TopicalMathematics 0580TrigonometryPythagoras’ theorem and trigonometryPaper 2

Pythagoras’ theorem and trigonometry — Paper 2 · IGCSE Mathematics 0580

E6.6· 12 questions · 54 marks · 65 min · 2013–2025· Structured questions

Every Cambridge IGCSE Mathematics Paper 2 question on pythagoras’ theorem and trigonometry, laid out as 12 A4 pages with the mark scheme below. Nothing is left out. Free to read, no account.

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Questions12 pages

Question 1: For Examiner′s F C Use 6 cm NOT TO SCALE D A 5 cm E 12 cm B The diagram shows a triangular prism of length 12 cm. Triangle ABC is a cross s…1 / 12
Question 2: A B NOT TO SCALE 5 cm D C 13 cm F E 4 cm H G The diagram shows a cuboid ABCDEFGH. AE = 5 cm, EH = 4 cm and AG = 13 cm. Calculate the angle …2 / 12
Question 3: P Q NOT TO 2 cm SCALE D C 3 cm A 4 cm B The diagram shows a prism of length 4 cm. The cross section is a right-angled triangle. BC = 3 cm a…3 / 12
Question 4: C B 18 cm NOT TO SCALE 13.5 cm 21 cm D E A C lies on a circle with diameter AD. B lies on AC and E lies on AD such that BE is parallel to C…4 / 12
Question 5: F G NOT TO SCALE E H B C 5.5 cm A 20 cm D The diagram shows cuboid ABCDEFGH of length 20 cm and width 5.5 cm. The volume of the cuboid is 4…5 / 12
Question 6: H G NOT TO SCALE E F 6 cm C D 6 cm A B 8 cm The diagram shows a cuboid. AB = 8cm , AD = 6cm and DH = 6cm . Calculate angle HAF. Angle HAF =…6 / 12
Question 7: Q NOT TO SCALE P D C 4 cm 7 cm A B 5 cm The diagram shows a triangular prism ABCDQP of length 7 cm. The cross-section is triangle PAB with …7 / 12
Question 8: H G E F 9.2 cm NOT TO SCALE D C 4.5 cm A B 15.1 cm The diagram shows a cuboid ABCDEFGH. AB = 15.1 cm, BC = 4.5 cm and CG = 9.2 cm. Calculat…8 / 12
Question 9: B 6.7 cm 81° A NOT TO 5.9 cm SCALE C Calculate the area of triangle ABC. ........................................... cm2 [2]9 / 12
Question 10: 9.1 cm E F 6.5 cm A B NOT TO SCALE H G 4 cm D C The diagram shows a cuboid. HD = 4 cm, EH = 6.5 cm and EF = 9.1 cm. Calculate the angle bet…10 / 12
Question 11: W V 4 cm NOT TO SCALE D C 5 cm A 15 cm B The diagram shows a triangular prism with cross-section triangle BCV. Angle BCV = 90° , BC = 5cm ,…11 / 12
Question 12: NOT TO E SCALE D 18 cm 6 cm 60° A B C 17 cm The quadrilateral ACDE is formed by two right-angled triangles ABE and BCD. AC = 17 cm, AE = 18…12 / 12

Mark scheme12 answers

Answers below. Sit the paper first if you are practising.

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Mathematics 0580 · Pythagoras’ theorem and trigonometry — Paper 2

IGCSE · topical answer key — answer key (teacher use)

Question

Answer

Marks

1Mark scheme for question 14
2Mark scheme for question 23
3Mark scheme for question 34
4Mark scheme for question 45
5Mark scheme for question 55
6Mark scheme for question 66
7Mark scheme for question 74
8Mark scheme for question 84
9Mark scheme for question 92
10Mark scheme for question 104
11Mark scheme for question 114
12Mark scheme for question 129
QuestionAnswerMarksFrom
1see sheet40580/21 May/June 2013
2see sheet30580/21 May/June 2017
3see sheet40580/22 Oct/Nov 2017
4see sheet50580/21 May/June 2020
5see sheet50580/21 May/June 2020
6see sheet60580/22 May/June 2020
7see sheet40580/22 Feb/March 2023
8see sheet40580/21 Oct/Nov 2023
9see sheet20580/21 May/June 2024
10see sheet40580/21 May/June 2024
11see sheet40580/23 May/June 2024
12see sheet90580/22 Feb/March 2025

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Questions as text

Q1 · For Examiner′s F C Use 6 cm NOT TO SCALE D A 5 cm E 12 cm B The diagram shows a… 0580/21 May/June 2013

23 For Examiner′s F C Use 6 cm NOT TO SCALE D A 5 cm E 12 cm B The diagram shows a triangular prism of length 12 cm. Triangle ABC is a cross section of the prism. Angle BAC = 90°, AC = 6 cm and AB = 5 cm. Calculate the angle between the line CE and the base ABED. Answer … [4] _____________________________________________________________________________________

4 marks

Mark scheme: 23 4 M1 for recognition of angle CEA 24.8 or 24.77 to 24.78 M1 for 122 + 52 6 M1 for tan = oe their AE

This question in 0580/21 May/June 2013

Q2 · A B NOT TO SCALE 5 cm D C 13 cm F E 4 cm H G The diagram shows a cuboid ABCDEFGH 0580/21 May/June 2017

13 A B NOT TO SCALE 5 cm D C 13 cm F E 4 cm H G The diagram shows a cuboid ABCDEFGH. AE = 5 cm, EH = 4 cm and AG = 13 cm. Calculate the angle between the line AG and the base EFGH of the cuboid. … [3]

3 marks

Mark scheme: 13 22.6 or 22.61 to 22.62 3 5 M2 forr sin [=] ooe 13 or M1 for identifyinng angle AGE

This question in 0580/21 May/June 2017

Q3 · P Q NOT TO 2 cm SCALE D C 3 cm A 4 cm B The diagram shows a prism of length 4 cm 0580/22 Oct/Nov 2017

26 P Q NOT TO 2 cm SCALE D C 3 cm A 4 cm B The diagram shows a prism of length 4 cm. The cross section is a right-angled triangle. BC = 3 cm and CQ = 2 cm. Calculate the angle between the line AQ and the base, ABCD, of the prism. … [4]

4 marks

Mark scheme: 26 21.8 or 21.80… 4 2 M3 for tan = oe 32 + 4 2 or M1 for 3 2 + 4 2 or 32 + 4 2 + 2 2 and M1 for recognising angle QAC

This question in 0580/22 Oct/Nov 2017

Q4 · C B 18 cm NOT TO SCALE 13.5 cm 21 cm D E A C lies on a circle with diameter AD 0580/21 May/June 2020

13 C B 18 cm NOT TO SCALE 13.5 cm 21 cm D E A C lies on a circle with diameter AD. B lies on AC and E lies on AD such that BE is parallel to CD. AB = 21 cm, CD = 18 cm and BE = 13.5 cm. Work out the radius of the circle. … cm [5]

5 marks

Mark scheme: 13 16.6 or 16.64… 5 18 M2 for 21× = [ AC ] oe 13.5 13.5 18 or M1 for scale factor or oe soi 18 13.5 Then Pythagoras method: and M2 for 28 2 + 18 2 [÷ 2] or ( theirAC ) 2 + 18 2 [÷ 2] or M1 for AD 2 = 28 2 + 18 2 2 2 2 or AD = ( theirAC ) + 18 OR alternative trigonometry method e.g. 21 M1 for tan E = 13.5 18 and M1 for AD = cos their 57.3

This question in 0580/21 May/June 2020

Q5 · F G NOT TO SCALE E H B C 5.5 cm A 20 cm D The diagram shows cuboid ABCDEFGH of length 20… 0580/21 May/June 2020

19 F G NOT TO SCALE E H B C 5.5 cm A 20 cm D The diagram shows cuboid ABCDEFGH of length 20 cm and width 5.5 cm. The volume of the cuboid is 495 cm 3. Find the angle between the line AG and the base of the cuboid ABCD. … [5]

5 marks

Mark scheme: 19 12.2 or 12.24… 5 4.5 M4 for tan = oe 20 2 + 5.5 2 or M1 for recognising angle GAC 495 M1 for 20 × 5.5 M1 for 20 2 + 5.5 2 or 20 2 + 5.5 2 + (their 4. 5) 2 their 4.5 M1 for tan = oe 20 2 + 5.5 2

This question in 0580/21 May/June 2020

Q6 · H G NOT TO SCALE E F 6 cm C D 6 cm A B 8 cm The diagram shows a cuboid 0580/22 May/June 2020

27 H G NOT TO SCALE E F 6 cm C D 6 cm A B 8 cm The diagram shows a cuboid. AB = 8cm , AD = 6cm and DH = 6cm . Calculate angle HAF. Angle HAF = … [6]

6 marks

Mark scheme: 27 64.9 or 64.89 to 64.90 6 + 72 − 100 B5 for [cos =]100 2 × 10 × 72 OR M1 for 82 + 62 M1 for 62 + 62 (theirAF ) 2 + ( theirAH ) 2 − ( theirHF ) 2 M2 for 2 × (theirAF ) × (theirAH ) or M1 for (theirHF)2 = (theirAF)2 + (their AH)2 – 2 × (theirAF) × (their AH) cos(HAF) AF, AH etc from correct method

This question in 0580/22 May/June 2020

Q7 · Q NOT TO SCALE P D C 4 cm 7 cm A B 5 cm The diagram shows a triangular prism ABCDQP of… 0580/22 Feb/March 2023

22 Q NOT TO SCALE P D C 4 cm 7 cm A B 5 cm The diagram shows a triangular prism ABCDQP of length 7 cm. The cross-section is triangle PAB with PA = 4 cm , AB = 5 cm and angle PAB = 90° . Calculate the angle between the line PC and the base ABCD. … [4]

4 marks

Mark scheme: 22 24.9 or 24.93 to 24.94 4 4 M3 for tan = oe 5 2 + 7 2 or M2 for 52 + 72 oe or 52 + 72 + 42 oe or M1 for recognition of angle PCA.

This question in 0580/22 Feb/March 2023

Q8 · H G E F 9.2 cm NOT TO SCALE D C 4.5 cm A B 15.1 cm The diagram shows a cuboid ABCDEFGH 0580/21 Oct/Nov 2023

21 H G E F 9.2 cm NOT TO SCALE D C 4.5 cm A B 15.1 cm The diagram shows a cuboid ABCDEFGH. AB = 15.1 cm, BC = 4.5 cm and CG = 9.2 cm. Calculate the angle that the diagonal BH makes with the face ADHE. … [4] Question 22 is printed on the next page.

4 marks

Mark scheme: 21 55.9 or 55.85… 4 15.1 M3 for tan[…] = oe 4.5 2 + 9.2 2 or M2 for [AH2 =] 4.52 + 9.22 or [BH2 =] 4.52 + 9.22 + 15.12 or M1 for recognising angle BHA if 0 scored SC1 for [angle BHD =] 59.7[1…] or 59.72

This question in 0580/21 Oct/Nov 2023

Q9 · B 6.7 cm 81° A NOT TO 5.9 cm SCALE C Calculate the area of triangle ABC 0580/21 May/June 2024

17 B 6.7 cm 81° A NOT TO 5.9 cm SCALE C Calculate the area of triangle ABC. … cm2 [2]

2 marks

Mark scheme: 17 19.5 or 19.52… 2 1 M1 for × 6.7 × 5.9 × sin 81 oe 2

This question in 0580/21 May/June 2024

Q10 · 9.1 cm E F 6.5 cm A B NOT TO SCALE H G 4 cm D C The diagram shows a cuboid 0580/21 May/June 2024

21 9.1 cm E F 6.5 cm A B NOT TO SCALE H G 4 cm D C The diagram shows a cuboid. HD = 4 cm, EH = 6.5 cm and EF = 9.1 cm. Calculate the angle between CE and the base CDHG. … [4]

4 marks

Mark scheme: 21 33.2 or 33.18… 4 6.5 M3 for tan  oe 4 2  9.12 or M2 for 4 2  9.12 oe or 4 2  9.12  6.5 2 oe or M1 for recognising the angle ECH

This question in 0580/21 May/June 2024

Q11 · W V 4 cm NOT TO SCALE D C 5 cm A 15 cm B The diagram shows a triangular prism with… 0580/23 May/June 2024

24 W V 4 cm NOT TO SCALE D C 5 cm A 15 cm B The diagram shows a triangular prism with cross-section triangle BCV. Angle BCV = 90° , BC = 5cm , CV = 4cm and AB = 15cm . Calculate the angle between AV and the base ABCD. … [4]

4 marks

Mark scheme: 24 14.2 or 14.19 to 14.20 4 4 M3 for tan = oe 15 2  5 2 or M2 for 15 2  5 2 or15 2  52  4 2 or M1 for recognition of angle VAC

This question in 0580/23 May/June 2024

Q12 · NOT TO E SCALE D 18 cm 6 cm 60° A B C 17 cm The quadrilateral ACDE is formed by two… 0580/22 Feb/March 2025

18 NOT TO E SCALE D 18 cm 6 cm 60° A B C 17 cm The quadrilateral ACDE is formed by two right-angled triangles ABE and BCD. AC = 17 cm, AE = 18 cm and BD = 6 cm. (a) Show that CD = 10 cm. [5] (b) Find the perimeter of the quadrilateral ACDE. Give your answer in the form p + k q . … cm [4]

9 marks

Mark scheme: 18(a) AB M1 = cos60 or [AB = ] 18cos 60 18 1 A1 cos 60 = and [AB =] 9 2 Correct use of Pythagoras’ theorem M1 i.e. [CD2 =] 6 2 + (17 −theirAB ) 2 oe Correct evaluation for their AB M1 [CD2 =] 36 + 64 or CD = 36 + 64 100 = 10 A1 Dep on M1A1M1M1 18(b) 39 + 9 3 4 B3 for [BE =] 9 3 or for answer k + 9 3 or for answer equivalent to 39 + 9 3 but not in required form OR BE 3 M2 for = oe or better 18 2 BE or M1 for = sin60 oe or better 18 M1 for 18 + 17 + 10 + their BE – 6 oe OR M2 for 182 −their 92 oe or M1 for BE2 + (their 9)2 = 182 oe M1 for 18 + 17 + 10 + their BE – 6 oe

This question in 0580/22 Feb/March 2025