Cambridge IGCSE Mathematics 0580 — 2019 May/June Paper 2 · Variant 2

0580/22/M/J/19 · 25 questions · 70 marks · ≈79 min

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Mark scheme6 pages

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Questions as text

Q1 · Write down a prime number between 50 and 60

1 Write down a prime number between 50 and 60. ............................................... [1]

Mark scheme: Question Answer Marks Partial Marks 1 53 or 59 1

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Q2 · 2 Use your calculator to work out 1 sin 33°

2 2 Use your calculator to work out 1 sin 33° . -` j ............................................... [1]

Mark scheme: 2 0.839 or 0.8386 to 0.8387 1

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Q3 · Write the recurring decimal .07o as a fraction

3 Write the recurring decimal .07o as a fraction. ............................................... [1]

Mark scheme: 3 7 1 9

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Question 4

4 Complete each statement. (a) A quadrilateral with only one pair of parallel sides is called a ............................................... . [1] (b) An angle greater than 90° but less than 180° is called ............................................... . [1]

Mark scheme: 4(a) Trapezium 1 4(b) Obtuse 1

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Q5 · The distance between Prague and Vienna is 254 kilometres

5 The distance between Prague and Vienna is 254 kilometres. The local time in Prague is the same as the local time in Vienna. A train leaves Prague at 15 20 and arrives in Vienna at 19 50 the same day. Calculate the average speed of the train. ...................................... km/h [2]

Mark scheme: 5 56.4 or 56.44… 2 254 254 M1 for or [× 60 ] their 4.5 their 270

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Question 6

6 Solve the equation. 9f + 11 = 3f + 23 f = ............................................... [2]

Mark scheme: 6 2 2 M1 for 9f – 3f oe or 23 − 11 oe

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Q7 · NOT TO SCALE 3.5 cm 8.4 cm Calculate the area of this triangle

7 NOT TO SCALE 3.5 cm 8.4 cm Calculate the area of this triangle. ........................................ cm2 [2]

Mark scheme: 7 14.7 2 1 M1 for × 8.4 × 3.5 oe 2

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Q8 · Write 0.047 883 correct to 2 significant figures

8 (a) Write 0.047 883 correct to 2 significant figures. ............................................... [1] (b) Write 0.005 27 in standard form. ............................................... [1]

Mark scheme: 8(a) 0.048 cao 1 8(b) 5.27 × 10−3 1

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Q9 · Find the highest common factor (HCF) of 90 and 48

9 Find the highest common factor (HCF) of 90 and 48. ............................................... [2]

Mark scheme: 9 6 2 M1 for 2 × 32 × 5 or 24 × 3 or for 2 × 3 as final answer or B1 for 2 or 3 as final answer

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Q10 · On a map with scale 1 : 25 000, the area of a lake is 33.6 square centimetres

10 On a map with scale 1 : 25 000, the area of a lake is 33.6 square centimetres. Calculate the actual area of the lake, giving your answer in square kilometres. ........................................ km2 [2]

Mark scheme: 10 2.1 2 33.6 × 25000 2 M1 for oe 100000 2 or answer figs 21

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Q11 · Write down the matrix that represents an enlargement, scale factor 3, centre (0, 0)

11 Write down the matrix that represents an enlargement, scale factor 3, centre (0, 0). [2] f p

Mark scheme: 11  3 0  2 B1 for one row or one column correct in a   2 by 2 matrix in the final answer  0 3   0 3  or SC1 for    3 0 

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Question 12

12 Simplify. (a) 5m 2 # 2m 3 ............................................... [2] 3 (b) x 8 ` j ............................................... [1]

Mark scheme: 12(a) 10m 5 final answer 2 B1 for 10 m k or km 5 as final answer 12(b) x 24 final answer 1

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Q13 · ' 7 .13 Without using a calculator, work out 2 14 3 You must show all your working and…

' 7 .13 Without using a calculator, work out 2 14 3 You must show all your working and give your answer as a mixed number in its simplest form. ............................................... [3]

Mark scheme: 13 9 7 63 12 M2 9 × or ÷ oe with common B1 for oe seen 4 3 28 28 4 denominator 9 7 or M1 for their × 4 3 1 A1 5 cao 4

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Q14 · Solve the simultaneous equations

14 Solve the simultaneous equations. You must show all your working. 5x + 8y = 4 1 2 x + 3y = 7 x = .............................................. y = .............................................. [3]

Mark scheme: 14 Correctly eliminating one variable M1 [x =] − 4 A2 A1 for one correct [y =] 3 If M0 scored, SC1 for 2 values satisfying one of the original equations

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Q15 · Shona buys a chair in a sale for $435.60

15 Shona buys a chair in a sale for $435.60 . This is a reduction of 12% on the original price. Calculate the original price of the chair. $ ............................................... [3]

Mark scheme: 15 495 3 100 − 12 M2 for 435.6 ÷ oe 100 or B1 for recognising 435.6 as 88[%]

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Q16 · Y 10 8 6 4 2 –4 –2 0 2 4 6 8 10 12 14 x –2 –4 –6 + 6 y H 3x - 4 x + y H 5 y G- 12 x (a)…

16 y 10 8 6 4 2 –4 –2 0 2 4 6 8 10 12 14 x –2 –4 –6 + 6 y H 3x - 4 x + y H 5 y G- 12 x (a) By shading the unwanted regions of the grid, find and label the region R that satisfies the three inequalities. [2] (b) Find the largest value of x + y in the region R, where x and y are integers. ............................................... [1]

Mark scheme: 16(a) R identified correctly 2 B marks 0 1 1 2 0 1 1 1 0 0 1 1 1 0 0 16(b) 7 1

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Q17 · Write as a single fraction in its simplest form

17 Write as a single fraction in its simplest form. 2 x x + 3 + x + 3 x - 5 ............................................... [3]

Mark scheme: 17 3 x 2 − 4 x + 9 3 B1 for common denominator final answer ( x + 3 )( x − 5 ) oe isw ( x + 3 )( x − 5 ) M1 for 2 x ( x − 5 ) + ( x + 3 )( x + 3 ) or better

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Q18 · The table shows the number of people in different age groups at a cinema

18 The table shows the number of people in different age groups at a cinema. Age ( y years) 15 1 y G 25 25 1 y G 30 30 1 y G 50 50 1 y G 80 Number of people 35 32 44 12 Dexter draws a histogram to show this information. The height of the bar he draws for the group 15 1 y G 25 is 7 cm. Calculate the height of each of the remaining bars. 25 1 y G 30 ........................................ cm 30 1 y G 50 ........................................ cm 50 1 y G 80 ........................................ cm [3]

Mark scheme: 18 12.8 3 B2 for 2 correct heights or 3 correct freq 4.4 densities 0.8 or B1 for 1 correct height or 2 correct freq densities

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Q19 · Rearrange this formula to make m the subject

19 Rearrange this formula to make m the subject. k + m P = m ............................................... [4]

Mark scheme: 19 k 4 k m = final answer B3 for final answer P − 1 P − 1 OR M1 for multiplying or dividing by m correctly M1 for term(s) in m on one side correctly and terms not in m on the other side correctly M1 for correctly factorising m with a 2-term bracket oe M1 for correct division by their 2-term bracket with m as the subject To a maximum of M3 for an incorrect answer

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Q20 · Solve the equation 3x 2 - 2x - 10 = 0

20 Solve the equation 3x 2 - 2x - 10 = 0 . Show all your working and give your answers correct to 2 decimal places. x = ..................... or x = ..................... [4]

Mark scheme: 20 2 B2 2 −−( 2 ) ± ( −2 ) − 4 ( 3 )( −10 ) B1 for ( −2 ) − 4 ( 3 )( − 10 ) or better 2 × 3 p + q p − q and if in form or then r r B1 for p = −(− 2) and r = 2(3) −1.52 and 2.19 final ans cao B1B1 If B0B0, SC1 for −1.5 and 2.2 or −1.523 to −1.522... and 2.189.... or 1.52 and −2.19 or −1.52 and 2.19 seen in working

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Q21 · In the Venn diagram, shade X l k Y

21 (a) In the Venn diagram, shade X l k Y . X Y [1] (b) The Venn diagram below shows information about the number of gardeners who grow melons (M ), potatoes (P ) and carrots (C ). M P 3 6 12 2 5 10 7 23 C (i) A gardener is chosen at random from the gardeners who grow melons. Find the probability that this gardener does not grow carrots. ............................................... [2] (ii) Find n ((M k P) j C l) . ............................................... [1]

Mark scheme: 21(a) 1 X Y 21(b)(i) 9 2 9 k oe B1 for or provided fraction is less 16 k 16 than 1 21(b)(ii) 46 1

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Q22 · 7 3 4 22 A = B = e1 3o e0 1o (a) Calculate AB

2 7 3 4 22 A = B = e1 3o e0 1o (a) Calculate AB. [2] f p (b) Find A -1 , the inverse of A. [2] f p

Mark scheme: 22(a)  6 15  2 B1 for 2 correct elements    3 7  22(b)  − 3 7  2  3 −7    oe isw B1 for k   soi or det = − 1 soi  1 − 2   −1 2 

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Q23 · N NOT TO D C SCALE p X A q B M ABCD is a parallelogram with AB = q and AD = p

23 N NOT TO D C SCALE p X A q B M ABCD is a parallelogram with AB = q and AD = p . ABM is a straight line with AB : BM = 1 : 1. ADN is a straight line with AD : DN = 3 : 2 . (a) Write MN , in terms of p and q, in its simplest form. MN = .............................................. [2] (b) The straight line NM cuts BC at X. X is the midpoint of MN. BX = kp Find the value of k. k = .............................................. [2]

Mark scheme: 23(a) 5 2 M1 for correct unsimplified answer p−2q oe simplified 3 5 or cp−2q or p + cq c ≠ 0 3 or for a correct route 23(b) 5 their c B2FT for if their (a) is cp−2q oe 2 6 2 JJJJG 5 M1 for MX = p−q 6 JJJJG 1 or MX = their (a) 2 JJJG JJJG 1 or BX = AN 2 JJJJG 1 or q + their (a) or q + MX −kp = 0 oe 2

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Q24 · H G E F 12 cm NOT TO SCALE D C 7 cm A 18 cm B ABCDEFGH is a cuboid

24 H G E F 12 cm NOT TO SCALE D C 7 cm A 18 cm B ABCDEFGH is a cuboid. AB = 18 cm, BC = 7 cm and CG = 12 cm. Calculate the angle that the diagonal AG makes with the base ABCD. ............................................... [4] Question 25 is printed on the next page.

Mark scheme: 24 31.9 or 31.85... 4 12 M3 for tan = oe 18 2 + 7 2 or M2 for 18 2 + 7 2 or M1 for 18 2 + 7 2 or B1 for identifying correct angle CAG

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Q25 · Y 77 66 55 A 44 33 22 11 –11 –10 –9 –8 –7 –6 –5 –4 –3 –2 –1 0 1 2 3 4 5 6 7 8 x –1 –2 –3…

25 y 77 66 55 A 44 33 22 11 –11 –10 –9 –8 –7 –6 –5 –4 –3 –2 –1 0 1 2 3 4 5 6 7 8 x –1 –2 –3 B C –4 –5 –6 –7 Describe fully the single transformation that maps (a) triangle A onto triangle B, ............................................................................................................................................................ ............................................................................................................................................................ [3] (b) triangle A onto triangle C. ............................................................................................................................................................ ............................................................................................................................................................ [3]

Mark scheme: 25(a) Rotation 3 B1 for each 90° clockwise oe (1, 0) 25(b) Enlargement 3 B1 for each − 2 (0, 2)

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What was in this paper

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Cambridge’s own grade thresholds for 2019 May/June, Paper 2 · Variant 2. A higher threshold means an easier paper — the bar moves with how the cohort did.

A55/70
B46/70
C38/70
D31/70
E25/70