Cambridge IGCSE Mathematics 0580 — 2012 May/June Paper 2 · Variant 1

0580/21/M/J/12 · 21 questions · 70 marks · ≈79 min

The question paper and its mark scheme, free to read here and free to download. This is Cambridge’s own paper, exactly as it was sat.

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Question paper12 pages

Cambridge IGCSE Mathematics 0580 2012 May/June Paper 2 · Variant 1 question paper, page 1 of 12
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Mark scheme4 pages

Answers below. Sit the paper first if you are practising.

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Questions as text

Q1 · The price of a ticket for a football match is $124

1 The price of a ticket for a football match is $124 . For Examiner's (a) Calculate the amount received when 76 500 tickets are sold. Use Answer(a) $ [1] (b) Write your answer to part (a) in standard form. Answer(b) $ [1]

Mark scheme: Qu Answers Mark Part marks 1 (a) 9486000 1 (b) 9.486 × 106 1ft

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Q2 · Gregor changes $700 into euros (€) when the rate is €1 = $1.4131

2 Gregor changes $700 into euros (€) when the rate is €1 = $1.4131 . Calculate the amount he receives. Answer € [2]

Mark scheme: 2 495.36 2 M1 for 700 ÷ 1.4131

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Question 3

3 Factorise completely. 15p2 + 24pt Answer [2]

Mark scheme: 3 3p(5p + 8t) final answer 2 B1 for answer of 3(5p2 + 8pt) or p(15p + 24t) or SC1 for correct answer seen in working 8

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Q4 · Write the following in order of size, smallest first

4 Write the following in order of size, smallest first. 8 0.47 0.22 tan 25° 17 Answer < < < [2]

Mark scheme: 8 4 tan 25 < 0.22 < 0.47 < 2 M1 correct conversion to decimals 0.466, 0.469, 0.471 17 x

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Q5 · For Examiner's NOT TO Use 29 cm SCALE x cm 53.2° Calculate the value of x

5 For Examiner's NOT TO Use 29 cm SCALE x cm 53.2° Calculate the value of x. Answer x = [2]

Mark scheme: x 5 23.2 2 M1 for sin 53.2 = implicit form or better 29 8 + 4 + 8 + 9 + y

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Q6 · Leon scores the following marks in 5 tests

6 Leon scores the following marks in 5 tests. 8 4 8 y 9 His mean mark is 7.2. Calculate the value of y. Answer y = [2]

Mark scheme: 8 + 4 + 8 + 9 + y 6 7 2 M1 = 7 .2 oe 5

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Q7 · The sides of a rectangle are 6.3 cm and 4.8 cm, each correct to 1 decimal place

7 The sides of a rectangle are 6.3 cm and 4.8 cm, each correct to 1 decimal place. Calculate the upper bound for the area of the rectangle. Answer cm2 [2]

Mark scheme: 7 30.7975 cao 2 M1 6.35 and 4.85 seen

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Q8 · Find r when (5) 3 = 125

8 Find r when (5) 3 = 125 . Examiner's Use Answer r = [2]

Mark scheme: 8 9 2 M1 125 = 5 3

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Q9 · D A B (a) The point C lies on AD and angle ABC = 67°

9 D A B (a) The point C lies on AD and angle ABC = 67°. Draw accurately the line BC. [1] (b) Using a straight edge and compasses only, construct the perpendicular bisector of AB. Show clearly all your construction arcs. [2]

Mark scheme: 9 (a) 1 B1 C marked on AD unless the line stops at AD and angle of 67° at B also correct ruled line (b) 2 B1 correct arcs B1 correct ruled line perpendicular bisector of AB 750 × 5 × 2 5

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Q10 · For 10 Shania invests $750 at a rate of 2 2 % per year simple interest

1 For 10 Shania invests $750 at a rate of 2 2 % per year simple interest. Examiner's Use Calculate the total amount Shania has after 5 years. Answer $ [3]

Mark scheme: 750 × 5 × 5.2 10 843.75 3 M2 for + 750 oe 100 750 × 5 × 5.2 or M1 for oe 100 or SC2 for answer 93.75 IGCSE – May/June 2012 0580 21

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Q11 · Solve the simultaneous equations

11 Solve the simultaneous equations. 3x + 5y = 24 x + 7y = 56 Answer x = y = [3]

Mark scheme: 11 x = −7 3 M1 for consistent multiplication and addition/ y = 9 subtraction as appropriate. Allow computational errors A1 for x= –7 or y = 9 55 27 25 27

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Q12 · 9 For 12 Without using your calculator, work out 1 +

5 9 For 12 Without using your calculator, work out 1 + . Examiner's 6 10 Use You must show your working and give your answer as a mixed number in its simplest form. Answer [3]

Mark scheme: 55 27 25 27 12 + oe or )1( + oe M1 for denominator of 30k 30 30 30 30 82 52 oe or )1( oe M1 for denominator of 30k dependent on previous M1 30 30 11 2 M2 must be scored A1 If M0 scored then SC1 for common denominator of 15 30k seen k

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Q13 · Y is inversely proportional to x2

13 y is inversely proportional to x2. When x = 4, y = 3. Find y when x = 5. Answer y = [3]

Mark scheme: k 13 1.92 3 M1 y = 2 oe B1 for k = 48 x

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Q14 · For y Examiner's Use 7 6 5 4 3 2 1 x –8 –7 –6 –5 –4 –3 –2 –1 0 1 2 3 4 5 6 7 –1 The…

14 For y Examiner's Use 7 6 5 4 3 2 1 x –8 –7 –6 –5 –4 –3 –2 –1 0 1 2 3 4 5 6 7 –1 The region R contains points which satisfy the inequalities 1 y Y x + 4, y [ 3 and x + y [ 6. 2 On the grid, label with the letter R the region which satisfies these inequalities. You must shade the unwanted regions. [3]

Mark scheme: 14 2 R 3 1 3 2 0 1 2

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Q15 · The scale of a map is 1 : 500 000

15 The scale of a map is 1 : 500 000 . (a) The actual distance between two towns is 172 km. Calculate the distance, in centimetres, between the towns on the map. Answer(a) cm [2] (b) The area of a lake on the map is 12 cm2. Calculate the actual area of the lake in km2. Answer(b) km2 [2]

Mark scheme: 15 (a) 34.4 2 SC1 figs 344 seen (b) 300 2 SC1 figs 3 seen − 1 2 

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Q16 ·  5 2   − 1 − 2  For Examiner's16 M =   N =    − 3 4   2 6  Use Calculate…

 5 2   − 1 − 2  For Examiner's16 M =   N =    − 3 4   2 6  Use Calculate (a) MN, Answer(a) MN = [2] (b) M−1, the inverse of M. Answer(b) M–1 = [2]

Mark scheme:  1 2  16 (a)   2 B1 any two entries correct  11 30  1  4 − 2  1  a b   4 − 2  (b)   oe 2 B1   or k   26  3 5  26  c d   3 5  4 3c

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Q17 · Make w the subject of the formula

17 Make w the subject of the formula. 4 + w c = w + 3 Answer w = [4]

Mark scheme: 4 − 3c 17 w = www 4 M1 clearing denominator and removing brackets c − 1 M1 correctly collecting terms in w on one side only M1 factorising correctly M1 divide by coefficient of w

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Q18 · For 20 Examiner's Use 15 Speed 10 (m / s) 5 0 10 20 30 40 50 60 70 80 90 100 110 120 Time…

18 For 20 Examiner's Use 15 Speed 10 (m / s) 5 0 10 20 30 40 50 60 70 80 90 100 110 120 Time (s) The diagram shows the speed-time graph for the first 120 seconds of a car journey. (a) Calculate the acceleration of the car during the first 25 seconds. Answer(a) m/s2 [1] (b) Calculate the distance travelled by the car in the first 120 seconds. Answer(b) m [4]

Mark scheme: 18 (a) 0.8 1 (b) 1850 4 M1 for area = distance travelled M1 for two correct area statements M1 for complete correct area statement IGCSE – May/June 2012 0580 21

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Q19 · For S R Examiner's Use T Q t O P p O is the origin and OPQRST is a regular hexagon

19 For S R Examiner's Use T Q t O P p O is the origin and OPQRST is a regular hexagon. = p and = t. Find, in terms of p and t, in their simplest forms, (a) , Answer(a) = [1] (b) , Answer(b) = [2] (c) the position vector of R. Answer(c) [2]

Mark scheme: 19 (a) −p + t 1 (b) p + 2t 2 M1 for a correct route from P to R or unsimplified answer (c) 2(p + t) or 2p + 2t 2ft M1 for OR or a correct route or ft p + their (b) unsimplified provided their (b) is a vector PT

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Q20 · For R Examiner's Use NOT TO O SCALE 78° 5 cm P T R and T are points on a circle, centre…

20 For R Examiner's Use NOT TO O SCALE 78° 5 cm P T R and T are points on a circle, centre O, with radius 5 cm. PR and PT are tangents to the circle and angle POT = 78°. A thin rope goes from P to R, around the major arc RT and then from T to P. Calculate the length of the rope. Answer cm [6] Question 21 is printed on the next page.

Mark scheme: PT 20 64.8 to 64.9 6 M2 5 tan 78 soi by 23.5 or M1 tan 78 = or 5 5 5 sin 78 or tan 12 sin 12 360 − 2 × 78 M2 × 2 × π × 5 soi by 17.8 360 or M1 for 2π5 seen used M1 for their arc + 2 (their PT) 1 3 2

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Q21 · In this question, give all your answers as fractions

21 In this question, give all your answers as fractions. For Examiner's A box contains 3 red pencils, 2 blue pencils and 4 green pencils. Use Raj chooses 2 pencils at random, without replacement. Calculate the probability that (a) they are both red, Answer(a) [2] (b) they are both the same colour, Answer(b) [3] (c) exactly one of the two pencils is green. Answer(c) [3]

Mark scheme: 1 3 2 21 (a) 2 M1 × 12 3 + 2 + 4 (their 9 ) − 1 5 4 × 3 2 (× 1) (b) 3 M2 their(a) + + 18 their 72 their 72 4 × 3 2 (× 1) or M1 or their 72 their 72 5 4 5 (c) 3 M2 2 × × 9 3 + 2 + 4 (their 9 ) − 1 4 5 or M1 × 3 + 2 + 4 (their 9 ) − 1

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What was in this paper

The subtopics covered by these 21 questions, and how many questions each got. Open one in a new tab to see every Cambridge question on it.

What you needed in this session

Cambridge’s own grade thresholds for 2012 May/June, Paper 2 · Variant 1. A higher threshold means an easier paper — the bar moves with how the cohort did.

A54/70
C32/70
E21/70