Cambridge IGCSE Mathematics 0580 — 2007 Oct/Nov Paper 1 · Variant 1

0580/11/O/N/07 · 18 questions · 56 marks · ≈63 min

The question paper and its mark scheme, free to read here and free to download. This is Cambridge’s own paper, exactly as it was sat.

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Question paper25 pages

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Mark scheme7 pages

Answers below. Sit the paper first if you are practising.

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Questions as text

Q1 · On a winter’s day in Vienna the maximum temperature was –2°C

1 On a winter’s day in Vienna the maximum temperature was –2°C. For The minimum temperature was 11°C lower than this. Examiner's Write down the minimum temperature. Use Answer °C [1]

Mark scheme: Question Answers Mark Notes 1 −13 1 Not 13–

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Q2 · Chris and Roberto share $35 in the ratio 5:2

2 Chris and Roberto share $35 in the ratio 5:2. Calculate how much Roberto receives. Answer $ [2]

Mark scheme: 2 ($) 10 2 M1 for 35 ÷ (5 + 2) or better. SC1 for ($) 25 only or 25:10 or 25 and 10 in the answer space.

More questions on Ratio and proportion

Q3 · Solve the equation 1 – 2x = x + 4

3 Solve the equation 1 – 2x = x + 4. Answer x = [2]

Mark scheme: 3 (x = ) − 1 2 M1 for 1 − 4 = x + 2x oe Not embedded unless x = –1 seen.

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Q4 · In 2005, a toy cost 52.50 reals in Brazil

4 In 2005, a toy cost 52.50 reals in Brazil. In Argentina, 1 peso = 0.875 reals. Work out the cost of the toy in pesos. Answer pesos [2]

Mark scheme: 4 60 2 M1 for 52.50 ÷ 0.875. SC1 for answers 59.659 rot or 60.3448 rot (from rounding 0.875 to 0.88 or 0.87.)

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Q5 · Factorise completely 4xy – 2x

5 Factorise completely 4xy – 2x. For Examiner's Use Answer [2]

Mark scheme: 5 2x(2y − 1) final answer 2 SC1 for x(4y − 2) or 2(2xy − x) or 2x(2y +1) Or SC1 for 2x(2y – 1) not as final answer.

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Q6 · NOT TO SCALE 25 m pº 30 m The height of a tree is 25 metres

6 NOT TO SCALE 25 m pº 30 m The height of a tree is 25 metres. The shadow of the tree has a length of 30 metres. Calculate the size of the angle marked p° in the diagram. Answer p = [2]

Mark scheme: 6 art39.8 2 M1 for tan p = 2530 oe

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Q7 · The distance, d kilometres, between Windhoek and Cape Town is 1300 km, correct to the…

7 The distance, d kilometres, between Windhoek and Cape Town is 1300 km, correct to the nearest 100 kilometres. Complete the statement about the value of d. Answer d < [2]

Mark scheme: 7 1250 (≤ d <) 1350 2 1 mark for each in correct order 13

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Q8 · For Examiner's Use Draw all the lines of symmetry on the shape above

8 (a) For Examiner's Use Draw all the lines of symmetry on the shape above. [1] (b) A quadrilateral has rotational symmetry of order 2 and no lines of symmetry. Write down the geometrical name of this shape. Answer(b) [1]

Mark scheme: 8 1 Lines must be a minimum of length and height (a) Two correct lines of of the figure. symmetry, No extra lines (b) Parallelogram 1

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Question 9

5 ... 9 (a) Write in the missing number. = 6 18 [1] (b) Without using your calculator and writing down all your working, show that 2 5 7 1 − = . 9 6 18 Answer(b) [2]

Mark scheme: 9 (a) 15 1 (b) 119 oe B1 Eg 5466 Allow 99 + 29 or better 18 22 − 1518 = 187 oe E1 Must be finally reduced to 187

More questions on Fractions, decimals and percentages

Q10 · Each interior angle of a regular polygon is 150°

10 Each interior angle of a regular polygon is 150°. For (a) Work out the size of each exterior angle. Examiner's Use Answer(a) [1] (b) Work out the number of sides of this polygon. Answer(b) [2]

Mark scheme: 10 (a) 30 1 (b) 12 2ft M1 for 360 ÷ either 30 or their (a) ft. answer only when calculation gives an integer > 2

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Q11 · North NOT TO SCALE 140º A 50 km B A ship travels 50 kilometres from A to B on a bearing…

11 North NOT TO SCALE 140º A 50 km B A ship travels 50 kilometres from A to B on a bearing of 140°, as shown in the diagram. Calculate how far south B is from A. Answer km [3]

Mark scheme: 11 art38.3 3 M1 for 50d = cos (180 – 140) oe soi M1dep. for ( d =) 50 cos (180 – 140) oe SC1 for 32.1 (distance east) 11

More questions on Right-angled triangles

Q12 · For y Examiner's Use NOT TO 3 SCALE l x 0 1 A straight line, l, crosses the x-axis at (1…

12 For y Examiner's Use NOT TO 3 SCALE l x 0 1 A straight line, l, crosses the x-axis at (1, 0) and the y-axis at (0, 3). (a) Find the gradient of the line l. Answer(a) [1] (b) Write down the equation of the line l, in the form y = mx + c. Answer(b) y = [2]

Mark scheme: 12 (a) −3 1 B1 for their (a)x or +3 as intercept seen (b) (y =) −3x + 3 2ft in the equation. Not y = 3 Final answer

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Q13 · A school has 240 students

13 A school has 240 students. (a) There are 131 girls. What percentage of the students are girls? Answer(a) [2] (b) One day 6.25% of the 240 students are absent. Work out the number of students who are absent. Answer(b) [2]

Mark scheme: 13 (a) 55 or art 54.6 2 M1 for 131 ÷ 240(× 100) implied by 54.5 (b) 15 2 M1 for 6.25 ÷ 100 × 240 SC1 for answer 225

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Q14 · Calculate the circumference of a circle of diameter 8 cm

14 (a) Calculate the circumference of a circle of diameter 8 cm. For Examiner's Use Answer(a) cm [2] (b) Q NOT TO SCALE 29º A B AQB is a semi-circle. Angle QAB = 29°. Work out the size of angle ABQ. Answer(b) Angle ABQ = [2]

Mark scheme: 14 (a) art 25.1 www 2 M1 for π × 8 or 2π × 8 ÷ 2 implied by answer of 25 (b) 61 (Can be on 2 M1 for 90 – 29 or 180 – 90 – 29 diagram) SC1 for angle Q = 90° soi

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Q15 · Simplify (a) a0, Answer(a) [1] 2 (b) ( 3x ) Answer(b) [1] -2  3  (c)  

15 Simplify (a) a0, Answer(a) [1] 2 (b) ( 3x ) Answer(b) [1] -2  3  (c)   .   x  Answer(c) [2]

Mark scheme: 15 (a) 1 1 (b) x 6 1 1 3 or better. E.g. ( x3) 2 )2 (c) x92 2 M1 for ( x B1 if answer contains x 2 as numerator or 3 2(or 9) as denominator. 15

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Q16 · Write 17 598 correct to 2 significant figures

16 (a) (i) Write 17 598 correct to 2 significant figures. For Examiner's Use Answer(a)(i) [1] (ii) Write your answer to part (a)(i) in standard form. Answer(a)(ii) [1] (b) Write 5.649 × 10-2 as a decimal, correct to 3 decimal places. Answer(b) [2]

Mark scheme: 16 (a)(i) 18 000 1 (ii) 1.8 × 10 4 1 ft 1.7598 × 10 4 gets 0 (b) 0.056 2 B1 for 0.06 or 0.0565 or 0.05649 or 0.057 seen SC1 for final answer 0.0560(0)

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Q17 · Alex invests $200 for 2 years at 4.05% per year simple interest

17 (a) Alex invests $200 for 2 years at 4.05% per year simple interest. Calculate how much interest Alex receives. Answer(a) $ [2] (b) Bobbie invests $200 for 2 years at 4% per year compound interest. Calculate how much interest Bobbie receives. Give your answer to 2 decimal places. Answer(b) $ [2]

Mark scheme: 17 (a) ($) 16.2(0) 2 M1 for (200 × 4.05 × 2)/100 SC1 for 216.2(0) (b) ($) 16.3(2) or 16.3(0) 2 M1 for 200(1.04) 2 − 200oe SC1 for 216.3(2). SC1 for both 8.(00) and 8.3(2) seen

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Q18 · For y Examiner's Use 5 4 3 2 1 x –4 –3 –2 –1 0 1 2 3 4 5 6 K –1 –2 –3 –4 –5 − 3  (a) KL…

18 For y Examiner's Use 5 4 3 2 1 x –4 –3 –2 –1 0 1 2 3 4 5 6 K –1 –2 –3 –4 –5 − 3  (a) KL =   . The point K is marked on the diagram.  3  (i) Draw KL on the diagram. [1] (ii) Write down the co-ordinates of the point L. Answer(a)(ii) ( , ) [1] (b) P is the point (−3, −3).  2  PR=   and PS = 2PR.   1  Find the co-ordinates of S. Answer(b) ( , ) [2] Question 19 is printed on the next page.

Mark scheme: 18 (a)(i) Vector KL drawn 1 If arrow shown, it must be correct. Only ft their point if labelled L. (ii) (0,2) 1 ft M1 for vector PS drawn or for (b) (1, −1) 2  4  (PS =)    2  SC1 Point S on diagram at (1, –1) 12

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What was in this paper

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What you needed in this session

Cambridge’s own grade thresholds for 2007 Oct/Nov, Paper 1 · Variant 1. A higher threshold means an easier paper — the bar moves with how the cohort did.

C33/56
E19/56
F13/56