Percentages — Paper 1 · IGCSE Mathematics 0580

14 Bernard is buying a radio priced at $19.60. The shopkeeper gives him a 15% discount. Calculate how much Bernard pays. Answer $ [3]

3 marks

Mark scheme: 14 16.66 cao 3 M1 for 0.15 x 19.60 (implied by 2.94 seen) M1 for 19.60 – his 2.94 (allow if 2.94 is rounded to 2.90, method only) or M2 for 0.85 x 19.60 [allow for (1 – 0.15) x 19.60] Answer 1666 2 marks, 1670 1 mark ww. 16.7(0) implies M2

This question in 0580/11 Oct/Nov 2004

17 Ferdinand’s electricity meter is read every three months. For The reading on 1st April was 70683 units and on 1st July it was 71701 units. Examiner's Use (a) How many units of electricity did he use in those three months? Answer(a) units [1] (b) Electricity costs 8.78 cents per unit. Calculate his bill for those three months. Give your answer in dollars, correct to the nearest cent. Answer(b) $ [2]

3 marks

Mark scheme: 17 (a) 1018 1 (b) 89.38 final answer ft. 2 M1 for his (a) x 8.78 soi or SC1 for answer in cents. IGCSE EXAMINATIONS – NOVEMBER 2004 0580/0581 1

This question in 0580/11 Oct/Nov 2004

3 Anne took a test in chemistry. She scored 20 marks out of 50. Work out her percentage mark. Answer % [1]

1 marks

Mark scheme: 3 40 1

This question in 0580/11 May/June 2005

7 Alphonse spends $28 on food. For 4 Examiner's This amount is of his allowance. Use 9 Calculate his allowance. Answer $ [2]

2 marks

Mark scheme: 7 63 2 M1 for 28 ÷ 4 x 9 (can be implied by 2524 ) 63.64 or 63.63 implies M1

This question in 0580/11 May/June 2005

21 SALE All items 35% Reduction Abdul bought a spade in this sale. Its original price was $16. (a) How much did Abdul save? Answer (a) $ [2] (b) The next day, all items were sold at half the original price. How much more would Abdul have saved if he had waited until the next day to buy the spade? Answer (b) $ [1]

3 marks

Mark scheme: 21 (a) 5.6(0) oe (allow 5 35) 2 M1 for 35 ÷ 100 × 16 SC1 for $10.40 1ft $8 – their (a) if positive result from their (a) (b) 2.4(0) oe www 2 allow saving calculated from comparing costs or (allow 2 5) 15 savings

This question in 0580/11 May/June 2005

13 The population of Latvia in 1989 was 2 700 000. In 1994 it was 2 500 000. Calculate the percentage decrease in the population between 1989 and 1994. Answer % [3]

3 marks

Mark scheme: 13 (Decrease) 200 000 B1 2500000 (alt. method) x 100 or 92.5 B1 2700000 subtract answer from 100 M1 Their 200 000 M1 × 100 2700 000 7.41 or 7.40(7….) A1

This question in 0580/11 Oct/Nov 2005

19 Joseph buys 45 kilograms of potatoes from a supplier for $0.65 per kilogram. (a) How much does he pay for the potatoes? Answer(a) $ [1] (b) He then puts the potatoes into bags which each hold 2.5 kilograms. How many bags can he fill with the potatoes? Answer(b) bags [1] (c) At the market he sells the bags of potatoes for $2.20 per bag. Calculate the smallest number of complete bags he needs to sell in order to make a profit. Answer(c) bags [2]

4 marks

Mark scheme: 19 (a) 29.25 or 29.2 or 29.3 1 (b) 18 1 (c) Their (a) ÷ 2.20 M1 Implied by 13.3 or 13.2 (...) seen 14 A [16]

This question in 0580/11 Oct/Nov 2005

20 For Examiner's Use $900 Lorenzo saves money for a motorbike. The marked price of the motorbike is $900. He pays a deposit of 35% of the marked price. (a) Calculate his deposit. Answer(a) $ [2] (b) He then makes 12 monthly payments of $60 each. How much more than the $900 marked price does he pay altogether? Answer(b) $ [3]

5 marks

Mark scheme: 20 (a) 35 ÷ 100 × 900 M1 =315 A1 (b) (Payments) 720 B1 Implied by 1035 seen Deposit + Payments – 900 M1 135 A1 f.t. No follow through for negative answer

This question in 0580/11 Oct/Nov 2005

11 Rodriguez puts $500 into a bank account. The bank pays 5% compound interest per year. For Examiner's (a) How much is the interest after one year? Use Answer(a) $ [1] (b) Work out the total amount he has in his bank account after two years. Answer(b) $ [2]

3 marks

Mark scheme: 11 (a) ($) 25 1 (b) ($) 551.25 2 M1 for 500 x 1.052 or (c’s (a) + 500) x 1.05

This question in 0580/11 May/June 2006

14 (a) Pierre arrives at school at 08 40 and leaves at 15 30. How long, in hours and minutes, is he in school? Answer(a) h min [1] (b) Each day, Pierre gets up at 07 00 and goes to bed at 22 00. What percentage of each day is he in bed? Answer(b) % [2]

3 marks

Mark scheme: 14 (a) 6 (h) 50 (min) 1 (b) 37.5 (%) 2 B1 for 9 (hours) seen or M1 for c’s 9 ÷ 24 x 100

This question in 0580/11 May/June 2006

19 A shopkeeper buys some ready-made meals from a supplier. For Examiner's (a) Complete the bill shown below. Use Meal Cost of one meal Number of meals Total cost Chicken curry $3.48 15 $ Pizza $2.99 28 $ [1] (b) He sells all 15 Chicken curry meals for $4.00 each. Work out the total profit on these meals. Answer(b) $ [1] (c) He sells 15 Pizzas for $3.55 each but is unable to sell the rest. Calculate his loss on the Pizzas as a percentage of the total cost of the Pizzas. Answer(c) % [2]

4 marks

Mark scheme: 19 (a) 52.2(0) 83.7(2) 1 (b) 7.8(0) 1ft 60 − their ($3.48 × 15) (c) art 36.4 allow –ve. 2ft M1 for ((their 83.72 − 15 × 3.55)/their 83.72) × Accept 36www 100 or 100 − ((15 × 3.55)/their 83.72) × 100

This question in 0580/11 Oct/Nov 2006

13 A school has 240 students. (a) There are 131 girls. What percentage of the students are girls? Answer(a) [2] (b) One day 6.25% of the 240 students are absent. Work out the number of students who are absent. Answer(b) [2]

4 marks

Mark scheme: 13 (a) 55 or art 54.6 2 M1 for 131 ÷ 240(× 100) implied by 54.5 (b) 15 2 M1 for 6.25 ÷ 100 × 240 SC1 for answer 225

This question in 0580/11 Oct/Nov 2007

17 (a) Alex invests $200 for 2 years at 4.05% per year simple interest. Calculate how much interest Alex receives. Answer(a) $ [2] (b) Bobbie invests $200 for 2 years at 4% per year compound interest. Calculate how much interest Bobbie receives. Give your answer to 2 decimal places. Answer(b) $ [2]

4 marks

Mark scheme: 17 (a) ($) 16.2(0) 2 M1 for (200 × 4.05 × 2)/100 SC1 for 216.2(0) (b) ($) 16.3(2) or 16.3(0) 2 M1 for 200(1.04) 2 − 200oe SC1 for 216.3(2). SC1 for both 8.(00) and 8.3(2) seen

This question in 0580/11 Oct/Nov 2007

19 ForFor Examiner'sExaminer's UseUse Silver Other Yellow Red The accurate pie chart shows information about the colours of 240 cars in a car park. (a) The sector angle for silver cars is 90°. Calculate the number of silver cars in the car park. Answer(a) [1] (b) There are 36 yellow cars in the car park. Showing all your working, calculate the sector angle for yellow cars. Answer(b) [2] (c) (i) Measure and write down the sector angle for red cars. Answer(c)(i) [1] (ii) Calculate the percentage of red cars in the car park. Answer(c)(ii) % [2]

6 marks

Mark scheme: 19 (a) 60 1 (b) 36 ÷ 240 × 360 oe M1 oe e.g. 36 × 90 ÷ 60 54 A1 W2 54 with some relevant working shown (c) (i) 116 to 118 1 (ii) 32.5 or their (c) (i) ÷ 3.6 2ft M1 for their (c) (i) ÷ 360 × 100 Or for their (c) (i) × (60 ÷ 90) ÷ 240 × 100 Allow revised angle in range 116 – 118 seen with working

This question in 0580/12 Oct/Nov 2009

16 Daniel invested $2500 for 2 years at 5.5% per year compound interest. Examiner's Use Calculate how much interest he received. Answer $ [3]

3 marks

Mark scheme: 16 ($)282.56(…) 3 M1 for 2500 × 1.0552 oe 2782(. ...) and M1 dep for subtracting 2500

This question in 0580/12 May/June 2010

5 In a sale, the price of a boat was reduced from $21 000 to $16 800. Calculate the reduction as a percentage of the original price. Answer % [2]

2 marks

Mark scheme: their ( 21000 16800) 4200 5 20 2 M1 for or 21000 21000

This question in 0580/13 May/June 2010

7 Maria puts $600 into a bank account for 3 years at a rate of 3.4% per year compound interest. Calculate how much will be in the account at the end of the 3 years. Answer $ [3]

3 marks

Mark scheme: 7 662.794 to 663.304…. final answer 3 M2 for 600 × 1.0343 or M1 for (600 + 0.034 × 600) × 0.034 or (600 × 1.034) × 0.034 and M1 dep correct method for the remaining time.

This question in 0580/12 Oct/Nov 2010

9 When Valentina was 10 years old, her mass was 32 kg. Two years later her mass had increased by 45%. Calculate Valentina’s mass when she was 12 years old. Answer kg [2]

2 marks

Mark scheme: 9 46.4 2 M1 for 32 × 1.45 oe or B1 for answer of 14.4 3 1875

This question in 0580/13 Oct/Nov 2010

15 Amiria invests $200 for 2 years at 3% per year compound interest. For Examiner's Calculate the total amount Amiria has at the end of the two years. Use Answer $ [3]

3 marks

Mark scheme: 15 212.18 final answer cao 3 M2 for 200 × 1.032 oe or M1 for (200 × 1.03) × 0.03 oe

This question in 0580/13 Oct/Nov 2010

1 A concert hall has 1540 seats. For Examiner's Calculate the number of people in the hall when 55% of the seats are occupied. Use Answer [1]

1 marks

Mark scheme: Qu. Answers Mark Part Marks 1 847 1

This question in 0580/11 May/June 2011

13 Paulo invests $3000 at a rate of 4% per year compound interest. Calculate the total amount Paulo has after 2 years. Give your answer correct to the nearest dollar. Answer $ [3]

3 marks

Mark scheme: 13 3245 3 M1 for 3000 × 1.04 2 A1 for 3244.8 If zero, SC2 for answer of 245 If zero, SC1 for their answer corrected to nearest dollar

This question in 0580/11 May/June 2011

11 The table shows the opening and closing times of a café. For Examiner's Use Mon Tue Wed Thu Fri Sat Sun Opening time 0600 0600 0600 0600 0600 (a) 0800 Closing time 2200 2200 2200 2200 2200 2200 1300 (a) The café is open for a total of 100 hours each week. Work out the opening time on Saturday. Answer(a) [2] (b) The owner decides to close the café at a later time on Sunday. This increases the total number of hours the café is open by 4%. Work out the new closing time on Sunday. Answer(b) [1]

3 marks

Mark scheme: 11 (a) (0)700 or 7 am 2 M1 100 – (5 × their(22 – 6) + their(13 – 8)) or better soi (b) 1700 or 5 pm 1 IGCSE – May/June 2011 0580 12

This question in 0580/12 May/June 2011

18 Eva invests $120 at a rate of 3% per year compound interest. For Examiner's Calculate the total amount Eva has after 2 years. Use Give your answer correct to 2 decimal places. Answer $ [3]

3 marks

Mark scheme: 18 127.31 cao 3 M1 for 120 × 1.032 A1 for 127.308 If M0 award SC2 for 7.31 or 247.31

This question in 0580/13 May/June 2011

7 (a) Calculate 60% of 200. Answer(a) [1] (b) Write 0.36 as a fraction. Give your answer in its lowest terms. Answer(b) [2]

3 marks

Mark scheme: 7 (a) 120 1 9 36 18 (b) cao 2 B1 or 25 for100 50 2

This question in 0580/11 Oct/Nov 2011

18 (a) Lucinda invests $500 at a rate of 5% per year simple interest. For Examiner's Calculate the interest Lucinda has after 3 years. Use Answer(a) $ [2] (b) Andy invests $500 at a rate of 5% per year compound interest. Calculate how much more interest Andy has than Lucinda after 3 years. Answer(b) $ [4]

6 marks

Mark scheme: 500 × 5 × 3 18 (a) 75 2 M1 for oe 100 or SC1 for answer of 575 (b) 3.81(25) 4 M2 for 500 × 1.05 × 1.05 × 1.05 or M1 for 500 × 1.05 × 1.05 A1 for 578.81(25) or 78.81(25) seen and A1ft for value of 500(1.05)3 – 500 – their (a)

This question in 0580/11 Oct/Nov 2011

9 Calculate the selling price of a bicycle bought for $120 and sold at a profit of 15%. Answer $ [2]

2 marks

Mark scheme: 9 ($)138 2 M1 for 120 × 1.15 oe SC1 answer 18

This question in 0580/13 Oct/Nov 2011

13 Pedro invested $800 at a rate of 5% per year compound interest. Calculate the total amount he has after 2 years. Answer $ [2]

2 marks

Mark scheme: 13 882 2 M1 800 × 1.05 × 1.05 2 2 2

This question in 0580/13 Oct/Nov 2011

1 Kyle scores 84 marks out of 96 in an examination. For Examiner's Work out his percentage mark. Use Answer % [1]

1 marks

Mark scheme: Qu Answers Mark Part marks 1 87.5 1

This question in 0580/11 May/June 2012

1 For 13 Shania invests $750 at a rate of 2 2 % per year simple interest. Examiner's Use Calculate the total amount Shania has after 5 years. Answer $ [3]

3 marks

Mark scheme: 750 × 5 × 5.2 13 843.75 3 M2 for + 750 oe 100 750 × 5 × 5.2 or M1 for oe 100 or SC2 for answer 93.75 55 27 25 27

This question in 0580/11 May/June 2012

4 A football ground seats 28 750 people when it is full. For Examiner's Use (a) Write 28 750 correct to the nearest thousand. Answer(a) [1] (b) One day 17 250 people attended a football match. Work out 17 250 as a percentage of 28 750. Answer(b) % [1]

2 marks

Mark scheme: 4 (a) 29 000 1 (b) 60 1

This question in 0580/11 Oct/Nov 2012

9 Patrick buys some bananas for $35. He sells all the bananas for $40.60 . Calculate his percentage profit. Show all your working. Answer % [3]

3 marks

Mark scheme: 9 16 3 40.60 − 35 40 6. M2 for × 100 or × 100 − 100 or 35 35 40 6. M1 for 40.60 – 35 or 35

This question in 0580/12 Oct/Nov 2012

16 Musa borrows $600 for 2 years at a rate of 7.5% per year compound interest. At the end of the 2 years she repays the amount owing in full. Calculate the total amount she has to repay. Give your answer correct to the nearest dollar. Answer $ [3]

3 marks

Mark scheme: 5.7 2 16 ($) 693 (.00) 3 M1 for 600(1 + ) or equivalent in stages. 100 A1 for 693.4 or 693.37 or 693.38 or 693.375 A1ft for their answer to the nearest dollar If zero SC2 for 93 and SC1 for 93.4 or 93.37 or 93.38

This question in 0580/12 Oct/Nov 2012

15 Bruce invested $420 at a rate of 4% per year compound interest. Calculate the total amount Bruce has after 2 years. Give your answer correct to 2 decimal places. Answer $ … [3] _____________________________________________________________________________________

3 marks

Mark scheme:  + 1  oe15 454.27 cao final answer 3 M1 for 420 ×  100  and A1 for 454 or 454.2 to 454.3 or SC2 for answer 34.27 or SC1 for answer 34.2 to 34.3

This question in 0580/11 May/June 2013

21 Carol invests $6250 at a rate of 2% per year compound interest. For Examiner's Use Calculate the total amount Carol has after 3 years. Answer $ … [3] _____________________________________________________________________________________

3 marks

Mark scheme: 2 21 6632.55 cao final answer 3 M2 for 6250 × + 1  oe  100  2  2 or M1 for 6250 × + 1  oe  100  SC2 for answer 382.55 final answer

This question in 0580/12 May/June 2013

13 Huy borrowed $4500 from a bank at a rate of 5% per year compound interest. He paid back the money and interest at the end of 2 years. How much interest did he pay? Answer $ … [3] _____________________________________________________________________________________

3 marks

Mark scheme: 13 ( $ ) 461.25 cao 3 M1 for 4 500 × 1.05 2 oe A1 for 4961.25 A1ft their amount − 4500 OR M2for 4500×0.05+(4500×1.05)×1.05 or M1 for 4500 × 0.05 + 4500

This question in 0580/13 May/June 2013

3 Work out 72 cents as a percentage of 83 cents. Answer … % [1] _____________________________________________________________________________________

1 marks

Mark scheme: 3 86.7 or 86.74 to 86.75 1

This question in 0580/11 Oct/Nov 2013

10 Calculate 17.5% of 44 kg. Answer … kg [2] _____________________________________________________________________________________

2 marks

Mark scheme: 17.5 10 7.7 2 M1 for 44 × oe 100

This question in 0580/11 Oct/Nov 2013

15 At the beginning of July, Kim had a mass of 63 kg. At the end of July, his mass was 61 kg. Calculate the percentage loss in Kim’s mass. Answer … % [3] __________________________________________________________________________________________

3 marks

Mark scheme: M2 for × 100 oe or 100 – ×100 oe 15 3.17 or 3.174 to 3.175 3 63 63 63− 61 61 or M1 for oe or × 100 63 63  1 1  3  1 

This question in 0580/12 May/June 2014

17 Dominic invests $850 at a rate of 3.5% per year compound interest. Calculate the total amount he has after 3 years. Answer $ … [3] __________________________________________________________________________________________

3 marks

Mark scheme: 17 [$] 942.41 3 M2 for 850× .1035 3 oe or M1 for 850 × .1035 × .1035 oe or SC2 for answer of interest only

This question in 0580/11 Oct/Nov 2014

12 $760 is invested for 3 years at a rate of 4.5% per year simple interest. Work out the total interest at the end of the 3 years. Answer $ … [2] __________________________________________________________________________________________

2 marks

Mark scheme: 5.4 12 102.6[0] 2 M1 for 760 × 3 × or better 100

This question in 0580/12 Feb/March 2015

3 (a) A mass of 300 kg is increased by 8%. Work out the increase in mass. Answer(a) … kg [1] (b) Nelson scores 27 out of 40 in a history test. Work out his score as a percentage. Answer(b) … % [1] __________________________________________________________________________________________

2 marks

Mark scheme: 3 (a) 24 final answer 1 (b) 67.5 1

This question in 0580/11 May/June 2015

5 Prince Charming invests $3000 for 5 years at a rate of 4% per year simple interest. Calculate the total interest he will receive. Answer $ … [2] __________________________________________________________________________________________

2 marks

Mark scheme: 3000 × 5 × 4 5 600 2 M1 for oe 100 If zero scored, SC1 for answer 3600

This question in 0580/11 May/June 2015

16 In a sale, the cost of a coat is reduced from $85 to $67.50 . Calculate the percentage reduction in the cost of the coat. Answer … % [3] __________________________________________________________________________________________

3 marks

Mark scheme: 16 20.6 or 20.58 to 20.59 3 85 − 675. 67 5.  M2 for × 100 or − 1  × 100 85  85  85 − 67 5. 675. or M1 for or × 100 85 85 675. − 85 If zero scored SC1 for × 100 85

This question in 0580/13 May/June 2015

2 From a sample of 80 batteries, 3 are faulty. Work out the percentage of faulty batteries. … % [1]

1 marks

Mark scheme: 2 3.75 or 3¾ 1

This question in 0580/11 May/June 2016

6 Work out $216 as a percentage of $600. … % [1]

1 marks

Mark scheme: 6 36 1

This question in 0580/12 May/June 2016

8 David goes to college by bus. On 6 mornings out of 45, the bus is late. In one year David goes to college by bus 180 times. Estimate how many mornings the bus is late in one year. … [2]

2 marks

Mark scheme: 8 24 2 M1 for 6 ÷ 45 or 180 ÷ 45

This question in 0580/12 May/June 2016

14 Cheng invested $4500 at a rate of 3.5% per year compound interest. Calculate the total amount he has after 3 years. $ … [3]

3 marks

Mark scheme: 3.5  1 +14 4 990 or 4 989 or 4 989.2 or 4 989.23 3 M2 for 4 500   oe  100  2  3.5  or M1 for 4 500  1 +  oe  100 

This question in 0580/13 May/June 2016

19 Kaasni invested $2400 at a rate of 7.5% per year compound interest. Calculate the total value of this investment at the end of 3 years. Give your answer correct to 2 decimal places. $ … [3]

3 marks

Mark scheme: 19 2981.51 3 M2 for 2400 × 1.0753 oe or M1 for 2400 × 1.0752 oe If zero scored SC2 for 581.51 or SC1 for 581.512[5] or 581.513

This question in 0580/12 Feb/March 2017

4 Work out 85 cents as a percentage of $2.03 . … % [1]

1 marks

Mark scheme: 4 41.9 or 41.87… 1

This question in 0580/12 May/June 2017

10 (a) Write 0.03 as a percentage. … % [1] (b) Write 37% as a fraction. … [1]

2 marks

Mark scheme: 10(a) 3 1 10(b) 37 1 100

This question in 0580/12 May/June 2017

23 Pablo has $16 400 to invest in one of these savings plans. Plan A pays compound interest at a rate of 4% per year. Plan B pays simple interest at a rate of 4% per year. Pablo invests the $16 400 for 3 years. Calculate how much more he will receive from Plan A than from Plan B. Give your answer correct to 2 decimal places. $ … [5] Question 24 is printed on the next page.

5 marks

Mark scheme: 23 79.76 or 79.77 5 Total amounts method  4  3 M2 for 16400  1 +  oe  100   4  2 or M1 for 16400  1 +  oe  100  and 16400 × 4 × 3 M2 for + 16400 100 16400 × 4 × 3 or M1 for 100 Interests method B3 for 2047 to 2048 or M3 for 656 + 682[.24] + 709[.5296]  4  3 or for 16400  1 +  – 16400  100  and 16400 × 4 × 3 M1 for 100

This question in 0580/12 May/June 2017

17 $600 is invested for 3 years at a rate of 2.5% per year compound interest. Calculate the total value of the investment at the end of the 3 years. $ … [3]

3 marks

Mark scheme: 17 646 or 646.1[3…] 3 M2 for 600 × 1.0253 oe or M1 for 600 × 1.0252 oe If zero scored, SC2 for 46.1 or 46.1[3…]

This question in 0580/13 May/June 2017

10 Write 55 g as a percentage of 2.2 kg. … % [2]

2 marks

Mark scheme: 10 2.5 2 M1 for 2200 or 0.055 seen or SC1 for answer figs 25

This question in 0580/12 Oct/Nov 2017

2 Work out 16% of $525. $ … [1]

1 marks

Mark scheme: 2 84 1

This question in 0580/13 Oct/Nov 2017

12 Adilla invests $1200 at a rate of 2.6% per year compound interest. Calculate the value of her investment at the end of 2 years. $ … [2]

2 marks

Mark scheme: 12 1263.21 2 2  100 + 2.6  M1 for 1200 ×   oe  100 

This question in 0580/13 Oct/Nov 2017

19 Friedrich borrows $1200 for 3 years at a rate of 5.6% per year compound interest. Work out the total amount he pays back at the end of the 3 years. $ … [3]

3 marks

Mark scheme: 19 1410 or 1413 or 1413.1[0 … ] 3 3  5.6  M2 for 1200  1 +  oe  100   5.6  2 or M1 for 1200  1 +  oe  100 

This question in 0580/12 May/June 2018

9 Increase $22 by 15%. $ … [2]

2 marks

Mark scheme: 9 25.3[0] 2 15 M1 for 22 × oe or better 100

This question in 0580/13 May/June 2018

1 Work out 8% of 140. … [1]

1 marks

Mark scheme: Question Answer Marks Partial Marks 1 11.2 oe 1

This question in 0580/11 Oct/Nov 2018

3 Work out $1.45 as a percentage of $72.50 . … % [1]

1 marks

Mark scheme: 3 2 1

This question in 0580/13 Oct/Nov 2018

25 Jo invests $5000 at a rate of 2% per year compound interest. Calculate the value of her investment at the end of 3 years. $ … [3]

3 marks

Mark scheme: 25 5306.04 3 3  2  M2 for 5000 ×  1 +  oe  100   2  2 or M1 for 5000 ×  1 +  oe  100  If 0 scored SC1 for 306.04

This question in 0580/13 Oct/Nov 2018

22 The number of passengers on a train increases from 63 to 77. Calculate the percentage increase. … % [3]

3 marks

Mark scheme: 22 2 3 77 − 22 or 22.2 or 22.22... M2 for 63[× 100] oe or 9 63 77 × 100 [– 100] oe 63 77 or M1 for oe 63

This question in 0580/12 Feb/March 2019

2 Work out $1.20 as a percentage of $16. … % [1]

1 marks

Mark scheme: 2 7.5 oe 1

This question in 0580/11 May/June 2019

4 The probability that Tommy has his calculator for his mathematics lesson is 0.4 . There are 120 mathematics lessons in one year. Work out an estimate of the number of mathematics lessons in one year that Tommy has his calculator. … [1]

1 marks

Mark scheme: 4 48 1

This question in 0580/12 May/June 2019

19 Harry invests $800 for 2 years at a rate of 3% per year compound interest. Calculate the amount of interest he receives at the end of the 2 years. $ … [3]

3 marks

Mark scheme: 19 48.72 3 2  3  M1 for 800 1 + oe    100  A1 for 848.72

This question in 0580/13 May/June 2019

3 Work out 5% of $25. $ … [1]

1 marks

Mark scheme: 3 1.25 1

This question in 0580/11 Oct/Nov 2019

15 Paula invests $600 at a rate of r % per year simple interest. At the end of 10 years, the total interest earned is $90. Find the value of r. r = … [2]

2 marks

Mark scheme: 15 1.5 2 600 × r × 10 M1 for = 90 oe or better 100

This question in 0580/11 Oct/Nov 2019

18 Javier invests $750 for 3 years at a rate of 1.8% per year compound interest. Calculate the value of his investment at the end of the 3 years. $ … [3]

3 marks

Mark scheme: 18 791 or 791.2…. nfww 3 3 8.1  M2 for 750 × + 1  oe  100  2 8.1  or M1 for 750 × + 1  oe  100 

This question in 0580/12 Oct/Nov 2019

9 The price of a television is $560. This price is reduced by 18% in a sale. Work out the sale price. $ … [2]

2 marks

Mark scheme: 9 459.2[0] 2 M1 for 560 × (1 −18 ) oe 100

This question in 0580/13 Oct/Nov 2019

21 Lucia invests $5000 at a rate of 4.5% per year compound interest. Calculate the value of her investment at the end of 7 years. $ … [2]

2 marks

Mark scheme: 21 2 7 6800 or 6804 or M1 for 5000+ 1 5.4  6803.3 to 6803.31  100 

This question in 0580/11 May/June 2020

19 Roberto buys a toy for $5.00 . He then sells it for $4.60 . Calculate his percentage loss. … % [2]

2 marks

Mark scheme: 19 8 2 5 − 4.60 4.60 M1 for [×100] or × 100 5 5

This question in 0580/12 May/June 2020

17 Trina invests $16 000 at a rate of 5% per year compound interest. Work out the value of her investment at the end of 4 years. $ … [2]

2 marks

Mark scheme: 17 19 448.1[0] final answer 2 M1 for 16 000 (1 + 1005 )4 oe

This question in 0580/11 Oct/Nov 2020

13 Increase 42 by 16%. … [2]

2 marks

Mark scheme: 13 48.72 2 16 M1 for × 42 oe or better 100

This question in 0580/12 Oct/Nov 2020

13 Saanvi makes some biscuits. 5 She sells of the biscuits. 13 She now has 96 biscuits left. Work out the total number of biscuits Saanvi makes. … [3]

3 marks

Mark scheme: 13 156 3 8 M1 for 96 = x 13 M1 for 96 × 13 = 8x or better

This question in 0580/12 Feb/March 2021

18 Annie invests $8300 at a rate of 5.6% per year compound interest. Calculate the value of her investment at the end of 6 years. $ … [2]

2 marks

Mark scheme: 18 11 500, 11 510, 11 509, 11 509.6[…] 2 6  5.6  M1 for 8300 ×  1 +   100 

This question in 0580/11 May/June 2021

9 20 15 Number of students 10 5 0 1 to 20 21 to 40 41 to 60 61 to 80 81 to 100 Marks The bar chart shows the marks scored by a group of 55 students in an examination. Work out the percentage of this group of students who scored marks from 21 to 80. … % [3]

3 marks

Mark scheme: 9 81.8 or 81.81 to 81.82 3 M2 for their12 + their15 + their18 [× 100] oe 55 or M1 for their 12 + their 15 + their 18 oe

This question in 0580/12 May/June 2021

10 Chung invests $2460 at a rate of 3.5% per year simple interest. Calculate the total amount of his investment at the end of 4 years. $ … [3]

3 marks

Mark scheme: 10 2804.4[0] final answer 3 2460 × 3.5 × 4 M2 for + 2460 oe 100 2460 × 3.5 × 4 or M1 for oe 100

This question in 0580/11 Oct/Nov 2021

22 In a group of 650 people, 117 are left-handed. Find the expected number of left-handed people in a group of 5000 people. … [2]

2 marks

Mark scheme: 22 900 2 117 M1 for [5000 ×] 650

This question in 0580/12 Oct/Nov 2021

1 Write 1 (a) as a percentage, 2 … % [1] (b) 0.7 as a fraction, … [1] 11 (c) as a decimal. 20 … [1]

3 marks

Mark scheme: Question Answer Marks Partial Marks 1(a) 50 1 1(b) 7 1 or equivalent fraction 10 1(c) 0.55 cao 1

This question in 0580/13 Oct/Nov 2021

10 Write 26 g as a percentage of 208 g. … % [1]

1 marks

Mark scheme: 10 12.5 1

This question in 0580/13 Oct/Nov 2021

18 Marek buys a computer for $420. He sells it at a loss of 15%. Calculate the selling price of this computer. $ … [2]

2 marks

Mark scheme: 18 357 2  15  M1 for  1 −  × 420 oe  100  or B1 for 63

This question in 0580/13 Oct/Nov 2021

12 The price of a computer is $520. This price is reduced by 15% in a sale. Work out the sale price. $ … [2]

2 marks

Mark scheme: 12 442 2 100 − 15 M1 for  520 oe 100 or B1 for 78

This question in 0580/11 Oct/Nov 2022

19 Qianna invests $3000 at a rate of 4% per year compound interest. Calculate the value of her investment at the end of 6 years. $ … [2]

2 marks

Mark scheme: 19 3800 or 3795 or 3796 or 3795.9… 2 6  4  M1 for 3000 × 1 + oe    100 

This question in 0580/12 Feb/March 2023

22 Vanessa invests $8500 at a rate of 3.5% per year compound interest. Calculate the value of her investment at the end of 6 years. Give your answer correct to the nearest dollar. $ … [3]

3 marks

Mark scheme: 22 10449 cao 3 B2 for 10400, 10440, 10450, 10448, 10448.7, 10448.67…  3.5  6 or M1 for 8500 [×] 1  oe    100  B1 for rounding their decimal answer correct to the nearest dollar

This question in 0580/13 May/June 2023

15 Shubhu invests $750 in a savings account for 5 years. The account pays simple interest at a rate of 1.8% per year. Calculate the total interest she earns during the 5 years. $ … [2]

2 marks

Mark scheme: 15 67.5[0] 2 750  1.8  5  M1 for oe 100

This question in 0580/13 Oct/Nov 2023

16 The price of a game increases from $48 to $56.40 . Calculate the percentage increase in the price. … % [2]

2 marks

Mark scheme: 16 17.5 2 56.40 M1 for ( − 1) [× 100] oe or 48 56.40  48 [×100] 48 56.40 or  100 [− 100] 48

This question in 0580/13 May/June 2024

9 Edith invests $3000 in a savings account. The account pays simple interest at a rate of 2.6% per year. Calculate the total interest earned during the 3 years. $ … [2]

2 marks

Mark scheme: 9 234 2 3000  2.6 3 M1 for 100

This question in 0580/11 Oct/Nov 2024

14 Write 34 as a percentage of 80. … % [1]

1 marks

Mark scheme: 14 42.5 1

This question in 0580/11 Oct/Nov 2024

20 Josh buys a car for $7800 and sells it for $5265. Calculate his percentage loss. … % [2]

2 marks

Mark scheme: 20 32.5 2 7800 − 5265 M1 for 100  oe 7800  7800 − 5265  or  1 −   100  oe  7800    oe or 100 − 5265  100   7800 

This question in 0580/11 Oct/Nov 2024

16 Dana invests $3600 at a rate of 3.8% per year compound interest. Calculate the value of her investment at the end of 5 years. $ … [2]

2 marks

Mark scheme: 16 4340 or 4338 or 4337.99…. 2 3.8 5 M1 for 3600 (1 + ) oe 100

This question in 0580/12 Oct/Nov 2024

22 Mia invests $1270 for 5 years at a rate of 2.1% per year compound interest. Calculate the value of her investment at the end of the 5 years. $ … [2]

2 marks

Mark scheme: 22 1409.07 or 1409.069… 1410, 1409, 2 5  2.1  1409.1 M1 for 1270   1 +  oe  100 

This question in 0580/13 Oct/Nov 2024

2 Write 0.07 (a) as a percentage … % [1] (b) as a fraction … [1] (c) in standard form. … [1]

3 marks

Mark scheme: 2(a) 7 1 2(b) 7 1 100 2(c) 7  10− 2 1

This question in 0580/12 Feb/March 2025

10 A shape is drawn on a 1 cm 2 grid. (a) Find the area of the shape. … cm2 [1] (b) On the grid, shade 50% of the shape. [1]

2 marks

Mark scheme: 10(a) 20 1 10(b) 10 squares shaded 1

This question in 0580/12 Feb/March 2025

2 Write three-quarters as (a) a decimal … [1] (b) a percentage. … % [1]

2 marks

Mark scheme: 2(a) 0.75 1 2(b) 75 1

This question in 0580/12 May/June 2025

16 On Monday the cost of a concert ticket is $x. On Tuesday the cost of a ticket for the same concert is 20% more than the cost on Monday. Jack buys 4 tickets on Monday and 5 tickets on Tuesday. Jack pays $270 in total. Work out the value of x. x = … [3]

3 marks

Mark scheme: 16 27 3 B2 for 10 or 10x  20  or M1 for [5 ×]  x + x  oe  100 

This question in 0580/13 May/June 2025

9 (a) Shade 3of this grid. 4 [1] (b) Work out 15% of 80. … [2]

3 marks

Mark scheme: 9(a) 15 rectangles shaded 1 9(b) 12 2 15 M1 for full correct method e.g. 80  100 oe

This question in 0580/11 Oct/Nov 2025

11 The stem-and-leaf diagram shows the number of customers entering a shop each day for 20 days. 3 0 1 5 9 4 1 4 6 8 9 5 1 3 4 4 4 7 8 6 3 6 6 7 2 Key : 3 0 represents 30 customers (a) Find the range. … [1] (b) Find the mode. … [1] (c) Work out the percentage of these 20 days when more than 55 customers enter the shop. … % [2] (d) (i) Find the median. … [1] (ii) On the next day 48 customers enter the shop. Will the median increase or decrease? Give a reason for your answer. … because … … [1]

6 marks

Mark scheme: 11(a) 42 1 11(b) 54 1 11(c) 30 2 6 B1 for oe 20 11(d)(i) 52 1 11(d)(ii) Decrease AND acceptable reason e.g. 48 1 is below the median

This question in 0580/12 Oct/Nov 2025

14 Victoria invests $2000 at a rate of 5% per year simple interest. Calculate the value of her investment after 4 years. $ … [3]

3 marks

Mark scheme: 14 2400 nfww 3 B2 for 400 nfww 5 or M2 for 2000  × 4 + 2000 100 5 or M1 for 2000  [× 4] 100

This question in 0580/13 Oct/Nov 2025