C2.2· 14 questions · 32 marks · 38 min · 2017–2025· Structured questions
Every Cambridge IGCSE Mathematics - International Paper 2 question on algebraic manipulation, laid out as 4 A4 pages with the mark scheme below. Nothing is left out. Free to read, no account.
![Question 1: Simplify 4 (2x - 1) - 3 (x - 2) . ..................................................... [2]](https://img.pastlit.com/crops/cc9b678b-fab2-4799-9c9c-e77e40f48e9b/q5.webp)
![Question 2: v = u + at Rearrange the formula to write t in terms of a, u and v. t = ................................................... [2]](https://img.pastlit.com/crops/8bdc0595-e3d1-4f1d-beed-e3743b70aa7a/q7.webp)
1 / 4![Question 4: t = 3p2 (a) Find the value of t when p = 4. t = .................................................... [1] (b) Re-arrange the formula to writ…](https://img.pastlit.com/crops/395e00f2-840e-4048-800d-5b6a9ef37bef/q4.webp)
![Question 5: Find the highest common factor (HCF) of 8p4q8 and 4p3q10. .................................................... [2]](https://img.pastlit.com/crops/395e00f2-840e-4048-800d-5b6a9ef37bef/q14.webp)
2 / 4![Question 7: y = 2 Rearrange the formula to make w the subject. w = ................................................ [1]](https://img.pastlit.com/crops/f762bb7c-3665-42c3-b4d8-45b2802d959e/q11.webp)
![Question 8: Expand the brackets and simplify. 5x (2 - 3 x) - 3x (3x - 2 ) ................................................. [2]](https://img.pastlit.com/crops/8474f23b-d5df-4edc-8a93-91714152e5aa/q9.webp)
![Question 9: Expand. 3 ( 2x - 1) ................................................. [1]](https://img.pastlit.com/crops/ee9d8776-92d9-4913-ad66-74da6b18b9aa/q5.webp)
3 / 4![Question 11: Simplify # . a4 ................................................. [1]](https://img.pastlit.com/crops/fd9da03e-7e7b-4c8c-863d-a3146ed9ad6f/q4.webp)
![Question 12: Simplify. 3x - 2y + x + y ................................................. [2]](https://img.pastlit.com/crops/9fdaa2c8-92d2-491e-bf80-83b9a91170b5/q3.webp)
![Question 13: Simplify fully. (a) 3a - 6b - 2a + b ................................................. [2] (b) 7 ( x - 3) - 2 ( 2x - 1) ...................…](https://img.pastlit.com/crops/dda12d37-1cda-46b9-af22-1b8ceed07be6/q4.webp)
4 / 4Answers below. Sit the paper first if you are practising.
Pastlit
Mathematics - International 0607 · Algebraic manipulation — Paper 2
IGCSE · topical answer key — answer key (teacher use)
Question
Answer
Marks
2
2
4
3
2
5
1
2
1
1
1
2
4
2| Question | Answer | Marks | From |
|---|---|---|---|
| 1 | see sheet | 2 | 0607/22 May/June 2017 |
| 2 | see sheet | 2 | 0607/23 May/June 2017 |
| 3 | see sheet | 4 | 0607/23 Oct/Nov 2018 |
| 4 | see sheet | 3 | 0607/22 May/June 2019 |
| 5 | see sheet | 2 | 0607/22 May/June 2019 |
| 6 | see sheet | 5 | 0607/21 Oct/Nov 2020 |
| 7 | see sheet | 1 | 0607/22 Oct/Nov 2021 |
| 8 | see sheet | 2 | 0607/23 Oct/Nov 2021 |
| 9 | see sheet | 1 | 0607/23 May/June 2022 |
| 10 | see sheet | 1 | 0607/21 Oct/Nov 2022 |
| 11 | see sheet | 1 | 0607/22 Feb/March 2024 |
| 12 | see sheet | 2 | 0607/21 May/June 2024 |
| 13 | see sheet | 4 | 0607/23 May/June 2024 |
| 14 | see sheet | 2 | 0607/23 May/June 2025 |
5 Simplify 4 (2x - 1) - 3 (x - 2) . … [2]
2 marks
Mark scheme: 5 5x + 2 final answer 2 B1 for ax + 2 or 5x + b
7 v = u + at Rearrange the formula to write t in terms of a, u and v. t = … [2]
2 marks
Mark scheme: 7 v − u 2 M1 for correct rearrangement for at or t oe final answer M1 for correct division by a a
1 y = mx + c 1 (a) Find y when m = , x = -2 and c = 4. 2 y = … [2] (b) Rearrange the formula to write m in terms of x, y and c. m = … [2]
4 marks
Mark scheme: Question Answer Marks Partial Marks 1(a) 3 2 1 M1 for × ( −2 ) + 4 2 1(b) y − c 2 M1 for correct rearrangement to oe final answer isolate the m term x M1 for correct division by x
4 t = 3p2 (a) Find the value of t when p = 4. t = … [1] (b) Re-arrange the formula to write p in terms of t. p = … [2]
3 marks
Mark scheme: 4(a) 48 1 4(b) t 2 M1 for correct division M1 for correct square root, involving t 3
14 Find the highest common factor (HCF) of 8p4q8 and 4p3q10. … [2]
2 marks
Mark scheme: 14 4p 3 q 8 2 B1 for kp 3 q 8 or 4 p k q 8 or 4 p 3 q k
10 Factorise. (a) 8x + 14 … [1] (b) 8ax 2 - 6bx 3 … [2] (c) 6ax + 9 ay - 8bx - 12by … [2]
5 marks
Mark scheme: 10(a) 2(4 x + 7) 1 10(b) 2 x 2 (4a − 3bx ) 2 M1 for a correct partial factorisation e.g. 2(4ax 2 − 3bx3 ) or x(8ax − 6bx 2 ) or x 2(8a − 6bx) or 2 x(4ax − 3bx 2 ) 10(c) (2 x + 3 y )(3a − 4b) 2 M1 for 3a (2 x + 3 y ) − 4b(3 y + 2 x ) or 2 x(3a − 4b) + 3 y (3a − 4b)
11 y = 2 Rearrange the formula to make w the subject. w = … [1]
1 marks
Mark scheme: 11 2y final answer 1
9 Expand the brackets and simplify. 5x (2 - 3 x) - 3x (3x - 2 ) … [2]
2 marks
Mark scheme: 9 −24 x 2 + 16 x final answer 2 B1 for −24 x 2 + kx or kx 2 + 16 x as answer or M1 for 10 x − 15 x 2 or −9 x 2 + 6 x
5 Expand. 3 ( 2x - 1) … [1]
1 marks
Mark scheme: 5 6x – 3 final answer 1
3 Expand. 3 ( x - 2y) … [1]
1 marks
Mark scheme: 3 3 x − 6 y final answer 1
4 Simplify # . a4 … [1]
1 marks
Mark scheme: 4 a6 1
3 Simplify. 3x - 2y + x + y … [2]
2 marks
Mark scheme: 3 4x y final answer 2 B1 for each term
4 Simplify fully. (a) 3a - 6b - 2a + b … [2] (b) 7 ( x - 3) - 2 ( 2x - 1) … [2]
4 marks
Mark scheme: 4(a) a – 5b Final answer 2 B1 for a – kb or ka – 5b 4(b) 3x – 19 Final answer 2 B1 for 3x + k or kx – 19 or M1 for 7x – 21 – 4x + 2
3 Simplify. 2x - 3y - x - 2y … [2]
2 marks
Mark scheme: 3 x − 5 y 2 B1 for x + ky or kx − 5 y , k not zero