TopicalMathematics 0580Transformations and vectorsVectors in two dimensionsPaper 1

Vectors in two dimensions — Paper 1 · IGCSE Mathematics 0580

E7.2· 69 questions · 174 marks · 209 min · 2004–2024· Structured questions

Every Cambridge IGCSE Mathematics Paper 1 question on vectors in two dimensions, laid out as 37 A4 pages with the mark scheme below. Nothing is left out. Free to read, no account.

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Questions37 pages

Question 1:  3   – 1 a =   and b =    4   2  Work out a – 2b.       Answer [2]Question 2:  2   3  p =   and q =   .  −3   1  (a) Write p + q as a column vector.     Answer (a) p + q =   [2]     (b) The point…1 / 37
Question 3: − 1  For 15 =   and = 3 . Examiner's  4  Use (a) Write as a column vector.   Answer(a) =   [1]   (b) Make two statements abou…Question 4: Write the following as single vectors. For Examiner's Use  2   1   3  (a)   +   −   − 1  3   0        Answer(a)…2 / 37
Question 5: For Examiner's y Use 10 C 8 6 4 B 2 A x 0 2 4 6 8 10 Points A, B and C are shown on the grid. (a) Plot the point D on the grid above so tha…3 / 37
Question 6: For y Examiner's G Use 5 4 3 2 F 1 x –3 –2 –1 0 1 2 3 4 5 –1 –2 –3 –4 The points F and G are shown on the grid. (a) Write down the co-ordin…4 / 37
Question 7: ForFor y Examiner'sExaminer's G UseUse 5 4 3 2 F 1 x –3 –2 –1 0 1 2 3 4 5 –1 –2 –3 –4 The points F and G are shown on the grid. (a) Write d…Question 8:  3  − 1  0  d =   e =   f =    −5   4   7  Calculate (a) d – e,   Answer(a)   [2]     (b) 4f.   Answer(b)…5 / 37
Question 9: 6  − 3   2  19 f =  g =   h =   0  6   −2  Calculate (a) 3f,           Answer(a)   [2] (b) g – h.      …Question 10: Flags A and B are shown on the grid. For Examiner's y Use 6 5 A 4 3 2 1 x –6 –5 –4 –3 –2 –1 0 1 2 3 4 5 6 –1 –2 –3 –4 B –5 –6 (a) Describe …6 / 37
Question 11: For  3  − 5  Examiner's AB =   AC =   Use  −3   0  (a) Calculate AB + 3AC.   Answer(a) [2]     (b) Write down .   Ans…7 / 37
Question 12: y 7 C 6 B 5 4 3 A 2 1 x 0 1 2 3 4 5 6 7 The diagram shows three points, A(1, 2), B(7, 5) and C(5, 7). (a) Write as column vectors (i) AC, …8 / 37
Question 13: For y Examiner's Use 4 3 2 B 1 x –3 –2 –1 0 1 2 3 4 5 6 7 A –1 –2 –3 (a) Write down the vector .     Answer(a)   [1]     − 3  (…9 / 37
Question 14:  3 − 5  12 =   and =    −1  4  (a) Find . You may use the grid below to help if you wish.     Answer(a) =   [2]   …Question 15: For Examiner's Use A S The diagram shows the map of part of an orienteering course. Sanji runs from the start, S, to the point A. Write as …10 / 37
Question 16: For y Examiner's Use 7 6 5 4 3 A 2 1 x –5 –4 –3 –2 –1 0 1 2 3 4 5 –1 –2 –3 B –4 (a) Write down the co-ordinates of point A. Answer(a) ( , )…Question 17: Work out For Examiner's Use  5   6  (a)   −   ,  3   −2      Answer(a)   [1]      3 (b) 5   .  −4     …11 / 37
Question 18: − For Examiner's16 p =   q =   r =    9  − 5   3  Use Calculate (a) 7p ,     Answer(a)   [2]     (b) q – r .  …Question 19:  4   − 2  7 a =   b =    −1   − 3  Work out a + 3b.     Answer   [2]    12 / 37
Question 20: Write each of the following as a single vector. 6 -4 (a) + e 1 o e 2 o Answer(a) [1] e o 2 (b) 4 3 e- o Answer(b) [1] e o _________________…Question 21: 4 -5 a = b = e 7 o e 2 o Write each of the following as a single vector. (a) 6a Answer(a) [1] e o (b) a + b Answer(b) [1] e o _____________…13 / 37
Question 22: For Examiner′s y Use 6 P 5 4 3 2 1 x –4 –3 –2 –1 0 1 2 3 4 5 6 7 8 –1 –2 Q –3 –4 The points P and Q are marked on the grid. (a) Work out th…Question 23: - 1 2 p = q = - 2 4 e o e o Work out p + q. Answer [1] f p ________________________________________________________________________________…14 / 37
Question 24: - 1 7 a = b = e- 3 o e 5 o Work out a – 2b. Answer [2] f p_________________________________________________________________________________…Question 25: - 3 2 a = b = 4 e o e 6 o Write each of the following as a single vector. (a) 2a Answer(a) [1] f p (b) a – b Answer(b) [1] f p ____________…15 / 37
Question 26: y 7 6 5 4 A 3 2 1 x –7 –6 –5 –4 –3 –2 –1 0 1 2 3 4 5 –1 –2 –3 3 Draw the image of triangle A after a translation by the vector [2] 4 e- o. …Question 27: 9 The point P has co-ordinates (2, –5) and = e- 7 o. (a) Write down the co-ordinates of Q. Answer(a) (...................... , ............…16 / 37
Question 28: 3 - 8 a = b = 5 e o e 7 o Write each of the following as a single vector. (a) 3a Answer(a) [1] f p (b) a – b Answer(b) [1] f p ____________…17 / 37
Question 29: y 6 A 5 4 B 3 2 1 x 0 1 2 3 4 5 6 7 8 (a) Write down the co-ordinates of A. Answer(a) (...................... , ......................) [1]…Question 30: - 1 6 p = q = 2 3 o e- o e Work out 3p – q. Answer [2] f p ________________________________________________________________________________…18 / 37
Question 31: y 4 3 2 A 1 x –4 –3 –2 –1 0 1 2 3 4 5 –1 –2 –3 2 Draw the image of shape A after a translation by the vector [2] e - 3 o.__________________…Question 32: (a) y 4 3 2 A 1 x –4 –3 –2 –1 0 1 2 3 4 –1 –2 B –3 –4 Points A and B are shown on the grid. Write AB as a column vector. Answer(a) AB = [1]…19 / 37
Question 33: y 4 G 3 2 1 x 0 –4 –3 –2 –1 1 2 3 4 –1 –2 F –3 –4 Points F and G are marked on the grid. (a) Write FG as a column vector. FG = [1] f p - 5 …Question 34: Work out. - 2 - 4 (a) + 3 7 f- p f p [1] e o 2 (b) 5 8 f- p [1] e o20 / 37
Question 35: - 3 15 (a) p = q = 2 e - o e 0 o Work out (i) 3p, [1] f p (ii) p – q. [1] f p (b) B 3 Point B is marked on the grid and AB = e - 2 o. On th…21 / 37
Question 36: -2 8 (a) Write 3 as a single vector. e 1 o [1] f p (b) y 4 2 x –4 –2 0 2 4 –2 A –4 -7 Point A is marked on the grid and AB = . e 4 o On the…Question 37: - 2 7 a = b = c - 6 m c 4 m Work out 2a – b. [2] f p22 / 37
Question 38: y 6 5 A 4 3 2 1 x –6 –5 –4 –3 –2 –1 0 1 2 3 4 5 6 –1 –2 B –3 –4 –5 –6 (a) Write down the co-ordinates of point A. ( .......................…23 / 37
Question 39: 2 6 m = n = c- 7m c 6 m Work out (a) 3m, [1] f p (b) m – n. [1] f pQuestion 40: (a) Work out. 5 - 3 + c - 1 m c 2 m [1] f p (b) A is the point (3, 6) and B is the point (5, 10). Work out AB. AB = [1] f p 1 (c) C is the …24 / 37
Question 41: (a) Work out. 3 1 + c- 2 m c- 1m [1] f p (b) y 10 9 A 8 7 6 B 5 4 3 2 1 x 0 1 2 3 4 5 6 7 8 9 10 Points A and B are marked on the grid. - 4…Question 42: 5 - 3 a = b = c- 1m c- 4m Write a + 2b as a single vector. [2] f p25 / 37
Question 43: 13 (a) GH = c- 4 m Find (i) 5 GH , [1] f p (ii) HG. [1] f p 6 2 8 (b) + = c 7 m c y m c 3 m Find the value of y. y = ......................…Question 44: 4 8 s = t = f- 1p f 2 p Work out 5s – t. [2] f pQuestion 45: 2 - 3 g = h = c 5 m c 4 m Write as a single vector (a) g + h, [1] f p (b) -h. [1] f p26 / 37
Question 46: 5 - 7 a = b = c- 2m c- 3m Work out a + 3b. [2] f pQuestion 47: Work out. 2 (a) 6 c- 1m [1] f p 5 2 (b) - c- 3m c4m [1] f p27 / 37
Question 48: y 8 7 6 B 5 4 A 3 2 1 0 x –5 –4 –3 –2 –1 1 2 3 4 5 6 –1 –2 –3 –4 (a) Write down the co-ordinates of point A. ( ................. , ........…28 / 37
Question 49: - 5 0 e = f = e 4o e6o Write as a single vector (a) 3e, [1] f p (b) f - e . [1] f pQuestion 50: Work out. 4 1 (a) - e-2o e5o [1] f p 3 (b) 6 e0o [1] f pQuestion 51: 1 11 p = q = e0o e6o Work out 2p + 3q . [2] f p29 / 37
Question 52: Work out. - 3 2 (a) + f 5p f - 4p [1] f p 6 1 (b) - f2p f5p [1] f p 2 (c) 4 f - 5p [1] f pQuestion 53: Point A has coordinates (6, 4) and point B has coordinates (2, 7). Write AB as a column vector. AB = [1] f p30 / 37
Question 54: y 4 3 2 Q 1 – 4 – 3 – 2 – 1 0 1 2 3 4 x – 1 P – 2 – 3 – 4 (a) Write PQ as a column vector. [1] f p (b) Write 3PQ as a single vector. [1] f p31 / 37
Question 55: y 4 B 3 2 A C 1 x – 4 – 3 – 2 – 1 0 1 2 3 4 – 1 – 2 – 3 – 4 Points A, B and C are shown on the grid. (a) Write down the coordinates of poin…Question 56: Work out. 6 8 (a) + e- 5o e- 1o [1] f p - 4 (b) 3 e 7o [1] f p32 / 37
Question 57: - 2 7 a = b = e- 7o e 6o Work out a - b . [1] f pQuestion 58: 5 10 (a) a = b = e - 4 o e2o Work out. (i) 8b [1] f p (ii) a – b [1] f p 5 (b) Point L has coordinates ( - 3, 6 ) and LM = e- 2o. Find the …Question 59: Work out. 3 - 5 (a) + e- 2o e 7o [1] f p 3 (b) 5 e- 1o [1] f p33 / 37
Question 60: Points A and B are plotted on the grid. y 4 3 B 2 1 – 3 – 2 – 1 0 1 2 3 x – 1 A – 2 – 3 (a) Write down the coordinates of point B. ( ......…Question 61: - 1 10 p = q = e8o e 4o Find (a) p - q , [1] f p (b) 6p. [1] f p34 / 37
Question 62: The grid shows point P and point R. y 5 P 4 3 2 1 – 5 – 4 – 3 – 2 – 1 0 1 2 3 4 5 x – 1 – 2 – 3 R – 4 – 5 (a) Write down the coordinates of…Question 63: - 1 2 8 v = y = e 3o e5o Find (a) v - y [1] f p (b) 2 v . [1] f p35 / 37
Question 64: 3 - 2 a = b = e 7 o e 5o Work out a - 2 b . [2] f pQuestion 65: - 12 15 F is the point ( 1, - 4 ) , FG = and GH = e- 3o e 35o. Find (a) 3FG [1] f p (b) FG + GH [1] f p (c) the coordinates of the point G.…Question 66: - 6 13 10 a = b = c = e9o e 1o e- 2o Work out. (a) a + b [1] f p (b) 3c [1] f p36 / 37
Question 67: y 5 B 4 3 2 A 1 x – 4 –3 –2 –1 0 1 2 3 4 5 6 7 8 Write AB as a column vector. AB = [1] f pQuestion 68: 6 10 a = b = e- 7o e- 7o Work out a - b . [1] f pQuestion 69: y 6 5 4 3 B 2 1 0 x 1 2 3 4 5 6 7 8 3 AB = e o - 2 Mark point A on the grid. [1]37 / 37

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Mathematics 0580 · Vectors in two dimensions — Paper 1

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Another paper, or another topic

All of Transformations and vectors

Questions as text

Q1 ·  3   – 1 a =   and b =    4   2  Work out a – 2b 0580/11 Oct/Nov 2004

8  3   – 1 a =   and b =    4   2  Work out a – 2b.       Answer [2]

2 marks

Mark scheme: 8  5  1 + 1 One mark each component. If   only number 5 in bracket allow   0 1 mark. − 2   2  If 0 scored SC1 for   or    4   −4   0  seen, or    5  Ignore a line between Components

This question in 0580/11 Oct/Nov 2004

Q2 ·  2   3  p =   and q =   0580/11 Oct/Nov 2005

11  2   3  p =   and q =   .  −3   1  (a) Write p + q as a column vector.     Answer (a) p + q =   [2]     (b) The point O is marked on the grid below. Draw the vector where = p. y 3 2 1 x –3 –2 –1 O 1 2 3 –1 –2 –3 [1]

3 marks

Mark scheme: 11 (a)  5  2 1 mark for each correct component.    −2  (b) Correct Vector Drawn 1

This question in 0580/11 Oct/Nov 2005

Q3 · − 1  For 15 =   and = 3 0580/11 May/June 2006

− 1  For 15 =   and = 3 . Examiner's  4  Use (a) Write as a column vector.   Answer(a) =   [1]   (b) Make two statements about the relationship between the lines AB and CD. Statement 1 Statement 2 [2]

3 marks

Mark scheme: 15 (a) − 3  1    12  (b) Parallel oe. 1 CD is 3 times as long as AB oe. 1

This question in 0580/11 May/June 2006

Q4 · Write the following as single vectors 0580/11 Oct/Nov 2006

21 Write the following as single vectors. For Examiner's Use  2   1   3  (a)   +   −   − 1  3   0        Answer(a)   [2]      5  (b) 6    −4    Answer(b)   [2]    

4 marks

Mark scheme: 21 Ignore ‘fraction’ lines in (a) and (b)  0  Allow coordinate form (a)   Final ans 2 1 mark for each correct component.  4   30  (b)   Final ans 2 1 mark for each correct component.  −24 

This question in 0580/11 Oct/Nov 2006

Q5 · For Examiner's y Use 10 C 8 6 4 B 2 A x 0 2 4 6 8 10 Points A, B and C are shown on the… 0580/11 May/June 2009

17 For Examiner's y Use 10 C 8 6 4 B 2 A x 0 2 4 6 8 10 Points A, B and C are shown on the grid. (a) Plot the point D on the grid above so that ABCD is a rhombus. [1] (b) Write BD as a column vector.   Answer(b) BD =   [2]     (c) M is the mid-point of AC. Write as a column vector.   Answer(c) =   [1]    

4 marks

Mark scheme: 17 (a) D plotted at (3, 7) 1 Within 1 mm by eye. − 4  (b)   2ft 1 mark for each component  4  −1 if in working, no brackets  3  (c)   1cao SC1 Both (b) and (c) correct but written as  3  coordinates.

This question in 0580/11 May/June 2009

Q6 · For y Examiner's G Use 5 4 3 2 F 1 x –3 –2 –1 0 1 2 3 4 5 –1 –2 –3 –4 The points F and G… 0580/11 Oct/Nov 2009

13 For y Examiner's G Use 5 4 3 2 F 1 x –3 –2 –1 0 1 2 3 4 5 –1 –2 –3 –4 The points F and G are shown on the grid. (a) Write down the co-ordinates of the point F. Answer(a)( , ) [1] (b) Write as a column vector. Answer(b) = ( ) [1]  _2  (c) GH =   . Mark and label the point H on the grid. [1]  _7 

3 marks

Mark scheme: 13 (a) (–2, 1) 1 All coordinates/components reversed.  4  ie (a) (1, −2), (b)   , (c) (−3, 3)  6   6  (b)   1 mark 0, 0, SC1  4  (c) H at (2, –2) 1

This question in 0580/11 Oct/Nov 2009

Q7 · ForFor y Examiner'sExaminer's G UseUse 5 4 3 2 F 1 x –3 –2 –1 0 1 2 3 4 5 –1 –2 –3 –4 The… 0580/12 Oct/Nov 2009

13 ForFor y Examiner'sExaminer's G UseUse 5 4 3 2 F 1 x –3 –2 –1 0 1 2 3 4 5 –1 –2 –3 –4 The points F and G are shown on the grid. (a) Write down the co-ordinates of the point F. Answer(a)( , ) [1] (b) Write as a column vector. Answer(b) = ( ) [1]  _5  (c) =   . Mark and label the point H on the grid. [1]  _3 

3 marks

Mark scheme: 13 (a) (–2, 1) 1 All coordinates/components reversed.  4  ie (a) (1, −2), (b)   , (c) (1, 0)  6   6  (b)   1 mark 0, 0, SC1  4  (c) H at (–1, 2) 1

This question in 0580/12 Oct/Nov 2009

Q8 ·  3  − 1  0  d =   e =   f =    −5   4   7  Calculate (a) d – e, … 0580/11 May/June 2010

15  3  − 1  0  d =   e =   f =    −5   4   7  Calculate (a) d – e,   Answer(a)   [2]     (b) 4f.   Answer(b)   [2]    

4 marks

Mark scheme: 15 (a)  4  1, 1  −9  (b)  0  1, 1  28 

This question in 0580/11 May/June 2010

Q9 · 6  − 3   2  19 f =  g =   h =   0  6   −2  Calculate (a) 3f,     … 0580/13 May/June 2010

6  − 3   2  19 f =  g =   h =   0  6   −2  Calculate (a) 3f,           Answer(a)   [2] (b) g – h.           Answer(b)   [2]

4 marks

Mark scheme:  18  19 (a)  0  1, 1 − 5  (b)  8  1, 1

This question in 0580/13 May/June 2010

Q10 · Flags A and B are shown on the grid 0580/12 Oct/Nov 2010

16 Flags A and B are shown on the grid. For Examiner's y Use 6 5 A 4 3 2 1 x –6 –5 –4 –3 –2 –1 0 1 2 3 4 5 6 –1 –2 –3 –4 B –5 –6 (a) Describe fully the single transformation which maps flag A onto flag B. Answer(a) [3]  5  (b) On the grid, draw the translation of flag A by the vector   . [2]  −3 

5 marks

Mark scheme: 16 (a) Rotation or enlargement 1 Two transformations named, zero for (a) 180° (SF) −1 1 Independent (about or centre) origin oe 1 Independent (b) Correct translation 2 B1 for 5 right or 3 down applied 5 right and 3 down 12 

This question in 0580/12 Oct/Nov 2010

Q11 · For  3  − 5  Examiner's AB =   AC =   Use  −3   0  (a) Calculate AB + 3AC 0580/12 Oct/Nov 2010

17 For  3  − 5  Examiner's AB =   AC =   Use  −3   0  (a) Calculate AB + 3AC.   Answer(a) [2]     (b) Write down .   Answer(b) = [1]     (c) AC is drawn on the grid below. C A (i) On the grid, draw AB . [1] (ii) Write down the obtuse angle between AB and AC. Answer(c)(ii) [1] Question 18 is printed on the next page.

5 marks

Mark scheme: 17 (a)  − 12  2 B1 for 1 component correct.  − 3  (b) − 3   3  1 (c) (i) Vector AB drawn 1 Diagonal line, ignore working lines (ii) 134° to 136° 1 x x

This question in 0580/12 Oct/Nov 2010

Q12 · Y 7 C 6 B 5 4 3 A 2 1 x 0 1 2 3 4 5 6 7 The diagram shows three points, A(1, 2), B(7, 5)… 0580/13 Oct/Nov 2010

18 y 7 C 6 B 5 4 3 A 2 1 x 0 1 2 3 4 5 6 7 The diagram shows three points, A(1, 2), B(7, 5) and C(5, 7). (a) Write as column vectors (i) AC,     Answer(a)(i) AC =   [1]     (ii) CB.     Answer(a)(ii) CB =   [1]     (b) Use two of the symbols +, –, = in the spaces to make a correct statement. AC CB AB [1]

3 marks

Mark scheme:  4  18 (a) (i)  5  1  2  (ii)  −2  1 (b) (AC) + (CB) = (AB) 1 1 1

This question in 0580/13 Oct/Nov 2010

Q13 · For y Examiner's Use 4 3 2 B 1 x –3 –2 –1 0 1 2 3 4 5 6 7 A –1 –2 –3 (a) Write down the… 0580/11 May/June 2011

17 For y Examiner's Use 4 3 2 B 1 x –3 –2 –1 0 1 2 3 4 5 6 7 A –1 –2 –3 (a) Write down the vector .     Answer(a)   [1]     − 3  (b) =    1  Mark the point C on the grid. [1] (c) Work out − 3  7  (i)   +   ,  1   −4      Answer(c)(i)   [1]     − 3 (ii) 4 ×   .  1      Answer(c)(ii)   [1]    

4 marks

Mark scheme:   17 (a)   1  2  (b) C marked at (1, 2) 1  4  (c)   1  −3  − 12  (d)   1  4 

This question in 0580/11 May/June 2011

Q14 ·  3 − 5  12 =   and =    −1  4  (a) Find 0580/12 May/June 2011

 3 − 5  12 =   and =    −1  4  (a) Find . You may use the grid below to help if you wish.     Answer(a) =   [2]     (b) Work out .     Answer(b) =   [1]    

3 marks

Mark scheme: 12 − 2  1,1 B1 for 1 correct component. (a)   SC1 for both correct but written as coordinates as  3  the answer.  2  1ft ft their (a) with signs reversed. (b)   Not a strict follow through.  −3 

This question in 0580/12 May/June 2011

Q15 · For Examiner's Use A S The diagram shows the map of part of an orienteering course 0580/11 Oct/Nov 2011

1 For Examiner's Use A S The diagram shows the map of part of an orienteering course. Sanji runs from the start, S, to the point A. Write as a column vector.     Answer   [1]    

1 marks

Mark scheme: Qu. Answers Mark Part Marks 1 −3  1    4  4

This question in 0580/11 Oct/Nov 2011

Q16 · For y Examiner's Use 7 6 5 4 3 A 2 1 x –5 –4 –3 –2 –1 0 1 2 3 4 5 –1 –2 –3 B –4 (a) Write… 0580/11 May/June 2012

17 For y Examiner's Use 7 6 5 4 3 A 2 1 x –5 –4 –3 –2 –1 0 1 2 3 4 5 –1 –2 –3 B –4 (a) Write down the co-ordinates of point A. Answer(a) ( , ) [1] (b) Write as a column vector.     Answer(b) =   [1]      2  (c) =    3  Write down the co-ordinates of C. Answer(c) ( , ) [1]

3 marks

Mark scheme: 17 (a) (–1, 2) 1  4  (b)   1  −5  (c) 1 (1, 5)

This question in 0580/11 May/June 2012

Q17 · Work out For Examiner's Use  5   6  (a)   −   ,  3   −2     … 0580/13 May/June 2012

8 Work out For Examiner's Use  5   6  (a)   −   ,  3   −2      Answer(a)   [1]      3 (b) 5   .  −4      Answer(b)   [1]    

2 marks

Mark scheme: 8 (a) − 1  1    5  (b)  15  1    −20 

This question in 0580/13 May/June 2012

Q18 · − For Examiner's16 p =   q =   r =    9  − 5   3  Use Calculate (a) 7p… 0580/11 Oct/Nov 2012

− For Examiner's16 p =   q =   r =    9  − 5   3  Use Calculate (a) 7p ,     Answer(a)   [2]     (b) q – r .     Answer(b)   [2]    

4 marks

Mark scheme:  (a)  1, 116  63  7   (b)  1, 1   −8

This question in 0580/11 Oct/Nov 2012

Q19 ·  4   − 2  7 a =   b =    −1   − 3  Work out a + 3b 0580/12 Oct/Nov 2012

 4   − 2  7 a =   b =    −1   − 3  Work out a + 3b.     Answer   [2]    

2 marks

Mark scheme: 7  −2   2  − 6   −10 B1 for each correct component or [3b] =   seen  − 9 

This question in 0580/12 Oct/Nov 2012

Q20 · Write each of the following as a single vector 0580/11 May/June 2013

5 Write each of the following as a single vector. 6 -4 (a) + e 1 o e 2 o Answer(a) [1] e o 2 (b) 4 3 e- o Answer(b) [1] e o _____________________________________________________________________________________

2 marks

Mark scheme: 5 (a)  2    1 3    8  (b)   1  −12 

This question in 0580/11 May/June 2013

Q21 · 4 -5 a = b = e 7 o e 2 o Write each of the following as a single vector 0580/12 May/June 2013

10 4 -5 a = b = e 7 o e 2 o Write each of the following as a single vector. (a) 6a Answer(a) [1] e o (b) a + b Answer(b) [1] e o _____________________________________________________________________________________

2 marks

Mark scheme:   10 (a)   1 42   − 1 (b)   1 9  

This question in 0580/12 May/June 2013

Q22 · For Examiner′s y Use 6 P 5 4 3 2 1 x –4 –3 –2 –1 0 1 2 3 4 5 6 7 8 –1 –2 Q –3 –4 The… 0580/13 May/June 2013

12 For Examiner′s y Use 6 P 5 4 3 2 1 x –4 –3 –2 –1 0 1 2 3 4 5 6 7 8 –1 –2 Q –3 –4 The points P and Q are marked on the grid. (a) Work out the vector . Answer(a) = [1] f p - 8 (b) = - 1 e o Find the co-ordinates of the point R. Answer(b) ( … , … ) [1] _____________________________________________________________________________________

2 marks

Mark scheme: 12 (a)  9  [PQ =]   1  −7  (b) (−1 , −3) 1

This question in 0580/13 May/June 2013

Q23 · - 1 2 p = q = - 2 4 e o e o Work out p + q 0580/12 Oct/Nov 2013

3 - 1 2 p = q = - 2 4 e o e o Work out p + q. Answer [1] f p _____________________________________________________________________________________

1 marks

Mark scheme:  2  2   1 2  

This question in 0580/12 Oct/Nov 2013

Q24 · - 1 7 a = b = e- 3 o e 5 o Work out a – 2b 0580/11 May/June 2014

4 - 1 7 a = b = e- 3 o e 5 o Work out a – 2b. Answer [2] f p__________________________________________________________________________________________

2 marks

Mark scheme:   7   2 B1 for each component −13  − 2   2  or for   or   seen  10   −10 

This question in 0580/11 May/June 2014

Q25 · - 3 2 a = b = 4 e o e 6 o Write each of the following as a single vector 0580/13 May/June 2014

9 - 3 2 a = b = 4 e o e 6 o Write each of the following as a single vector. (a) 2a Answer(a) [1] f p (b) a – b Answer(b) [1] f p __________________________________________________________________________________________

2 marks

Mark scheme:  6  9 (a)   1  8   − 5  (b)   1  − 2 

This question in 0580/13 May/June 2014

Q26 · Y 7 6 5 4 A 3 2 1 x –7 –6 –5 –4 –3 –2 –1 0 1 2 3 4 5 –1 –2 –3 3 Draw the image of… 0580/13 May/June 2014

20 y 7 6 5 4 A 3 2 1 x –7 –6 –5 –4 –3 –2 –1 0 1 2 3 4 5 –1 –2 –3 3 Draw the image of triangle A after a translation by the vector [2] 4 e- o. __________________________________________________________________________________________

2 marks

Mark scheme:  k   3 20 Triangle at ( 2, −1) ( 2, 1) ( 1, −2) 2 B1 for translation by   or    −4   k 

This question in 0580/13 May/June 2014

Q27 · 9 The point P has co-ordinates (2, –5) and = e- 7 o 0580/12 Feb/March 2015

6 9 The point P has co-ordinates (2, –5) and = e- 7 o. (a) Write down the co-ordinates of Q. Answer(a) ( … , … ) [1] (b) Write 4 as a column vector. Answer(b) [1] f p __________________________________________________________________________________________

2 marks

Mark scheme: 9 (a) (8, –12) 1  24  (b)   1  −28 

This question in 0580/12 Feb/March 2015

Q28 · 3 - 8 a = b = 5 e o e 7 o Write each of the following as a single vector 0580/11 May/June 2015

8 3 - 8 a = b = 5 e o e 7 o Write each of the following as a single vector. (a) 3a Answer(a) [1] f p (b) a – b Answer(b) [1] f p __________________________________________________________________________________________

2 marks

Mark scheme: 8 (a) 1  9     15  (b) 1  11    −2 

This question in 0580/11 May/June 2015

Q29 · Y 6 A 5 4 B 3 2 1 x 0 1 2 3 4 5 6 7 8 (a) Write down the co-ordinates of A 0580/13 May/June 2015

17 y 6 A 5 4 B 3 2 1 x 0 1 2 3 4 5 6 7 8 (a) Write down the co-ordinates of A. Answer(a) ( … , … ) [1] (b) Write down the vector . Answer(b) = [1] f p (c) Work out. + 6 5 e- 4 2 o e o Answer(c) [1] f p (d) Work out. - 3 6 e 7 o Answer(d) [1] f p __________________________________________________________________________________________

4 marks

Mark scheme: 17 (a) 1, 5 1  5  (b)   1  −2   6  (c)   1  −1 − 18  (d)   1  42 

This question in 0580/13 May/June 2015

Q30 · - 1 6 p = q = 2 3 o e- o e Work out 3p – q 0580/11 Oct/Nov 2015

4 - 1 6 p = q = 2 3 o e- o e Work out 3p – q. Answer [2] f p __________________________________________________________________________________________

2 marks

Mark scheme: 6  13  2  12    B1 for   seen  9   −6   13   j  or B1 for   or   as answer  k   −9 

This question in 0580/11 Oct/Nov 2015

Q31 · Y 4 3 2 A 1 x –4 –3 –2 –1 0 1 2 3 4 5 –1 –2 –3 2 Draw the image of shape A after a… 0580/11 Oct/Nov 2015

7 y 4 3 2 A 1 x –4 –3 –2 –1 0 1 2 3 4 5 –1 –2 –3 2 Draw the image of shape A after a translation by the vector [2] e - 3 o.__________________________________________________________________________________________

2 marks

Mark scheme: 7 Triangle (3, –2), (4, –2), 2 B1 for movement 2 right or 3 down (4, –1) 785

This question in 0580/11 Oct/Nov 2015

Q32 · Y 4 3 2 A 1 x –4 –3 –2 –1 0 1 2 3 4 –1 –2 B –3 –4 Points A and B are shown on the grid 0580/12 Oct/Nov 2015

12 (a) y 4 3 2 A 1 x –4 –3 –2 –1 0 1 2 3 4 –1 –2 B –3 –4 Points A and B are shown on the grid. Write AB as a column vector. Answer(a) AB = [1] f p 5 (b) CD = e - 7 o Write DC as a column vector. Answer(b) DC = [1] f p

2 marks

Mark scheme:  6  12 (a)   1  −3  − 5  1 (b)    7 

This question in 0580/12 Oct/Nov 2015

Q33 · Y 4 G 3 2 1 x 0 –4 –3 –2 –1 1 2 3 4 –1 –2 F –3 –4 Points F and G are marked on the grid 0580/12 Feb/March 2016

14 y 4 G 3 2 1 x 0 –4 –3 –2 –1 1 2 3 4 –1 –2 F –3 –4 Points F and G are marked on the grid. (a) Write FG as a column vector. FG = [1] f p - 5 (b) GH = c- 6m Mark the point H on the grid. [1]

2 marks

Mark scheme:  1  14 (a)   1  5  (b) H marked at (–3,–3) 1 0 9

This question in 0580/12 Feb/March 2016

Question 34 0580/11 May/June 2016

8 Work out. - 2 - 4 (a) + 3 7 f- p f p [1] e o 2 (b) 5 8 f- p [1] e o

2 marks

Mark scheme:  − 6 8 (a) 1    4   10  (b) 1    − 40 

This question in 0580/11 May/June 2016

Q35 · - 3 15 (a) p = q = 2 e - o e 0 o Work out (i) 3p, [1] f p (ii) p – q 0580/12 May/June 2016

4 - 3 15 (a) p = q = 2 e - o e 0 o Work out (i) 3p, [1] f p (ii) p – q. [1] f p (b) B 3 Point B is marked on the grid and AB = e - 2 o. On the grid, mark point A. [1]

3 marks

Mark scheme:  12 15 (a) (i) 1    −6   7  (ii) 1    −2  (b) A in correct position 1

This question in 0580/12 May/June 2016

Q36 · -2 8 (a) Write 3 as a single vector 0580/13 May/June 2016

-2 8 (a) Write 3 as a single vector. e 1 o [1] f p (b) y 4 2 x –4 –2 0 2 4 –2 A –4 -7 Point A is marked on the grid and AB = . e 4 o On the grid, mark the point B. [1]

2 marks

Mark scheme:  6  8 (a) 1    3  (b) Point B at (−3, 2) 1

This question in 0580/13 May/June 2016

Q37 · - 2 7 a = b = c - 6 m c 4 m Work out 2a – b 0580/11 Oct/Nov 2016

5 - 2 7 a = b = c - 6 m c 4 m Work out 2a – b. [2] f p

2 marks

Mark scheme:   7   2 B1 for one correct component  −16   10  or for   seen  −12  8 3

This question in 0580/11 Oct/Nov 2016

Q38 · Y 6 5 A 4 3 2 1 x –6 –5 –4 –3 –2 –1 0 1 2 3 4 5 6 –1 –2 B –3 –4 –5 –6 (a) Write down the… 0580/11 Oct/Nov 2016

20 y 6 5 A 4 3 2 1 x –6 –5 –4 –3 –2 –1 0 1 2 3 4 5 6 –1 –2 B –3 –4 –5 –6 (a) Write down the co-ordinates of point A. ( … , … ) [1] (b) Plot the point (5, –2). Label this point C. [1] (c) Write down the mathematical name of triangle ABC. … [1] (d) Write AB as a column vector. AB = [1] f p - 2 (e) BD = c 5m Write down the co-ordinates of point D. ( … , … ) [1]

5 marks

Mark scheme: 20 (a) (1, 4) 1 (b) Point plotted at ( 5, −2) 1 (c) Isosceles 1FT Strict FT of their (b)  −4  (d)   1  −6  (e) (−5, 3) 1

This question in 0580/11 Oct/Nov 2016

Q39 · 2 6 m = n = c- 7m c 6 m Work out (a) 3m, [1] f p (b) m – n 0580/12 Oct/Nov 2016

5 2 6 m = n = c- 7m c 6 m Work out (a) 3m, [1] f p (b) m – n. [1] f p

2 marks

Mark scheme:  15 6 (a) 1    − 21   3  (b) 1    − 13 

This question in 0580/12 Oct/Nov 2016

Question 40 0580/13 Oct/Nov 2016

18 (a) Work out. 5 - 3 + c - 1 m c 2 m [1] f p (b) A is the point (3, 6) and B is the point (5, 10). Work out AB. AB = [1] f p 1 (c) C is the point (5, 8) and CD = c 2 m. Find the co-ordinates of the point D. ( … , … ) [1]

3 marks

Mark scheme:  18 (a)  1 1 2 (b)  1 4 (c) (6, 10) 1

This question in 0580/13 Oct/Nov 2016

Question 41 0580/12 Feb/March 2017

21 (a) Work out. 3 1 + c- 2 m c- 1m [1] f p (b) y 10 9 A 8 7 6 B 5 4 3 2 1 x 0 1 2 3 4 5 6 7 8 9 10 Points A and B are marked on the grid. - 4 BC = c 0m (i) On the grid, plot the point C. [1] (ii) Write AC as a column vector. [1] f p

3 marks

Mark scheme:  4  21 (a)   1  −3  (b) (i) Point at (3, 5) 1 JJJG  1  (ii) 1FT FT their AC    −3  1

This question in 0580/12 Feb/March 2017

Q42 · 5 - 3 a = b = c- 1m c- 4m Write a + 2b as a single vector 0580/11 May/June 2017

13 5 - 3 a = b = c- 1m c- 4m Write a + 2b as a single vector. [2] f p

2 marks

Mark scheme: 13  −1  2  −6   k    B1 for   seen or answer   or  −9   −8   −9   −1     k 

This question in 0580/11 May/June 2017

Q43 · 13 (a) GH = c- 4 m Find (i) 5 GH , [1] f p (ii) HG 0580/13 May/June 2017

6 13 (a) GH = c- 4 m Find (i) 5 GH , [1] f p (ii) HG. [1] f p 6 2 8 (b) + = c 7 m c y m c 3 m Find the value of y. y = … [1]

3 marks

Mark scheme: 13(a)(i)  30  1    −20  13(a)(ii)  −6  1    4  13(b) − 4 1

This question in 0580/13 May/June 2017

Q44 · 4 8 s = t = f- 1p f 2 p Work out 5s – t 0580/13 Oct/Nov 2017

3 4 8 s = t = f- 1p f 2 p Work out 5s – t. [2] f p

2 marks

Mark scheme: 8  11  2  11   k   15    B1 for   or   or   seen  − 7   k   − 7   − 5 

This question in 0580/13 Oct/Nov 2017

Q45 · 2 - 3 g = h = c 5 m c 4 m Write as a single vector (a) g + h, [1] f p (b) -h 0580/11 May/June 2018

12 2 - 3 g = h = c 5 m c 4 m Write as a single vector (a) g + h, [1] f p (b) -h. [1] f p

2 marks

Mark scheme: 12(a)  − 1  1    9  12(b)  3  1    − 4 

This question in 0580/11 May/June 2018

Q46 · 5 - 7 a = b = c- 2m c- 3m Work out a + 3b 0580/12 May/June 2018

12 5 - 7 a = b = c- 2m c- 3m Work out a + 3b. [2] f p

2 marks

Mark scheme: 12  − 16  2  −21   − 16   k    B1 for [3b =]   or   or    − 11   −9   k   −11 

This question in 0580/12 May/June 2018

Question 47 0580/11 Oct/Nov 2018

11 Work out. 2 (a) 6 c- 1m [1] f p 5 2 (b) - c- 3m c4m [1] f p

2 marks

Mark scheme: 11(a)  12  1    −6  11(b)  3  1    −7 

This question in 0580/11 Oct/Nov 2018

Q48 · Y 8 7 6 B 5 4 A 3 2 1 0 x –5 –4 –3 –2 –1 1 2 3 4 5 6 –1 –2 –3 –4 (a) Write down the… 0580/13 Oct/Nov 2018

23 y 8 7 6 B 5 4 A 3 2 1 0 x –5 –4 –3 –2 –1 1 2 3 4 5 6 –1 –2 –3 –4 (a) Write down the co-ordinates of point A. ( … , … ) [1] (b) Plot the point C at (4, −3). [1] (c) Find the vector AB. AB = [1] f p Questions 24, 25 and 26 are printed on the next page.

3 marks

Mark scheme: 23(a) (5, 3) 1 23(b) Point plotted at (4, −3) 1 23(c)  −8  1    2 

This question in 0580/13 Oct/Nov 2018

Q49 · - 5 0 e = f = e 4o e6o Write as a single vector (a) 3e, [1] f p (b) f - e 0580/12 Feb/March 2019

11 - 5 0 e = f = e 4o e6o Write as a single vector (a) 3e, [1] f p (b) f - e . [1] f p

2 marks

Mark scheme: 11(a)  − 15  1    1 2  11(b) 5 1  2

This question in 0580/12 Feb/March 2019

Question 50 0580/11 May/June 2019

8 Work out. 4 1 (a) - e-2o e5o [1] f p 3 (b) 6 e0o [1] f p

2 marks

Mark scheme: 8(a)  3  1    −7  8(b)  18  1    0 

This question in 0580/11 May/June 2019

Q51 · 1 11 p = q = e0o e6o Work out 2p + 3q 0580/13 May/June 2019

5 1 11 p = q = e0o e6o Work out 2p + 3q . [2] f p

2 marks

Mark scheme: 11  13  2  10   3   13   n    B1 for   or   or   or    18   0   18   m   18 

This question in 0580/13 May/June 2019

Question 52 0580/13 Oct/Nov 2019

17 Work out. - 3 2 (a) + f 5p f - 4p [1] f p 6 1 (b) - f2p f5p [1] f p 2 (c) 4 f - 5p [1] f p

3 marks

Mark scheme: 17(a) −1 1 1 17(b) 5 1 −3 17(c) 8 1 −20

This question in 0580/13 Oct/Nov 2019

Q53 · Point A has coordinates (6, 4) and point B has coordinates (2, 7) 0580/12 Feb/March 2020

10 Point A has coordinates (6, 4) and point B has coordinates (2, 7). Write AB as a column vector. AB = [1] f p

1 marks

Mark scheme: 10  − 4  1    3 

This question in 0580/12 Feb/March 2020

Q54 · Y 4 3 2 Q 1 – 4 – 3 – 2 – 1 0 1 2 3 4 x – 1 P – 2 – 3 – 4 (a) Write PQ as a column vector 0580/11 May/June 2020

9 y 4 3 2 Q 1 – 4 – 3 – 2 – 1 0 1 2 3 4 x – 1 P – 2 – 3 – 4 (a) Write PQ as a column vector. [1] f p (b) Write 3PQ as a single vector. [1] f p

2 marks

Mark scheme: 9(a)  −5  1    3  9(b)  −15  1 FT their (a)    9 

This question in 0580/11 May/June 2020

Q55 · Y 4 B 3 2 A C 1 x – 4 – 3 – 2 – 1 0 1 2 3 4 – 1 – 2 – 3 – 4 Points A, B and C are shown… 0580/12 May/June 2020

12 y 4 B 3 2 A C 1 x – 4 – 3 – 2 – 1 0 1 2 3 4 – 1 – 2 – 3 – 4 Points A, B and C are shown on the grid. (a) Write down the coordinates of point C. ( … , … ) [1] (b) On the grid, plot point D so that ABCD is a parallelogram. [1] - 4 (c) On the grid, plot point E so that EA = [2] e 3o.

4 marks

Mark scheme: 12(a) (3, 1) 1 12(b) D plotted at (–2, –1) 1 12(c) E plotted at (1, –2) 2 B1 for E plotted at (1, k) or (k, –2) or  4  AE =    − 3 

This question in 0580/12 May/June 2020

Question 56 0580/11 May/June 2021

9 Work out. 6 8 (a) + e- 5o e- 1o [1] f p - 4 (b) 3 e 7o [1] f p

2 marks

Mark scheme: 9(a)  14  1    −6  9(b)  −12  1    21 

This question in 0580/11 May/June 2021

Q57 · - 2 7 a = b = e- 7o e 6o Work out a - b 0580/12 May/June 2021

5 - 2 7 a = b = e- 7o e 6o Work out a - b . [1] f p

1 marks

Mark scheme: 7  7  1    −13 

This question in 0580/12 May/June 2021

Q58 · 5 10 (a) a = b = e - 4 o e2o Work out 0580/13 May/June 2021

3 5 10 (a) a = b = e - 4 o e2o Work out. (i) 8b [1] f p (ii) a – b [1] f p 5 (b) Point L has coordinates ( - 3, 6 ) and LM = e- 2o. Find the coordinates of point M. ( … , … ) [1]

3 marks

Mark scheme: 10(a)(i) 40 1 16 10(a)(ii) −2 1 −6 10(b) 2 4 1

This question in 0580/13 May/June 2021

Question 59 0580/12 Oct/Nov 2021

14 Work out. 3 - 5 (a) + e- 2o e 7o [1] f p 3 (b) 5 e- 1o [1] f p

2 marks

Mark scheme: 14(a)  −2  1    5  14(b)  15  1    −5 

This question in 0580/12 Oct/Nov 2021

Q60 · Points A and B are plotted on the grid 0580/13 Oct/Nov 2021

2 Points A and B are plotted on the grid. y 4 3 B 2 1 – 3 – 2 – 1 0 1 2 3 x – 1 A – 2 – 3 (a) Write down the coordinates of point B. ( … , … ) [1] (b) Write AB as a vector. [1] f p (c) On the grid, plot point C at (-2, 3). [1]

3 marks

Mark scheme: 2(a) (2, 3) 1 2(b) 4 1  5 2(c) C plotted at (–2, 3) 1

This question in 0580/13 Oct/Nov 2021

Q61 · - 1 10 p = q = e8o e 4o Find (a) p - q , [1] f p (b) 6p 0580/12 May/June 2022

2 - 1 10 p = q = e8o e 4o Find (a) p - q , [1] f p (b) 6p. [1] f p

2 marks

Mark scheme: 10(a) 3 1  4 10(b)  12  1    48 

This question in 0580/12 May/June 2022

Q62 · The grid shows point P and point R 0580/13 May/June 2022

11 The grid shows point P and point R. y 5 P 4 3 2 1 – 5 – 4 – 3 – 2 – 1 0 1 2 3 4 5 x – 1 – 2 – 3 R – 4 – 5 (a) Write down the coordinates of point P. ( … , … ) [1] 3 (b) PQ = e- 2o Mark point Q on the grid. [1] (c) Find QR. QR = [1] f p (d) Complete this statement. [1] PQ + QR = …

4 marks

Mark scheme: 11(a) (−1, 4) 1 11(b) Q marked at (2, 2) 1 11(c)   6  1 FT their point Q     5  11(d) PR 1

This question in 0580/13 May/June 2022

Q63 · - 1 2 8 v = y = e 3o e5o Find (a) v - y [1] f p (b) 2 v 0580/12 Feb/March 2023

- 1 2 8 v = y = e 3o e5o Find (a) v - y [1] f p (b) 2 v . [1] f p

2 marks

Mark scheme: 8(a)  −3  1    −2  8(b)  −2  1    6 

This question in 0580/12 Feb/March 2023

Q64 · 3 - 2 a = b = e 7 o e 5o Work out a - 2 b 0580/11 May/June 2023

11 3 - 2 a = b = e 7 o e 5o Work out a - 2 b . [2] f p

2 marks

Mark scheme: 11  7  2 7  b    B1 for  or   as answer   3  a   3    4   4  or   or   in working  10   10 

This question in 0580/11 May/June 2023

Q65 · - 12 15 F is the point ( 1, - 4 ) , FG = and GH = e- 3o e 35o 0580/12 May/June 2023

8 - 12 15 F is the point ( 1, - 4 ) , FG = and GH = e- 3o e 35o. Find (a) 3FG [1] f p (b) FG + GH [1] f p (c) the coordinates of the point G. ( … , … ) [1]

3 marks

Mark scheme: 15(a)  24  1    9  15(b)  4  1    32  15(c) (9, –7) 1

This question in 0580/12 May/June 2023

Q66 · - 6 13 10 a = b = c = e9o e 1o e- 2o Work out 0580/13 Oct/Nov 2023

4 - 6 13 10 a = b = c = e9o e 1o e- 2o Work out. (a) a + b [1] f p (b) 3c [1] f p

2 marks

Mark scheme: 10(a)  −2  1    10  10(b)  39  1    −6 

This question in 0580/13 Oct/Nov 2023

Q67 · Y 5 B 4 3 2 A 1 x – 4 –3 –2 –1 0 1 2 3 4 5 6 7 8 Write AB as a column vector 0580/12 Feb/March 2024

15 y 5 B 4 3 2 A 1 x – 4 –3 –2 –1 0 1 2 3 4 5 6 7 8 Write AB as a column vector. AB = [1] f p

1 marks

Mark scheme: 15  −10  1    3 

This question in 0580/12 Feb/March 2024

Q68 · 6 10 a = b = e- 7o e- 7o Work out a - b 0580/12 May/June 2024

5 6 10 a = b = e- 7o e- 7o Work out a - b . [1] f p

1 marks

Mark scheme: 10   1  1    0 

This question in 0580/12 May/June 2024

Q69 · Y 6 5 4 3 B 2 1 0 x 1 2 3 4 5 6 7 8 3 AB = e o - 2 Mark point A on the grid 0580/12 Oct/Nov 2024

19 y 6 5 4 3 B 2 1 0 x 1 2 3 4 5 6 7 8 3 AB = e o - 2 Mark point A on the grid. [1]

1 marks

Mark scheme: 19 (1, 4) plotted 1

This question in 0580/12 Oct/Nov 2024