E2.6· 48 questions · 158 marks · 190 min · 2004–2025· Structured questions
Every Cambridge IGCSE Mathematics Paper 2 question on inequalities, laid out as 26 A4 pages with the mark scheme below. Nothing is left out. Free to read, no account.
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2 / 26![Question 3: Solve the inequality 6(2 − 3x) − 4(1 − 2x)=Y= 0. For Examiner's Use Answer [3]](https://img.pastlit.com/crops/f6785ed3-b7c6-4414-86f7-95afd0c180cf/q13.webp)

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6 / 26![Question 9: x is a positive integer and 15x – 43 < 5x + 2 . Work out the possible values of x. Answer [3]](https://img.pastlit.com/crops/2ea1cdd1-0ac1-4d2a-9eb1-3863763961b9/q6.webp)
![Question 10: Solve the inequality. For 3y + 7 Y 2 – y Examiner's Use Answer [2]](https://img.pastlit.com/crops/7d2ecca1-d244-4252-a128-f49d8668c0e9/q4.webp)
7 / 26![Question 12: Solve the inequality. For Examiner′s 3x – 1 Ğ 11x + 2 Use Answer ............................................... [2] ______________________…](https://img.pastlit.com/crops/567ded07-0b3f-4c8c-875b-2d005c37e2c5/q8.webp)
![Question 13: Solve 6x + 3 < x < 3x + 9 for integer values of x. Answer ............................................... [4] _____________________________…](https://img.pastlit.com/crops/d2824a80-da1c-4c55-bc27-755625d3dfa3/q18.webp)
8 / 26![Question 15: Solve the inequality for positive integer values of x. 21 + x > x + 1 5 Answer ................................................ [4] _______…](https://img.pastlit.com/crops/38b224a5-3de2-4949-9b52-2cd23c89fbcf/q15.webp)
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11 / 26![Question 21: Find the positive integers that satisfy the inequality t + 2 2 3 t - 6 . ................................................. [3]](https://img.pastlit.com/crops/e18cd8ca-3982-4ed1-875e-59ee460b0e12/q7.webp)
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![Question 24: Solve the inequality. 3n - 11 2 5n - 18 ................................................. [2]](https://img.pastlit.com/crops/cae494a3-a333-4a4a-8193-3f050cf63cf3/q13.webp)
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14 / 26![Question 27: Find the integers which satisfy the inequality. - 5 1 2n - 1 G 5 .............................................. [3]](https://img.pastlit.com/crops/f58fe106-fb06-4f53-b748-06e94598dfe7/q14.webp)
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![Question 31: Find the integer values of n that satisfy the inequality 15 G 4n 1 28 . ................................................. [3]](https://img.pastlit.com/crops/af298087-6708-4727-a500-b922ddfec1c6/q12.webp)
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22 / 26![Question 40: Solve. 6 - x 4 - 3 x H 5 ................................................. [3]](https://img.pastlit.com/crops/e49dc108-f780-445f-ad72-25e3b02f56aa/q13.webp)
![Question 41: n – 2 – 1 0 1 Write down the inequality, in terms of n, shown by the number line. ................................................. [1]](https://img.pastlit.com/crops/5b6344f7-8440-4f61-84d7-5041ff1ffd9c/q7.webp)
23 / 26![Question 43: Solve. 30 (a) = 6 x x = ................................................ [1] (b) 11x - 3 H 2 ( 2x + 9) ....................................…](https://img.pastlit.com/crops/e5b18bd6-5bd4-4f34-81df-5233dc85aa27/q8.webp)
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26 / 26Answers below. Sit the paper first if you are practising.
Pastlit
Mathematics 0580 · Inequalities — Paper 2
IGCSE · topical answer key — answer key (teacher use)
Question
Answer
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2| Question | Answer | Marks | From |
|---|---|---|---|
| 1 | see sheet | 2 | 0580/21 Oct/Nov 2004 |
| 2 | see sheet | 5 | 0580/21 May/June 2009 |
| 3 | see sheet | 3 | 0580/21 Oct/Nov 2009 |
| 4 | see sheet | 4 | 0580/22 May/June 2010 |
| 5 | see sheet | 3 | 0580/21 Oct/Nov 2010 |
| 6 | see sheet | 5 | 0580/22 Oct/Nov 2010 |
| 7 | see sheet | 5 | 0580/23 Oct/Nov 2010 |
| 8 | see sheet | 4 | 0580/22 Oct/Nov 2011 |
| 9 | see sheet | 3 | 0580/22 May/June 2012 |
| 10 | see sheet | 2 | 0580/23 May/June 2012 |
| 11 | see sheet | 3 | 0580/21 Oct/Nov 2012 |
| 12 | see sheet | 2 | 0580/21 May/June 2013 |
| 13 | see sheet | 4 | 0580/22 May/June 2013 |
| 14 | see sheet | 4 | 0580/22 Oct/Nov 2013 |
| 15 | see sheet | 4 | 0580/21 May/June 2014 |
| 16 | see sheet | 2 | 0580/22 Feb/March 2016 |
| 17 | see sheet | 5 | 0580/22 Feb/March 2016 |
| 18 | see sheet | 2 | 0580/21 May/June 2016 |
| 19 | see sheet | 4 | 0580/23 May/June 2016 |
| 20 | see sheet | 4 | 0580/21 Oct/Nov 2016 |
| 21 | see sheet | 3 | 0580/22 Oct/Nov 2016 |
| 22 | see sheet | 5 | 0580/23 Oct/Nov 2016 |
| 23 | see sheet | 3 | 0580/21 May/June 2017 |
| 24 | see sheet | 2 | 0580/22 May/June 2017 |
| 25 | see sheet | 3 | 0580/23 May/June 2017 |
| 26 | see sheet | 7 | 0580/21 Oct/Nov 2017 |
| 27 | see sheet | 3 | 0580/22 Oct/Nov 2017 |
| 28 | see sheet | 2 | 0580/21 May/June 2018 |
| 29 | see sheet | 4 | 0580/21 May/June 2018 |
| 30 | see sheet | 3 | 0580/22 May/June 2018 |
| 31 | see sheet | 3 | 0580/21 Oct/Nov 2018 |
| 32 | see sheet | 2 | 0580/22 Oct/Nov 2018 |
| 33 | see sheet | 3 | 0580/22 Oct/Nov 2018 |
| 34 | see sheet | 3 | 0580/22 May/June 2019 |
| 35 | see sheet | 2 | 0580/22 Oct/Nov 2019 |
| 36 | see sheet | 4 | 0580/22 Oct/Nov 2019 |
| 37 | see sheet | 4 | 0580/23 Oct/Nov 2019 |
| 38 | see sheet | 4 | 0580/23 May/June 2020 |
| 39 | see sheet | 2 | 0580/23 May/June 2021 |
| 40 | see sheet | 3 | 0580/21 Oct/Nov 2021 |
| 41 | see sheet | 1 | 0580/22 Feb/March 2022 |
| 42 | see sheet | 2 | 0580/23 May/June 2022 |
| 43 | see sheet | 4 | 0580/22 May/June 2023 |
| 44 | see sheet | 4 | 0580/21 May/June 2024 |
| 45 | see sheet | 4 | 0580/22 Oct/Nov 2024 |
| 46 | see sheet | 2 | 0580/22 Feb/March 2025 |
| 47 | see sheet | 4 | 0580/21 Oct/Nov 2025 |
| 48 | see sheet | 2 | 0580/22 Oct/Nov 2025 |
4 Solve the inequality 5 −x3 < 17 . Answer [2]
2 marks
Mark scheme: 4 x > -4 or -4 < x 2* M1 -4 seen on answer line or M1 correct movement of 2 terms
20 For Examiner's y Use 6 5 4 3 2 1 0 x 1 2 3 4 5 6 –1 –2 –3 –4 –5 (a) Draw the three lines y = 4, 2x – y = 4 and x + y = 6 on the grid above. [4] (b) Write the letter R in the region defined by the three inequalities below. y Y 4 2x – y [ 4 x + y [ 6 [1]
5 marks
Mark scheme: 20 draw 2x – y = 4 2 W1 Line through (2,0) or (0,–4) draw x + y = 6 1 draw y = 4 1 R correct region identified by R 1 0 6
13 Solve the inequality 6(2 − 3x) − 4(1 − 2x)=Y= 0. For Examiner's Use Answer [3]
3 marks
Mark scheme: 13 x [ 0.8 or x [ 4 cao 3 B1 12 – 18x B1 –4 + 8x these terms may be 5 reversed if moved to the other side of the inequality allow >=
14 y 10 8 6 4 2 x –4 –2 0 2 4 6 8 10 12 14 16 18 By shading the unwanted regions of the grid above, find and label the region R which satisfies the following four inequalities. y [ 2 x + y [ 6 y Y x + 4 x + 2y Y 18 [4]
4 marks
Mark scheme: 14 4 Mark the position of the letter R (or the worst unshaded region if R is missing) as follows IGCSE – May/June 2010 0580 22
x − 1 For 13 Solve the inequality. 2x + 5 I Examiner's 4 Use Answer [3]
3 marks
Mark scheme: 13 x < –3 3 M1 correct move M1 correct move M1 correct move
20 For y Examiner's Use 8 7 6 5 4 3 2 1 x 0 1 2 3 4 5 6 7 8 (a) Draw the lines y = 2, x + y = 6 and y = 2x on the grid above. [4] (b) Label the region R which satisfies the three inequalities x + y [ 6, y [ 2 and y Y 2x. [1]
5 marks
Mark scheme: 20 (a) 4 B1 y = 2 single line thro B1 (6, 0) and B1 (0,6) R B1 y = 2x (b) 1 Correct R cao IGCSE – October/November 2010 0580 22
22 For y Examiner's Use 9 8 7 6 5 4 3 2 1 x 0 –6 –5 –4 –3 –2 –1 1 2 3 4 –1 Find the three inequalities which define the shaded triangle in the diagram. Answer [5]
5 marks
Mark scheme: 22 y [ 1, x Y 3, y Y x + 5 oe 5 B1 y R 1 B1 x R 3 B2 y R x + 5 or B1 y R – x + 5 where R is any inequality B1 all 3 inequalities correct
14 For y Examiner's Use 7 6 5 R 4 3 2 1 x 0 1 2 3 4 5 6 7 The region R is bounded by three lines. Write down the three inequalities which define the region R. Answer [4]
4 marks
Mark scheme: 14 y ≤ 5 4 B1 each inequality but accept any of the four x ≥ 2 inequality symbols y ≥ x Final B1 all 3 symbols correct
6 x is a positive integer and 15x – 43 < 5x + 2 . Work out the possible values of x. Answer [3]
3 marks
Mark scheme: 6 1, 2, 3, 4 3 M1 10x < 45 A1 x < 4.5
4 Solve the inequality. For 3y + 7 Y 2 – y Examiner's Use Answer [2]
2 marks
Mark scheme: 4 y ø –1.25 2 M1 inequality with y’s and constants correctly collected
9 Solve the inequality. 2 x − 3 x − Y=2 5 3 Answer [3]
3 marks
Mark scheme: 9 x Y 39 www 3 M1 correct first move M1 correct 2nd move M1 correct move to answer line
8 Solve the inequality. For Examiner′s 3x – 1 Ğ 11x + 2 Use Answer … [2] _____________________________________________________________________________________
2 marks
Mark scheme: 8 x ≥−3 oe 2 M1 for –3 ≤ 8x oe 8 If 0 then SC1 for −3 with incorrect inequality. 8
18 Solve 6x + 3 < x < 3x + 9 for integer values of x. Answer … [4] _____________________________________________________________________________________
4 marks
Mark scheme: 18 −1 −2 −3 −4 4 B3 for x < − 3 5 and x > −5.4 oe or B2 for x < − 3 5 or x > −5.4 oe or B1 for 5x < − 3 or − 9 < 2x oe Or mark on answer line −1 oe
16 Solve the inequality. x x - 2 + < 5 2 3 Answer … [4] _____________________________________________________________________________________
4 marks
Mark scheme: 16 x <6.8 4 B3 for 6.8 with wrong inequality or equal as answer. Or M1 for first move completed correctly and M1 for second move completed correctly and M1 for third move completed correctly 11 5
15 Solve the inequality for positive integer values of x. 21 + x > x + 1 5 Answer … [4] __________________________________________________________________________________________ 1
4 marks
Mark scheme: 15 [0], 1, 2, 3 4 M1 for moving the 5 correctly M1 for collecting their terms A1 for a correct inequality for x eg [0 ≤ ] x < 4 12
4 Solve the inequality. 6n + 3 8n … [2]
2 marks
Mark scheme: 4 n < 1.5 oe final answer 2 B1 for 1.5 oe in answer or M1 for 3 > 8n − 6n oe 5 2 12 4
19 y 4 3 2 1 x –3 –2 –1 0 1 2 3 4 –1 Find the four inequalities that define the region that is not shaded. … … … … [5]
5 marks
Mark scheme: 19 y < 2 oe and x ⩾ –2 oe 2 B1 for either correct 1 1 y ⩾ x + 1 oe and y ⩽ – x + 3 oe 3 B2 for either y ⩾ x + 1 oe or y ⩽ – x + 3 oe 2 2 1 or SC2 for y = x + 1 oe and y = – x + 3 oe 2 1 or SC1 for y = x + 1 oe or y = – x + 3 oe 2 1 or SC4 for y ⩽ 2 oe , x > –2 oe, y > x + 1 oe 2 and y < – x + 3 oe
13 Solve the inequality. n + 7 1 5n – 8 … [2]
2 marks
Mark scheme: 13 n > 3.75 2 M1 for 7 + 8 < 5n – n oe
20 y 5 4 R 3 2 1 x 0 1 2 3 4 5 Find four inequalities that define the region, R, on the grid. … … … … [4]
4 marks
Mark scheme: 20 y < 4 4 B1 for each correct answer to a maximum of y ⩾ 3 3 marks. x ⩾ 2 First two may be combined as a single inequality y > x e.g. 3 ⩽ y < 4 for B2 After 0 scored SC1 for use of = signs or incorrect inequality signs in all four equations 9 6 + 4 8
21 y 4 NOT TO SCALE R x 0 1 4 Write down the three inequalities that define the unshaded region, R. … … … [4]
4 marks
Mark scheme: 21 y ⩾ 0 and x ⩾ 1 oe 4 SC3 for y > 0, x > 1 and x + y < 4 oe and or x + y ⩽4 oe B1 for y ⩾ 0 B1 for x ⩾ 1 oe and B2 for x + y ⩽ 4 oe or M1 for grad = –1 soi If B0 scored for first two B marks, SC1 for y = 0 and x = 1 or with incorrect inequality sign
7 Find the positive integers that satisfy the inequality t + 2 2 3 t - 6 . … [3]
3 marks
Mark scheme: 7 1, 2, 3 3 B2 for t < 4 or M1 for 2 + 6 > 3t – t oe or better If zero scored, SC1 for answer 0, 1, 2, 3 or 1, 2, 3, 4
24 y 7 6 5 4 R 3 2 1 0 x 0 1 2 3 4 5 6 7 8 9 10 11 Find the three inequalities that define the unshaded region, R. … … … [5]
5 marks
Mark scheme: 3 3 24 y ⩽ − x + 6 oe 5 SC4 for y < − x + 6, x > 2, y ⩾ x oe 5 5 x ⩾ 2 oe or y > x oe 3 B3 for y ⩽ − x + 6 oe 5 final answers 3 or B2 for y = − x + 6 oe 5 3 or B1 for gradient = – oe soi 5 and B2 for x ⩾ 2 and y > x oe or B1 for either x ⩾ 2 or y > x oe or for x = 2 and y = x with incorrect inequalities
10 y 5 4 3 2 1 x 0 1 2 3 4 5 6 –1 By shading the unwanted regions of the grid, find and label the region R that satisfies the following four inequalities. y G 2 y H 1 y G 2x - 1 y G 5 - x [3]
3 marks
Mark scheme: 10 Correct regionn identified 3 0 1 1 2 2 3 2 1 2 1 RR SC1 foor
13 Solve the inequality. 3n - 11 2 5n - 18 … [2]
2 marks
Mark scheme: 13 n < 3.5 oe final answer 2 M1 for 18 – 11 > 5n – 3n oe
16 (a) Solve the inequality. x + 13 H 3x + 7 … [2] (b) List the positive integers that satisfy the inequality in part (a). … [1]
3 marks
Mark scheme: 16(a) x ⩽ 3 final answer 2 M1 for 13 − 7 ⩾ 3x − x oe 16(b) 1, 2, 3 1FT correct answer or FT their answer to (a)
23 In one week, Neha spends x hours cooking and y hours cleaning. The time she spends cleaning is at least equal to the time she spends cooking. This can be written as y H x. She spends no more than 16 hours in total cooking and cleaning. She spends at least 4 hours cooking. (a) Write down two more inequalities in x and/or y to show this information. … … [2] (b) Complete the diagram to show the three inequalities. Shade the unwanted regions. y y = x 18 16 14 12 Hours 10 cleaning 8 6 4 2 x 0 2 4 6 8 10 12 14 16 18 Hours cooking [3] (c) Neha receives $10 for each hour she spends cooking and $8 for each hour she spends cleaning. Work out the largest amount she could receive. $ … [2]
7 marks
Mark scheme: 23(a) x + y ⩽ 16 oe 2 B1 for each mark final answers x ⩾ 4 oe If zero scored, SC1 for x + y < 16 and x > 4 23(b) Correct shading 3 M2 for lines at x = 4 and x + y = 16 or for correct shading of x < 4 or x + y > 16 or M1 for line at x = 4 or their x = 4 or for line at x + y = 16 or their x + y = 16 23(c) 144 2 M1 for (8, 8) selected or for 10 × x + 8 × y for any numerical point which is inside or on the boundary of their unshaded region
14 Find the integers which satisfy the inequality. - 5 1 2n - 1 G 5 … [3]
3 marks
Mark scheme: 14 –1, 0, 1, 2, 3 3 B2 for −<2 n - 3 or list with one error or omission or M1 for –5 + 1 < 2n or 2n ⩽ 5 + 1 or a list with 3 correct and no more than 1 incorrect or if zero scored, SC1 for 5, 3, 1, –1, –3
12 Solve the inequality. 3n - 5 2 17 + 8n … [2]
2 marks
Mark scheme: 12 2 2 M1 for 8n − 3n < −−5 17 or better n < − 4.4 or n < − 4 5 or 3n – 8n > 17 + 5 or better final answer
21 y 3 2 R 1 x 0 1 2 3 4 5 6 There are four inequalities that define the region R. One of these is y G x + 1. Find the other three inequalities. … … … [4]
4 marks
Mark scheme: 21 y ⩾ 1.5 oe 4 3 SC3 for y >1.5 oe and y > x oe and 4 y ⩾3 x oe 4 1 y ⩽ − x + 3 oe 1 2 y < − x + 3 oe 2 or B3 for any two correct inequalities or B1 for y ⩾ 1.5 oe and 3 1 B2 for y ⩾ x oe or y < − x + 3 oe 4 2 3 1 or y = x oe and y = − x + 3 oe or 4 2 with incorrect inequality signs 3 or B1 for y = x oe OR 4 1 y = − x + 3 oe or with incorrect 2 inequality signs
19 y 6 5 4 3 2 1 x 0 –2 –1 1 2 3 4 5 6 –1 –2 Find the two inequalities that define the region on the grid that is not shaded. … … [3]
3 marks
Mark scheme: 19 y > 2 oe final answer 3 B1 for y > 2 oe final answer y ⩾ 3 – x oe final answer B2 for y ⩾ 3 – x oe final answer or B1 for y = 3 – x oe soi or SC2 for y ⩾ 2 oe and y > 3 – x oe final answer
12 Find the integer values of n that satisfy the inequality 15 G 4n 1 28 . … [3]
3 marks
Mark scheme: 12 4, 5, 6 3 B2 for 1 error or 1 omission or M2 for 3.75 ⩽ n < 7 oe or M1 for 3.75 ⩽ n or n < 7 or better
6 Solve. 7m - 2 H 19 … [2]
2 marks
Mark scheme: 6 m ⩾ 3 final answer 2 M1 for correct first step e.g. 7m ⩾ 19 + 2
14 y 8 7 6 5 4 3 2 1 0 1 2 3 4 x By shading the unwanted regions of the grid, find and label the region R that satisfies the following four inequalities. x G 3 x H 2 y G 2x + 1 y H 4 - x [3]
3 marks
Mark scheme: 14 Correct reggion identifieed 3 B marks or SC1 for 1 2 1 2 3 2 R 0 1 2 1
16 y 10 8 6 4 2 –4 –2 0 2 4 6 8 10 12 14 x –2 –4 –6 + 6 y H 3x - 4 x + y H 5 y G- 12 x (a) By shading the unwanted regions of the grid, find and label the region R that satisfies the three inequalities. [2] (b) Find the largest value of x + y in the region R, where x and y are integers. … [1]
3 marks
Mark scheme: 16(a) R identified correctly 2 B marks 0 1 1 2 0 1 1 1 0 0 1 1 1 0 0 16(b) 7 1
9 Solve the inequality. x - 13 2 12 + 3x 2 … [2]
2 marks
Mark scheme: 9 x < –10 final answer 2 x M1 for –12 –13 > 3x – oe 2
16 y 6 5 4 3 2x + y = 6 2 1 0 1 2 3 4 5 x By shading the unwanted regions of the grid, find and label the region R that satisfies the following inequalities. y G 5 2x + y H 6 y H x + 1 [4]
4 marks
Mark scheme: 16 y = 5 ruled 4 B2 for two correct lines y = x + 1 ruled or B1 for one correct line Correct region indicated B2 for indication of correct region or B1 for shading that satisfies two of the inequalities
17 y 7 6 5 4 3 2 1 – 5 – 4 – 3 – 2 – 1 0 1 2 3 4 5 x – 1 – 2 – 3 – 4 – 5 By shading the unwanted regions on the grid, draw and label the region R that satisfies the following inequalities. - 2 1 x G 3 y G x + 3 [4]
4 marks
Mark scheme: 17 4 B1 for x = –2 dashed ruled line and x = 3 solid ruled line B1 for y = x + 3 solid ruled line B2 for indication of correct region or B1 for shading that satisfies two of the inequalities, e.g. two of x > –2, x ⩽ 3 and y ⩽ x + 3
13 y 4 3 2 R 1 x 0 1 2 3 4 Write down the three inequalities that define the region R. … … … [4]
4 marks
Mark scheme: 13 x + y < 4 4 B3 for any two correct or B1 for y ⩾ 1.5 y ⩾ 1.5 B2 for x + y < 4 or y ⩽ 2x + 1 or x + y = 4 and y = 2x + 1 or with incorrect y ⩽ 2x + 1 inequality signs or B1 for x + y = 4 or y = 2x + 1 or SC3 for > instead of ⩾ etc.
12 x is an integer and - 3 G 2 x - 1 1 3 . Find the values of x. … [2]
2 marks
Mark scheme: 12 –1, 0, 1 final answer 2 B1 for –1 ⩽ x < 2 or two correct answers and no extras or three correct answers and one extra/wrong
13 Solve. 6 - x 4 - 3 x H 5 … [3]
3 marks
Mark scheme: 13 x 1 final answer 3 6 M1 for 20 – 15x ⩾ 6 – x or 4 − 3x −x 5 5 M1 for correctly isolating terms in x FT their first step of dealing with the 5 x 6 20 – 6 ⩾ – x + 15x or −3x + − 4 5 5
7 n – 2 – 1 0 1 Write down the inequality, in terms of n, shown by the number line. … [1]
1 marks
Mark scheme: 7 n > − 1 oe 1
15 Solve. 12x - 3 H 4x + 13 … [2]
2 marks
Mark scheme: 15 x ⩾ 2 final answer 2 M1 for 12x – 4x ≥ 13 + 3 oe
8 Solve. 30 (a) = 6 x x = … [1] (b) 11x - 3 H 2 ( 2x + 9) … [3]
4 marks
Mark scheme: 8(a) 5 1 8(b) x ⩾ 3 final answer 3 M1 for correct first step 11x – 3 ≥ 4x + 18 or 5.5x – 1.5 ⩾ 2x + 9 or better M1 for correctly collecting their x terms on one side and their number terms on the other side e.g. 11x – 4x ⩾ 18 + 3 or better
11 y 7 6 5 4 3 R 2 1 x – 1 0 1 2 3 4 5 6 7 – 1 Find the inequalities that define the unshaded region, R. … [4]
4 marks
Mark scheme: 11 y < x 4 B1 for y < x x < 6 B1 for x < 6 1 ⩽ y ⩽ 5 oe B2 for 1 ⩽ y ⩽ 5 or B1 for y ⩾ 1 or y ⩽ 5 If B0 scored, SC2 for y ⩽ x, x ⩽ 6 and 1 < y < 5 oe or SC1 for three correct from y = x, x = 6, y = 1 and y = 5
13 y 5 4 3 2 1 – 5 – 4 – 3 – 2 – 1 0 1 2 3 4 5 x – 1 – 2 – 3 – 4 – 5 The region R satisfies these inequalities. - 3 1 y G 2 y G x - 1 By drawing suitable straight lines and shading unwanted regions, find and label the region R. [4]
4 marks
Mark scheme: 13 4 B1 for y = 2 solid line B1 for y = x – 1 solid line B1 for y = –3 dashed line B1 for correct region identified satisfying the given inequalities R
7 x -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 Write down the inequality for x represented on the number line. … [2]
2 marks
Mark scheme: 7 –3 < x ⩽ 4 2 B1 for –3< x or x ⩽ 4
16 y 6 5 4 R 3 2 1 0 1 2 3 4 x Write down all the inequalities that define the region R. … … … … [4]
4 marks
Mark scheme: 16 x ⩽ 2.5 4 B3 for answer y > 3 x < 2.5 y ⩾ 3 y < 4 y < 2x y ⩽ 4 y ⩽ 2x OR B1 for each If 0 or 1 scored, instead award SC2 for recognition of x = 2.5, y = 3, y = 4, y = 2x If 0 scored, SC1 for recognition of y = 2x
7 Represent the inequality - 4 1 x G 3 on the number line. x – 6 – 5 – 4 – 3 – 2 – 1 0 1 2 3 4 5 6 [2]
2 marks
Mark scheme: 7 2 B1 for open circle at –4 and closed circle at 3 or for a line between –4 and 3 (any circles)