10.2· 87 questions · 87 marks · 104 min · 2004–2025· Multiple choice
Every Cambridge A Level Physics Paper 1 question on kirchhoff’s laws, laid out as 34 A4 pages with the mark scheme below. Nothing is left out. Free to read, no account.

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34 / 34Answers below. Sit the paper first if you are practising.
Pastlit
Physics 9702 · Kirchhoff’s laws — Paper 1
A Level · topical answer key — answer key (teacher use)
Question
Answer
Marks
Pastlit
Physics 9702 · Kirchhoff’s laws — Paper 1
A Level · topical answer key — answer key (teacher use)
Question
Answer
Marks
| Question | Answer | Marks | From |
|---|---|---|---|
| 1 | A | 1 | 9702/11 Oct/Nov 2004 |
| 2 | B | 1 | 9702/11 Oct/Nov 2006 |
| 3 | B | 1 | 9702/11 May/June 2009 |
| 4 | A | 1 | 9702/11 Oct/Nov 2009 |
| 5 | A | 1 | 9702/12 Oct/Nov 2009 |
| 6 | A | 1 | 9702/11 May/June 2010 |
| 7 | A | 1 | 9702/13 May/June 2010 |
| 8 | C | 1 | 9702/11 May/June 2011 |
| 9 | C | 1 | 9702/13 May/June 2011 |
| 10 | C | 1 | 9702/12 Oct/Nov 2011 |
| 11 | D | 1 | 9702/12 May/June 2012 |
| 12 | A | 1 | 9702/11 May/June 2013 |
| 13 | D | 1 | 9702/13 May/June 2013 |
| 14 | C | 1 | 9702/12 Oct/Nov 2013 |
| 15 | C | 1 | 9702/13 Oct/Nov 2013 |
| 16 | A | 1 | 9702/12 May/June 2014 |
| 17 | B | 1 | 9702/12 May/June 2014 |
| 18 | A | 1 | 9702/13 May/June 2014 |
| 19 | A | 1 | 9702/13 Oct/Nov 2014 |
| 20 | A | 1 | 9702/12 May/June 2015 |
| 21 | C | 1 | 9702/13 May/June 2015 |
| 22 | D | 1 | 9702/13 Oct/Nov 2015 |
| 23 | D | 1 | 9702/12 Feb/March 2016 |
| 24 | A | 1 | 9702/12 Feb/March 2016 |
| 25 | A | 1 | 9702/11 May/June 2016 |
| 26 | D | 1 | 9702/11 Oct/Nov 2016 |
| 27 | A | 1 | 9702/11 Oct/Nov 2016 |
| 28 | D | 1 | 9702/13 Oct/Nov 2016 |
| 29 | A | 1 | 9702/13 Oct/Nov 2016 |
| 30 | C | 1 | 9702/12 Feb/March 2017 |
| 31 | C | 1 | 9702/13 May/June 2017 |
| 32 | B | 1 | 9702/11 Oct/Nov 2017 |
| 33 | B | 1 | 9702/12 Oct/Nov 2017 |
| 34 | B | 1 | 9702/13 Oct/Nov 2017 |
| 35 | C | 1 | 9702/13 Oct/Nov 2017 |
| 36 | A | 1 | 9702/11 May/June 2018 |
| 37 | C | 1 | 9702/11 May/June 2018 |
| 38 | B | 1 | 9702/12 May/June 2018 |
| 39 | A | 1 | 9702/11 Oct/Nov 2018 |
| 40 | B | 1 | 9702/12 Oct/Nov 2018 |
| 41 | C | 1 | 9702/13 Oct/Nov 2018 |
| 42 | C | 1 | 9702/11 May/June 2019 |
| 43 | A | 1 | 9702/12 May/June 2019 |
| 44 | A | 1 | 9702/12 May/June 2019 |
| 45 | B | 1 | 9702/13 May/June 2019 |
| 46 | B | 1 | 9702/11 Oct/Nov 2019 |
| 47 | D | 1 | 9702/11 Oct/Nov 2019 |
| 48 | A | 1 | 9702/12 Oct/Nov 2019 |
| 49 | A | 1 | 9702/13 Oct/Nov 2019 |
| 50 | B | 1 | 9702/12 Feb/March 2020 |
| 51 | A | 1 | 9702/12 May/June 2020 |
| 52 | A | 1 | 9702/13 May/June 2021 |
| 53 | B | 1 | 9702/13 May/June 2021 |
| 54 | D | 1 | 9702/11 Oct/Nov 2021 |
| 55 | A | 1 | 9702/11 Oct/Nov 2021 |
| 56 | A | 1 | 9702/13 Oct/Nov 2021 |
| 57 | A | 1 | 9702/12 Feb/March 2022 |
| 58 | A | 1 | 9702/11 May/June 2022 |
| 59 | A | 1 | 9702/12 May/June 2022 |
| 60 | D | 1 | 9702/11 Oct/Nov 2022 |
| 61 | C | 1 | 9702/13 Oct/Nov 2022 |
| 62 | C | 1 | 9702/13 Oct/Nov 2022 |
| 63 | B | 1 | 9702/12 Feb/March 2023 |
| 64 | A | 1 | 9702/12 Feb/March 2023 |
| 65 | A | 1 | 9702/12 May/June 2023 |
| 66 | B | 1 | 9702/12 May/June 2023 |
| 67 | A | 1 | 9702/13 May/June 2023 |
| 68 | D | 1 | 9702/12 Oct/Nov 2023 |
| 69 | A | 1 | 9702/12 Oct/Nov 2023 |
| 70 | C | 1 | 9702/13 Oct/Nov 2023 |
| 71 | C | 1 | 9702/12 May/June 2024 |
| 72 | A | 1 | 9702/12 May/June 2024 |
| 73 | C | 1 | 9702/13 May/June 2024 |
| 74 | B | 1 | 9702/11 Oct/Nov 2024 |
| 75 | A | 1 | 9702/12 Oct/Nov 2024 |
| 76 | C | 1 | 9702/13 Oct/Nov 2024 |
| 77 | C | 1 | 9702/12 Feb/March 2025 |
| 78 | D | 1 | 9702/12 May/June 2025 |
| 79 | A | 1 | 9702/12 May/June 2025 |
| 80 | A | 1 | 9702/14 May/June 2025 |
| 81 | B | 1 | 9702/14 May/June 2025 |
| 82 | A | 1 | 9702/11 Oct/Nov 2025 |
| 83 | C | 1 | 9702/11 Oct/Nov 2025 |
| 84 | A | 1 | 9702/12 Oct/Nov 2025 |
| 85 | A | 1 | 9702/13 Oct/Nov 2025 |
| 86 | C | 1 | 9702/13 Oct/Nov 2025 |
| 87 | C | 1 | 9702/14 Oct/Nov 2025 |
37 In the circuit shown, the ammeters have negligible resistance and the voltmeters have infinite resistance. I1 3 Ω I2 2 Ω A A 6 Ω 2 Ω V V V1 V2 The readings on the meters are I1, I2, V1 and V2, as labelled on the diagram. Which is correct? A I1 > I2 and V1 > V2 B I1 > I2 and V1 < V2 C I1 < I2 and V1 > V2 D I1 < I2 and V1 < V2
1 marks
Answer: A
36 The diagram represents a circuit. I2 20.2 mA I1 A 10.6 mA 10.8 mA Some currents have been shown on the diagram. What are the currents I1 and I2? I1 I2 A 0.2 mA 10.8 mA B 0.2 mA 30.8 mA C –0.2 mA 20.0 mA D –0.2 mA 30.8 mA
1 marks
Answer: B
33 Two cells of e.m.f. 3.0 V and 1.2 V and negligible internal resistance are connected to resistors of resistance 9.0 Ω and 18 Ω as shown. 3.0 V 1.2 V I 9.0 Ω 18 Ω What is the value of the current I in the 9.0 Ω resistor? A 0.10 A B 0.20 A C 0.30 A D 0.47 A Space for working
1 marks
Answer: B
33 Each of Kirchhoff's two laws presumes that some quantity is conserved. Which row states Kirchhoff's first law and names the quantity that is conserved? statement quantity the algebraic sum of A currents into a junction is charge zero the algebraic sum of B currents into a junction is energy zero the e.m.f. in a loop is equal to the algebraic sum C of the product of current charge and resistance round the loop the e.m.f. in a loop is equal to the algebraic sum D of the product of current energy and resistance round the loop
1 marks
Answer: A
32 Each of Kirchhoff's two laws presumes that some quantity is conserved. Which row states Kirchhoff's first law and names the quantity that is conserved? statement quantity the algebraic sum of A currents into a junction is charge zero the algebraic sum of B currents into a junction is energy zero the e.m.f. in a loop is equal to the algebraic sum C of the product of current charge and resistance round the loop the e.m.f. in a loop is equal to the algebraic sum D of the product of current energy and resistance round the loop
1 marks
Answer: A
34 In deriving a formula for the combined resistance of three different resistors in series, Kirchhoff’s laws are used. Which physics principle is involved in this derivation? A the conservation of charge B the direction of the flow of charge is from negative to positive C the potential difference across each resistor is the same D the current varies in each resistor, in proportion to the resistor value
1 marks
Answer: A
36 In deriving a formula for the combined resistance of three different resistors in series, Kirchhoff’s laws are used. Which physics principle is involved in this derivation? A the conservation of charge B the direction of the flow of charge is from negative to positive C the potential difference across each resistor is the same D the current varies in each resistor, in proportion to the resistor value
1 marks
Answer: A
35 The diagram shows part of a current-carrying circuit. The ammeter has negligible internal resistance. 1.0 Ω 2.0 Ω A 5.0 A 5.0 A 5.0 Ω What is the reading on the ammeter? A 0.7 A B 1.3 A C 1.5 A D 1.7 A Space for working
1 marks
Answer: C
37 The diagram shows part of a current-carrying circuit. The ammeter has negligible internal resistance. 1.0 Ω 2.0 Ω A 5.0 A 5.0 A 5.0 Ω What is the reading on the ammeter? A 0.7 A B 1.3 A C 1.5 A D 1.7 A
1 marks
Answer: C
36 Each of Kirchhoff’s laws is linked to the conservation of a physical quantity. Which physical quantities are assumed to be conserved in the formulation of Kirchhoff’s first law and of Kirchhoff’s second law? Kirchhoff’s Kirchhoff’s first law second law A energy charge B energy momentum C charge energy D momentum energy
1 marks
Answer: C
35 The diagram shows a circuit with four voltmeter readings V, V1, V2 and V3. V V1 V V R V2 V R 2R V3 V Which equation relating the voltmeter readings must be true? A V = V1 + V2 + V3 B V + V1 = V2 + V3 C V3 = 2(V2) D V – V1 = V3 Space for working
1 marks
Answer: D
34 The principles of conservation of which two quantities are associated with Kirchhoff’s first and second laws? first law second law A charge energy B charge voltage C energy charge D voltage charge Space for working
1 marks
Answer: A
31 Two cells X and Y are connected in series with a resistor of resistance 9.0 Ω, as shown. 9.0 Ω X Y Cell X has an electromotive force (e.m.f.) of 1.0 V and an internal resistance of 1.0 Ω. Cell Y has an e.m.f. of 2.0 V and an internal resistance of 2.0 Ω. What is the current in the circuit? A 0.25 A B 0.17 A C 0.10 A D 0.083 A Space for working
1 marks
Answer: D
38 Four resistors of resistance R, 2R, 3R and 4R are connected to form a network. A battery of negligible internal resistance and a voltmeter are connected to the resistor network as shown. 3R 4R V 2R R The voltmeter reading is 2 V. What is the electromotive force (e.m.f.) of the battery? A 2 V B 4 V C 6 V D 10 V
1 marks
Answer: C
38 A 20 V d.c. supply is connected to a circuit consisting of five resistors L, M, N, P and Q. L M 7 V drop 4 V N drop P Q + – 20 V rise There is a potential drop of 7 V across L and a further 4 V potential drop across N. What are the potential drops across M, P and Q? potential drop potential drop potential drop across M / V across P / V across Q / V A 9 7 13 B 13 7 13 C 13 11 9 D 17 3 17
1 marks
Answer: C
33 Cell X has an e.m.f. of 2.0 V and an internal resistance of 2.0 Ω. Cell Y has an e.m.f. of 1.6 V and an internal resistance of 1.2 Ω. These two cells are connected to a resistor of resistance 0.8 Ω, as shown. cell X 2.0 V 2.0 Ω 0.8 Ω 1.6 V 1.2 Ω cell Y What is the current in cell X? A 0.10 A B 0.50 A C 0.90 A D 1.0 A Space for working
1 marks
Answer: A
36 In the circuit shown, all the resistors are identical. V1 V4 V2 V3 The reading on voltmeter V1 is 8.0 V and the reading on voltmeter V2 is 1.0 V. What are the readings on the other voltmeters? reading on reading on voltmeter V3 / V voltmeter V4 / V A 1.5 1.0 B 3.0 2.0 C 4.5 3.0 D 6.0 4.0 Space for working
1 marks
Answer: B
37 What is the current in the 40 Ω resistor of the circuit shown? 20 Ω 20 Ω 40 Ω 20 Ω 20 Ω 10 V A zero B 0.13 A C 0.25 A D 0.50 A
1 marks
Answer: A
37 In the circuit shown, the ammeters have negligible resistance and the voltmeters have infinite resistance. I1 I2 3 Ω 2 Ω A A 6 Ω 2 Ω V V V1 V2 The readings on the meters are I1, I2, V1 and V2, as labelled on the diagram. Which statement is correct? A I1 > I2 and V1 > V2 B I1 > I2 and V1 < V2 C I1 < I2 and V1 > V2 D I1 < I2 and V1 < V2 Space for working
1 marks
Answer: A
35 Each of Kirchhoff's two laws presumes that some quantity is conserved. Which row states Kirchhoff's first law and names the quantity that is conserved? statement quantity the algebraic sum of A currents into a junction is charge zero the algebraic sum of B currents into a junction is energy zero the e.m.f. in a loop is equal to the algebraic sum C of the product of current charge and resistance round the loop the e.m.f. in a loop is equal to the algebraic sum D of the product of current energy and resistance round the loop
1 marks
Answer: A
37 The diagram shows part of a current-carrying circuit. The ammeter has negligible resistance. 1.0 Ω 2.0 Ω A 5.0 A 5.0 A 5.0 Ω What is the reading on the ammeter? A 0.7 A B 1.3 A C 1.5 A D 1.7 A
1 marks
Answer: C
37 A network of resistors, each of resistance 1 Ω, is connected as shown. 1 Ω 1 Ω 1 Ω V 1 Ω 1 Ω 1 Ω 1 A The current passing through the end resistor is 1 A. What is the potential difference (p.d.) V across the input terminals? A 2 V B 5 V C 8 V D 13 V
1 marks
Answer: D
34 Three cells with e.m.f.s V1, V2 and V3, have negligible internal resistance. These cells are connected to three resistors with resistances R1, R2 and R3, as shown. V1 I R1 V2 V3 R2 R3 The current in the circuit is I. Which equation is correct? A V1 + V2 + V3 = I (R1 + R2 + R3) B V1 + V2 – V3 = I (R1 + R2 + R3) C V1 – V2 + V3 = I (R1 + R2 + R3) D V1 – V2 – V3 = I (R1 + R2 + R3)
1 marks
Answer: D
36 In deriving a formula for the combined resistance of three different resistors in series, Kirchhoff’s laws are used. Which physics principle is involved in this derivation? A the conservation of charge B the direction of the flow of charge is from negative to positive C the potential difference across each resistor is the same D the current varies in each resistor, in proportion to the resistor value
1 marks
Answer: A
35 There is a current from P to R in the resistor network shown. 3 V 6 V Q P R S 5 V The potential difference (p.d.) between P and Q is 3 V. The p.d. between Q and R is 6 V. The p.d. between P and S is 5 V. Which row in the table is correct? p.d. between p.d. between Q and S S and R A 2 V 4 V B 2 V 10 V C 3 V 4 V D 3 V 10 V
1 marks
Answer: A
36 In the circuit shown, the reading on the ammeter is zero. R1 R3 A R2 R4 The four resistors have different resistances R1, R2, R3 and R4. Which equation is correct? A R1 – R3 = R2 – R4 B R1 × R3 = R2 × R4 C R1 – R4 = R2 – R3 D R1 × R4 = R2 × R3
1 marks
Answer: D
37 The diagram shows currents I1, I2, I3, I4 and I5 in different branches of a circuit. I1 I2 I3 I4 I5 Which equation is correct? A I1 = I2 + I3 B I2 = I1 + I3 C I3 = I4 + I5 D I4 = I5 + I3
1 marks
Answer: A
36 In the circuit shown, the reading on the ammeter is zero. R1 R3 A R2 R4 The four resistors have different resistances R1, R2, R3 and R4. Which equation is correct? A R1 – R3 = R2 – R4 B R1 × R3 = R2 × R4 C R1 – R4 = R2 – R3 D R1 × R4 = R2 × R3
1 marks
Answer: D
37 The diagram shows currents I1, I2, I3, I4 and I5 in different branches of a circuit. I1 I2 I3 I4 I5 Which equation is correct? A I1 = I2 + I3 B I2 = I1 + I3 C I3 = I4 + I5 D I4 = I5 + I3
1 marks
Answer: A
35 Two cells are connected to a load resistor of resistance 3.0 Ω. The electromotive force (e.m.f). and the internal resistance of each of the cells is shown. 6.0 V 3.0 V 0.8 Ω 1.2 Ω 3.0 Ω What is the current in the load resistor? A 0.60 A B 1.2 A C 1.8 A D 3.0 A
1 marks
Answer: C
35 A 20 V d.c. supply is connected to a circuit consisting of five resistors L, M, N, P and Q. L M 7 V drop 4 V N drop P Q + – 20 V rise There is a potential drop of 7 V across L and a further 4 V potential drop across N. What are the potential drops across M, P and Q? potential drop potential drop potential drop across M / V across P / V across Q / V A 9 7 13 B 13 7 13 C 13 11 9 D 17 3 17
1 marks
Answer: C
37 A cell of electromotive force E and negligible internal resistance is connected to a network of resistors of resistances R1, R2, R3 and R4 as shown. E I1 R1 I2 R2 I3 R3 R4 The branches of the circuit have currents I1, I2 and I3. Which equation is correct? A I1R1 + I2R2 = I3R3 + I3R4 B I2R2 – I3R4 – I3R3 = 0 C E = I1R1 + I2R2 + I3R3 + I3R4 D E = I1R1 + I2R2 – I3R3 – I3R4
1 marks
Answer: B
37 The circuit shown contains a resistor S that is neither in series nor in parallel with the other resistors. 12.0 V 0.50 Ω 3.0 A 4.0 A 0.5 A S R R Kirchhoff’s laws can be used with the data in the diagram to deduce the resistance of each of the two identical resistors labelled R. What is the resistance of each resistor R? A 3.0 Ω B 4.0 Ω C 4.8 Ω D 5.0 Ω
1 marks
Answer: B
36 Two cells, each with electromotive force (e.m.f.) E, but different internal resistances r1 and r2, are connected in series to a resistor R. The reading on the voltmeter is 0 V. V E E r1 r2 R What is the resistance of R? r1r2 A 0 B r1 – r2 C r1 + r2 D r1 + r2
1 marks
Answer: B
37 Three identical cells each have electromotive force (e.m.f.) E and negligible internal resistance. The cells are connected to three identical resistors, each of resistance R, as shown. E R P Q E R R E What is the potential difference between P and Q? E 2E A 0 B C D E 3 3
1 marks
Answer: C
33 The sum of the electrical currents into a point in a circuit is equal to the sum of the currents out of the point. Which statement is correct? A This is Kirchhoff’s first law, which results from the conservation of charge. B This is Kirchhoff’s first law, which results from the conservation of energy. C This is Kirchhoff’s second law, which results from the conservation of charge. D This is Kirchhoff’s second law, which results from the conservation of energy.
1 marks
Answer: A
34 In the circuit shown, the batteries have negligible internal resistance. 15 V 9 V I1 I2 I3 2.0 Ω 2.0 Ω 2.0 Ω What are the values of the currents I1, I2 and I3? I1 / A I2 / A I3 / A A –5.5 1.0 6.5 B 0.5 4.0 3.5 C 3.5 4.0 0.5 D 6.5 1.0 –5.5
1 marks
Answer: C
34 Four different resistors are arranged as shown. A current of 1.5 A enters the network at junction X and leaves through junction Y. 1.5 A Y 70 Ω 60 Ω 1.5 A X 50 Ω 30 Ω What is the current in the resistor of resistance 30 Ω? A 0.21 A B 0.50 A C 0.75 A D 1.0 A
1 marks
Answer: B
37 A battery is connected to a network of six resistors, as shown. 1.2 V 2.2 V 4.1 V 1.2 V 3.7 V R The potential differences across five of the resistors are labelled on the diagram. What is the potential difference across resistor R? A 4.4 V B 4.6 V C 6.6 V D 11.2 V
1 marks
Answer: A
37 Kirchhoff’s second law is a consequence of a basic principle. What is this principle? A The charge flowing in an electric circuit is conserved. B The energy in an electric circuit is conserved. C The sum of the electric currents entering a point in an electrical circuit is equal to the sum of the electric currents leaving that point. D The sum of the potential differences in a circuit is equal to the sum of the products of the current and resistance.
1 marks
Answer: B
37 In the circuit shown, the ammeter reading is zero. 50 Ω R 12 V 24 V 100 Ω 200 Ω A What is the resistance of resistor R? A 100 Ω B 200 Ω C 400 Ω D 600 Ω
1 marks
Answer: C
37 A battery with negligible internal resistance is connected to three resistors, as shown. 0.30 A X All three resistors have the same resistance. The current in the battery is 0.30 A. What is the current in resistor X? A 0.10 A B 0.15 A C 0.20 A D 0.30 A
1 marks
Answer: C
36 Kirchhoff’s first law states that the sum of the currents entering a junction in a circuit is equal to the sum of the currents leaving it. The law is based on the conservation of a physical quantity. What is this physical quantity? A charge B energy C mass D momentum
1 marks
Answer: A
37 A circuit contains two batteries, each of negligible internal resistance, and two resistors as shown. 9.0 Ω galvanometer 24 V 3.0 Ω X The galvanometer has a current reading of zero. What is the electromotive force (e.m.f.) of battery X? A 6.0 V B 8.0 V C 16.0 V D 18.0 V
1 marks
Answer: A
38 Two cells of electromotive force (e.m.f.) 3.0 V and 1.2 V and negligible internal resistance are connected to resistors of resistance 9.0 Ω and 18 Ω as shown. 3.0 V 1.2 V I 9.0 Ω 18 Ω What is the current I in the 9.0 Ω resistor? A 0.10 A B 0.20 A C 0.30 A D 0.47 A
1 marks
Answer: B
34 Kirchhoff’s two laws for electric circuits can be derived by using conservation laws. On which conservation laws do Kirchhoff’s laws depend? Kirchhoff’s Kirchhoff’s first law second law A charge current B charge energy C current mass D energy current
1 marks
Answer: B
36 The diagram shows a circuit containing four voltmeters. The readings on the voltmeters are V1, V2, V3 and V4. All the readings are positive. V V3 V1 V V2 V V V4 Which equation relating the voltmeter readings is correct? A V1 = V2 + V4 B V1 = V2 + V3 + V4 C V2 + V3 = V4 D V3 + V4 – V2 = 0
1 marks
Answer: D
34 Two cells with electromotive forces E1 and E2 and internal resistances r1 and r2 are connected to a resistor R as shown. cell 1 cell 2 E1 E2 r1 r2 current R The terminal potential difference across cell 1 is zero. Which expression gives the resistance of resistor R? E r − E r E r − E r E r 1 2 − E r E r 1 2 − E r A 2 1 1 2 B 2 1 1 2 C 2 1 D 2 1 E E E E 1 2 1 2
1 marks
Answer: A
37 Which row correctly describes Kirchhoff’s laws? physics principle physics principle Kirchhoff’s first law applied for first Kirchhoff’s second law applied for law second law A The sum of the conservation The sum of the e.m.f.s conservation currents entering a of charge around any closed loop of energy junction equals the in a circuit equals the sum of the currents sum of the p.d.s around leaving the junction. the same loop. B The sum of the conservation The sum of the e.m.f.s conservation currents entering a of energy around any closed loop of charge junction equals the in a circuit equals the sum of the currents sum of the p.d.s around leaving the junction. the same loop. C The sum of the e.m.f.s conservation The sum of the currents conservation around any closed of energy entering a junction of charge loop in a circuit equals equals the sum of the the sum of the p.d.s currents leaving the around the same loop. junction. D The sum of the e.m.f.s conservation The sum of the currents conservation around any closed of charge entering a junction of energy loop in a circuit equals equals the sum of the the sum of the p.d.s currents leaving the around the same loop. junction.
1 marks
Answer: A
35 Two batteries are connected together, as shown. battery 1 battery 2 12 V 9 V 0.3 Ω 0.1 Ω Battery 1 has electromotive force (e.m.f.) 12 V and internal resistance 0.3 Ω. Battery 2 has e.m.f. 9 V and internal resistance 0.1 Ω. What are the e.m.f. and the internal resistance of a single battery that has the same effect as the combination? internal e.m.f. / V resistance / Ω A 3 0.2 B 3 0.4 C 21 0.2 D 21 0.4
1 marks
Answer: B
37 Kirchhoff’s first and second laws link to the conservation of physical quantities. Which quantities do they link to? first law second law A charge energy B charge momentum C energy charge D energy momentum
1 marks
Answer: A
35 The diagram shows a circuit containing two batteries connected together. 12.0 V 1.0 Ω I 8.0 V 0.5 Ω What is the current I ? A 2.7 A B 4.0 A C 8.0 A D 13 A
1 marks
Answer: A
37 A battery of electromotive force (e.m.f.) E and negligible internal resistance is connected to four resistors of resistances R1, R2, R3 and R4. I1 I2 R1 R3 E R2 R4 The currents I1 and I2 in the resistors are as shown. Which equation is correct? A 0 = I1(R1 + R2) + I2(R3 + R4) B 0 = I1(R1 + R2) – I2(R3 + R4) C E = I1(R1 + R2) + I2(R3 + R4) D E = I1(R1 + R2) – I2(R3 + R4)
1 marks
Answer: B
33 A circuit contains two resistors, P and Q, and a power supply of negligible internal resistance, as shown. P Q The current in resistor P is 2.0 A and the power dissipated by resistor P is 18 W. Resistor Q dissipates 240 J of energy when a charge of 40 C passes through it. What is the electromotive force (e.m.f.) of the power supply? A 3.0 V B 6.0 V C 9.0 V D 15 V
1 marks
Answer: D
37 Three identical cells, each of electromotive force (e.m.f.) E and internal resistance r, are connected as shown. E r X E r r E current Y What is the potential difference between points X and Y? A 0 B E C 2E D 3E
1 marks
Answer: A
37 The circuit shown contains three cells of electromotive forces 3.0 V, 2.0 V and 4.0 V, in series with a resistor of resistance 5.0 . The cells have negligible internal resistance. 3.0 V 5.0 Ω I 4.0 V 2.0 V What is the current I in the circuit? A 0.20 A B 0.60 A C 1.0 A D 1.8 A
1 marks
Answer: A
35 Each of Kirchhoff’s two laws presumes that some quantity is conserved. Which row states Kirchhoff’s first law and names the quantity that is conserved? statement quantity A the algebraic sum of currents charge into a junction is zero B the algebraic sum of currents energy into a junction is zero C the e.m.f. in a loop is equal to the charge algebraic sum of the product of current and resistance round the loop D the e.m.f. in a loop is equal to the energy algebraic sum of the product of current and resistance round the loop
1 marks
Answer: A
36 The sum of the currents entering a junction in an electrical circuit is always equal to the sum of the currents leaving the junction. Why is this? A It is a consequence of the conservation of charge. B It is a consequence of the conservation of electromotive force. C It is a consequence of the conservation of energy. D It is a consequence of the conservation of potential difference.
1 marks
Answer: A
36 Kirchhoff’s first and second laws are consequences of the conservation of different quantities. What are those quantities? Kirchhoff’s Kirchhoff’s first law second law A charge energy B energy current C current charge D energy charge
1 marks
Answer: A
36 A circuit consists of a battery, a voltmeter and five fixed resistors, as shown. The voltmeter reading is Zero. What is the resistance of resistor R? A 1.19 Bo 2.1 C 4.00 D 8.0Q
1 marks
Answer: D
35 Each of Kirchhoff’s laws is linked to the conservation of a physical quantity. Which conserved physical quantities are used in the derivation of Kirchhoff’s first law and of Kirchhoff’s second law? Kirchhoff’s Kirchhoff’s first law second law A energy charge B energy momentum C charge energy D momentum energy
1 marks
Answer: C
36 Three batteries and three identical resistors are connected in a circuit PQR, as shown. 9.6 V P Q 8.4 V 6.3 V R The batteries have negligible internal resistance. What is the potential difference between points P and Q? A 1.5 V B 2.1 V C 7.1 V D 12.1 V
1 marks
Answer: C
35 Kirchhoff’s two laws for electric circuits can be derived by using conservation laws. On which conservation laws do Kirchhoff’s laws depend? Kirchhoff’s Kirchhoff’s first law second law A charge current B charge energy C current mass D energy current
1 marks
Answer: B
36 A battery of electromotive force (e.m.f.) 10V and internal resistance r is connected to three resistors of resistances R, 2.02 and 15Q, as shown. A current of 0.45A is in the resistor of resistance 2.0Q and a current of 0.48A is in the resistor of resistance 15Q. 150 What are the values of rand R? r/Q. R/Q. A 3.0 14 B 3.0 20 Cc 5.8 14 D 5.8 20
1 marks
Answer: A
35 Kirchhoff’s first law is a consequence of the conservation of which quantity? A charge B energy C momentum D potential difference
1 marks
Answer: A
36 Three identical cells each have electromotive force (e.m.f.) E and negligible internal resistance. The cells are connected to three identical resistors, each of resistance R, as shown. E R E R R E What is the potential difference across one of the resistors? E 2E A 0 B C D E 3 3
1 marks
Answer: B
35 Kirchhoff’s first law states that the sum of the currents entering a junction in a circuit is equal to the sum of the currents leaving it. The law is based on the conservation of a physical quantity. What is this physical quantity? A charge B energy C mass D momentum
1 marks
Answer: A
34 Some resistors and a battery of electromotive force (e.m.f.) E and negligible internal resistance are connected in series, as shown. E Which statement is correct? A The e.m.f. across each resistor equals the potential difference across the battery. B The potential difference across each resistor equals the e.m.f. E of the battery. C The sum of the e.m.f.s across the resistors equals the potential difference across the battery. D The sum of the potential differences across the resistors equals the e.m.f. E of the battery.
1 marks
Answer: D
35 Kirchhoff’s first law is a consequence of the conservation of which physical quantity? A charge B energy C linear momentum D potential difference
1 marks
Answer: A
35 Three resistors, R1, R2 and R3, are connected in parallel to a cell. The currents in the resistors are I1, I2 and I3. The potential differences across the resistors are V1, V2 and V3. The current in the cell is I0. The potential difference across the cell is V0, as shown. V0 I0 V1 I1 R1 V2 I2 R2 V3 I3 R3 Which equation can be obtained by applying Kirchhoff’s second law to the circuit? A I0 = I1 = I2 = I3 B I0 = I1 + I2 + I3 C V0 = V1 = V2 = V3 D V0 = V1 + V2 + V3
1 marks
Answer: C
30 The diagram shows a cell of negligible internal resistance connected to a switch and two resistors of resistances R and 2R. X A R 2R Y A The circuit also contains two ammeters X and Y. The reading on X is 4.0 A when the switch is open. What are the readings on X and Y after the switch is closed? reading reading on X / A on Y / A A 4.0 1.3 B 4.0 2.7 C 6.0 2.0 D 6.0 4.0
1 marks
Answer: C
34 Which description of Kirchhoff’s first law is correct? A It considers the currents at a junction in a circuit and is a consequence of the conservation of charge. B It considers the currents at a junction in a circuit and is a consequence of the conservation of energy. C It considers the electromotive forces and potential differences in a circuit loop and is a consequence of the conservation of charge. D It considers the electromotive forces and potential differences in a circuit loop and is a consequence of the conservation of energy.
1 marks
Answer: A
36 The diagram shows a circuit consisting of a cell and three resistors R1, R2 and R3. 1.60 V 0.64 A R1 R2 0.48 V R3 0.32 A The cell has electromotive force (e.m.f.) 1.60 V and negligible internal resistance. The current in the cell is 0.64 A. The potential difference across R1 is 0.48 V. The current in R3 is 0.32 A. What is the resistance of R2? A 1.5 B 2.5 C 3.5 D 5.0
1 marks
Answer: C
31 Kirchhoff’s second law is a consequence of a basic principle. What is this principle? A The charge flowing in an electric circuit is conserved. B The energy in an electric circuit is conserved. C The sum of the electric currents entering a point in an electric circuit is equal to the sum of the electric currents leaving that point. D The sum of the potential differences in an electric circuit is equal to the sum of the products of the current and resistance.
1 marks
Answer: B
36 Each of Kirchhoff’s laws is a statement based on the conservation of a physical quantity. Which quantity is conserved in each law? Kirchhoff’s Kirchhoff’s first law second law A charge energy B energy current C power charge D resistance power
1 marks
Answer: A
37 A circuit contains a battery of electromotive force E and internal resistance r connected to two resistors each of resistance 2.50. The resistors are connected in parallel as shown. The current in one of the resistors is 0.80A. Which expression, where E is in volts and ris in ohms, gives the internal resistance r? E-4.0 B E-4.0 Cc E-2.0 D E-2.0 1.6 0.80 1.6 0.80 A
1 marks
Answer: C
35 The diagram shows a junction in a circuit where three wires, P, Q and R, meet. The currents in P and Q are 1 A and 3 A respectively, in the directions shown. Q 3 A 1 A P R How much charge passes a given point in wire R in a time of 5 s? A 0.4 C B 2 C C 10 C D 20 C
1 marks
Answer: C
36 The diagram shows a four-terminal box connected to a battery and two ammeters. 1 3 A A 2 4 The currents in the two ammeters are identical. Which circuit, within the box, gives this result? A B C D 1 3 1 3 1 3 1 3 2 4 2 4 2 4 2 4
1 marks
Answer: D
37 Each of Kirchhoff’s two laws presumes that some quantity is conserved. Which row states Kirchhoff’s first law and names the quantity that is conserved? statement quantity A The algebraic sum of currents charge at a junction is zero. B The algebraic sum of currents energy at a junction is zero. C The e.m.f. in a loop is equal to charge the algebraic sum of the product of current and resistance round the loop. D The e.m.f. in a loop is equal to energy the algebraic sum of the product of current and resistance round the loop.
1 marks
Answer: A
34 The sum of the electrical currents into a point in a circuit is equal to the sum of the currents out of the point. Which statement is correct? A This is Kirchhoff’s first law, which results from the conservation of charge. B This is Kirchhoff’s first law, which results from the conservation of energy. C This is Kirchhoff’s second law, which results from the conservation of charge. D This is Kirchhoff’s second law, which results from the conservation of energy.
1 marks
Answer: A
35 A battery of electromotive force (e.m.f.) 6.0V and negligible internal resistance is connected to three resistors, as shown. OV 6 my 60Q 0.12A The current in the battery is 0.12A. What is resistance R? A 12Q B 300 C 500 D 60
1 marks
Answer: B
34 The diagram shows a circuit containing a battery and cells with negligible internal resistance. Some values of current, electromotive force (e.m.f.) and resistance are shown. One resistor is labelled P. 9.0V = 3.0A P 2.0A 2.02 1.0V What is the resistance of resistor P? A 0.409 B 0.800 C 2.09 D 2.8Q
1 marks
Answer: A
37 The diagram shows the currents in part of an electric circuit. I1 I2 I4 I3 I5 The resistors are identical. Which equation is not correct? A I1 = I2 + I4 + I5 B I2 = I1 – I3 C I2 = I3 + I4 + I5 D I4 = I3 – I5
1 marks
Answer: C
37 The principles of conservation of which two quantities are associated with Kirchhoff’s first and second laws? first law second law A charge energy B charge voltage C energy charge D voltage charge
1 marks
Answer: A
34 The diagram shows a circuit containing a battery and cells with negligible internal resistance. Some values of current, electromotive force (e.m.f.) and resistance are shown. One resistor is labelled P. 9.0V = 3.0A P 2.0A 2.02 1.0V What is the resistance of resistor P? A 0.409 B 0.800 C 2.09 D 2.8Q
1 marks
Answer: A
37 The diagram shows the currents in part of an electric circuit. I1 I2 I4 I3 I5 The resistors are identical. Which equation is not correct? A I1 = I2 + I4 + I5 B I2 = I1 – I3 C I2 = I3 + I4 + I5 D I4 = I3 – I5
1 marks
Answer: C
36 Four resistors of resistance R, 2R, 3R and 4R are connected to form a network. A battery of negligible internal resistance and a voltmeter are connected to the resistor network as shown. 3R 4R V 2R R The voltmeter reading is 2 V. What is the electromotive force (e.m.f.) of the battery? A 2 V B 4 V C 6 V D 10 V
1 marks
Answer: C