Cambridge IGCSE Mathematics 0580 — 2019 May/June Paper 2 · Variant 1

0580/21/M/J/19 · 26 questions · 70 marks · ≈79 min

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Mark scheme6 pages

Answers below. Sit the paper first if you are practising.

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Questions as text

Q1 · Work out $1.20 as a percentage of $16

1 Work out $1.20 as a percentage of $16. .........................................% [1]

Mark scheme: Question Answer Marks Partial Marks 1 7.5 oe 1

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Q2 · Factorise 5y - 6py

2 Factorise 5y - 6py. ............................................ [1]

Mark scheme: 2 y (5 − 6 p ) final answer 1

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Q3 · Calculate 3 8.1 2 - 1.3 0 .8

3 Calculate 3 8.1 2 - 1.3 0 .8 . ............................................ [1]

Mark scheme: 3 4.01 or 4.007 to 4.008 1

More questions on Powers and roots

Q4 · An equilateral triangle has sides of length 15 cm, correct to the nearest centimetre

4 An equilateral triangle has sides of length 15 cm, correct to the nearest centimetre. Calculate the upper bound of the perimeter of this triangle. ....................................... cm [1]

Mark scheme: 4 46.5 1

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Q5 · The volume of a cuboid is 180 cm3

5 The volume of a cuboid is 180 cm3. The base is a square of side length 6 cm. Calculate the height of this cuboid. ....................................... cm [2]

Mark scheme: 5 5 2 M1 for 180 ÷ 62 oe

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Question 6

6 Simplify. (a) t21 ÷ t7 ............................................ [1] (b) (u5)5 ............................................ [1]

Mark scheme: 6(a) t14 final answer 1 6(b) u 25 final answer 1

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Q7 · NOT TO SCALE 12 cm x cm 35° The diagram shows a right-angled triangle

7 NOT TO SCALE 12 cm x cm 35° The diagram shows a right-angled triangle. Calculate the value of x. x = ............................................ [2]

Mark scheme: 7 6.88 or 6.882 to 6.883 2 x M1 for sin 35 [=] oe or better 12

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Q8 · NOT TO O SCALE C A 130° B A, B and C are points on the circle, centre O

8 NOT TO O SCALE C A 130° B A, B and C are points on the circle, centre O. Find the obtuse angle AOC. Angle AOC = ............................................ [2]

Mark scheme: 8 100 2 M1 for reflex angle = 2 × 130 or opposite angle of a cyclic quadrilateral shown = 50

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Q9 · Write the recurring decimal .047o as a fraction

9 Write the recurring decimal .047o as a fraction. Show all your working. ............................................ [2]

Mark scheme: 9 47.77…– 4.77… oe M1 43 A1 Allow equivalent fractions 90 43 If M0 then SC1 for or equivalent 90 fraction with no/insufficient working

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Q10 · F(x) = 2x + 3 Find f(1 - x) in its simplest form

10 f(x) = 2x + 3 Find f(1 - x) in its simplest form. ............................................ [2]

Mark scheme: 10 5 – 2x final answer 2 M1 for 2(1 – x) + 3 oe

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Q11 · 1 2 3 4 5 The diagram shows five cards

11 1 2 3 4 5 The diagram shows five cards. Two of the cards are taken at random, without replacement. Find the probability that both cards show an even number. ............................................ [2]

Mark scheme: 11 2 2 2 1 oe M1 for × oe 20 5 4

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Q12 · 27 28 29 30 31 32 33 From the list of numbers, write down (a) a multiple of 7…

12 27 28 29 30 31 32 33 From the list of numbers, write down (a) a multiple of 7, ............................................ [1] (b) a cube number, ............................................ [1] (c) a prime number. ............................................ [1]

Mark scheme: 12(a) 28 1 12(b) 27 1 12(c) 29 or 31 1

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Q13 · X 2 + 4x - 9 = (x + a) 2 + b Find the value of a and the value of b

13 x 2 + 4x - 9 = (x + a) 2 + b Find the value of a and the value of b. a = ............................................ b = ............................................ [3]

Mark scheme: 13 [a = ] 2 3 B2 for either correct or (x + 2)2 – 13 [b = ] – 13 OR M1 for 2a = 4 soi M1 for a2+ b = – 9 soi OR M1 for x2 + ax + ax + a2 [+b] or better

More questions on Algebraic manipulation

Q14 · 214 Without using a calculator, work out +

5 214 Without using a calculator, work out + . 6 3 You must show all your working and give your answer as a mixed number in its simplest form. ............................................ [3]

Mark scheme: 14 5 4 M1 2 correct fractions with a suitable common + oe denominator 6k 6 6 1 A2 9 12 cao A1 for 6 oe

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Question 15

15 Expand and simplify. (x + 1)(x + 2) + 2x (x - 3) ............................................ [3]

Mark scheme: 15 3 x 2 − 3 x + 2 final answer 3 B2 for x 2 + 2 x + x + 2 + 2 x 2 − 6 x oe or B1 for 3 correct terms of x 2 + 2 x + x + 2 oe

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Q16 · Y is inversely proportional to the square root of (x + 1)

16 y is inversely proportional to the square root of (x + 1). When x = 8, y = 2. Find y when x = 99. y = ............................................ [3]

Mark scheme: 16 [ ± ] 0.6 oe 3 k M1 for y = x + 1 theirk M1 for y = 99 + 1 OR 2 8 + 1 M2 for 99 + 1 or M1 for 2 8 + 1 = y 99 + 1

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Q17 · Factorise p 2 - q 2

17 (a) Factorise p 2 - q 2 . ............................................ [1] (b) p 2 - q 2 = 7 and p - q = 2 . Find the value of p + q. ............................................ [2]

Mark scheme: 17(a) ( p − q )( p + q ) final answer 1 17(b) 7 2 M1 for 2 × (p + q) = 7 oe 2 2 2 2 2 or for ( 2 + q ) − q = 7 or p − ( p − 2 ) = 7

More questions on Equations

Q18 · 18 (a) Simplify 81y 16 4

3 18 (a) Simplify 81y 16 4 . ` j ............................................ [2] (b) 2 3 = 4 p Find the value of p. p = ............................................ [1]

Mark scheme: 18(a) 27y 12 final answer 2 B1 for ky12 or 27 ky in final answer 18(b) 3 1 oe 2

More questions on Powers and roots

Q19 · A model of a car has a scale 1 : 20

19 A model of a car has a scale 1 : 20. The volume of the actual car is 12 m3. Find the volume of the model. Give your answer in cubic centimetres. ......................................cm3 [3]

Mark scheme: 19 1500 3 3  20  M2 for 12 ÷   oe  100   20  3  100  3 or M1 for   or   oe  100   20  OR M1 for ÷ 203 oe M1 for × 1003 oe

More questions on Scale drawings

Q20 · Write as a single fraction in its simplest form

20 Write as a single fraction in its simplest form. 1 2 - x + 2 3x - 1 ............................................ [3]

Mark scheme: 20 x − 5 3 B1 for common denominator isw expansion final answer ( x + 2)(3 x − 1) M1 for 3 x −−1 2( x + 2) or better

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Q21 · V NOT TO SCALE 10 cm D C M A 8 cm B The diagram shows a pyramid with a square base ABCD…

21 V NOT TO SCALE 10 cm D C M A 8 cm B The diagram shows a pyramid with a square base ABCD of side length 8 cm. The diagonals of the square, AC and BD, intersect at M. V is vertically above M and VM = 10 cm. Calculate the angle between VA and the base. ............................................ [4]

Mark scheme: 21 60.5 or 60.50… 4 10 M3 for tan = oe 1 2 2 8 + 8 2 1 2 2 or M2 for [ × ] 8 + 8 2 or M1 for 82 + 82 or 4 2 + 4 2 or B1 for recognising the angle required

More questions on Right-angled triangles

Q22 · These are the first four terms of a sequence

22 (a) These are the first four terms of a sequence. 5 8 11 14 (i) Write down the next term. ............................................ [1] (ii) Find an expression, in terms of n, for the nth term. ............................................ [2] (b) These are the first five terms of another sequence. 1 3 7 13 21 2 4 6 8 10 Find the next term. ............................................ [1]

Mark scheme: 22(a)(i) 17 1 22(a)(ii) 3n + 2 oe final answer 2 B1 for 3n + k or cn + 2, c ≠ 0 22(b) 31 1 oe 12

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Q23 · 1 23 P = e2 4o (a) Find P2

3 1 23 P = e2 4o (a) Find P2. [2] f p (b) Find P–1. [2] f p

Mark scheme: 23(a)  11 7  2 B1 for 2 or 3 correct elements    14 18  23(b) 1  4 − 1  2  4 − 1    oe isw B1 for k   or for det = 10 soi 10  − 2 3   − 2 3 

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Q24 · 20 NOT TO Speed SCALE (m/s) 0 0 60 70 Time (seconds) The diagram shows information about…

24 20 NOT TO Speed SCALE (m/s) 0 0 60 70 Time (seconds) The diagram shows information about the final 70 seconds of a car journey. (a) Find the deceleration of the car between 60 and 70 seconds. .....................................m/s2 [1] (b) Find the distance travelled by the car during the 70 seconds. .........................................m [3]

Mark scheme: 24(a) 2 1 24(b) 1300 3 20 M2 for × (60 + 70) oe 2 or M1 for any relevant area

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Q25 · C K B M NOT TO q SCALE L O p A OABC is a parallelogram and O is the origin

25 C K B M NOT TO q SCALE L O p A OABC is a parallelogram and O is the origin. CK = 2KB and AL = LB. M is the midpoint of KL. OA = p and OC = q. Find, in terms of p and q, giving your answer in its simplest form (a) KL, KL = ............................................ [2] (b) the position vector of M. ............................................ [2] Question 26 is printed on the next page.

Mark scheme: 25(a) 1 1 2 M1 for a correct unsimplified answer or a p − q oe simplified correct route 3 2 25(b) 5 3 2 M1 for a correct unsimplified answer or a p + q oe simplified correct route 6 4

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Q26 · Line L passes through the points (0, -3) and (6, 9)

26 Line L passes through the points (0, -3) and (6, 9). (a) Find the equation of line L. ............................................ [3] (b) Find the equation of the line that is perpendicular to line L and passes through the point (0, 2). ............................................ [2]

Mark scheme: 26(a) y = 2 x − 3 oe 3 B2 for 2 x − 3 or y = theirm x – 3 or y = 2x + c 9 −−( 3) or M1 for oe or 9 = 6m – 3 oe 6 − 0 or B1 for 2x seen or [y =]mx – 3 m ≠0 26(b) 1 2 1 y = − x + 2 oe FT their (a) y = – x + 2 2 their m 1 B1 for gradient – , gradient FT their (a) 2 or for y = mx + 2 m ≠0

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What was in this paper

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What you needed in this session

Cambridge’s own grade thresholds for 2019 May/June, Paper 2 · Variant 1. A higher threshold means an easier paper — the bar moves with how the cohort did.

A53/70
B45/70
C38/70
D29/70
E21/70