 quantity unit potential difference or p.d. or emf V/volts ignore voltmeter 2 10(c) increasing (length) increases resistance owtte 1 increasing (diameter) decreases resistance owtte 1
9 (a) Fig. 9.1 shows a simple circuit. A 0.50 A V 12.0 Ω 6.0 Ω Fig. 9.1 (i) The current in the wires of the circuit is a flow of particles. Indicate the name of these particles. Tick one box. electrons atoms protons [1] (ii) Calculate the combined resistance of the two resistors. resistance = … Ω [1] (iii) Calculate the potential difference (p.d.) reading that would be shown on the voltmeter. potential difference (p.d.) = … V [3] (b) The circuit is changed. The two resistors are connected in parallel. Explain what happens, if anything, to the current reading on the ammeter. … … … [2] [Total: 7]
7 marks
Mark scheme: 9(a)(i) top box (electrons) ticked 1 9(a)(ii) 12 + 6 seen or 18 (Ω) 1 9(a)(iii) (V =) I × R 1 (V =) 0.50 × 18(.0) 1 (V =) 9.0 (V) ecf from (a)(ii) 1 9(b) (reading/current) increases 1 (because effective circuit) resistance decreases/resistors in parallel have less resistance 1
10 (a) Fig. 10.1 shows an electrical circuit. 12 V power supply A X R V Fig. 10.1 (i) State the name for the component labelled X and state its function in this circuit. name for component … function … … [2] (ii) Describe how the circuit shown in Fig. 10.1 could be used to find the resistance of the fixed resistor R. … … … … … [3] (b) An electrical heater has a resistance of 21.8 Ω when connected to a 240 V mains supply. (i) Calculate the current in the heater. current = … A [3] (ii) Suggest a rating for the fuse to be fitted to the mains plug for the heater. fuse rating = … A [1] [Total: 9]
9 marks
Mark scheme: 10(a)(i) variable resistor 1 change the current 1 10(a)(ii) Any three from: use low value of current measure (and record) current measure (and record) voltage repeat other values (of I and V) plot graph of pd against current (and find gradient) OR use V = I × R 3 10(b)(i) V = I × R in any form OR (I =) V ÷ R 1 240 ÷ 21.8 1 11.0 (A) 1 10(b)(ii) Answer in range 12 to 15 (A) 1
9 A student fits an electrical generator to a bicycle. When the front wheel turns, a magnet rotates between two coils of wire. A lamp is connected to the coils of wire. When the magnet is rotating, the lamp is lit. Fig. 9.1 shows the magnet, the coils of wire and the lamp. N S lamp Fig. 9.1 (a) Describe and explain how rotating the magnet causes the lamp to light. … … … … [3] (b) State three ways of increasing the brightness of the bicycle lamp. 1. … 2. … 3. … [3] (c) The generator provides an a.c. supply for the lamp. (i) State the meaning of the term a.c. … [1] (ii) Describe how a.c. differs from d.c. … … [1] [Total: 8]
8 marks
Mark scheme: 9(a) magnetic field (of magnet) B1 changes / cuts coil / linked to coil B1 induces / causes / produces / generates an emf / voltage / current OR electromagnetic induction B1 9(b) stronger magnet more turns on coil(s) turn magnet at higher speed B3 9(c)(i) alternating (current) B1 9(c)(ii) a.c. changes direction OR d.c one direction only B1
10 Fig. 10.1 shows a circuit used by a student to test a metal wire made of nichrome. ammeter X A 0.8 A ammeter Y A component Z V nichrome wire Fig. 10.1 (a) State the name of component Z. … [1] (b) The current reading on ammeter X is 0.8 A. State the reading on ammeter Y. … [1] (c) The current in the nichrome wire is 0.8 A. The potential difference (p.d.) across the nichrome wire is 4.5 V. Calculate the resistance of the nichrome wire. resistance = … Ω [3] (d) The student tests a different nichrome wire, which is thicker than the wire in (c), but of the same length. When testing this wire, the current in the wire is different from the value given in (c). State and explain the difference in current. … … … [2] [Total: 7]
7 marks
Mark scheme: 10(a) variable resistor or rheostat B1 10(b) 0.8 (A) B1 10(c) V = IR OR (R =) V ÷ I C1 4.5 ÷ 0.8 C1 5.6(25) A1 10(d) (current) increases OR larger B1 (as new/thicker wire has) less resistance B1
9 Fig. 9.1 shows a circuit with two lamps and three ammeters connected in series to a power supply. A1 A3 A2 Fig. 9.1 (a) The current shown on ammeter A1 is 0.6 A. Complete the table with the values for the current that would be shown on the other two ammeters. ammeter current / A A2 A3 [1] (b) The resistance of each lamp is 20 Ω. Determine the combined resistance of the lamps. resistance = … Ω [1] (c) The circuit is changed. The two lamps are connected in parallel. (i) Compare the current from the power supply with the current in each lamp. … … [1] (ii) Compare the resistance of one lamp in this circuit with the combined resistance of the two lamps connected in parallel. … … [1] (d) A different series circuit contains a 140 Ω fixed resistor. An ammeter in the circuit shows a current of 0.30 A. Calculate the potential difference (p.d.) across the resistor. State the unit. potential difference = … [4] [Total: 8]
8 marks
Mark scheme: 9(a) A2 = 0.6 A AND A3 = 0.6 A B1 9(b) 40 (Ω) B1 9(c)(i) current from source is higher than in each lamp or reverse argument B1 9(c)(ii) (combined) resistance of lamps in parallel is less / lower (than one lamp) B1 9(d) V = IR in any recognisable form C1 V = 0.30 × 140 C1 42 A1 V or volts B1
10 Fig. 10.1 shows the apparatus for an experiment on electrostatics. iron nail aluminium clamp and stand cotton thread plastic stirrup polythene strip Fig. 10.1 (a) Identify the pieces of equipment that are electrical conductors and those that are electrical insulators. Draw a line from each piece of equipment to the correct box. aluminium clamp and stand conductor plastic stirrup iron nail insulator cotton thread [1] (b) State and explain how the polythene strip can be given a negative charge. … … … [2] (c) Describe how the apparatus in Fig. 10.1 could be used to demonstrate that the polythene strip has a negative charge. … … … [2] [Total: 5]
5 marks
Mark scheme: 10(a) clamp AND nail to conductor AND stirrup AND thread to insulator B1 10(b) rubbed with a cloth B1 electrons transfer to polythene / from cloth B1 10(c) (bring) a negatively charged rod / strip / object near B1 repulsion B1
9 A student makes a circuit to switch on a 6.0 V lamp from two different switches X and Y. Fig. 9.1 shows the circuit. + 6.0 V – P R switch X switch Y Q S Fig. 9.1 (a) Switch X is in position P. State the position of switch Y for the lamp to be lit. … [1] (b) The current in the lamp is 0.50 A when the potential difference (p.d.) across the lamp is 6.0 V. Calculate the resistance of the lamp. Include the unit. resistance = … [4] (c) The student connects another 6.0 V lamp in parallel with the first lamp, as shown in Fig. 9.2. + 6.0 V – switch X switch Y Fig. 9.2 Give two advantages of connecting the lamps in parallel. … … … [2] [Total: 7]
7 marks
Mark scheme: 9(a) (position) R B1 9(b) V = IR in any form C1 (R =) 6.0 ÷ 0.5 OR 6.0 = 0.5 × R C1 (R=) 12 A1 Ω or ohms B1 9(c) both lamps have correct p.d. OR voltage (across them) B1 if one lamp fails the other is still lit B1
9 Fig. 9.1 shows a plastic ruler. Fig. 9.1 (a) Suggest and explain how a student could give a positive charge to a plastic ruler. … … … [3] (b) A plastic ruler is given a positive charge. A sphere hangs from an insulating thread. A student holds the ruler near the sphere, as shown in Fig. 9.2. The ruler repels the sphere. insulating thread positively charged ruler sphere Fig. 9.2 (i) State what charge, if any, the sphere carries. … [1] (ii) Explain your answer to (b)(i). … [1] [Total: 5]
5 marks
Mark scheme: 9(a) (rule) rubbed with a cloth owtte B1 electrons or negative charges move B1 on to the cloth OR from / off the ruler B1 9(b)(i) positive B1 9(b)(ii) same charges repel B1
9 (a) A student tests some materials to find which ones are electrical conductors. He uses the circuit in Fig. 9.1. A component B X Y Fig. 9.1 (i) State the name of component B. … [1] (ii) Describe how the student can use the circuit in Fig. 9.1 to test whether a material is an electrical conductor. … … … … [2] (iii) State which materials are electrical conductors. Put a tick in the box next to each material that is an electrical conductor. plastic copper rubber gold [1] (b) The student connects a resistor R, between X and Y. The student determines the resistance of the resistor. (i) Name the instrument he uses to measure the potential difference (p.d.) across resistor R. … [1] (ii) The current in resistor R is 0.2 A when the p.d. across the resistor is 6.0 V. Calculate the resistance of resistor R. resistance = … Ω [3] [Total: 8]
8 marks
Mark scheme: 9(a)(i) variable resistor B1 9(a)(ii) connect material in gap/between X and Y B1 if reading on ammeter material is a(n electrical) conductor B1 9(a)(iii) BOTH copper AND gold ticked i.e. 2nd and 4th boxes B1 9(b)(i) voltmeter B1 9(b)(ii) V = IR OR (R = ) V/I C1 = 6.0 ÷ 0. C1 = 30 (Ω) A1
9 A student is experimenting with magnets and electric charges. (a) The student places a bar magnet on a piece of paper, as shown in Fig. 9.1. N S piece of paper Fig. 9.1 Show the pattern of magnetic field lines around the bar magnet. Draw two lines above the magnet and two lines below the magnet. Start and finish each line at a pole. Include one arrow to show the direction of the magnetic field. [3] (b) The student rubs a plastic rod with a dry cloth. The plastic rod becomes positively charged. Explain why the friction between the plastic and the cloth causes the plastic to become positively charged. … … … … [2] (c) The student investigates the forces between two pairs of objects. Fig. 9.2 and Fig. 9.3 show the pairs of objects. State whether there is a force of attraction, a force of repulsion, or no force between the pairs of objects. Draw a ring around one phrase for each pair of objects. 1. two positively charged spheres thin cotton + + + + + + + + + + + + + + + + Fig. 9.2 force of attraction force of repulsion no force 2. a bar magnet and a bar of copper metal N S bar of copper metal Fig. 9.3 force of attraction force of repulsion no force [2] [Total: 7]
7 marks
Mark scheme: 9(a) correct field pattern for bar magnet B1 no lines crossing and good detail of curvature B1 correct direction of arrow, i.e. out from N pole B1 9(b) electrons M1 move from the rod/to the cloth A1 9(c) 1. force of repulsion circled B1 2. no force circled B1
10 Fig. 10.1 shows the symbol for an electrical component. Fig. 10.1 (a) State the name of the component shown in Fig. 10.1. … [1] (b) The resistance of the component shown in Fig. 10.1 varies with temperature. Fig. 10.2 shows a graph of resistance against temperature for the component. 5000 resistance / Ω 4000 3000 2000 1000 0 –10 10 30 50 70 90 110 Temperature / °C Fig. 10.2 (i) Use Fig. 10.2 to determine the resistance of the component at a temperature of 10 °C. … Ω [1] (ii) At another temperature, the resistance of the component is 800 Ω. Calculate the current in the component when it is connected to a 12.0 V supply. current = … A [3] [Total: 5]
5 marks
Mark scheme: 10(a) thermistor B1 10(b)(i) 2000 (Ω) B1 10(b)(ii) (I =) V ÷ R OR V = I × R in any form 12 ÷ 800 0.015 (A) C1 C1 A1
11 Fig. 11.1 shows a diagram of an electrical device. The diagram is not complete. The coil rotates in a magnetic field when connected to a d.c. power supply. coil magnet S N Y X Fig. 11.1 (a) (i) Explain the meaning of the term d.c. … … [1] (ii) Complete the diagram in Fig. 11.1 by drawing the symbols for two cells in series and a switch to make a circuit. [2] (b) (i) State the name of the electrical device shown in Fig. 11.1. … [1] (ii) State two changes to the electrical device that will make the coil in the device rotate faster. 1. … 2. … [2] [Total: 6]
6 marks
Mark scheme: 11(a)(i) current is in one direction B1 11(a)(ii) symbols for two cells connected in series symbol for a switch B1 B1 11(b)(i) motor B1 11(b)(ii) any two from: increasing number of turns on coil increasing the current (in the coil) increasing the strength of the magnetic field B2
9 (a) Fig. 9.1 shows the magnetic field pattern around a bar magnet. bar magnet Fig. 9.1 (i) On Fig. 9.1, write the letters N and S to indicate the north and south poles of the magnet. [1] (ii) Fig. 9.2 shows a soft-iron bar placed close to a permanent magnet. permanent magnet soft-iron bar Fig. 9.2 State and explain what happens to the soft-iron bar. You may draw on Fig. 9.2. … … … [3] (b) Three balls P, Q and R are electrically charged. The balls are suspended by threads of insulating material. Fig. 9.3 shows the arrangement. insulated thread – ball P ball R ball Q Fig. 9.3 Ball P is negatively charged. (i) State the charge on ball Q and the charge on ball R. ball Q … ball R … [2] (ii) Explain your answer for part (i) for the charge on ball Q. … … … [2] [Total: 8]
8 marks
Mark scheme: 9(a)(i) N and S poles correctly labelled B1 9(a)(ii) (iron bar and magnet) attract (each other) B1 (iron) bar becomes an induced magnet B1 with opposite pole next to pole of magnet B1 Question Answer Marks 9(b)(i) (charge on Q is) negative B1 (charge on R is) positive B1 9(b)(ii) (ball) Q is repelled (by negative charge on P) B1 has same charge (as on P) B1
10 A student connects three identical lamps J, K and L in a circuit, as shown in Fig. 10.1. Switch S1 is open and the current in ammeter A1 = 0.2 A. A1 K A2 J A3 L S1 Fig. 10.1 Use words from the box to complete the sentences. Each word may be used once, more than once, or not at all. the same increased decreased (a) The switch S1 in Fig. 10.1 is closed. State and explain the effect on the circuit. (i) The current in ammeter A1 is … because the resistance of the whole circuit is … . [2] (ii) The current in ammeter A2 is … . [1] (b) A student measures the potential difference (p.d.) across lamp J by using a voltmeter. On Fig. 10.1, draw the correct electrical symbol for the voltmeter with the correct connections. [2] (c) The p.d. across lamp J is 3.0 V and the current shown by ammeter A3 is 0.15 A. Calculate the resistance of lamp J. Include the unit in your answer. resistance of lamp J = … unit … [4] [Total: 9]
9 marks
Mark scheme: 10(a)(i) increased B1 decreased B1 10(a)(ii) the same B1 10(b) correct voltmeter symbol B1 in parallel with battery B1 10(c) R = V ÷ I in any form C1 3(.0) ÷ 0.15 C1 20 A1 Ω / ohms B1
9 A student tests whether a bar magnet affects three different materials. Fig. 9.1 shows the bar magnet and a sample of each material A, B and C. A N S B C Fig. 9.1 The student tests each sample by holding each pole of the magnet close to one end of the sample. Table 9.1 shows his observations. Table 9.1 sample effect of N pole effect of S pole A attraction attraction B no effect no effect C attraction repulsion (a) Using the information in Table 9.1, draw a straight line from each sample to its correct property. Draw three lines. sample property A magnetic and magnetised B magnetic but not magnetised C non-magnetic [2] (b) Describe one method of producing a magnet from a bar of unmagnetised steel. … … … [2] (c) Another student does an experiment with some electrostatically charged plastic rods. Fig. 9.2 shows the student’s arrangement. negatively charged nylon plastic thread rod negatively charged plastic rod Fig. 9.2 Describe and explain what happens as the student brings one negatively charged rod close to the other negatively charged rod. … … … [2] [Total: 6]
6 marks
Mark scheme: 9(a) sample A magnetic and magnetised sample B magnetic but not magnetised sample C non-magnetic 9(b) use (same pole) of (permanent) magnet stroke bar (repeatedly) in same / one direction owtte OR place (bar / steel) in coil / solenoid current in coil OR connect coil to battery / power supply B2 9(c) rods repel OR move apart / away B1 like / same (type of) charges on both rods B1
10 Fig. 10.1 shows a metal kettle used for heating water. The kettle is connected to the mains power supply. The metal case is connected to earth. A fault causes the live wire to come loose and touch the metal case, as shown. live wire touching the metal case fuse heating element live wire earth wire neutral wire Fig. 10.1 (a) (i) The kettle is switched on. There is a very large electric current in the live wire. Explain why this large electric current can be dangerous. … … [1] (ii) Explain how a fuse helps to protect against the danger of a large electric current. … … … [2] (iii) Explain why the kettle is not safe to use with the fuse connected into the neutral wire instead of the live wire. … … [1] (b) The current in a device when operating normally is 3.1 A. State a suitable value for the fuse. Choose one of these values: 3 A, 5 A, 10 A and 13 A. … [1] (c) A small kettle has a potential difference (p.d.) of 12 V (d.c.) across its heating element. The current in the heating element is 2.5 A. Calculate the resistance of the heating element. resistance of the heating element = … Ω [3] [Total: 8]
8 marks
Mark scheme: 10(a)(i) (large current produces large) heating effect OR overheating OR (could) cause fire. B1 10(a)(ii) fuse melts B1 breaks circuit OR stops current in circuit B1 10(a)(iii) (metal case / kettle) would still be live OR connected to 240 V / mains (when fuse has melted) B1 10(b) 5 A B1 10(c) (R =) V ÷ I OR V = IR C1 12 ÷ 2.5 C1 4.8 (Ω) A1
10 (a) Describe an experiment to show that a force acts on a current-carrying conductor placed in a magnetic field. You may draw a diagram to help your answer. … … … … … … … [4] (b) A current in a wire can cause the wire to get hot and melt the wire. Describe how to reduce the heating effect of a current. … … [1] [Total: 5]
5 marks
Mark scheme: 10(a) wire or rod positioned between magnetic poles B1 diagram or description of working circuit B1 current in circuit OR switch circuit on B1 wire / rod moves owtte B1 10(b) use resistor in series / only allow current to flow for a short time / use a smaller current / use a smaller p.d. / reduce the pd of the power supply B1
9 Fig. 9.1 shows an electric circuit. buzzer A V thermistor Fig. 9.1 (a) When the circuit is in a cool room, the voltmeter reading is 5.6 V and the ammeter reading is 0.040 A. Calculate the resistance of the thermistor. resistance of thermistor = … Ω [3] (b) The temperature of the thermistor increases and the buzzer turns on. State and explain how the increase in temperature affects the current in the thermistor. … … [2] (c) Suggest a possible use for the circuit shown in Fig. 9.1. … [1] [Total: 6]
6 marks
Mark scheme: 9(a) C1 5.6 ÷ 0.04 C1 140 (Ω) A1 9(b) (current in thermistor) increases B1 (because) resistance of thermistor decreases B1 9(c) fire / high temperature alarm / warning B1
9 (a) The box lists four materials. aluminium iron plastic wood Use words from the box to answer parts (i) and (ii). Each word may be used once, more than once or not at all. (i) State all materials that are electrical insulators. … [1] (ii) State one example of a magnetic material. … [1] (b) Fig. 9.1 shows two magnets, P and Q, which are repelling each other. N magnet P magnet Q Fig. 9.1 On magnet P, the N pole is labelled N. On Fig. 9.1, label the other pole on magnet P and both poles on magnet Q. [1] (c) One advantage that electromagnets have, compared with permanent magnets, is that their strength can easily be altered. State one other advantage of an electromagnet compared with a permanent magnet. … [1] (d) A student wants to make the strongest electromagnet possible. Indicate which properties produce the strongest electromagnet. Tick (3) one box in each list. number of turns material in the core size of current in the coil in the coil 200 turns air 20 mA 100 turns iron 0.5 A 50 turns plastic 3.0 A [3] [Total: 7]
7 marks
Mark scheme: 9(a)(i) plastic AND wood B1 9(a)(ii) iron B1 9(b) B1 9(c) (electromagnet can be) switched off OR switched on B1 N S S N Question Answer Marks 9(d) feature 1: top box ticked (200 turns) B1 feature 2: middle box ticked (iron) B1 feature 3: bottom box ticked (3.0 A) B1
9 (a) Fig. 9.1 shows an electric circuit. component X A V light-dependent resistor (LDR) Fig. 9.1 (i) The current in the metal wires of the circuit is a flow of particles. State the name of these particles. … [1] (ii) State the name of component X. … [1] (iii) The circuit is in a darkened room. The voltmeter reading is 5.5 V and the ammeter reading is 0.050 A. Calculate the resistance of the light-dependent resistor (LDR). resistance = … Ω [3] (b) The light in the room is switched on. The room becomes bright. State and explain how increasing the brightness of the light that falls on the LDR changes the current in the circuit. … … [2] [Total: 7]
7 marks
Mark scheme: 9(a)(i) 9(a)(ii) (component X is a) variable resistor B1 9(a)(iii) V= IR or (R =) V/I C1 5.5 ÷ 0.05 (0) C1 110 (Ω) A1 9(b) (current in circuit) increases B1 (because) resistance of LDR decreases B1
9 (a) Fig. 9.1 shows two uncharged balloons suspended from a beam by light thread. beam light thread balloons Fig. 9.1 The balloons are close to each other but not touching. In the box below, draw the position of the balloons when they both have a positive charge. beam [1] (b) Table 9.1 includes a list of materials. State whether each material is an electrical conductor or an electrical insulator. The first example is done for you. Table 9.1 material conductor or insulator copper conductor rubber wood iron gold [2] (c) An uncharged cloth rubs an uncharged plastic rod. The cloth becomes positively charged and the plastic rod becomes negatively charged. Explain how the cloth becomes positively charged. … … … … [3] [Total: 6]
6 marks
Mark scheme: 9(a) showing repulsion B1 9(b) insulators: rubber AND wood B1 conductors: iron AND gold B1 9(c) electrons / negative charges B1 move / transfer B1 from cloth to rod B1
8 (a) Fig. 8.1 shows the magnetic field pattern around a bar magnet. Fig. 8.1 (i) On Fig. 8.1, label the north and south poles of the magnet, using the letters N and S. [1] (ii) A soft‑iron bar is positioned as shown in Fig. 8.2. soft-iron bar Fig. 8.2 State and explain what happens to the soft‑iron bar. … … … [3] (b) (i) A plastic rod is rubbed with a cloth. The plastic rod becomes positively charged. Explain how the friction between the cloth and the rod causes the rod to become positively charged. Use your ideas about the movement of charge. … … [2] (ii) Plastic is an electrical insulator. Iron is an electrical conductor. State two other materials that are electrical conductors. 1 … 2 … [1] [Total: 7]
7 marks
Mark scheme: 8(a)(i) N marked on left AND S on the right of magnet B1 8(a)(ii) (soft-iron / bar / it) is attracted to the (N pole of the) magnet B1 (soft-iron / bar / it) becomes induced magnet B1 with opposite pole nearest to magnet B1 8(b)(i) electrons move M1 from the rod OR to the cloth A1 8(b)(ii) TWO electrical conductors named B1
9 This question is about electric circuits. (a) (i) State the name of the instrument used to measure potential difference (p.d.) in an electric circuit. … [1] (ii) State the unit for the electromotive force (e.m.f.) of a battery. … [1] (b) (i) A student connects a circuit to determine the resistance of a wire. The current in the wire is 0.20 A when the potential difference across the wire is 6.4 V. Calculate the resistance of the wire. resistance = … Ω [3] (ii) The student has some wires of the same material as those in (b)(i) but of various lengths and thicknesses. He wants a wire with higher resistance than the wire in (b)(i). State two ways of identifying a wire with a higher resistance by comparing its length and thickness with the wire in (b)(i). 1 … 2 … [2] [Total: 7]
7 marks
Mark scheme: 9(a)(i) voltmeter B1 9(a)(ii) volts B1 9(b)(i) (R=) V ÷ I or V = I × R or in any form C1 6.4 ÷ 0.2 C1 32 (Ω) A1 9(b)(ii) increase the length (of the wire using the same thickness) B1 smaller diameter (of wire using the same length) B1
10 (a) Fig. 10.1 shows two resistors connected in series with a cell and three ammeters. reading = A1 A A reading = A3 reading = A2 A Fig. 10.1 (i) State the physical quantity that an ammeter measures. … [1] (ii) Indicate the correct statement about the readings A1, A2 and A3 on the ammeters in Fig. 10.1. Tick one box. A2 is greater than A1 A2 is less than A3 A1 is equal to A3 A1 is equal to (A2 + A3) [1] (b) (i) Draw a circuit diagram for a battery connected to two resistors in parallel. [2] (ii) State one advantage of connecting lamps in parallel. … [1] (c) Fig. 10.2 shows another circuit. component X Fig. 10.2 The circuit consists of a power supply, a lamp and component X. (i) Name component X in Fig. 10.2. … [1] (ii) Suggest one use of the circuit. … [1] (iii) Describe how to use component X and explain its effect on the circuit. … … … [2] [Total: 9]
9 marks
Mark scheme: 10(a)(i) (electric) current B1 10(a)(ii) tick in third box A1 is equal to A3 B1 10(b)(i) resistors in parallel B1 connected to battery AND correct circuit symbol for battery B1 10(b)(ii) same brightness / if one fails the rest are still lit / lamps can be switched off independently / same p.d. across owtte B1 10(c)(i) potential divider / potentiometer B1 10(c)(ii) dimmer / change light output / intensity B1 10(c)(iii) move the slider B1 varies p.d. (across lamp) B1
9 (a) The circuit diagrams in Fig. 9.1 and Fig. 9.2 each show two resistors connected to a battery. Fig. 9.1 shows two resistors connected in series. Fig. 9.2 shows two resistors connected in parallel. All the resistors have the same resistance. Ignore the resistance of the ammeters. 12 V 12 V A3 A1 A2 A4 A5 Fig. 9.1 Fig. 9.2 Compare the currents in the ammeters by completing the sentences. (i) The current in A1 is … the current in A2. [1] (ii) The current in A3 is … the current in A4. [1] (iii) The current in A4 is … the current in A5. [1] (iv) The current in A1 is … the current in A3. [1] (b) The lights in a room are connected in parallel with a power supply. State one advantage of connecting the lights in parallel. … [1] (c) The circuit diagram in Fig. 9.3 shows a resistor Q connected to a battery. A Q Fig. 9.3 The current in resistor Q is 0.048 A. The potential difference (p.d.) across resistor Q is 12 V. Calculate the resistance of resistor Q. Include the unit in your answer. resistance = … unit … [4] [Total: 9]
9 marks
Mark scheme: 9(a)(i) the same as B1 9(a)(ii) larger than B1 9(a)(iii) the same as B1 9(a)(iv) smaller than B1 9(b) same brightness / if one fails the rest are still lit / lamps can be switched off independently / same p.d. across owtte B1 9(c) V = I × R in any form (R =) V ÷ I C1 12 ÷ 0.048 C1 250 A1 Ω / ohms B1
8 (a) A student has a box containing objects made of different materials. The objects are: aluminium foil a silver ring an iron bar a plastic strip a glass lens (i) State which objects are made of electrically insulating materials. … [1] (ii) State which object is made of a magnetic material. … [1] (b) Fig. 8.1 shows two magnets, X and Y. The magnets are attracting each other. N attraction magnet X magnet Y Fig. 8.1 On magnet X, the N pole is labelled N. On Fig. 8.1, complete the labelling for the magnetic poles of each magnet. [1] (c) The student attaches a thin cotton thread to each of two light metal spheres, P and Q. She suspends the spheres as shown in Fig. 8.2. thin cotton support thread P Q Fig. 8.2 (i) The student puts a positive charge on sphere P only. Complete the diagram in Fig. 8.3 to show the positions of the spheres. support Fig. 8.3 [1] (ii) The student puts a positive charge on sphere P and on sphere Q. Complete the diagram in Fig. 8.4 to show the positions of the spheres. support Fig. 8.4 [2] [Total: 6]
6 marks
Mark scheme: 8(a)(i) plastic strip AND glass lens B1 8(a)(ii) iron bar B1 Question Answer Marks 8(b) end of magnet X labelled S (pole) AND end of magnet Y nearest magnet X labelled N (pole) AND other end is S (pole) B1 8(c)(i) spheres drawn closer together B1 8(c)(ii) spheres drawn further apart M1 both strings at an angle to vertical A1
9 A student has a battery-operated torch. Fig. 9.1 shows the electrical components in the torch circuit. battery plastic case + brass switch connecting strip lamp Fig. 9.1 (a) Using standard symbols, draw a circuit diagram for the circuit in the torch. [4] (b) When the torch is switched on, the potential difference (p.d.) across the lamp is 1.4 V and the current in the lamp is 0.26 A. (i) State the current in the brass connecting strip. current = … A [1] (ii) Calculate the resistance of the lamp. resistance = … Ω [3] [Total: 8]
8 marks
Mark scheme: 9(a) correct symbol for battery B1 correct symbol for switch B1 correct symbol for lamp B1 all 3 components connected in series B1 9(b)(i) 0.26 (A) B1 9(b)(ii) 5.4 () A3 1.4 ÷ 0.26 (C2) V= IR or (R =) V/I (C1)
9 The circuit in Fig. 9.1 shows two resistors, a battery, a voltmeter and a switch connected by metal wires. 12 V A B 10Ω 20Ω V Fig. 9.1 (a) State a quantity that a voltmeter measures. … [1] (b) The switch is closed. There is a current in the circuit. (i) State the name of the type of particle that flows in the metal wires. … [1] (ii) State the name of an instrument that measures electric current. … [1] (c) The reading on the voltmeter is 4.0 V. (i) Calculate the current in the 10 Ω resistor. current = … A [3] (ii) Determine the current in the 20 Ω resistor. current = … A [1] (iii) The 10 Ω resistor is replaced by a 15 Ω resistor and the 20 Ω resistor is also replaced by a 15 Ω resistor. State the effect, if any, on the current in the circuit. Explain your answer. … … [2] [Total: 9]
9 marks
Mark scheme: 9(a) electromotive force/e. m. f./ potential difference/p. d./ voltage B1 Question Answer Marks 9(b)(i) electron(s) B1 9(b)(ii) ammeter B1 9(c)(i) 0.4(0) (A) A3 4(.0) ÷ 10 (C2) (I = ) V ÷ R in any form (C1) 9(c)(ii) 0.4(0) (A) OR same as (c)(i) B1 9(c)(iii) no change/same M1 resultant/total/combined resistance does not change A1
8 Fig. 8.1 shows an electric circuit set up by a student. switch ammeter metal wire battery lamp 15 Ω resistor Fig. 8.1 (a) Using standard symbols, draw a circuit diagram for the student’s circuit. [4] (b) When the switch is closed there is a current in the circuit. State the name of the particles flowing in the metal wire. … [1] (c) The current in the 15 Ω resistor in Fig. 8.1 is 0.40 A when the switch is closed. Calculate the potential difference (p.d.) across the 15 Ω resistor. p.d. across resistor = … V [3] [Total: 8]
8 marks
Mark scheme: 8(a) 5 correct symbols for 3 marks B3 3 or 4 correct symbols for 2 marks 1 or 2 correct symbols for 1 mark any from: • correct symbol for battery • correct symbol for ammeter • correct symbol for lamp • correct symbol for fixed resistor • correct symbol for switch. all components drawn connected in a series circuit B1 8(b) electrons B1 8(c) 6(.0) (V) A3 0.40 15 C2 (V =) I R OR R = V / I C1
8 A student uses the circuit in Fig. 8.1 to find the resistance of a piece of iron wire. variable battery resistor ammeter voltmeter A B iron wire rule Fig. 8.1 (a) Complete Fig. 8.2 to show the circuit diagram for the arrangement shown in Fig. 8.1. The piece of iron wire is shown as the thicker line between the points A and B. 4.5 V A B [3] Fig. 8.2 (b) The reading on the voltmeter is 1.56 V. The reading on the ammeter is 0.112 A. Calculate the resistance of the iron wire. Include the unit in your answer. resistance = … unit … [4] [Total: 7]
7 marks
Mark scheme: 8(a) ammeter, battery and test wire in complete series circuit B1 voltmeter in parallel with AB B1 correct circuit symbols for ammeter AND voltmeter B1 8(b) 14 A3 1.56 ÷ 0.112 (C2) (R =) V ÷ I in any form OR V = I R (C1) / ohm(s) B1
9 Fig. 9.1 shows a transformer. An a.c. voltmeter is connected to the output of the secondary coil. core 10 V a.c. V voltmeter number of number of primary turns = 200 secondary turns = 800 Fig. 9.1 (a) State the meaning of a.c. … [1] (b) State the name of the type of transformer shown. … [1] (c) State a suitable material for the core of the transformer in Fig. 9.1. … [1] (d) Using the information in Fig. 9.1, calculate the reading on the voltmeter. reading on voltmeter = … V [3] (e) The 10 V a.c. power supply is replaced by a 10 V d.c. battery. State the reading on the voltmeter. reading on voltmeter = … V [1] [Total: 7]
7 marks
Mark scheme: 9(a) alternating (current) B1 9(b) step-up B1 9(c) (soft) iron B1 9(d) 40 (V) A3 (VS =) 800 / 200 10 (C2) VP / VS = NP / NS in any form (C1) 9(e) zero B1
8 (a) A student uses a dry cloth to rub a plastic rod. State how the plastic rod gains a positive charge from friction between the cloth and the rod. … … … [2] (b) Three balls, P, Q and R, are electrically charged. The balls are suspended by threads of insulating material. Fig. 8.1 shows the arrangement. insulated thread P + Q R Fig. 8.1 The charge on ball P is positive. State the charge on ball Q and the charge on ball R. ball Q … ball R … [2] (c) The student connects ball P to earth with a copper wire. Charges from the earth flow in the copper wire to ball P. State the name of the electrically charged particles moving in the copper wire. … [1] [Total: 5]
5 marks
Mark scheme: 8(a) negative charges OR electrons B1 move from rod OR move to cloth B1 8(b) (ball Q is) positive B1 (ball R is) negative B1 8(c) (free) electrons B1
9 Fig. 9.1 shows an electric kettle. Fig. 9.1 (a) (i) The power input of the kettle is 1.5 kW. The potential difference of the mains electrical supply for the kettle is 220 V. Calculate the current in the kettle when it is switched on. current in kettle = … A [4] (ii) The 1.5 kW kettle is used for a total of 4.0 hours. The cost of 1.0 kW h of electrical energy is 14 pennies (p). Calculate the cost of the energy used by the kettle in 4.0 hours. cost of energy = … p [3] (b) Fig. 9.2 shows an overloaded extension lead. Fig. 9.2 Explain the danger of connecting too many plugs to an extension lead. … … … [2] [Total: 9]
9 marks
Mark scheme: 9(a)(i) (I =) 6.8 (A) A4 (I =) 1500 ÷ 220 (C2) P = I V OR (I =) P ÷ V (C1) 1.5 kW = 1500 W (C1) 9(a)(ii) (cost of energy =) 84 (p) A3 (cost of energy =) 1.5 4(.0) 14 (C2) (cost of energy =) power time cost of 1 kW h (C1) OR number of kW h cost of 1 kW h 9(b) large current (in extension lead / socket) B1 (can cause) overheating / fire B1
9 Fig. 9.1 shows a series circuit. Two of the components in the circuit are labelled. power supply lamp Fig. 9.1 (a) State the name of two other components in the circuit. 1 … 2 … [2] (b) The current in the lamp is 0.40 A. The potential difference (p.d.) across the lamp is 6.0 V. Calculate the power dissipated in the lamp. power = … W [3] (c) Draw on Fig. 9.1 to show a lamp connected in parallel with the lamp in the circuit. Use the correct symbol. [1] [Total: 6]
6 marks
Mark scheme: 9(a) any two from: switch ammeter variable resistor B2 9(b) (power =) 2.4 (W) A3 (power =) 0.4(0) 6(.0) (C2) (power =) I V (C1) 9(c) lamp symbol drawn in parallel with lamp in circuit B1
8 A student uses the circuit in Fig. 8.1 to measure the resistance of the heater in the circuit. variable resistor heater Fig. 8.1 (a) The symbols for the meters in Fig. 8.1 are incomplete. Complete the symbols for the two meters by writing in the circles in Fig. 8.1. [2] (b) The current in the heater is 1.4 A and the potential difference (p.d.) across the heater is 8.0 V. Calculate the resistance of the heater. resistance = … Ω [3] (c) The heater is switched on for 30 s. The current in the heater is 1.4 A and the p.d. across it is 8.0 V. Calculate the electrical energy transferred by the heater during the 30 s. energy transferred = … J [3] [Total: 8]
8 marks
Mark scheme: 8(a) ammeter symbol correct B1 voltmeter symbol correct B1 8(b) (R =) 5.7 () A3 (R =) 8(.0) ÷ 1.4 (C2) V = IR in any form OR (R =) V ÷ I (C1) 8(c) (E =) 340 (J) A3 (E =) 8(.0) 1.4 30 (C2) (E =) V I t (C1)
8 (a) Fig. 8.1 shows the electrical symbols for some circuit components. Draw a line from each electrical symbol to the name of the circuit component it represents. electrical symbol circuit component fuse lamp heater thermistor Fig. 8.1 [3] (b) Fig. 8.2 shows a circuit including a battery, a fixed resistor R and an ammeter. A R Fig. 8.2 The reading on the ammeter is 0.38 A. The potential difference across the fixed resistor R is 12 V. (i) Calculate the resistance of the fixed resistor R. resistance = … Ω [3] (ii) Calculate the electrical power transferred in the fixed resistor R. Include the unit. power transferred = … unit … [4] [Total: 10]
10 marks
Mark scheme: 8(a) B1 B1 B1 8(b)(i) (R =) V ÷ I in any form C1 12 ÷ 0.38 C1 32 () A1 8(b)(ii) (P =) IV in any form C1 12 0.38 C1 4.6 A1 W OR watts B1
6 Fig. 6.1 shows four wind turbines. air ground Fig. 6.1 (a) Describe how a wind turbine generates electrical power. … … … [3] (b) The electrical power output of a wind turbine is 624 kW. The output current is 520 A. Calculate the output voltage of the wind turbine. output voltage = … V [4] (c) For transmission, the output voltage is increased to 132 kV. State two advantages of transmitting electrical power at high voltage. 1 … 2 … [2] [Total: 9]
9 marks
Mark scheme: 6(a) KE of wind B1 rotates / turns / spins turbine OR blades B1 (turbine) turns / spins / rotates generator B1 6(b) (output voltage =) 1200 (V) OR 1.2 kV A4 (V =) 624 000 ÷ 520 (C3) conversion: 624 kW = 624 000 (W) (C1) power = I V OR (V =) P ÷ I (C1) 6(c) any two from: B2 greater efficiency as lower current (is used) (so) reduces power / energy losses thinner cables can be used (so reducing costs) OR pylons further apart idea of increased distance of transmission (of electrical power)
9 Fig. 9.1 shows an electric water heater. The heater is connected to the mains electrical supply. water heater plastic cover Fig. 9.1 Fig. 9.2 shows the electrical safety label for the heater. Water Heater Model xxxxxx1 230 V (volts) 720 W (watts) Disconnect from the mains supply before removing the plastic cover. Fig. 9.2 (a) (i) Explain why the safety label states, ‘Disconnect from the mains supply before removing the plastic cover.’ … … [1] (ii) The heater is switched on. Calculate the current in the heater. Use the information in Fig. 9.2. current = … A [3] (b) Table 9.1 shows some electrical meter readings for the water heater. Table 9.1 date meter reading / kW h 1st October 3771 31st October 3797 Electrical energy costs 18 cents per kW h. Calculate the cost of using the heater from 1st October until 31st October. cost = … cents [3] [Total: 7]
7 marks
Mark scheme: 9(a)(i) (prevent) risk of (electric) shock / electrocution B1 9(a)(ii) 3.1 (A) A3 720/230 (C2) (current =) power / voltage OR (I =) P / V (C1) 9(b) 468 (cents) A3 26 18 (C2) (cost =) number of kWh cost per kWh (C1) number of kWh = 3797 – 3771 OR 26 (C1)
7 Two identical resistors, R1 and R2, are connected to a 24 V battery, as shown in Fig. 7.1. 24 V R1 R2 Fig. 7.1 The value of each resistor is 50 Ω. (a) Calculate the combined resistance of R1 and R2 when they are connected as shown in Fig. 7.1. combined resistance = … Ω [1] (b) Show that the current in the circuit is approximately 0.25 A. [3] (c) Determine the potential difference (p.d.) across R1. p.d. = … V [1] (d) Calculate the power transferred in R1. power = … W [3] (e) A student connects R1, R2 and the battery to make a different circuit. The resistors R1 and R2 are connected so their combined resistance is as small as possible. Draw a circuit diagram to show how R1 and R2 are connected to the battery. [1] [Total: 9]
9 marks
Mark scheme: 7(a) 100 () B1 7(b) 0.24 (A) B1 24 / 100 (current =) voltage / resistance B1 Need to see zone (a) B1 7(c) 12 (V) B1 7(d) 3(.0) (W) OR 2.9 (W) A3 0.25 12 (C2) (power =) current voltage OR (P =) V × I (C1) 7(e) (two) resistors in parallel B1
9 (a) Describe what is meant by alternating current (a.c.). … [1] (b) A teacher demonstrates how a loudspeaker works by using the equipment shown in Fig. 9.1. direction of vibration of paper cone strong magnet N S coil paper cone Fig. 9.1 There is an alternating current in the coil. The paper cone and coil vibrate as shown in Fig. 9.1. (i) Explain why the paper cone vibrates. Use your ideas about magnetism. … … … … [3] (ii) When the paper cone vibrates, the teacher hears a sound. Suggest a value for the frequency of the alternating current. Include the unit. frequency = … unit … [2] [Total: 6]
6 marks
Mark scheme: 9(a) (current repeatedly) changes direction B1 9(b)(i) any three from: B3 magnetic effect of current coil becomes an electromagnet attracted to magnet repelled by magnet 9(b)(ii) any number(s) between 20 and 20 000 B1 Hz / kHz B1
9 A student connects the electrical circuit shown in Fig. 9.1. switch ammeter metal wire battery lamp thermistor Fig. 9.1 (a) Fig. 9.2 shows part of the circuit diagram for the circuit in Fig. 9.1. Fig. 9.2 Complete the circuit diagram in Fig. 9.2 to represent the circuit in Fig. 9.1. Use standard electrical symbols. [4] (b) The potential difference across the lamp is 5.4 V and the current in the lamp is 0.20 A. (i) Calculate the resistance of the lamp. resistance = … Ω [3] (ii) The lamp is switched on for 30 s. Calculate the energy transferred in the lamp during this time. energy transferred = … J [3] (c) The student increases the temperature of the thermistor. State and explain what happens to the current in the circuit. … … [2] [Total: 12]
12 marks
Mark scheme: 9(a) correct symbol for: ammeter B1 lamp B1 thermistor B1 symbols connected in series circuit B1 9(b)(i) 27 () A3 5.4 ÷ 0.2(0) (C2) (R=) V ÷ I OR V = I R or in any form (C1) 9(b)(ii) 32 (J) A3 (E =) 5.4 0.2 30 (C2) (E=) VItOR P t OR I2 R t (C1) 9(c) current increases B1 (because) resistance (of thermistor) decreases B1
8 Fig. 8.1 shows an arrangement for making an electromagnet. The electromagnet consists of a solenoid and a core. 12 V variable resistor A X direction of current in solenoid core of electromagnet Fig. 8.1 (a) (i) The electromagnet is a temporary magnet. State one material which is suitable for the core of the electromagnet. … [1] (ii) The battery is made from cells connected in series. Each cell in the battery has an electromotive force (e.m.f.) of 1.5 V. Calculate the number of cells in the battery in Fig. 8.1. number of cells = … [2] (b) The switch is closed. The direction of the current in the solenoid is shown in Fig. 8.1. (i) There is a magnetic field around the electromagnet. State the name of a piece of equipment that can show the direction of a magnetic field. … [1] (ii) State the name of the pole labelled X on the core of the electromagnet. … [1] (c) The resistance of the solenoid is 8.0 Ω. The current in the solenoid is 1.2 A. Calculate the potential difference (p.d.) across the solenoid. p.d. = … V [3] [Total: 8]
8 marks
Mark scheme: 8(a)(i) (soft) iron B1 8(a)(ii) 8 (cells) A2 (number of cells =) 12 ÷ 1.5 OR battery e.m.f ÷ e.m.f. of 1 cell (C1) 8(b)(i) (plotting) compass B1 8(b)(ii) north OR N (pole) B1 8(c) (V =) 9.6 (V) A3 (V =) 8(.0) 1.2 (C2) R = V ÷ I in any form OR (V =) I R (C1)
7 A battery, a lamp L, a fixed resistor R and a switch S are connected as shown in Fig. 7.1. 6.0 V R L S Fig. 7.1 (a) The potential difference (p.d.) across lamp L is 4.8 V and the current in lamp L is 0.40 A. Calculate the resistance of lamp L. resistance = … Ω [3] (b) State and explain how closing switch S affects the brightness of lamp L. … … … … [3] [Total: 6]
6 marks
Mark scheme: 7(a) A3 4.8 / 0.4 (C2) V = IR OR (R = ) V / I (C1) 7(b) (lamp is) brighter OR (brightness) increases B1 resistance of wire and resistor in parallel is less than resistance of wire owtte OR voltage across lamp / L increases B1 (so) current in lamp increases B1
8 Fig. 8.1 shows part of a circuit for measuring the resistance of a lamp. A Fig. 8.1 (a) Draw on Fig. 8.1 to show how to connect a voltmeter to measure the potential difference across the lamp. Use the electrical symbol for a voltmeter. [2] (b) The current in the lamp is 0.41 A and the potential difference across the lamp is 12 V. Calculate the resistance of the lamp. resistance = … Ω [3] (c) Calculate the electrical power transferred in the lamp. Include the unit. power transferred = … unit … [4] [Total: 9]
9 marks
Mark scheme: 8(a) correct symbol B1 voltmeter in parallel with lamp B1 8(b) 29 () A3 12 0.41 (C2) (R =) V I OR V = I R in any form (C1) 8(c) 4.9 A3 0.41 12 OR 0.412 29 (C2) (P =) I V in any form OR (P =) I 2 R (C1) W B1
9 A student tests various materials to determine whether they are electrical conductors or insulators. The student uses the circuit shown in Fig. 9.1. 6 V battery switch A X Y Fig. 9.1 (a) The student connects a piece of tin metal between X and Y. Describe how the student can determine whether tin is an electrical conductor. … … … [2] (b) Describe electrical conduction in a metal. Use your ideas about electrons in your answer. … … … … [3] [Total: 5]
5 marks
Mark scheme: 9(a) either: B2 close switch (see if) lamp lights OR reading on ammeter OR lamp lights OR reading on ammeter (so material is (a)) conductor OR lamp lights OR reading on ammeter (so must have electric) current in tin 9(b) mention of free OR de-localised electrons (in the metal) B1 able to move from one atom / ion / particle to another B1 when p.d. OR voltage (applied across the metal / material) B1
8 (a) A student connects a circuit with two lamps and three switches, S1, S2 and S3, as shown in Fig. 8.1. 6.0 V S1 S3 S2 Fig. 8.1 (i) The student switches on one lamp. State which switches the student closes to switch on only one lamp. … [1] (ii) The student opens all the switches then switches on two lamps. State which switches the student closes to switch on two lamps. … [1] (b) Fig. 8.2 shows the manufacturer’s information for one of the lamps. voltage = 6.0 V current = 0.53 A Fig. 8.2 Calculate the resistance of the lamp when it is connected to a 6.0 V power source. resistance = … Ω [3] (c) Calculate the electrical power transferred in the lamp when it is connected to a 6.0 V power source. Include the unit. power transferred = … unit … [4] [Total: 9]
9 marks
Mark scheme: 8(a)(i) Switch S1 AND Switch S2 B1 8(a)(ii) Switch S1 AND Switch S3 B1 8(b) 11() A3 6(.0) 0.53 (C2) V = I R OR (R =) V I (C1) 8(c) 3.2 A3 0.53 x 6(.0) (C2) (P =) I V (C1) W B1
9 A student set up the electrical circuit that is shown in Fig. 9.1. switch ammeter metal wire battery lamp voltmeter variable resistor Fig. 9.1 (a) Fig. 9.2 shows part of the circuit diagram for the circuit in Fig. 9.1. A battery switch ammeter Fig. 9.2 Complete the circuit diagram in Fig. 9.2 to represent the circuit in Fig. 9.1. Use standard circuit symbols. [4] (b) The potential difference (p.d.) across the lamp is 11 V and the current in the lamp is 0.44 A. Calculate the resistance of the lamp. resistance = … Ω [3] (c) The student moves the sliding contact from position A to position B, as shown in Fig. 9.3. metal bar sliding contact in position A connection to lamp connection to battery coil of resistance wire metal bar sliding contact in position B connection to lamp connection to battery coil of resistance wire Fig. 9.3 State and explain any effect on the current in the circuit when the sliding contact is moved from position A to position B. … … … … [2] [Total: 9]
9 marks
Mark scheme: 9(a) correct symbol for: B1 voltmeter lamp B1 variable resistor B1 lamp and variable resistor connected in series circuit AND B1 voltmeter in parallel with lamp 9(b) 25 () A3 11 ÷ 0.44 (C2) (R =) V ÷ I or V = I R or in any form (C1) 9(c) current increases B1 (because) resistance (of variable resistor) decreases OR there is less resistance wire (in the circuit / for current to move B1 through)
8 Fig. 8.1 shows the circuit diagram for a 16 Ω resistor and an 8.0 Ω resistor connected to a 6.0 V battery. 6.0 V 16 Ω 8.0 Ω Fig. 8.1 (a) Calculate the combined resistance of the two resistors shown in Fig. 8.1. combined resistance = … Ω [2] (b) The potential difference across the 8.0 Ω resistor is 2.0 V. Calculate the current in the resistor. current = … A [3] (c) State the name of the particles that move through the metal wires when there is a current in the circuit. … [1] (d) A student measures the potential difference across the 16 Ω resistor by using a meter. On Fig. 8.1, draw the electrical symbol for this meter and its connections. [2] [Total: 8]
8 marks
Mark scheme: 8(a) 24 () A2 (combined resistance =) R1 + R2 OR 16 + 8(.0) C1 8(b) (I =) 0.25 (A) A3 (I =) 2(.0) ÷ 8(.0) C2 V = IR in any form OR (I =) V ÷ R C1 8(c) electrons B1 8(d) voltmeter correctly connected across 16 resistor A2 correct voltmeter symbol in wrong place OR incorrect meter connected across 16 resistor C1
9 Fig. 9.1 shows a router. The router emits Wi-Fi signals. router Fig. 9.1 (a) The power input to the router circuit is 9.0 W. The potential difference across the router circuit is 12 V. Calculate the current in the router circuit. current in router circuit = … A [3] (b) The energy used by the router each hour is 0.0090 kW h. One unit (kW h) of energy costs 50 cents. Calculate the cost of using the router for 24 hours. cost for 24 hours = … cents [3] (c) The router uses a transformer. The number of turns Np on the primary coil of the transformer is 3600. The primary voltage Vp to the transformer is 240 V. The secondary voltage Vs of the transformer is 12 V. Calculate the number of turns Ns on the secondary coil of the transformer. number of turns on secondary coil = … [3] (d) The mains plug for the router includes a fuse that protects the router. Explain how a fuse works. … … … [3] [Total: 12]
12 marks
Mark scheme: 9(a) (current =) 0.75 (A) A3 (current =) 9 ÷ 12 C2 power = IV OR (I =) P ÷ V C1 9(b) 11 (cents) A3 (cost =) 0.009(0) 24 50 OR 0.216 50 OR 0.009 1200 OR 0.45 24 C2 (cost =) (energy in) kW h (number of) hours cost (of one unit) C1 9(c) (Ns =) 180 A3 (Ns =) {12 3600} ÷ 240 OR (Ns =) 3600 ÷ 20 OR 240 ÷ 12 = 3600 ÷ Ns C2 Vs ÷ Vp = Ns ÷ Np C1 9(d) any three from: B3 • idea of large current (in fuse or any part of circuit) • (large current causes) heating in fuse • idea that fuse is made from low melting point wire • fuse / (fuse) wire melts • (and) idea disconnects / isolates (router / wires / circuit) from supply / mains
8 Fig. 8.1 shows a mains-powered electric fan heater fixed on a bathroom wall. electric fan heater pull cord Fig. 8.1 The pull cord switches the fan heater on and off. (a) Suggest why a pull cord is safer than a push switch for a fan heater in a bathroom. … … [1] (b) Fig. 8.2 shows the electric circuit for the fan heater. switch mains supply X heater M Y Fig. 8.2 State the name for component X and for component Y. X … Y … [2] (c) Fig. 8.3 shows the information label on the fan heater. power = 2000 W voltage = 230 V Fig. 8.3 Calculate the current supplied to the fan heater. current = … A [3] [Total: 6]
6 marks
Mark scheme: 8(a) reduces risk of electric shock / electrocution OR reference to damp conditions B1 8(b) symbol X: fuse B1 symbol Y: motor B1 8(c) 8.7 (A) A3 2000 ÷ 230 C2 power = current voltage OR (current =) power ÷ voltage C1
8 Fig. 8.1 shows a mains-powered electric fan heater fixed on a bathroom wall. electric fan heater pull cord Fig. 8.1 The pull cord switches the fan heater on and off. (a) Suggest why a pull cord is safer than a push switch for a fan heater in a bathroom. … … [1] (b) Fig. 8.2 shows the electric circuit for the fan heater. switch mains supply X heater M Y Fig. 8.2 State the name for component X and for component Y. X … Y … [2] (c) Fig. 8.3 shows the information label on the fan heater. power = 2000 W voltage = 230 V Fig. 8.3 Calculate the current supplied to the fan heater. current = … A [3] [Total: 6]
6 marks
Mark scheme: 8(a) reduces risk of electric shock / electrocution OR reference to damp conditions B1 8(b) symbol X: fuse B1 symbol Y: motor B1 8(c) 8.7 (A) A3 2000 ÷ 230 C2 power = current voltage OR (current =) power ÷ voltage C1
7 (a) A student has six metal bars. The bars are all the same size. Four of the bars are magnets, one is a bar of unmagnetised steel and the other is a bar of copper metal. The student arranges the bars in pairs with a small gap between them as shown in Fig. 7.1. For each pair of bars in Fig. 7.1, state whether a force acts between the bars. Choose from these phrases: attractive force no force repulsive force Each phrase may be used once, more than once or not at all. For each pair of bars, write your answer on the dotted line. N S N S pair 1 … N S unmagnetised steel pair 2 … N S copper pair 3 … Fig. 7.1 [2] (b) Describe what is meant by a magnetic field. … … [1] (c) In another experiment, the student compares different electrically conducting and electrically insulating materials. (i) State the name of one electrically conducting material and the name of one electrically insulating material. electrically conducting material … electrically insulating material … [2] (ii) Explain how electrical conducting materials allow a current to pass. … … [2] [Total: 7]
7 marks
Mark scheme: 7(a) (pair 1) attractive force B2 (pair 2) attractive force (pair 3) no force 7(b) region/area in which a magnet(ic pole) experiences a force B1 OR region/area in which a magnetic material experiences a force 7(c)(i) name of an electrically conducting material B1 name of an electrically insulating material B1 7(c)(ii) idea (they have) electrons/charges/ions M1 (that) can move (from ion to ion OR freely in conducting materials) A1
8 A television uses many electrical components. (a) The potential difference (voltage) across a component is 72 V. The current in the component is 0.024 A. Calculate the resistance of the component. resistance = … Ω [3] (b) The television uses a transformer. The input voltage (Vp) to the transformer is 120 V. The number of turns (Np) on the input coil is 560. The number of turns (Ns) on the output coil is 70. Calculate the output voltage (Vs) of the transformer. output voltage = … V [3] (c) The potential difference (voltage) across a resistor is 64 V. The current in the resistor is 2.2 mA. Calculate the power of the resistor. power = … W [4] (d) The energy used by the television in one hour is 0.14 kWh. The cost of one kWh of energy is 36 cents. Calculate the cost of using the television for 6.0 hours. cost for 6 hours = … cents [3] [Total: 13]
13 marks
Mark scheme: 8(a) 3000 () A3 72 / 0.024 (C2) V = IR OR (R = )V / I (C1) 8(b) (output voltage Vs =) 15 (V) A3 Vs / 120 = 70 / 560 OR (Vs =) (70 / 560) 120 (C2) Vs / Vp = Ns / Np in any form (C1) 8(c) (power = ) 0.14 (W) A4 (power = ) 2.2 10-3 64 (C3) (power = ) I V (C1) 2.2 (mA) = 0. 0022 (A) OR 2.2 x 10-3 (A) (C1) 8(d) 30 (cents) A3 (cost = ) 0.14 6(.0) 36 OR 0.84 36 OR 0.14 216 OR 5.04 6 (C2) (cost = ) (energy in) kW h (number of) hours cost (of one unit) (C1)
7 Fig. 7.1 shows a lamp connected in series with four 1.5 V cells and an ammeter. A voltmeter is connected across the lamp. A V Fig. 7.1 (a) Determine the potential difference across the four cells. potential difference = … V [1] (b) (i) The reading on the ammeter is 0.64 A. The reading on the voltmeter is 5.8 V. Calculate the resistance of the lamp. resistance of the lamp = … Ω [3] (ii) Calculate the energy transferred by the lamp in 140 s. energy transferred = … J [3] (c) On Fig. 7.1, draw a second lamp so that there is a bigger current in the ammeter when the second lamp is connected. [1] [Total: 8]
8 marks
Mark scheme: 7(a) 6(.0) (V) B1 7(b)(i) 9.1 () A3 5.8 ÷ 0.64 C2 (resistance =) potential difference ÷ current C1 7(b)(ii) 520 (J) A3 5.8 0.64 140 or 3.712 140 or 5.8 89.6 or 0.64 812 C2 (energy transferred =) potential difference current time C1 7(c) lamp in parallel with original lamp B1
7 (a) A student is making a torch. (i) The torch needs a potential difference (p.d) of 6.0 V. The electromotive force (e.m.f.) of each cell for the torch is 1.5 V. State the number of cells that the torch needs. number of cells = … [1] (ii) The student has the following components for the electrical part of the torch: a 6.0 V lamp a switch several 1.5 V cells connecting wire Draw a circuit diagram to show how the components are connected in series to make the torch. Use standard circuit symbols. [3] (b) The p.d. across the lamp is 6.0 V. The current in the lamp is 0.25 A (i) Calculate the resistance of the lamp. resistance = … Ω [3] (ii) Calculate the power of the lamp. power = … W [3] [Total: 10]
10 marks
Mark scheme: 7(a)(i) 4 (cells) B1 7(a)(ii) three (cell (s) / battery, lamp and switch) circuit symbols correct A2 one or two (from cell(s) / battery, lamp and switch) circuit symbols correct C1 a complete circuit with cell (s), lamp and switch in series B1 7(b)(i) 24 () A3 6(.0) ÷ 0.25 C2 (resistance =) potential difference ÷ current C1 7(b)(ii) 1.5 (W) A3 6(.0) 0.25 C2 (power =) potential difference current C1