TopicalMathematics 0580Coordinate geometryGradient of linear graphsPaper 3

Gradient of linear graphs — Paper 3 · IGCSE Mathematics 0580

C3.3· 12 questions · 106 marks · 127 min · 2005–2025· Structured questions

Every Cambridge IGCSE Mathematics Paper 3 question on gradient of linear graphs, laid out as 15 A4 pages with the mark scheme below. Nothing is left out. Free to read, no account.

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Questions15 pages

Question 1: (a) For y Examiner's Use 3 2 1 x –3 –2 –1 0 1 2 3 4 5 –1 –2 –3 –4 –5 The simultaneous equations 2x − y = 3 and x + y = 2 can be solved grap…1 / 15
Question 1 (continued)2 / 15
Question 2: For y Examiner's Use B A 6 5 4 3 2 1 x 3 2 1 0 1 2 3 4 5 6 7 8 1 2 3 4 Two straight lines labelled A and B are shown on the grid above. (a)…3 / 15
Question 3: For y Examiner's Use 6 5 4 3 2 1 x –4 –3 –2 –1 0 1 2 3 4 5 6 –1 –2 l –3 (a) Find the gradient of the line l. Answer(a) [2] (b) (i) Complete…4 / 15
Question 4: For y Examiner's Use B 6 4 2 A E C x –4 –2 0 2 4 6 8 10 12 –2 –4 –6 Triangle ABC is drawn on a 1cm2 grid. E is the point (0, 0). (a) Write …5 / 15
Question 4 (continued)6 / 15
Question 5: (a) (i) Complete the table for y = 5 + 3x – x2. For Examiner′s Use x –2 –1 0 1 2 3 4 5 y –5 5 7 5 –5 [3] (ii) On the grid, draw the graph o…7 / 15
Question 5 (continued)Question 6: (a) (i) Write down the gradient of the line y =- 4 x + 7 . ................................................ [1] (ii) Write down the equatio…8 / 15
Question 6 (continued)9 / 15
Question 7: (a) (i) Write down the co-ordinates of the point where the line y = 6x - 3 crosses the y-axis. (................. , .................) [1] …10 / 15
Question 7 (continued)11 / 15
Question 8: The line L is shown on the grid. y 25 20 L 15 10 5 x – 4 – 3 – 2 – 1 0 1 2 3 4 5 – 5 – 10 – 15 (a) Find the equation of the line L in the f…12 / 15
Question 9: The diagram shows a line L and two points, A and B, on a grid. y 66 L 5 A 44 3 2 1 B x – 6 – 5 – 4 – 3 – 2 – 1 00 1 2 3 4 5 6 7 88 – 1 – 2 …13 / 15
Question 10: The grid shows a line L. y 6 5 L 4 3 2 1 – 6 – 5 – 4 – 3 – 2 – 1 0 1 2 3 4 5 6 x – 1 – 2 – 3 – 4 – 5 – 6 (a) Find the equation of line L. G…14 / 15
Question 10 (continued)Question 11: The equation of line L is y = 5x - 3 . (a) Write down the gradient of line L. ................................................. [1] (b) Wri…Question 12: The equation of a line is y =- 5x + 7 . (a) Write down the gradient of this line. ................................................. [1] (b)…15 / 15

Mark scheme12 answers

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Mathematics 0580 · Gradient of linear graphs — Paper 3

IGCSE · topical answer key — answer key (teacher use)

Question

Answer

Marks

1Mark scheme for question 113
2Mark scheme for question 27
3Mark scheme for question 39
4Mark scheme for question 414
5Mark scheme for question 515
6Mark scheme for question 615
7Mark scheme for question 77
8Mark scheme for question 88
9Mark scheme for question 98
10Mark scheme for question 106
11Mark scheme for question 112
12Mark scheme for question 122
QuestionAnswerMarksFrom
1see sheet130580/31 Oct/Nov 2005
2see sheet70580/31 Oct/Nov 2006
3see sheet90580/31 Oct/Nov 2011
4see sheet140580/31 May/June 2012
5see sheet150580/33 Oct/Nov 2013
6see sheet150580/31 May/June 2018
7see sheet70580/32 May/June 2019
8see sheet80580/31 Oct/Nov 2019
9see sheet80580/31 May/June 2021
10see sheet60580/31 May/June 2022
11see sheet20580/31 May/June 2025
12see sheet20580/32 May/June 2025

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Questions as text

Q1 · For y Examiner's Use 3 2 1 x –3 –2 –1 0 1 2 3 4 5 –1 –2 –3 –4 –5 The simultaneous… 0580/31 Oct/Nov 2005

7 (a) For y Examiner's Use 3 2 1 x –3 –2 –1 0 1 2 3 4 5 –1 –2 –3 –4 –5 The simultaneous equations 2x − y = 3 and x + y = 2 can be solved graphically. (i) Which of these equations is shown by the line on the grid above? Answer(a)(i) [1] (ii) Find the gradient of the line on the grid. Answer(a)(ii) [2] (iii) Complete the table below for the other equation. x −1 0 1 2 3 y [2] (iv) Draw this line on the grid above. [1] (v) Use your graphs to write down the solution to the two equations. Give your values correct to 1 decimal place. Answer(a)(v) x = y = [3] (b) Use algebra to solve the following simultaneous equations exactly. For Show all your working. Examiner's Use 2x − y = 3, x + y = 2. Answer(b) x = y = [4]

13 marks

Mark scheme: 7 (a) (i) y = 2x – 3 oe 1 (ii) 2 oe 2 SC1 for gradient of other line (–1) (iii) 3 2 1 0 –1 2 1 for two correct (iv) correct line drawn 1 (v) (x =) 1.6 1.7, or 1.8 3 2 for correct answers not to 1 dp (y =) 0.2, 0.3, or 0.4 or 1 for 1 answer correct (b) eliminating one of the M1 working must be seen variables but second M1 can imply the eliminating the other M1 first variable (√) 1.66 or 5/3 only A1 0.3 or 1/3 only A1 SC1 for 1.67 and 0.333 [13]

This question in 0580/31 Oct/Nov 2005

Q2 · For y Examiner's Use B A 6 5 4 3 2 1 x 3 2 1 0 1 2 3 4 5 6 7 8 1 2 3 4 Two straight lines… 0580/31 Oct/Nov 2006

7 For y Examiner's Use B A 6 5 4 3 2 1 x 3 2 1 0 1 2 3 4 5 6 7 8 1 2 3 4 Two straight lines labelled A and B are shown on the grid above. (a) Find the gradient of line A. Answer(a) [2] (b) The equation of line B can be written as y = mx + c. Find the values of m and c. Answer(b) m = c = [2] (c) (i) On the diagram draw the line which is parallel to B and passes through the point (1,−1). [1] (ii) Write down the equation of this line. Answer(c) (ii) [2]

7 marks

Mark scheme: 7 (a) –1 2 k SC1 for 1 SC1 for − K (b) (m =) 2 1 (c =) 3 1 (c) (i) Correct line drawn. 1 must cross both axes and line A (ii) y = 2x – 3 oe 2ft SC1 for m = 2 or c = –3. Follow through their line for 2 and SC1. 7

This question in 0580/31 Oct/Nov 2006

Q3 · For y Examiner's Use 6 5 4 3 2 1 x –4 –3 –2 –1 0 1 2 3 4 5 6 –1 –2 l –3 (a) Find the… 0580/31 Oct/Nov 2011

5 For y Examiner's Use 6 5 4 3 2 1 x –4 –3 –2 –1 0 1 2 3 4 5 6 –1 –2 l –3 (a) Find the gradient of the line l. Answer(a) [2] (b) (i) Complete the table below for x + 2y = 6 . x 0 2 y 0 [3] (ii) On the grid, draw the line x + 2y = 6 for −4 Y x Y 6 . [2] (c) The equation of the line l is 4x + 3y = 4. Use your diagram to solve the simultaneous equations 4x + 3y = 4 and x + 2y = 6 . Answer(c) x = y = [2]

9 marks

Mark scheme: − 4 rise 5 (a) oe, –1.2 to –1.4 2 B1 for attempt at 3 run (b) (i) 3, 2, 6 3 B1 for each value (ii) Correct continuous line 2ft Minimum length (0,3) to (6,0) B1 for plotting their 3 points (c) x = −2, y = 4 2ft B1 for their x, B1 for their y from their intersections

This question in 0580/31 Oct/Nov 2011

Q4 · For y Examiner's Use B 6 4 2 A E C x –4 –2 0 2 4 6 8 10 12 –2 –4 –6 Triangle ABC is drawn… 0580/31 May/June 2012

6 For y Examiner's Use B 6 4 2 A E C x –4 –2 0 2 4 6 8 10 12 –2 –4 –6 Triangle ABC is drawn on a 1cm2 grid. E is the point (0, 0). (a) Write down the gradient of the line AB. Answer(a) [2] (b) The gradient of BC is – 0.5 . Write down the equation of the line BC in the form y = mx + c. Answer(b) y = [2] (c) Write down the ratio AE : EC. For Give your answer in its simplest form. Examiner's Use Answer(c) : [2] (d) Measure angle ABE. Answer(d) Angle ABE = [1] (e) Triangle ABE is similar to triangle BCE. Explain what the word similar tells you about the triangles ABE and BCE. Answer(e) [2] (f) Calculate the area of triangle ABC. Answer(f) cm2 [3] (g) ABCD is a rectangle. (i) Mark point D on the grid. [1] (ii) Write down the co-ordinates of D. Answer(g)(ii) ( , ) [1]

14 marks

Mark scheme: (e) 6 × 10–3 4 M1 ‘50’ × ‘120’ figs seen in area calculation A1 for 6000 seen (implied by 0.006 later) M1 for dividing by 1000², 0.05 & 0.12 seen or ×10–6 oe somewhere B1 ft from ‘their 0.006’ provided SF power is –ve Or SC1 for 0.6 × 10–2 oe 9 (a) (i) 226 to 226.224 cm³ 3 M1 π × 3² × 8 B1 for units : cm³ (ii) 8 cao www 4 B1 1500 used M1ft 3 × their (a)(i) 4 their 1500 M1ft 3 × their (a)(i) 4 16 (b) 5.09 (5.092 to 5.10) 2 M1 π (c) 148 cm² 3 M2 for 2 × 4 × 5 + 2 × 4 × 6 + 2 × 5 × 6 SC1 for 2 × 4 × 5 oe or 4 × 5 + 4 × 6 + 5 × 6 implied by 40, 48, 60 or 74, or list of 20, 20, 24, 24, 30, 30 (d) (i) mv oe 1 (ii) msv oe 1ft Ft (d)(i) × s (iii) 1000 msv oe 1ft Ft (d)(ii) × 1000

This question in 0580/31 May/June 2012

Q5 · Complete the table for y = 5 + 3x – x2 0580/33 Oct/Nov 2013

5 (a) (i) Complete the table for y = 5 + 3x – x2. For Examiner′s Use x –2 –1 0 1 2 3 4 5 y –5 5 7 5 –5 [3] (ii) On the grid, draw the graph of y = 5 + 3x – x2 for –2 Y x Y 5. y 8 7 6 5 4 3 2 1 x –2 –1 0 1 2 3 4 5 –1 –2 –3 –4 –5 –6 [4] (b) Use your graph to solve the equation 5 + 3x – x2 = 0 . Answer(b) x = … or x = … [2] (c) (i) On the grid, draw the line of symmetry of y = 5 + 3x – x2. [1] For Examiner′s Use (ii) Write down the equation of this line of symmetry. Answer(c)(ii) … [1] (d) (i) On the grid, draw a straight line from (–1, 1) to (3, 5). [1] (ii) Work out the gradient of this line. Answer(d)(ii) … [2] (iii) Write down the equation of this line in the form y = mx + c. Answer(d)(iii) y = … [1] _____________________________________________________________________________________

15 marks

Mark scheme: 5 (a) (i) 1, 7, 1 1, 1, 1 (ii) 8 points correctly plotted P3FT P2FT for 6 or 7 correct P1FT for 4 or 5 correct Correct smooth curve through all 8 C1 correct points IGCSE – October/November 2013 0580 33 (b) –1.1 to –1.3 and 4.1 to 4.3 1FT, 1FT (c) (i) Line x = 1.5 drawn 1 (ii) x = 1.5 oe 1FT Equation of their line in (c)(i) (d) (i) Ruled continuous line drawn 1 rise (ii) 1 2 M1 for for their line run (iii) [y =] x + 2 1FT their (d)(ii) + their 2

This question in 0580/33 Oct/Nov 2013

Q6 · Write down the gradient of the line y =- 4 x + 7 0580/31 May/June 2018

10 (a) (i) Write down the gradient of the line y =- 4 x + 7 . … [1] (ii) Write down the equation of a line parallel to y = 2x + 3 . y = … [1] (iii) Write down the co-ordinates of the point where the graph of y = 6x - 5 crosses the y-axis. ( … , … ) [1] (iv) The point (k, 7) lies on the line y = 4x - 3 . Find the value of k. k = … [2] (b) (i) Complete the table of values for y = x 2 - x - 5 . x - 3 - 2 - 1 0 1 2 3 4 y 7 - 3 - 5 [3] (ii) On the grid, draw the graph of y = x 2 - x - 5 for - 3 G x G 4 . y 8 7 6 5 4 3 2 1 x –3 –2 –1 0 1 2 3 4 –1 –2 –3 –4 –5 –6 [4] (iii) Write down the co-ordinates of the lowest point on the graph. ( … , … ) [1] (iv) (a) On the grid, draw the line of symmetry of the graph. [1] (b) Write down the equation of this line. … [1]

15 marks

Mark scheme: 10(a)(i) – 4 1 10(a)(ii) 2x + k k ≠ 3 1 10(a)(iii) (0, –5) 1 10(a)(iv) 2.5 2 M1 for 7 = 4k – 3 or better 10(b)(i) 1, –5, –3, 1, 7 3 B2 for 4 correct B1 for 3 correct 10(b)(ii) Correct smooth curve 4 B3FT for 8 or 7 correct plots or B2FT for 5 or 6 correct plots or B1FT for 3 or 4 correct plots 10(b)(iii) (0.5, h ) 1 where –5.5 ⩽ h < –5 10(b)(iv)(a) Correct line of symmetry drawn 1 10(b)(iv)(b) x = 0.5 oe 1

This question in 0580/31 May/June 2018

Q7 · Write down the co-ordinates of the point where the line y = 6x - 3 crosses the y-axis 0580/32 May/June 2019

8 (a) (i) Write down the co-ordinates of the point where the line y = 6x - 3 crosses the y-axis. ( … , … ) [1] (ii) Write down the equation of the straight line that • passes through the origin and • is parallel to y = 6x - 3 . … [1] (b) y 4 3 2 1 – 4 – 3 – 2 – 1 0 1 2 3 4 x – 1 – 2 – 3 – 4 (i) On the grid, draw the line through the point (- 3, - 2) that is perpendicular to the y-axis. [1] (ii) On the grid, draw the line y =- 2x . [1] (c) The equations of two straight lines are y = 3x + 13 and y = 7x - 3 . Use algebra to solve these two simultaneous equations to find the co-ordinates of the point where the lines meet. You must show all your working. ( … , … ) [3] Question 9 is printed on the next page.

7 marks

Mark scheme: 8(a)(i) (0, −3) 1 8(a)(ii) y = 6 x oe 1 8(b)(i) y = −2 drawn, ruled 1 8(b)(ii) y = −2 x drawn, ruled 1 8(c) For correct method seen to M1 3 x + 13 = 7 x − 3 oe eliminate one variable x = 4 A1 y = 25 A1 If M0 scored, SC1 for 2 values that substitute to give y – 3x rounding to 13.0, or y – 7x rounding to −3.0 or SC1 if no working shown, but 2 correct answers given

This question in 0580/32 May/June 2019

Q8 · The line L is shown on the grid 0580/31 Oct/Nov 2019

6 The line L is shown on the grid. y 25 20 L 15 10 5 x – 4 – 3 – 2 – 1 0 1 2 3 4 5 – 5 – 10 – 15 (a) Find the equation of the line L in the form y = mx + c . y = … [3] (b) The equation of a different line is y = 3x - 4 . (i) Write down the gradient of this line. … [1] (ii) Write down the co-ordinates of the point where this line crosses the y˗axis. ( … , … ) [1] (c) On the grid, draw the graph of y =- 2x + 1 for - 4 G x G 5 . [3]

8 marks

Mark scheme: 6(a) 4x + 2 3 B2 for 4x + c or B1 for mx + 2, m ≠ 0 4k and M1 for rise/run of k 6(b)(i) 3 1 6(b)(ii) (0, –4) 1 6(c) Correct ruled line 3 B2 for 2 correct points plotted from x = –4 to x = 5 or B1 for one correct point plotted soi or M1 for line with gradient –2 If B0 or M0 scored, SC1 for a correct table with a minimum of 3 correct coordinates

This question in 0580/31 Oct/Nov 2019

Q9 · The diagram shows a line L and two points, A and B, on a grid 0580/31 May/June 2021

4 The diagram shows a line L and two points, A and B, on a grid. y 66 L 5 A 44 3 2 1 B x – 6 – 5 – 4 – 3 – 2 – 1 00 1 2 3 4 5 6 7 88 – 1 – 2 (a) Write down the coordinates of point A. ( … , … ) [1] (b) (i) Find the gradient of line L. … [1] (ii) Write down the equation of line L in the form y = mx + c . y = … [2] (c) (i) Draw a line that is perpendicular to line L and passes through the point A. [1] (ii) This line crosses the x-axis at point C. Mark point C on the grid and write down the coordinates of point C. ( … , … ) [1] (iii) Find, by measuring, the perimeter of triangle ABC. … cm [2]

8 marks

Mark scheme: 4(a) ( −2,4) 1 4(b)(i) −0.5 oe 1 4(b)(ii) [ y =] − 0.5x + 3 2 FT their (b)(i) B1FT for [ y =] − 0.5x + c or for [ y =] their (b)(i)x + c or for [ y =] mx + 3 4(c)(i) Correct ruled line drawn 1 4(c)(ii) (–4, 0) 1 FT their (c)(i) for x-coord 4(c)(iii) 23.0 to 23.8 2 FT provided their 3 lengths seen M1 for AB + AC + BC soi or B1FT for AB = 8.7 to 9.1 or BC = 10 or AC = 4.3 to 4.7

This question in 0580/31 May/June 2021

Q10 · The grid shows a line L 0580/31 May/June 2022

8 The grid shows a line L. y 6 5 L 4 3 2 1 – 6 – 5 – 4 – 3 – 2 – 1 0 1 2 3 4 5 6 x – 1 – 2 – 3 – 4 – 5 – 6 (a) Find the equation of line L. Give your answer in the form y = mx + c . y = … [2] (b) (i) Complete the table of values for y = 2x + 5 . x −5 −3 0 y −5 5 [1] (ii) On the grid, draw the graph of y = 2x + 5 . [1] (c) Write down the coordinates of the point which lies on both line L and the graph of y = 2x + 5 . ( … , … ) [1] (d) Write down the equation of the line that is parallel to y = 2x + 5 and passes through the point (0, 18). … [1]

6 marks

Mark scheme: 8(a) 1 2 M1 for rise ÷ run [y =] – + 2 or for [y =] kx + 2 (k ≠ 0) 2x 1 or [y =] – 2x + j oe 8(b)(i) −1 1 8(b)(ii) Correct ruled line on grid 1 8(c) −1.2, 2.6 1 FT Line L and their (b)(ii) 8(d) y = 2x + 18 1

This question in 0580/31 May/June 2022

Q11 · The equation of line L is y = 5x - 3 0580/31 May/June 2025

12 The equation of line L is y = 5x - 3 . (a) Write down the gradient of line L. … [1] (b) Write down the equation of a line parallel to line L. y = … [1]

2 marks

Mark scheme: 12(a) 5 1 12(b) 5x + k (k ≠ −3) 1

This question in 0580/31 May/June 2025

Q12 · The equation of a line is y =- 5x + 7 0580/32 May/June 2025

15 The equation of a line is y =- 5x + 7 . (a) Write down the gradient of this line. … [1] (b) Find the coordinates of the point where this line crosses the y-axis. ( … , … ) [1]

2 marks

Mark scheme: 15(a) −5 1 15(b) 0 , 7 1

This question in 0580/32 May/June 2025