16.2· 14 questions · 14 marks · 17 min · 2004–2019· Multiple choice
Every Cambridge A Level Biology Paper 1 question on the roles of genes in, laid out as 4 A4 pages with the mark scheme below. Nothing is left out. Free to read, no account.




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4 / 4Answers below. Sit the paper first if you are practising.
Pastlit
Biology 9700 · The roles of genes in — Paper 1
A Level · topical answer key — answer key (teacher use)
Question
Answer
Marks
| Question | Answer | Marks | From |
|---|---|---|---|
| 1 | B | 1 | 9700/11 Oct/Nov 2004 |
| 2 | A | 1 | 9700/12 May/June 2010 |
| 3 | A | 1 | 9700/13 May/June 2010 |
| 4 | D | 1 | 9700/12 Oct/Nov 2010 |
| 5 | B | 1 | 9700/11 Oct/Nov 2011 |
| 6 | D | 1 | 9700/13 May/June 2013 |
| 7 | C | 1 | 9700/13 Oct/Nov 2013 |
| 8 | D | 1 | 9700/13 May/June 2014 |
| 9 | A | 1 | 9700/13 Oct/Nov 2014 |
| 10 | B | 1 | 9700/13 Oct/Nov 2015 |
| 11 | D | 1 | 9700/13 Oct/Nov 2016 |
| 12 | B | 1 | 9700/13 Oct/Nov 2017 |
| 13 | B | 1 | 9700/13 Oct/Nov 2017 |
| 14 | B | 1 | 9700/13 May/June 2019 |
22 In the DNA sequence for sickle cell anaemia, adenine replaces thymine in a CTT triplet, forming the triplet CAT. During synthesis of the sickle cell haemoglobin molecule, the amino acid valine is incorporated instead of glutamic acid. What is the anticodon in the transfer RNA molecule carrying this valine? A CAT B CAU C GTA D GUA
1 marks
Answer: B
23 What is the minimum number of base substitutions required to change the nucleotide sequence of the HbA (normal) allele to the HbS (sickle cell) allele? A 1 B 2 C 3 D 4
1 marks
Answer: A
39 What is the minimum number of base substitutions required to change the nucleotide sequence of the HbA (normal) allele to the HbS (sickle cell) allele? A 1 B 2 C 3 D 4
1 marks
Answer: A
22 S and T are products of a biochemical pathway. A different enzyme, coded for by different specific genes, catalyses each step in the pathway. gene 1 gene 2 gene 3 S enzyme 3 enzyme 1 enzyme 2 P Q R enzyme 4 T gene 4 What is the possible outcome to the pathway if a mutation in gene 3 leads to an inactive enzyme? A There is a decrease in the activity of gene 1 and gene 2. B There is an accumulation of product S. C There is an increase in the rate of reaction of enzyme 4. D There is an increase in the production of T.
1 marks
Answer: D
19 A gene codes for the production of a protein, p53, that binds to damaged DNA during interphase and prevents its replication. A carcinogen in cigarette smoke mutates this gene. Which statement explains why this mutation may cause cancer? A Lack of p53 allows cells to undergo mitosis. B Lack of p53 allows cells with damaged DNA to replicate. C The carcinogen in cigarette smoke increases the rate of cell division. D The p53 causes uncontrolled cell division.
1 marks
Answer: B
21 Gene mutations in either the BRCA71 or the BRCA2 genes are responsible for the majority of hereditary breast cancer in humans. The proteins produced by the two genes migrate to the nucleus where they interact with other proteins, such as those produced by the tumour suppressor gene, p53 and the DNA repair gene, RADS1. Which combination of gene activity is most likely to result in breast cancer? gene OAS. 53 RAD51 A Vv Vv J B Vv V x c V x J D x x x key / = gene produces normal protein X =gene produces abnormal protein or no protein
1 marks
Answer: D
20 Which term best describes the length of DNA that codes for the synthesis of a polypeptide? A anticodon B codon C gene D nucleotide
1 marks
Answer: C
21 The statements are about genes and proteins involved in breast cancer. e The protein coded by the BRAC7 gene inhibits the growth of breast cancer cells. e The protein coded by the RAD57 gene is required for the repair of damaged DNA. Which combination of genes is most likely to result in breast cancer? gene BRAC1 RAD51 v v key ¥ =normal active gene X = mutated gene 0 OW D> ~ «K & x v x
1 marks
Answer: D
18 The statements are about genes and proteins, involved in breast cancer. e The protein coded by the BRAC7 gene inhibits the growth of breast cancer cells. e The protein coded by the p53 gene suppresses tumours. Which combination of genes is most likely to result in breast cancer? gene BRAC1 p53 A x x B x J Cc J x D J J key ¥ =normal active gene X = mutated gene
1 marks
Answer: A
11 Haemoglobin, a globular protein, consists of four polypeptide chains, two alpha chains and two beta chains. In normal individuals, in the DNA which codes for each beta chain, the sixth triplet has a code for glutamic acid. In individuals with sickle cell anaemia this base triplet mutates and codes for valine. What does this mutation change in the haemoglobin molecule? A the iron content B the primary structure C the quaternary structure D the secondary structure
1 marks
Answer: B
18 Gene mutations in either the BRCA7 or the BRCA2 genes are responsible for the majority of hereditary breast cancer in humans. The proteins produced by the two genes migrate to the nucleus where they interact with other proteins, such as those produced by the tumour suppressor gene, p53, and the DNA repair gene, RADS1. Which combination of gene activity is most likely to result in breast cancer? gene Ona > p53 RAD51 A J J V B J J x Cc J x V D x x x key / = gene produces normal protein X =gene produces abnormal protein or no protein
1 marks
Answer: D
24 A gene codes for the sequence of amino acids in a single polypeptide. Haemoglobin consists of two α-globins and two β-globins. How many genes are needed to code for a single haemoglobin molecule? A 1 B 2 C 4 D 8
1 marks
Answer: B
25 A single substitution in an allele of the gene coding for haemoglobin results in sickle cell haemoglobin. The mRNA sequence for three amino acids for normal haemoglobin is shown. CCUGAAGAG The mRNA sequence for sickle cell haemoglobin is shown. CCUGUAGAG The table shows some of the triplet codes for two amino acids. DNA triplet codes amino acid CTC Glu CTT Glu CAT Val CAC Val Which row is correct for the substituted DNA nucleotide of the allele and the substituted amino acid of the protein? DNA new amino nucleotide acid A A Glu B A Val C T Glu D T Val
1 marks
Answer: B
24 A gene codes for the production of a protein, p53, that binds to damaged DNA during interphase and prevents its replication. A carcinogen in cigarette smoke mutates this gene. Which statement explains why this mutation may cause cancer? A Cells with no p53 are allowed to undergo mitosis. B Cells with no p53 allow their damaged DNA to replicate. C The carcinogen in cigarette smoke increases the rate of cell division. D The p53 causes uncontrolled cell division.
1 marks
Answer: B