Cambridge IGCSE Mathematics 0580 — 2016 Oct/Nov Paper 2 · Variant 3

0580/23/O/N/16 · 25 questions · 70 marks · ≈79 min

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Mark scheme5 pages

Answers below. Sit the paper first if you are practising.

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Questions as text

Q1 · V = 4p2 Find V when p = 3

1 V = 4p2 Find V when p = 3. V = ................................................[1]

Mark scheme: Question Answer Mark Part marks 1 36 1

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Question 2

2 Simplify. n2 × n5 .................................................[1]

Mark scheme: 2 n7 final answer 1

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Q3 · 99° NOT TO SCALE 113° 82° 70° 67° 98° 110° 81° A B 96° 100° 83° 57° 80° 84° 123° 97° C D…

3 99° NOT TO SCALE 113° 82° 70° 67° 98° 110° 81° A B 96° 100° 83° 57° 80° 84° 123° 97° C D The diagram shows four quadrilaterals A, B, C and D. Which one of these could be a cyclic quadrilateral? .................................................[1]

Mark scheme: 3 B 1 6

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Q4 · Write in standard form

4 Write in standard form. (a) 2 470 000 ................................................. [1] (b) 0.0079 ................................................. [1]

Mark scheme: 4 (a) 2.47 × 106 1 (b) 7.9 × 10–3 1 18 5 18 k 5 k

More questions on Standard form

Q5 · 1 5 Without using a calculator, work out 5 + 6

3 1 5 Without using a calculator, work out 5 + 6 . Write down all the steps of your working and give your answer as a fraction in its simplest form. ................................................. [2]

Mark scheme: 18 5 18 k 5 k 5 and oe must be shown M1 and 30 30 30 k 30 k 23 cao A1 30

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Q6 · James is an animal doctor

6 James is an animal doctor. The table shows some information about the cats he saw in one week. Day Monday Tuesday Wednesday Thursday Friday Number of 2 4 1 3 2 cats seen Mean mass of 1.9 0.9 2.1 1.8 2 a cat (kg) One of the cats James saw had a mass of 4 kg. On which day did he see this cat? ................................................. [2]

Mark scheme: 6 Thursday 2 M1 for 5.4 found or at least two of: 3.8, 3.6 and 4 found 2 3

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Q7 · Write these in order of size, smallest first

7 Write these in order of size, smallest first. 0.63 0.22 .009 0.42 .......................... 1 ......................... 1 ......................... 1 .........................[2] smallest

Mark scheme: 7 0.42 0.63 0.22 0.09 2 M1 for decimal conversion 0.216 and 0.3 and 0.16

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Q8 · The length of a car is 4.2 m, correct to 1 decimal place

8 The length of a car is 4.2 m, correct to 1 decimal place. Write down the upper bound and the lower bound of the length of this car. Upper bound = .......................................... m Lower bound = .......................................... m [2]

Mark scheme: 8 4.25 2 B1 for each or both answers reversed 4.15

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Q9 · 30 28 26 24 22 D 20 C 18 Distance (km) 16 B 14 12 10 8 A 6 4 2 0 0 10 20 30 40 50 60 70…

9 30 28 26 24 22 D 20 C 18 Distance (km) 16 B 14 12 10 8 A 6 4 2 0 0 10 20 30 40 50 60 70 80 90 Time (minutes) The diagram shows the distance-time graph for the first 65 minutes of a bicycle journey. (a) There are four different parts to the journey labelled A, B, C and D. Write down the part of the journey with the fastest speed. ................................................. [1] (b) After the first 65 minutes the bicycle travels at a constant speed of 20 km/h for 15 minutes. Draw this part of the journey on the diagram. [1]

Mark scheme: 9 (a) A 1 (b) A ruled line joining (65, 23) to 1 (80, 28)

More questions on Rates

Question 10

10 Calculate. (a) 2 3 - 10 + 4 2 ................................................. [1] 2 3 # tan 70° (b) 3 ................................................. [1]

Mark scheme: 10 (a) 2.9[0] or 2.900 to 2.901 1 (b) 3.17 or 3.172 to 3.173 1  40  10 

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Q11 · Ahmed paid $34 000 for a car

11 Ahmed paid $34 000 for a car. His car decreased in value by 40% at the end of the first year. The value at the end of the second year was 10% less than the value at the end of the first year. Calculate the value of Ahmed’s car after 2 years. $ ................................................ [2]

Mark scheme:  40  10 11 18 360 2 M1 for 34 000 × 1 − × 1 − oe     100  100   1  4  5  3

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Q12 · NOT TO SCALE 5 cm The diagram shows a hemisphere with diameter 5 cm

12 NOT TO SCALE 5 cm The diagram shows a hemisphere with diameter 5 cm. Calculate the volume of this hemisphere. [The volume, V, of a sphere with radius r is V = 43 r r 3.] ........................................ cm3 [2]

Mark scheme:  1  4  5  ×12 32.7 or 32.72 to 32.73 2 M1 for × π×     2  3  2 

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Q13 · Write the recurring decimal .02o as a fraction

13 Write the recurring decimal .02o as a fraction. [ .02o means 0.222…] ................................................. [2]

Mark scheme: 2 13 oe, must be a fraction 2 M1 for 2.2 – 0.2 oe 9 k or B1 for 9

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Q14 · The shaded shape is made by joining a square and a rhombus

14 The shaded shape is made by joining a square and a rhombus. NOT TO SCALE 4.5 cm 5 cm Work out (a) the perimeter of the shaded shape, ......................................... cm [1] (b) the area of the shaded shape. ........................................ cm2 [2]

Mark scheme: 14 (a) 30 1 (b) 47.5 2 M1 for 4.5 × 5 oe

More questions on Compound shapes and parts of shapes

Q15 · A NOT TO SCALE C 44° B Triangle ABC is an isosceles triangle with AB = CB

15 (a) A NOT TO SCALE C 44° B Triangle ABC is an isosceles triangle with AB = CB. Angle ABC = 44°. Find angle ACB. Angle ACB = ............................................... [1] (b) A regular polygon has an exterior angle of 40°. Work out the number of sides of this polygon. ................................................. [2]

Mark scheme: 15 (a) 68 1 (b) 9 2 M1 for 360 ÷ 40 oe or 180 ( n − 2 ) = 140 oe n k

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Q16 · D is inversely proportional to (w + 1)2

16 d is inversely proportional to (w + 1)2. d = 3.2 when w = 4. Find d when w = 7. d = ................................................ [3]

Mark scheme: k 16 1.25 3 M1 for d = 2 or better ( w + 1) their k M1 for [d=] ( 7 + 1) 2 or M2 for 3.2(4 + 1)2 = d(7 + 1)2 oe 1 − 3

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Q17 · A is the point (8, 3) and B is the point (12, 1)

17 A is the point (8, 3) and B is the point (12, 1). Find the equation of the line, perpendicular to the line AB, which passes through the point (0, 0). ................................................. [3]

Mark scheme: 1 − 3 17 y = 2x oe 3 M1 for oe 12 − 8 1 − 3 M1 for perpendicular gradient × their = –1 12 − 8 oe If zero scored, SC1 for answer y = kx k ≠2 or 0

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Q18 · X - 318 f(x) = x2 g ( x) = 2 Find (a) f(– 5)…

x - 318 f(x) = x2 g ( x) = 2 Find (a) f(– 5), ................................................. [1] (b) gf(x), ................................................. [1] (c) g –1(x). g –1(x) = ................................................ [2]

Mark scheme: 18 (a) 25 1 x 2 − 3 (b) oe final answer 1 2 y − 3 (c) 2x + 3 final answer 2 M1 for correct first step, e.g. x = 2 or 2y = x – 3

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Q19 · The curve y = x3 + 2x2 – 4x is shown on the grid

19 The curve y = x3 + 2x2 – 4x is shown on the grid. y 9 8 7 6 5 4 3 2 1 x –3 –2 –1 0 1 2 –1 –2 –3 –4 –5 (a) By drawing a suitable tangent, find an estimate of the gradient of the curve when x = 1. ................................................. [3] (b) A point D lies on the curve. The x co-ordinate of D is negative. The gradient of the tangent at D is 0. Write down the co-ordinates of D. ( .................... , .................... ) [1]

Mark scheme: 19 (a) Correct tangent B1 No daylight between tangent and curve at point of contact. Consider point of contact as midpoint between two vertices of daylight, the midpoint must be between x = 0.8 and x = 1.2 2.1 ⩽ grad ⩽ 3.9 2 dep on B1 rise M1 for also dep on any tangent drawn or run close attempt at tangent at any point Must see correct or implied calculation from a drawn tangent (b) (–2, 8) 1

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Q20 · , 2 8 7 , 9 .3 , r ,20 (a)  = % / 9 A = {integers} B = {irrational numbers} Write all…

5 , 2 8 7 , 9 .3 , r ,20 (a)  = % / 9 A = {integers} B = {irrational numbers} Write all the elements of  in their correct place on the Venn diagram. A B [2] (b) Shade the region in each of the Venn diagrams below. E F C D G C l , D E + F l + G [2]

Mark scheme: 20 (a) E 2 B1 for 3 elements in the correct place A B 9.3 π 7 2√8 ହ ଽ (b) E 1 C D E E F 1 G 1

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Q21 · B 6.2 cm 82° A NOT TO SCALE 4.7 cm C Calculate the area of triangle ABC

21 (a) B 6.2 cm 82° A NOT TO SCALE 4.7 cm C Calculate the area of triangle ABC. .........................................cm2 [2] (b) E 107 mm NOT TO SCALE x° D 75 mm F The area of triangle DEF is 2050 mm2. Work out the value of x. x = ................................................ [2]

Mark scheme: 1 21 (a) 14.4 or 14.42 to 14.43 2 M1 for × 6.2 × 4.7 × sin 82 oe 2 2050 (b) 30.7 or 30.72… 2 M1 for sin = 1 × 1 07 × 75 2

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Q22 · The table shows some information about the mass, m grams, of 200 bananas

22 The table shows some information about the mass, m grams, of 200 bananas. Mass (m grams) 90 1 m G 110 110 1 m G 120 120 1 m G 125 125 1 m G 140 Frequency 40 70 60 30 Height of column 6 in histogram (cm) Complete the table. [4]

Mark scheme: 22 1 3.5 1 4 B3 for 2 correct B2 for 1 correct or M1 for 2, 7, […] and 2 seen [FDs]

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Question 23

23 Simplify. 42 np - 7n 12pt - 2t + 18mp - 3 m ................................................. [4]

Mark scheme: 23 7 n final answer 4 M1 for 7n(6p – 1) seen 2t + 3m and M2 for (2t + 3m)(6p – 1) seen or M1 for 2t(6p – 1) + 3m(6p – 1) or 6p(2t + 3m) – 1(2t + 3m)

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Q24 · Y 7 6 5 4 R 3 2 1 0 x 0 1 2 3 4 5 6 7 8 9 10 11 Find the three inequalities that define…

24 y 7 6 5 4 R 3 2 1 0 x 0 1 2 3 4 5 6 7 8 9 10 11 Find the three inequalities that define the unshaded region, R. ................................................. ................................................. ................................................. [5]

Mark scheme: 3 3 24 y ⩽ − x + 6 oe 5 SC4 for y < − x + 6, x > 2, y ⩾ x oe 5 5 x ⩾ 2 oe or y > x oe 3 B3 for y ⩽ − x + 6 oe 5 final answers 3 or B2 for y = − x + 6 oe 5 3 or B1 for gradient = – oe soi 5 and B2 for x ⩾ 2 and y > x oe or B1 for either x ⩾ 2 or y > x oe or for x = 2 and y = x with incorrect inequalities

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Q25 · 2 7 - 3 - 2 3 1 - 9 25 A = B = C = D = c2 1m c4 5m c 4 5 - 1m c 0m (a) Which of these…

4 2 7 - 3 - 2 3 1 - 9 25 A = B = C = D = c2 1m c4 5m c 4 5 - 1m c 0m (a) Which of these four matrix calculations is not possible? A + B 3C CB AD ................................................. [1] (b) Calculate AB. [2] f p (c) Work out B –1, the inverse of B. [2] f p (d) Explain why matrix A does not have an inverse. .............................................................................................................................................................. [1]

Mark scheme: 25 (a) CB 1  36 −2  (b) 2 B1 for two correct entries    18 −1  1  5 3   5 3  (c)   oe isw 2 B1 for k   seen or det = 47 soi 47  −4 7   −4 7  (d) The determinant is 0 oe 1

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Cambridge’s own grade thresholds for 2016 Oct/Nov, Paper 2 · Variant 3. A higher threshold means an easier paper — the bar moves with how the cohort did.

A53/70
B41/70
C29/70
D23/70
E18/70