Cambridge IGCSE Mathematics - International 0607 — 2024 May/June Paper 2 · Variant 3
0607/23/M/J/24 · 14 questions · 40 marks · ≈45 min
The question paper and its mark scheme, free to read here and free to download. This is Cambridge’s own paper, exactly as it was sat.
Question paper8 pages








Mark scheme5 pages
Answers below. Sit the paper first if you are practising.





Questions as text
Q1 · Work out 1.1 - 0.22
1 Work out 1.1 - 0.22 . ................................................. [2]
Mark scheme: Question Answer Marks Partial Marks 1 1.06 oe 2 B1 for 0.04
Question 2
2 Work out - . 4 6 ................................................. [2]
Mark scheme: 2 7 2 9 k 2 oe M1 for k or oe 12 12 12 12 12
Q3 · A quadrilateral has rotational symmetry of order 2 and no lines of symmetry
3 A quadrilateral has rotational symmetry of order 2 and no lines of symmetry. Write down the mathematical name of this quadrilateral. ................................................. [1]
Mark scheme: 3 Parallelogram 1
Question 4
4 Simplify fully. (a) 3a - 6b - 2a + b ................................................. [2] (b) 7 ( x - 3) - 2 ( 2x - 1) ................................................. [2]
Mark scheme: 4(a) a – 5b Final answer 2 B1 for a – kb or ka – 5b 4(b) 3x – 19 Final answer 2 B1 for 3x + k or kx – 19 or M1 for 7x – 21 – 4x + 2
Q5 · One week a shop sells 120 jars of ketchup
5 One week a shop sells 120 jars of ketchup. The table shows the number of jars of each size sold. Size Small Medium Large Number sold 20 70 30 Show this information in a pie chart. [3]
Mark scheme: 5 Correctly labelled pie chart 3 B2 for one sector correct with sector angles 60, 210 and 90 or correct pie chart not labelled or B1 for two of 60, 210 and 90 soi
Q6 · P = 5 # 10 -8 q = 6.8 # 10 -7 Find, giving your answers in standard form, (a) pq…
6 p = 5 # 10 -8 q = 6.8 # 10 -7 Find, giving your answers in standard form, (a) pq ................................................. [2] (b) p + q . ................................................. [2]
Mark scheme: 6(a) 3.4 × 10–14 cao 2 B1 for any equivalent seen 6(b) 7.3 × 10–7 cao 2 B1 for figs 73 or 0.5 × 10–7 or 68 × 10–8 seen
Q7 · A, b and c are prime numbers
7 a, b and c are prime numbers. V = a 2 b 4 c 3 W = a 5 b 3 c Find the lowest common multiple (LCM) of V and W in terms of a, b and c. ................................................. [2]
Mark scheme: 7 a5b4c3 Final answer 2 B1 for a5b4ck or a5bkc3 or akb4c3 or for any common multiple
Q8 · Jasmine drives a distance of a km at a speed of 50 km/h
8 Jasmine drives a distance of a km at a speed of 50 km/h. She then drives a distance of b km at a speed of 60 km/h. She takes a total time of T hours for this journey. Find a formula for T in terms of a and b. T = ................................................ [2]
Mark scheme: 8 a b 2 a b oe B1 for or seen 50 60 50 60
Q9 · In each Venn diagram, shade the given set
9 In each Venn diagram, shade the given set. U U A B P Q A j B ( P k Q ) l [2]
Mark scheme: 9 2 B1 for each
Q10 · The cumulative frequency curve shows the heights of 120 young trees
10 The cumulative frequency curve shows the heights of 120 young trees. 120 100 80 Cumulative 60 frequency 40 20 0 0 1 2 3 4 5 6 Height (metres) Find (a) the median ............................................. m [1] (b) the interquartile range. ............................................. m [2]
Mark scheme: 10(a) 3.4 1 10(b) 0.9 2 B1 for [LQ=] 2.9 or [UQ=] 3.8
Question 11
11 Factorise completely. 48x 2 - 75y 2 ................................................. [3]
Mark scheme: 11 3(4x + 5y)(4x – 5y) Final answer 3 B2 for (12x + 15y)(4x – 5y) or (4x + 5y)(12x – 15y) or B1 for 3(16x2 – 25y2) If 0 scored, SC1 for 48 x 75 y )( 48 x 75 y
Q12 · Y is inversely proportional to the square root of x
12 y is inversely proportional to the square root of x. v is directly proportional to y2. When x = 9 , y = 2 and v = 12 . Find v in terms of x. Give your answer in its simplest form. v = ................................................ [4]
Mark scheme: 12 108 4 6 B3 for y = and v = 3y2 x x 6 or B2 for y = or v = 3y2 x k or M1 for y = or v = cy2 x OR B2 for v c x M1 for substituting x = 9, v = 12
Q13 · Find the value of 4 log 2 + 2 log 5 - log 4
13 Find the value of 4 log 2 + 2 log 5 - log 4 . ................................................. [3] Question 14 is printed on the next page.
Mark scheme: 13 2 3 M1 for one correct use of alog b = log ba M1 for one correct use of log a + log b = log ab a or log a – log b = log b
Q14 · NOT TO SCALE 2.5 The diagram shows 15 circles in an equilateral triangle
14 NOT TO SCALE 2.5 The diagram shows 15 circles in an equilateral triangle. The circles touch each other and the triangle. The radius of each circle is 2.5 cm. The length of each side of the triangle is a + b 3 cm where a and b are integers. ` j Find the value of a and the value of b. a = ................................................ b = ................................................ [5]
Mark scheme: 14 [a =] 20 5 B1 for a = 20 soi [b =] 5 2.5 M2 for x = oe tan30 2.5 or M1 for tan30 = oe x 1 B1 for tan 30 = or tan 60 = 3 3
What was in this paper
The subtopics covered by these 14 questions, and how many questions each got. Open one in a new tab to see every Cambridge question on it.
What you needed in this session
Cambridge’s own grade thresholds for 2024 May/June, Paper 2 · Variant 3. A higher threshold means an easier paper — the bar moves with how the cohort did.