Cambridge IGCSE Mathematics 0580 — 2010 Oct/Nov Paper 2 · Variant 2
0580/22/O/N/10 · 22 questions · 70 marks · ≈79 min
The question paper and its mark scheme, free to read here and free to download. This is Cambridge’s own paper, exactly as it was sat.
Question paper12 pages












Mark scheme4 pages
Answers below. Sit the paper first if you are practising.




Questions as text
Q1 · For Examiner's Use For the diagram, write down (a) the order of rotational symmetry…
1 For Examiner's Use For the diagram, write down (a) the order of rotational symmetry, Answer(a) [1] (b) the number of lines of symmetry. Answer(b) [1]
Mark scheme: Qu. Answers Mark Part Marks 1 (a) 5 1 (b) 0 1
Q2 · In a group of 30 students, 18 have visited Australia, 15 have visited Botswana and 5 have…
2 In a group of 30 students, 18 have visited Australia, 15 have visited Botswana and 5 have not visited either country. Work out the number of students who have visited Australia but not Botswana. Answer [2]
Mark scheme: 2 10 2 M1 33 – 25 M1 30 – 15 – 5 oe or 38 – 30 with no further working J
Q3 · Rearrange the formula J = mv – mu to make m the subject
3 Rearrange the formula J = mv – mu to make m the subject. Answer m = [2]
Mark scheme: J 3 m = 2 M1 m(v – u) seen v − u
Q4 · D For Examiner's NOT TO Use C SCALE 50° A B O O is the centre of the circle
4 D For Examiner's NOT TO Use C SCALE 50° A B O O is the centre of the circle. DA is the tangent to the circle at A and DB is the tangent to the circle at C. AOB is a straight line. Angle COB = 50°. Calculate (a) angle CBO, Answer(a) Angle CBO = [1] (b) angle DOC. Answer(b) Angle DOC = [1]
Mark scheme: 4 (a) 40 1 (b) 65 1 20 50
Q5 · J NOT TO 50 m SCALE 20 m G R JGR is a right-angled triangle
5 J NOT TO 50 m SCALE 20 m G R JGR is a right-angled triangle. JR = 50m and JG = 20m. Calculate angle JRG. Answer Angle JRG = [2]
Mark scheme: 20 50 5 23.6 2 M1 sin R = 20/50 or = sin R sin 90 3
Q6 · Write 0.00658 (a) in standard form, Answer(a) [1] (b) correct to 2 significant figures
6 Write 0.00658 (a) in standard form, Answer(a) [1] (b) correct to 2 significant figures. Answer(b) [1]
Mark scheme: 6 (a) 6.58 × 10–3 1 × and 10 essential (b) 0.0066 cao 1 Allow 6.6 × 10–3 1
Q7 · = a + tb and = a + (3t – 5)b where t is a number
7 = a + tb and = a + (3t – 5)b where t is a number. For Examiner's Use Find the value of t when = . Answer t = [2]
Mark scheme: 1 7 t = 2 2 M1 (b)t = (b)(3t – 5) 2
Q8 · 7 1 8 Show that + 1 = 2
7 7 1 8 Show that + 1 = 2 . 27 9 27 Write down all the steps in your working. Answer [2]
Mark scheme: 8 Answer given so only working scores 2 M1 7/27 + 48/27 or 7/27 + (1)21/27 marks M1 completely correct finish
Q9 · When a car wheel turns once, the car travels 120 cm, correct to the nearest centimetre
9 When a car wheel turns once, the car travels 120 cm, correct to the nearest centimetre. Calculate the lower and upper bounds for the distance travelled by the car when the wheel turns 20 times. Answer lower bound cm upper bound cm [2]
Mark scheme: 9 2390 2 M1 119.5 and 120.5 2410 or B1 for one correct answer
Q10 · For A B Examiner's Use NOT TO 140° 140° SCALE E C 140° D The pentagon has three angles…
10 For A B Examiner's Use NOT TO 140° 140° SCALE E C 140° D The pentagon has three angles which are each 140°. The other two interior angles are equal. Calculate the size of one of these angles. Answer [3]
Mark scheme: 10 60 3 B1 540 used M1 [their 540 – 3 × 140]/2 2
Q11 · The resistance, R, of an object being towed through the water varies directly as the…
11 The resistance, R, of an object being towed through the water varies directly as the square of the speed, v. R = 50 when v = 10. Find R when v = 16. Answer R = [3]
Mark scheme: 11 128 3 M1 R = kv2 1 A1 k = 2 x − 7
Q12 · Write as a single fraction, in its simplest form
12 Write as a single fraction, in its simplest form. 3 2 − x + 2 x − 1 Answer [3]
Mark scheme: x 7 12 3 M1 3(x – 1) – 2(x + 2) seen ( x − 1)( x + 2) B1 denominator correct seen A1 all correct IGCSE – October/November 2010 0580 22 2
Q13 · For Examiner's NOT TO Use SCALE The diagram shows a circle of radius 5cm in a square of…
13 For Examiner's NOT TO Use SCALE The diagram shows a circle of radius 5cm in a square of side 18cm. Calculate the shaded area. Answer cm2 [3]
Mark scheme: 13 245 or 246 3 M1 π × 52 M1 182 – their kπ
Q14 · Draw, accurately, the locus of all the points outside the triangle which are 3…
14 Draw, accurately, the locus of all the points outside the triangle which are 3 centimetres away from the triangle. [3]
Mark scheme: 14 3 M1 2 lines correct length M1 2 compass arcs correct length A1 complete accurate drawing with all lines and arcs solid
Q15 · The air fare from Singapore to Stockholm can be paid for in Singapore dollars (S$) or…
15 The air fare from Singapore to Stockholm can be paid for in Singapore dollars (S$) or Malaysian For Ringitts (RM). Examiner's One day the fare was S$740 or RM1900 and the exchange rate was S$1= RM2.448 . Use How much less would it cost to pay in Singapore dollars? Give your answer in Singapore dollars correct to the nearest Singapore dollar. Answer S$ [3]
Mark scheme: 15 36 cao 3 M1 1900/2.448 (= 776.14) A1 “776.(14…)” – 740 (= 36.14…) 4 8 4 8
Q16 · Simplify 1 16 16 2 (a) x , 81 Answer(a) [2] 16 y 10 × 4 y −4 (b) 7
16 Simplify 1 16 16 2 (a) x , 81 Answer(a) [2] 16 y 10 × 4 y −4 (b) 7 . 32 y Answer(b) [2]
Mark scheme: 4 4 16 (a) x8 2 B1 B1 x8 9 9 (b) 2y–1 2 B1 2 B1 y–1
Q17 · Boys Girls Total Asia 62 28 Europe 35 45 Africa 17 Total 255 For a small international…
17 Boys Girls Total Asia 62 28 Europe 35 45 Africa 17 Total 255 For a small international school, the holiday destinations of the 255 students are shown in the table. (a) Complete the table. [3] (b) What is the probability that a student chosen at random is a girl going on holiday to Europe? Answer(b) [1]
Mark scheme: 17 (a) 3 B1 two or three correct Boys Girls Total or B2 four or five correct Asia 62 28 90 Europe 35 45 80 Africa 68 17 85 Total 165 90 255 3 45 15 9 (b) or 0.176(47…) 1 Allow , , 17 255 85 51 14 0 ( ) −
Q18 · For 2 4 3 −4 Examiner's A = B = Use 5 3 −5 2 (a) Work out…
18 For 2 4 3 −4 Examiner's A = B = Use 5 3 −5 2 (a) Work out AB. Answer(a) [2] (b) Find | B |, the determinant of B. Answer(b) [1] (c) I is the (2 × 2) identity matrix. Find the matrix C, where C = A – 7I . Answer(c) [2]
Mark scheme: 14 0 18 (a) 0 −14 2 B1 two or three correct answers (b) –14 1 − 5 4 (c) 5 − 4 2 B1 two or three terms correct 2 2 2
Q19 · For P Examiner's Use 8 cm NOT TO SCALE C B 10 cm M D 10 cm A The diagram represents a…
19 For P Examiner's Use 8 cm NOT TO SCALE C B 10 cm M D 10 cm A The diagram represents a pyramid with a square base of side 10 cm. The diagonals AC and BD meet at M. P is vertically above M and PB = 8cm. (a) Calculate the length of BD. Answer(a) BD = cm [2] (b) Calculate MP, the height of the pyramid. Answer(b) MP = cm [3]
Mark scheme: 19 (a) 14.1 2 M1 (BD2) = 102 + 102 or sin45 = 10/CD (b) 3.74 or 3.78 3 M1 (a)/2 M1 (their (a)/2)2 + PM2 = 82
Q20 · For y Examiner's Use 8 7 6 5 4 3 2 1 x 0 1 2 3 4 5 6 7 8 (a) Draw the lines y = 2, x + y…
20 For y Examiner's Use 8 7 6 5 4 3 2 1 x 0 1 2 3 4 5 6 7 8 (a) Draw the lines y = 2, x + y = 6 and y = 2x on the grid above. [4] (b) Label the region R which satisfies the three inequalities x + y [ 6, y [ 2 and y Y 2x. [1]
Mark scheme: 20 (a) 4 B1 y = 2 single line thro B1 (6, 0) and B1 (0,6) R B1 y = 2x (b) 1 Correct R cao IGCSE – October/November 2010 0580 22
Q21 · An animal starts from rest and accelerates to its top speed in 7 seconds
21 An animal starts from rest and accelerates to its top speed in 7 seconds. It continues at this speed for Examiner's 9 seconds and then slows to a stop in a further 4 seconds. Use The graph shows this information. 14 12 10 Speed 8 (m / s) 6 4 2 0 2 4 6 8 10 12 14 16 18 20 Time (seconds) (a) Calculate its acceleration during the first seven seconds. Answer(a) m/s2 [1] (b) Write down its speed 18 seconds after the start. Answer(b) m/s [1] (c) Calculate the total distance that the animal travelled. Answer(c) m [3] Question 22 is printed on the next page.
Mark scheme: 21 (a) 2 1 (b) 6.7 to 7.3 1 (c) 203 3 M1 intention to find area under the graph 1 1 M1 × 7 × 14 + 9 × 14 + × 4 × 14 oe 2 2
Q22 · The line y = 2x + 7 meets the y-axis at A
22 (a) The line y = 2x + 7 meets the y-axis at A. For Examiner's Write down the co-ordinates of A. Use Answer(a) A = ( , ) [1] (b) A line parallel to y = 2x + 7 passes through B(0, 3). (i) Find the equation of this line. Answer(b)(i) [2] (ii) C is the point on the line y = 2x + 1 where x = 2. Find the co-ordinates of the midpoint of BC. Answer(b)(ii) ( , ) [3]
Mark scheme: 22 (a) (0, 7) 1 (b) (i) y = 2x + 3 2 B1 y = 2x + c, c ≠ 7 or B1 y = kx + 3, k ≠ 0 (ii) (1, 4) 3 B1 y = 5 0 + 2 3+"5" M1 , A1 (1, ft4) 2 2
What was in this paper
The subtopics covered by these 22 questions, and how many questions each got. Open one in a new tab to see every Cambridge question on it.
2Angles2Area and perimeter2Ratio and proportion2Algebraic fractions1Drawing linear graphs1Equations of linear graphs1Fractions, decimals and percentages1Geometrical constructions1Indices I1Interpreting statistical data1Introduction to probability1Limits of accuracy1Pythagoras’ theorem1Right-angled triangles1Standard form1Symmetry1Vectors in two dimensions1What you needed in this session
Cambridge’s own grade thresholds for 2010 Oct/Nov, Paper 2 · Variant 2. A higher threshold means an easier paper — the bar moves with how the cohort did.