18.1· 157 questions · 157 marks · 188 min · 2005–2025· Multiple choice
Every Cambridge A Level Chemistry Paper 1 question on carboxylic acids, laid out as 47 A4 pages with the mark scheme below. Nothing is left out. Free to read, no account.



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47 / 47Answers below. Sit the paper first if you are practising.
Pastlit
Chemistry 9701 · Carboxylic acids — Paper 1
A Level · topical answer key — answer key (teacher use)
Question
Answer
Marks
Pastlit
Chemistry 9701 · Carboxylic acids — Paper 1
A Level · topical answer key — answer key (teacher use)
Question
Answer
Marks
Pastlit
Chemistry 9701 · Carboxylic acids — Paper 1
A Level · topical answer key — answer key (teacher use)
Question
Answer
Marks
Pastlit
Chemistry 9701 · Carboxylic acids — Paper 1
A Level · topical answer key — answer key (teacher use)
Question
Answer
Marks
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| 1 | D | 1 | 9701/11 Oct/Nov 2005 |
| 2 | B | 1 | 9701/11 May/June 2006 |
| 3 | C | 1 | 9701/11 Oct/Nov 2007 |
| 4 | C | 1 | 9701/11 Oct/Nov 2007 |
| 5 | D | 1 | 9701/11 May/June 2008 |
| 6 | C | 1 | 9701/11 May/June 2008 |
| 7 | A | 1 | 9701/11 May/June 2008 |
| 8 | C | 1 | 9701/11 Oct/Nov 2008 |
| 9 | A | 1 | 9701/11 May/June 2009 |
| 10 | B | 1 | 9701/11 Oct/Nov 2009 |
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| 15 | A | 1 | 9701/11 Oct/Nov 2010 |
| 16 | D | 1 | 9701/11 Oct/Nov 2010 |
| 17 | B | 1 | 9701/11 Oct/Nov 2010 |
| 18 | C | 1 | 9701/12 Oct/Nov 2010 |
| 19 | A | 1 | 9701/13 Oct/Nov 2010 |
| 20 | D | 1 | 9701/13 Oct/Nov 2010 |
| 21 | D | 1 | 9701/12 May/June 2011 |
| 22 | C | 1 | 9701/13 May/June 2011 |
| 23 | A | 1 | 9701/13 May/June 2011 |
| 24 | see sheet | 1 | 9701/12 Oct/Nov 2011 |
| 25 | C | 1 | 9701/11 May/June 2012 |
| 26 | C | 1 | 9701/12 May/June 2012 |
| 27 | C | 1 | 9701/13 May/June 2012 |
| 28 | B | 1 | 9701/11 Oct/Nov 2012 |
| 29 | D | 1 | 9701/11 Oct/Nov 2012 |
| 30 | B | 1 | 9701/12 Oct/Nov 2012 |
| 31 | D | 1 | 9701/12 Oct/Nov 2012 |
| 32 | D | 1 | 9701/13 Oct/Nov 2012 |
| 33 | C | 1 | 9701/13 Oct/Nov 2012 |
| 34 | B | 1 | 9701/11 May/June 2013 |
| 35 | C | 1 | 9701/11 May/June 2013 |
| 36 | D | 1 | 9701/12 May/June 2013 |
| 37 | C | 1 | 9701/13 May/June 2013 |
| 38 | A | 1 | 9701/13 May/June 2013 |
| 39 | C | 1 | 9701/11 Oct/Nov 2013 |
| 40 | B | 1 | 9701/11 Oct/Nov 2013 |
| 41 | A | 1 | 9701/11 Oct/Nov 2013 |
| 42 | C | 1 | 9701/12 Oct/Nov 2013 |
| 43 | B | 1 | 9701/12 Oct/Nov 2013 |
| 44 | B | 1 | 9701/13 Oct/Nov 2013 |
| 45 | A | 1 | 9701/12 May/June 2014 |
| 46 | D | 1 | 9701/13 May/June 2014 |
| 47 | B | 1 | 9701/13 May/June 2014 |
| 48 | C | 1 | 9701/11 Oct/Nov 2014 |
| 49 | C | 1 | 9701/12 Oct/Nov 2014 |
| 50 | B | 1 | 9701/12 May/June 2015 |
| 51 | D | 1 | 9701/12 May/June 2015 |
| 52 | C | 1 | 9701/12 May/June 2015 |
| 53 | A | 1 | 9701/12 May/June 2015 |
| 54 | see sheet | 1 | 9701/12 Oct/Nov 2015 |
| 55 | C | 1 | 9701/12 Feb/March 2016 |
| 56 | C | 1 | 9701/12 Feb/March 2016 |
| 57 | A | 1 | 9701/12 Feb/March 2016 |
| 58 | C | 1 | 9701/11 May/June 2016 |
| 59 | A | 1 | 9701/12 May/June 2016 |
| 60 | A | 1 | 9701/11 Oct/Nov 2016 |
| 61 | D | 1 | 9701/11 Oct/Nov 2016 |
| 62 | A | 1 | 9701/13 Oct/Nov 2016 |
| 63 | D | 1 | 9701/13 Oct/Nov 2016 |
| 64 | D | 1 | 9701/12 May/June 2017 |
| 65 | A | 1 | 9701/12 May/June 2017 |
| 66 | D | 1 | 9701/12 May/June 2017 |
| 67 | A | 1 | 9701/13 May/June 2017 |
| 68 | A | 1 | 9701/11 Oct/Nov 2017 |
| 69 | B | 1 | 9701/11 Oct/Nov 2017 |
| 70 | B | 1 | 9701/12 Oct/Nov 2017 |
| 71 | A | 1 | 9701/13 Oct/Nov 2017 |
| 72 | B | 1 | 9701/13 Oct/Nov 2017 |
| 73 | A | 1 | 9701/11 May/June 2018 |
| 74 | C | 1 | 9701/11 May/June 2018 |
| 75 | C | 1 | 9701/12 May/June 2018 |
| 76 | D | 1 | 9701/11 Oct/Nov 2018 |
| 77 | B | 1 | 9701/11 Oct/Nov 2018 |
| 78 | D | 1 | 9701/13 Oct/Nov 2018 |
| 79 | B | 1 | 9701/13 Oct/Nov 2018 |
| 80 | A | 1 | 9701/12 Feb/March 2019 |
| 81 | D | 1 | 9701/12 Feb/March 2019 |
| 82 | C | 1 | 9701/12 Feb/March 2019 |
| 83 | C | 1 | 9701/12 Feb/March 2019 |
| 84 | C | 1 | 9701/11 May/June 2019 |
| 85 | C | 1 | 9701/11 May/June 2019 |
| 86 | D | 1 | 9701/12 May/June 2019 |
| 87 | B | 1 | 9701/12 May/June 2019 |
| 88 | C | 1 | 9701/12 May/June 2019 |
| 89 | A | 1 | 9701/13 May/June 2019 |
| 90 | B | 1 | 9701/11 Oct/Nov 2019 |
| 91 | D | 1 | 9701/11 Oct/Nov 2019 |
| 92 | C | 1 | 9701/12 Oct/Nov 2019 |
| 93 | B | 1 | 9701/13 Oct/Nov 2019 |
| 94 | D | 1 | 9701/13 Oct/Nov 2019 |
| 95 | A | 1 | 9701/12 Feb/March 2020 |
| 96 | C | 1 | 9701/11 May/June 2020 |
| 97 | A | 1 | 9701/11 May/June 2020 |
| 98 | A | 1 | 9701/12 May/June 2020 |
| 99 | A | 1 | 9701/12 May/June 2020 |
| 100 | C | 1 | 9701/13 May/June 2020 |
| 101 | C | 1 | 9701/13 May/June 2020 |
| 102 | D | 1 | 9701/11 Oct/Nov 2020 |
| 103 | B | 1 | 9701/11 Oct/Nov 2020 |
| 104 | D | 1 | 9701/13 Oct/Nov 2020 |
| 105 | D | 1 | 9701/12 Feb/March 2021 |
| 106 | C | 1 | 9701/12 Feb/March 2021 |
| 107 | B | 1 | 9701/12 Feb/March 2021 |
| 108 | C | 1 | 9701/11 May/June 2021 |
| 109 | B | 1 | 9701/12 May/June 2021 |
| 110 | D | 1 | 9701/12 May/June 2021 |
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| 113 | C | 1 | 9701/11 Oct/Nov 2021 |
| 114 | B | 1 | 9701/12 Oct/Nov 2021 |
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| 116 | C | 1 | 9701/13 Oct/Nov 2021 |
| 117 | B | 1 | 9701/11 May/June 2022 |
| 118 | C | 1 | 9701/12 May/June 2022 |
| 119 | D | 1 | 9701/11 Oct/Nov 2022 |
| 120 | C | 1 | 9701/11 Oct/Nov 2022 |
| 121 | C | 1 | 9701/11 Oct/Nov 2022 |
| 122 | D | 1 | 9701/12 Oct/Nov 2022 |
| 123 | A | 1 | 9701/12 Oct/Nov 2022 |
| 124 | D | 1 | 9701/13 Oct/Nov 2022 |
| 125 | C | 1 | 9701/13 Oct/Nov 2022 |
| 126 | C | 1 | 9701/13 Oct/Nov 2022 |
| 127 | B | 1 | 9701/13 May/June 2023 |
| 128 | C | 1 | 9701/11 Oct/Nov 2023 |
| 129 | C | 1 | 9701/12 Oct/Nov 2023 |
| 130 | C | 1 | 9701/12 Oct/Nov 2023 |
| 131 | D | 1 | 9701/12 Feb/March 2024 |
| 132 | D | 1 | 9701/12 Feb/March 2024 |
| 133 | B | 1 | 9701/12 Feb/March 2024 |
| 134 | C | 1 | 9701/12 Feb/March 2024 |
| 135 | D | 1 | 9701/11 May/June 2024 |
| 136 | D | 1 | 9701/11 May/June 2024 |
| 137 | D | 1 | 9701/12 May/June 2024 |
| 138 | D | 1 | 9701/13 May/June 2024 |
| 139 | D | 1 | 9701/11 Oct/Nov 2024 |
| 140 | D | 1 | 9701/11 Oct/Nov 2024 |
| 141 | C | 1 | 9701/12 Oct/Nov 2024 |
| 142 | A | 1 | 9701/12 Oct/Nov 2024 |
| 143 | D | 1 | 9701/12 Feb/March 2025 |
| 144 | A | 1 | 9701/12 Feb/March 2025 |
| 145 | D | 1 | 9701/11 May/June 2025 |
| 146 | B | 1 | 9701/11 May/June 2025 |
| 147 | A | 1 | 9701/11 May/June 2025 |
| 148 | D | 1 | 9701/11 May/June 2025 |
| 149 | A | 1 | 9701/12 May/June 2025 |
| 150 | D | 1 | 9701/12 May/June 2025 |
| 151 | A | 1 | 9701/14 May/June 2025 |
| 152 | D | 1 | 9701/11 Oct/Nov 2025 |
| 153 | C | 1 | 9701/11 Oct/Nov 2025 |
| 154 | C | 1 | 9701/12 Oct/Nov 2025 |
| 155 | C | 1 | 9701/12 Oct/Nov 2025 |
| 156 | D | 1 | 9701/13 Oct/Nov 2025 |
| 157 | C | 1 | 9701/13 Oct/Nov 2025 |
29 Lactic acid occurs naturally, for example in sour milk. Its displayed formula is shown. H H O O H C C C O H H H Which reaction occurs with lactic acid? A It decolourises aqueous bromine rapidly. B It is insoluble in water. C It reduces Fehling’s reagent. D Two molecules react with each other in the presence of a strong acid.
1 marks
Answer: D
40 Which statements about lactic acid, CH3CH(OH)CO2H, are correct? 1 Lactic acid forms optical isomers. 2 Two hydrogen atoms per lactic acid molecule can be involved in hydrogen bonding. 3 Lactic acid would form an aldehyde when oxidised by acidified potassium dichromate(VI).
1 marks
Answer: B
26 Butanedioic acid occurs in amber, algae, lichens, sugar cane and beets. It may be synthesised in two steps from 1,2-dibromoethane. step 1 step 2 BrCH2CH2Br X HO2CCH2CH2CO2H Which reagents could be used for this synthesis? step 1 step 2 A HCN(g) HCl (aq) B HCO2Na(aq) HCl (aq) C KCN(aq/alcoholic) H2SO4(aq) D NaOH(aq) K2Cr2O7 / H2SO4(aq)
1 marks
Answer: C
40 Monopotassium citrate is used as an emulsifying agent in powdered milk and in powdered soups. It may be represented by the formula shown. CH2CO2H HO C CO2 K+ – CH2CO2H Which statements about monopotassium citrate are correct? 1 It can form optical isomers. 2 It can act as a dibasic acid. 3 It can form esters with both acids and alcohols.
1 marks
Answer: C
29 Which compound is both chiral and acidic? A B C D H CO2H CH3 OH CH2Br CH(OH)CO2H C HCO2CH CH2CO2H C CH3 H CO2H
1 marks
Answer: D
37 Aspirin is a widely-available pain-killer, whose properties have been known for centuries. The structure of aspirin is shown. OH C O O C CH3 O Which functional groups are present in aspirin? 1 alcohol 2 carboxylic acid 3 ester
1 marks
Answer: C
40 Ferulic acid is an antioxidant that occurs widely in plants. HO CH=CHCO2H CH3O ferulic acid Which reagents can react with the –CH=CHCO2H part of the molecule? 1 NaOH(aq) 2 acidified KMnO4 3 HBr
1 marks
Answer: A
27 The stomach wall can become sensitive to acidic compounds. Which is the most acidic compound? A B C D CO2H CO2H CO2H CH3CH(OH)CO2H OCOCH3 CH(OH) CH(OH) lactic acid CH(OH) CH2 aspirin CO2H CH(OH) CH(OH) malic acid CH2OH gluconic acid
1 marks
Answer: C
26 Glycol, used in anti-freeze, has the formula HOCH2CH2OH. It can be oxidised to give a number of products. What is the molecular formula of an oxidation product of glycol that will not react with sodium? A C2H2O2 B C2H2O3 C C2H2O4 D C2H4O2
1 marks
Answer: A
29 The characteristic odour of rum is attributed to the compound 2-ethyl-3-methylbutanoic acid. CH3 C2H5 H3C C C C OH H H O 2-ethyl-3-methylbutanoic acid Which compound will produce 2-ethyl-3-methylbutanoic acid by heating under reflux with alcoholic sodium cyanide and subsequent acid hydrolysis of the reaction product? CH3 A CH3 CH CH2 CHBr CH3 CH3 B CH3 CH CHBr CH2 CH3 CH3 C2H5 C CH3 CH CH CH2Br CH3 CH2Br D CH3 CH CH2 CH CH3
1 marks
Answer: B
37 Propanoic acid occurs naturally as a result of the bacterial fermentation of milk, and is partly responsible for the flavour of Swiss cheese. O OH propanoic acid Which starting materials could be used to synthesise propanoic acid? 1 CH3CH2CH2OH 2 CH3CH2CN 3 CH3CH2CHO
1 marks
Answer: A
34 When organic refuse decomposes in water carboxylic acids are formed. The water becomes acidic and aquatic life is destroyed. Which additives are suitable to remove this acid pollution? 1 calcium carbonate 2 calcium hydroxide 3 potassium nitrate
1 marks
Answer: B
38 Propanoic acid occurs naturally as a result of the bacterial fermentation of milk, and is partly responsible for the flavour of Swiss cheese. O OH propanoic acid Which starting materials could be used to synthesise propanoic acid? 1 CH3CH2CH2OH 2 CH3CH2CN 3 CH3CH2CHO
1 marks
Answer: A
39 Propanoic acid occurs naturally as a result of the bacterial fermentation of milk, and is partly responsible for the flavour of Swiss cheese. O OH propanoic acid Which starting materials could be used to synthesise propanoic acid? 1 CH3CH2CH2OH 2 CH3CH2CN 3 CH3CH2CHO
1 marks
Answer: A
22 A compound Y has all of the properties below. • It is a liquid at 25 °C. • It mixes completely with water. • It reacts with aqueous sodium hydroxide. What could Y be? A ethanoic acid B ethanol C ethene D ethyl ethanoate
1 marks
Answer: A
26 Lactic acid occurs naturally, for example in sour milk. H H O O H C C C H H O H lactic acid What is a property of lactic acid? A It decolourises aqueous bromine rapidly. B It is insoluble in water. C It reduces Fehling’s reagent. D Two molecules react with each other in the presence of a strong acid.
1 marks
Answer: D
39 An organic compound decolourises aqueous bromine and reacts with sodium to produce hydrogen. Which molecular formula could represent this compound? 1 C3H6O 2 C3H4O2 3 C3H8O
1 marks
Answer: B
22 When ethanal, CH3CHO, reacts with HCN and the organic product is hydrolysed by aqueous acid, organic compound Y is formed. When propanal, C2H5CHO, is heated under reflux with acidified potassium dichromate(VI), organic compound Z is formed. What is the difference in relative molecular mass of compounds Y and Z? A 12 B 14 C 16 D 17
1 marks
Answer: C
20 A compound Y has all of the properties below. • It is a liquid at 25 °C. • It mixes completely with water. • It reacts with aqueous sodium hydroxide. What could Y be? A ethanoic acid B ethanol C ethene D ethyl ethanoate
1 marks
Answer: A
26 Lactic acid occurs naturally, for example in sour milk. H H O O H C C C H H O H lactic acid What is a property of lactic acid? A It decolourises aqueous bromine rapidly. B It is insoluble in water. C It reduces Fehling’s reagent. D Two molecules react with each other in the presence of a strong acid.
1 marks
Answer: D
40 An organic compound, X, will react with an excess of calcium metal to produce a salt with the empirical formula CaC4H6O4. What could be the identity of X? 1 ethanoic acid 2 butanedioic acid 3 methylpropanedioic acid
1 marks
Answer: D
19 Butanedioic acid occurs in amber, algae, lichens, sugar cane and beets. It may be synthesised in two steps from 1,2-dibromoethane. step 1 step 2 BrCH2CH2Br X HO2CCH2CH2CO2H Which reagents could be used for this synthesis? step 1 step 2 A HCN(g) HCl (aq) B HCO2Na(aq) HCl (aq) C KCN(aq / alcoholic) H2SO4(aq) D NaOH(aq) K2Cr2O7 / H2SO4(aq)
1 marks
Answer: C
39 Sorbitol is an artificial sweetener used to sweeten chocolate which is suitable for diabetics. OH H C H H C OH HO C H H C OH H C OH H C H OH sorbitol Which functional groups can be produced when this molecule is subjected to oxidation under suitable conditions? 1 aldehyde 2 carboxylic acid 3 ketone
1 marks
Answer: A
40 Which pairs of homologous series have the same C:H ratio in their general formulae? 1 aldehydes and ketones 2 carboxylic acids and esters 3 alkenes and ketones
1 marks
21 An organic compound J reacts with sodium to produce an organic ion with a charge of –3. J reacts with NaOH(aq) to produce an organic ion with a charge of –1. What could be the structural formula of J? A HO2CCH(OH)CH2CO2H B HO2CCH(OH)CH2CHO C HOCH2CH(OH)CH2CO2H D HOCH2COCH2CHO
1 marks
Answer: C
26 Complete combustion of compound X gives carbon dioxide and water only. A sample of X is mixed with aqueous potassium(V) dichromate and boiled under reflux for one hour. The mixture is then distilled and the only organic substance present is collected. The organic substance collected reacts with sodium to give hydrogen, but does not react with 2,4-dinitrophenylhydrazine reagent and does not react with ethanol in the presence of concentrated sulfuric acid to give an ester. What can be deduced from this information? A X is a carboxylic acid. B X is a ketone. C X is an alcohol. D X is an alkane.
1 marks
Answer: C
21 An organic compound J reacts with sodium to produce an organic ion with a charge of –3. J reacts with NaOH(aq) to produce an organic ion with a charge of –1. What could be the structural formula of J? A HO2CCH(OH)CH2CO2H B HO2CCH(OH)CH2CHO C HOCH2CH(OH)CH2CO2H D HOCH2COCH2CHO
1 marks
Answer: C
27 Which reagent reacts with ethanol and also reacts with ethanoic acid? A acidified potassium dichromate(VI) B sodium C sodium carbonate D sodium hydroxide
1 marks
Answer: B
40 Oleic acid is found in olive oil. It has the following formula. H H C C O CH3(CH2)7 (CH2)7 C OH Which reagents will give a positive result with oleic acid? 1 aqueous bromine 2 acidified potassium dichromate(VI) 3 Fehling’s reagent
1 marks
Answer: D
27 Which reagent reacts with ethanol and also reacts with ethanoic acid? A acidified potassium dichromate(VI) B sodium C sodium carbonate D sodium hydroxide
1 marks
Answer: B
40 Oleic acid is found in olive oil. It has the following formula. H H C C O CH3(CH2)7 (CH2)7 C OH Which reagents will give a positive result with oleic acid? 1 aqueous bromine 2 acidified potassium dichromate(VI) 3 Fehling’s reagent
1 marks
Answer: D
27 Santonin is a drug that was once widely used to expel parasitic worms from the body. CH3 O CH3 CH3 O O santonin When santonin is first treated with warm dilute H2SO4, and then the product of this reaction is treated with cold acidified KMnO4, a final product X is obtained. How many atoms of hydrogen in each molecule of product X can be displaced with sodium metal? A 2 B 4 C 5 D 6
1 marks
Answer: D
39 An organic compound, X, will react with calcium metal to produce a salt with the empirical formula CaC4H4O4. What could be the identity of X? 1 ethanoic acid 2 butanedioic acid 3 2-methylpropanedioic acid
1 marks
Answer: C
21 Lactic acid (2-hydroxypropanoic acid), CH3CH(OH)CO2H, is found in sour milk. Which reaction could occur with lactic acid? A CH3CH(OH)CO2H + CH3OH → CH3CH(OCH3)CO2H + H2O B CH3CH(OH)CO2H + HCO2H → CH3CH(O2CH)CO2H + H2O C CH3CH(OH)CO2H + NaHCO3 → CH3CH(ONa)CO2H + H2O + CO2 D CH3CH(OH)CO2H + Cl 2 → CH3CH(Cl )CO2H + HOCl
1 marks
Answer: B
40 Which reagents, when used in an excess, can be used to make sodium lactate, CH3CH(OH)CO2Na, from lactic acid, CH3CH(OH)CO2H? 1 Na 2 NaHCO3 3 NaOH
1 marks
Answer: C
40 An organic compound, Z, will react with calcium metal to produce a salt with the empirical formula CaC4H6O4. What could be the identity of Z? 1 ethanoic acid 2 butanedioic acid 3 methylpropanedioic acid
1 marks
Answer: D
23 Burnt sugar has a characteristic smell caused partly by the following compound. O CH3 C CHO This compound contains two functional groups. Which reagent will react with both functional groups? A acidified potassium dichromate(VI) B Fehling’s solution C hydrogen cyanide D sodium hydroxide
1 marks
Answer: C
40 Ethanoic acid, CH3CO2H, is an important chemical which is used in the industrial manufacture of rayon and aspirin. Which processes can be used to make ethanoic acid? 1 hydrolysis of ethanenitrile 2 oxidation of ethanol 3 oxidation of ethanal
1 marks
Answer: A
22 The compound ‘leaf alcohol’ is partly responsible for the smell of new-mown grass. CH3CH2CH=CHCH2CH2OH leaf alcohol What will be formed when ‘leaf alcohol’ is oxidised using an excess of hot, acidified K2Cr2O7(aq)? A CH3CH2CH(OH)CH(OH)CH2CO2H B CH3CH2COCOCH2CO2H C CH3CH2CH=CHCH2CO2H D CH3CH2CO2H and HO2CCH2CO2H
1 marks
Answer: C
26 How many moles of hydrogen, H2, are evolved when an excess of sodium metal is added to one mole of citric acid? CO2H HO C CH2CO2H CH2CO2H citric acid A 1 B 2 C 3 D 4
1 marks
Answer: B
38 An organic compound Y, molecular formula C6H14O, may be oxidised to compound Z, molecular formula C6H12O2. What could be the structural formula of Y? 1 CH3CH2CH(CH2OH)CH2CH3 2 (CH3)3CCH2CH2OH 3 CH3CH2CH(CH3)CH2CH2OH
1 marks
Answer: A
22 The compound ‘leaf alcohol’ is partly responsible for the smell of new-mown grass. CH3CH2CH=CHCH2CH2OH leaf alcohol What will be formed when ‘leaf alcohol’ is oxidised using an excess of hot, acidified K2Cr2O7(aq)? A CH3CH2CH(OH)CH(OH)CH2CO2H B CH3CH2COCOCH2CO2H C CH3CH2CH=CHCH2CO2H D CH3CH2CO2H and HO2CCH2CO2H
1 marks
Answer: C
26 How many moles of hydrogen, H2, are evolved when an excess of sodium metal is added to one mole of citric acid? CO2H HO C CH2CO2H CH2CO2H citric acid A 1 B 2 C 3 D 4
1 marks
Answer: B
40 The structural formulae of two compounds are shown below. O O CH3CH2CH2CH2CH2C CH3CH2CH2CH2CH2OC OH H Which statements about these compounds are correct? 1 The two compounds are structural isomers of each other. 2 The empirical formula of both compounds is C3H6O. 3 Both compounds are carboxylic acids.
1 marks
Answer: B
40 Propanoic acid occurs naturally as a result of the bacterial fermentation of milk, and is partly responsible for the flavour of Swiss cheese. O OH propanoic acid Which starting materials could be used to synthesise propanoic acid? 1 CH3CH2CH2OH 2 CH3CH2CHO 3 CH3CH2CN
1 marks
Answer: A
38 When hydrolysed with dilute sulfuric acid, which compounds produce propanoic acid? 1 CH3CH2CO2CH3 2 CH3CH2CH2CN 3 CH3CH2CH2Cl
1 marks
Answer: D
39 Propane-1,2,3-triol is the raw material for many important industrial chemical processes. CH2 CH CH2 OH OH OH propane-1,2,3-triol Which statements about propane-1,2,3-triol are correct? 1 It reacts with carboxylic acids to form compounds containing up to three ester groups. 2 It can be oxidised to form compounds with aldehyde and ketone functional groups. 3 It can be oxidised to form compounds with up to three carboxylic acid groups.
1 marks
Answer: B
24 Lactic acid, CH3CH(OH)CO2H, causes pain when it builds up in muscles. Which reagent reacts with both of the –OH groups in lactic acid? A acidified potassium dichromate(VI) B ethanol C sodium D sodium hydroxide
1 marks
Answer: C
24 Lactic acid, CH3CH(OH)CO2H, causes pain when it builds up in muscles. Which reagent reacts with both of the –OH groups in lactic acid? A acidified potassium dichromate(VI) B ethanol C sodium D sodium hydroxide
1 marks
Answer: C
2 The shell of a chicken’s egg makes up 5% of the mass of an average egg. An average egg has a mass of 50 g. Assume the egg shell is pure calcium carbonate. How many complete chicken’s egg shells would be needed to neutralise 50 cm3 of 2.0 mol dm–3 ethanoic acid? A 1 B 2 C 3 D 4
1 marks
Answer: B
28 Lactic acid occurs naturally, for example in sour milk. H H O O H C C C H H O H lactic acid What is a property of lactic acid? A It decolourises aqueous bromine rapidly. B It is insoluble in water. C It reduces Fehling’s reagent. D Two molecules react with each other in the presence of a strong acid.
1 marks
Answer: D
29 Citric acid is found in lemon juice. HO2CCH2C(OH)(CO2H)CH2CO2H citric acid What is the volume of 0.4 mol dm–3 sodium hydroxide solution required to neutralise a solution containing 0.005 mol of citric acid? A 12.5 cm3 B 25.0 cm3 C 37.5 cm3 D 50.0 cm3
1 marks
Answer: C
40 Monopotassium citrate is used as an emulsifying agent in powdered milk and in powdered soups. It may be represented by the formula shown. CH2CO2H HO C CO2 K+ – CH2CO2H monopotassium citrate Which statements about monopotassium citrate are correct? 1 It does not have a chiral carbon atom. 2 It can act as a dibasic acid. 3 It reacts with NaHCO3 to give CO2.
1 marks
Answer: A
22 Methanoic acid, HCO2H, has acidic properties similar to those of other carboxylic acids. In addition it can be oxidised by the same oxidising agents that are capable of oxidising aldehydes. Which pair consists of two compounds that will give the same observations with Fehling’s reagent? A HCO2H and CH3CO2H B HCO2H and CH3CO2CH3 C HCO2H and CH3CH2COCH3 D HCO2H and CH3CH2CHO
1 marks
28 Which mixture could be used to produce propyl methanoate? A CH3CH2CO2H and CH3OH B CH3CH2CH2CH2OH and HCO2H C CH3CH2CH2OH and HCO2H D CH3CH2CH2CO2H and CH3OH
1 marks
Answer: C
37 Which reagents, when used in an excess, can be used to make sodium lactate, CH3CH(OH)CO2Na, from lactic acid, CH3CH(OH)CO2H? 1 Na 2 NaHCO3 3 NaOH
1 marks
Answer: C
39 An unknown organic compound Z reacts with sodium to give a combustible gas as one product. Z does not give a yellow precipitate with alkaline aqueous iodine. What is a possible identity of Z? 1 ethanoic acid 2 pentan-3-ol 3 propan-1-ol
1 marks
Answer: A
26 Malic acid is found in apples. OH H C CH2CO2H CO2H malic acid Which reagent will react with all three –OH groups present in the malic acid molecule? A ethanol in the presence of concentrated sulfuric acid B potassium hydroxide C sodium D sodium carbonate
1 marks
Answer: C
25 Malic acid is found in apples. OH H C CH2CO2H CO2H malic acid Which reagent will react with only one of the – OH groups in the malic acid molecule? A ethanoic acid in the presence of concentrated sulfuric acid B sodium C sodium hydrogen carbonate D sodium hydroxide
1 marks
Answer: A
28 Which reaction would not give ethanoic acid? A heating ethanenitrile under reflux with dilute sodium hydroxide B heating ethanenitrile under reflux with dilute sulfuric acid C heating ethanal under reflux with acidified sodium dichromate(VI) D heating ethanol under reflux with acidified sodium dichromate(VI)
1 marks
Answer: A
39 Several structural isomers of C3H6O3 are listed below. HOCH2COCH2OH HOCH2CH(OH)CHO HOCH2CH2CO2H CH3CH(OH)CO2H Which statements about these structural isomers are correct? 1 One mole of each reacts with two moles of sodium. 2 Only one of the isomers contains a tertiary alcohol group. 3 They all contain a primary alcohol group.
1 marks
Answer: D
28 Which reaction would not give ethanoic acid? A heating ethanenitrile under reflux with dilute sodium hydroxide B heating ethanenitrile under reflux with dilute sulfuric acid C heating ethanal under reflux with acidified sodium dichromate(VI) D heating ethanol under reflux with acidified sodium dichromate(VI)
1 marks
Answer: A
39 Several structural isomers of C3H6O3 are listed below. HOCH2COCH2OH HOCH2CH(OH)CHO HOCH2CH2CO2H CH3CH(OH)CO2H Which statements about these structural isomers are correct? 1 One mole of each reacts with two moles of sodium. 2 Only one of the isomers contains a tertiary alcohol group. 3 They all contain a primary alcohol group.
1 marks
Answer: D
24 A sample of 2.76 g of ethanol was mixed with an excess of aqueous acidified potassium dichromate(VI). The reaction mixture was then boiled under reflux for one hour. The required organic product was then collected by distillation. The yield of product was 75.0%. Which mass of product was collected? A 1.26 g B 1.98 g C 2.07 g D 2.70 g
1 marks
Answer: D
28 A carboxylic acid, P, has no possible chain isomers. It reacts with an alcohol, Q, that has only one positional isomer. What could be the ester formed from a reaction between P and Q? A butyl propanoate B ethyl butanoate C pentyl ethanoate D propyl pentanoate
1 marks
Answer: A
29 Which compound is chiral and reacts with Na2CO3 to give CO2? A B C D CH3 OH CH2Br CH(Br)CO2H H CO2H C HCO2CH CH2 C CH3 H CO2H CH3
1 marks
Answer: D
23 Carboxylic acids may be prepared by several different methods. In which reaction would propanoic acid be formed? A adding ammonium propanoate to dilute sulfuric acid B heating ethyl propanoate with aqueous sodium hydroxide C heating propan-2-ol with acidified potassium manganate(VII) under reflux D heating propyl ethanoate with dilute sulfuric acid
1 marks
Answer: A
25 Citric acid can be converted into tricarballylic acid in two stages. An intermediate, Q, is formed. CH2 CO2H CH2 CO2H stage 1 stage 2 HO C CO2H Q CH CO2H CH2 CO2H CH2 CO2H citric acid tricarballylic acid Which reagents are needed for each stage? stage 1 stage 2 A concentrated H2SO4 H2(g) and Ni B concentrated H2SO4 LiAl H4 C LiAl H4 H2SO4(aq) D NaOH(aq) H2(g) and Ni
1 marks
Answer: A
28 At room temperature, propanoic acid was reacted to produce sodium propanoate. No gas was produced during the reaction. What could the propanoic acid have reacted with? A NaHCO3(aq) B NaOH(aq) C Na2CO3(aq) D Na2SO4(aq)
1 marks
Answer: B
40 Carboxylic acids can be converted into their salts by a number of reactions at room temperature. Which reactions would produce sodium butanoate and a gas? 1 sodium carbonate + butanoic acid 2 sodium + butanoic acid 3 sodium hydroxide + butanoic acid
1 marks
Answer: B
25 Citric acid can be converted into tricarballylic acid in two stages. An intermediate, Q, is formed. CH2 CO2H CH2 CO2H stage 1 stage 2 HO C CO2H Q CH CO2H CH2 CO2H CH2 CO2H citric acid tricarballylic acid Which reagents are needed for each stage? stage 1 stage 2 A concentrated H2SO4 H2(g) and Ni B concentrated H2SO4 LiAl H4 C LiAl H4 H2SO4(aq) D NaOH(aq) H2(g) and Ni
1 marks
Answer: A
28 At room temperature, propanoic acid was reacted to produce sodium propanoate. No gas was produced during the reaction. What could the propanoic acid have reacted with? A NaHCO3(aq) B NaOH(aq) C Na2CO3(aq) D Na2SO4(aq)
1 marks
Answer: B
28 Which reagent could be used to carry out the following reaction? O O OH A a solution containing acidified dichromate(VI) ions B a solution containing dilute, acidified manganate(VII) ions C a solution containing hot, concentrated, acidified manganate(VII) ions D concentrated sulfuric acid
1 marks
Answer: A
29 Four reactions of propanoic acid to form salts and other products are shown. Which reaction does not show the formulae of all the correct products? A B CH3CH2CO2 – K+(aq) + H2O(l) (CH3CH2CO2 –)2Mg2+(aq) + H2(g) KOH Mg(s) CH3CH2CO2H(aq) propanoic Na2CO3 acid Ca(OH)2 C D CH3CH2CO2 – Na+(aq) + CO2(g) (CH3CH2CO2 –)2Ca2+(aq) + H2O(l)
1 marks
Answer: C
30 The infra-red spectrum of an organic compound is shown. 100 transmittance % 50 0 4000 3000 2000 1500 1000 500 wavenumber / cm–1 Which compound could give this spectrum? A CH3CH2CO2H B CH3CH(OH)CH3 C CH3COCH3 D CH3COCH2OH Section B
1 marks
Answer: C
26 Sodium reacts with 1 mol of compound Y to produce 1 mol of H2(g). Which compound could Y be? A CH3CH2CH2CH2OH B (CH3)3COH C CH3CH2CH2CO2H D CH3CH(OH)CO2H
1 marks
Answer: D
28 Ethanedioic acid, HO2CCO2H, is reduced using an excess of lithium aluminium hydride, LiAl H4. What is the organic product of the reaction? A ethanol B ethane-1,2-diol C ethanedial, OHCCHO D methane
1 marks
Answer: B
26 Sodium reacts with 1 mol of compound Y to produce 1 mol of H2(g). Which compound could Y be? A CH3CH2CH2CH2OH B (CH3)3COH C CH3CH2CH2CO2H D CH3CH(OH)CO2H
1 marks
Answer: D
28 Ethanedioic acid, HO2CCO2H, is reduced using an excess of lithium aluminium hydride, LiAl H4. What is the organic product of the reaction? A ethanol B ethane-1,2-diol C ethanedial, OHCCHO D methane
1 marks
Answer: B
25 Which product is formed when 3-methylpentane-1,3,4-triol is heated under reflux with an excess of acidified potassium dichromate(VI)? A HO2CCH2C(CH3)(OH)COCH3 B HO2CCH2COC(OH)(CH3)2 C OHCCH2C(CH3)(OH)COCH3 D HO2CCH2CO(CH3)COCH3
1 marks
Answer: A
29 1 mole of each of the following four compounds is reacted separately with: ● an excess of sodium ● an excess of sodium carbonate. Which compound produces the same volume of gas with each of the two reagents? A B C D OH O O O OH OH H HO HO HO HO O
1 marks
Answer: D
30 An infra-red spectrum shows a broad peak at 3000 cm–1 and a strong peak at 1710 cm–1. Which substance could have produced this spectrum? A methyl propanoate B propan-2-ol C propanoic acid D propanone
1 marks
Answer: C
40 Carboxylic acids can be prepared from alcohols, nitriles or esters. Which statements are correct? 1 Both primary and secondary alcohols can be oxidised to carboxylic acids. 2 Carboxylic acids can be made from nitriles by hydrolysis. 3 Ethyl propanoate gives propanoic acid when reacted with hydrochloric acid.
1 marks
Answer: C
39 Carboxylic acids can be made by several different reactions. Which statements are correct? 1 The acid hydrolysis of CH3CH2CN will make ethanoic acid. 2 The oxidation of CH3CH2CH2CH2OH will make butanoic acid. 3 The oxidation of CH3CH2CHO will make propanoic acid.
1 marks
Answer: C
40 Carboxylic acids react with alcohols to produce esters. Carboxylic acid X forms one ester only with molecular formula C5H10O2. What could X be? 1 ethanoic acid 2 propanoic acid 3 butanoic acid
1 marks
Answer: C
24 Alcohol W cannot be made by reducing a carboxylic acid with LiAl H4. Alcohol W gives only one product when dehydrated with concentrated sulfuric acid. What could be the identity of W? A butan-1-ol B butan-2-ol C propan-1-ol D propan-2-ol
1 marks
Answer: D
28 The diagram shows that a carboxylic acid P may be formed from X, Y or Z. alcohol aldehyde X Y carboxylic acid P nitrile Z Which row is correct? the change in Mr alcohol X is is greatest for A primary Y to P B primary Z to P C secondary Y to P D secondary Z to P
1 marks
Answer: B
40 An oxidising agent that can oxidise ethanal to ethanoic acid or ethanoate ions will also oxidise methanoic acid, HCO2H, to carbon dioxide and water. Which reagents, on heating, will react differently with HCO2H and CH3CO2H? 1 Na2CO3(aq) 2 Fehling’s reagent 3 dilute acidified KMnO4
1 marks
Answer: C
30 An ester is shown. O O O H O What is the structure of the carboxylic acid that would be obtained by acid hydrolysis of the ester linkage? A B O O OH O O H OH HO O C D O O O O O O O OH HO O
1 marks
Answer: A
28 Tartaric acid, HO2CCH(OH)CH(OH)CO2H, is found in many plants. A sample of tartaric acid reacts with an excess of LiAl H4 to form the organic product J. What happens when NaOH(aq) is added to separate samples of tartaric acid and J? A Both tartaric acid and J react. B Only tartaric acid reacts. C Only J reacts. D Neither tartaric acid nor J react.
1 marks
Answer: B
30 The infra-red spectrum of compound P is shown. 100 transmittance / % 50 0 4000 3000 2000 1500 1000 500 wavenumber / cm–1 What could be compound P? A methyl ethanoate B propanal C propanoic acid D propan-2-ol
1 marks
Answer: D
39 Which reagents, when used in excess, can convert Y into Z? CH3CH(OH)CO2H → CH3CH(OH)CO2Na Y Z 1 Na 2 Na2CO3 3 NaOH
1 marks
Answer: C
28 Tartaric acid, HO2CCH(OH)CH(OH)CO2H, is found in many plants. A sample of tartaric acid reacts with an excess of LiAl H4 to form the organic product J. What happens when NaOH(aq) is added to separate samples of tartaric acid and J? A Both tartaric acid and J react. B Only tartaric acid reacts. C Only J reacts. D Neither tartaric acid nor J react.
1 marks
Answer: B
30 The infra-red spectrum of compound P is shown. 100 transmittance / % 50 0 4000 3000 2000 1500 1000 500 wavenumber / cm–1 What could be compound P? A methyl ethanoate B propanal C propanoic acid D propan-2-ol
1 marks
Answer: D
27 Which reaction would produce propanoic acid as one of its products? A heating (CH3)2C=CHCH2CH3 with concentrated, acidified KMnO4 B heating CH3CH2CO2CH2CH2CH3 with NaOH(aq) C heating CH3CH2OH with acidified K2Cr2O7 under reflux D reacting CH3CHO with HCN then heating the organic product with H2SO4(aq)
1 marks
Answer: A
21 Which statement is correct? A 2,2-dimethylpropanoic acid is an isomer of propyl methanoate. B 2-methylbutan-2-ol is an isomer of hexan-3-ol. C 3-methylbutan-2-one is an isomer of pentanal. D 3,3-dimethylbutan-2-one is an isomer of pentan-3-one.
1 marks
Answer: C
30 Which reaction produces an organic anion with a good yield? A heating ethanenitrile under reflux with dilute sodium hydroxide B heating ethanenitrile under reflux with dilute sulfuric acid C heating ethane with sodium metal D heating ethanol under reflux with dilute sodium hydroxide Section B
1 marks
Answer: A
20 Compound X is shown. compound X CO2H OH X is treated separately with NaOH(aq) and LiAl H4 to give Y and Z. CO2H NaOH(aq) LiAl H4 Y Z OH What are Y and Z? Y Z CO2Na CH2OH A OH OH CO2Na CO2H B OH OH CO2Na CH2OH C ONa OH CO2Na CO2H D ONa OH
1 marks
Answer: A
25 Which substance forms propanoic acid as one of the products when it reacts with hot concentrated acidified potassium manganate(VII)? A but-1-ene B but-2-ene C 2-methylpropene D 2-methylbut-1-ene
1 marks
Answer: A
25 The diagram shows the infrared spectrum of an organic compound. What could be the identity of this compound? A propan-1-ol B propanal C propanoic acid D propanone
1 marks
Answer: C
26 Which reagent reacts with both of the –OH groups in lactic acid, CH3CH(OH)CO2H? A acidified potassium dichromate(VI) B ethanol C sodium D sodium hydroxide
1 marks
Answer: C
29 Which compound is chiral and reacts with Na2CO3 to give CO2? A B C D CH3 OH CH2Br CH(Br)CO2H H CO2H C HCO2CH CH2 C CH3 H CO2H CH3
1 marks
Answer: D
37 The structure of compound R is shown. compound R O OH O Which statements about compound R are correct? 1 It has an Mr of 116. 2 It contains two groups that show strong absorptions between 1640 and 1740 cm–1 in its infrared spectrum. 3 Its only infrared absorption between 2500 and 3000 cm–1 is sharp and strong.
1 marks
Answer: B
29 Which compound is chiral and reacts with Na2CO3 to give CO2? A B C D CH3 OH CH2Br CH(Br)CO2H H CO2H C HCO2CH CH2 C CH3 H CO2H CH3
1 marks
Answer: D
28 Ethanedioic acid has the formula HO2CCO2H. What is the formula of aluminium ethanedioate? A Al C2O4 B Al (C2O4)3 C Al 2C2O4 D Al 2(C2O4)3
1 marks
Answer: D
29 Which reaction gives butanoic acid as one of its products? A acid hydrolysis of butyl ethanoate B alkaline hydrolysis of butyl ethanoate C acid hydrolysis of ethyl butanoate D alkaline hydrolysis of ethyl butanoate
1 marks
Answer: C
40 An organic compound, T, does not fizz when aqueous sodium carbonate is added to it. Compound T contains 27.6% by mass of oxygen. What could be the identity of T? 1 propanal 2 ethyl butanoate 3 3-methylpentanoic acid
1 marks
Answer: B
27 How many moles of hydrogen, H2, are evolved when an excess of sodium metal is added to one mole of citric acid? citric acid CO2H HO C CH2CO2H CH2CO2H A 0.5 B 1.5 C 2 D 4
1 marks
Answer: C
3 The structures represent three compounds, each with four carbon atoms per molecule. X Y Z O O O OH O O–Na+ Which row is correct? lowest highest boiling point boiling point A X Y Z B Y X Z C Z X Y D Z Y X
1 marks
Answer: B
21 Hexadeca-10,12-dien-1-ol is produced by silk moths from hexadecanoic acid in a three-step enzymic process. hexadecanoic acid O OH step 1 O OH step 2 O OH step 3 OH Which row contains correct descriptions of the three steps? step 1 step 2 step 3 A elimination elimination dehydration B elimination reduction reduction C oxidation elimination oxidation D oxidation oxidation reduction
1 marks
Answer: D
40 Which mixtures form a carboxylic acid as one of the products? O 1 AK + H,SO,(aq) > O- 2 AK, + H,SO,(aq) > 3 NRA + H80,(aq) >
1 marks
Answer: B
39 Three compounds, X, Y and Z, are shown. X Y Z C2H5COCH3 C2H5CHO CH3CO2H Which statements about X, Y and Z are correct? 1 X reacts with alkaline aqueous iodine. 2 Y reacts with Tollens’ reagent. 3 Z does not react with alkaline aqueous iodine.
1 marks
Answer: A
28 Citric acid is found in lemon juice. citric acid HO2CCH2C(OH)(CO2H)CH2CO2H Which volume of 0.40 mol dm–3 sodium hydroxide solution is required to neutralise a solution containing 0.0050 mol of citric acid? A 12.5 cm3 B 25.0 cm3 C 37.5 cm3 D 50.0 cm3
1 marks
Answer: C
29 Organic compound Z has an alcohol group and a carboxylic acid group. Compound Z reacts with magnesium carbonate to make a salt with a relative formula mass of 230.3. Compound Z does not react with acidified potassium manganate(VII). What could be the identity of compound Z? A 2-hydroxy-2-methylbutanoic acid B 2-hydroxy-2-methylpropanoic acid C 3-hydroxy-2-methylbutanoic acid D 3-hydroxy-2-methylpropanoic acid
1 marks
Answer: B
30 The infra-red spectrum of Y is shown. 100 transmittance / % 50 0 4000 3000 2000 1500 1000 500 wavenumber / cm–1 What could Y be? A CH3CO2C2H5 B CH2(OH)CH=CHCH2OH C CH3(CH2)2CO2H D CH2(OH)(CH2)2CHO
1 marks
Answer: B
28 Citric acid is found in lemon juice. citric acid HO2CCH2C(OH)(CO2H)CH2CO2H Which volume of 0.40 mol dm–3 sodium hydroxide solution is required to neutralise a solution containing 0.0050 mol of citric acid? A 12.5 cm3 B 25.0 cm3 C 37.5 cm3 D 50.0 cm3
1 marks
Answer: C
38 Two 1 g samples of Y are reacted separately and completely with sodium and with sodium carbonate. The volumes of the gases produced are collected and measured. relative volumes of gases with Na with Na2CO3 Y 2 1 What could Y be? A CH3CH(OH)CH2OH B CH3CH(OH)CO2H C CH3COCH2OH D CH3COCO2H
1 marks
Answer: B
37 Which reaction is a redox reaction? A ethanenitrile heated under reflux with dilute hydrochloric acid B ethanoic acid reacted with aqueous sodium hydroxide C ethanoic acid reacted with sodium D ethyl ethanoate heated under reflux with dilute hydrochloric acid
1 marks
Answer: C
29 The structure of santonin is shown. santonin CH3 O CH3 CH3 O O Santonin is first treated with warm dilute H2SO4. The product of this reaction is treated with cold dilute acidified KMnO4. A final product, Q, is obtained. How many atoms of hydrogen in each molecule of product Q will react with sodium metal? A 2 B 4 C 5 D 6
1 marks
Answer: D
31 Three colourless liquids with the following formulae are contained in separate unlabelled bottles. CH3CH2CO2H CH3CH(OH)CO2H CH3COCO2H Which two tests, carried out on separate samples of each liquid, will successfully identify each liquid? test 1 test 2 A NaHCO3 2,4-DNPH reagent B NaHCO3 Tollens’ reagent C warm acidified dichromate 2,4-DNPH reagent D warm acidified dichromate Tollens’ reagent
1 marks
Answer: C
35 Structural isomerism and stereoisomerism should be considered when answering this question. How many isomeric compounds with molecular formula C5H6O4 contain two –CO2H groups and one C=C double bond? A 5 B 6 C 7 D 8
1 marks
Answer: C
26 The structure of tartaric acid is shown. tartaric acid OH O HO OH O OH Which statements about tartaric acid are correct? 1 A molecule of tartaric acid has more than one chiral centre. 2 The molecular formula of tartaric acid is C4H4O6. 3 One molecule of tartaric acid produces four hydrogen ions in aqueous solution. A 1, 2 and 3 B 1 and 2 only C 2 and 3 only D 1 only
1 marks
Answer: D
40 A molecule of an organic compound, P, contains three carbon atoms and shows a strong absorption at 1720 cm–1 in its infrared spectrum. P is reacted with an excess of hot acidified potassium dichromate(VI) forming organic product Q. Q shows a strong absorption at 1700 cm–1 and a strong, broad absorption centred at 2800 cm–1 in its infrared spectrum. bond functional group containing the bond characteristic infrared absorption range (in wavenumbers) / cm–1 C–O hydroxy, ester 1040–1300 C=C aromatic compound, alkene 1500–1680 C=O amide 1640–1690 carbonyl, carboxyl 1670–1740 ester 1710–1750 C≡N nitrile 2200–2250 C–H alkane 2850–2950 N–H amine, amide 3300–3500 O–H carboxyl 2500–3000 hydroxy 3200–3600 What is P? A propanal B propanone C propan-1-ol D propan-2-ol
1 marks
Answer: A
29 The structure of santonin is shown. santonin CH3 O CH3 CH3 O O Santonin is first treated with warm dilute H2SO4. The product of this reaction is treated with cold dilute acidified KMnO4. A final product, Q, is obtained. How many atoms of hydrogen in each molecule of product Q will react with sodium metal? A 2 B 4 C 5 D 6
1 marks
Answer: D
31 Three colourless liquids with the following formulae are contained in separate unlabelled bottles. CH3CH2CO2H CH3CH(OH)CO2H CH3COCO2H Which two tests, carried out on separate samples of each liquid, will successfully identify each liquid? test 1 test 2 A NaHCO3 2,4-DNPH reagent B NaHCO3 Tollens’ reagent C warm acidified dichromate 2,4-DNPH reagent D warm acidified dichromate Tollens’ reagent
1 marks
Answer: C
35 Structural isomerism and stereoisomerism should be considered when answering this question. How many isomeric compounds with molecular formula C5H6O4 contain two –CO2H groups and one C=C double bond? A 5 B 6 C 7 D 8
1 marks
Answer: C
1 Propanoic acid is treated with reagent X at room temperature. The organic product of the reaction is sodium propanoate. No gas is produced during the reaction. What could be reagent X? A NaHCO3(aq) B NaOH(aq) C Na2CO3(aq) D Na2SO4(aq)
1 marks
Answer: B
39 The infrared spectrum of compound L is shown. 100 transmittance % 50 0 4000 3000 2000 1500 1000 500 wavenumber / cm–1 bond functional groups containing the bond characteristic infrared absorption range (in wavenumbers) / cm–1 C–O hydroxy, ester 1040–1300 C=C aromatic compound, alkene 1500–1680 C=O amide 1640–1690 carbonyl, carboxyl 1670–1740 ester 1710–1750 C≡N nitrile 2200–2250 C–H alkane 2850–2950 N–H amine, amide 3300–3500 O–H carboxyl 2500–3000 hydroxy 3200–3600 What is the structure of L? A HOCH2COCH2OH B HOCH2CH(OH)CHO C HOCH2CH(OH)CH2OH D HOCH2CH2COOH
1 marks
Answer: C
37 Three equations are shown. 1 CH3COOH + MgCO3 →CH3COOMg + CO2 + H2O 2 CH3CH2COOH + Na →CH3CH2COONa + H2 3 CH3CH2COOH + 2Ba(OH)2 →CH3CH2COOBa2 + 2H2O Which of the equations are correct? A 1, 2 and 3 B 1 and 2 only C 2 only D 3 only
1 marks
Answer: C
39 The diagram shows an ester. It is heated under reflux with an excess of NaOH(aq). O O Which row shows the 2 products of the reaction? product 1 product 2 A O OH OH B O ONa OH C O OH ONa D O ONa ONa
1 marks
Answer: C
31 X is an organic compound containing the elements carbon, hydrogen and oxygen only. The table shows the observations made from three chemical tests carried out on X. reagent added observation Na(s) effervescence Na2CO3(s) effervescence hot H+ / Cr2O7 2–(aq) remains orange What is a possible structure of X? A B C D OH O O O HO O OH OH OH OH
1 marks
Answer: D
37 Compound Z is formed by the reaction scheme shown. warm with reflux with CH3CH2Br compound X compound Z KCN in ethanol dilute HCl What is the formula of compound Z? A CH3CH2Cl B CH3CH2CN C CH3COOH D CH3CH2COOH
1 marks
Answer: D
38 Hydroxyethanal, HOCH2CHO, is heated under reflux with an excess of acidified K2Cr2O7 until no further oxidation takes place. What is the skeletal formula of the organic product? A B C D O O OH O HO HO OH OH OH OH O O O O
1 marks
Answer: B
40 The infrared spectrum of a compound is shown. 100 transmittance / % 50 0 4000 3000 2000 1500 1000 500 wavenumber / cm–1 characteristic infrared absorption range bond functional groups containing the bond (in wavenumbers) / cm–1 C–O hydroxy, ester 1040–1300 C=C aromatic compound, alkene 1500–1680 C=O amide 1640–1690 carbonyl, carboxyl 1670–1740 ester 1710–1750 C≡N nitrile 2200–2250 C–H alkane 2850–2950 N–H amine, amide 3300–3500 O–H carboxyl 2500–3000 hydroxy 3200–3600 Which functional group could the compound contain? A alcohol B carboxylic acid C ester D nitrile
1 marks
Answer: C
36 The product of the reaction between propanone and hydrogen cyanide is hydrolysed under acidic conditions. What is the formula of the final product? A CH3CH(OH)COOH B CH3CH2CH2COOH C (CH3)2CHCONH2 D (CH3)2C(OH)COOH
1 marks
Answer: D
37 P is a carboxylic acid with molecular formula C5H10O2. Carboxylic acid P reacts with an excess of LiAl H4 to form compound Q. Which pairs of molecules could be carboxylic acid P and compound Q? carboxylic acid P compound Q 1 CH3(CH2)3COOH CH3(CH2)3OH 2 CH3(CH2)3COOH CH3(CH2)3CHO 3 (CH3)3CCOOH (CH3)3CCH2OH A 1 and 2 B 1 and 3 C 2 and 3 D 3 only
1 marks
Answer: D
30 1 mole of each of the following four compounds is reacted separately with: ● an excess of sodium ● an excess of sodium carbonate. Which compound produces the same volume of gas with each of the two reagents? A B C D OH O O O OH OH H HO HO HO HO O
1 marks
Answer: D
40 A sample of but-2-enoic acid, CH3CH=CHCOOH, is analysed using infrared spectroscopy. The infrared spectrum shows a broad peak in the range 2500–3000 cm–1. characteristic infrared absorption range bond functional groups containing the bond (in wavenumbers) / cm–1 C–O hydroxy, ester 1040–1300 C=C aromatic compound, alkene 1500–1680 C=O amide 1640–1690 carbonyl, carboxyl 1670–1740 ester 1710–1750 C≡N nitrile 2200–2250 C–H alkane 2850–2950 N–H amine, amide 3300–3500 O–H carboxyl 2500–3000 hydroxy 3200–3600 Which bond is responsible for this peak? A C=C B C=O C C–O D O–H
1 marks
Answer: D
29 Vitamin A contains retinol. retinol OH Under appropriate conditions, acidified KMnO4(aq) can be used to break C=C bonds. After these bonds have been broken, further oxidation of the fragments may occur. Under which conditions is the acidified KMnO4(aq) used and what do the final oxidation products include? conditions final oxidation products A cold, dilute aldehydes and carboxylic acids B cold, dilute ketones and carboxylic acids C hot, concentrated aldehydes and carboxylic acids D hot, concentrated ketones and carboxylic acids
1 marks
Answer: D
34 Compound Y reacts with alkaline I2(aq). When the products of this reaction are acidified, a dicarboxylic acid is produced. The formula of the dicarboxylic acid is HOOC–R–COOH where R consists of one or more CH2 groups. Which compound is Y? A pentan-1,4-diol B pentan-1,5-diol C pentan-2,3-diol D pentan-2,4-diol
1 marks
Answer: D
33 The compound ‘leaf alcohol’ is partly responsible for the smell of new-mown grass. leaf alcohol CH3CH2CH=CHCH2CH2OH What will be formed when ‘leaf alcohol’ is oxidised using an excess of hot acidified K2Cr2O7(aq)? A CH3CH2CH(OH)CH(OH)CH2CO2H B CH3CH2COCOCH2CO2H C CH3CH2CH=CHCH2CO2H D CH3CH2CO2H and HO2CCH2CO2H
1 marks
Answer: C
37 A sample of propanoic acid of mass 3.70 g reacts with an excess of magnesium. A second sample of propanoic acid of mass 3.70 g reacts with an excess of sodium. Both reactions go to completion forming a gas. Which row is correct? volume of gas formed volume of gas formed with magnesium with sodium at s.t.p. / cm3 at s.t.p. / cm3 A 560 560 B 560 1120 C 1120 560 D 1120 1120
1 marks
Answer: A
26 Organic compound X has the empirical formula C2H4O. Compound X is reduced by LiAl H4, but not by NaBH4. What is compound X? A ethanoic acid B ethanal C butan-1-ol D butanoic acid
1 marks
Answer: D
38 The diagrams show the structures of two isomeric dicarboxylic acids, X and Y. O O O HO HO OH C H C C C C C C H C H H OH O X Y X can be reduced to compound P with empirical formula C2H5O. Y can be reduced to compound Q, also with empirical formula C2H5O. Which statement is correct? A X is a cis isomer; compound P and compound Q are identical. B X is a cis isomer; compound P and compound Q are isomers of each other. C X is a trans isomer; compound P and compound Q are identical. D X is a trans isomer; compound P and compound Q are isomers of each other.
1 marks
Answer: A
6 P is a compound that burns in an excess of oxygen to give carbon dioxide and water only. 2.20g of P contains 1.20g of carbon and 0.20g of hydrogen. When P is added to a solution of sodium carbonate, bubbles of gas are seen. What is P? A CH3CHO B CH3CO2H C CH3COCH2CH2OH D CH3CH2CH2CO2H
1 marks
Answer: D
25 Three reagents are listed. 1 aqueous sodium carbonate 2 LiAlH4 3 water Which reagents react with pure ethanoic acid to give a solution containing ethanoate ions? A 1 and 2 B 1 and 3 C 1 only D 2 and 3
1 marks
Answer: B
28 An organic compound J reacts with an excess of sodium to produce an organic ion with a charge of –3. J reacts with an excess of NaOH(aq) to produce an organic ion with a charge of –1. What is the structural formula of J? A HOCH2CH(OH)CH2CO2H B HO2CCH(OH)CH2CHO C HO2CCH(OH)CH2CO2H D HOCH2COCH2CHO
1 marks
Answer: A
34 Compound W contains atoms of carbon, nitrogen and hydrogen. Compound W reacts with HCl(aq) to produce propanoic acid. Which row is correct? functional group in compound W name of compound W A amine ethylamine B nitrile ethanenitrile C amine propylamine D nitrile propanenitrile
1 marks
Answer: D
18 Compound M is a white solid. It is the chloride of a Period 3 element. Information about some reactions starting with compound M is given in the table. reaction observation compound M + non-polar solvent colourless solution compound M added a little at a time to water steamy fumes, Q colourless solution, R fumes Q tested with moist blue litmus paper paper turns red solution R + a few drops of NaOH(aq) white precipitate + excess NaOH(aq) dissolves to give a colourless solution What is compound M? A aluminium chloride B magnesium chloride C phosphorus pentachloride D sodium chloride
1 marks
Answer: A
27 Methanoic acid, HCO2H, has acidic properties similar to those of other carboxylic acids. In addition, it can be oxidised by the same oxidising agents that are capable of oxidising aldehydes. Which pair consists of two compounds that will give the same observations with Fehling’s reagent? A HCO2H and CH3CO2H B HCO2H and CH3CO2CH3 C HCO2H and CH3CH2COCH3 D HCO2H and CH3CH2CHO
1 marks
Answer: D
2 What is the empirical formula of butanoic acid? A C2H4O B C3H6O C C4H8O D C5H10O
1 marks
Answer: A
34 Three mixtures are heated under reflux. Which mixtures will produce sodium propanoate as one product? 1 CH3CH2CHO + NaBH4(aq) 2 CH3CH2CH2OH + Na(s) 3 CH3CH2CN + NaOH(aq) A 1, 2 and 3 B 1 and 2 only C 2 and 3 only D 3 only
1 marks
Answer: D
37 The table shows the reagents and products of three reactions. reagents products 1 ethanoic acid + Na2CO3 CH3CO2Na + H2O + CO2 2 ethanoic acid + Mg (CH3CO2)2Mg + H2O 3 ethanoic acid + CH3OH CH3CO2CH3 + H2O Which rows are correct? A 1, 2 and 3 B 1 and 2 only C 1 and 3 only D 2 and 3 only
1 marks
Answer: C
33 HOCH2CHO is heated under reflux with an excess of acidified K2Cr2O7 until there is no further reaction. What is the final product of this reaction? A HOOCCHO B HOCH2COOH C HOOCCOOH D HOOCCH2COOH
1 marks
Answer: C
37 In four separate reactions, W, X, Y and Z, 1 mol of an organic compound reacts with an excess of a reagent. organic compound reagent W (CH2COOH)2 Na X CH3CH(OH)CH2COOH Na2CO3 Y CH3CH(OH)CH2COOH NaOH Z CH(OH)(COOH)CH2COOH Na The volume of any gas produced is collected and measured. All gas volumes are measured at the same temperature and pressure. What is the order of the reactions from greatest total volume of gas collected to least total volume of gas collected? greatest least volume volume A W Y Z X B W Z Y X C Z W X Y D Z X W Y
1 marks
Answer: C
34 Three mixtures are heated under reflux. Which mixtures will produce sodium propanoate as one product? 1 CH3CH2CHO + NaBH4(aq) 2 CH3CH2CH2OH + Na(s) 3 CH3CH2CN + NaOH(aq) A 1, 2 and 3 B 1 and 2 only C 2 and 3 only D 3 only
1 marks
Answer: D
37 The table shows the reagents and products of three reactions. reagents products 1 ethanoic acid + Na2CO3 CH3CO2Na + H2O + CO2 2 ethanoic acid + Mg (CH3CO2)2Mg + H2O 3 ethanoic acid + CH3OH CH3CO2CH3 + H2O Which rows are correct? A 1, 2 and 3 B 1 and 2 only C 1 and 3 only D 2 and 3 only
1 marks
Answer: C