6.2· 206 questions · 206 marks · 247 min · 2004–2025· Multiple choice
Every Cambridge A Level Biology Paper 1 question on protein synthesis, laid out as 58 A4 pages with the mark scheme below. Nothing is left out. Free to read, no account.





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58 / 58Answers below. Sit the paper first if you are practising.
Pastlit
Biology 9700 · Protein synthesis — Paper 1
A Level · topical answer key — answer key (teacher use)
Question
Answer
Marks
Pastlit
Biology 9700 · Protein synthesis — Paper 1
A Level · topical answer key — answer key (teacher use)
Question
Answer
Marks
Pastlit
Biology 9700 · Protein synthesis — Paper 1
A Level · topical answer key — answer key (teacher use)
Question
Answer
Marks
Pastlit
Biology 9700 · Protein synthesis — Paper 1
A Level · topical answer key — answer key (teacher use)
Question
Answer
Marks
Pastlit
Biology 9700 · Protein synthesis — Paper 1
A Level · topical answer key — answer key (teacher use)
Question
Answer
Marks
| Question | Answer | Marks | From |
|---|---|---|---|
| 1 | D | 1 | 9700/11 Oct/Nov 2004 |
| 2 | A | 1 | 9700/11 Oct/Nov 2004 |
| 3 | B | 1 | 9700/11 Oct/Nov 2004 |
| 4 | A | 1 | 9700/11 Oct/Nov 2004 |
| 5 | B | 1 | 9700/11 Oct/Nov 2004 |
| 6 | B | 1 | 9700/11 May/June 2006 |
| 7 | B | 1 | 9700/11 May/June 2006 |
| 8 | A | 1 | 9700/11 Oct/Nov 2006 |
| 9 | D | 1 | 9700/11 Oct/Nov 2007 |
| 10 | D | 1 | 9700/11 Oct/Nov 2007 |
| 11 | B | 1 | 9700/11 Oct/Nov 2007 |
| 12 | B | 1 | 9700/11 May/June 2008 |
| 13 | D | 1 | 9700/11 May/June 2008 |
| 14 | B | 1 | 9700/11 Oct/Nov 2008 |
| 15 | C | 1 | 9700/11 Oct/Nov 2008 |
| 16 | A | 1 | 9700/11 Oct/Nov 2008 |
| 17 | C | 1 | 9700/12 Oct/Nov 2009 |
| 18 | A | 1 | 9700/12 Oct/Nov 2009 |
| 19 | A | 1 | 9700/11 May/June 2010 |
| 20 | A | 1 | 9700/11 May/June 2010 |
| 21 | A | 1 | 9700/12 May/June 2010 |
| 22 | A | 1 | 9700/13 May/June 2010 |
| 23 | A | 1 | 9700/12 Oct/Nov 2010 |
| 24 | A | 1 | 9700/11 May/June 2011 |
| 25 | C | 1 | 9700/12 May/June 2011 |
| 26 | C | 1 | 9700/12 May/June 2011 |
| 27 | A | 1 | 9700/13 May/June 2011 |
| 28 | B | 1 | 9700/11 Oct/Nov 2011 |
| 29 | A | 1 | 9700/11 Oct/Nov 2011 |
| 30 | A | 1 | 9700/13 Oct/Nov 2011 |
| 31 | B | 1 | 9700/13 Oct/Nov 2011 |
| 32 | C | 1 | 9700/11 May/June 2012 |
| 33 | A | 1 | 9700/11 May/June 2012 |
| 34 | A | 1 | 9700/12 May/June 2012 |
| 35 | A | 1 | 9700/12 May/June 2012 |
| 36 | B | 1 | 9700/12 May/June 2012 |
| 37 | A | 1 | 9700/13 May/June 2012 |
| 38 | C | 1 | 9700/13 May/June 2012 |
| 39 | D | 1 | 9700/11 Oct/Nov 2012 |
| 40 | D | 1 | 9700/11 Oct/Nov 2012 |
| 41 | C | 1 | 9700/12 Oct/Nov 2012 |
| 42 | A | 1 | 9700/12 Oct/Nov 2012 |
| 43 | B | 1 | 9700/13 Oct/Nov 2012 |
| 44 | C | 1 | 9700/13 Oct/Nov 2012 |
| 45 | C | 1 | 9700/13 Oct/Nov 2012 |
| 46 | C | 1 | 9700/11 May/June 2013 |
| 47 | A | 1 | 9700/11 May/June 2013 |
| 48 | C | 1 | 9700/12 May/June 2013 |
| 49 | B | 1 | 9700/12 May/June 2013 |
| 50 | D | 1 | 9700/13 May/June 2013 |
| 51 | B | 1 | 9700/13 May/June 2013 |
| 52 | B | 1 | 9700/12 Oct/Nov 2013 |
| 53 | C | 1 | 9700/12 Oct/Nov 2013 |
| 54 | B | 1 | 9700/12 Oct/Nov 2013 |
| 55 | A | 1 | 9700/12 Oct/Nov 2013 |
| 56 | D | 1 | 9700/13 Oct/Nov 2013 |
| 57 | B | 1 | 9700/13 Oct/Nov 2013 |
| 58 | D | 1 | 9700/11 May/June 2014 |
| 59 | C | 1 | 9700/12 May/June 2014 |
| 60 | A | 1 | 9700/13 May/June 2014 |
| 61 | C | 1 | 9700/13 May/June 2014 |
| 62 | B | 1 | 9700/11 Oct/Nov 2014 |
| 63 | A | 1 | 9700/11 Oct/Nov 2014 |
| 64 | C | 1 | 9700/12 Oct/Nov 2014 |
| 65 | A | 1 | 9700/13 Oct/Nov 2014 |
| 66 | B | 1 | 9700/11 May/June 2015 |
| 67 | D | 1 | 9700/12 May/June 2015 |
| 68 | D | 1 | 9700/12 May/June 2015 |
| 69 | C | 1 | 9700/13 May/June 2015 |
| 70 | C | 1 | 9700/13 May/June 2015 |
| 71 | A | 1 | 9700/13 May/June 2015 |
| 72 | D | 1 | 9700/11 Oct/Nov 2015 |
| 73 | B | 1 | 9700/11 Oct/Nov 2015 |
| 74 | A | 1 | 9700/12 Oct/Nov 2015 |
| 75 | C | 1 | 9700/12 Oct/Nov 2015 |
| 76 | D | 1 | 9700/13 Oct/Nov 2015 |
| 77 | B | 1 | 9700/13 Oct/Nov 2015 |
| 78 | B | 1 | 9700/12 Feb/March 2016 |
| 79 | D | 1 | 9700/12 Feb/March 2016 |
| 80 | B | 1 | 9700/12 Feb/March 2016 |
| 81 | A | 1 | 9700/11 May/June 2016 |
| 82 | B | 1 | 9700/11 May/June 2016 |
| 83 | A | 1 | 9700/12 May/June 2016 |
| 84 | A | 1 | 9700/12 May/June 2016 |
| 85 | B | 1 | 9700/12 May/June 2016 |
| 86 | see sheet | 1 | 9700/13 May/June 2016 |
| 87 | see sheet | 1 | 9700/13 May/June 2016 |
| 88 | see sheet | 1 | 9700/13 May/June 2016 |
| 89 | A | 1 | 9700/11 Oct/Nov 2016 |
| 90 | D | 1 | 9700/11 Oct/Nov 2016 |
| 91 | C | 1 | 9700/13 Oct/Nov 2016 |
| 92 | D | 1 | 9700/13 Oct/Nov 2016 |
| 93 | C | 1 | 9700/12 Feb/March 2017 |
| 94 | A | 1 | 9700/12 Feb/March 2017 |
| 95 | B | 1 | 9700/11 May/June 2017 |
| 96 | A | 1 | 9700/11 May/June 2017 |
| 97 | C | 1 | 9700/12 May/June 2017 |
| 98 | D | 1 | 9700/12 May/June 2017 |
| 99 | D | 1 | 9700/13 May/June 2017 |
| 100 | C | 1 | 9700/12 Oct/Nov 2017 |
| 101 | C | 1 | 9700/13 Oct/Nov 2017 |
| 102 | C | 1 | 9700/13 Oct/Nov 2017 |
| 103 | B | 1 | 9700/12 Feb/March 2018 |
| 104 | C | 1 | 9700/11 May/June 2018 |
| 105 | C | 1 | 9700/11 May/June 2018 |
| 106 | C | 1 | 9700/12 May/June 2018 |
| 107 | A | 1 | 9700/13 May/June 2018 |
| 108 | C | 1 | 9700/13 May/June 2018 |
| 109 | D | 1 | 9700/13 May/June 2018 |
| 110 | D | 1 | 9700/11 Oct/Nov 2018 |
| 111 | D | 1 | 9700/11 Oct/Nov 2018 |
| 112 | A | 1 | 9700/13 Oct/Nov 2018 |
| 113 | C | 1 | 9700/12 Feb/March 2019 |
| 114 | D | 1 | 9700/12 Feb/March 2019 |
| 115 | B | 1 | 9700/11 May/June 2019 |
| 116 | C | 1 | 9700/11 May/June 2019 |
| 117 | B | 1 | 9700/12 May/June 2019 |
| 118 | D | 1 | 9700/12 May/June 2019 |
| 119 | B | 1 | 9700/13 May/June 2019 |
| 120 | A | 1 | 9700/11 Oct/Nov 2019 |
| 121 | A | 1 | 9700/12 Oct/Nov 2019 |
| 122 | B | 1 | 9700/12 Oct/Nov 2019 |
| 123 | C | 1 | 9700/13 Oct/Nov 2019 |
| 124 | A | 1 | 9700/13 Oct/Nov 2019 |
| 125 | B | 1 | 9700/13 Oct/Nov 2019 |
| 126 | D | 1 | 9700/12 Feb/March 2020 |
| 127 | D | 1 | 9700/12 May/June 2020 |
| 128 | C | 1 | 9700/13 May/June 2020 |
| 129 | B | 1 | 9700/13 May/June 2020 |
| 130 | C | 1 | 9700/13 Oct/Nov 2020 |
| 131 | C | 1 | 9700/12 Feb/March 2021 |
| 132 | B | 1 | 9700/11 May/June 2021 |
| 133 | B | 1 | 9700/11 May/June 2021 |
| 134 | C | 1 | 9700/12 May/June 2021 |
| 135 | D | 1 | 9700/12 May/June 2021 |
| 136 | C | 1 | 9700/12 May/June 2021 |
| 137 | D | 1 | 9700/13 May/June 2021 |
| 138 | C | 1 | 9700/13 May/June 2021 |
| 139 | B | 1 | 9700/13 May/June 2021 |
| 140 | D | 1 | 9700/11 Oct/Nov 2021 |
| 141 | D | 1 | 9700/11 Oct/Nov 2021 |
| 142 | C | 1 | 9700/12 Oct/Nov 2021 |
| 143 | B | 1 | 9700/13 Oct/Nov 2021 |
| 144 | A | 1 | 9700/11 May/June 2022 |
| 145 | D | 1 | 9700/12 May/June 2022 |
| 146 | C | 1 | 9700/12 May/June 2022 |
| 147 | C | 1 | 9700/13 May/June 2022 |
| 148 | B | 1 | 9700/13 May/June 2022 |
| 149 | A | 1 | 9700/13 May/June 2022 |
| 150 | B | 1 | 9700/11 Oct/Nov 2022 |
| 151 | B | 1 | 9700/11 Oct/Nov 2022 |
| 152 | D | 1 | 9700/12 Oct/Nov 2022 |
| 153 | B | 1 | 9700/12 Oct/Nov 2022 |
| 154 | D | 1 | 9700/12 Oct/Nov 2022 |
| 155 | B | 1 | 9700/13 Oct/Nov 2022 |
| 156 | D | 1 | 9700/13 Oct/Nov 2022 |
| 157 | C | 1 | 9700/12 Feb/March 2023 |
| 158 | C | 1 | 9700/11 May/June 2023 |
| 159 | B | 1 | 9700/11 May/June 2023 |
| 160 | D | 1 | 9700/11 May/June 2023 |
| 161 | C | 1 | 9700/11 May/June 2023 |
| 162 | B | 1 | 9700/12 May/June 2023 |
| 163 | A | 1 | 9700/12 May/June 2023 |
| 164 | B | 1 | 9700/12 May/June 2023 |
| 165 | B | 1 | 9700/12 May/June 2023 |
| 166 | C | 1 | 9700/12 May/June 2023 |
| 167 | C | 1 | 9700/13 May/June 2023 |
| 168 | C | 1 | 9700/12 Oct/Nov 2023 |
| 169 | C | 1 | 9700/13 Oct/Nov 2023 |
| 170 | B | 1 | 9700/13 Oct/Nov 2023 |
| 171 | D | 1 | 9700/13 Oct/Nov 2023 |
| 172 | C | 1 | 9700/13 Oct/Nov 2023 |
| 173 | B | 1 | 9700/12 Feb/March 2024 |
| 174 | A | 1 | 9700/12 Feb/March 2024 |
| 175 | A | 1 | 9700/11 May/June 2024 |
| 176 | B | 1 | 9700/11 May/June 2024 |
| 177 | D | 1 | 9700/11 May/June 2024 |
| 178 | D | 1 | 9700/12 May/June 2024 |
| 179 | B | 1 | 9700/12 May/June 2024 |
| 180 | B | 1 | 9700/12 May/June 2024 |
| 181 | D | 1 | 9700/13 May/June 2024 |
| 182 | C | 1 | 9700/13 May/June 2024 |
| 183 | C | 1 | 9700/13 May/June 2024 |
| 184 | D | 1 | 9700/11 Oct/Nov 2024 |
| 185 | B | 1 | 9700/11 Oct/Nov 2024 |
| 186 | D | 1 | 9700/11 Oct/Nov 2024 |
| 187 | C | 1 | 9700/11 Oct/Nov 2024 |
| 188 | A | 1 | 9700/12 Oct/Nov 2024 |
| 189 | B | 1 | 9700/12 Oct/Nov 2024 |
| 190 | C | 1 | 9700/12 Oct/Nov 2024 |
| 191 | D | 1 | 9700/13 Oct/Nov 2024 |
| 192 | B | 1 | 9700/13 Oct/Nov 2024 |
| 193 | D | 1 | 9700/13 Oct/Nov 2024 |
| 194 | D | 1 | 9700/12 Feb/March 2025 |
| 195 | C | 1 | 9700/12 May/June 2025 |
| 196 | A | 1 | 9700/13 May/June 2025 |
| 197 | C | 1 | 9700/13 May/June 2025 |
| 198 | D | 1 | 9700/13 May/June 2025 |
| 199 | C | 1 | 9700/13 May/June 2025 |
| 200 | D | 1 | 9700/14 May/June 2025 |
| 201 | D | 1 | 9700/14 May/June 2025 |
| 202 | C | 1 | 9700/11 Oct/Nov 2025 |
| 203 | D | 1 | 9700/11 Oct/Nov 2025 |
| 204 | B | 1 | 9700/13 Oct/Nov 2025 |
| 205 | B | 1 | 9700/13 Oct/Nov 2025 |
| 206 | A | 1 | 9700/13 Oct/Nov 2025 |
3 When not involved in protein synthesis, ribosomes exist as separate subunits. What do these subunits consist of? A mRNA and lipid B mRNA and tRNA C rRNA and lipid D rRNA and protein
1 marks
Answer: D
13 How many different polypeptides, each consisting of r amino acids, can be made if the number of different amino acids available is n ? n r r n n A B C n x r D r
1 marks
Answer: A
22 In the DNA sequence for sickle cell anaemia, adenine replaces thymine in a CTT triplet, forming the triplet CAT. During synthesis of the sickle cell haemoglobin molecule, the amino acid valine is incorporated instead of glutamic acid. What is the anticodon in the transfer RNA molecule carrying this valine? A CAT B CAU C GTA D GUA
1 marks
Answer: B
23 In transcription, what is transcribed and what is the product? transcribed product A DNA mRNA B DNA polypeptide C mRNA DNA D mRNA polypeptide
1 marks
Answer: A
24 The table shows mRNA triplets and their corresponding amino acids. mRNA triplet GCA GCG GAA GAG AAA AAG amino acid ala ala glu glu lys lys A tripeptide is glu-lys-ala. Which sequence of bases in DNA could code for this tripeptide? A CTCCGTTTT B CTTTTCCGT C TTCCGTCTT D TTTCTCCGC
1 marks
Answer: B
23 In a genetic engineering experiment a piece of double-stranded DNA containing 6000 nucleotides is transcribed and translated. What is the total number of amino acids used? A 500 B 1000 C 2000 D 3000
1 marks
Answer: B
24 DNA from a chromosome is analysed and 20 % of its bases are found to be cytosine. Which percentage of uracil molecules will be found in mRNA transcribed from this DNA? A 20 B 30 C 40 D 60
1 marks
Answer: B
22 What terminates the formation of a polypeptide chain during protein synthesis in cells? A when a ‘stop’ codon is reached on the mRNA molecule B when a ‘stop’ codon is reached on the tRNA molecule C when the ribosome reaches the end of the mRNA molecule D when the ribosome reaches the end of the tRNA molecule
1 marks
Answer: A
21 Which type of molecule is the end product of translation? A amino acid B DNA C mRNA D polypeptide
1 marks
Answer: D
22 An unidentified single-stranded molecule was described as having the following features. • complementary base pairing along some of its length • an area that can attach to a ribosome • a site to which a specific amino acid attaches What is the unidentified molecule? A DNA polymerase B messenger RNA C RNA polymerase D transfer RNA
1 marks
Answer: D
23 Some antibacterial drugs can affect the synthesis of proteins. antimicrobial rifampicin streptomycin tetracycline drug mode of binds to RNA genetic code misread prevents binding of action polymerase during translation tRNA to ribosome Which is the correct set of immediate effects of these drugs? antimicrobial rifampicin streptomycin tetracycline drug A defective protein mRNA does not bind to amino acids not added synthesised ribosome to growing chain B mRNA not synthesised defective protein amino acids not added synthesised to growing chain C mRNA not synthesised mRNA does not bind to transcription prevented ribosome D transcription prevented defective protein mRNA does not bind to synthesised ribosome
1 marks
Answer: B
21 The RNA triplet UAG acts as a stop codon terminating the synthesis of a polypeptide. The diagram shows a strand of DNA which codes for four amino acids. Where would a mutation, introducing a thymine nucleotide, result in the termination of transcription? T C C A C T C G A T G C A B C D
1 marks
Answer: B
24 Part of the amino acid sequences in normal and sickle cell haemoglobin are shown. normal haemoglobin sickle cell haemoglobin thr-pro-glu-glu thr-pro-val-glu Possible mRNA codons for these amino acids are glutamine (glu) GAA GAG proline (pro) CCU CCC threonine (thr) ACU ACC valine (val) GUA GUG Which tRNA molecule is not involved in the formation of this part of the sickle cell haemoglobin? A B C D C U C U U A U C A U G G
1 marks
Answer: D
10 Haemoglobin is a globular protein consisting of four polypeptide chains – 2 alpha chains and 2 beta chains. In normal individuals, in the DNA which codes for each beta chain, the sixth triplet has a code for glutamic acid. In individuals with sickle cell anaemia this base triplet changes and codes for valine. What aspect of the haemoglobin molecule does this mutation change? A the iron content B the primary structure C the quaternary structure D the secondary structure
1 marks
Answer: B
21 What is the function of the enzyme RNA polymerase? A to form a polypeptide using mRNA as a template B to form a strand of DNA using mRNA as a template C to form a strand of mRNA using DNA as a template D to form a strand of mRNA using tRNA as a template
1 marks
Answer: C
22 The table gives the tRNA anticodons for four amino acids. amino acid anticodon (tRNA) asparagine UUA glutamic acid CUU proline GGA threonine UGG A cell makes a polypeptide with the amino acid sequence: glutamic acid – asparagine – threonine – proline What was the sequence of bases on the strand of the DNA which was complimentary to the mRNA from which this polypeptide was formed? A CTTTTATGGGGA B CUUUUAUGGGGA C GAAAATACCCCT D GAAAAUACCCCU
1 marks
Answer: A
22 The following statements describe events that take place during DNA replication and transcription. Which statement is not correct? DNA transcription replication A adenine pairs with thymine yes no B both DNA polynucleotide chains act as templates yes no C the original DNA molecule is changed after the process no yes D uracil pairs with adenine no yes
1 marks
Answer: C
23 A peptide consists of ten amino acids of four different kinds. What is the theoretical minimum number of tRNA molecules required to translate the mRNA for this peptide? A 4 B 10 C 12 D 30
1 marks
Answer: A
23 What is the minimum number of base substitutions required to change the nucleotide sequence of the HbA (normal) allele to the HbS (sickle cell) allele? A 1 B 2 C 3 D 4
1 marks
Answer: A
24 In a DNA molecule, the base sequence AGT codes for the amino acid serine. What is the base sequence of the anti-codon on the tRNA to which serine becomes attached? A AGU B GAU C TCA D UCA
1 marks
Answer: A
22 In a DNA molecule, the base sequence AGT codes for the amino acid serine. What is the base sequence of the anti-codon on the tRNA to which serine becomes attached? A AGU B GAU C TCA D UCA
1 marks
Answer: A
40 In a DNA molecule, the base sequence AGT codes for the amino acid serine. What is the base sequence of the anti-codon on the tRNA to which serine becomes attached? A AGU B GAU C TCA D UCA
1 marks
Answer: A
20 Which row shows the correct combination? triplet code codon anticodon A DNA mRNA tRNA B DNA tRNA mRNA C mRNA DNA tRNA D tRNA mRNA DNA
1 marks
Answer: A
22 The following events occur during transcription. 1 Bonds break between complementary bases. 2 Bonds form between complementary bases. 3 Sugar-phosphate bonds form. 4 Free nucleotides pair with complementary nucleotides. Before the mRNA leaves the nucleus, which events will have occurred twice? A 1 and 2 only B 1, 3 and 4 only C 2, 3 and 4 only D 1, 2, 3 and 4
1 marks
Answer: A
21 The table shows the tRNA anticodons for four amino acids. amino acid anticodon (tRNA) asparagine UUA glutamic acid CUU proline GGA threonine UGG A cell makes a polypeptide with the following amino acid sequence. glutamic acid – asparagine – threonine – proline What was the sequence of bases on the DNA from which this was formed? A GGAAATACCCTT B CAAAATACCCCT C CTTTTATGGGGA D CTTTTATCCGGA
1 marks
Answer: C
22 What does the enzyme RNA polymerase synthesise? A a polypeptide from an mRNA template B a strand of DNA from an mRNA template C mRNA from a DNA template D mRNA from a tRNA template
1 marks
Answer: C
29 The following events occur during transcription. 1 Bonds break between complementary bases. 2 Bonds form between complementary bases. 3 Sugar-phosphate bonds form. 4 Free nucleotides pair with complementary nucleotides. Before the mRNA leaves the nucleus, which events will have occurred twice? A 1 and 2 only B 1, 3 and 4 only C 2, 3 and 4 only D 1, 2, 3 and 4
1 marks
Answer: A
20 In a genetic engineering experiment a piece of double-stranded DNA containing 6000 nucleotides coding for a specific polypeptide is transcribed and translated. What is the total number of amino acids in this polypeptide? A 500 B 1000 C 2000 D 3000
1 marks
Answer: B
22 Which molecule has its synthesis directly controlled by DNA? A amylase B cholesterol C glycogen D phospholipid
1 marks
Answer: A
30 Which molecule has its synthesis directly controlled by DNA? A amylase B cholesterol C glycogen D phospholipid
1 marks
Answer: A
32 In a genetic engineering experiment a piece of double-stranded DNA containing 6000 nucleotides coding for a specific polypeptide is transcribed and translated. What is the total number of amino acids in this polypeptide? A 500 B 1000 C 2000 D 3000
1 marks
Answer: B
20 Which statement describes a process that occurs during protein synthesis? A Transcription is the linking together of a tRNA molecule and a specific amino acid. B Transcription is the linking together of free DNA nucleotides. C Translation is the linking together of amino acids coded for by mRNA. D Translation is the synthesis of an mRNA molecule by base pairing of nucleotides with DNA.
1 marks
Answer: C
22 A length of double-stranded DNA contains 120 nucleotides and codes for polypeptide X. What is the maximum length of polypeptide X? A 20 amino acids B 40 amino acids C 60 amino acids D 120 amino acids
1 marks
Answer: A
19 What does the process of transcription require? A ATP, DNA and free nucleotide bases B DNA, mRNA and RNA polymerase C mRNA, ribosomes and RNA polymerase D ribosomes, tRNA and ATP
1 marks
Answer: A
20 A peptide consists of ten amino acids of four different kinds. What is the theoretical minimum number of different tRNA molecules required to translate the mRNA for this peptide? A 4 B 10 C 12 D 30
1 marks
Answer: A
21 Which statements about tRNA structure are correct? 1 There is a binding site for the attachment of a specific amino acid, as well as a different binding site for the attachment to the ribosome, in order to allow translation to occur. 2 There is a ribose-phosphate backbone with strong covalent phosphodiester bonds and areas within the polynucleotide chain where base-pairing by hydrogen bonding occurs. 3 There is a section known as an anticodon that contains the same triplet of bases as the triplet of DNA bases that has been transcribed to produce the mRNA codon. A 1 only B 1 and 2 only C 2 and 3 only D 1, 2 and 3
1 marks
Answer: B
23 A length of double-stranded DNA contains 120 nucleotides and codes for polypeptide X. What is the maximum length of polypeptide X? A 20 amino acids B 40 amino acids C 60 amino acids D 120 amino acids
1 marks
Answer: A
24 Which statement describes a process that occurs during protein synthesis? A Transcription is the linking together of a tRNA molecule and a specific amino acid. B Transcription is the linking together of free DNA nucleotides. C Translation is the linking together of amino acids coded for by mRNA. D Translation is the synthesis of an mRNA molecule by base pairing of nucleotides with DNA.
1 marks
Answer: C
20 What does the process of translation require? A DNA, free nucleotide bases and mRNA B DNA, mRNA and RNA polymerase C mRNA, ribosomes and RNA polymerase D mRNA, ribosomes and tRNA
1 marks
Answer: D
21 Which features of DNA enable it to meet these requirements as a molecule of inheritance? requirement of DNA molecule ability to remain ability to contain ability to transfer ability to replicate stable information information A complementary formation of mRNA sequence of sugar-phosphate base pairing for translation nucleotides backbone B formation of mRNA complementary sugar-phosphate sequence of for translation base pairing backbone nucleotides C sequence of sugar-phosphate complementary formation of mRNA nucleotides backbone base pairing for translation D sugar-phosphate sequence of formation of mRNA complementary backbone nucleotides for translation base pairing
1 marks
Answer: D
22 Which row in the table correctly shows situations in which both DNA and RNA are both involved? replication | transcription | translation v v x key JY involved 0 0O DW > Jv x Jv x Jv x X not involved x x Jv
1 marks
Answer: C
23 The diagram shows the stages in the production of a polypeptide. DNA nucleotide sequence template strand T A C G A C A A T C G C mRNA sequence A U G C U G U U A G C G amino acid sequence met leu leu ala Which feature of the triplet code is illustrated by the information given? A An amino acid can be coded for by more than one triplet. B The triplet code is non-overlapping and is only read in one direction. C The triplet code is universal for the DNA of all organisms. D There are some triplets that code for ‘start’ and ‘stop’.
1 marks
Answer: A
19 The sequence of nucleotides in DNA in a gene that controls the synthesis of a protein is arranged in triplets, each coding for specific amino acids. The table shows three examples of these triplets. triplet code example 1 DNA code TAC 2 mRNA code AUG 3 tRNA code UAC Which are the correct codon and anticodon? codon anticodon A 1 3 B 2 3 C 3 1 D 3 2
1 marks
Answer: B
20 Enzymes are ……1…… proteins, made up of polypeptides. A gene is a sequence of ……2……, which are parts of a ……3…… molecule coding for a polypeptide. Which words correctly complete gaps 1, 2 and 3 in the sentences? 1 2 3 A fibrous amino acids tRNA B fibrous bases DNA C globular nucleotides DNA D globular triplets mRNA
1 marks
Answer: C
21 Which process does not occur during the formation of messenger RNA? A condensation B polymerisation C replication D transcription
1 marks
Answer: C
23 Which type of molecule is always the end product of transcription? A amino acid B functional protein C mRNA D polypeptide
1 marks
Answer: C
24 The table gives tRNA anticodons for four amino acids. amino acid tRNA anticodon asparagine UUA glutamic acid CUU proline GGA threonine UGG A cell makes a polypeptide with the amino acid sequence: glutamic acid – asparagine – threonine – proline What was the sequence of bases on the strand of the DNA which was complementary to the mRNA from which this polypeptide was formed? A CTTTTATGGGGA B CUUUUAUGGGGA C GAAAATACCCCT D GAAAAUACCCCU
1 marks
Answer: A
23 Which type of molecule is the end product of translation? A amino acid B mRNA C polypeptide D tRNA
1 marks
Answer: C
24 A polypeptide molecule contains the amino acid sequence: glycine – leucine – lysine – valine. The table shows DNA codes for these amino acids. glycine leucine lysine valine CCC GAA TTT CAA Which tRNA anticodons are needed for the synthesis of this polypeptide? A CCC GAA TTT CAA B CCC GAA UUU CAA C GGG CUU AAA GUU D GGG CUU UUU GUU
1 marks
Answer: B
22 One gene provides the code for the production of which molecule? A amino acid B DNA C nucleotide D polypeptide
1 marks
Answer: D
23 A polypeptide has the amino acid sequence glycine – arginine – lysine – serine. The table gives possible tRNA anticodons for each amino acid. amino acid tRNA anticodons arginine UCC GCG glycine CCA CCU lysine UUC UUU serine AGG UCG Which sequence of bases on DNA would code for the polypeptide? A CCACGCAAGAGC B CCTTCCTTCTCG C GGAAGGAAAAGC D GGTTGGTTGTGC
1 marks
Answer: B
3 A piece of mammalian tissue was homogenised and centrifuged. The biochemical activity of four subcellular fractions was investigated. Which diagram indicates the fraction with maximum synthesis of messenger RNA? A B lysosomes mitochondria mitochondria activity nuclei ribosomes activity nuclei lysosomes ribosomes C D mitochondria mitochondria lysosomes ribosomes activity activity nuclei ribosomes lysosomes nuclei
1 marks
Answer: B
19 The following statements describe events that take place during DNA replication and transcription. Which row is not correct? DNA transcription replication A adenine pairs with thymine yes no B both DNA polynucleotide chains act as templates yes no C the original DNA molecule is changed after the process no yes D uracil pairs with adenine no yes
1 marks
Answer: C
20 Which statements about complementary base pairing are correct? 1 Purines and pyrimidines are different sizes. 2 It occurs during translation. 3 The base pairs are of different length. 4 Uracil forms two hydrogen bonds with adenine. A 1, 2 and 3 only B 1, 2 and 4 only C 1, 3 and 4 only D 2, 3 and 4 only
1 marks
Answer: B
21 What is the minimum number of base substitutions required to change the nucleotide sequence of the HbA (normal) allele to the HbS (sickle cell) allele? A 1 B 2 C 3 D 4
1 marks
Answer: A
3 What explains why cells with no nucleoli die? A They do not have centrioles and cannot divide. B They do not have mitochondria and cannot release energy. C They do not have mRNA and cannot transcribe DNA. D They do not have ribosomes and cannot synthesise protein.
1 marks
Answer: D
21 Which statements about complementary base pairing are correct? 1 It occurs during translation. 2 Purines and pyrimidines are the same size. 3 The base pairs are of equal length. 4 Uracil forms three hydrogen bonds with adenine. A 1 and 2 only B 1 and 3 only C 2 and 3 only D 3 and 4 only
1 marks
Answer: B
22 Part of the amino acid sequences in normal and sickle cell haemoglobin are shown. normal haemoglobin sickle cell haemoglobin thr-pro-glu-glu thr-pro-val-glu Possible mRNA codons for these amino acids are shown below. glutamine (glu) GAA GAG proline (pro) CCU CCC threonine (thr) ACU ACC valine (val) GUA GUG Which tRNA molecule is not involved in the formation of this part of the sickle cell haemoglobin? A B C D C U C U U A U C A U G G
1 marks
Answer: D
21 What is the correct sequence for the processes involved in the formation of an enzyme in a cell? A transcription → condensation → translation → ionic bonding B translation → hydrogen bonding → transcription → condensation C transcription → translation → condensation → ionic bonding D translation → transcription → ionic bonding → hydrogen bonding
1 marks
Answer: C
24 What terminates the formation of a polypeptide chain during protein synthesis in cells? A when a ‘stop’ codon is reached on the mRNA molecule B when a ‘stop’ codon is reached on the tRNA molecule C when the ribosome reaches the end of the mRNA molecule D when the ribosome reaches the end of the tRNA molecule
1 marks
Answer: A
40 The growth of crop plants is often limited by the availability of nitrogen in the soil. The graph shows the results of an investigation into the yield of a crop plant, with increasing levels of nitrogen supplied. 7 6 5 yield of a crop plant 4 / tonnes per ha 3 2 1 0 0 40 80 120 160 nitrogen supplied / kg per ha Which of the following best explains the shape of this curve? protein synthesis DNA synthesis A increases no effect B no effect no effect C increases increases D no effect increases
1 marks
Answer: C
19 Some antibiotics work by binding to ribosomes and preventing protein synthesis. Which statement explains why these antibiotics kill bacterial cells but not human cells? A In bacterial cells mRNA is formed in the cytoplasm from naked DNA. B Ribosomes in human cells have a different structure from those in bacterial cells. C The antibiotics cannot pass through human cell surface membranes. D The tRNA molecules in bacterial cells are different from those in human cells.
1 marks
Answer: B
20 Which statements about tRNA are correct? 1 contains base pairing 2 contains hydrogen bonds 3 is single stranded A 1, 2 and 3 B 1 and 2 only C 1 and 3 only D 2 and 3 only
1 marks
Answer: A
5 Which sequence shows some of the stages in the production and secretion of an enzyme? A Golgi apparatus → ribosome → rough endoplasmic reticulum → mRNA B mRNA → smooth endoplasmic reticulum → Golgi apparatus → vesicle C ribosome → rough endoplasmic reticulum → vesicle → Golgi apparatus D smooth endoplasmic reticulum → mRNA → vesicle → ribosome
1 marks
Answer: C
21 Which molecules are involved in transcription and which molecules are involved in translation? transcription translation A DNA and mRNA mRNA and tRNA B DNA and tRNA mRNA and amino acids C mRNA and amino acids DNA and mRNA D tRNA and mRNA amino acids and DNA
1 marks
Answer: A
20 Which row shows two pairs of nucleotides formed during transcription? first base pair transcribed second base pair transcribed number of number of bases bases hydrogen bonds hydrogen bonds A AU 2 CG 2 B AU 2 CG 3 C AU 2 TU 2 D AU 3 CG 2
1 marks
Answer: B
20 What is needed to transcribe DNA? A DNA ligase B DNA polymerase C ribosomes D RNA polymerase
1 marks
Answer: D
21 In a ribosome, which bond holds together two adjacent amino acids? A disulfide B hydrogen C ionic D peptide
1 marks
Answer: D
4 Ribosomes exist as separate subunits that bind together during protein synthesis. What do these subunits consist of? A mRNA and protein B mRNA and tRNA C rRNA and protein D rRNA and tRNA
1 marks
Answer: C
21 Which row shows two pairs of nucleotides formed when mRNA is translated? first base pair translated second base pair translated number of number of bases present bases present hydrogen bonds hydrogen bonds A AT 2 TU 2 B AU 2 AT 2 C AU 2 GC 3 D AU 3 GC 3
1 marks
Answer: C
22 Sickle cell anaemia is caused by a mutation in an allele of the gene that codes for the β-globin polypeptide of haemoglobin. The diagram shows the sequence of bases in a small section of the coding strand of DNA for both the HbA (normal) and HbS (sickle cell) β-globin alleles. HbA CTGACTCCTGAGGAGAAGTCT HbS CTGACTCCTGTGGAGAAGTCT How will the mutation in the HbS allele result in the production of an altered version of the β-globin polypeptide? A A tRNA molecule with the anticodon GUG will hydrogen bond to the altered codon on mRNA. B All the amino acids coded for after the mutation will differ from those in the HbA protein. C mRNA transcribed from the HbS allele will contain the codon CAC instead of the codon CTC. D The ribosome will be unable to continue translation of the HbS mRNA after the altered codon.
1 marks
Answer: A
20 The statements describe the features of some nucleic acids. 1 carry an amino acid to a ribosome 2 carry a genetic code sequence out of the nucleus 3 carry a genetic code sequence to a ribosome Which functions are carried out only by mRNA? A 1, 2 and 3 B 1 and 2 only C 1 and 3 only D 2 and 3 only
1 marks
Answer: D
21 The antibiotic chloramphenicol prevents prokayotes from reproducing by inhibiting the enzyme which catalyses the formation of peptide bonds during translation. What will be prevented by the action of this antibiotic? A binding of amino acids to tRNA B condensation of amino acids C pairing between codons and anticodons D positioning of amino acids by tRNA
1 marks
Answer: B
20 What occurs during DNA replication and transcription and translation? 1 ATP provides energy. 2 Condensation reactions occur to form a polymer. 3 Hydrogen bonds form between purine and pyrimidine bases. A 1, 2 and 3 B 1 and 2 only C 2 only D 3 only
1 marks
Answer: A
21 Ricin is a toxic protein which inactivates ribosomes. Which effect will this have on protein synthesis? A Amino acids will be unable to bind to the binding sites on specific tRNA molecules. B Anticodons on mRNA molecules will not base pair to codons on tRNA molecules. C Peptide bonds will not form between adjacent amino acids in the growing polypeptide. D RNA nucleotides will be unable to join by condensation reactions to form rRNA.
1 marks
Answer: C
20 Which statements describe how a gene mutation can lead to the production of a non-functional protein? 1 During transcription an incorrect nucleotide is added to a DNA molecule. 2 A codon in the mRNA transcribed from the mutated gene is changed. 3 The order of the bases in an anticodon on tRNA is altered during translation. A 1, 2 and 3 B 1 and 2 only C 2 and 3 only D 2 only
1 marks
Answer: D
21 Some antibiotics kill prokaryotes by binding to RNA polymerase. What effect will this have on protein synthesis? A Codons on mRNA will be unable to hydrogen bond to complementary anticodons on tRNA. B Condensation reactions joining RNA nucleotides will not take place to form mRNA. C DNA will not unwind and unzip to allow for base-pairing with RNA nucleotides. D Free RNA nucleotides will not base-pair to exposed bases on the DNA template strand.
1 marks
Answer: B
2 The electron micrograph shows part of a eukaryotic cell. Which of the labelled organelles is a site of protein synthesis? A B C D
1 marks
Answer: B
21 One gene provides the code for the production of which type of molecule? A amino acid B DNA C nucleotide D polypeptide
1 marks
Answer: D
22 The table shows the mode of action of two antibacterial drugs that can affect the synthesis of proteins. antibacterial rifampicin streptomycin drug mode of binds to RNA causes errors in action polymerase translation If bacteria are treated with both drugs, what will be the immediate effects? 1 Transcription will stop, but faulty proteins may continue to be synthesised. 2 If translation has started, proteins may be faulty. 3 Translation will be inhibited. A 1, 2 and 3 B 1 and 2 only C 1 and 3 only D 2 and 3 only
1 marks
Answer: B
21 The diagram shows the nucleotide sequence of a small section of a gene which is transcribed. CGCCGCACGCGC The table shows the amino acids coded for by 10 mRNA codons. mRNA codon amino acid AAG Lys ACG Thr CGG CGC CGU Arg CCG Pro GCC GCG Ala GGC Gly UGC Cys What is the order of the four amino acids in the polypeptide translated from this small section of a gene? A Ala-Ala-Cys-Ala B Ala-Arg-Gly-Ala C Arg-Ala-Pro-Arg D Arg-Arg-Thr-Arg
1 marks
Answer: A
22 The statements describe the features of some nucleic acids. 1 carry an amino acid to a ribosome 2 carry a genetic code sequence out of the nucleus 3 carry a genetic code sequence to a ribosome 4 hold amino acids in position for translation Which functions are carried out by tRNA? A 1 and 2 B 1 and 4 C 2 and 3 D 3 and 4
1 marks
Answer: B
19 Which statements about complementary base pairing are correct? 1 Cytosine forms three hydrogen bonds with guanine. 2 Purines and pyrimidines are different sizes. 3 It allows transcription to occur. 4 The base pairs are of different lengths. A 1, 2 and 3 B 1, 2 and 4 C 1, 3 and 4 D 2, 3 and 4
1 marks
Answer: A
21 Which statements about tRNA are correct? 1 It contains base pairing. 2 It contains hydrogen bonds. 3 It contains uracil. 4 It is single stranded. A 1, 2, 3 and 4 B 1, 3 and 4 only C 1 and 2 only D 2 and 3 only
1 marks
Answer: A
22 The diagram shows the nucleotide sequence of a small section of a gene which is transcribed. TTCTTCCCGTTC The table shows the amino acids coded for by 10 mRNA codons. mRNA codon amino acid AAG Lys ACG Thr CGG CGC CGU Arg CCG Pro GCC GCG Ala GGC Gly UGC Cys What is the order of the four amino acids in the polypeptide translated from this small section of a gene? A Cys-Cys-Gly-Cys B Lys-Lys-Gly-Lys C Lys-Lys-Pro-Lys D Thr-Thr-Pro-Thr
1 marks
Answer: B
5 Which types of RNA are found in both prokaryotic and eukaryotic cells? mRNA rRNA tRNA v v v key /¥ = present X = absent 0 OD D> ~ « & a aN x < x
1 marks
18 Which processes occur in bone marrow cells that are in a mitotic cell cycle? 1 phosphate groups bind to ADP molecules to form ATP 2 bonds form between nucleotides in a DNA strand 3 tRNA anticodons hydrogen bond with codons on mRNA A 1, 2 and 3 B 1 and 2 only C 1 and 3 only D 2 only
1 marks
22 The diagram shows the nucleotide sequence of a small section of a gene which is transcribed. CGGGCCCCGCGG The table shows the amino acids coded for by 10 mRNA codons. mRNA codon amino acid AAG Lys ACG Thr CGG CGC CGU Arg CCG Pro GCC GCG Ala GGC Gly UGC Cys What is the order of the four amino acids in the polypeptide translated from this small section of a gene? A Ala-Ala-Cys-Ala B Ala-Arg-Gly-Ala C Arg-Ala-Pro-Arg D Arg-Arg-Thr-Arg
1 marks
21 When a gene mutation occurs, which of the following may be altered, resulting in the production of a non-functional protein? 1 amino acid sequence 2 DNA nucleotide sequence 3 mRNA nucleotide sequence A 1, 2 and 3 B 1 and 2 only C 2 and 3 only D 2 only
1 marks
Answer: A
22 The diagram shows the nucleotide sequence of a small section of a gene which is transcribed. GCAGCATGCGCG The table shows the amino acids coded for by 10 mRNA codons. mRNA codon amino acid AAG Lys ACG Thr CGG CGC CGU Arg CCG Pro GCC GCG Ala GGC Gly UGC Cys What is the order of the four amino acids in the polypeptide translated from this small section of a gene? A Ala-Ala-Cys-Ala B Ala-Arg-Gly-Ala C Arg-Ala-Pro-Arg D Arg-Arg-Thr-Arg
1 marks
Answer: D
21 The diagram shows the nucleotide sequence of a small section of a gene which is transcribed. GCGCGCGGCCGC The table shows the amino acids coded for by 10 mRNA codons. mRNA codon amino acid AAG Lys ACG Thr CGG CGC CGU Arg CCG Pro GCC GCG Ala GGC Gly UGC Cys What is the order of the four amino acids in the polypeptide translated from this small section of a gene? A Ala-Ala-Cys-Ala B Ala-Arg-Gly-Ala C Arg-Ala-Pro-Ala D Arg-Arg-Thr-Arg
1 marks
Answer: C
22 The following events occur during transcription. 1 Bonds break between complementary bases. 2 Bonds form between complementary bases. 3 Sugar-phosphate bonds form. 4 Free nucleotides pair with complementary nucleotides. Before the mRNA molecule leaves the nucleus, which events will have occurred twice? A 1, 2, 3 and 4 B 1, 3 and 4 only C 2, 3 and 4 only D 1 and 2 only
1 marks
Answer: D
25 Rifampicin is an antibiotic used to treat tuberculosis. It works by inhibiting RNA polymerase in bacteria. Which of these processes will be directly inhibited by this antibiotic? 1 ATP synthesis 2 transcription 3 translation A 1 and 2 B 1 and 3 C 2 only D 3 only
1 marks
Answer: C
27 The diagram shows the stages in the production of part of a polypeptide. DNA nucleotide sequence template strand T A C G A C A A T C G C mRNA sequence A U G C U G U U A G C G amino acid sequence met leu leu ala Which feature of the triplet code is illustrated by the information given? A An amino acid can be coded for by more than one triplet. B The triplet code is non-overlapping and is only read in one direction. C The triplet code is universal for the DNA of all organisms. D There are some triplets that code for ‘start’ and ‘stop’.
1 marks
Answer: A
5 Some secretory cells synthesise and release glycoproteins. What is the correct order of the sequence of events as they occur in the secretory cell? 1 exocytosis 2 product accumulates in secretory vesicle 3 mRNA binds to ribosomes 4 synthesis of glycoprotein A 3, 4, 1, 2 B 3, 4, 2, 1 C 4, 3, 1, 2 D 4, 3, 2, 1
1 marks
Answer: B
25 Which statements about tRNA are correct? 1 contains base pairing 2 contains hydrogen bonds 3 is single stranded A 1, 2 and 3 B 1 and 2 only C 1 and 3 only D 2 and 3 only
1 marks
Answer: A
19 Different tissues in a plant were supplied with a radioactively labelled substance to identify which tissues were actively synthesising mRNA. Which radioactively labelled substances would be most suitable for this experiment? 1 adenine 2 ribose 3 inorganic phosphate 4 uracil A 1, 2, 3 and 4 B 1, 2 and 3 only C 2 and 4 only D 4 only
1 marks
Answer: C
20 Electron micrographs may show large numbers of ribosomes forming chains along mRNA molecules. What is the advantage of this arrangement, compared to when ribosomes appear singly on the mRNA? A Different polypeptides can be produced simultaneously. B Fewer tRNA molecules are required to translate the polypeptide. C Large polypeptide chains can be produced. D Polypeptides can be produced more rapidly.
1 marks
Answer: D
21 Which statement is correct? A During transcription, mRNA is synthesised from DNA nucleotides to have the same sequence of nucleotides as the DNA strand on which it was made. B During transcription, tRNA is synthesised from RNA nucleotides and carries codons that are complementary to the sequence of nucleotides on the DNA strand on which it was made. C During translation, mRNA is synthesised from RNA nucleotides to have the complementary sequence of nucleotides to that of the DNA strand on which it was made. D During translation, ribosomes join amino acids in a sequence determined by mRNA with the complementary sequence of nucleotides to that of the DNA strand on which it was made.
1 marks
Answer: D
25 The diagram shows the nucleotide sequence of a small section of a gene which is transcribed. GCGCGCGGCGCG The table shows the amino acids coded for by 10 mRNA codons. mRNA codon amino acid AAG Lys ACG Thr CGG CGC CGU Arg CCG Pro GCC GCG Ala GGC Gly UGC Cys What is the order of the four amino acids in the polypeptide translated from this small section of a gene? A Ala-Ala-Cys-Ala B Ala-Arg-Gly-Ala C Arg-Ala-Pro-Arg D Arg-Arg-Thr-Arg
1 marks
Answer: C
3 A cell was supplied with cytosine labelled with radioactive carbon. In which cell structure would radioactivity be detected first? A endoplasmic reticulum B Golgi body C nucleus D ribosome
1 marks
Answer: C
23 Rifampicin is an antibiotic used to treat tuberculosis. It works by inhibiting RNA polymerase in bacteria. Which of these processes are prevented by this antibiotic? 1 DNA replication 2 transcription 3 translation A 1, 2 and 3 B 1 and 2 only C 2 and 3 only D 3 only
1 marks
Answer: C
25 The table shows three anticodons for different amino acids. amino acid anticodon alanine CGU histidine GUA serine UCA Which DNA triplet on the DNA template strand codes for the amino acid serine? A AGU B TCA C TGT D UCA
1 marks
Answer: B
5 Radioactively-labelled nucleotides are introduced into a cell. 1 2 3 4 In which cell structures will the radioactivity first become concentrated? A 1 and 2 B 1 and 4 C 2 and 3 D 3 and 4
1 marks
Answer: C
23 Which is the correct DNA triplet on the original DNA template that codes for the amino acid histidine (His)? amino acid anticodon Ala CGU His GUA Ser UCA A CAU B CGT C GTA D GUA
1 marks
Answer: C
25 Which statements about tRNA are correct? 1 Hydrogen bonds between bases temporarily hold tRNA against mRNA. 2 The base sequences in the tRNA molecules are the same as the base sequences in the mRNA that is being translated. 3 The specificity of the tRNA molecule for glycine and the specificity of the enzyme that loads glycine are both necessary for correct loading. A 1, 2 and 3 B 1 and 2 only C 1 and 3 only D 2 and 3 only
1 marks
Answer: C
24 What occurs during each of DNA replication and transcription and translation? 1 ATP provides energy. 2 Condensation reactions occur to form a polymer. 3 Hydrogen bonds form between purine and pyrimidine bases. A 1, 2 and 3 B 1 and 2 only C 2 only D 3 only
1 marks
Answer: A
25 Part of a sequence of DNA from a person with a genetic disease is: TAGTAACCACAAAGG The corresponding sequence of DNA from a person without this genetic disease is: TAGTAAAAACCACAAAGG The possible mRNA codons for some amino acids are shown in the table. amino acid mRNA codons 1 GGU GGC GGA GGG 2 AUU AUC AUA 3 UUU UUC 4 UCU UCC UCA UCG Which amino acid is missing from a person with this genetic disease? A 1 B 2 C 3 D 4
1 marks
Answer: C
38 Some antibiotics work by binding to ribosomes. Which statement explains why these antibiotics kill bacteria cells but do not kill most human cells? A mRNA in bacteria is formed in the cytoplasm from naked DNA. B The antibiotics cannot pass through human cell membranes. C The codes used for amino acids in bacteria are different from those used by humans. D The ribosomes of bacteria have a different structure from those of humans.
1 marks
Answer: D
12 Which statements about the primary structure of a protein are correct? 1 It may be branched. 2 It is determined by the sequence of DNA bases. 3 It is unique to that protein. 4 It determines the tertiary structure of the protein. A 1, 2 and 3 B 1, 2 and 4 C 1, 3 and 4 D 2, 3 and 4
1 marks
Answer: D
23 Following translation, the alpha polypeptide chain of haemoglobin, α-globin, undergoes modification. During this modification, the first amino acid is removed, leaving 141 amino acid residues. How many nucleotides does the gene coding for α-globin contain? A 141 B 142 C 423 D 426
1 marks
Answer: D
23 A length of double-stranded DNA contains 120 nucleotides and codes for a section of a polypeptide. What is the maximum length of this section of a polypeptide? A 20 amino acids B 40 amino acids C 60 amino acids D 120 amino acids
1 marks
Answer: A
6 Ribosomes exist as separate subunits that are bound together during protein synthesis. What do these subunits consist of? A mRNA and protein B mRNA and tRNA C rRNA and protein D rRNA and tRNA
1 marks
Answer: C
22 Rifampicin is an antibiotic used to treat tuberculosis (TB). It works by inhibiting RNA polymerase in bacteria. Which processes are directly inhibited by this antibiotic? 1 DNA replication 2 transcription 3 ATP synthesis A 1, 2 and 3 B 1 and 2 only C 1 and 3 only D 2 only
1 marks
Answer: D
24 In a genetic engineering experiment a piece of double-stranded DNA containing 6000 nucleotides coding for a specific polypeptide is transcribed and translated. What is the total number of amino acids in this polypeptide? A 500 B 1000 C 2000 D 3000
1 marks
Answer: B
25 Which statements about tRNA are correct? 1 Hydrogen bonds between bases temporarily hold tRNA against mRNA. 2 The base sequences in the tRNA molecules are the same as the base sequences in the mRNA that is being translated. 3 tRNA translates the base sequence in mRNA into the amino acid sequence in a protein. A 1, 2 and 3 B 1 and 2 only C 1 and 3 only D 2 and 3 only
1 marks
Answer: C
19 Which statements about complementary base pairing are correct? 1 It allows translation to occur. 2 Purines and pyrimidines are the same size. 3 The base pairs are of equal length. 4 Uracil forms two hydrogen bonds with adenine. A 1, 2, 3 and 4 B 1, 3 and 4 only C 1 and 4 only D 2 and 3 only
1 marks
Answer: B
21 The diagram shows part of the DNA sequence of a gene and a mutated sequence of the same gene. normal DNA sequence ... CCG GAT TAT TGC GAG AAA TGG CAT TCT AGG ... mutated DNA sequence ... CCG GAT GTA TTG CGA GAA ATG CAT TCT AGG ... What are possible effects of the mutated sequence? 1 the presence of mRNA stop codons, UAG, UAA or UGA 2 a change in the sequence of amino acids 3 a non-functional protein 4 ribosomes cannot translate the mRNA A 1, 2 and 3 B 1, 3 and 4 C 1 and 4 only D 2 and 3 only
1 marks
Answer: D
28 The table shows the DNA triplet codes for some amino acids. amino acid DNA triplet code amino acid DNA triplet code arginine GCA glycine CCA arginine GCC glycine CCG arginine GCG glycine CCT asparagine TTA lysine TTC asparagine TTG lysine TTT STOP ATC proline GGA cysteine ACA proline GGC cysteine ACG valine CAC The base sequence on the DNA strand coding for a polypeptide is shown. CCA TTC ACG GCG TTA GCA Two mutations occur in this sequence during DNA replication. Which mutated DNA would have no effect on the polypeptide synthesised? A CCA ATC ACG GCG TTG GCA B CCA TTC ACA GCA TTA GCA C CCA TTC ACG CCG TTA GCC D CCT TTC ACG GCG TTA GGA
1 marks
Answer: B
23 Sickle cell anaemia is caused by a mutation in an allele of the gene that codes for the β-globin polypeptide of haemoglobin. The diagram shows the sequence of bases in a small section of the coding strand of DNA for both the HbA (normal) and HbS (sickle cell) β-globin alleles. HbA CTGACTCCTGAGGAGAAGTCT HbS CTGACTCCTGTGGAGAAGTCT How will the mutation in the allele result in the production of an altered version of the β-globin polypeptide? A A tRNA molecule with the anticodon GUG will hydrogen bond to the altered codon on mRNA. B All the amino acids coded for after the mutation will differ from those in the HbA protein. C mRNA transcribed from the HbS allele will contain the codon CAC instead of the codon CTC. D The ribosome will be unable to continue translation of the HbS mRNA after the altered codon.
1 marks
Answer: A
6 Which types of RNA are present in prokaryotic cells and in eukaryotic cells? mRNA rRNA tRNA v v v key v¥ = present 0 0O WwW > v v x x Jv J X = not present x Jv x
1 marks
Answer: A
22 The RNA triplet UAG acts as a stop codon terminating the synthesis of a polypeptide. The diagram shows a strand of DNA which codes for four amino acids. Where would an insertion mutation of a thymine nucleotide result in the termination of translation? T C C A C T C G A T G C A B C D
1 marks
Answer: B
9 Three proteins that have a quaternary structure are listed. • Type IX collagen is formed from three different polymers. • The main form of haemoglobin contains two alpha globins and two beta globins. • HIV protease consists of two identical polymers. Which row shows the correct number of genes needed to code for each protein? number of genes type IX HIV haemoglobin collagen protease A 1 2 2 B 1 4 1 C 3 2 1 D 3 4 2
1 marks
Answer: C
21 What is the maximum number of codon-anticodon interactions within one ribosome? A 2 B 3 C 4 D 6
1 marks
Answer: A
23 Which statements about tRNA structure are correct? 1 There is a binding site for the attachment of a specific amino acid and a different binding site for the attachment to the ribosome, so that translation can occur. 2 There is a ribose-phosphate backbone with strong phosphodiester bonds and areas within the polynucleotide chain where base pairing occurs. 3 There is an anticodon that contains the same triplet of bases as the triplet of DNA bases that has been transcribed to produce the mRNA codon. A 1, 2 and 3 B 1 and 2 only C 1 only D 2 and 3 only
1 marks
Answer: B
24 The table shows the tRNA anticodons for four amino acids. amino acid tRNA anticodons asparagine UUA, UUG glutamic acid CUU, CUC proline GGA, GGG, GGU, GGC threonine UGA, UGG, UGU, UGC A cell makes a polypeptide containing the amino acid sequence shown. asparagine – threonine – proline – glutamic acid Which sequence of bases on the transcribed strand of a DNA molecule could code for this part of the polypeptide? A AATACCCCTGAA B AATACCCCTCAA C TTACTTGGATGG D TTATGGGGACTT
1 marks
Answer: D
24 Part of the nucleotide sequence of an mRNA molecule is shown, with spaces between the codons. CAG UAC AGC AAU CUA UAA The translation of the codons is provided. amino acid codon or STOP AAU asn AGC ser CAG gln CUA leu UAA STOP UAC tyr UAU tyr Which events will cause the termination of polypeptide synthesis during translation? 1 Deletion of C from the leu codon. 2 Deletion of C from the tyr codon. 3 The ribosome reaching the UAA codon. A 1, 2 and 3 B 1 and 2 only C 1 and 3 only D 2 and 3 only
1 marks
Answer: D
22 The sequence of bases in mRNA for the first eight amino acids in the β-polypeptide of adult haemoglobin is: GUG–CAC–CUG–ACU–CCU–GAG–GAG–AAG. In haemoglobin C, which is a cause of haemolytic anaemia, the sequence is: GUG–CAC–CUG–ACU–CCU–AAG–GAG–AAG. The coding for seven of the amino acids is listed. amino acid DNA triplet glu CTC his GTG leu GAG lys TTC pro GGA thr TGA phe AAG Which change occurs to the amino acid sequence of adult haemoglobin to make haemoglobin C? A Histidine is changed to leucine. B Proline is changed to threonine. C Glutamic acid is changed to lysine. D Leucine is changed to phenylalanine.
1 marks
Answer: C
23 Some antibiotics kill prokaryotes by binding to RNA polymerase. What effect will this have on protein synthesis? A Codons on mRNA will be unable to hydrogen bond to complementary anticodons on tRNA. B Condensation reactions joining RNA nucleotides will not take place to form mRNA. C DNA will not unwind and unzip to allow for base pairing with RNA nucleotides. D Free RNA nucleotides will not base pair to exposed bases on the DNA template strand.
1 marks
Answer: B
24 A molecule of transfer RNA (tRNA) has the anticodon sequence UAC. What will be the corresponding nucleotide sequence in the DNA? A ATG B AUG C TAC D TUG
1 marks
Answer: C
21 A piece of double-stranded DNA containing 12 103 nucleotides is transcribed and translated to produce a single polypeptide. What is the maximum number of amino acids in this polypeptide? A 6 103 B 4 103 C 2 103 D 1 103
1 marks
Answer: C
21 The statements describe the process of translation. 1 A peptide bond forms between adjacent amino acids. 2 Hydrogen bonds form between the anticodon and the codon. 3 mRNA binds to the ribosome. 4 tRNA enters the ribosome carrying a specific amino acid. In which order does this process take place? A 3 2 1 4 B 3 4 2 1 C 4 2 1 3 D 4 2 3 1
1 marks
Answer: B
22 The sequence of amino acids in a section of a polypeptide is: … histidine–proline–aspartic acid–leucine... amino acid possible DNA triplet codes aspartic acid CTA CTG histidine GTA GTG leucine GAT GAC proline GGA GGG What is a correct sequence of mRNA codons for this polypeptide section? A …CAC CCC GAA CUG… B …CAU CCU GAC CUA… C …GTA CCA CTG GAT… D …GUA GGA CUG GAU…
1 marks
Answer: B
3 Which sequence shows the correct order of some of the stages in the production and secretion of an enzyme? A Golgi body ribosome rough endoplasmic reticulum mRNA B mRNA smooth endoplasmic reticulum Golgi body vesicle C ribosome rough endoplasmic reticulum vesicle Golgi body D smooth endoplasmic reticulum mRNA vesicle ribosome
1 marks
Answer: C
21 The diagram shows a strand of DNA and mRNA during transcription. 1 2 P C G P P G C P 3 Which row correctly identifies 1, 2 and 3? 1 2 3 A purine deoxyribose two hydrogen bonds B purine ribose three hydrogen bonds C pyrimidine deoxyribose two hydrogen bonds D pyrimidine ribose three hydrogen bonds
1 marks
Answer: D
22 Two students were discussing the involvement of DNA and RNA in transcription and translation. Student 1 always stated correct facts. Student 2 gave further information, which was sometimes correct. correct facts given by student 1 further information given by student 2 1 A length of mRNA is 747 nucleotides This mRNA can produce a polypeptide long, including stop and start codons. that is 249 amino acids long. 2 Adjacent mRNA codons of AAU There is a total of 14 hydrogen bonds and CUG bind to complementary formed between these two codons and tRNA anticodons. their anticodons. 3 RNA polymerase catalyses the formation During translation, an RNA adenine of the mRNA from the template strand nucleotide will pair with a DNA thymine of DNA. nucleotide. 4 A DNA adenine nucleotide is structurally The difference is in the hexose sugars; different to an RNA adenine nucleotide. DNA is deoxyribose and RNA is ribose. Which further information, given by student 2, is correct? A 1 and 4 B 2 and 3 C 2 only D 4 only
1 marks
Answer: C
21 Some of the events that occur during transcription are listed. 1 Bonds break between complementary bases. 2 Bonds form between complementary bases. 3 Sugar-phosphate bonds form. 4 Free nucleotides pair with complementary nucleotides. Before the mRNA molecule leaves the nucleus, which events occur twice during transcription? A 1, 2 and 3 B 1, 3 and 4 C 2, 3 and 4 D 1 and 2 only
1 marks
Answer: D
22 The table shows the DNA triplet codes for some amino acids. amino acid DNA triplet code amino acid DNA triplet code arginine GCA glycine CCA arginine GCC glycine CCG arginine GCG glycine CCT asparagine TTA lysine TTC asparagine TTG lysine TTT cysteine ACA proline GGA cysteine ACG proline GGC STOP ATC valine CAC The base sequence on the DNA template strand coding for part of a polypeptide is shown. CCA TTC ACG GCG TTA GCA Two mutations occur in this sequence during DNA replication. Which mutated DNA would result in a polypeptide with one different amino acid? A CCA ATC ACG GCG TTG GCA B CCA TTC ACA GCA TTA GCA C CCA TTC ACG CCG TTA GCC D CCT TTC ACG GCG TTA GCC
1 marks
Answer: C
23 A gene codes for the sequence of amino acids in a single polypeptide. Haemoglobin consists of two -globins and two -globins. How many genes are needed to code for a single haemoglobin molecule? A 1 B 2 C 4 D 8
1 marks
Answer: B
3 In which cell structures does DNA transcription occur? chloroplast A D mitochondrion nucleus C B
1 marks
Answer: D
24 What is the correct tRNA anticodon coding for the amino acid proline? DNA triplet code amino acid on transcribed strand alanine CGT histidine GTG proline GGT A CCA B CCU C GGT D GGU
1 marks
Answer: D
23 The mRNA sequences of the three stop codons are shown. UAA UAG UGA Which mutation in the template (transcribed) strand of a DNA sequence that codes for a polypeptide would cause translation to stop prematurely? A ATT changed to ATC B ACT changed to ACA C ACC changed to ATT D ATC changed to TAG
1 marks
Answer: C
22 When a gene for protease is activated, which nucleic acid will be formed? A DNA B mRNA C rRNA D tRNA
1 marks
Answer: B
25 A student sketched a diagram to represent the process of transcription. Which part of their diagram shows the non-transcribed strand? T A A T A G C B C G T U A T U A C C G direction of D A A T transcription C C G G G C G G C T A T A C A T C G
1 marks
Answer: A
22 Rifampicin is an antibiotic used to treat tuberculosis. It works by inhibiting RNA polymerase in bacteria. Which processes are directly inhibited by this antibiotic? 1 DNA replication 2 enzyme synthesis 3 ATP synthesis A 1, 2 and 3 B 1 and 2 only C 1 and 3 only D 2 only
1 marks
Answer: D
23 The table shows the DNA triplet codes for some amino acids. amino acid DNA triplet code amino acid DNA triplet code arginine GCA glycine CCA arginine GCC glycine CCG arginine GCG glycine CCT asparagine TTA lysine TTC asparagine TTG lysine TTT cysteine ACA proline GGA cysteine ACG proline GGC STOP ATC valine CAC The base sequence on the template DNA strand coding for part of a polypeptide is shown. CCA ACG GCG TTA TTC GCA Two mutations occur in this sequence during DNA replication. Which mutated template DNA strand would result in a shorter polypeptide? A CCA ACA GCA TTA TTC GCA B CCA ACG CCG TTA TTC GCC C CCA ACG GCG TTG ATC GCA D CCT ACG GCG TTA TTC GGA
1 marks
Answer: C
22 Which statement about the transcription and translation of a gene is correct? A The non-transcribed strand of DNA has a base sequence that is identical to the mRNA produced in transcription. B The template strand of DNA has a base sequence that is identical to the mRNA produced in transcription. C The non-transcribed strand of DNA has a base sequence that is complementary to the tRNA molecules required in translation. D The template strand of DNA has a base sequence that is complementary to the tRNA molecules required in translation.
1 marks
Answer: C
23 Which statement about mRNA is correct? A The primary transcript becomes modified by the joining of introns to become mRNA. B The primary transcript is synthesised and then modified to mRNA in the nucleus. C mRNA contains nucleotides containing the sugar deoxyribose. D The bases in mRNA are held together by covalent bonds.
1 marks
Answer: B
25 The sequence of bases in DNA coding for the first eight amino acids in the -polypeptide of adult haemoglobin is: CAC GTG GAC TGA GGA CTC CTC TTC However, in haemoglobin C, which is a cause of haemolytic anaemia, it becomes: CAC GTG GAC TGA GGA TTC CTC TTC Some of the DNA triplets that code for the amino acids are listed in the table. amino acid DNA triplet Glu CTC His GTG Leu GAG Lys TTC Pro GGA Thr TGA Which change occurs to the amino acid sequence of normal haemoglobin to make it haemoglobin C? A Glutamic acid is changed to lysine. B Histidine is changed to leucine. C Leucine is changed to lysine. D Proline is changed to threonine.
1 marks
Answer: A
24 The sequence shows the series of bases at the start of a gene. TAC CGA CCA CCA CAA CCA CGA... After transcription, the mRNA was translated via tRNA into a sequence of amino acids. When this part of the polypeptide was analysed, it was found to contain the amino acids in the table. amino acid number present Ala 2 Gly 3 Met 1 Val 1 What is the sequence of amino acids in this part of the polypeptide? A Met Ala Gly Ala Gly Gly Val B Met Ala Gly Gly Val Gly Ala C Met Gly Ala Ala Val Ala Gly D Met Gly Ala Ala Gly Gly Val
1 marks
Answer: B
25 The table shows the mode of action of two antibacterial drugs that can affect the synthesis of proteins. antibacterial rifampicin streptomycin drug mode of binds to RNA causes errors in action polymerase translation If bacteria are treated with the drugs rifampicin and streptomycin, what will be the immediate effects? 1 Transcription will stop but faulty proteins may continue to be synthesised. 2 If translation has started, proteins may be faulty. 3 Translation will be inhibited. A 1, 2 and 3 B 1 and 2 only C 1 and 3 only D 2 and 3 only
1 marks
Answer: B
23 A section of the polypeptide coding for the haemoglobin β-chain contains the following amino acids. – Pro – Glu – Glu – Patients with sickle cell anaemia have mutated β-polypeptide chains. The section of the mutated polypeptide contains the following amino acids. – Pro – Val – Glu – The table shows the possible anticodons for Val. amino acid anticodon Val C A A Val C A G Val C A C Val C A U What is the corresponding DNA triplet code for the substituted amino acid in the mutated polypeptide? A G T T B G A C C C T C D C A T
1 marks
Answer: D
24 Which diagram correctly represents temporary hydrogen bonding during transcription? A B C D A U C G G C T U
1 marks
Answer: B
25 The diagram shows part of the DNA sequence of a gene and a mutated sequence of the same gene. normal DNA sequence ... CCG GAT TAT TGC GAG AAA TGG CAT TCT AGG ... mutated DNA sequence ... CCG GAT GTA TTG CGA GAA ATG CAT TCT AGG ... What are possible effects of the mutated sequence? 1 the presence of mRNA stop codons, UAG, UAA or UGA 2 a change in the sequence of amino acids 3 a non-functional protein 4 ribosomes cannot translate the mRNA A 1, 2 and 3 B 1, 3 and 4 C 1 and 4 only D 2 and 3 only
1 marks
Answer: D
3 Which letter represents cell structures where mRNA may be found? cytoplasm A C B mitochondrion nucleus D
1 marks
Answer: B
25 Following translation, the alpha polypeptide chain of haemoglobin, α-globin, undergoes modification. During this modification, the first amino acid is removed, leaving 141 amino acid residues. How many nucleotides does the mRNA coding for α-globin contain? A 141 B 142 C 423 D 426
1 marks
Answer: D
24 Different tissues in a plant were supplied with a radioactively labelled substance to identify which tissues were actively synthesising mRNA. Which radioactively labelled substances would be suitable for this experiment? 1 adenine 2 uracil 3 inorganic phosphate 4 ribose A 1, 2, 3 and 4 B 1, 2 and 3 only C 2 and 4 only D 4 only
1 marks
Answer: C
19 Which statement about messenger RNA is correct? A In eukaryotic cells, mRNA is made by removing exons from the primary RNA transcript. B mRNA is a single-stranded polynucleotide containing a different purine base than DNA. C mRNA molecules contain ribose sugars joined to phosphate groups by phosphodiester bonds. D The monomers of mRNA contain a phosphate group, deoxyribose sugar and a nitrogenous base.
1 marks
Answer: C
20 Which structures are involved in transcription only? DNA template : RNA anticodons strand polymerase A WA J x B J x J Cc x Jv x D x x v key JY = involved X = not involved
1 marks
Answer: B
21 One gene provides the code for the production of which type of molecule? A amino acid B DNA C nucleotide D polypeptide
1 marks
Answer: D
22 The table shows some mRNA codons that code for certain amino acids. mRNA codon amino acid GCG, GCA, GCC, GCU alanine ACG, ACA, ACC, ACU threonine UGC, UGU cysteine UAC, UAU tyrosine CAG, CAA glutamine CGG, CGA, CGC, CGU arginine A DNA template strand has the base sequence shown. ACAGTATTATTTGCAACG What would the change in the amino acid be if the first base in the fifth DNA triplet was substituted for an A base? A alanine to cysteine B alanine to threonine C arginine to cysteine D arginine to threonine
1 marks
Answer: C
3 Which cell structures can have mRNA inside them? 1 chloroplast 2 mitochondrion 3 nucleus 4 rough endoplasmic reticulum A 1, 2, 3 and 4 B 1, 2 and 3 only C 2, 3 and 4 only D 3 and 4 only
1 marks
Answer: B
22 One characteristic of DNA is that it is a universal genetic code. What is meant by a universal genetic code? A All living organisms use the same triplet code for amino acids. B All DNA triplets code for a different amino acid. C Not all DNA triplets code for an amino acid. D All living organisms contain the same four nucleic acids.
1 marks
Answer: A
23 Which statement about mRNA is correct? A It is a polymer made of nucleotides all joined with hydrogen bonds. B Each nucleotide subunit contains the sugar ribose. C It always has an equal proportion of adenine and uracil. D The mRNA sequence is identical to the template strand of DNA.
1 marks
Answer: B
24 The diagram shows part of the process of translation. Z X Y What are the names of the structures labelled X, Y and Z? X Y Z A anticodon codon mRNA B anticodon codon tRNA C codon anticodon mRNA D codon anticodon tRNA
1 marks
Answer: B
25 The DNA triplets of genes are translated as amino acids or stop signals during protein synthesis. The table shows some of these triplets. name of DNA triplet amino acid ATA tyrosine ATG tyrosine ACA cysteine ACG cysteine ATC stop signal ACC tryptophan What could be the effects of one substitution mutation in a triplet coding for tyrosine? 1 The triplet is translated as cysteine. 2 The triplet is translated as tryptophan. 3 The triplet is translated as tyrosine. 4 Translation stops at this triplet. A 1, 2 and 3 B 1, 2 and 4 C 1, 3 and 4 D 2, 3 and 4
1 marks
Answer: C
26 The diagram shows the process of translation occurring at a ribosome. ribosome S C A U U C G C U A A U G What is the base sequence at S? A CUA B CAT C GAU D GAT
1 marks
Answer: C
23 The RNA codon wheel is a tool used to find which amino acid would be translated from an mRNA sequence. Gly Phe Leu Glu Asp Ser CUAG CU AG AG CUAG UC Tyr Ala UCAG G U UC Stop A C AG C A Cys UCAG UC Val Stop U G U G A G Trp Arg AG G UCAG A C U UC Leu Ser A C AG UCAG Lys UC C A U G Pro Asn CUAG CU AG G CUAG His Thr ACU Gln Met Arg Ile Codon position 1 is in the centre of the wheel, codon position 2 is in the middle of the wheel and codon position 3 is near the edge of the wheel. The three letters on the outside edge of the wheel identify the amino acid. The diagram shows a section of DNA coding for one amino acid. The template strand is outlined in a box and the DNA base sequence is read in the 5′ to 3′ direction. template strand Which amino acid is coded for by this section of DNA? A Gly B Pro C Trp D Thr
1 marks
Answer: C
7 Which processes occur in eukaryotes and prokaryotes? 1 hydrolysis 2 mitosis 3 transcription 4 translation A 1, 2 and 3 B 1, 2 and 4 C 1, 3 and 4 D 2, 3 and 4
1 marks
Answer: C
23 The genome of the bacterium Escherichia coli has been altered to enable it to code for an amino acid that is not found in nature. All the ATC DNA stop triplets on the strand of DNA that is transcribed have been substituted to ATT. The ATC triplet can then be inserted to code for the new amino acid. A new tRNA can then be constructed to carry the new amino acid. What is the anticodon of this new tRNA? A ATC B AUC C TAG D UAG
1 marks
Answer: B
24 40% of the bases in a section of a non-transcribed strand of DNA are purine molecules. What will be the total percentage of cytosine and uracil bases in the primary transcript that is transcribed from the other strand of the DNA? A 20% B 30% C 40% D 60%
1 marks
Answer: D
40 Some vaccines do not contain antigens. The vaccines contain a molecule of mRNA. Cells in the immune system use the mRNA molecule to make a protein antigen. The statements describe the stages of how mRNA vaccines work when they enter a cell of the immune system. 1 B-lymphocytes and T-lymphocytes with complementary receptors bind to the protein. 2 Lymphocytes differentiate into memory cells that give long lasting immunity. 3 Ribosomes translate the mRNA molecule to make a protein. 4 The cell displays the protein on its cell surface membrane. What is the correct order of the stages of how mRNA vaccines work? A 1 → 2 → 4 → 3 B 3 → 1 → 2 → 4 C 3 → 4 → 1 → 2 D 4 → 1 → 2 → 3
1 marks
Answer: C
25 Which statements about complementary base pairing are correct? 1 Purines and pyrimidines are different sizes. 2 Complementary base pairing occurs during translation. 3 The base pairs are of different lengths. 4 Uracil forms two hydrogen bonds with adenine. A 1, 2 and 3 B 1, 2 and 4 C 1, 3 and 4 D 2, 3 and 4
1 marks
Answer: B
27 Which molecule has its synthesis directly controlled by DNA? A amylase B cholesterol C glycogen D phospholipid
1 marks
Answer: A
10 What is the correct order of locations in the cell for the production of an extracellular enzyme? A nucleus ribosome rough endoplasmic reticulum Golgi body B ribosome nucleus Golgi body rough endoplasmic reticulum C ribosome rough endoplasmic reticulum nucleus Golgi body D rough endoplasmic reticulum nucleus Golgi body ribosome
1 marks
Answer: A
22 The diagram shows the nucleotide sequence of a small section of the transcribed strand of a gene. CGG GCC CCG CGG The table shows the amino acids coded for by 10 mRNA codons. mRNA codon amino acid AAG Lys ACG Thr CGG CGC CGU Arg CCG Pro GCC GCG Ala GGC Gly UGC Cys What is the sequence of the four amino acids in the polypeptide translated from this small section of a gene? A Ala-Ala-Cys-Ala B Ala-Arg-Gly-Ala C Arg-Ala-Pro-Arg D Arg-Arg-Thr-Arg
1 marks
Answer: B
23 What does the process of translation require? A DNA, free nucleotide bases and mRNA B DNA, mRNA, amino acids and RNA polymerase C mRNA, ribosomes and RNA polymerase D mRNA, ribosomes, amino acids and tRNA
1 marks
Answer: D
7 Which statements about peptide bond formation are correct? 1 The bond formation occurs between a carbon of one amino acid and a nitrogen of the next amino acid after the amino acids detach from tRNA. 2 The bond formation occurs at the ribosome while the amino acids are still attached to tRNA, and is a hydrolysis reaction. 3 The bond formation is important for growth of an organism and when the bond forms, a water molecule is removed. A 1 and 3 B 2 and 3 C 2 only D 3 only
1 marks
Answer: D
21 The mRNA codons ACU, ACC, ACA and ACG all code for the same amino acid, threonine. Which anticodons could specify an amino acid other than threonine? 1 UCA 2 ACC 3 UGU 4 UGC A 1, 3 and 4 B 1 and 2 C 2 and 3 D 3 and 4 only
1 marks
Answer: B
23 In eukaryotes, the RNA molecules formed during transcription are modified by the removal of non-coding sequences. This is followed by the joining together of coding sequences to form mRNA. What are the coding sequences also called? A codons B exons C introns D primary transcripts
1 marks
Answer: B
22 A transcription error results in the deletion of one nucleotide from the middle of a primary transcript. mRNA forms from the primary transcript. Which statement describes one possible effect of this deletion on the protein translated from this mRNA? A The protein will be unchanged as the same amino acids can be coded by another codon formed by the deletion. B The tertiary structure of the protein is not affected as only one amino acid has been changed by the deletion. C Only one amino acid has been changed by the deletion but this changes the quaternary structure of the protein. D The sequence of amino acids in the protein will be different as all the codons from the deletion onwards are changed.
1 marks
Answer: D
23 Which statements correctly describe the process of translation? 1 The nucleotide sequence on an mRNA molecule is used to produce a specific amino acid chain. 2 A section of DNA is copied into an mRNA molecule by RNA polymerase. 3 A polypeptide is produced because anticodons on tRNA molecules attach to mRNA codons through peptide bonds. A 1 and 2 B 1 and 3 C 1 only D 2 and 3
1 marks
Answer: C
24 A molecule of mRNA was used in translation. Part of its sequence is shown. GAU CUG UAA CGG There were no introns present in the section of DNA that was transcribed to make this mRNA. What is the sequence of the non-transcribed DNA strand for this section? A CTA GAC ATT GCC B CUA GAC AUU GCC C GAT CTG TAA CGG D GAU CUG UAA CGG
1 marks
Answer: C
2 Which statement explains why lymphocytes with no nucleoli die? A The cells do not have centrioles and cannot divide. B The cells do not have mitochondria and cannot release energy. C The cells do not have mRNA and cannot transcribe DNA. D The cells do not have ribosomes and cannot synthesise protein.
1 marks
Answer: D
5 The statements describe processes that take place in a secretory cell. 1 Modification of the protein occurs in the Golgi body. 2 mRNA leaves the nucleus. 3 Ribosomes bind to mRNA during translation. 4 Transcription of a specific DNA sequence occurs. 5 Vesicles fuse with the cell surface membrane. 6 Vesicles transport the protein to the Golgi body. Statement 4 is the first process, and statement 5 is the last process. What is the correct sequence of the middle four processes? A 2 3 1 6 B 2 3 6 1 C 3 2 1 6 D 3 2 6 1
1 marks
Answer: B
23 Which statements describe how a gene mutation can lead to the production of a non-functional protein? 1 During transcription, an incorrect nucleotide is added to a DNA molecule. 2 The mutated gene results in a new codon being transcribed. 3 The order of the bases in an anticodon on tRNA is altered during translation. A 1, 2 and 3 B 1 and 2 only C 2 and 3 only D 2 only
1 marks
Answer: D
25 The diagram shows the nucleotide sequence of a small section of the transcribed strand of a gene. GCG CGC GGC GCG The table shows the amino acids coded for by 10 mRNA codons. mRNA codon amino acid AAG Lys ACG Thr CGG CGC CGU Arg CCG Pro GCC GCG Ala GGC Gly UGC Cys What is the sequence of the four amino acids in the polypeptide translated from this small section of a gene? A Ala-Ala-Cys-Ala B Ala-Arg-Gly-Ala C Arg-Ala-Pro-Arg D Arg-Arg-Thr-Arg
1 marks
Answer: C
20 Which processes occur in bone marrow cells that are in a mitotic cell cycle? 1 Phosphate groups bind to ADP molecules to form ATP. 2 Bonds form between nucleotides in a DNA strand. 3 Hydrogen bonds form between tRNA anticodons and mRNA codons. A 1, 2 and 3 B 1 and 2 only C 1 and 3 only D 2 only
1 marks
Answer: A
22 A polypeptide molecule contains the amino acid sequence: glycine – leucine – lysine – valine. The table shows DNA triplets for these amino acids. glycine leucine lysine valine CCC GAA TTT CAA Which tRNA anticodons are needed for the synthesis of this polypeptide? A CCC GAA TTT CAA B CCC GAA UUU CAA C GGG CUU AAA GUU D GGG CUU UUU GUU
1 marks
Answer: B
25 During the production of protein molecules, only one strand from the DNA double helix is used. Which name is given to the DNA strand that is used to produce a new protein? A non-transcribed strand B leading strand C template strand D lagging strand
1 marks
Answer: C
23 Which strand of DNA does RNA polymerase bind to? A lagging strand B leading strand C non-transcribed strand D template strand
1 marks
Answer: D
24 Which processes occur during the formation of messenger RNA? 1 condensation 2 polymerisation 3 replication 4 transcription A 1, 2 and 3 B 1, 2 and 4 C 1, 3 and 4 D 2, 3 and 4
1 marks
Answer: B
25 The anticodon for the amino acid tryptophan is ACC. What shows a template DNA sequence that includes the DNA triplet for tryptophan? A UGG CGU CCG B GCU GAC ACG C CTT TGG ATG D CCT ACC CAT
1 marks
Answer: D
25 The diagram represents the process of transcription of a gene in the nucleus of an animal cell. P Q RNA polymerase R Which row correctly identifies P, Q and R? P Q R A mRNA transcribed strand template strand B primary transcript transcribed strand template strand C mRNA template strand non-transcribed strand D primary transcript template strand non-transcribed strand
1 marks
Answer: D
25 The table shows all the possible DNA triplet codes for some amino acids. DNA triplet amino acid code cysteine ACA cysteine ACG tryptophan ACC isoleucine TAA isoleucine TAG isoleucine TAT methionine TAC The amino acid sequence is shown. methionine – isoleucine – cysteine – tryptophan What is the maximum number of different DNA sequences that could produce this amino acid sequence? A 1 B 4 C 6 D 7
1 marks
Answer: C
4 Which cell structures contain ribosomal RNA? 1 chloroplasts 2 mitochondria 3 nuclei A 1, 2 and 3 B 1 and 2 only C 2 and 3 only D 3 only
1 marks
Answer: A
23 Which statements about tRNA are correct? 1 Hydrogen bonds between bases temporarily bond tRNA to mRNA. 2 The base sequences in the tRNA molecules are the same as the base sequences in the mRNA that is being translated. 3 Some codons in mRNA do not have corresponding tRNA anticodons. A 1, 2 and 3 B 1 and 2 only C 1 and 3 only D 2 and 3 only
1 marks
Answer: C
24 Why is the genetic code described as universal? A Each codon is made up of a sequence of three bases. B More than one codon can represent one amino acid. C Mutations can change the genetic code in all organisms. D The genetic code is the same in all organisms.
1 marks
Answer: D
26 Three proteins that have a quaternary structure are listed. ● Type IX collagen is formed from three different polymers. ● The main form of haemoglobin contains two alpha globins and two beta globins. ● HIV protease consists of two identical polymers. Which row shows the correct number of genes needed to code for each protein? number of genes type IX HIV haemoglobin collagen protease A 1 2 2 B 1 4 1 C 3 2 1 D 3 4 2
1 marks
Answer: C
25 How many genes could code for one collagen molecule? A 1 gene only B 2 genes only C 3 genes only D 1 gene or 2 genes or 3 genes
1 marks
Answer: D
26 The diagram shows some events during the formation of an mRNA molecule at transcription. P 5′ 3′ Q Q S R What is correctly identified in the diagram? A P are introns. B Q are exons. C R is a primary transcript. D S are non-coding sequences.
1 marks
Answer: D
22 The gene that codes for protein R is 130 kb long. Protein R is 220 kDa in mass. The typical mass of an amino acid is 110 Da. (1000 base pairs = 1 kb, 1000 Da = 1 kDa) Which row is correct? approximate length approximate length of introns in this of mRNA for this gene / base pairs gene / base pairs A 6000 6000 B 6000 130 000 C 124 000 6000 D 124 000 130 000
1 marks
Answer: C
25 The table shows some of the DNA triplet codes for some amino acids. amino acid DNA triplet code amino acid DNA triplet code arginine GCA glycine CCA arginine GCC glycine CCG arginine GCG glycine CCT asparagine TTA lysine TTC asparagine TTG lysine TTT cysteine ACA proline GGA cysteine ACG proline GGC STOP ATC valine CAC The base sequence on the template DNA strand coding for part of a polypeptide is shown. CCA TTC ACG GCG TTA GCA Two mutations occur in this sequence during DNA replication. Which mutated DNA would result in two different amino acids? A CCA ATC ACG GCG TTG GCA B CCA TTC ACA GCA TTA GCA C CCA TTC ACG CCG TTA GCC D CCA TTC ACG GCG TTC GGA
1 marks
Answer: D
25 Which statements about complementary base pairing are correct? 1 It occurs during translation. 2 Purines and pyrimidines are the same size. 3 The base pairs are of equal length. 4 Uracil forms three hydrogen bonds with adenine. A 1 and 2 B 1 and 3 C 2 and 3 D 3 and 4
1 marks
Answer: B
26 Which statement is correct for protein synthesis? A During translation, the strand of DNA used is the template strand. B mRNA is formed when introns are removed from the primary transcript. C The DNA primary transcript is modified by removing exons. D tRNA has codons which attach to anticodons on the mRNA.
1 marks
Answer: B
27 A mutation occurred in this original DNA nucleotide sequence. C T A G A A T C C T C T C C C After the mutation occurred, the new DNA nucleotide sequence coded for the amino acids Asp, Leu, Gly and Glu. The table shows the amino acids that are coded for by each DNA triplet. 2nd base A G T C AAA Phe AGA Ser ATA Tyr ACA Cys AAG Phe AGG Ser ATG Tyr ACG Cys A AAT Leu AGT Ser ATT Stop ACT Stop AAC Leu AGC Ser ATC Stop ACC Trp GAA Leu GGA Pro GTA His GCA Arg GAG Leu GGG Pro GTG His GCG Arg G GAT Leu GGT Pro GTT Gln GCT Arg GAC Leu GGC Pro GTC Gln GCC Arg 1st base TAA Ile TGA Thr TTA Asn TCA Ser TAG Ile TGG Thr TTG Asn TCG Ser T TAT Ile TGT Thr TTT Lys TCT Arg TAC Met TGC Thr TTC Lys TCC Arg CAA Val CGA Ala CTA Asp CCA Gly CAG Val CGG Ala CTG Asp CCG Gly C CAT Val CGT Ala CTT Glu CCT Gly CAC Val CGC Ala CTC Glu CCC Gly Which type of gene mutation occurred in the DNA nucleotide sequence? A deletion of one nucleotide B insertion of one nucleotide C insertion of two nucleotides D substitution of one nucleotide
1 marks
Answer: A