Cambridge IGCSE Physical Science 0652 — 2002 Oct/Nov Paper 3 · Variant 1
0652/31/O/N/02
The question paper and its mark scheme, free to read here and free to download. This is Cambridge’s own paper, exactly as it was sat.
Question paper16 pages
















Mark scheme7 pages
Answers below. Sit the paper first if you are practising.







Paper as text
Question paper, page 1
TIME 1 hour 15 minutes INSTRUCTIONS TO CANDIDATES Write your name, Centre number and candidate number in the spaces at the top of this page. Answer all questions. Write your answers in the spaces provided on the question paper. INFORMATION FOR CANDIDATES The number of marks is given in brackets [ ] at the end of each question or part question. A copy of the Periodic Table is printed on page 16. This question paper consists of 15 printed pages and 1 blank page. MML 1293 3/01 S11455/6 © CIE 2002 [Turn over Candidate Centre Number Number Candidate Name FOR EXAMINER’S USE 1 2 3 4 5 6 7 8 9 10 TOTAL International General Certificate of Secondary Education CAMBRIDGE INTERNATIONAL EXAMINATIONS PHYSICAL SCIENCE 0652/3 PAPER 3 OCTOBER/NOVEMBER SESSION 2002 1 hour 15 minutes Candidates answer on the question paper. No additional materials are required. UNIVERSITY of CAMBRIDGE Local Examinations Syndicate www.XtremePapers.com
Question paper, page 2
1 The table, Fig. 1.1, shows some of the properties of the elements in Group V of the Periodic Table. Fig.1.1 (a) Complete the table by suggesting the density of antimony, the type of structure for antimony and the type of oxide formed by phosphorus. [3] (b) Suggest a reason why the melting points of the elements do not show a steady trend. … … … … [2] 2 0652/3/O/N/02 For Examiner’s Use element nitrogen phosphorus arsenic antimony bismuth density in g / cm3 0.0012 2.2 5.7 9.8 melting point in K 63 317 1090 905 545 type of structure covalent molecule covalent molecule metallic metallic type of oxide acidic amphoteric amphoteric amphoteric
Question paper, page 3
2 Fig. 2.1 shows a force of 80 N applied to the pedal of a bicycle. The force is applied at a distance of 30 cm from the axis about which the gear wheel turns. Fig. 2.1 (a) Calculate the moment of the force about the axis. Write down the equation that you use and show your working. moment of the force = … [3] (b) (i) Explain what is meant by power. … … [1] (ii) Suggest why the power input to the gear wheel changes with the position of the pedal. … … … … [2] 30cm gear wheel 80N pedal 3 0652/3/O/N/02 [Turn over For Examiner’s Use
Question paper, page 4
3 Iron is extracted from the ore haematite, Fe2O3, in a blast furnace by reduction with carbon. The carbon is put into the furnace in the form of coke. (a) (i) Use the Periodic Table on page 16 of this paper to deduce the charge on an oxide ion. charge on oxide ion … [1] (ii) Use the answer to (i) and the formula of haematite to find the charge on the ion of iron present in haematite. charge on iron ion … [1] (iii) Write down the formula of the chloride which would be formed using the ion of iron in (ii). formula of chloride … [1] (iv) Iron forms another chloride named iron(II) chloride. Describe a simple chemical test to distinguish between a solution of the chloride of iron in (iii) and a solution of iron(II) chloride. Test … … Result with iron(II) chloride … … Result with chloride of iron in (iii) … … [3] (b) Write a balanced equation for the reduction of haematite, Fe2O3, by carbon. … [2] (c) (i) What other solid is mixed with the coke and iron ore in a blast furnace? … (ii) What is the reason for adding this substance to the furnace? … … … [2] 4 0652/3/O/N/02 For Examiner’s Use
Question paper, page 6
4 Fig. 4.1 shows the fruit of a plant. Its structure allows the fruit to fall slowly so that several fruits can be scattered by horizontal breezes. Fig. 4.1 The mass of the fruit and parachute of tiny hairs is 1.2 g. (a) (i) Calculate the weight of the fruit and parachute. [g = 10 N / kg] weight = … [2] (ii) When the fruit falls at a constant vertical speed what is the magnitude of the upward force acting on it? magnitude of upward force = … [1] (iii) The fruit falls at 0.2 m / s. Calculate the kinetic energy of the fruit. Write down the equation that you use and show your working. kinetic energy = … [3] fruit parachute 6 0652/3/O/N/02 For Examiner’s Use
Question paper, page 7
(b) The fruit falls to the ground from a height of 0.3 m in 1.5 s at a constant vertical speed. (i) Calculate the gravitational potential energy of the fruit before it falls. Show your working. gravitational potential energy = … [2] (ii) On the grid of Fig. 4.2 show how the gravitational potential energy changes over the 1.5 s period. Mark numbers and units on the vertical axis. Fig. 4.2 [2] (iii) Explain the energy change that occurs as the fruit falls through the air. … … … [2] gravitational potential energy time in seconds 0 0.5 1.0 1.5 7 0652/3/O/N/02 [Turn over For Examiner’s Use
Question paper, page 8
5 The soluble salt magnesium sulphate can be prepared by reacting the insoluble solid magnesium oxide with sulphuric acid. The reaction is carried out by adding the solid to warm dilute sulphuric acid until no more solid reacts. The salt is isolated by filtering and slowly evaporating the solution until crystals of the hydrated salt are produced. (a) Explain why it is necessary to filter the solution before evaporating it. … … [1] (b) Calcium sulphate is an insoluble salt, but calcium nitrate is soluble. (i) Explain why the method described above cannot be used to prepare calcium sulphate crystals from calcium oxide. … … [1] (ii) Suggest a suitable method for preparing calcium sulphate using sulphuric acid as one of the starting materials. … … … … [3] 8 0652/3/O/N/02 For Examiner’s Use
Question paper, page 9
(c) The equation for the reaction between magnesium oxide and sulphuric acid may be written: MgO + H2SO4 →MgSO4 + H2O (i) Calculate the relative molecular mass, Mr, for magnesium oxide. You should use the Periodic Table on page 16 of this paper to help you answer this question. Mr of magnesium oxide = … [1] (ii) Calculate the number of moles in 8 g of magnesium oxide. number of moles of magnesium oxide = … [1] (iii) Hence calculate the volume of sulphuric acid of concentration 2 mol / dm3 which will react with 8 g of magnesium oxide. Show your working. volume of sulphuric acid = … [3] 9 0652/3/O/N/02 [Turn over For Examiner’s Use
Question paper, page 10
6 Fig. 6.1 shows a section through a ripple tank. The dipper is made to bounce up and down by the rotation of a motor mounted on a pair of rubber bands. For each rotation of the motor one new wave is sent out. Fig. 6.1 (a) A series of alternate bright and dark lines can be seen on the screen below the tank. Suggest how this pattern is formed. … … … [2] lamp rubber band motor dipper screen tank 10 0652/3/O/N/02 For Examiner’s Use
Question paper, page 11
(b) Explain how you would measure the wavelength of the wave. … … … … … … [4] (c) The waves travel at a speed of 2.5 cm / s and their wavelength is 4.2 cm. Calculate how many times the motor must rotate in a minute. Write down the equation that you use and show your working. number of rotations per minute = … [4] 11 0652/3/O/N/02 [Turn over For Examiner’s Use
Question paper, page 12
7 Ethanol and methanol are members of the same homologous series of organic compounds. Ethanol, C2H5OH, may be produced by the addition reaction between ethene, C2H4, and steam. (a) (i) Write down the formula of methanol. … [1] (ii) Draw a dot-and-cross diagram to show the bonding in methanol. You need only show the outer shell electrons in each atom. [2] (iii) Explain why ethanol and methanol are considered to be members of the same homologous series. … … [1] (b) (i) Write an equation for the addition reaction between ethene and steam. … [2] (ii) State two of the conditions necessary for this reaction to occur. 1. … 2. … [2] (c) State one industrial method of obtaining the ethene used to make ethanol. … … [1] 12 0652/3/O/N/02 For Examiner’s Use
Question paper, page 13
8 Fig. 8.1 shows a circuit in which an ammeter and voltmeter are included. Calculate the ammeter and voltmeter readings in this circuit. You can only gain full marks for this question by writing down any equations that you use and showing your working. Fig. 8.1 ammeter reading = … A voltmeter reading = … V [6] 6V 8 6 12 V A 13 0652/3/O/N/02 [Turn over For Examiner’s Use
Question paper, page 14
9 Aluminium is a very reactive metal which is protected from corrosion by a layer of aluminium oxide. This oxide has amphoteric properties. (a) Explain why the oxide layer formed on aluminium protects it from corrosion but iron is not protected by the formation of a layer of rust. … … … [2] (b) Oven cleaners often contain sodium hydroxide to help remove fat. Explain why such a cleaner should not be used on aluminium utensils. … … … [2] (c) Aluminium is not extracted from its ore by reduction with carbon. (i) Name the main ore of aluminium. … [1] (ii) Suggest a reason why aluminium cannot be extracted by reduction with carbon. … … [1] 14 0652/3/O/N/02 For Examiner’s Use
Question paper, page 15
10 (a) Complete the following sentences about transformers using only words from the list. Each word may be used once, more than once or not at all. changing constant current direct induction output primary resistance voltage waves Transformers work using the principle of electromagnetic ………………………… . A ………………………… current in the ………………………… coil generates a voltage across the secondary coil. In a step-up transformer the output ………………………… is greater than the input voltage. [4] (b) A step-down transformer with a primary coil of 500 turns is used to transform 120 V to 6 V. Calculate the number of turns on the secondary coil. Show all your working. number of turns = … [2] 15 0652/3/O/N/02 For Examiner’s Use
Question paper, page 16
16 0652/3/O/N/02 DATA SHEET The Periodic Table of the Elements The volume of one mole of any gas is 24 dm3 at room temperature and pressure (r.t.p.). *58-71 Lanthanoid series †90-103 Actinoid series Key a = relative atomic mass X = atomic symbol b = proton (atomic) number Group I 7 Li Lithium 3 9 Be Beryllium 4 23 Na Sodium 11 24 Mg Magnesium 12 39 K Potassium 19 40 Ca Calcium 20 45 Sc Scandium 21 48 Ti Titanium 22 51 V Vanadium 23 52 Cr Chromium 24 55 Mn Manganese 25 56 Fe Iron 26 59 Co Cobalt 27 59 Ni Nickel 28 64 Cu Copper 29 65 Zn Zinc 30 70 Ga Gallium 31 27 Al Aluminium 13 11 B Boron 5 73 Ge Germanium 32 28 Si Silicon 14 12 C Carbon 6 75 As Arsenic 33 31 P Phosphorus 15 14 N Nitrogen 7 79 Se Selenium 34 32 S Sulphur 16 16 O Oxygen 8 80 Br Bromine 35 35.5 Cl Chlorine 17 19 F Fluorine 9 84 Kr Krypton 36 40 Ar Argon 18 20 Ne Neon 10 4 He Helium 2 85 Rb Rubidium 37 88 Sr Strontium 38 89 Y Yttrium 39 91 Zr Zirconium 40 93 Nb Niobium 41 96 Mo Molybdenum 42 Tc Technetium 43 101 Ru Ruthenium 44 103 Rh Rhodium 45 106 Pd Palladium 46 108 Ag Silver 47 112 Cd Cadmium 48 115 In Indium 49 119 Sn Tin 50 122 Sb Antimony 51 128 Te Tellurium 52 127 I Iodine 53 131 Xe Xenon 54 133 Cs Caesium 55 137 Ba Barium 56 139 La Lanthanum 57 * 178 Hf Hafnium 72 181 Ta Tantalum 73 140 Ce Cerium 58 a X b 232 Th Thorium 90 Pa Protactinium 91 238 U Uranium 92 Np Neptunium 93 Pu Plutonium 94 Am Americium 95 Cm Curium 96 Bk Berkelium 97 Cf Californium 98 Es Einsteinium 99 Fm Fermium 100 Md Mendelevium 101 No Nobelium 102 Lr Lawrencium 103 141 Pr Praseodymium 59 144 Nd Neodymium 60 Pm Promethium 61 150 Sm Samarium 62 152 Eu Europium 63 157 Gd Gadolinium 64 159 Tb Terbium 65 162 Dy Dysprosium 66 165 Ho Holmium 67 167 Er Erbium 68 169 Tm Thulium 69 173 Yb Ytterbium 70 175 Lu Lutetium 71 184 W Tungsten 74 186 Re Rhenium 75 190 Os Osmium 76 192 Ir Iridium 77 195 Pt Platinum 78 197 Au Gold 79 201 Hg Mercury 80 204 Tl Thallium 81 207 Pb Lead 82 209 Bi Bismuth 83 Po Polonium 84 At Astatine 85 Rn Radon 86 Fr Francium 87 226 Ra Radium 88 227 Ac Actinium 89 † 1 H Hydrogen 1 II III IV V VI VII 0
Mark scheme, page 1
CAMBRIDGE INTERNATIONAL EXAMINATIONS NOVEMBER 2002 INTERNATIONAL GCSE UNIVERSITY of CAMBRIDGE Local Examinations Syndicate
Mark scheme, page 2
Page 1 Mark Scheme [Syllabus | Paper | IGCSE Examinations — November 2002 [0652 [ 3 | (a) 5,8-9.7 1 metallic 1 acid : , 1 (b) idea that mp depends on structure and idea that (1) there are different structures gases (simple) molecular and metal giant max two (accept metallic) wo (1) marks here gases weakly bound and metals strongly bound or gases weak force and metals strong forces (1) idea of strength of metallic bond decreasing as the size of the ion increases => weaker electrostatic attraction (1+1) 5 (a) monient = force x (perpendicular) distance (accept F x d but not F x a) 1 80 x 30 or 80x 0.3 1 2400 Nem or 24. Nm (not N/cm etc. unit 1 penalty) (b) (i) rate of doing work / rate of transfer of energy / work over time or equivalent (not symbols 1 unless defined) (ii) moment changes 1 distance changes 1 max 2 forces changes 1
Mark scheme, page 3
Page 2 Mark Scheme Syllabus | Paper t IGCSE Examinations — November 2002 0652 3 3 (a) (i) = -2 or 2- 1 (ii) +3 or 3+ 1 (iii) FeCl; : A (iv) add (aqueous) ammonia or ammonium 1 mandatory hydroxide green precipitate 1 orange/red/brown precipitate 1 (b) Fe,03+3C > 2Fe+3CO | formulae correct 1 or 2Fe.03;+ 3C > 4Fe + 3COQ2 | correctly balanced 1 Fe,03 + 3CO > 2Fe + 3CO2 (c) (i) limestone /calcium carbonate 1 (ii) to remove impurities from ore 1 10 4 (a) (i) evidence of g>kg 1 1.2 x 107 N or 0.012 N* 4 (12 N scores °1) (i) a@@ , 4 (iii) % mv 1 evidence of 0.2 squared ; 1 2.4x 105 J* 4 (b) (i) mgh 1 3.6 x 10° J* 1 ecf for mass from (a)(iii) allow 3.6 J if mass penalised in (a)(iii)
Mark scheme, page 4
Page 3 Mark Scheme Syllabus Paper IGCSE Examinations — November 2002 0652 3 5 (a) (b) (c) (i) (iii) (i) (ii) 0) (ii) (iii) line of negative slope (curved or straight) passing through (0,(b)(i) value) and (1.5 s, 0) gravitational potential energy > heat (ignore mention of k.e.) of air or fruit or explanation that k.e. not gained because constant speed *one unit penalty only for all the parts in this question to remove excess oxide or MgO not “to remove solid or residue” calcium sulphate is insoluble / not possible to separate (from oxide) by filtering‘ add calcium nitrate (solution) to sulphuric acid filter dry residue by warming 40 (ignore unit) 0.2 (ignore unit) 0.2 mol H2SO4 needed / ratio 1:1 2 mol in 1000 cm? / vol = no of moles/concentration 100 cm? or 0.1 dm? (unit penalty) 12 10
Mark scheme, page 5
Page 4 Mark Scheme IGCSE Examinations —- November 2002 [_Syllabus | Paper (0652 3 6 (a) (b) (c) 7 (a) (ii) (iii) mention of light wave behaves as lenses /refraction of light rays etc , use set up shown / project light on to screen measure distance between 2 light or dark bands use of ruler / mention of middle or edges of bands improved by using several bands idea of need to work out scaling freezing using strobe v=faA 0.60 (or 0.5952) or 2.5/4.2 multiplication by 60 36 (35.7) no unit penalty CH3;0H any shared pairs seen all shells filled (each H —2,C and O-8) same functional group (OH) / same general formula (C,H2n+20) / undergo similar reactions/ all alcohols/ similar chemical properties max 10 1 mandatory
Mark scheme, page 6
Page 5 ] Mark Scheme Syllabus | Paper I IGCSE Examinations — November 2002 0652 3 (b) (i) | formulae correct 1 1+1 correctly balanced 1 (ii) high temperature not “heat” catalyst high pressure not “pressure” 2 (c) (catalytic) cracking of alkanes 1 9 : 1 R,=42 1 R, = 129 (or 8 Q+R, value) ecf wrong Rp 1 V = IR (or arrangement) 1 1=0.5 (A) ecf 1 V=2(V) ecf 1 6 or any equivalent method with including 2 marks for relevant equations - answers alone gain two marks
Mark scheme, page 7
Page 6 Mark Scheme Syllabus | Paper IGCSE Examinations — November 2002 0652 3 9 (a) oxide forms layer which bonds to aluminium (or layer is tough and impermeable) 1 rust (iron oxide) flakes of leaving another exposed surface/ rust traps water and air(O2) in contact with iron 1 (b) amphoteric oxides dissolve in alkalis 1 NaOH removes(dissolves) oxide (layer) / Al reacts with NaOH 41 (c) (i) _ bauxite 1 (ii) Al too (allow “very”) reactive / bond with oxide too strong / too much energy is needed / carbon is not reactive enough to reduce aluminium oxide 1 not “it is more reactive” 6 10 (a) induction 4 changing : 41 primary ; - 1 voltage 41 (b) NJ/Np = V./Vp or equivalent 4 25 (ignore any unit) — 4 6 Total