Cambridge IGCSE Mathematics - International 0607 — 2020 May/June Paper 2 · Variant 1
0607/21/M/J/20 · 16 questions · 40 marks · ≈45 min
The question paper and its mark scheme, free to read here and free to download. This is Cambridge’s own paper, exactly as it was sat.
Question paper8 pages
Mark scheme5 pages
Answers below. Sit the paper first if you are practising.
Questions as text
Q1 · A cuboid has a square base of side 10 cm and a volume of 1200 cm3
1 A cuboid has a square base of side 10 cm and a volume of 1200 cm3. Work out the height of the cuboid. ............................................... cm [2]
Mark scheme: Question Answer Marks Partial Marks 1 12 2 M1 for 102 oe seen
Q2 · P = q = - 1 - 2 (a) Find p + q
2 p = q = - 1 - 2 (a) Find p + q . [1] f p (b) A is the point (2, 7). The point A is translated to the point B by the vector p + q . Find the coordinates of B. ( ........................ , ........................ ) [2]
Mark scheme: 2(a) 4 1 −3 2(b) (6, 4) 2 FT their(a) B1 for each coordinate
Q3 · Work out ' 2
3 Work out ' 2 . 4 2 Give your answer as a fraction in its lowest terms. .................................................... [3]
Mark scheme: 3 3 3 3 2 15 50 M2 for × or ÷ oe 10 4 5 20 20 5 2 or M1 for or seen 2 5
Q4 · A truck of length 10 m passes a gate of length 2 m
4 A truck of length 10 m passes a gate of length 2 m. The speed of the truck is 8 m/s. Find the time the truck takes to completely pass the gate. .................................................. s [2]
Mark scheme: 4 1.5 oe 2 10 + 2 M1 for 8
Q5 · Find the volume of a cone with radius 3 cm and perpendicular height 8 cm
5 Find the volume of a cone with radius 3 cm and perpendicular height 8 cm. Give your answer in terms of r. ............................................. cm3 [2]
Mark scheme: 5 24π 2 1 2 M1 for × π × 3 × 8 3
Q6 · 30° NOT TO x cm SCALE 14 cm Work out the value of x
6 30° NOT TO x cm SCALE 14 cm Work out the value of x. x = .................................................... [3]
Mark scheme: 6 7 3 x M2 for = 0.5 oe 14 x or M1 for = sin30 14 or B1 for sin30 = 0.5 oe
Question 7
7 Simplify. 15w 15 (a) 3 3w .................................................... [2] 2 (b) 125y 6 3 ` j .................................................... [2]
Mark scheme: 7(a) 5w12 2 B1 for kw12 or 5 w k 7(b) 25y 4 2 B1 for ky 4 or 25 ky
Q8 · A = 2 r rh + 3rr 2 Rearrange the formula to write h in terms of r, r and A
8 A = 2 r rh + 3rr 2 Rearrange the formula to write h in terms of r, r and A. h = .................................................... [2]
Mark scheme: 8 A − 3πr 2 2 M1 for correct rearrangement for term oe final answer in h 2πr M1 for correct division by 2πr
Q9 · B C NOT TO SCALE x° 70° T A A, B and C are points on a circle
9 B C NOT TO SCALE x° 70° T A A, B and C are points on a circle. TA is a tangent to the circle at A. CA = CB and angle BAT = 70°. Work out the value of x. x = .................................................... [2]
Mark scheme: 9 55 2 B1 for angle C = 70 1 or M1 for (180 − theirC ) 2
Q10 · When Jack sells a computer for $264 he makes a profit of 20%
10 When Jack sells a computer for $264 he makes a profit of 20%. Work out the price Jack paid for the computer. $ .................................................... [2]
Mark scheme: 10 220 2 264 M1 for oe 20 1 + 100
Q11 · Y is inversely proportional to x
11 y is inversely proportional to x. When x = 9 , y = 2 . Find y in terms of x. y = .................................................... [2]
Mark scheme: 11 6 2 k M1 for 2 = x 9
Q12 · 3 log y = 2 log x - log w Find y in terms of x and w
12 3 log y = 2 log x - log w Find y in terms of x and w. y = .................................................... [3]
Mark scheme: 12 2 3 M1 for 2logx = logx2 or 3logy = logy3 x 3 (implied by cube root in answer). w M1 for correct use of p log p − log q = log q
Question 13
13 Rationalise the denominator. 9 7 - 2 .................................................... [2]
Mark scheme: 13 3( 7 + 2) or 3 7 + 6 2 7 + 2 M1 for × 7 + 2
Q14 · Y (4, 2) 0 x In the diagram, the graph passes through the point (4, 2)
14 y (4, 2) 0 x In the diagram, the graph passes through the point (4, 2). Write down the equation of the graph. .................................................... [2]
Mark scheme: 14 8 2 k y = oe M1 for y = oe x x
Question 15
15 Simplify. 3 - a 3p - 6t - ap + 2at .................................................... [3] Question 16 is printed on the next page.
Mark scheme: 15 1 3 B2 for ( p − 2t )(3 − a ) final answer p − 2t or B1 for 3( p − 2t ) − a ( p − 2t ) or for p (3 − a ) − 2t (3 − a )
Q16 · Write as a single fraction in its simplest form
16 Write as a single fraction in its simplest form. 1 2 - x - 3 x .................................................... [3]
Mark scheme: 16 6 − x 3 B1 for x – 2 (x – 3) or better oe final answer M1 for common denominator x(x – 3) x ( x − 3) oe
What was in this paper
The subtopics covered by these 16 questions, and how many questions each got. Open one in a new tab to see every Cambridge question on it.