Proportion — Paper 2 · IGCSE Mathematics - International 0607

15 y \ x3 When x = 2, y = 2. Find y when x = 10. y = … [3]

3 marks

Mark scheme: 15 16 3 k oe M1 for y = 3 oe 1000 x M1 for substituting x = 2 and y = 2 in their equation to find k

This question in 0607/23 May/June 2017

10 y is inversely proportional to the square root of x. When x = 9, y = 12. Find y when x = 100. … [3]

3 marks

Mark scheme: 10 3.6 3 9 36 M2 for 12 × oe or y = 100 x y 12 k or M1 for = or y = 9 100 x

This question in 0607/21 Oct/Nov 2017

12 y is proportional to . x When x = 4, y = 2. Find y when x = 64. y = … [3]

3 marks

Mark scheme: 12 0.5 oe 3 k M1 for y = oe x A1 for k = 4 OR y 4 M2 for = or better 2 64

This question in 0607/22 Oct/Nov 2017

8 y varies inversely as x2. When x = 3, y = 4. Find y in terms of x. y = … [2]

2 marks

Mark scheme: 8 36 2 k 2 M1 for y = oe or yx = k x 2 x 2

This question in 0607/21 May/June 2018

17 y is inversely proportional to x + 4 . When x = 5, y = 12. Find y in terms of x. y = … [2]

2 marks

Mark scheme: 17 36 2 k M1 for 12 = x + 4 5 + 4

This question in 0607/22 May/June 2019

11 y varies inversely as x. When x = 16 , y = 9 . Find y in terms of x. y = … [2]

2 marks

Mark scheme: 11 36 2 k y = M1 for y = x x

This question in 0607/21 Oct/Nov 2019

11 y is inversely proportional to x. When x = 9 , y = 2 . Find y in terms of x. y = … [2]

2 marks

Mark scheme: 11 6 2 k M1 for 2 = x 9

This question in 0607/21 May/June 2020

14 y varies inversely as the square root of x. When x = 25 , y = 6 . Find y in terms of x. y = … [2] Question 15 is printed on the next page.

2 marks

Mark scheme: 14 30 2 k y = M1 for y = oe x x

This question in 0607/23 May/June 2020

7 y varies inversely as x. When x = 3 , y = 16 . Find x when y = 6 . x = … [3]

3 marks

Mark scheme: 7 8 3 48 16 × 3 M2 for 6 = or x = x 6 k or M1 for y = or 16 × 3 = 6 × x x

This question in 0607/21 Oct/Nov 2020

14 y varies inversely as x - 3 . When x = 1, y = 4 . Find y in terms of x. y = … [2]

2 marks

Mark scheme: 14 16 2 k y = 2 M1 for y = 2 oe ( x − 3 ) ( x − 3 )

This question in 0607/23 Oct/Nov 2020

16 p varies inversely as the square root of q. When q = 9, p = 12. Find p when q = 16. p = … [3]

3 marks

Mark scheme: 16 9 3 36 B2 for p = oe q 12 × 9 or = p or better 16 k or M1 for p = oe q or 12 × 9 = p × 16

This question in 0607/23 May/June 2021

9 y varies inversely as the square of ( x + 2 ) . When x = 4, y = 0.5 . Find y in terms of x. y = … [2]

2 marks

Mark scheme: 9 18 2 k M1 for oe ( x + 2) 2 ( x + 2) 2

This question in 0607/21 Oct/Nov 2021

11 y is inversely proportional to ( x + 2) 2 . When x = 3, y = 2. (a) Find y in terms of x. y = … [2] (b) Find the positive value of x when y = 0.5 . x = … [2] Question 12 is printed on the next page.

4 marks

Mark scheme: 11(a) 50 2 k M1 for y = ( x  2) 2 ( x  2) 2 11(b) 8 2 M1 for (x + 2)2 = their 50 ÷ 0.5

This question in 0607/23 May/June 2022

9 y is inversely proportional to x3. When x = 5, y = 2 . Find y when x = 10 . y = … [3]

3 marks

Mark scheme: 9 1 3 k oe M1 for y = oe 4 x 3 A1 for k = 250 OR  10  3 M2 for 2 ÷   oe  5  1 y 10 3 or M1 for = oe 2 1 53

This question in 0607/22 Oct/Nov 2022

14 y varies inversely as the square of ( x - 3 ) . When x = 6 , y = 20 . Find the value of y when x = 9 . … [3]

3 marks

Mark scheme: 14 5 3 k M1 for y  oe ( x  3) 2 A1 for k = 180 OR (9  3) 2 M2 for 20  oe (6  3) 2 1 y (9  3) 2 or M1 for  oe 20 1 (6  3) 2

This question in 0607/22 May/June 2023

13 y varies inversely as the square root of ( x + 1) . When x = 8 , y = 5 . Find y in terms of x. y = … [2]

2 marks

Mark scheme: 13 15 2 k M1 for y = oe x + 1 x + 1

This question in 0607/21 Oct/Nov 2023

12 y is inversely proportional to x2. When x = 2 , y = 10 . Find y in terms of x. y = … [2]

2 marks

Mark scheme: 12 40 2 k oe M1 for y = oe x 2 x 2

This question in 0607/23 Oct/Nov 2023

14 y is inversely proportional to the square of x. When x = 2 , y = 12 . Find y when x = 4 . y = … [3]

3 marks

Mark scheme: 14 3 3 k M1 for y = oe x 2 A1 for k = 48 OR  4  2 M2 for 12 ÷   oe  2  or M1 for 12 × 22 = y × 42 oe

This question in 0607/22 Feb/March 2024

12 y is inversely proportional to the square root of x. v is directly proportional to y2. When x = 9 , y = 2 and v = 12 . Find v in terms of x. Give your answer in its simplest form. v = … [4]

4 marks

Mark scheme: 12 108 4 6 B3 for y = and v = 3y2 x x 6 or B2 for y = or v = 3y2 x k or M1 for y = or v = cy2 x OR B2 for v c x M1 for substituting x = 9, v = 12

This question in 0607/23 May/June 2024

7 y varies as the square of ( x + 1) . When y = 18 , x = 2 . Find y when x = 3 . y = … [3]

3 marks

Mark scheme: 7 32 3 M2 for y = 2( x + 1) 2 or 18 y = (2 + 1) 2 (3 + 1) 2 2 18 or M1 for y = k ( x + 1) or 2 (2 + 1)

This question in 0607/21 Oct/Nov 2024

16 y varies inversely as x. When x = 4 , y = 8 . Find y in terms of x. y = … [2] Questions 17 and 18 are printed on the next page.

2 marks

Mark scheme: 16 16 2 k M1 for oe x x

This question in 0607/22 Oct/Nov 2024

21 y is inversely proportional to x3. y = 1 when x = 2. (a) Find y in terms of x. y = … [2] (b) Find x when y = 27. x = … [2]

4 marks

Mark scheme: 21(a) 8 2 k y = final answer M1 for y = x 3 x 3 21(b) 2 2 their 8 M1 for 27 = 3 x 3

This question in 0607/21 May/June 2025