The four operations — Paper 1 · IGCSE Mathematics 0580

1 At a weather centre the temperature at midnight was −21 oC. For By noon the next day it had risen to −4 oC. Examiner's By how many degrees had the temperature risen? Use Answer oC [1]

1 marks

Mark scheme: 1 17 1 Not -17

This question in 0580/11 Oct/Nov 2004

2 Place brackets in the following calculation to make it a correct statement. 10 − 5 × 9 + 3 = 60 [1]

1 marks

Mark scheme: 2 (10 - 5) x (9 + 3) 1 Ignore omission of final bracket only

This question in 0580/11 Oct/Nov 2004

17 Ferdinand’s electricity meter is read every three months. For The reading on 1st April was 70683 units and on 1st July it was 71701 units. Examiner's Use (a) How many units of electricity did he use in those three months? Answer(a) units [1] (b) Electricity costs 8.78 cents per unit. Calculate his bill for those three months. Give your answer in dollars, correct to the nearest cent. Answer(b) $ [2]

3 marks

Mark scheme: 17 (a) 1018 1 (b) 89.38 final answer ft. 2 M1 for his (a) x 8.78 soi or SC1 for answer in cents. IGCSE EXAMINATIONS – NOVEMBER 2004 0580/0581 1

This question in 0580/11 Oct/Nov 2004

7 The table below shows the average monthly temperatures (°C) in the Islas Orcadas, Argentina. Examiner's Use Jan Feb Mar Apr May June July Aug Sept Oct Nov Dec 1 1 0.5 –1 –5 –8 –9 –8 –5 –3 –1 0.5 (a) Work out the difference between the highest and the lowest average monthly temperature. Answer(a) °C [1] (b) The highest recorded temperature for July is x °C. This is 21 °C above the average for July shown in the table. Work out the value of x. Answer(b) x = [1]

2 marks

Mark scheme: 7 (a) 10 (allow –10) 1 (b) 12 1

This question in 0580/11 Oct/Nov 2005

1 The temperature at noon at an Antarctic weather centre was –15 °C. For At midnight it had fallen by 12 °C. Examiner's Use What was the temperature at midnight? Answer oC [1]

1 marks

Mark scheme: 1 –27 1

This question in 0580/11 May/June 2006

1 At noon one day the temperature is −9.5 °C. For By midnight the temperature has fallen by 3.6 °C. Examiner's What is the temperature at midnight? Use Answer °C [1]

1 marks

Mark scheme: Question Answers Mark Notes 1 −13.1 1

This question in 0580/11 Oct/Nov 2006

2 Insert brackets to make the following statement correct. 2 × 3 – 4 + 5 = 3 [1]

1 marks

Mark scheme: 2 2 × ( 3 − 4 ) + 5 = 3 1 & no other brackets

This question in 0580/11 Oct/Nov 2006

1 On a winter’s day in Vienna the maximum temperature was –2°C. For The minimum temperature was 11°C lower than this. Examiner's Write down the minimum temperature. Use Answer °C [1]

1 marks

Mark scheme: Question Answers Mark Notes 1 −13 1 Not 13–

This question in 0580/11 Oct/Nov 2007

3 On 1st August the level of water in a lake was −15 metres. A month later the level was 2 metres higher. 5 Write down the new level of water. 0 –5 –10 –15 Answer m [1]

1 marks

Mark scheme: 3 −13 1

This question in 0580/11 Oct/Nov 2008

0.0763 2 (a) Calculate . 1.85 + 4.7×8 Answer(a) [1] (b) Write 0.0763 in standard form. Answer(b) [1]

2 marks

Mark scheme: 2 (a) 0.00193(4….) 1 or 1.93(4…) × 10–3 (b) 7.63 × 10–2 1cao

This question in 0580/11 May/June 2009

1 Insert one pair of brackets to make the following equation correct. For Examiner's 2 × 8 − 5 − 4 = 15 Use [1]

1 marks

Mark scheme: Qu. Answers Mark Part Marks 1 2 × 8 − (5 − 4) = 15 1

This question in 0580/11 Oct/Nov 2009

1 Insert one pair of brackets to make the following equation correct. ForFor Examiner'sExaminer's 2 × 8 − 5 − 4 = 15 UseUse [1]

1 marks

Mark scheme: Qu. Answers Mark Part Marks 1 2 × 8 − (5 − 4) = 15 1

This question in 0580/12 Oct/Nov 2009

6 Martin recorded the outside temperature every three hours. At 07 00 the temperature was − 2°C. (a) This was 5°C higher than the temperature at 04 00. Write down the temperature at 04 00. Answer(a) °C [1] (b) At 10 00 the temperature was 11°C. Write down the increase in temperature between 07 00 and 10 00. Answer(b) °C [1]

2 marks

Mark scheme: 6 (a) –7 1 (b) 13 1 their (17000 − 15300 )7 10 2 M1 for 17000 15300 W1 for × 100 or answer 90(%) 17000

This question in 0580/11 May/June 2010

8 Examiner's Use 2x – 7 NOT TO SCALE x + 3 x The lengths, in centimetres, of the sides of a triangle are x , x + 3 and 2x − 7. The perimeter of the triangle is 52 cm. (a) Use this information to write down an equation in x. Answer(a) [1] (b) Find the value of x. Answer(b) x = [2]

3 marks

Mark scheme: 8 (a) x + x + 3 + 2x – 7 = 52 or better 1 (b) 14 2ft W1 for 4x or 56 seen Follow through their (a) if linear and equal to 52 for 1 or 2 marks.

This question in 0580/11 May/June 2010

1 On Monday the temperature was − 3°C. For On Tuesday the temperature fell by 5°C. Examiner's Use Write down the temperature on Tuesday. Answer °C [1]

1 marks

Mark scheme: Qu. Answers Mark Part Marks 1 −8 1 Accept negative or minus in place of ‘–’

This question in 0580/11 Oct/Nov 2010

3 Francis recorded a temperature of −4°C on Sunday. For By Monday it had gone down by 3°C. Examiner's Use (a) Find the temperature on Monday. Answer(a) °C [1] (b) On Tuesday the temperature was −1°C. Find the change in temperature between Monday and Tuesday. Answer(b) °C [1]

2 marks

Mark scheme: 3 (a) −7 1 (b) (+)6 1ft ft −1 − their (a)

This question in 0580/12 Oct/Nov 2010

14 9.6 × 7.8 − 0.53 × 86 4.95 (a) (i) Rewrite this calculation with each number written correct to 1 significant figure. Answer(a)(i) [1] (ii) Work out the answer to your calculation in part(a)(i). Do not use a calculator and show all your working. Answer(a)(ii) [2] (b) Use your calculator to work out the correct answer to the original calculation. Answer(b) [1]

4 marks

Mark scheme: 10 × 8 − 5.0 × 90 14 (a) (i) 1 5 (ii) 7(.0) cao 2 B1 for 80 (from 10 × 8) or 45 (from 0.5 × 90) or 5 (denominator) seen (b) 5.92 or 5.919(…..) 1

This question in 0580/12 Oct/Nov 2010

4 In a desert the temperature at noon was 38°C. At midnight the temperature was –3°C. (a) Find the change in temperature between noon and midnight. Answer(a) °C [1] (b) At 02 00 the temperature was 4°C below the midnight temperature. Write down the temperature at 02 00. Answer(b) °C [1]

2 marks

Mark scheme: 4 (a) 41 or −41 1 (b) −7 1 2 2

This question in 0580/13 Oct/Nov 2010

1 (a) Write down ten thousand and seventy three in figures. For Examiner's Answer(a) [1] Use (b) Work out 13 + 5 × 4 – 2. Write down all the steps of your working. Answer(b) [1]

2 marks

Mark scheme: Qu. Answers Mark Part Marks 1 (a) 10 073 1 (b) 13 + 20 − 2 = 31 1 Accept 20 seen with answer 31

This question in 0580/13 May/June 2011

1 The temperature on Monday is 3 °C. For On Tuesday it is 5 °C lower. Examiner's Use Find the temperature on Tuesday. Answer °C [1]

1 marks

Mark scheme: Qu. Answers Mark Part Marks 1 −2(°C) 1

This question in 0580/12 Oct/Nov 2011

4 Insert one pair of brackets into each calculation to make the answer correct. (a) 7 × 6 – 3 + 5 = 26 [1] (b) 8 – 6 × 4 – 1 = –10 [1]

2 marks

Mark scheme: 4 (a) 7 × (6 − 3) + 5 1 (b) 8 − 6 × (4 − 1) 1

This question in 0580/13 Oct/Nov 2011

9 The temperature at the top of a mountain is –12°C. The temperature at the bottom of the mountain is 18°C. (a) Work out the difference in these temperatures. Answer(a) °C [1] (b) 18°C is given correct to the nearest degree. Write down the upper bound for this temperature. Answer(b) °C [1]

2 marks

Mark scheme: 9 (a) 30 1 (b) 18.5 1 x

This question in 0580/11 May/June 2012

15 Without using your calculator, work out the following. For Show all the steps of your working and give each answer as a fraction in its simplest form. Examiner's Use 11 1 (a) − 12 3 Answer(a) [2] 1 11 (b) ÷ 4 13 Answer(b) [2]

4 marks

Mark scheme: 15 (a) 11 4 M1 correct use of a common denominator − oe 2 12 12 7 cao ww 0 A1 12 1 13 (b) × oe 2 M1 inversion and operation change 4 11 13 cao ww 0 44 A1 21

This question in 0580/13 May/June 2012

18 (a) Find the value of 7p – 3q when p = 8 and q = O5 . Answer(a) [2] (b) Factorise completely. 3uv + 9vw Answer(b) [2]

4 marks

Mark scheme: 18 (a) 71 2 M1 for 7×8 – 3×–5 or B1 56 and –15 (b) 3v (u + 3w) final answer 2 B1 for 3(uv + 3vw) or v (3u + 9w) As final answer

This question in 0580/13 May/June 2012

8 Work out. For Examiner's Use (a) 4 – 5 – 6 Answer(a) [1] − 8 (b) − 2 Answer(b) [1]

2 marks

Mark scheme: 8 (a) –7 1 (b) (+) 4 1

This question in 0580/12 Oct/Nov 2012

2 One January day in Munich, the temperature at noon was 3°C. At midnight the temperature was –8°C. Write down the difference between these two temperatures. Answer … °C [1] _____________________________________________________________________________________

1 marks

Mark scheme: 2 11 or −11 1

This question in 0580/11 May/June 2013

18 (a) –3 – 4 –7 2 5 Choose three different numbers from the list to complete this calculation. … + … + … = – 6 [1] (b) Find the value of 5x – 3y when x = –2 and y = 4. Answer(b) … [2] _____________________________________________________________________________________

3 marks

Mark scheme: 18 (a) –4, –7, [+]5 in any order 1 (b) –22 2 M1 for –10 and –12 seen SC1 for –10 +12 seen 5 k B1 f

This question in 0580/12 May/June 2013

5.27 - 0 .938 Calculate . 4 .89 - 4. 07 Give your answer correct to 4 signifi cant fi gures. Answer … [2] _____________________________________________________________________________________

2 marks

Mark scheme: 8 5.293 cao 2 B1 for 5.29 or 5.292 to 5.2927

This question in 0580/11 Oct/Nov 2013

4 -2 1 20 a = b = c = -5 0 e 3 o e o e o Find (a) 4a, Answer(a) [2] f p (b) b – c. Answer(b) [2] f p _____________________________________________________________________________________

4 marks

Mark scheme:  16  20 (a)   2 B1 for each correct component 12   − 3  (b)   2 B1 for each correct component 5   9 1 ( )

This question in 0580/11 Oct/Nov 2013

1 Put one pair of brackets into this equation to make it correct. For Examiner′s Use 3 + 5 × 4 – 2 = 13 [1] _____________________________________________________________________________________

1 marks

Mark scheme: Qu. Answer Mark Part Marks 1 3 + 5 × (4 – 2) 1 2 

This question in 0580/12 Oct/Nov 2013

6 Use a calculator to work out the following. (a) 3 (– 4 × 62 – 5) Answer(a) … [1] (b) 3 × tan 30° + 2 × sin 45° Answer(b) … [1] _____________________________________________________________________________________

2 marks

Mark scheme: 6 (a) −447 1 (b) 2 1

This question in 0580/12 Oct/Nov 2013

1 Work out. 10 – 3 × 2 Answer … [1] __________________________________________________________________________________________

1 marks

Mark scheme: 1 4 1

This question in 0580/11 May/June 2014

5 (a) The temperature on Monday was –6°C. On Tuesday the temperature was 3 degrees lower. Write down the temperature on Tuesday. Answer(a) … °C [1] (b) The temperature on Saturday was –2°C. The temperature on Sunday was 8°C. Write down the difference in these two temperatures. Answer(b) … °C [1] __________________________________________________________________________________________

2 marks

Mark scheme: 5 (a) –9 1 (b) 10 or −10 1

This question in 0580/12 May/June 2014

4 Calculate. 56.2 - 34.8 - 0.2 Answer … [1] __________________________________________________________________________________________

1 marks

Mark scheme: 4 −107 1

This question in 0580/13 May/June 2014

11 –3 –5 1 0 3 Three different numbers from the list are added together to give the smallest possible total. Complete the sum below. … + … + … = … [2] __________________________________________________________________________________________

2 marks

Mark scheme: 11 –3, –5, 0 [=] –8 2 B1 for –3, –5 and 0 in any order seen on left hand side. or B1 for –8 seen on answer line in correct position

This question in 0580/13 May/June 2014

1 Insert one pair of brackets only to make the following statement correct. 6 + 5 × 10 – 8 = 16 [1] __________________________________________________________________________________________

1 marks

Mark scheme: Qu. Answer Mark Part marks 1 6 + 5 × (10 – 8) = 16 1 One pair of brackets only

This question in 0580/12 Oct/Nov 2014

8.24 + 2.56 .2 Calculate 1.26 - 0.72 Answer … [1] __________________________________________________________________________________________

1 marks

Mark scheme: 2 20 1

This question in 0580/12 Oct/Nov 2014

2 The temperature in Berlin is –7 °C and the temperature in Istanbul is –3 °C. (a) Write down how many degrees colder it is in Berlin than it is in Istanbul. Answer(a) … °C [1] (b) Sydney is 23 degrees warmer than Berlin. Write down the temperature in Sydney. Answer(b) … °C [1] __________________________________________________________________________________________

2 marks

Mark scheme: 2 (a) 4 1 (b) 16 1

This question in 0580/11 May/June 2015

8 (a) Work out. (–6) – (–8) Answer(a) … [1] (b) Write in the missing number. –3 × … = 18 [1] __________________________________________________________________________________________

2 marks

Mark scheme: 8 (a) [+] 2 1 (b) −6 1

This question in 0580/13 May/June 2015

6.4 + 7.3 .18 (a) Calculate 19.56 - 3.51 Give your answer correct to 2 significant figures. Answer(a) … [2] (b) Write the following numbers in order of size, smallest first. 5 57% 0.5077 0.507 9 Answer(b) … < … < … < … [2] __________________________________________________________________________________________

4 marks

Mark scheme: 18 (a) [0].85 final answer 2 B1 for 0.853[5…] or 13.7 and 16.05 seen 5 (b) 0.507 0.5077 57% 2 M1 for 3 in the correct order 9 or B1 for [0].57 and [0].55… or 0.56

This question in 0580/13 May/June 2015

2 At midnight the temperature in Newtown was –8 °C. At noon the next day the temperature in Newtown was 9 °C. Work out the rise in temperature from midnight to noon. Answer … °C [1] __________________________________________________________________________________________

1 marks

Mark scheme: 2 [+]17 1 4

This question in 0580/11 Oct/Nov 2015

5 Calculate. (a) 3.2 × (5.7 – 1.3) + 4.8 Answer(a) … [1] (b) 2.54 - 0.85 Answer(b) … [1] __________________________________________________________________________________________

2 marks

Mark scheme: 5 (a) 18.88 cao final answer 1 (b) 1.3 1 13  12 

This question in 0580/11 Oct/Nov 2015

1 Write down the difference in temperature between 8°C and −9°C. Answer … °C [1]

1 marks

Mark scheme: Question Answer Mark Part marks 1 17 1

This question in 0580/12 Oct/Nov 2015

2.07 - 1.89 .5 Calculate 5.71 - 3.92 Answer … [1] __________________________________________________________________________________________

1 marks

Mark scheme: 5 [0].101 or [0].1005 to [0].1006 1

This question in 0580/13 Oct/Nov 2015

10 (a) At 9 am the temperature was –3°C. At 1pm the temperature had risen by 5°C. Work out the temperature at 1pm. Answer(a) … °C [1] (b) Work out –7 – 2. Answer(b) … [1] __________________________________________________________________________________________

2 marks

Mark scheme: 10 (a) 2 1 (b) −9 1 2

This question in 0580/13 Oct/Nov 2015

8 In each part, fill in the missing number to make a correct statement. (a) ^- 6 + 11h # … = - 20 [1] 7 … (b) = [1] 8 176

2 marks

Mark scheme: 8 (a) –4 1 (b) 154 1 2

This question in 0580/12 Feb/March 2016

2 Calculate. 4 3.07 + 2 5.03 - 1.79 … [1]

1 marks

Mark scheme: 2 5.89 or 5.885 to 5.886 1

This question in 0580/12 May/June 2016

21 The table shows the temperature each night for a week. Monday Tuesday Wednesday Thursday Friday Saturday Sunday –3 °C 1 °C – 4 °C –2 °C 5 °C 3 °C –1 °C (a) Which night was the coldest? … [1] (b) Find the difference between the temperature on Monday night and the temperature on Tuesday night. … °C [1] (c) Find the range. … °C [1] (d) Find the median. … °C [1]

4 marks

Mark scheme: 21 (a) Wed[nesday] 1 (b) 4 1 (c) 9 1 (d) –1 nfww 1 1

This question in 0580/12 May/June 2016

5 Calculate. 17.85 - 7.96 18 - 3.5 2 … [1]

1 marks

Mark scheme: 5 1.72 1

This question in 0580/13 May/June 2016

6 2 3 –4 –6 –8 From the list of numbers, write down (a) three numbers whose sum is –12, … , … , … [1] (b) two numbers whose product is –24. … , … [1]

2 marks

Mark scheme: 6 (a) 2 −6 −8 1 (b) 3 −8 1 1

This question in 0580/13 May/June 2016

2 Write down the temperature which is 5 °C below –2 °C. … °C [1]

1 marks

Mark scheme: 2 −7 1

This question in 0580/11 Oct/Nov 2016

5 (a) Put one pair of brackets into this calculation to make it correct. 6 + 12 ÷ 2 × 3 = 8 [1] (b) Work out. 1.17 + 1.28 3.92 … [1]

2 marks

Mark scheme: 5 (a) 6 + 12 ÷ (2 × 3) = 8 1 (b) 0.625 oe 1  15 

This question in 0580/12 Oct/Nov 2016

7 The temperature at midnight was –8°C. The temperature at 5 am was –3°C. (a) Work out the difference between the two temperatures. … °C [1] (b) The temperature at midday was 9°C higher than the temperature at 5 am. Work out the temperature at midday. … °C [1]

2 marks

Mark scheme: 7 (a) 5 1 (b) 6 1

This question in 0580/12 Oct/Nov 2016

2 Work out. −2 + 7 – 8 … [1]

1 marks

Mark scheme: 2 –3 1

This question in 0580/13 Oct/Nov 2016

18 (a) Work out. 5 - 3 + c - 1 m c 2 m [1] f p (b) A is the point (3, 6) and B is the point (5, 10). Work out AB. AB = [1] f p 1 (c) C is the point (5, 8) and CD = c 2 m. Find the co-ordinates of the point D. ( … , … ) [1]

3 marks

Mark scheme:  18 (a)  1 1 2 (b)  1 4 (c) (6, 10) 1

This question in 0580/13 Oct/Nov 2016

1 Write down the difference in temperature between -4 °C and -9 °C. … °C [1]

1 marks

Mark scheme: Question Answer Marks Part Marks 1 5 1

This question in 0580/12 Feb/March 2017

21 (a) Work out. 3 1 + c- 2 m c- 1m [1] f p (b) y 10 9 A 8 7 6 B 5 4 3 2 1 x 0 1 2 3 4 5 6 7 8 9 10 Points A and B are marked on the grid. - 4 BC = c 0m (i) On the grid, plot the point C. [1] (ii) Write AC as a column vector. [1] f p

3 marks

Mark scheme:  4  21 (a)   1  −3  (b) (i) Point at (3, 5) 1 JJJG  1  (ii) 1FT FT their AC    −3  1

This question in 0580/12 Feb/March 2017

10 The table shows the temperatures in five places at 10 am one day in January. Place Temperature (°C) Helsinki -7 Chicago -10 London 3 Moscow -4 Bangkok 26 (a) Which place was the coldest? … [1] (b) At 2 pm the temperature in Helsinki had increased by 4 °C. Write down the temperature in Helsinki at 2 pm. … °C [1]

2 marks

Mark scheme: 10(a) Chicago 1 10(b) −3 1

This question in 0580/11 May/June 2017

18 (a) Work out. 3 + 2 # - 4 … [1] (b) In each of these, insert one pair of brackets to make the statement correct. (i) 3 # 5 + 2 + 2 = 23 [1] (ii) 12 ÷ 4 + 2 = 2 [1]

3 marks

Mark scheme: 18(a) –5 1 18(b)(i) 3 × (5 + 2) + 2 = 23 1 18(b)(ii) 12 ÷ (4 + 2) = 2 1

This question in 0580/11 May/June 2017

7 The daily temperature, in °C, at 3 pm in a town is shown below. Monday Tuesday Wednesday Thursday Friday Saturday Sunday 3 -2 1 2 -4 3 5 (a) Which day had the coldest temperature? … [1] (b) Work out the difference in the temperatures on Friday and Saturday. … °C [1]

2 marks

Mark scheme: 7(a) Friday 1 7(b) 7 1

This question in 0580/12 May/June 2017

11 Complete these calculations to make them correct. 24 + 8 (a) = … 4 [1] (b) -18 ÷ … = 2 [1] 7 … 21 (c) # = 8 40 … [1]

3 marks

Mark scheme: 11(a) 8 1 11(b) −9 1 11(c) 3 1 or equivalent fraction 5

This question in 0580/13 May/June 2017

14 Work out. 3 - 1 (a) + d 2 n d 5n [1] f p 6 4 (b) - d 3 n d - 2 n [1] f p 2 (c) 4 d 5 n [1] f p

3 marks

Mark scheme: 14(a) 2 1  7 14(b) 2 1  5 14(c)  8  1    20 

This question in 0580/11 Oct/Nov 2017

2 One day, at noon, in Maseru, the temperature was 17 °C. At midnight the temperature was 20 °C lower. Work out the temperature at midnight. … °C [1]

1 marks

Mark scheme: 2 −3 1

This question in 0580/12 Oct/Nov 2017

7 Work out. 6.32 + 2.06 4.15 - 0.12 Give your answer correct to 1 decimal place. … [2]

2 marks

Mark scheme: 7 2.1 2 B1 for 2.08 or 2.079… or 2.10

This question in 0580/12 Oct/Nov 2017

13 The table shows the temperature at midday in some cities on 1st February. City Temperature Berlin 6 °C Moscow –10 °C Stockholm 1 °C Toronto 0 °C Warsaw –2 °C (a) Write down the city with the lowest temperature. … [1] (b) Work out the difference between the temperature in Berlin and the temperature in Warsaw. … °C [1] (c) The temperature in Minsk was 3 °C higher than the temperature in Moscow. Work out the temperature in Minsk. … °C [1]

3 marks

Mark scheme: 13(a) Moscow 1 13(b) 8 1 13(c) –7 1

This question in 0580/13 Oct/Nov 2017

19 (a) Work out. 5 2 (i) + c- 1m c 6 m [1] f p - 5 (ii) 4 c 2m [1] f p (b) y 4 3 P 2 1 x 0 –4 –3 –2 –1 1 2 3 4 –1 –2 –3 –4 4 P is the point (-1, 2) and PQ = c- 3m. Find the co-ordinates of Q. ( … , … ) [1]

3 marks

Mark scheme: 19(a)(i) 7 1  5 19(a)(ii)  − 20  1    8  19(b) 3, −1 1

This question in 0580/13 May/June 2018

9 (a) On Monday, the lowest temperature was –12 °C. The highest temperature was 4 °C. Work out the difference between these temperatures. … °C [1] (b) On Tuesday, the highest temperature was –3 °C. The lowest temperature was 8 °C lower than this. Work out the lowest temperature on Tuesday. … °C [1]

2 marks

Mark scheme: 9(a) 16 1 9(b) –11 1

This question in 0580/11 Oct/Nov 2018

16 Calculate. (a) .413 … [1] (b) - 4 - 5 2 - 2 # 4 # - 3 ^ h … [1] 4.88 - 2.36 (c) 5.3 + 1.9 … [1] (d) 56.25 - 3 15.625 … [1]

4 marks

Mark scheme: 16(a) 68.921 1 16(b) –53 1 16(c) [0].35 1 16(d) 5 1

This question in 0580/12 Oct/Nov 2018

4 Calculate. 5.39 - 0.98 0.743 - 0.0743 … [1]

1 marks

Mark scheme: 4 6.59 or 6.594 to 6.595 1

This question in 0580/13 Oct/Nov 2018

2 - 3 6 Work out - c 5 m c 4m. [1] f p

1 marks

Mark scheme: 6 5 1  1

This question in 0580/13 Oct/Nov 2018

9 (a) At noon on Wednesday, the temperature was 5 °C. At midnight, the temperature was 8 °C lower. Work out the temperature at midnight. … °C [1] (b) At noon on Saturday, the temperature was 15 °C. At midnight, the temperature was –3 °C. Work out the difference in these temperatures. … °C [1]

2 marks

Mark scheme: 9(a) −3 1 9(b) 18 1

This question in 0580/13 Oct/Nov 2018

4 The temperature at 07 00 is -3 °C. This temperature is 11 °C higher than the temperature at 01 00. Find the temperature at 01 00. … °C [1]

1 marks

Mark scheme: 4 −14 1

This question in 0580/12 Feb/March 2019

5 (a) On Monday the temperature at midday is 4 °C and the temperature at midnight is -3 °C. Work out the difference between these two temperatures. … °C [1] (b) On Wednesday the temperature at midday is -1 °C. By 7 pm the temperature has fallen by 4 °C. Work out the temperature at 7 pm. … °C [1]

2 marks

Mark scheme: 5(a) 7 1 5(b) −5 1

This question in 0580/11 May/June 2019

3 Insert one pair of brackets to make this statement correct. 4 # 6 - 2 + 1 = 17 [1]

1 marks

Mark scheme: 3 4 × (6 – 2) + 1 = 17 1

This question in 0580/12 May/June 2019

5 (a) Subtract 123 from 1 million. … [1] (b) Subtract 9 from 2. … [1]

2 marks

Mark scheme: 5(a) 999 877 1 5(b) −7 1

This question in 0580/12 May/June 2019

5 Giulio’s reaction times are measured in two games. In the first game his reaction time is 13 of a second. In the second game his reaction time is 18 of a second. Find the difference between the two reaction times. … s [1]

1 marks

Mark scheme: 5 5 1 or 0.208 or 0.2083… 24

This question in 0580/13 May/June 2019

8 Calculate. (a) - 12 ' - 2 … [1] (b) 3 2 3 + 2 … [1]

2 marks

Mark scheme: 8(a) 6 1 8(b) 2.15 or 2.154 … 1

This question in 0580/13 May/June 2019

2 The lowest temperature recorded at Scott Base in Antarctica is -57.0 °C. The highest temperature recorded at Scott Base is 63.8 °C more than this. What is the highest temperature recorded at Scott Base? … °C [1]

1 marks

Mark scheme: 2 6.8 1

This question in 0580/12 Oct/Nov 2019

5 Put one pair of brackets into each calculation to make it correct. (a) 8 + 6 - 2 # 5 = 28 [1] (b) 8 + 6 - 2 # 5 = 60 [1]

2 marks

Mark scheme: 5(a) 8 + (6 – 2) × 5 = 28 1 5(b) (8 + 6 – 2) × 5 = 60 1

This question in 0580/13 Oct/Nov 2019

6 (a) Write down the temperature that is 7 °C below -3 °C. … °C [1] (b) Work out the difference in temperature between -4 °C and 4 °C. … °C [1]

2 marks

Mark scheme: 6(a) −10 1 6(b) 8 1

This question in 0580/13 Oct/Nov 2019

3 (a) The temperature on Monday was -7 °C. The temperature on Tuesday was 5 °C lower than on Monday. The temperature on Wednesday was 8 °C higher than on Tuesday. Find the temperature on Wednesday. … °C [2] (b) Kyra has a faulty thermometer. It always shows the temperature as 2 °C higher than the actual temperature. The temperature on the thermometer is T °C. Write an expression, in terms of T, for the actual temperature. … °C [1]

3 marks

Mark scheme: 3(a) −4 2 B1 for −12 seen or M1 for −7 − 5 + 8 or better 3(b) T – 2 cao 1

This question in 0580/12 Feb/March 2020

5 Put one pair of brackets in each statement to make it correct. (a) 16 ' 8 + 4 # 2 = 1 [1] (b) 16 ' 8 + 4 # 2 = 12 [1]

2 marks

Mark scheme: 5(a) 16 ÷ (8 + 4 × 2) = 1 1 5(b) (16 ÷ 8 + 4) × 2 = 12 1

This question in 0580/12 May/June 2020

68 + 183 Edelgard tries to calculate . 9 - 5 (a) She types into her calculator 68 + 18 ' 9 - 5 . Explain why this does not give Edelgard the correct answer. … [1] 68 + 18 (b) Work out the correct answer to . 9 - 5 … [1]

2 marks

Mark scheme: 3(a) Correct reason 1 3(b) 21.5 oe 1

This question in 0580/13 May/June 2020

5 Write down the number that is 7 more than -38. … [1]

1 marks

Mark scheme: 5 − 31 1

This question in 0580/13 May/June 2020

10 Work out. 2 5 (a) + e- 3o e- 1o [1] f p 2 (b) 4 e- 5o [1] f p

2 marks

Mark scheme: 10(a)  7  1    −4  10(b)  8  1    − 20 

This question in 0580/11 Oct/Nov 2020

8 Work out the difference in temperature between - 6 °C and 5 °C. … °C [1]

1 marks

Mark scheme: 8 11 1

This question in 0580/12 Oct/Nov 2020

7 (a) This table shows the temperature, in °C, at midnight and at 3 pm for four cities on the same day. City Temperature at midnight (°C) Temperature at 3 pm (°C) Sydney 21 28 Oslo –3 1 Toronto –18 –8 Seoul –5 4 Use the table to complete this statement. The city with the biggest difference in temperature between midnight and 3 pm is … with a difference of … °C. [2] (b) The temperature at midnight in Moscow was –11 °C. At 3 pm the temperature has increased by 5 °C. Work out the temperature at 3 pm. … °C [1]

3 marks

Mark scheme: 7(a) Toronto 10 2 B1 for each 7(b) –6 1

This question in 0580/13 Oct/Nov 2020

2 (a) Find the value of 225. … [1] 2 (b) Write down the reciprocal of . 3 … [1] (c) Work out three‑quarters of one‑third. … [1] (d) Work out - 7 - ( 6 - 8) . … [1]

4 marks

Mark scheme: 2(a) 15 1 2(b) 1 1 12 oe 2(c) 1 1 oe 4 2(d) –5 1

This question in 0580/11 May/June 2021

6 (a) Without using a calculator, work out 9 + 5 # 7 - 4 ' 2 . You must show all your working. … [2] (b) Insert one pair of brackets into this statement to make it correct. 9 + 5 # 7 - 4 ' 2 = 96 [1]

3 marks

Mark scheme: 6(a) 9 + 35 − 2 M1 42 A1 6(b) (9 + 5) × 7 – 4 ÷ 2 = 96 cao 1

This question in 0580/12 May/June 2021

8 Write down the number that you (a) add to - 4 to give an answer of 9, … [1] (b) subtract from - 9 to give an answer of - 4 . … [1]

2 marks

Mark scheme: 8(a) 13 1 8(b) −5 1

This question in 0580/12 May/June 2021

3 Write down the number that is 23 less than - .16 . … [1]

1 marks

Mark scheme: 3 –24.6 1

This question in 0580/13 May/June 2021

5 218 Without using a calculator, work out 1 + . 6 5 You must show all your working and give your answer as a mixed number in its simplest form. … [3]

3 marks

Mark scheme: 18 25 or 55 12 M1 25 k or 55 k 12 k and Accept and 30 30 30 k 30 k 7 A2 67 k 37 k 2 cao A1 for or 1 30 30 k 30 k

This question in 0580/11 Oct/Nov 2021

8 The temperature at midnight is -8.5 °C. The temperature at 11 am is -1 °C. Work out the difference between the temperature at midnight and the temperature at 11 am. … °C [1]

1 marks

Mark scheme: 8 7.5 1

This question in 0580/12 Oct/Nov 2021

8 The temperature at midnight was -8 °C. The temperature at noon is 6 °C. (a) Work out the difference between these two temperatures. … °C [1] (b) The temperature at 7 am is 5 °C higher than the temperature at midnight. Work out the temperature at 7 am. … °C [1]

2 marks

Mark scheme: 8(a) 14 1 8(b) –3 1

This question in 0580/13 Oct/Nov 2021

12 (a) = ! 2 1 Put a ring around each of the symbols that make this statement correct. 0.5 … 5% [1] (b) Insert one pair of brackets to make this statement correct. 7 - 3 - 1 + 2 = 7 [1]

2 marks

Mark scheme: 12(a) ≠ and > indicated 1 12(b) 7– (3 – 1) + 2 = 7 cao 1

This question in 0580/13 Oct/Nov 2021

11 322 Without using a calculator, work out + . 12 4 You must show all your working and give your answer as a mixed number in its simplest form. … [3]

3 marks

Mark scheme: 22 11 9 M1 Allow any correct common denominator + oe 12k 12 12 2 A2 20 13 cao A1 for 12 or equivalent improper fraction or mixed number

This question in 0580/13 Oct/Nov 2021

6 This is Edha’s method to work out 99 # 27 without using a calculator. 99 # 27 = 100 # 27 - 27 = 2700 - 27 = 2673 Show how to use Edha’s method to work out 99 # 68 without using a calculator. [2]

2 marks

Mark scheme: 6 100 × 68 − 68 2 M1 for 100 × 68 − 68 = 6800 − 68 = 6732

This question in 0580/12 Feb/March 2022

9 Put one pair of brackets into this calculation to make it correct. 150 - 17 - 5 # 2 2 = 33 [1]

1 marks

Mark scheme: 9 2 1 150 − 17 − ( 5 × 2 ) = 33

This question in 0580/12 Feb/March 2022

20 Balavan has n marbles. n He gives his sister marbles. 5 n He gives his cousin marbles. 2 Write an expression, in terms of n, for the number of marbles that Balavan has now. Give your answer in its simplest form. … [2]

2 marks

Mark scheme: 20 3 2 7 1 1 n B1 for n or n − n − n oe 10 10 5 2

This question in 0580/12 Feb/March 2022

1 - 0.711 Calculate , giving your answer correct to 4 significant figures. 0. 45 - 0.38 … [2]

2 marks

Mark scheme: 11 4.286 cao 2 30 B1 for 4.285[7...] or 4.29 or or 7 2 4 7 or for correctly rounding their more accurate decimal to 4sf

This question in 0580/11 May/June 2022

16 v = 3 - 5t (a) Work out the value of v when t = 4. v = … [1] (b) Make t the subject of the formula. t = … [2]

3 marks

Mark scheme: 16(a) −17 1 16(b) 3 v v  3 2 M1 for or final answer 5 5 v 3 5t = 3 – v or v – 3 = −5t or   t 5 5

This question in 0580/11 May/June 2022

22 The table shows the population and area of three countries in 2020. Country Population Area (km2) Nigeria .206 # 108 9.11 # 10 5 Comoros 8.70 # 10 5 1.86 # 10 3 Vietnam 9.73 # 10 7 3.10 # 10 5 (a) Calculate the difference in population between Nigeria and Vietnam. … [1] (b) Which of Comoros or Vietnam has the greater population density? You must show all your working. population Population density = 2 > area(km ) H … [3]

4 marks

Mark scheme: 22(a) 108 700 000 1 or 1.087 × 108 22(b) 8.70 × 105 ÷ 1.86 × 103 oe M1 9.73 × 107 ÷ 3.10 × 105 oe M1 Comoros A1 Dependent on M2

This question in 0580/11 May/June 2022

7 Put one pair of brackets into each calculation to make it correct. (a) 6 # 7 - 5 + 4 = 16 [1] (b) - 2 2 + 24 ' 12 - 4 = 2 [1]

2 marks

Mark scheme: 7(a) 6 × ሺ 7 −5 ሻ+ 4 = 16 1 7(b) (−2 )ଶ+ 24 ÷ 12 − 4 = 2 1

This question in 0580/12 May/June 2022

8 At noon, the temperature is 4 °C. At midnight, the temperature is - 9 °C. Work out the difference in temperature between noon and midnight. … °C [1]

1 marks

Mark scheme: 8 13 or −13 1

This question in 0580/12 May/June 2022

7 The temperature, in °C, is recorded at the same time in six cities. London Helsinki Oslo Paris Madrid Berlin 6 –2 –5 7 9 2 (a) Which city has the coldest temperature? … [1] (b) What is the difference in temperature between Helsinki and Paris? … °C [1]

2 marks

Mark scheme: 7(a) Oslo 1 7(b) 9 1

This question in 0580/11 Oct/Nov 2022

1 513 Without using a calculator, work out + . 3 6 You must show all your working and give your answer as a mixed number in its simplest form. … [2]

2 marks

Mark scheme: 13 2 5 M1 i.e. correct fractions with common + oe denominator 6k 6 6 1 A1 16 cao

This question in 0580/11 Oct/Nov 2022

6 Put one pair of brackets in each statement to make it correct. (a) 10 - 4 ' 2 + 18 = 21 [1] (b) 7 # 3 + 1 + 2 = 30 [1]

2 marks

Mark scheme: 6(a) (10 − 4) ÷ 2 + 18 = 21 1 6(b) 7 × (3 + 1) + 2 = 30 1

This question in 0580/12 Oct/Nov 2022

3 -7 12 -3 2 8 -6 15 -4 -8 From the list of numbers, find (a) all the numbers which are less than -5 … [1] (b) the product of the largest number and the smallest number. … [1]

2 marks

Mark scheme: 3(a) −6, −7, −8 1 3(b) −120 1

This question in 0580/12 Feb/March 2023

6 Find the temperature that is 8 °C colder than - 5 °C. … °C [1]

1 marks

Mark scheme: 6 –13 1

This question in 0580/12 May/June 2023

3 Work out. - 4 + 6 # 3 … [1]

1 marks

Mark scheme: 3 14 1

This question in 0580/13 May/June 2023

6 Write down the number that is 9 greater than - 23 . … [1]

1 marks

Mark scheme: 6 –14 1

This question in 0580/12 Oct/Nov 2023

10 - 9 - 7 - 3 - 1 0 2 5 6 8 From this list of numbers, find (a) the highest number possible from the product of two of the numbers … [1] (b) the lowest number possible from the product of three of the numbers. … [1]

2 marks

Mark scheme: 10(a) 63 1 10(b) −432 1

This question in 0580/12 Feb/March 2024

6 (a) Work out. 28 - 16 ' 2 … [1] (b) Find the reciprocal of 4. 5 … [1]

2 marks

Mark scheme: 6(a) 20 1 6(b) 1 1 1.25 or 1 oe 4

This question in 0580/11 May/June 2024

7 The temperature on Monday is –27 °C. The temperature on Tuesday is 15 °C higher than on Monday. Work out the temperature on Tuesday. … °C [1]

1 marks

Mark scheme: 7 12 1

This question in 0580/11 May/June 2024

6 The temperature at midnight is -4 °C. The temperature at noon is 25 °C. Work out the difference between these two temperatures. … °C [1]

1 marks

Mark scheme: 6 29 1

This question in 0580/12 May/June 2024

2 Put one pair of brackets into this calculation to make it correct. 5 + 4 # 3 + 9 = 53 [1]

1 marks

Mark scheme: 2 5 + 4 × (3 + 9) = 53 1

This question in 0580/13 May/June 2024

9 One day the temperature in Tokyo is - 5 °C and the temperature in Manila is 18 °C. (a) Work out the difference between these two temperatures. … °C [1] (b) The temperature in Tokyo rises by 4 °C. Find the new temperature in Tokyo. … °C [1]

2 marks

Mark scheme: 9(a) 23 1 9(b) –1 1

This question in 0580/13 May/June 2024

7 Put one pair of brackets in each calculation to make it correct. (a) 15 + 12 - 3 # 4 = 51 [1] (b) 15 + 12 - 3 # 4 = 96 [1]

2 marks

Mark scheme: 7(a) 15 + (12 − 3) × 4 = 51 1 7(b) (15 + 12 − 3) × 4 = 96 1

This question in 0580/12 Oct/Nov 2024

11 The temperature in town A is - 8 °C and the temperature in town B is 16 °C. (a) Find the difference in these two temperatures. … °C [1] (b) The temperature in town A rises by 12 °C. Find the temperature in town A now. … °C [1]

2 marks

Mark scheme: 11(a) 24 1 11(b) 4 1

This question in 0580/12 Oct/Nov 2024

18 Simplify. 18 x 6 3x 2 … [2]

2 marks

Mark scheme: 18 6x4 final answer 2 B1 for 6xk (k ≠ 0) or mx4 (m ≠ 0) as final answer or correct answer spoilt

This question in 0580/12 Oct/Nov 2024

1 11 18 Without using a calculator, work out 2 - 1 . 4 12 You must show all your working and give your answer as a fraction in its simplest form. … [3]

3 marks

Mark scheme: 18 B1 Correct step for dealing with mixed numbers 9 23 1 11 oe or − 9 k 23k 4 12 14 12 Allow or 4 k 12 k oe M1 Correct method to find common denominator 27 23 11 and 31 and 3 11 12 12 12 12 e.g. 2 and 1 12 12 1 A1 cao 3

This question in 0580/13 Oct/Nov 2024

7 Work out - 6 # - 3 + 7 # 2 . … [2]

2 marks

Mark scheme: 7 32 2 B1 for 18 or 14

This question in 0580/12 Feb/March 2025

11 19.5 # 20 .4 = 397. 8 Work out. (a) 1.95 # 2 .04 … [1] (b) 3978 ' 204 … [1]

2 marks

Mark scheme: 11(a) 3.978 1 11(b) 19.5 1

This question in 0580/12 Feb/March 2025

1 3 24 Work out 1 + 1 . 3 4 Give your answer as a mixed number in its simplest form. … [3]

3 marks

Mark scheme: 24 1 3 4 7 3 nfww B1 for or oe 12 3 4 1 3 or for 2 + + oe 3 4 16 21 4 9 M1 for and or and 12 12 12 12

This question in 0580/11 May/June 2025

12 Tim has a method for multiplying a number by 99. He shows his method for 53 # 99 . 53 # 99 = 53 # 100 - 53 = 5300 - 53 = 5247 Work out 85 # 99 using Tim’s method. … [2]

2 marks

Mark scheme: 12 85 × 99 M1 85  100 − 85 8500 − 85 8415 A1

This question in 0580/12 May/June 2025

3 (a) Write down 169 . … [1] (b) Work out the value of 24. … [1] (c) Work out the value of 10 -2 . … [1] (d) Work out -18 ' -4 . … [1] (e) Work out 1.6 # 0. 02 . … [1]

5 marks

Mark scheme: 3(a) 13 1 3(b) 16 1 3(c) 1 1 or 0.01 100 3(d) 9 1 1 or 4.5 or 4 2 2 3(e) 0.032 1

This question in 0580/13 May/June 2025

1 4 24 Work out 3 - 1 . 2 7 Give your answer as a mixed number in its simplest form. … [3]

3 marks

Mark scheme: 24 13 3 27 114 cao nfww B2 for 14 7 k 11k or B1 for or 2 k 7 k 49 22 M1 for and 14 14 7 8 or 3 and 1 14 14 their 7  7 their 11  2 or and 2  7 7  2 or211 and 8 14 14 35 8 or and 14 14 8 or 72 and 14 14

This question in 0580/13 May/June 2025

11 The temperature at midnight is - 2°C . The temperature at noon is 5 °C. (a) Find the difference between these temperatures. … °C [1] (b) The temperature at 9 am is 8 °C higher than the temperature at midnight. Work out the temperature at 9 am. … °C [1]

2 marks

Mark scheme: 11(a) 7 1 11(b) 6 1

This question in 0580/11 Oct/Nov 2025

11 2 18 Work out - . 18 9 Give your answer as a fraction in its simplest form. … [2]

2 marks

Mark scheme: 18 7 2 11 4 cao M1 for – oe 18 18 18

This question in 0580/11 Oct/Nov 2025

9 The temperature at midday on Monday is –3 °C. The temperature at 10 pm on Monday is –15 °C. (a) Calculate the difference between these two temperatures. … °C [1] (b) The temperature at midday on Tuesday is 23 °C higher than the temperature at 10 pm on Monday. Calculate the temperature at midday on Tuesday. … °C [1]

2 marks

Mark scheme: 9(a) 12 1 9(b) 8 1

This question in 0580/12 Oct/Nov 2025