Cambridge IGCSE Mathematics 0580 — 2011 May/June Paper 2 · Variant 1
0580/21/M/J/11 · 20 questions · 70 marks · ≈79 min
The question paper and its mark scheme, free to read here and free to download. This is Cambridge’s own paper, exactly as it was sat.
Question paper12 pages












Mark scheme3 pages
Answers below. Sit the paper first if you are practising.



Questions as text
Q1 · A concert hall has 1540 seats
1 A concert hall has 1540 seats. ForFor Examiner'sExaminer's Calculate the number of people in the hall when 55% of the seats are occupied. UseUse Answer [1]
Mark scheme: g g Qu. Answers Mark Part Mark 1 847 1
Q2 · Shade the required region on each Venn diagram
2 Shade the required region on each Venn diagram. A B A B A ∪ B' (A ∩ B)' [2]
Mark scheme: 2 correct regions shaded 1, 1
Q3 · Calculate 810.25 ÷ 4−2
3 Calculate 810.25 ÷ 4−2 . Answer [2]
Mark scheme: 3 48 2 B1 for 3 and 16 seen
Q4 · Find m when 4m × 42 = 412
4 (a) Find m when 4m × 42 = 412 . Answer(a) m = [1] p 5 (b) Find p when 6 ÷ 6 = 6 . Answer(b) p = [1]
Mark scheme: 4 (a) 10 1 (b) 5.5 oe 1
Q5 · A hummingbird beats its wings 24 times per second
5 A hummingbird beats its wings 24 times per second. ForFor Examiner'sExaminer's (a) Calculate the number of times the hummingbird beats its wings in one hour. UseUse Answer(a) [1] (b) Write your answer to part (a) in standard form. Answer(b) [1]
Mark scheme: ( ) 5 (a) 86400 1 (b) 8.64 × 104 1ft 3
Q6 · NOT TO SCALE 6 cm 2 cm A company makes solid chocolate eggs and their shapes are…
6 NOT TO SCALE 6 cm 2 cm A company makes solid chocolate eggs and their shapes are mathematically similar. The diagram shows eggs of height 2 cm and 6 cm. The mass of the small egg is 4 g. Calculate the mass of the large egg. Answer g [2]
Mark scheme: 3 6 108 2 M1 for 33 or 27 or 1 or 1 seen 3 27
Q7 · Find the length of the straight line from Q (−8, 1) to R (4 , 6)
7 Find the length of the straight line from Q (−8, 1) to R (4 , 6). Answer QR = [3]
Mark scheme: 7 13 3 B1 for 12, 5 seen M1 for (their 12)2 + (their 5)2 or M2 √[(–8 – 4)2 + (1 – 6)2] oe or M1 if √ missing 3
Q8 · Calculate the radius of a sphere with volume 1260 cm3
8 Calculate the radius of a sphere with volume 1260 cm3 . ForFor 4 Examiner'sExaminer's [The volume, V, of a sphere with radius r is V = πr3.] UseUse 3 Answer cm [3]
Mark scheme: 3 8 6.70 3 M1 for ( r3 = ) 1260 × oe seen 4 π M1 for 3 of their r3 seen or implied
Q9 · A B 2x° NOT TO SCALE C D x° 5x° AB is parallel to CD
9 A B 2x° NOT TO SCALE C D x° 5x° AB is parallel to CD. Calculate the value of x. Answer x = [3]
Mark scheme: 9 22.5 oe 3 B2 180 = 5x +2x + x oe or better B1 for 2x or 6x marked in the correct place on the diagram.
Q10 · Solve the simultaneous equations
10 Solve the simultaneous equations. 3x + y = 30 2x – 3y = 53 Answer x = y = [3]
Mark scheme: g 10 x = 13 3 M1 for consistent multiplication and y = –9 addition/subtraction A1 for x = 13 or A1 for y = -9
Q11 · A rectangular photograph measures 23.3 cm by 19.7 cm, each correct to 1 decimal place
11 A rectangular photograph measures 23.3 cm by 19.7 cm, each correct to 1 decimal place. ForFor Calculate the lower bound for Examiner'sExaminer's UseUse (a) the perimeter, Answer(a) cm [2] (b) the area. Answer(b) cm2 [1]
Mark scheme: y 11 (a) 85.8 2 M1 for 23.25 and 19.65 seen (b) 456.8625 cao 1
Q12 · A train leaves Barcelona at 21 28 and takes 10 hours and 33 minutes to reach Paris
12 A train leaves Barcelona at 21 28 and takes 10 hours and 33 minutes to reach Paris. (a) Calculate the time the next day when the train arrives in Paris. Answer(a) [1] (b) The distance from Barcelona to Paris is 827 km. Calculate the average speed of the train in kilometres per hour. Answer(b) km/h [3]
Mark scheme: ( ) 12 (a) (0)8(.)01 (am) 1 Not 8.01pm (b) 78.4 or 78.38 to 78.39 3 M2 for 827 ÷ 10.55 or M1 for figs 827 ÷ their time 2 7 × 20 000
Q13 · The scale on a map is 1: 20 000
13 The scale on a map is 1: 20 000. ForFor Examiner'sExaminer's (a) Calculate the actual distance between two points which are 2.7 cm apart on the map. UseUse Give your answer in kilometres. Answer(a) km [2] (b) A field has an area of 64 400 m2 . Calculate the area of the field on the map in cm2 . Answer(b) cm2 [2]
Mark scheme: 7.2 × 20 000 13 (a) 0.54 2 M1 for oe 10 0000 or SC1 for figs 54 in answer (b) 1.61 2 SC1 for figs 161 or M1 2002 or 20 0002 seen IGCSE – May/June 2011 0580 21 ( )( )
Q14 · Solve the equation 2x2 + 3x – 6 = 0
14 Solve the equation 2x2 + 3x – 6 = 0. Show all your working and give your answers correct to 2 decimal places. Answer x = or x = [4]
Mark scheme: 14 –2.64, 1.14 cao with working 4 B1 for 32 − 4(2 )(− 6 ) or better seen anywhere B1 for p = –3 and r = 2 × 2 or better as long as in p + q p − q the form or r r After B0B0, SC1 for –2.6 or –2.637(45…) and 1.1 or 1.137(45…)
Q15 · A teacher asks 36 students which musical instruments they play
15 A teacher asks 36 students which musical instruments they play. ForFor Examiner'sExaminer's P = {students who play the piano} UseUse G = {students who play the guitar} D = {students who play the drums} The Venn diagram shows the results. P G x 2 8 1 5 4 7 5 D (a) Find the value of x. Answer(a) x = [1] (b) A student is chosen at random. Find the probability that this student (i) plays the drums but not the guitar, Answer(b)(i) [1] (ii) plays only 2 different instruments. Answer(b)(ii) [1] (c) A student is chosen at random from those who play the guitar. Find the probability that this student plays no other instrument. Answer(c) [1]
Mark scheme: ( ) 15 (a) 4 1 12 (b) (i) oe 0.333 1 36 11 (ii) , 0.306 or 0.3055 to 1 36 0.3056 1 8 (c) oe 0.533(3…) 15 k 2
Q16 · ForFor Examiner'sExaminer's UseUse k cm The diagram shows a square of side k cm
16 ForFor Examiner'sExaminer's UseUse k cm The diagram shows a square of side k cm. The circle inside the square touches all four sides of the square. (a) The shaded area is A cm2. Show that 4A = 4k2 – πk2. Answer (a) [2] (b) Make k the subject of the formula 4A = 4k2 – πk2. Answer(b) k = [3]
Mark scheme: k 16 (a) Answer given 2 M1 (A =)k2 – π 2 πk 2 E1 A = k2 – 4 correctly completed to 4A = 4k2 – πk2 4 A A (b) k = (±) or 2 3 M1 factorising (must contain a π) (4 − π ) (4 − π ) M1 division (by coefficient of k2) M1 square root
Q17 · ForFor C Examiner'sExaminer's UseUse NOT TO SCALE O B 24° T A A, B and C are points on a…
17 ForFor C Examiner'sExaminer's UseUse NOT TO SCALE O B 24° T A A, B and C are points on a circle, centre O. TA is a tangent to the circle at A and OBT is a straight line. AC is a diameter and angle OTA = 24°. Calculate (a) angle AOT, Answer(a) Angle AOT = [2] (b) angle ACB, Answer(b) Angle ACB = [1] (c) angle ABT. Answer(c) Angle ABT = [2]
Mark scheme: q 17 (a) 66° 2 M1 for 90° clearly identified as A (b) 33° 1 (c) 123° 2 B1 for OBA or OAB = 57°
Q18 · ForFor S Examiner'sExaminer's UseUse Q X NOT TO SCALE P M R In the diagram, PQS, PMR, MXS…
18 ForFor S Examiner'sExaminer's UseUse Q X NOT TO SCALE P M R In the diagram, PQS, PMR, MXS and QXR are straight lines. PQ = 2 QS. M is the midpoint of PR. QX : XR = 1 : 3. = q and = r. (a) Find, in terms of q and r, (i) , Answer(a)(i) = [1] (ii) . Answer(a)(ii) = [1] (b) By finding , show that X is the midpoint of MS. Answer (b) [3]
Mark scheme: ( ) 18 (a) (i) -r + q or q – r 1 (ii) ½(3q – r) oe 1 Must be simplified (b) correct working 3 M1 for MX = ½ r + ¾ their (–r + q) M1 using a different route for XS or ½ MS E1 dep correct simplification and conclusion
Q19 · ForFor 15 Examiner'sExaminer's UseUse 10 Speed (metres per second) 5 0 2 4 6 8 10 12 14…
19 ForFor 15 Examiner'sExaminer's UseUse 10 Speed (metres per second) 5 0 2 4 6 8 10 12 14 Time (minutes) The diagram shows the speed-time graph of a train journey between two stations. The train accelerates for two minutes, travels at a constant maximum speed, then slows to a stop. (a) Write down the number of seconds that the train travels at its constant maximum speed. Answer(a) s [1] (b) Calculate the distance between the two stations in metres. Answer(b) m [3] (c) Find the acceleration of the train in the first two minutes. Give your answer in m/s2. Answer(c) m/s2 [2] Question 20 is printed on the next page.
Mark scheme: p p 19 (a) 480 1 (b) 9900 3 M1 for attempt at area under graph M1 for 0.5 × 15 × (their (a) + 14 × 60) oe or 0.5 × 15 × (8 + 14) oe 1 2 M1 for numerical vertical/horizontal or numerical (c) 0.125 or 8 use of v = u + at but t ≤ 120 or t ≤ 2
Q20 · F(x) = x3 g(x) = 2x − 3 ForFor Examiner'sExaminer's UseUse (a) Find (i) g(6)…
20 f(x) = x3 g(x) = 2x − 3 ForFor Examiner'sExaminer's UseUse (a) Find (i) g(6), Answer(a)(i) [1] (ii) f(2x). Answer(a)(ii) [1] (b) Solve fg(x) = 125. Answer(b) x = [3] (c) Find the inverse function g−1(x) . Answer(c) g –1(x) = [2]
Mark scheme: 20 (a) (i) 9 1 (ii) 8x3 cao 1 (b) 4 www 3 M1 for (2x – 3)3 = 125 M1 2x – 3 = 5 (c) x + 3 2 M1 for x ± 3 = 2y or x = y ± 3 2 2
What was in this paper
The subtopics covered by these 20 questions, and how many questions each got. Open one in a new tab to see every Cambridge question on it.
2Rates2Algebraic manipulation1Angles1Circle theorems I1Indices I1Introduction to algebra1Introduction to probability1Length and midpoint1Limits of accuracy1Percentages1Powers and roots1Ratio and proportion1Scale drawings1Sets1Statistical charts and diagrams1Surface area and volume1Vectors in two dimensions1What you needed in this session
Cambridge’s own grade thresholds for 2011 May/June, Paper 2 · Variant 1. A higher threshold means an easier paper — the bar moves with how the cohort did.