Cambridge IGCSE Mathematics 0580 — 2024 Oct/Nov Paper 1 · Variant 3
0580/13/O/N/24 · 24 questions · 56 marks · ≈63 min
The question paper and its mark scheme, free to read here and free to download. This is Cambridge’s own paper, exactly as it was sat.
Question paper12 pages












Mark scheme6 pages
Answers below. Sit the paper first if you are practising.






Questions as text
Q1 · Write 6475 correct to the nearest ten
1 Write 6475 correct to the nearest ten. ................................................. [1]
Mark scheme: Question Answer Marks Partial Marks 1 6480 1
Q2 · Write 0.75 as a fraction
2 Write 0.75 as a fraction. ................................................. [1]
Mark scheme: 2 75 1 or equivalent fraction 100
Q3 · A piece of string has length 65.1 cm
3 A piece of string has length 65.1 cm. The string is cut into 7 equal pieces. Find the length of each piece. .............................................cm [1]
Mark scheme: 3 9.3 1
Q4 · 7 19 8 12 3 12 9 7 12 Find the mode of these numbers
4 7 19 8 12 3 12 9 7 12 Find the mode of these numbers. ................................................. [1]
Mark scheme: 4 12 1
Q5 · A bag contains 6 red balls, 4 green balls and 2 blue balls
5 A bag contains 6 red balls, 4 green balls and 2 blue balls. Zia takes a ball from the bag at random. A B C D E F G 0 1 Write down the letter from the probability scale that shows the probability that (a) Zia takes a green ball ................................................. [1] (b) Zia takes a yellow ball ................................................. [1] (c) Zia does not take a blue ball. ................................................. [1]
Mark scheme: 5(a) C 1 5(b) A 1 5(c) F 1
Q6 · These are the first four terms of a sequence
6 These are the first four terms of a sequence. 19 26 33 40 (a) (i) Find the next term. ................................................. [1] (ii) Write down the term to term rule for this sequence. ................................................. [1] (b) These are the first four terms of another sequence. -1 2 5 8 Find the nth term of this sequence. ................................................. [2]
Mark scheme: 6(a)(i) 47 1 6(a)(ii) Add 7 oe 1 6(b) 3n – 4 2 B1 for 3n + j or kn – 4 k ≠ 0, or 3n – 4 seen then spoilt
Question 7
7 Simplify. 3p - t – p - 4t ................................................. [2]
Mark scheme: 7 2p – 5t final answer 2 B1 for 2p or −5t in final answer or for 2 p – 5t seen then spoilt
Q8 · 61 62 63 64 65 66 67 68 69 From the list of numbers, write down (a) a cube number…
8 61 62 63 64 65 66 67 68 69 From the list of numbers, write down (a) a cube number ................................................. [1] (b) a prime number. ................................................. [1]
Mark scheme: 8(a) 64 1 8(b) 61 or 67 1
Q9 · The scale drawing shows the positions of town K and town L
9 The scale drawing shows the positions of town K and town L. The scale is 1 cm represents 10 km. North L North K Scale : 1 cm to 10 km (a) Find the actual distance between town K and town L. ........................................... km [2] (b) Measure the bearing of town L from town K. ................................................. [1] (c) Town M is 40 km from town L on a bearing of 140°. On the scale drawing, mark the position of town M. [2]
Mark scheme: 9(a) 85 2 B1 for 8.5 or M1 for their 8.5 × 10 9(b) 065 1 9(c) M in correct position 2 B1 for a correct length, 4cm or B1 for a correct bearing, 140º
Q10 · The surface area of a cube is 121.5 cm 2
10 The surface area of a cube is 121.5 cm 2. Calculate the length of one side of the cube. ............................................ cm [2]
Mark scheme: 10 4.5 2 M1 for 121.5 ÷ 6
Q11 · NOT TO SCALE 80° w° The diagram shows three lines meeting at a point
11 (a) NOT TO SCALE 80° w° The diagram shows three lines meeting at a point. Find the value of w. w = ................................................ [1] (b) D 80° NOT TO SCALE y° A B C BCD is an isosceles triangle. ABC is a straight line. Work out the value of y. y = ................................................ [3]
Mark scheme: 11(a) 190 1 11(b) 130 3 B2 for DBC or BCD = 50 or M2 for 180 – ((180 – 80) ÷ 2) oe or M1 for (180 – 80) ÷ 2
Q12 · Write down the equation of a line parallel to the line y = 2x
12 Write down the equation of a line parallel to the line y = 2x . ................................................. [1]
Mark scheme: 12 y = 2x + k, k ≠ 0 oe 1
Q13 · Each student in a class of 20 students records the number of coins in their pockets
13 Each student in a class of 20 students records the number of coins in their pockets. The table shows the results. Number of coins 0 1 2 3 4 5 6 Frequency 3 1 7 8 0 0 1 (a) Find the median. ................................................. [1] (b) Calculate the mean. ................................................. [3]
Mark scheme: 13(a) 2 1 13(b) 2.25 3 M1 for [3×0] + 1×1 + 7×2 + 8×3 + [0×4] + [0×5] + 1×6 oe or for 45 their fx M1 dep for dep on first M1 20
Q14 · Expand 4 ( x - 3)
14 Expand 4 ( x - 3) . ................................................. [1]
Mark scheme: 14 4x – 12 final answer 1
Q15 · Find the size of an interior angle of a regular 15-sided polygon
15 Find the size of an interior angle of a regular 15-sided polygon. ................................................. [2]
Mark scheme: 15 156 2 180 (15 – 2 ) M1 for 180 – 360 ÷ 15 oe or oe 15
Q16 · Rio buys some pens
16 Rio buys some pens. 7 He sells 63 pens, which is of the pens he buys. 9 Work out how many pens he buys. ................................................. [2]
Mark scheme: 16 81 2 M1 for 63 ÷ 7 [×9]
Q17 · Ed has n books
17 Ed has n books. Sam has 3 times as many books as Ed Jane has 2 books fewer than Sam. The total number of books is 54. Use this information to write down an equation and solve it to find the value of n. n = ................................................ [4]
Mark scheme: 17 7n = 56 M3 OR M2 for n + 3n + 3n – 2 = 54 or any correct equation which would lead to 7n – 2 = 54 OR M1 for rearranging their equation to give an = b OR B1 for 3n or 3n – 2 8 A1 Dep on at least M2 If 0 scored SC1 for answer 8 without algebra
Q18 · 11 18 Without using a calculator, work out 2 - 1
1 11 18 Without using a calculator, work out 2 - 1 . 4 12 You must show all your working and give your answer as a fraction in its simplest form. ................................................. [3]
Mark scheme: 18 B1 Correct step for dealing with mixed numbers 9 23 1 11 oe or − 9 k 23k 4 12 14 12 Allow or 4 k 12 k oe M1 Correct method to find common denominator 27 23 11 and 31 and 3 11 12 12 12 12 e.g. 2 and 1 12 12 1 A1 cao 3
Q19 · % = {workers in an office} C = {workers who drink coffee} T = {workers who drink tea} 47…
19 % = {workers in an office} C = {workers who drink coffee} T = {workers who drink tea} 47 people work in the office. 32 people drink tea. % C T 6 8 (a) Complete the Venn diagram. [2] (b) Write down n( C + T ) . ................................................. [1] (c) Work out the probability that a worker chosen at random does not drink coffee. ................................................. [1]
Mark scheme: 19(a) 2 B1 for each or C T If 0 scored SC1 for n(c) = 33 7 26 19(b) 26 1 FT their diagram 19(c) 14 1 oe 47
Q20 · The weight, w grams, of a box is 463.9 grams, correct to 1 decimal place
20 The weight, w grams, of a box is 463.9 grams, correct to 1 decimal place. Complete the statement about the value of w. ............................ G w 1 ............................ [2]
Mark scheme: 20 463.85 463.95 2 B1 for each If 0 scored SC1 for both correct but reversed
Q21 · Calculate ( 6 .4 # 10 5 ) ' ( 2.5 # 10 -7 )
21 Calculate ( 6 .4 # 10 5 ) ' ( 2.5 # 10 -7 ) . Give your answer in standard form. ................................................. [1]
Mark scheme: 21 2.56 × 1012 1
Q22 · Mia invests $1270 for 5 years at a rate of 2.1% per year compound interest
22 Mia invests $1270 for 5 years at a rate of 2.1% per year compound interest. Calculate the value of her investment at the end of the 5 years. $ ................................................ [2]
Mark scheme: 22 1409.07 or 1409.069… 1410, 1409, 2 5 2.1 1409.1 M1 for 1270 1 + oe 100
Q23 · NOT TO SCALE 9.7 cm x cm 42° The diagram shows a right-angled triangle
23 NOT TO SCALE 9.7 cm x cm 42° The diagram shows a right-angled triangle. Calculate the value of x. x = ................................................ [2]
Mark scheme: 23 6.49 or 6.490 to 6.491 2 x M1 for sin 42 = or better 9.7
Q24 · A x cm NOT TO B SCALE 3.2 cm 6.75 cm 2.7 cm Shape A is mathematically similar to shape B
24 A x cm NOT TO B SCALE 3.2 cm 6.75 cm 2.7 cm Shape A is mathematically similar to shape B. Calculate the value of x. x = ................................................ [2]
Mark scheme: 24 8 2 3.2 2.7 M1 for = oe or better x 6.75
What was in this paper
The subtopics covered by these 24 questions, and how many questions each got. Open one in a new tab to see every Cambridge question on it.
2Angles2Averages and range2Limits of accuracy2Area and perimeter1Equations1Equations of linear graphs1Fractions, decimals and percentages1Introduction to probability1Percentages1Powers and roots1Rates1Ratio and proportion1Right-angled triangles1Scale drawings1Sequences1Sets1Similarity1Standard form1The four operations1What you needed in this session
Cambridge’s own grade thresholds for 2024 Oct/Nov, Paper 1 · Variant 3. A higher threshold means an easier paper — the bar moves with how the cohort did.