Cambridge IGCSE Mathematics 0580 — 2024 Feb/March Paper 3 · Variant 2
0580/32/F/M/24 · 8 questions · 104 marks · ≈117 min
The question paper and its mark scheme, free to read here and free to download. This is Cambridge’s own paper, exactly as it was sat.
Question paper16 pages
















Mark scheme8 pages
Answers below. Sit the paper first if you are practising.








Questions as text
Q1 · L P Draw a line through point P that is perpendicular to line l
1 (a) l P Draw a line through point P that is perpendicular to line l. [1] (b) Write down the mathematical names for two different quadrilaterals with • two lines of symmetry and • rotational symmetry of order two. ....................................... and ........................................ [2] (c) The diagram shows a quadrilateral on a 1 cm2 grid. Find the area of this quadrilateral. .......................................... cm2 [1] (d) H G x° F 143° 103° NOT TO SCALE 82° E y° D The diagram shows a quadrilateral DEFG and a straight line FGH. (i) Angle DEF = 82° . Write down the mathematical name for this type of angle. ................................................. [1] (ii) Work out the value of x. Give a geometrical reason for your answer. x = .......................... because ............................................................................................. ............................................................................................................................................. [2] (iii) Work out the value of y. Give a geometrical reason for your answer. y = .......................... because ............................................................................................. ............................................................................................................................................. [2]
Mark scheme: Question Answer Marks Partial Marks 1(a) Ruled line drawn through P, 1 perpendicular to l. 1(b) rectangle rhombus 2 B1 for each 1(c) 11 1 1(d)(i) acute 1 1(d)(ii) 37 1 Angles on a straight line add to 180 1 1(d)(iii) 32 1 Angles in a quadrilateral add to 360 1
Q2 · Fuel Fuel Garage A Garage B $1.41 per litre $1.50 per litre (i) Tiya buys 55 litres of…
2 (a) Fuel Fuel Garage A Garage B $1.41 per litre $1.50 per litre (i) Tiya buys 55 litres of fuel from garage A. Work out the change she receives from $100. $ ................................................. [2] (ii) Work out how much cheaper it is to buy 20 litres of fuel from garage A than from garage B. $ ................................................. [2] (iii) These are the amounts that 6 people spend on fuel at garage A. $63 $84.50 $72.23 $46 $54.10 $80 Calculate the mean number of litres that they buy. ......................................... litres [3] (iv) The cost of fuel at garage B increases from $1.50 to $1.53 . Calculate the percentage increase. ..............................................% [2] 2(b) The fuel tank of a car is full. 5 It takes 39 more litres of fuel to fill the tank. Work out the number of litres of fuel in a full tank. ......................................... litres [3] (c) (i) Use 1 litre = .022 gallons to complete this conversion graph. 30 25 20 Gallons 15 10 5 0 0 10 20 30 40 50 60 70 80 90 100 Litres [2] (ii) Use 1 litre = .022 gallons to complete this statement. 1 gallon = .............................. litres. [1] (d) A cylindrical tank for storing fuel has radius 1.5 metres and height 8 metres. Calculate the volume of the tank in litres. ......................................... litres [3]
Mark scheme: 2(a)(i) 22.45 2 M1 for 100 − 55 1.41 oe or B1 for 77.55 2(a)(ii) 1.8[0] 2 M1 for (1.50 − 1.41) 20 oe or B1 for 30 and 28.2[0] seen 2(a)(iii) 47.3 or 47.26… 3 M2 for 63 + 84.5 + 72.23 + 46 + 54.10 + 80 oe 6 1.41 or M1 for 63 + 84.5 + 72.23 + 46 + 54.10 + 80 oe 1.41 63 + 84.5 + 72.23 + 46 + 54.10 + 80 or oe 6 2(a)(iv) 2 2 1.53 − 1.50 M1 for 100 oe 1.50 1.53 or 100 −100 oe 1.50 1.53 or − 1 100 oe 1.50 2(b) 65 3 5 M2 for 39 oe 3 3 or M1 for 39 is equivalent to or for 5 39 3 5 if 0 scored then SC1 for 39 oe 2 2(c)(i) A straight line through (0,0) and (100,22) 2 B1 for a straight line drawn through the origin or for 2 correct points plotted 2(c)(ii) 4.55 or 4.545… 1 2(d) 56500, 56600 or 56540 to 56560…. 3 M2 for 1.5 2 ×8×1000 oe or 150 2 ×800÷1000 oe or M1 for 1.5 2 ×8 oe or 150 2 ×800 oe or B1 for final answer figs 565 to 566 If 0 scored, SC1: for their volume in m3 1000 or for their volume in cm3 1000 or for stating clearly 1m3=1000l or 1000 cm3=1l
Q3 · In triangle DEF, DE = 6 cm and DF = 4
3 (a) In triangle DEF, DE = 6 cm and DF = 4. 8 cm . Using a ruler and compasses only, construct triangle DEF. Leave in your construction arcs. The line EF has been drawn for you. E F [2] (b) B A C T D F G E (i) Write down the letter of the triangle that is congruent to triangle T. ................................................. [1] (ii) Write down the letter of the triangle that is similar but not congruent to triangle T. ................................................. [1] (c) NOT TO SCALE h 62° 62° 7 cm The diagram shows an isosceles triangle. (i) Show that the perpendicular height, h, is 6.58 cm, correct to 3 significant figures. [3] (ii) Calculate the area of the triangle. Give the units of your answer. ........................................... ...................... [3] (iii) Kalpit tries to arrange some of these triangles to make a regular polygon with centre O. O NOT TO SCALE 7 cm 7 cm 62° 62° 7 cm Show that Kalpit cannot make a regular polygon. [3]
Mark scheme: 3(a) Correct triangle drawn with construction 2 B1 for correct triangle drawn with arcs. incorrect or no arcs or for 2 correct arcs drawn If 0 scored, SC1 for reversed triangle with arcs. 3(b)(i) G 1 3(b)(ii) F 1 3(c)(i) 7 M2 h [h=] tan 62 oe M1 for tan62 = oe 2 7 2 6.582 to 6.583 A1 3(c)(ii) 23[.0] or 23.03 to 23.04… 2 1 M1 for 7 6.58 oe 2 cm2 1 3(c)(iii) 360 M2 M1 for 180 −2 62 oe 180 −2 62 6.4… which is not integer oe A1
Q4 · A shop sells 58 televisions in one week
4 (a) A shop sells 58 televisions in one week. The bar chart shows the number of televisions that the shop sells on five of the days. 16 14 12 10 Number of 8 televisions 6 4 2 0 Monday Tuesday Wednesday Thursday Friday Saturday Sunday (i) Write down the number of televisions that the shop sells on Monday. ................................................. [1] (ii) Find the fraction of the televisions that the shop sells on Sunday. ................................................. [1] (iii) The number of televisions that the shop sells on the other two days is in the ratio Wednesday : Friday = 2 : 3. Complete the bar chart. [4] (iv) Write down the mode. ................................................. [1] (b) A television has a price of $550. This price is reduced by 4%. Calculate the new price of this television. $ ................................................. [2] (c) The scatter diagram shows the prices of different sized televisions. Price Television size Write down the type of correlation shown in the scatter diagram. ................................................. [1] (d) Hemang buys two televisions. The probability that a television is faulty is 0.02 . 1st television 2nd television faulty .............. faulty 0.02 not faulty .............. faulty .............. .............. not faulty not faulty .............. (i) Complete the tree diagram. [2] (ii) Find the probability that Hemang buys two faulty televisions. ................................................. [2] (iii) The shop sells 4150 televisions in one year. Calculate the expected number of faulty televisions. ................................................. [1]
Mark scheme: 4(a)(i) 3 1 4(a)(ii) 11 1 cao 58 4(a)(iii) Completely correct bar chart 4 B3 for a bar height 8 drawn for Wednesday or a bar height 12 drawn for Friday. or 58 −−3 4 − 4 − 16 − 11 M2 for k , 2 + 3 k = 1,2 or 3 or M1 for 58 −−−−3 4 4 16 − 11 oe If 0 scored SC1 for 2 bars drawn correctly from their identified values in working 4(a)(iv) Saturday 1 4(b) 528 2 4 M1 for 550 1 − oe 100 or B1 for 22 4(c) Positive 1 4(d)(i) 0.02 2 B1 for 0.98 correctly placed once on tree 0.98 or for 0.02 correctly placed twice on tree. 0.98 0.02 0.98 oe 4(d)(ii) 0.0004 oe 2 M1 for 0.02 × 0.02 4(d)(iii) 83 1
Q5 · Complete the table of values for y =- x 2 + 5x + 7
5 (a) (i) Complete the table of values for y =- x 2 + 5x + 7 . x -1 0 1 2 3 4 5 6 y 11 11 1 [3] (ii) On the grid, draw the graph of y =- x 2 + 5x + 7 for - 1 G x G 6 . y 14 13 12 11 10 9 8 7 6 5 4 3 2 1 – 1 0 1 2 3 4 5 6 x [4] (iii) (a) Write down the equation of the line of symmetry of the graph. ................................................. [1] (b) The points ( -8, -97) and ( t, -97) also lie on the graph of y =- x 2 + 5 x + 7 . Use symmetry to find the value of t. t = ................................................. [1] (b) Write down the gradient of the line y = 9x - 4 . ................................................. [1] (c) Write down the equation of a line parallel to y =-5x + 19 . y = ................................................. [1] (d) y 7 6 L 5 4 3 2 1 – 4 – 3 – 2 – 1 0 1 2 3 4 x – 1 – 2 – 3 Find the equation of line L in the form y = mx + c . y = ................................................. [2] (e) Make x the subject of the formula y = mx + c . x = ................................................. [2]
Mark scheme: 5(a)(i) 1, 7, 13, 13, 7 3 B2 for 3 or 4 correct or B1 for 1 or 2 correct 5(a)(ii) Completely correct curve 4 B3FT for 7 or 8 correctly plotted points or B2FT for 5 or 6 correctly plotted points or B1FT for 3 or 4 correctly plotted points 5(a)(iii)(a) x = 2.5 oe 1 5(a)(iii)(b) 13 1 5(b) 9 1 5(c) y = −5 x + k where k 19 1 5(d) y = − x + 2 final answer 2 B1 for y = − x + c or y = mx + 2 where m is their gradient 5(e) − c 2 M1 for a correct first step x = y oe final answer m y c y −=c mx or = x + m m
Q6 · Town S is 44 km from town R on a bearing of 117°
6 (a) Town S is 44 km from town R on a bearing of 117°. (i) Using a scale of 1 cm represents 8 km, mark the position of town S. North R Scale: 1 cm to 8 km [2] (ii) Anvi cycles the 44 km from R to S. She leaves R at 13 15 and cycles at a speed of 12 km/h. Work out the time she arrives at S. ................................................. [3] (b) A tower has a height of 16 metres. When Jai makes a scale drawing of the tower it has a height of 20 cm. Work out the scale Jai uses, giving your answer in the form 1 : n. 1 : ................................................. [2] (c) X, Y and Z are three towns. Z North NOT TO 9.7 km SCALE X 6 km Y X is on a bearing of 288° from Y. Z is on a bearing of 018° from Y. (i) Show that angle XYZ is 90°. [2] (ii) XY = 6 km and YZ = 9.7 km . Calculate XZ. XZ = ............................................ km [2]
Mark scheme: 6(a)(i) The position of S correctly marked on the 2 B1 for S on bearing 117° from R diagram B1 for S 5.5 cm from R 6(a)(ii) 16 55 3 B2 for 3 [h] 40 [min] 44 or M1 for 12 6(b) [1:]80 2 M1 for 20:1600 or 0.2:16 or better 1600 16 or or 20 0.2 or B1 for answer figs 8 6(c)(i) 360 − 288 + 18 oe M2 M1 for 360 − 288 or 288 − 18 If 0 scored SC1 for 72 and 18 correctly marked on the diagram 6(c)(ii) 11.4 or 11.40 to 11.41 2 M1 for 6 2 + 9.7 2 or better
Q7 · P = 3a + 5 Find the value of P when a = 2
7 (a) P = 3a + 5 Find the value of P when a = 2 . P = ................................................. [1] (b) Solve these equations. (i) 7x =-42 x = ................................................. [1] (ii) 9 ( 8x - 7) = 72 x = ................................................. [3] (c) 5 8 # 5 k = 5 -24 Find the value of k. k = ................................................. [1] (d) Solve the simultaneous equations. -6x - y = 13 8x + y =- 51 x = ................................................. y = ................................................. [2] (e) n is an integer where n 2- 3 and n G 1. Write down all the possible values of n. ................................................. [2] (f) A boy walks for 35 minutes at x metres per minute. He then runs for t minutes at 160 metres per minute. Write down an expression, in terms of x and t, for the total distance, in metres, the boy travels. .............................................. m [2] (g) NOT TO SCALE x – 2 x + 5 Find an expression for the area of this rectangle. Give your answer in the form x 2 + ax + b . ................................................. [3] Question 8 is printed on the next page.
Mark scheme: 7(a) 11 1 7(b)(i) −6 1 7(b)(ii) 1.875 oe 3 M1 for a correct first step e.g. 8 x − 7 = 8 or 72 x− 63 = 72 M1FT for a correct second step e.g. 8 x = 15 or 72 x = 135 7(c) −32 1 7(d) x = − 19 y = 101 2 B1 for x = − 19 B1 for y = 101 7(e) −2, −1, 0, 1 2 B1 for 3 correct and no extras or 4 correct and one extra 7(f) 35x + 160t final answer 2 B1 for 35x or 160t seen in final answer or 35 x + 160t seen and spoilt 7(g) x 2 + 3 x − 10 final answer 3 B2 for x 2 + 5 x − 2 x − 10 with at least 3 terms correct or B1 for ( x + 5 )( x − 2 ) oe
Q8 · 120 people teach in a university mathematics department
8 (a) 120 people teach in a university mathematics department. Some information is shown in the table. Lecturers Professors Total Part-time 11 Full-time Total 120 One fifth of the people are professors. 30% of the people are part-time. Work out the number of full-time lecturers. ................................................. [4] (b) % = {children in a school} F = {children who like fruit} V = {children who like vegetables} 24 children like vegetables but do not like fruit. 8 children do not like fruit and do not like vegetables. n ( F + V ) = 9 n ( F ) = 3 # n ( V ) F V ........ ........ ........ ........ (i) Complete the Venn diagram. [3] (ii) Work out n ( F , V ) . ................................................. [1]
Mark scheme: 8(a) 71 nfww 4 B3 for 13 and 84 or for 25 and 96 OR B1 for 24 or 96 B1 for 36 or 84 8(b)(i) 3 If answer incorrect can score a maximum of 2 from: F V B1 for 24 and 8 correctly placed 90 9 24 B1 for 9 correctly placed B1FT for their n(F)= 3×their n(V) 8 8(b)(ii) 123 1 B1FT for their n(F V)
What was in this paper
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Cambridge’s own grade thresholds for 2024 Feb/March, Paper 3 · Variant 2. A higher threshold means an easier paper — the bar moves with how the cohort did.