C2.1· 23 questions · 78 marks · 94 min · 2009–2025· Structured questions
Every Cambridge IGCSE Mathematics Paper 1 question on introduction to algebra, laid out as 12 A4 pages with the mark scheme below. Nothing is left out. Free to read, no account.
![Question 1: z = 2x – y For Examiner's (a) Find z when x = –3 and y = 7. Use Answer(a) z = [1] (b) Make x the subject of the formula. Answer(b) x = [2]](https://img.pastlit.com/crops/2cd2f0a6-59d7-4645-88e0-286e35b9db74/q12.webp)
1 / 12
![Question 4: Simplify the expression. p + p + p + p Answer ................................................ [1] ________________________________________…](https://img.pastlit.com/crops/0cd3b717-f4d4-4889-8eb6-bafd28e3e284/q1.webp)
2 / 12
3 / 12![Question 8: (a) s = 4t + 3u Calculate s when t = 2.6 and u = –0.4 . Answer(a) s = ................................................ [2] (b) Solve 5x – 7…](https://img.pastlit.com/crops/e750ec9a-ee37-46c2-b89d-578bcbe1eb55/q19.webp)
4 / 12![Question 10: (a) Simplify. 3p + 5p + p ................................................. [1] (b) Multiply out the brackets. 4(q – 3) ...................…](https://img.pastlit.com/crops/47555cb7-c319-4d48-be19-3866e91f8491/q21.webp)
5 / 12![Question 12: Work out. - 2 - 1 (a) - e 5o e 1o [1] f p - 3 (b) 7 e 4o [1] f p](https://img.pastlit.com/crops/0fee0350-e4f1-477c-8455-a6924583aded/q4.webp)
![Question 13: T = a 2 + 4b Find the value of T when a = 5 and b = 3. T = ............................................... [2]](https://img.pastlit.com/crops/0fee0350-e4f1-477c-8455-a6924583aded/q8.webp)
6 / 12![Question 15: (a) Write down the gradient of the line y = 2x - 3 . ................................................. [1] (b) Complete the table of values…](https://img.pastlit.com/crops/1ecd7499-29c9-4bb9-a644-8829544d1437/q9.webp)
7 / 12
8 / 12
9 / 12
10 / 12
11 / 12
12 / 12Answers below. Sit the paper first if you are practising.
Pastlit
Mathematics 0580 · Introduction to algebra — Paper 1
IGCSE · topical answer key — answer key (teacher use)
Question
Answer
Marks
3
3
6
1
2
3
4
4
2
6
2
2
2
3
4
2
2
2
5
2
2
11
5| Question | Answer | Marks | From |
|---|---|---|---|
| 1 | see sheet | 3 | 0580/11 May/June 2009 |
| 2 | see sheet | 3 | 0580/12 May/June 2010 |
| 3 | see sheet | 6 | 0580/11 May/June 2011 |
| 4 | see sheet | 1 | 0580/12 May/June 2014 |
| 5 | see sheet | 2 | 0580/13 May/June 2014 |
| 6 | see sheet | 3 | 0580/11 Oct/Nov 2014 |
| 7 | see sheet | 4 | 0580/12 Feb/March 2015 |
| 8 | see sheet | 4 | 0580/11 Oct/Nov 2015 |
| 9 | see sheet | 2 | 0580/11 May/June 2016 |
| 10 | see sheet | 6 | 0580/12 Oct/Nov 2016 |
| 11 | see sheet | 2 | 0580/11 May/June 2018 |
| 12 | see sheet | 2 | 0580/12 Oct/Nov 2018 |
| 13 | see sheet | 2 | 0580/12 Oct/Nov 2018 |
| 14 | see sheet | 3 | 0580/12 Feb/March 2020 |
| 15 | see sheet | 4 | 0580/12 Feb/March 2020 |
| 16 | see sheet | 2 | 0580/12 Feb/March 2021 |
| 17 | see sheet | 2 | 0580/12 May/June 2021 |
| 18 | see sheet | 2 | 0580/12 Oct/Nov 2022 |
| 19 | see sheet | 5 | 0580/11 May/June 2023 |
| 20 | see sheet | 2 | 0580/13 Oct/Nov 2023 |
| 21 | see sheet | 2 | 0580/12 Oct/Nov 2024 |
| 22 | see sheet | 11 | 0580/12 May/June 2025 |
| 23 | see sheet | 5 | 0580/13 Oct/Nov 2025 |
12 z = 2x – y For Examiner's (a) Find z when x = –3 and y = 7. Use Answer(a) z = [1] (b) Make x the subject of the formula. Answer(b) x = [2]
3 marks
Mark scheme: 12 (a) (z =) − 13 1cao z + y z y (b) (x =) oe final answer 2 M1 for z + y = 2x or = x − or 2 2 2 –2x = –z – y ± z ± y SC1 for answer of form ± 2
10 When c = 10 and d = −2, find the value of the following expressions. (a) c + 2d Answer(a) [1] (b) 5c2 − cd Answer(b) [2]
3 marks
Mark scheme: 10 (a) 6 1 (b) 520 2 M1 for 5 × 102 − 10 × −2, or better If zero, SC1 for answer of 480 or 2520
19 Piet, Rob and Sam collect model aeroplanes. For Piet has x aeroplanes. Examiner's Rob has 7 more aeroplanes than Piet. Use Sam has three times as many aeroplanes as Piet. (a) Write down an expression, in terms of x, for (i) the number of aeroplanes Rob has, Answer(a)(i) [1] (ii) the number of aeroplanes Sam has. Answer(a)(ii) [1] (b) The total number of aeroplanes is 32. (i) Use the information in part (a) to write down an equation in x. Answer(b)(i) [1] (ii) Solve your equation. Answer(b)(ii) x = [2] (c) Write down the number of aeroplanes Rob has. Answer(c) [1]
6 marks
Mark scheme: 19 (a) (i) x + 7 1 (ii) 3x 1 (b) (i) x+their (a)(i)+their (a)(ii)=32 1ft ft dependent on 2 algebraic expressions in (a) or better (ii) (x =) 5 2ft M1 for 5x = 32 − 7 oe ft their (b)(i) with M1 for ax = b and A1 if answer is an integer. (c) 12 1ft ft their (b)(ii) substituted into their (a)(i) or their (b)(ii) + 7 evaluated correctly
1 Simplify the expression. p + p + p + p Answer … [1] __________________________________________________________________________________________
1 marks
Mark scheme: Qu. Part Answers Mark Part Marks 1 4p 1
14 Find the value of 3a – 5b when a = –4 and b = 2 . Answer … [2] __________________________________________________________________________________________
2 marks
Mark scheme: 14 –22 2 M1 for 3×(–4) –5×2 or B1 for −12 or −10 seen in the working. IGCSE – May/June 2014 0580 13 13
14 To hire a bicycle it costs $6 for each day, plus a fi xed charge of $15. (a) Maria pays $39 to hire a bicycle. How many days does she hire it for? Answer(a) … days [2] (b) Write down a formula for the cost, C dollars, to hire a bicycle for d days. Answer(b) C = … [1] __________________________________________________________________________________________
3 marks
Mark scheme: 14 (a) 4 [days] 2 M1 for (39 − 15) ÷ 6 or 15 + 6 + 6 + 6 + 6 1 (b) [C=] 15 + 6d Final answer
19 Idris has c toy cars. Fadl has twice as many cars as Idris. Baasim has three more cars than Fadl. (a) Write down an expression, in terms of c, to complete each statement. Fadl has … cars. Baasim has … cars. [2] (b) Write down an expression, in terms of c, for the total number of cars the three children have. Give your answer in its simplest form. Answer(b) … [2] __________________________________________________________________________________________
4 marks
Mark scheme: 19 (a) 2c 1 2c + 3 1FT FT is their 2c + 3 provided linear (b) 5c + 3 2FT M1 for c + their 2c + their(2c+3) provided linear
19 (a) s = 4t + 3u Calculate s when t = 2.6 and u = –0.4 . Answer(a) s = … [2] (b) Solve 5x – 7 = 10. Answer(b) x = … [2] __________________________________________________________________________________________
4 marks
Mark scheme: 19 (a) 9.2 2 M1 for 4 × 2.6 + 3 × (–0.4) or better (b) 3.4 2 M1 for one correct step in a 2-step method
12 y = mx + c Find the value of y when m = −2, x = −7 and c = −3. y = … [2]
2 marks
Mark scheme: 12 11 2 M1 for −2 × −7 − 3 soi
21 (a) Simplify. 3p + 5p + p … [1] (b) Multiply out the brackets. 4(q – 3) … [1] (c) Factorise completely. 10t + 15t2 … [2] (d) Solve the simultaneous equations. You must show all your working. 3x + y = 7 5x – y = 17 x = … y = … [2]
6 marks
Mark scheme: 21 (a) 9p final answer 1 (b) 4q – 12 final answer 1 (c) 5t(2 + 3t) final answer 2 M1 for t(10 + 15t) or 5(2t + 3t2) (d) [x = ] 3, [y = ] –2 2 B1 for one correct with working with supporting working If zero scored, SC1 for 2 values satisfying one of the original equations or SC1 if no working shown, but 2 correct answers given
6 Find the value of 7x + 3y when x = 12 and y = -6. … [2]
2 marks
Mark scheme: 6 66 2 B1 for 84 or −18 seen
4 Work out. - 2 - 1 (a) - e 5o e 1o [1] f p - 3 (b) 7 e 4o [1] f p
2 marks
Mark scheme: 4(a) − 1 1 4 4(b) − 21 1 28
8 T = a 2 + 4b Find the value of T when a = 5 and b = 3. T = … [2]
2 marks
Mark scheme: 8 37 2 B1 for 25 or 12
3 (a) The temperature on Monday was -7 °C. The temperature on Tuesday was 5 °C lower than on Monday. The temperature on Wednesday was 8 °C higher than on Tuesday. Find the temperature on Wednesday. … °C [2] (b) Kyra has a faulty thermometer. It always shows the temperature as 2 °C higher than the actual temperature. The temperature on the thermometer is T °C. Write an expression, in terms of T, for the actual temperature. … °C [1]
3 marks
Mark scheme: 3(a) −4 2 B1 for −12 seen or M1 for −7 − 5 + 8 or better 3(b) T – 2 cao 1
9 (a) Write down the gradient of the line y = 2x - 3 . … [1] (b) Complete the table of values for y = 2x - 3 . x -2 0 3 y [2] (c) On the grid, draw the graph of y = 2x - 3 for - 2 G x G 3 . y 4 2 – 2 – 1 0 1 2 3 x – 2 – 4 – 6 – 8 [1]
4 marks
Mark scheme: 9(a) 2 1 9(b) – 7 – 3 3 2 B1 for 2 correct 9(c) Correct ruled graph 1 FT their (b) provided it is a single ruled straight line
7 Work out. - 3 (a) 2 e 7o [1] f p 8 - 5 (b) + e- 6o e 2o [1] f p
2 marks
Mark scheme: 7(a) − 6 1 14 7(b) 3 1 −4
5 The formula for changing a temperature measured in Celsius (°C) to Fahrenheit (°F) is 9C F = + 32 . 5 Use this formula to change 65°C to Fahrenheit. … °F [2]
2 marks
Mark scheme: 5 149 2 M1 for 9 × 65 ÷ 5 [+32]
9 Work out. 6 4 (a) + e- 3o e- 5o [1] f p 3 (b) 6 e- 2o [1] f p
2 marks
Mark scheme: 9(a) 10 1 −8 9(b) 18 1 −12
25 At a cinema, an adult ticket costs $a and a child ticket costs $c. (a) Farah buys 3 adult tickets and 4 child tickets for $38.50 . Complete the equation. 3a + 4c = … [1] (b) Hana buys 6 adult tickets and 5 child tickets for $65.00 . Write down another equation in terms of a and c. … [1] (c) Solve the two simultaneous equations to find the value of a and the value of c. You must show all your working. a = … c = … [3]
5 marks
Mark scheme: 25(a) 38.5 1 25(b) 6a + 5c = 65 1 If 0 scored in part(a) and part(b), SC1 for 3850 in part(a) and 6a + 5c = 6500 in part(b) 25(c) Correctly eliminating one variable M1 Follow through their linear equations [a =] 7.5 A1 [c =] 4 A1 If M0 or M0 FT scored, SC1 for 2 values which satisfy one correct equation or one of their equations
18 A bar of chocolate costs $3 and a bag of sweets costs $5. Write down an expression for the total cost, in dollars, of x bars of chocolate and y bags of sweets. $ … [2]
2 marks
Mark scheme: 18 3x + 5y final answer 2 B1 for 3x or 5y in final answer or for 3x + 5y seen then spoilt
15 In a league, teams gain 4 points for each win, 2 points for each draw and bonus points. A team has x wins, y draws and b bonus points. Write down an expression, in terms of x, y and b, for the total number of points the team has. … [2]
2 marks
Mark scheme: 15 4x + 2y + b final answer 2 B1 for two correct terms in 4x + 2y + b as final answer or correct answer seen and spoilt
14 (a) Complete the table of values for y = ( x + 3 )( x - 2 ) . x -4 -3 -2 -1 0 1 2 3 y 6 -4 -4 [3] (b) On the grid, draw the graph of y = ( x + 3 )( x - 2 ) for - 4 G x G 3 . y 6 5 4 3 2 1 - 4 -3 -2 -1 0 1 2 3 x -1 -2 -3 - 4 -5 -6 -7 [4] (c) Write down the coordinates of the lowest point of the graph. ( … , … ) [1] (d) Write down the equation of the line of symmetry of the graph. … [1] (e) Use your graph to solve the equation ( x + 3)( x - 2) = 3 . x = … or x = … [2]
11 marks
Mark scheme: 14(a) [6], 0, [−4], -6, -6, [−4], 0, 6 3 B2 for 3 correct B1 for 1 correct 14(b) Correct curve 4 B3FT for 7 points correctly plotted or B2FT for 5 points correctly plotted or B1FT for 3 points correctly plotted 14(c) ( −0.5 , k) where −6.6 k −6 1 14(d) x = −0.5 oe 1 14(e) −3.6 to −3.4 2.4 to 2.6 2 FT their curve B1 for each or B1 for y = 3 drawn
11 (a) Sam buys 3 apples at 40 cents each. He also buys 5 peaches. The total cost is $3.45 . Find the cost of 1 peach. … cents [3] (b) Pears cost 55 cents each. Bananas cost 36 cents each. Write an expression, in cents, for the cost of x pears and y bananas. … [2]
5 marks
Mark scheme: 11(a) 45 3 345 − ( 3 40 ) M2 for oe 5 or M1 for 345 – (3 × 40) or B1 for 120 11(b) 55x + 36y final answer 2 B1 for 55x or 36y in final answer or final answer seen and spoilt If 0 scored SC1 for 0.55x + 0.36y