E7.2· 69 questions · 174 marks · 209 min · 2004–2024· Structured questions
Every Cambridge IGCSE Mathematics Paper 1 question on vectors in two dimensions, laid out as 37 A4 pages with the mark scheme below. Nothing is left out. Free to read, no account.
![Question 1: 3 – 1 a = and b = 4 2 Work out a – 2b. Answer [2]](https://img.pastlit.com/crops/44d13a35-d287-4292-aed4-91e4d89260b0/q8.webp)
1 / 37![Question 3: − 1 For 15 = and = 3 . Examiner's 4 Use (a) Write as a column vector. Answer(a) = [1] (b) Make two statements abou…](https://img.pastlit.com/crops/330e7cd0-4f7c-4217-94ad-0a3589db4652/q15.webp)
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5 / 37![Question 9: 6 − 3 2 19 f = g = h = 0 6 −2 Calculate (a) 3f, Answer(a) [2] (b) g – h. …](https://img.pastlit.com/crops/adc0e17b-0b50-4459-b9b5-4ff81317746a/q19.webp)
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9 / 37![Question 14: 3 − 5 12 = and = −1 4 (a) Find . You may use the grid below to help if you wish. Answer(a) = [2] …](https://img.pastlit.com/crops/af4d2622-57aa-4d05-a618-217ad2746dd0/q12.webp)
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11 / 37![Question 18: − For Examiner's16 p = q = r = 9 − 5 3 Use Calculate (a) 7p , Answer(a) [2] (b) q – r . …](https://img.pastlit.com/crops/79ec1b42-b10d-4fd4-a373-595575d45675/q16.webp)
12 / 37![Question 20: Write each of the following as a single vector. 6 -4 (a) + e 1 o e 2 o Answer(a) [1] e o 2 (b) 4 3 e- o Answer(b) [1] e o _________________…](https://img.pastlit.com/crops/bcac71ca-702b-4576-a59a-2c8caec60009/q5.webp)
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14 / 37![Question 24: - 1 7 a = b = e- 3 o e 5 o Work out a – 2b. Answer [2] f p_________________________________________________________________________________…](https://img.pastlit.com/crops/3ad71d0c-8684-4b41-941e-2c344a5df0a6/q7.webp)
15 / 37![Question 26: y 7 6 5 4 A 3 2 1 x –7 –6 –5 –4 –3 –2 –1 0 1 2 3 4 5 –1 –2 –3 3 Draw the image of triangle A after a translation by the vector [2] 4 e- o. …](https://img.pastlit.com/crops/44750ab3-2c1d-411c-bdc0-74320fe5deae/q20.webp)
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17 / 37![Question 29: y 6 A 5 4 B 3 2 1 x 0 1 2 3 4 5 6 7 8 (a) Write down the co-ordinates of A. Answer(a) (...................... , ......................) [1]…](https://img.pastlit.com/crops/e9e30d36-31f0-4b84-8b8a-8c2dc4464acb/q17.webp)
18 / 37![Question 31: y 4 3 2 A 1 x –4 –3 –2 –1 0 1 2 3 4 5 –1 –2 –3 2 Draw the image of shape A after a translation by the vector [2] e - 3 o.__________________…](https://img.pastlit.com/crops/e750ec9a-ee37-46c2-b89d-578bcbe1eb55/q7.webp)
19 / 37![Question 33: y 4 G 3 2 1 x 0 –4 –3 –2 –1 1 2 3 4 –1 –2 F –3 –4 Points F and G are marked on the grid. (a) Write FG as a column vector. FG = [1] f p - 5 …](https://img.pastlit.com/crops/61915e9e-3992-4bac-87b9-f9858a7c2163/q14.webp)
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21 / 37![Question 36: -2 8 (a) Write 3 as a single vector. e 1 o [1] f p (b) y 4 2 x –4 –2 0 2 4 –2 A –4 -7 Point A is marked on the grid and AB = . e 4 o On the…](https://img.pastlit.com/crops/21169036-4e1d-4ee8-bdff-d6a1824ab661/q8.webp)
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23 / 37![Question 39: 2 6 m = n = c- 7m c 6 m Work out (a) 3m, [1] f p (b) m – n. [1] f p](https://img.pastlit.com/crops/47555cb7-c319-4d48-be19-3866e91f8491/q6.webp)
24 / 37![Question 41: (a) Work out. 3 1 + c- 2 m c- 1m [1] f p (b) y 10 9 A 8 7 6 B 5 4 3 2 1 x 0 1 2 3 4 5 6 7 8 9 10 Points A and B are marked on the grid. - 4…](https://img.pastlit.com/crops/deb31e6c-dab7-4969-a198-e44f283d7f17/q21.webp)
25 / 37![Question 43: 13 (a) GH = c- 4 m Find (i) 5 GH , [1] f p (ii) HG. [1] f p 6 2 8 (b) + = c 7 m c y m c 3 m Find the value of y. y = ......................…](https://img.pastlit.com/crops/ae3bd608-1422-428e-a09a-fcfd571352e3/q13.webp)
![Question 44: 4 8 s = t = f- 1p f 2 p Work out 5s – t. [2] f p](https://img.pastlit.com/crops/eddebf33-6ce3-451f-9d9e-326f46ec645b/q8.webp)
26 / 37![Question 46: 5 - 7 a = b = c- 2m c- 3m Work out a + 3b. [2] f p](https://img.pastlit.com/crops/72fdd7a4-6cc0-4ac0-8ab9-117b690124ef/q12.webp)
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28 / 37![Question 49: - 5 0 e = f = e 4o e6o Write as a single vector (a) 3e, [1] f p (b) f - e . [1] f p](https://img.pastlit.com/crops/492eee66-4873-4ba9-a9f8-48d4d756c80e/q11.webp)
![Question 50: Work out. 4 1 (a) - e-2o e5o [1] f p 3 (b) 6 e0o [1] f p](https://img.pastlit.com/crops/9ca31dde-5c6a-4fd0-9e7e-e79fe29b4bd0/q8.webp)
29 / 37![Question 52: Work out. - 3 2 (a) + f 5p f - 4p [1] f p 6 1 (b) - f2p f5p [1] f p 2 (c) 4 f - 5p [1] f p](https://img.pastlit.com/crops/38d4efb8-0fc1-40d9-ba12-89b4e31a9600/q17.webp)
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32 / 37![Question 57: - 2 7 a = b = e- 7o e 6o Work out a - b . [1] f p](https://img.pastlit.com/crops/da0eb517-c9b6-487e-a526-903eeaa0bdb8/q7.webp)
![Question 58: 5 10 (a) a = b = e - 4 o e2o Work out. (i) 8b [1] f p (ii) a – b [1] f p 5 (b) Point L has coordinates ( - 3, 6 ) and LM = e- 2o. Find the …](https://img.pastlit.com/crops/e47f3805-d13e-4095-8d11-dbebb00ad824/q10.webp)
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35 / 37![Question 64: 3 - 2 a = b = e 7 o e 5o Work out a - 2 b . [2] f p](https://img.pastlit.com/crops/b70f0e40-bbe8-4586-9fc7-e30d73c9d676/q11.webp)
![Question 65: - 12 15 F is the point ( 1, - 4 ) , FG = and GH = e- 3o e 35o. Find (a) 3FG [1] f p (b) FG + GH [1] f p (c) the coordinates of the point G.…](https://img.pastlit.com/crops/4f4a137f-98cc-4116-b6ec-3f87f272896f/q15.webp)
36 / 37![Question 67: y 5 B 4 3 2 A 1 x – 4 –3 –2 –1 0 1 2 3 4 5 6 7 8 Write AB as a column vector. AB = [1] f p](https://img.pastlit.com/crops/e61c3206-1c8c-48f9-8834-4cc244a2c6a2/q15.webp)
![Question 68: 6 10 a = b = e- 7o e- 7o Work out a - b . [1] f p](https://img.pastlit.com/crops/d5a90822-8b12-4a2f-b166-28a405be7bd2/q10.webp)
37 / 37Answers below. Sit the paper first if you are practising.
Pastlit
Mathematics 0580 · Vectors in two dimensions — Paper 1
IGCSE · topical answer key — answer key (teacher use)
Question
Answer
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1| Question | Answer | Marks | From |
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| 1 | see sheet | 2 | 0580/11 Oct/Nov 2004 |
| 2 | see sheet | 3 | 0580/11 Oct/Nov 2005 |
| 3 | see sheet | 3 | 0580/11 May/June 2006 |
| 4 | see sheet | 4 | 0580/11 Oct/Nov 2006 |
| 5 | see sheet | 4 | 0580/11 May/June 2009 |
| 6 | see sheet | 3 | 0580/11 Oct/Nov 2009 |
| 7 | see sheet | 3 | 0580/12 Oct/Nov 2009 |
| 8 | see sheet | 4 | 0580/11 May/June 2010 |
| 9 | see sheet | 4 | 0580/13 May/June 2010 |
| 10 | see sheet | 5 | 0580/12 Oct/Nov 2010 |
| 11 | see sheet | 5 | 0580/12 Oct/Nov 2010 |
| 12 | see sheet | 3 | 0580/13 Oct/Nov 2010 |
| 13 | see sheet | 4 | 0580/11 May/June 2011 |
| 14 | see sheet | 3 | 0580/12 May/June 2011 |
| 15 | see sheet | 1 | 0580/11 Oct/Nov 2011 |
| 16 | see sheet | 3 | 0580/11 May/June 2012 |
| 17 | see sheet | 2 | 0580/13 May/June 2012 |
| 18 | see sheet | 4 | 0580/11 Oct/Nov 2012 |
| 19 | see sheet | 2 | 0580/12 Oct/Nov 2012 |
| 20 | see sheet | 2 | 0580/11 May/June 2013 |
| 21 | see sheet | 2 | 0580/12 May/June 2013 |
| 22 | see sheet | 2 | 0580/13 May/June 2013 |
| 23 | see sheet | 1 | 0580/12 Oct/Nov 2013 |
| 24 | see sheet | 2 | 0580/11 May/June 2014 |
| 25 | see sheet | 2 | 0580/13 May/June 2014 |
| 26 | see sheet | 2 | 0580/13 May/June 2014 |
| 27 | see sheet | 2 | 0580/12 Feb/March 2015 |
| 28 | see sheet | 2 | 0580/11 May/June 2015 |
| 29 | see sheet | 4 | 0580/13 May/June 2015 |
| 30 | see sheet | 2 | 0580/11 Oct/Nov 2015 |
| 31 | see sheet | 2 | 0580/11 Oct/Nov 2015 |
| 32 | see sheet | 2 | 0580/12 Oct/Nov 2015 |
| 33 | see sheet | 2 | 0580/12 Feb/March 2016 |
| 34 | see sheet | 2 | 0580/11 May/June 2016 |
| 35 | see sheet | 3 | 0580/12 May/June 2016 |
| 36 | see sheet | 2 | 0580/13 May/June 2016 |
| 37 | see sheet | 2 | 0580/11 Oct/Nov 2016 |
| 38 | see sheet | 5 | 0580/11 Oct/Nov 2016 |
| 39 | see sheet | 2 | 0580/12 Oct/Nov 2016 |
| 40 | see sheet | 3 | 0580/13 Oct/Nov 2016 |
| 41 | see sheet | 3 | 0580/12 Feb/March 2017 |
| 42 | see sheet | 2 | 0580/11 May/June 2017 |
| 43 | see sheet | 3 | 0580/13 May/June 2017 |
| 44 | see sheet | 2 | 0580/13 Oct/Nov 2017 |
| 45 | see sheet | 2 | 0580/11 May/June 2018 |
| 46 | see sheet | 2 | 0580/12 May/June 2018 |
| 47 | see sheet | 2 | 0580/11 Oct/Nov 2018 |
| 48 | see sheet | 3 | 0580/13 Oct/Nov 2018 |
| 49 | see sheet | 2 | 0580/12 Feb/March 2019 |
| 50 | see sheet | 2 | 0580/11 May/June 2019 |
| 51 | see sheet | 2 | 0580/13 May/June 2019 |
| 52 | see sheet | 3 | 0580/13 Oct/Nov 2019 |
| 53 | see sheet | 1 | 0580/12 Feb/March 2020 |
| 54 | see sheet | 2 | 0580/11 May/June 2020 |
| 55 | see sheet | 4 | 0580/12 May/June 2020 |
| 56 | see sheet | 2 | 0580/11 May/June 2021 |
| 57 | see sheet | 1 | 0580/12 May/June 2021 |
| 58 | see sheet | 3 | 0580/13 May/June 2021 |
| 59 | see sheet | 2 | 0580/12 Oct/Nov 2021 |
| 60 | see sheet | 3 | 0580/13 Oct/Nov 2021 |
| 61 | see sheet | 2 | 0580/12 May/June 2022 |
| 62 | see sheet | 4 | 0580/13 May/June 2022 |
| 63 | see sheet | 2 | 0580/12 Feb/March 2023 |
| 64 | see sheet | 2 | 0580/11 May/June 2023 |
| 65 | see sheet | 3 | 0580/12 May/June 2023 |
| 66 | see sheet | 2 | 0580/13 Oct/Nov 2023 |
| 67 | see sheet | 1 | 0580/12 Feb/March 2024 |
| 68 | see sheet | 1 | 0580/12 May/June 2024 |
| 69 | see sheet | 1 | 0580/12 Oct/Nov 2024 |
8 3 – 1 a = and b = 4 2 Work out a – 2b. Answer [2]
2 marks
Mark scheme: 8 5 1 + 1 One mark each component. If only number 5 in bracket allow 0 1 mark. − 2 2 If 0 scored SC1 for or 4 −4 0 seen, or 5 Ignore a line between Components
11 2 3 p = and q = . −3 1 (a) Write p + q as a column vector. Answer (a) p + q = [2] (b) The point O is marked on the grid below. Draw the vector where = p. y 3 2 1 x –3 –2 –1 O 1 2 3 –1 –2 –3 [1]
3 marks
Mark scheme: 11 (a) 5 2 1 mark for each correct component. −2 (b) Correct Vector Drawn 1
− 1 For 15 = and = 3 . Examiner's 4 Use (a) Write as a column vector. Answer(a) = [1] (b) Make two statements about the relationship between the lines AB and CD. Statement 1 Statement 2 [2]
3 marks
Mark scheme: 15 (a) − 3 1 12 (b) Parallel oe. 1 CD is 3 times as long as AB oe. 1
21 Write the following as single vectors. For Examiner's Use 2 1 3 (a) + − − 1 3 0 Answer(a) [2] 5 (b) 6 −4 Answer(b) [2]
4 marks
Mark scheme: 21 Ignore ‘fraction’ lines in (a) and (b) 0 Allow coordinate form (a) Final ans 2 1 mark for each correct component. 4 30 (b) Final ans 2 1 mark for each correct component. −24
17 For Examiner's y Use 10 C 8 6 4 B 2 A x 0 2 4 6 8 10 Points A, B and C are shown on the grid. (a) Plot the point D on the grid above so that ABCD is a rhombus. [1] (b) Write BD as a column vector. Answer(b) BD = [2] (c) M is the mid-point of AC. Write as a column vector. Answer(c) = [1]
4 marks
Mark scheme: 17 (a) D plotted at (3, 7) 1 Within 1 mm by eye. − 4 (b) 2ft 1 mark for each component 4 −1 if in working, no brackets 3 (c) 1cao SC1 Both (b) and (c) correct but written as 3 coordinates.
13 For y Examiner's G Use 5 4 3 2 F 1 x –3 –2 –1 0 1 2 3 4 5 –1 –2 –3 –4 The points F and G are shown on the grid. (a) Write down the co-ordinates of the point F. Answer(a)( , ) [1] (b) Write as a column vector. Answer(b) = ( ) [1] _2 (c) GH = . Mark and label the point H on the grid. [1] _7
3 marks
Mark scheme: 13 (a) (–2, 1) 1 All coordinates/components reversed. 4 ie (a) (1, −2), (b) , (c) (−3, 3) 6 6 (b) 1 mark 0, 0, SC1 4 (c) H at (2, –2) 1
13 ForFor y Examiner'sExaminer's G UseUse 5 4 3 2 F 1 x –3 –2 –1 0 1 2 3 4 5 –1 –2 –3 –4 The points F and G are shown on the grid. (a) Write down the co-ordinates of the point F. Answer(a)( , ) [1] (b) Write as a column vector. Answer(b) = ( ) [1] _5 (c) = . Mark and label the point H on the grid. [1] _3
3 marks
Mark scheme: 13 (a) (–2, 1) 1 All coordinates/components reversed. 4 ie (a) (1, −2), (b) , (c) (1, 0) 6 6 (b) 1 mark 0, 0, SC1 4 (c) H at (–1, 2) 1
15 3 − 1 0 d = e = f = −5 4 7 Calculate (a) d – e, Answer(a) [2] (b) 4f. Answer(b) [2]
4 marks
Mark scheme: 15 (a) 4 1, 1 −9 (b) 0 1, 1 28
6 − 3 2 19 f = g = h = 0 6 −2 Calculate (a) 3f, Answer(a) [2] (b) g – h. Answer(b) [2]
4 marks
Mark scheme: 18 19 (a) 0 1, 1 − 5 (b) 8 1, 1
16 Flags A and B are shown on the grid. For Examiner's y Use 6 5 A 4 3 2 1 x –6 –5 –4 –3 –2 –1 0 1 2 3 4 5 6 –1 –2 –3 –4 B –5 –6 (a) Describe fully the single transformation which maps flag A onto flag B. Answer(a) [3] 5 (b) On the grid, draw the translation of flag A by the vector . [2] −3
5 marks
Mark scheme: 16 (a) Rotation or enlargement 1 Two transformations named, zero for (a) 180° (SF) −1 1 Independent (about or centre) origin oe 1 Independent (b) Correct translation 2 B1 for 5 right or 3 down applied 5 right and 3 down 12
17 For 3 − 5 Examiner's AB = AC = Use −3 0 (a) Calculate AB + 3AC. Answer(a) [2] (b) Write down . Answer(b) = [1] (c) AC is drawn on the grid below. C A (i) On the grid, draw AB . [1] (ii) Write down the obtuse angle between AB and AC. Answer(c)(ii) [1] Question 18 is printed on the next page.
5 marks
Mark scheme: 17 (a) − 12 2 B1 for 1 component correct. − 3 (b) − 3 3 1 (c) (i) Vector AB drawn 1 Diagonal line, ignore working lines (ii) 134° to 136° 1 x x
18 y 7 C 6 B 5 4 3 A 2 1 x 0 1 2 3 4 5 6 7 The diagram shows three points, A(1, 2), B(7, 5) and C(5, 7). (a) Write as column vectors (i) AC, Answer(a)(i) AC = [1] (ii) CB. Answer(a)(ii) CB = [1] (b) Use two of the symbols +, –, = in the spaces to make a correct statement. AC CB AB [1]
3 marks
Mark scheme: 4 18 (a) (i) 5 1 2 (ii) −2 1 (b) (AC) + (CB) = (AB) 1 1 1
17 For y Examiner's Use 4 3 2 B 1 x –3 –2 –1 0 1 2 3 4 5 6 7 A –1 –2 –3 (a) Write down the vector . Answer(a) [1] − 3 (b) = 1 Mark the point C on the grid. [1] (c) Work out − 3 7 (i) + , 1 −4 Answer(c)(i) [1] − 3 (ii) 4 × . 1 Answer(c)(ii) [1]
4 marks
Mark scheme: 17 (a) 1 2 (b) C marked at (1, 2) 1 4 (c) 1 −3 − 12 (d) 1 4
3 − 5 12 = and = −1 4 (a) Find . You may use the grid below to help if you wish. Answer(a) = [2] (b) Work out . Answer(b) = [1]
3 marks
Mark scheme: 12 − 2 1,1 B1 for 1 correct component. (a) SC1 for both correct but written as coordinates as 3 the answer. 2 1ft ft their (a) with signs reversed. (b) Not a strict follow through. −3
1 For Examiner's Use A S The diagram shows the map of part of an orienteering course. Sanji runs from the start, S, to the point A. Write as a column vector. Answer [1]
1 marks
Mark scheme: Qu. Answers Mark Part Marks 1 −3 1 4 4
17 For y Examiner's Use 7 6 5 4 3 A 2 1 x –5 –4 –3 –2 –1 0 1 2 3 4 5 –1 –2 –3 B –4 (a) Write down the co-ordinates of point A. Answer(a) ( , ) [1] (b) Write as a column vector. Answer(b) = [1] 2 (c) = 3 Write down the co-ordinates of C. Answer(c) ( , ) [1]
3 marks
Mark scheme: 17 (a) (–1, 2) 1 4 (b) 1 −5 (c) 1 (1, 5)
8 Work out For Examiner's Use 5 6 (a) − , 3 −2 Answer(a) [1] 3 (b) 5 . −4 Answer(b) [1]
2 marks
Mark scheme: 8 (a) − 1 1 5 (b) 15 1 −20
− For Examiner's16 p = q = r = 9 − 5 3 Use Calculate (a) 7p , Answer(a) [2] (b) q – r . Answer(b) [2]
4 marks
Mark scheme: (a) 1, 116 63 7 (b) 1, 1 −8
4 − 2 7 a = b = −1 − 3 Work out a + 3b. Answer [2]
2 marks
Mark scheme: 7 −2 2 − 6 −10 B1 for each correct component or [3b] = seen − 9
5 Write each of the following as a single vector. 6 -4 (a) + e 1 o e 2 o Answer(a) [1] e o 2 (b) 4 3 e- o Answer(b) [1] e o _____________________________________________________________________________________
2 marks
Mark scheme: 5 (a) 2 1 3 8 (b) 1 −12
10 4 -5 a = b = e 7 o e 2 o Write each of the following as a single vector. (a) 6a Answer(a) [1] e o (b) a + b Answer(b) [1] e o _____________________________________________________________________________________
2 marks
Mark scheme: 10 (a) 1 42 − 1 (b) 1 9
12 For Examiner′s y Use 6 P 5 4 3 2 1 x –4 –3 –2 –1 0 1 2 3 4 5 6 7 8 –1 –2 Q –3 –4 The points P and Q are marked on the grid. (a) Work out the vector . Answer(a) = [1] f p - 8 (b) = - 1 e o Find the co-ordinates of the point R. Answer(b) ( … , … ) [1] _____________________________________________________________________________________
2 marks
Mark scheme: 12 (a) 9 [PQ =] 1 −7 (b) (−1 , −3) 1
3 - 1 2 p = q = - 2 4 e o e o Work out p + q. Answer [1] f p _____________________________________________________________________________________
1 marks
Mark scheme: 2 2 1 2
4 - 1 7 a = b = e- 3 o e 5 o Work out a – 2b. Answer [2] f p__________________________________________________________________________________________
2 marks
Mark scheme: 7 2 B1 for each component −13 − 2 2 or for or seen 10 −10
9 - 3 2 a = b = 4 e o e 6 o Write each of the following as a single vector. (a) 2a Answer(a) [1] f p (b) a – b Answer(b) [1] f p __________________________________________________________________________________________
2 marks
Mark scheme: 6 9 (a) 1 8 − 5 (b) 1 − 2
20 y 7 6 5 4 A 3 2 1 x –7 –6 –5 –4 –3 –2 –1 0 1 2 3 4 5 –1 –2 –3 3 Draw the image of triangle A after a translation by the vector [2] 4 e- o. __________________________________________________________________________________________
2 marks
Mark scheme: k 3 20 Triangle at ( 2, −1) ( 2, 1) ( 1, −2) 2 B1 for translation by or −4 k
6 9 The point P has co-ordinates (2, –5) and = e- 7 o. (a) Write down the co-ordinates of Q. Answer(a) ( … , … ) [1] (b) Write 4 as a column vector. Answer(b) [1] f p __________________________________________________________________________________________
2 marks
Mark scheme: 9 (a) (8, –12) 1 24 (b) 1 −28
8 3 - 8 a = b = 5 e o e 7 o Write each of the following as a single vector. (a) 3a Answer(a) [1] f p (b) a – b Answer(b) [1] f p __________________________________________________________________________________________
2 marks
Mark scheme: 8 (a) 1 9 15 (b) 1 11 −2
17 y 6 A 5 4 B 3 2 1 x 0 1 2 3 4 5 6 7 8 (a) Write down the co-ordinates of A. Answer(a) ( … , … ) [1] (b) Write down the vector . Answer(b) = [1] f p (c) Work out. + 6 5 e- 4 2 o e o Answer(c) [1] f p (d) Work out. - 3 6 e 7 o Answer(d) [1] f p __________________________________________________________________________________________
4 marks
Mark scheme: 17 (a) 1, 5 1 5 (b) 1 −2 6 (c) 1 −1 − 18 (d) 1 42
4 - 1 6 p = q = 2 3 o e- o e Work out 3p – q. Answer [2] f p __________________________________________________________________________________________
2 marks
Mark scheme: 6 13 2 12 B1 for seen 9 −6 13 j or B1 for or as answer k −9
7 y 4 3 2 A 1 x –4 –3 –2 –1 0 1 2 3 4 5 –1 –2 –3 2 Draw the image of shape A after a translation by the vector [2] e - 3 o.__________________________________________________________________________________________
2 marks
Mark scheme: 7 Triangle (3, –2), (4, –2), 2 B1 for movement 2 right or 3 down (4, –1) 785
12 (a) y 4 3 2 A 1 x –4 –3 –2 –1 0 1 2 3 4 –1 –2 B –3 –4 Points A and B are shown on the grid. Write AB as a column vector. Answer(a) AB = [1] f p 5 (b) CD = e - 7 o Write DC as a column vector. Answer(b) DC = [1] f p
2 marks
Mark scheme: 6 12 (a) 1 −3 − 5 1 (b) 7
14 y 4 G 3 2 1 x 0 –4 –3 –2 –1 1 2 3 4 –1 –2 F –3 –4 Points F and G are marked on the grid. (a) Write FG as a column vector. FG = [1] f p - 5 (b) GH = c- 6m Mark the point H on the grid. [1]
2 marks
Mark scheme: 1 14 (a) 1 5 (b) H marked at (–3,–3) 1 0 9
8 Work out. - 2 - 4 (a) + 3 7 f- p f p [1] e o 2 (b) 5 8 f- p [1] e o
2 marks
Mark scheme: − 6 8 (a) 1 4 10 (b) 1 − 40
4 - 3 15 (a) p = q = 2 e - o e 0 o Work out (i) 3p, [1] f p (ii) p – q. [1] f p (b) B 3 Point B is marked on the grid and AB = e - 2 o. On the grid, mark point A. [1]
3 marks
Mark scheme: 12 15 (a) (i) 1 −6 7 (ii) 1 −2 (b) A in correct position 1
-2 8 (a) Write 3 as a single vector. e 1 o [1] f p (b) y 4 2 x –4 –2 0 2 4 –2 A –4 -7 Point A is marked on the grid and AB = . e 4 o On the grid, mark the point B. [1]
2 marks
Mark scheme: 6 8 (a) 1 3 (b) Point B at (−3, 2) 1
5 - 2 7 a = b = c - 6 m c 4 m Work out 2a – b. [2] f p
2 marks
Mark scheme: 7 2 B1 for one correct component −16 10 or for seen −12 8 3
20 y 6 5 A 4 3 2 1 x –6 –5 –4 –3 –2 –1 0 1 2 3 4 5 6 –1 –2 B –3 –4 –5 –6 (a) Write down the co-ordinates of point A. ( … , … ) [1] (b) Plot the point (5, –2). Label this point C. [1] (c) Write down the mathematical name of triangle ABC. … [1] (d) Write AB as a column vector. AB = [1] f p - 2 (e) BD = c 5m Write down the co-ordinates of point D. ( … , … ) [1]
5 marks
Mark scheme: 20 (a) (1, 4) 1 (b) Point plotted at ( 5, −2) 1 (c) Isosceles 1FT Strict FT of their (b) −4 (d) 1 −6 (e) (−5, 3) 1
5 2 6 m = n = c- 7m c 6 m Work out (a) 3m, [1] f p (b) m – n. [1] f p
2 marks
Mark scheme: 15 6 (a) 1 − 21 3 (b) 1 − 13
18 (a) Work out. 5 - 3 + c - 1 m c 2 m [1] f p (b) A is the point (3, 6) and B is the point (5, 10). Work out AB. AB = [1] f p 1 (c) C is the point (5, 8) and CD = c 2 m. Find the co-ordinates of the point D. ( … , … ) [1]
3 marks
Mark scheme: 18 (a) 1 1 2 (b) 1 4 (c) (6, 10) 1
21 (a) Work out. 3 1 + c- 2 m c- 1m [1] f p (b) y 10 9 A 8 7 6 B 5 4 3 2 1 x 0 1 2 3 4 5 6 7 8 9 10 Points A and B are marked on the grid. - 4 BC = c 0m (i) On the grid, plot the point C. [1] (ii) Write AC as a column vector. [1] f p
3 marks
Mark scheme: 4 21 (a) 1 −3 (b) (i) Point at (3, 5) 1 JJJG 1 (ii) 1FT FT their AC −3 1
13 5 - 3 a = b = c- 1m c- 4m Write a + 2b as a single vector. [2] f p
2 marks
Mark scheme: 13 −1 2 −6 k B1 for seen or answer or −9 −8 −9 −1 k
6 13 (a) GH = c- 4 m Find (i) 5 GH , [1] f p (ii) HG. [1] f p 6 2 8 (b) + = c 7 m c y m c 3 m Find the value of y. y = … [1]
3 marks
Mark scheme: 13(a)(i) 30 1 −20 13(a)(ii) −6 1 4 13(b) − 4 1
3 4 8 s = t = f- 1p f 2 p Work out 5s – t. [2] f p
2 marks
Mark scheme: 8 11 2 11 k 15 B1 for or or seen − 7 k − 7 − 5
12 2 - 3 g = h = c 5 m c 4 m Write as a single vector (a) g + h, [1] f p (b) -h. [1] f p
2 marks
Mark scheme: 12(a) − 1 1 9 12(b) 3 1 − 4
12 5 - 7 a = b = c- 2m c- 3m Work out a + 3b. [2] f p
2 marks
Mark scheme: 12 − 16 2 −21 − 16 k B1 for [3b =] or or − 11 −9 k −11
11 Work out. 2 (a) 6 c- 1m [1] f p 5 2 (b) - c- 3m c4m [1] f p
2 marks
Mark scheme: 11(a) 12 1 −6 11(b) 3 1 −7
23 y 8 7 6 B 5 4 A 3 2 1 0 x –5 –4 –3 –2 –1 1 2 3 4 5 6 –1 –2 –3 –4 (a) Write down the co-ordinates of point A. ( … , … ) [1] (b) Plot the point C at (4, −3). [1] (c) Find the vector AB. AB = [1] f p Questions 24, 25 and 26 are printed on the next page.
3 marks
Mark scheme: 23(a) (5, 3) 1 23(b) Point plotted at (4, −3) 1 23(c) −8 1 2
11 - 5 0 e = f = e 4o e6o Write as a single vector (a) 3e, [1] f p (b) f - e . [1] f p
2 marks
Mark scheme: 11(a) − 15 1 1 2 11(b) 5 1 2
8 Work out. 4 1 (a) - e-2o e5o [1] f p 3 (b) 6 e0o [1] f p
2 marks
Mark scheme: 8(a) 3 1 −7 8(b) 18 1 0
5 1 11 p = q = e0o e6o Work out 2p + 3q . [2] f p
2 marks
Mark scheme: 11 13 2 10 3 13 n B1 for or or or 18 0 18 m 18
17 Work out. - 3 2 (a) + f 5p f - 4p [1] f p 6 1 (b) - f2p f5p [1] f p 2 (c) 4 f - 5p [1] f p
3 marks
Mark scheme: 17(a) −1 1 1 17(b) 5 1 −3 17(c) 8 1 −20
10 Point A has coordinates (6, 4) and point B has coordinates (2, 7). Write AB as a column vector. AB = [1] f p
1 marks
Mark scheme: 10 − 4 1 3
9 y 4 3 2 Q 1 – 4 – 3 – 2 – 1 0 1 2 3 4 x – 1 P – 2 – 3 – 4 (a) Write PQ as a column vector. [1] f p (b) Write 3PQ as a single vector. [1] f p
2 marks
Mark scheme: 9(a) −5 1 3 9(b) −15 1 FT their (a) 9
12 y 4 B 3 2 A C 1 x – 4 – 3 – 2 – 1 0 1 2 3 4 – 1 – 2 – 3 – 4 Points A, B and C are shown on the grid. (a) Write down the coordinates of point C. ( … , … ) [1] (b) On the grid, plot point D so that ABCD is a parallelogram. [1] - 4 (c) On the grid, plot point E so that EA = [2] e 3o.
4 marks
Mark scheme: 12(a) (3, 1) 1 12(b) D plotted at (–2, –1) 1 12(c) E plotted at (1, –2) 2 B1 for E plotted at (1, k) or (k, –2) or 4 AE = − 3
9 Work out. 6 8 (a) + e- 5o e- 1o [1] f p - 4 (b) 3 e 7o [1] f p
2 marks
Mark scheme: 9(a) 14 1 −6 9(b) −12 1 21
5 - 2 7 a = b = e- 7o e 6o Work out a - b . [1] f p
1 marks
Mark scheme: 7 7 1 −13
3 5 10 (a) a = b = e - 4 o e2o Work out. (i) 8b [1] f p (ii) a – b [1] f p 5 (b) Point L has coordinates ( - 3, 6 ) and LM = e- 2o. Find the coordinates of point M. ( … , … ) [1]
3 marks
Mark scheme: 10(a)(i) 40 1 16 10(a)(ii) −2 1 −6 10(b) 2 4 1
14 Work out. 3 - 5 (a) + e- 2o e 7o [1] f p 3 (b) 5 e- 1o [1] f p
2 marks
Mark scheme: 14(a) −2 1 5 14(b) 15 1 −5
2 Points A and B are plotted on the grid. y 4 3 B 2 1 – 3 – 2 – 1 0 1 2 3 x – 1 A – 2 – 3 (a) Write down the coordinates of point B. ( … , … ) [1] (b) Write AB as a vector. [1] f p (c) On the grid, plot point C at (-2, 3). [1]
3 marks
Mark scheme: 2(a) (2, 3) 1 2(b) 4 1 5 2(c) C plotted at (–2, 3) 1
2 - 1 10 p = q = e8o e 4o Find (a) p - q , [1] f p (b) 6p. [1] f p
2 marks
Mark scheme: 10(a) 3 1 4 10(b) 12 1 48
11 The grid shows point P and point R. y 5 P 4 3 2 1 – 5 – 4 – 3 – 2 – 1 0 1 2 3 4 5 x – 1 – 2 – 3 R – 4 – 5 (a) Write down the coordinates of point P. ( … , … ) [1] 3 (b) PQ = e- 2o Mark point Q on the grid. [1] (c) Find QR. QR = [1] f p (d) Complete this statement. [1] PQ + QR = …
4 marks
Mark scheme: 11(a) (−1, 4) 1 11(b) Q marked at (2, 2) 1 11(c) 6 1 FT their point Q 5 11(d) PR 1
- 1 2 8 v = y = e 3o e5o Find (a) v - y [1] f p (b) 2 v . [1] f p
2 marks
Mark scheme: 8(a) −3 1 −2 8(b) −2 1 6
11 3 - 2 a = b = e 7 o e 5o Work out a - 2 b . [2] f p
2 marks
Mark scheme: 11 7 2 7 b B1 for or as answer 3 a 3 4 4 or or in working 10 10
8 - 12 15 F is the point ( 1, - 4 ) , FG = and GH = e- 3o e 35o. Find (a) 3FG [1] f p (b) FG + GH [1] f p (c) the coordinates of the point G. ( … , … ) [1]
3 marks
Mark scheme: 15(a) 24 1 9 15(b) 4 1 32 15(c) (9, –7) 1
4 - 6 13 10 a = b = c = e9o e 1o e- 2o Work out. (a) a + b [1] f p (b) 3c [1] f p
2 marks
Mark scheme: 10(a) −2 1 10 10(b) 39 1 −6
15 y 5 B 4 3 2 A 1 x – 4 –3 –2 –1 0 1 2 3 4 5 6 7 8 Write AB as a column vector. AB = [1] f p
1 marks
Mark scheme: 15 −10 1 3
5 6 10 a = b = e- 7o e- 7o Work out a - b . [1] f p
1 marks
Mark scheme: 10 1 1 0
19 y 6 5 4 3 B 2 1 0 x 1 2 3 4 5 6 7 8 3 AB = e o - 2 Mark point A on the grid. [1]
1 marks
Mark scheme: 19 (1, 4) plotted 1