Cambridge IGCSE Science - Combined 0653 — 2013 Oct/Nov Paper 6 · Variant 1
0653/61/O/N/13
The question paper and its mark scheme, free to read here and free to download. This is Cambridge’s own paper, exactly as it was sat.
Question paper20 pages




















Mark scheme4 pages
Answers below. Sit the paper first if you are practising.




Paper as text
Question paper, page 1
This document consists of 18 printed pages and 2 blank pages. IB13 11_0653_61/FP © UCLES 2013 [Turn over *1766500653* UNIVERSITY OF CAMBRIDGE INTERNATIONAL EXAMINATIONS International General Certificate of Secondary Education COMBINED SCIENCE 0653/61 Paper 6 Alternative to Practical October/November 2013 1 hour Candidates answer on the Question Paper. No Additional Materials are required. READ THESE INSTRUCTIONS FIRST Write your Centre number, candidate number and name on all the work you hand in. Write in dark blue or black pen. You may use a pencil for any diagrams or graphs. Do not use staples, paper clips, glue or correction fluid. DO NOT WRITE IN ANY BARCODES. Answer all questions. Electronic calculators may be used. You may lose marks if you do not show your working or if you do not use appropriate units. At the end of the examination, fasten all your work securely together. The number of marks is given in brackets [ ] at the end of each question or part question. www.XtremePapers.com
Question paper, page 2
2 © UCLES 2013 0653/61/O/N/13 For Examiner's Use 1 Two experiments were set up as in Fig. 1.1. The apparatus is a model of the digestion and absorption of starch in the alimentary canal. glass rod visking tubing water starch and amylase Fig. 1.1 The piece of “visking tubing” represents the alimentary canal. The visking tubing is a selectively permeable membrane, which allows smaller molecules to pass through it but not larger molecules. In experiment 1, the liquid inside the visking tubing was starch solution. In experiment 2, this liquid was a mixture of starch solution and amylase solution. Both experiments were left for one hour. After this time, the liquid inside the visking tubing and the water in the beaker were each tested with iodine solution and with Benedict’s solution. The results are shown in Table 1.1. Table 1.1 experiment liquid tested test colour obtained conclusion iodine test inside visking tubing Benedict’s test blue iodine test brown 1 water in the beaker Benedict’s test blue iodine test brown inside visking tubing Benedict’s test red iodine test brown 2 water in the beaker Benedict’s test red (a) (i) Fill in the colour that was obtained for the top row of the Table 1.1. [1] (ii) In the top row of the last column of the table, state what can be concluded from this result. [1]
Question paper, page 3
3 © UCLES 2013 0653/61/O/N/13 [Turn over For Examiner's Use (iii) Fill in the remainder of the last column of Table 1.1, stating in each case whether starch or sugar is present or absent. [2] (b) (i) Explain what the results from experiment 2 tell you about the effect of amylase on starch molecules. [1] (ii) What do the results from experiment 2 tell you about the ability of sugar molecules to pass through the visking tubing? Explain your answer. [2] (c) For the experiment shown in Fig. 1.1, (i) state which part of the alimentary canal is represented by the visking tubing, [1] (ii) state what the beaker of water represents. [1] (d) Using the results of these experiments, explain why starch needs to be digested in the alimentary canal. [1]
Question paper, page 4
4 © UCLES 2013 0653/61/O/N/13 BLANK PAGE
Question paper, page 5
5 © UCLES 2013 0653/61/O/N/13 [Turn over For Examiner's Use 2 A student is doing an experiment with a converging lens. She is using the apparatus shown in Fig. 2.1. A converging lens is thicker in the middle and refracts light so that an image of an object can be seen on a screen some distance away. u v screen illuminated object lens 10 0 20 30 40 50 60 70 80 metre rule Fig. 2.1 When the lens is in the correct position between the illuminated object and the screen, a sharp image is formed on the screen. The student is investigating the relationship between u, the distance between the object and the lens and v, the distance between the image on the screen and the lens. • She places the lens so that u, the distance between the object and the lens, is 45.0 cm. • She adjusts the position of the screen until a sharp image of the illuminated object is formed on the screen. • She records, in Table 2.1, the position of the screen on the rule. • She uses the position of the screen and u to calculate v. • She calculates the ratio v / u. • She repeats the procedure for the other values of u shown in Table 2.1, on page 6.
Question paper, page 6
6 © UCLES 2013 0653/61/O/N/13 For Examiner's Use The positions of the screen when the values of u are 45.0 cm and 25.0 cm are shown in Fig. 2.2. 6 5 7 0 screen distance u = 45.0 cm 6 0 6 5 screen distance u = 25.0 cm Fig. 2.2 (a) (i) Read the position of the screen for the missing values and record them in Table 2.1. [2] (ii) Calculate the values of v, when the distances of u are 45.0 cm and 25.0 cm. Record these values in Table 2.1. [2] (iii) Calculate the missing values of the ratio v / u. Record them in Table 2.1. [2] Table 2.1 distance u / cm position of screen / cm distance v / cm ratio v / u 45 35 61.4 26.4 0.75 30 59.8 29.8 0.99 25 20 80.2 60.2 3.01
Question paper, page 7
7 © UCLES 2013 0653/61/O/N/13 [Turn over For Examiner's Use (b) (i) On the graph grid provided, plot a graph of distance v against the ratio v / u. Draw the best straight line. The line will not pass through the point (0,0). [2] 0 1 2 3 70 60 50 40 30 20 10 0 distance v / cm v / u (ii) The gradient of the line is a useful number that indicates how much a lens can magnify an image. Find the gradient of the straight line you have drawn. Show on your graph the values you use to calculate the gradient. gradient = [2]
Question paper, page 8
8 © UCLES 2013 0653/61/O/N/13 BLANK PAGE
Question paper, page 9
9 © UCLES 2013 0653/61/O/N/13 [Turn over For Examiner's Use 3 A student has been given solid X, a green powder. She carries out tests on solid X so that she can identify it. (a) Test 1 She heats solid X as shown in Fig. 3.1. solid X heat limewater Fig. 3.1 When solid X is heated, a gas bubbles into the limewater. The appearance of the limewater changes. A black powder is left in the heated test-tube. (i) Describe the change in the appearance of the limewater. [1] (ii) Name the gas that bubbles into the limewater. [1] (iii) As a result of this test, what can the student conclude about solid X? [1]
Question paper, page 10
10 © UCLES 2013 0653/61/O/N/13 For Examiner's Use (b) Test 2 The student allows the black powder left in the test-tube to cool. Then she adds dilute nitric acid and shakes the mixture. The black powder dissolves and a blue solution is made. She filters the mixture to obtain a blue filtrate. Draw a labelled diagram to show how she filters the mixture. [2] (c) Test 3 She divides the blue filtrate into two parts. To the first part, she adds a few drops of ammonia solution. A blue precipitate is formed. (i) The student thinks that there are copper ions in the blue solution. Name the blue precipitate. [1] (ii) The student adds more ammonia solution until the ammonia is in excess. The appearance of the mixture changes. State how the appearance of the mixture has changed. [1]
Question paper, page 11
11 © UCLES 2013 0653/61/O/N/13 [Turn over For Examiner's Use (d) Test 4 To the second part of the blue filtrate from (b), the student adds some iron filings. She shakes the mixture. The tube becomes warm and the appearance of the mixture changes. Assuming that the blue filtrate does contain copper(II) ions, describe (i) how the appearance of the solution changes, [1] (ii) how the appearance of the iron filings changes. [1] (e) Use the results of Tests 1 – 4 to state the name and formula of solid X. name formula [1]
Question paper, page 12
12 © UCLES 2013 0653/61/O/N/13 For Examiner's Use 4 A student was investigating the structure of plants. The student had a bean seedling. It is shown in Fig. 4.1. Fig. 4.1 (a) (i) Make a large drawing of the seedling in the space provided. [2] (ii) Measure to the nearest millimetre the complete length of the seedling in the photograph in Fig. 4.1. length = mm [1] (iii) Measure to the nearest millimetre the complete length of the seedling in your drawing. length of drawing = mm [1]
Question paper, page 13
13 © UCLES 2013 0653/61/O/N/13 [Turn over For Examiner's Use (iv) Calculate the magnification of your drawing. magnification = [1] (b) The student then prepared a slide of a transverse section of the root of the bean seedling. Fig. 4.2 shows the distribution of the different tissues in this root using a microscope. Fig. 4.2 (i) Draw a clear straight line on your diagram in (a)(i) to represent the transverse section that the student made. [1] (ii) Label the xylem tissue on Fig. 4.2. [1] (c) Outline a method the student could use to find where the xylem tissue is distributed in the stem of the bean seedling. [3]
Question paper, page 14
14 © UCLES 2013 0653/61/O/N/13 For Examiner's Use 5 The science class is making a display to show the elements in Period 3 of the Periodic Table, as in Fig. 5.1. A sample of each element is placed next to a card giving its symbol and atomic number. Ar 18 Cl 17 Mg 12 S 16 Al 13 P 15 Si 14 Na 11 liquid liquid Elements of Period 3 of the Periodic Table Fig. 5.1 (a) Write the names of element number 12 and element number 14. 12 14 [2] (b) Elements 11 and 15 are contained in bottles and covered with a liquid to prevent the element reacting with air. One element is covered by water and the other one by oil. Complete the sentences. The name of the element covered by water is . The name of the element covered by oil is . [1]
Question paper, page 15
15 © UCLES 2013 0653/61/O/N/13 [Turn over For Examiner's Use (c) The two gas-jars holding samples of elements 17 and 18 have lost their labels. How can a student tell from the appearance of the gases which gas-jar contains element number 17? [1] (d) Describe an experiment that a student can do to show that element number 13 is a metal. State the observation that the student will make. You may draw a diagram to help you. [2]
Question paper, page 16
16 © UCLES 2013 0653/61/O/N/13 For Examiner's Use Another student is doing an experiment to show the burning of element number 16 in oxygen. This is shown in Fig. 5.2. busen burner element burning oxygen Fig. 5.2 He places some of the powder in a spoon and heats it in a Bunsen flame. When the element ignites, he holds the spoon in the gas-jar of oxygen. After the powder finishes burning, he adds water to the gas-jar, places the lid on and shakes the jar. Then he adds Universal Indicator (full-range indicator) solution. (e) (i) State the flame colour of the burning element number 16. [1] (ii) Suggest why the student adds water to the gas-jar. [1] (iii) State the colour of the Universal Indicator (full-range indicator) in the gas-jar. [1] (iv) The student does the same experiment with a piece of element number 12. Suggest the colour of the Universal Indicator in this gas-jar. [1]
Question paper, page 17
17 © UCLES 2013 0654/61/O/N/13 [Turn over Please turn over for Question 6.
Question paper, page 18
18 © UCLES 2013 0653/61/O/N/13 For Examiner's Use 6 A student is finding the accurate value for the electrical resistance of a piece of resistance wire of length 1 metre. He uses the circuit shown in Fig. 6.1. d.c. source – + V A 1 metre long wire switch variable resistor Fig. 6.1 • The student sets the variable resistance at a high value. • He closes the switch. • He reads the ammeter to the nearest 0.01 A and the voltmeter to the nearest 0.05 V. He records the values in Table 6.1, reading number 1. • He opens the switch and decreases the variable resistance. • He closes the switch and records the new values for current and voltage, reading number 2. • He repeats this procedure until he has five sets of readings. Table 6.1 reading number 1 2 3 4 5 current / A 0.16 0.20 0.34 voltage / V 0.90 1.15 2.00 resistance of wire / ohms 5.6 5.7 5.9
Question paper, page 19
19 © UCLES 2013 0653/61/O/N/13 [Turn over For Examiner's Use (a) The ammeter and voltmeter dials for the missing readings are shown in Fig. 6.2. Record in Table 6.1 the values of current and voltage to the nearest 0.01 A and 0.05 V. [4] A 0 0.1 0.2 0.3 0.4 0.5 A 0 0.1 0.2 0.3 0.4 0.5 V 0 1 2 V 0 1 2 reading number 3 reading number 4 reading number 3 reading number 4 Fig. 6.2 (b) (i) Find the resistance of the wire using the values for readings numbers 3 and 4 and record the answers in Table 6.1. Calculate the resistance in ohms to one decimal place. Use the formula resistance = current voltage [2]
Question paper, page 20
20 Permission to reproduce items where third-party owned material protected by copyright is included has been sought and cleared where possible. Every reasonable effort has been made by the publisher (UCLES) to trace copyright holders, but if any items requiring clearance have unwittingly been included, the publisher will be pleased to make amends at the earliest possible opportunity. University of Cambridge International Examinations is part of the Cambridge Assessment Group. Cambridge Assessment is the brand name of University of Cambridge Local Examinations Syndicate (UCLES), which is itself a department of the University of Cambridge. © UCLES 2013 0653/61/O/N/13 For Examiner's Use (ii) The values of the resistance of the wire obtained from the five readings are not all the same. Study the experimental details again. Suggest a reason why the calculated values of the resistance are not all the same. [1] (iii) The student decides that reading number 5 gave the best value for the resistance of the wire. Suggest a better way of using the results to find the resistance of the wire. (You do not have to find the value for the resistance.) [1] (c) A current travels through the resistance wire each time that the student closes the switch. The teacher says that when the current is flowing, particles are passed from atom to atom along the wire. (i) Name these particles. [1] (ii) On Fig. 6.1, draw an arrow to show the direction of movement of these particles along the resistance wire. [1]
Mark scheme, page 1
CAMBRIDGE INTERNATIONAL EXAMINATIONS International General Certificate of Secondary Education MARK SCHEME for the October/November 2013 series 0653 COMBINED SCIENCE 0653/61 Paper 6 (Alternative to Practical), maximum raw mark 60 This mark scheme is published as an aid to teachers and candidates, to indicate the requirements of the examination. It shows the basis on which Examiners were instructed to award marks. It does not indicate the details of the discussions that took place at an Examiners’ meeting before marking began, which would have considered the acceptability of alternative answers. Mark schemes should be read in conjunction with the question paper and the Principal Examiner Report for Teachers. Cambridge will not enter into discussions about these mark schemes. Cambridge is publishing the mark schemes for the October/November 2013 series for most IGCSE, GCE Advanced Level and Advanced Subsidiary Level components and some Ordinary Level components. www.XtremePapers.com
Mark scheme, page 2
Page 2 Mark Scheme Syllabus Paper IGCSE – October/November 2013 0653 61 © Cambridge International Examinations 2013 1 (a) (i) blue-black ; [1] (ii) starch (still) present ; [1] (iii) (for sugar accept glucose, maltose, etc.) rows 2 to 4 correct, i.e. sugar absent, starch absent, sugar absent ; rows 5 to 8 correct, i.e. starch absent, sugar present, starch absent, sugar present ; [2] (b) (i) (breaks down / converts) starch to sugar ; [1] (ii) sugar molecules can pass through ; because molecules are small (enough to pass through) ; sugar present in the water or the beaker ; (any two, ignore refs to diffusion) [max 2] (c) (i) small intestine (allow duodenum, ilium) ; [1] (ii) blood / capillaries ; [1] (d) because molecules are too big / so that it can be absorbed / diffused ; [1] [Total: 10] 2 (a) (i) 67.8 ; 62.9 ; (no tolerance) [2] (ii) 67.8 – 45 = 22.8 (ecf) ; 62.9 – 25 = 37.9 (ecf) ; [2] (iii) 22.8/45 = 0.51 (ecf) ; 37.9/25 = 1.52 (ecf) ; [2] (b) (i) points plotted ± 1 small square ; (allow 1 error) best straight line drawn ; [2] (ii) clear evidence shown on graph ; 14.5 – 15.5 (ecf) ; [2] [Total: 10]
Mark scheme, page 3
Page 3 Mark Scheme Syllabus Paper IGCSE – October/November 2013 0653 61 © Cambridge International Examinations 2013 3 (a) (i) limewater becomes cloudy / milky / white ppt / white solid forms ; [1] (ii) carbon dioxide/CO2 ; [1] (iii) solid X is a (metal) carbonate or hydrogen carbonate (bicarbonate); [1] (b) diagram shows filter funnel containing paper and collecting vessel ; any two relevant labels ; [2] (c) (i) copper(II) hydroxide (allow copper hydroxide) ; [1] (ii) (dark) blue solution (both words necessary) ; [1] (d) (i) (blue solution) becomes colourless / green (solution) ; [1] (ii) (grey) filings become copper coloured / pink / brown / orange ; [1] (e) copper(II) carbonate (allow copper carbonate) AND CuCO3 (both correct) ; [1] [Total: 10] 4 (a) (i) diagram clearly drawn with sharp pencil ; diagram roughly to scale ; [2] (ii) In the range 52 mm to 57 mm ; [1] (iii) answer according to students own diagram ; [1] (iv) magnification correctly calculated from student’s own data ; [1] (b) (i) line correctly drawn through main part of root to make a transverse section ; [1] (ii) one area of xylem correctly labelled (the cross) ; [1] (c) cut seedling through stem ; put in coloured liquid ; and leave for a while ; cut section through stem and view with microscope / hand lens ; xylem will be coloured by the coloured liquid ; [max 3] [Total: 10]
Mark scheme, page 4
Page 4 Mark Scheme Syllabus Paper IGCSE – October/November 2013 0653 61 © Cambridge International Examinations 2013 5 (a) magnesium ; silicon ; [2] (b) phosphorus sodium ; (must be in correct order) [1] (c) (element number 17) (chlorine) is yellow / green / not colourless / is coloured ; [1] (d) include the sample in an electrical circuit / try to make it conduct electricity ; observation: bulb lights up / ammeter shows a reading ; [2] (e) (i) blue ; [1] (ii) to dissolve / make a solution ; [1] (iii) red / pink / orange ; (accept yellow) [1] (iv) blue / indigo / violet ; (accept dark green) [1] [Total: 10] 6 (a) 0.26 A ; 1.55 V ; [2] 0.30 A ; 1.80 V ; all 2dp, penalise once [2] (b) (i) 1.55/0.26 = 6.0 (ecf) ; 1.80/0.30 = 6.0 (ecf) ; [2] (ii) voltage is read to the nearest 0.05 V, giving a possibility of inaccuracy / the wire heats up ; [1] (iii) find the average / plot a graph and find the gradient ; [1] (c) (i) electrons ; [1] (ii) arrow shown pointing from left to right on the resistance wire ; [1] [Total: 10]