Cambridge IGCSE Mathematics - International 0607 — 2025 Oct/Nov Paper 4 · Variant 3

This document has 16 pages. Any blank pages are indicated. [Turn over Cambridge IGCSE™ CAMBRIDGE INTERNATIONAL MATHEMATICS 0607/43 Paper 4 Calculator (Extended) October/November 2025 1 hour 30 minutes You must answer on the question paper. You will need: Geometrical instruments INSTRUCTIONS ● Answer all questions. ● Use a black or dark blue pen. You may use an HB pencil for any diagrams or graphs. ● Write your name, centre number and candidate number in the boxes at the top of the page. ● Write your answer to each question in the space provided. ● Do not use an erasable pen or correction fluid. ● Do not write on any bar codes. ● You should use a graphic display calculator where appropriate. ● You may use tracing paper. ● You must show all necessary working clearly. You will be given marks for correct methods, including sketches, even if your answer is incorrect. ● Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless a different level of accuracy is specified in the question. ● For r, use either your calculator value or 3.142. INFORMATION ● The total mark for this paper is 75. ● The number of marks for each question or part question is shown in brackets [ ]. * 9 8 7 0 3 4 5 6 9 7 * DC (CJ/FC) 347096/3 © UCLES 2025 ,










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2 0607/43/O/N/25 © UCLES 2025 List of formulas Area, A, of triangle, base b, height h. A bh 2 1 = Area, A, of circle of radius r. rr A 2 = Circumference, C, of circle of radius r. r C r 2 = Curved surface area, A, of cylinder of radius r, height h. rrh A 2 = Curved surface area, A, of cone of radius r, sloping edge l. r A rl = Surface area, A, of sphere of radius r. r A r 4 2 = Volume, V, of prism, cross-sectional area A, length l. V Al = Volume, V, of pyramid, base area A, height h. V Ah 3 1 = Volume, V, of cylinder of radius r, height h. r V r h 2 = Volume, V, of cone of radius r, height h. r V r h 3 1 2 = Volume, V, of sphere of radius r. r V r 3 4 3 = For the equation ax2 + bx + c = 0, where a ! 0, x a b b ac 2 4 2 ! = - - For the triangle shown, sin sin sin A a B b C c = = cos a b c bc A 2 2 2 2 = + - sin ab C 2 1 Area = A c b a C B * 0000800000002 * ,










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3 0607/43/O/N/25 © UCLES 2025 [Turn over 1 134° x° y° NOT TO SCALE The diagram shows a straight line intersecting 2 parallel lines. Find the value of x and the value of y. x = … y = … [2] 2 Calculate . . . 20 2 5 1 1 7 3 2 1 - . Give your answer correct to 4 decimal places. … [2] 3 The exchange rate between pounds and rupees is 1 pound = 350.4 rupees. Convert 84 000 rupees into pounds. … pounds [1] * 0000800000003 * ,










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4 0607/43/O/N/25 © UCLES 2025 4 – 4.5 2 – 30 50 y x 0 ( ) f x x x 4 4 3 = + for values of x between -4.5 and 2. (a) On the diagram, sketch the graph of ( ) f y x = . [2] (b) Write down the zeros of ( ) f x . … [2] (c) Write down the coordinates of the local minimum point. ( … , … ) [1] (d) The equation ( ) f x k = has no solutions. Find the range of values of k. … [1] (e) Solve the equation ( ) f x x 20 10 = + . … [3] (f) (i) On the diagram, sketch the line x 2 =- . [1] (ii) Shade and label the region R where x 2 G- , ( ) f y x H and y x 20 10 G + . [1] * 0000800000004 * ,










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5 0607/43/O/N/25 © UCLES 2025 [Turn over 5 Solve the simultaneous equations. You must show all your working. x 3 - 1 = x y 5 2 24 + =- y x = … y = … [3] 6 The price of a computer is reduced by 10%. The price of the computer is then reduced by a further 15%. Calculate the overall percentage reduction in the price of the computer. …% [2] * 0000800000005 * ,










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6 0607/43/O/N/25 © UCLES 2025 7 The heights of 100 plants are measured. The results are shown in the cumulative frequency table. Height (h cm) h 5 G h 10 G h 20 G h 40 G h 60 G Cumulative frequency 7 32 63 85 100 (a) (i) On the grid, draw the cumulative frequency diagram. h 60 80 100 40 20 50 70 90 30 10 0 0 10 20 30 40 50 60 Cumulative frequency Height (cm) [3] (ii) Use your cumulative frequency diagram to find an estimate of (a) the median … cm [1] (b) the number of plants with a height greater than 30 cm. … [2] * 0000800000006 * ,










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7 0607/43/O/N/25 © UCLES 2025 [Turn over (b) (i) Complete the frequency table for the 100 plants. Height (h cm) h 0 5 1 G h 5 10 1 G h 10 20 1 G h 20 40 1 G h 40 60 1 G Frequency 7 25 15 [1] (ii) Calculate an estimate of the mean. … cm [2] 8 . v k 4 35 = e o . v 5 33 = Find the value of k. k = … [3] * 0000800000007 * ,










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8 0607/43/O/N/25 © UCLES 2025 9 10 cm 12 cm 12 cm 15 cm NOT TO SCALE The diagram shows a solid made with a cone, a cylinder and a hemisphere. The radius of each of the cone, the cylinder and the hemisphere is 12 cm. The height of the cone is 15 cm. The height of the cylinder is 10 cm. Calculate the total surface area of the solid. … cm2 [5] * 0000800000008 * ,










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9 0607/43/O/N/25 © UCLES 2025 [Turn over 10 NOT TO SCALE 100° The diagram shows a sector of a circle. The perimeter of the sector is 48.4 cm. Calculate the area of the sector. … cm2 [4] * 0000800000009 * ,










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10 0607/43/O/N/25 © UCLES 2025 11 y x a 3 = - Rearrange the formula to make x the subject. x = … [2] 12 y x 1 1 ? + When , x y 8 5 = = . Find y when x 24 = . y = … [3] * 0000800000010 * ,










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11 0607/43/O/N/25 © UCLES 2025 [Turn over 13 Rob and Sal each have $500 to invest. (a) Rob invests his $500 at a rate of 2.5% per year simple interest. Calculate the total value of Rob’s investment at the end of 4 years. $ … [3] (b) Sal invests her $500 at a rate of 1.95% per year compound interest. (i) Calculate the value of Sal’s investment at the end of 4 years. $ … [2] (ii) Find the number of complete years it takes for the total value of Sal’s investment of $500 to be first greater than $800. … [4] * 0000800000011 * ,









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12 0607/43/O/N/25 © UCLES 2025 14 80° 45° NOT TO SCALE D C B A 11.5 cm 3.5 cm 12 cm The diagram shows a quadrilateral ABCD with diagonal BD. (a) Calculate AB. AB = … cm [3] (b) Calculate angle CBD. Angle CBD = … [3] (c) Calculate the area of triangle ABC. … cm2 [2] * 0000800000012 * ,









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13 0607/43/O/N/25 © UCLES 2025 [Turn over 15 NOT TO SCALE w cm (w – 5 ) cm 55° The diagram shows a right-angled triangle. Calculate the value of w. w = … [3] 16 Simplify. ab abx x x 2 2 1 1 2 - + - - … [3] * 0000800000013 * ,









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14 0607/43/O/N/25 © UCLES 2025 17 Solid A is mathematically similar to solid B. The surface area of solid A is cm 383 2. The surface area of solid B is cm 792 2. The volume of solid B is cm 1810 3. Find the volume of solid A. … cm3 [3] * 0000800000014 * ,









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15 0607/43/O/N/25 © UCLES 2025 18 Solve tanx 1 1 + =- for ° ° x 0 180 G G . x = … [2] * 0000800000015 * ,









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16 0607/43/O/N/25 © UCLES 2025 Permission to reproduce items where third-party owned material protected by copyright is included has been sought and cleared where possible. Every reasonable effort has been made by the publisher (UCLES) to trace copyright holders, but if any items requiring clearance have unwittingly been included, the publisher will be pleased to make amends at the earliest possible opportunity. To avoid the issue of disclosure of answer-related information to candidates, all copyright acknowledgements are reproduced online in the Cambridge Assessment International Education Copyright Acknowledgements Booklet. This is produced for each series of examinations and is freely available to download at www.cambridgeinternational.org after the live examination series. Cambridge Assessment International Education is part of Cambridge Assessment. Cambridge Assessment is the brand name of the University of Cambridge Local Examinations Syndicate (UCLES), which is a department of the University of Cambridge. BLANK PAGE * 0000800000016 * ,









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This document consists of 10 printed pages. © Cambridge University Press & Assessment 2025 [Turn over Cambridge IGCSE™ CAMBRIDGE INTERNATIONAL MATHEMATICS 0607/43 Paper 4 (Extended) October/November 2025 MARK SCHEME Maximum Mark: 75 Published This mark scheme is published as an aid to teachers and candidates, to indicate the requirements of the examination. It shows the basis on which Examiners were instructed to award marks. It does not indicate the details of the discussions that took place at an Examiners’ meeting before marking began, which would have considered the acceptability of alternative answers. Mark schemes should be read in conjunction with the question paper and the Principal Examiner Report for Teachers. Cambridge International will not enter into discussions about these mark schemes. Cambridge International is publishing the mark schemes for the October/November 2025 series for most Cambridge IGCSE, Cambridge International A and AS Level components, and some Cambridge O Level components.

0607/43 Cambridge IGCSE – Mark Scheme PUBLISHED October/November 2025 © Cambridge University Press & Assessment 2025 Page 2 of 10 Generic Marking Principles These general marking principles must be applied by all examiners when marking candidate answers. They should be applied alongside the specific content of the mark scheme or generic level descriptions for a question. Each question paper and mark scheme will also comply with these marking principles. GENERIC MARKING PRINCIPLE 1: Marks must be awarded in line with: • the specific content of the mark scheme or the generic level descriptors for the question • the specific skills defined in the mark scheme or in the generic level descriptors for the question • the standard of response required by a candidate as exemplified by the standardisation scripts. GENERIC MARKING PRINCIPLE 2: Marks awarded are always whole marks (not half marks, or other fractions). GENERIC MARKING PRINCIPLE 3: Marks must be awarded positively: • marks are awarded for correct/valid answers, as defined in the mark scheme. However, credit is given for valid answers which go beyond the scope of the syllabus and mark scheme, referring to your Team Leader as appropriate • marks are awarded when candidates clearly demonstrate what they know and can do • marks are not deducted for errors • marks are not deducted for omissions • answers should only be judged on the quality of spelling, punctuation and grammar when these features are specifically assessed by the question as indicated by the mark scheme. The meaning, however, should be unambiguous. GENERIC MARKING PRINCIPLE 4: Rules must be applied consistently, e.g. in situations where candidates have not followed instructions or in the application of generic level descriptors. GENERIC MARKING PRINCIPLE 5: Marks should be awarded using the full range of marks defined in the mark scheme for the question (however; the use of the full mark range may be limited according to the quality of the candidate responses seen). GENERIC MARKING PRINCIPLE 6: Marks awarded are based solely on the requirements as defined in the mark scheme. Marks should not be awarded with grade thresholds or grade descriptors in mind.

0607/43 Cambridge IGCSE – Mark Scheme PUBLISHED October/November 2025 © Cambridge University Press & Assessment 2025 Page 3 of 10 Mathematics-Specific Marking Principles 1 Unless a particular method has been specified in the question, full marks may be awarded for any correct method. However, if a calculation is required then no marks will be awarded for a scale drawing. 2 Unless specified in the question, non-integer answers may be given as fractions, decimals or in standard form. Ignore superfluous zeros, provided that the degree of accuracy is not affected. 3 Allow alternative conventions for notation if used consistently throughout the paper, e.g. commas being used as decimal points. 4 Unless otherwise indicated, marks once gained cannot subsequently be lost, e.g. wrong working following a correct form of answer is ignored (isw). 5 Where a candidate has misread a number or sign in the question and used that value consistently throughout, provided that number does not alter the difficulty or the method required, award all marks earned and deduct just 1 A or B mark for the misread. 6 Recovery within working is allowed, e.g. a notation error in the working where the following line of working makes the candidate’s intent clear.

0607/43 Cambridge IGCSE – Mark Scheme PUBLISHED October/November 2025 © Cambridge University Press & Assessment 2025 Page 4 of 10 Annotations guidance for centres Examiners use a system of annotations as a shorthand for communicating their marking decisions to one another. Examiners are trained during the standardisation process on how and when to use annotations. The purpose of annotations is to inform the standardisation and monitoring processes and guide the supervising examiners when they are checking the work of examiners within their team. The meaning of annotations and how they are used is specific to each component and is understood by all examiners who mark the component. We publish annotations in our mark schemes to help centres understand the annotations they may see on copies of scripts. Note that there may not be a direct correlation between the number of annotations on a script and the mark awarded. Similarly, the use of an annotation may not be an indication of the quality of the response. The annotations listed below were available to examiners marking this component in this series. Annotations Annotation Meaning More information required Accuracy mark awarded zero Accuracy mark awarded one Accuracy mark awarded two Accuracy mark awarded three Independent mark awarded zero Independent mark awarded one Independent mark awarded two Independent mark awarded three Benefit of the doubt Communication mark Incorrect Follow through Highlighter Highlight a key point in the working Ignore subsequent work Method mark awarded zero Method mark awarded one Method mark awarded two

0607/43 Cambridge IGCSE – Mark Scheme PUBLISHED October/November 2025 © Cambridge University Press & Assessment 2025 Page 5 of 10 Annotation Meaning Method mark awarded three Misread Omission Off-page comment Allows comments to be entered at the bottom of the RM marking window and then displayed when the associated question item is navigated to. On-page comment Allows comments to be entered in speech bubbles on the candidate response. Premature rounding/approximation Special case Indicates that work/page has been seen Transcription error Correct Correct answer from incorrect working

0607/43 Cambridge IGCSE – Mark Scheme PUBLISHED October/November 2025 © Cambridge University Press & Assessment 2025 Page 6 of 10 MARK SCHEME NOTES The following notes are intended to aid interpretation of mark schemes in general, but individual mark schemes may include marks awarded for specific reasons outside the scope of these notes. Types of mark M Method marks, awarded for a valid method applied to the problem. A Accuracy mark, awarded for a correct answer or intermediate step correctly obtained. For accuracy marks to be given, the associated Method mark must be earned or implied. B Mark for a correct result or statement independent of Method marks. When a part of a question has two or more ‘method’ steps, the M marks are in principle independent unless the scheme specifically says otherwise; and similarly where there are several B marks allocated. The notation ‘dep’ is used to indicate that a particular M or B mark is dependent on an earlier mark in the scheme. Abbreviations awrt answers which round to cao correct answer only dep dependent FT follow through after error isw ignore subsequent working nfww not from wrong working oe or equivalent rot rounded or truncated SC Special Case soi seen or implied Question Answer Marks Partial Marks 1 [x = ] 134 [y = ] 46 2 B1 for each or if answers reversed 2 0.2784 cao 2 B1 for 0.27835... If 0 scored, SC1 for their 5 or more decimal place answer rounded correctly to 4 decimal places 3 239.73 or 240 or 239.7 or 239.72… 1 4(a) Correct sketch 2 B1 for correct shape but not passing through origin or crossing x-axis more than twice or with excessive feathering 2 1 0 -1 -2 -3 -4 40 20 0 -20 2 1 0 -1 -2 -3 -4 40 20 0 -20 2 1 0 -1 -2 -3 -4 40 20 0 -20 2 1 0 -1 -2 -3 -4 40 20 0 -20

0607/43 Cambridge IGCSE – Mark Scheme PUBLISHED October/November 2025 © Cambridge University Press & Assessment 2025 Page 7 of 10 Question Answer Marks Partial Marks 4(b) –4 and 0 2 B1 for each or B1 for (–4,0) and (0,0) 4(c) (–3, –27) 1 4(d) k < –27 1 FT their minimum point 4(e) –3.66 or –3.662 to –3.661 1.88 or 1.875... 3 B2 for one correct or for both correct but with y-coordinates included or M1 for line with positive gradient and positive y – intercept If 0 scored SC1 for -3.7 and 1.9 4(f)(i) line x = –2 drawn 1 4(f)(ii) Region left of x = –2, above y = f(x) and below y = 20 + 10x 1 FT if region bounded by their x = –2, their y = f(x) and their y = 20 + 10x if enclosed 5 Correct method to eliminate one variable M1 One arithmetic error allowed [x =] –2 [y =] –7 A2 From correct working A1 for one correct from correct working If A0 scored SC1 for values satisfying one equation 6 23.5 2 M1 for 0.9 × 0.85 oe or better 7(a)(i) Correct diagram drawn through 5 correct points 3 B1 for 4 or 5 correct horizontal plots B1 for 4 or 5 correct vertical plots Max 2 marks if bars also drawn 7(a)(ii)(a) 14 –17 1 FT their graph dep on cumulative frequency diagram 7(a)(ii)(b) 22 – 26 2 FT their graph B1 FT for 74 –78 seen dep on cumulative frequency diagram 7(b)(i) 31, 22 1 7(b)(ii) 20.8 2 M1 for at least 4 mid-values soi

0607/43 Cambridge IGCSE – Mark Scheme PUBLISHED October/November 2025 © Cambridge University Press & Assessment 2025 Page 8 of 10 Question Answer Marks Partial Marks 8 [ ] 3.08 oe 3 M2 for 2 2 5.33 4.35 − or better or M1 for k2 + 4.352 = 5.332 or better 9 2380 or 2382 to 2383... 5 M2 for 2 2 π 12 12 15   + or M1 for 2 2 12 15 + M1 for 2 π 12 10   M1 for 2 2 π 12  Max of 3 marks if more than 3 areas added 10 146 or 145.7... 4 M2 for 48.4 100 2 2 π 360 +  or M1 for [r + r +] 100 2 π 360  r = 48.4 M1 dep for 2 100 π ( ) 360 their r dep on at least M1 11 3 + y a oe final answer 2 M1 for correctly isolating x term M1 for correct cube root of their expression max M1 if answer incorrect 12 3 3 B2 for 15 1 = + y x or k =15 or M1 for 5 8 1 = + k or better OR M2 for 1 24 1 1 5 8 1 + = + y or 24 1 5 8 1 + = + y or better 13(a) 550 3 M2 for 500 + 500 2.5 4 100   oe or M1 for 500 2.5 4 100   oe 13(b)(i) 540.16 or 540 or 540.1 to 540.2 2 M1 for 500  4 1.95 1 100   +     oe

0607/43 Cambridge IGCSE – Mark Scheme PUBLISHED October/November 2025 © Cambridge University Press & Assessment 2025 Page 9 of 10 Question Answer Marks Partial Marks 13(b)(ii) 25 nfww 4 B3 for 24.3 or 24.33 to 24.34 OR M3 for 1.95 800 log 1 log 100 500     + =         n oe or good sketch indicating value between 24 and 25 or correct trials reaching 24 and 25 or M2 for 1.95 800 1 100 500   + =     n oe or suitable sketch with n > 4 or at least 3 correct trials with n > 4 or M1 for 1.95 500 1 800 100    + =     n oe soi by at least 2 trials with n > 1 14(a) 9.98 or 9.981... 3 M2 for 12sin(180 80 45) sin80 − − oe or M1 for sin80 sin(180 80 45) 12 − − = AB oe 14(b) 17[.0] or 16.95 to 16.96 nfww 3 M2 for [cos = ] 2 2 2 11.5 12 3.5 2 11.5 12 + −   oe or M1 for 2 2 2 3.5 11.5 12 2 11.5 12 cos = + −   CBD oe 14(c) 50.6 or 50.7 or 50.64 to 50.67 2 M1 for 1 11.5 sin(45 angle ) 2    + theirAB their CBD their (45 angle ) + their CBD must be acute 15 11.7 or 11.72 to 11.73 3 B2 for w – wcos55 = 5 oe or better or M1 for 5 cos55 − = w w oe or better 16 1 1 − ab or 1 1 −−ab final answer 3 B2 for (1 2 )( 1) − − x ab or B1 for (1 2 ) [1](1 2 ) − − − ab x x or [1]( 1) 2 ( 1) − − − ab x ab 17 609 or 608.6 to 608.7 3 M2 for 3 2 383 [1810 ] 792       oe or M1 for 383 792 or 792 383 or 2 3 1810 792 383     =         V oe

0607/43 Cambridge IGCSE – Mark Scheme PUBLISHED October/November 2025 © Cambridge University Press & Assessment 2025 Page 10 of 10 Question Answer Marks Partial Marks 18 116.6 or 117 or 116.56 to 116.57 2 M1 for tanx = –2 or appropriate sketch showing root If 0 scored, SC1 for answer of 63.4 or –63.4 63.43... or – 63.43...