Cambridge IGCSE Mathematics (with coursework) 0581 — 2002 Oct/Nov Paper 4 · Variant 1

This question paper consists of 7 printed pages and 1 blank page. SJF2283/CG S14616/1 © UCLES 2002 [Turn over International General Certificate of Secondary Education UNIVERSITY OF CAMBRIDGE LOCAL EXAMINATIONS SYNDICATE MATHEMATICS 0580/4, 0581/4 PAPER 4 OCTOBER/NOVEMBER SESSION 2002 2 hours 30 minutes Additional materials: Answer paper Electronic calculator Geometrical instruments Graph paper (1 sheet) Mathematical tables (optional) Tracing paper (optional) TIME 2 hours 30 minutes INSTRUCTIONS TO CANDIDATES Write your name, Centre number and candidate number in the spaces provided on the answer paper/ answer booklet. Answer all questions. Write your answers on the separate answer paper provided. All working must be clearly shown. It should be done on the same sheet as the rest of the answer. Marks will be given for working which shows that you know how to solve the problem even if you get the answer wrong. If you use more than one sheet of paper, fasten the sheets together. INFORMATION FOR CANDIDATES The number of marks is given in brackets [ ] at the end of each question or part question. The total of the marks for this paper is 130. Electronic calculators should be used. If the degree of accuracy is not specified in the question, and if the answer is not exact, the answer should be given to three significant figures. Answers in degrees should be given to one decimal place. For π, use either your calculator value or 3.142. www.XtremePapers.com

2 0580/4,0581/4/O/N02 1 (a) At an athletics meeting, Ben’s time for the 10000 metres race was 33 minutes exactly and he finished at 15 17. (i) At what time did the race start? [1] (ii) What was Ben’s average speed for the race? Give your answer in kilometres per hour. [2] (iii) The winner finished 51.2 seconds ahead of Ben. How long did the winner take to run the 10000 metres? [1] (b) The winning distance in the javelin competition was 80 metres. Otto’s throw was 95% of the winning distance. Calculate the distance of Otto’s throw. [2] (c) Pamela won the long jump competition with a jump of 6.16 metres. This was 10% further than Mona’s jump. How far did Mona jump? [2] 2 The diagram shows a sketch of the net of a solid tetrahedron (triangular prism). The right-angled triangle ABC is its base. AC = 8 cm, BC = 6cm and AB = 10cm. FC = CE = 5cm. (a) (i) Show that BE = √61cm. [1] (ii) Write down the length of DB. [1] (iii) Explain why DA = √89cm. [2] (b) Calculate the size of angle DBA. [4] (c) Calculate the area of triangle DBA. [3] (d) Find the total surface area of the solid. [3] (e) Calculate the volume of the solid. [The volume of a tetrahedron is (area of the base) × perpendicular height.] [3] 1–3 D A E C 6cm NOT TO SCALE 5cm 5cm 8cm 10cm B F

3 0580/4,0581/4/O/N02 [Turn over 3 Answer the whole of this question on a sheet of graph paper. (a) Using a scale of 1cm to represent 1 unit on each axis, draw an x-axis for –6
x
10 and a y-axis for –8
y
8. Copy the word EXAM onto your grid so that it is exactly as it is in the diagram above. Mark the point P (6,6). [2] (b) Draw accurately the following transformations. (i) Reflect the letter E in the line x = 0. [2] (ii) Enlarge the letter X by scale factor 3 about centre P (6,6). [2] (iii) Rotate the letter A 90° anticlockwise about the origin. [2] (iv) Stretch the letter M vertically with scale factor 2 and x-axis invariant. [2] (c) (i) Mark and label the point Q so that PQ →= . [1] (ii) Calculate |PQ →| correct to two decimal places. [2] (iii) Mark and label the point S so that PS → . [1] (iv) Mark and label the point R so that PQRS is a parallelogram. [1] –4 –1 –3 2 P(6,6) 0 2 4 6 8 10 -2 -4 -6 2 4 6 8 x y

4 0580/4,0581/4/O/N02 4 A wheel is divided into 10 sectors numbered 1 to 10 as shown in the diagram. The sectors 1, 2, 3 and 4 are shaded. The wheel is spun and when it stops the fixed arrow points to one of the sectors. (Each sector is equally likely.) (a) The wheel is spun once so that one sector is selected. Find the probability that (i) the number in the sector is even, [1] (ii) the sector is shaded, [1] (iii) the number is even or the sector is shaded, [1] (iv) the number is odd and the sector is shaded. [1] (b) The wheel is spun twice so that each time a sector is selected. Find the probability that (i) both sectors are shaded, [2] (ii) one sector is shaded and one is not, [2] (iii) the sum of the numbers in the two sectors is greater than 20, [2] (iv) the sum of the numbers in the two sectors is less than 4, [2] (v) the product of the numbers in the two sectors is a square number. [3] 1 6 2 5 3 4 7 10 8 9

5 0580/4,0581/4/O/N02 [Turn over 5 Answer the whole of this question on a sheet of graph paper. (a) The table gives values of f(x) = 24 + x2 for 0.8
x
6. x2 Calculate, correct to 1 decimal place, the values of l, m and n. [3] (b) Using a scale of 2cm to represent 1 unit on the x-axis and 2cm to represent 5 units on the y-axis, draw an x-axis for 0
x
6 and a y-axis for 0
y
40. Draw the graph of y = f(x) for 0.8
x
6. [6] (c) Draw the tangent to your graph at x = 1.5 and use it to calculate an estimate of the gradient of the curve at this point. [4] (d) (i) Draw a straight line joining the points (0, 20) and (6, 32). [1] (ii) Write down the equation of this line in the form y = mx + c. [2] (iii) Use your graph to write down the x-values of the points of intersection of this line and the curve y = f(x). [2] (iv) Draw the tangent to the curve which has the same gradient as your line in part d(i). [1] (v) Write down the equation for the tangent in part d(iv). [2] 6 (a) On 1st January 2000, Ashraf was x years old. Bukki was 5 years older than Ashraf and Claude was twice as old as Ashraf. (i) Write down in terms of x, the ages of Bukki and Claude on 1st January 2000. [2] (ii) Write down in terms of x, the ages of Ashraf, Bukki and Claude on 1st January 2002. [1] (iii) The product of Claude’s age and Ashraf’s age on 1st January 2002 is the same as the square of Bukki’s age on 1st January 2000. Write down an equation in x and show that it simplifies to x2 – 4x – 21 = 0. [4] (iv) Solve the equation x2 – 4x – 21 = 0. [2] (v) How old was Claude on 1st January 2002? [1] (b) Claude’s height, h metres, is one of the solutions of h2 + 8h – 17 = 0. (i) Solve the equation h2 + 8h – 17 = 0. Show all your working and give your answers correct to 2 decimal places. [4] (ii) Write down Claude’s height, to the nearest centimetre. [1] x f(x) 0.8 38.1 25 12.9 10 10.1 11.7 l m n 26 31 36.7 1 1.5 2 2.5 3 3.5 4 4.5 5 5.5 6

6 0580/4,0581/4/O/N02 7 (a) A group of students sat an examination. Each student got one of the grades A, B, C or D. The pie chart shows these results. 36 students got grade A, shown by an angle of 108°. (i) Calculate the total number of students who sat the examination. [2] (ii) How many students did not get grade A? [1] (iii) The ratio of the number of students getting grades B, C or D is 4 : 5 : 3. Find the number of students getting each grade. [3] (iv) Work out the angles in the pie chart for grades B, C and D. [3] (v) Find the ratio, in its lowest terms, the number of students with grade A : the number of students with grade B. [1] (b) A group of children were asked how much money they had saved. The histogram and table show the results. Use the histogram to calculate the values of p, q and r. [4] 0 10 Money saved in dollars (m) Frequency Density 20 30 40 50 60 70 80 m D A 108° NOT TO SCALE B C Money saved ($m) 0 < m
20 25 20 < m
30 p 30 < m
40 q 40 < m
70 r Frequency

7 0580/4,0581/4/O/N02 8 Sarah investigates cylindrical plant pots. The standard pot has base radius r cm and height h cm. Pot A has radius 3r and height h. Pot B has radius r and height 3h. Pot C has radius 3r and height 3h. (a) (i) Write down the volumes of pots A, B and C in terms of π , r and h. [3] (ii) Find in its lowest terms the ratio of the volumes of A : B : C. [2] (iii) Which one of the pots A, B or C is mathematically similar to the standard pot? Explain your answer. [2] (iv) The surface area of the standard pot is Scm2. Write down in terms of S the surface area of the similar pot. [2] (b) Sarah buys a cylindrical plant pot with radius 15cm and height 20cm. She wants to paint its outside surface (base and curved surface area). (i) Calculate the area she wants to paint. [2] (ii) Sarah buys a tin of paint which will cover 30m2. How many plant pots of this size could be painted on their outside surfaces completely using this tin of paint? [4] 9 (a) Write down the 10th term and the nth term of the following sequences. (i) 1, 2, 3, 4, 5 …, …, [1] (ii) 7, 8, 9, 10, 11 …, …, [1] (iii) 8, 10, 12, 14, 16 …, … . [3] (b) Consider the sequence 1(8 – 7), 2(10 – 8), 3(12 – 9), 4(14 – 10), …………, ………… . (i) Write down the next term and the 10th term of this sequence in the form a(b – c) where a, b and c are integers. [3] (ii) Write down the nth term in the form a(b – c) and then simplify your answer. [2] STANDARD NOT TO SCALE r 3r r 3h 3h 3r h h A B C

CAMBRIDGE INTERNATIONAL EXAMINATIONS NOVEMBER 2002 INTERNATIONAL GCSE ae eee cee ie en ce UNIVERSITY of CAMBRIDGE Local Examinations Syndicate

Page 1 Mark Scheme Syllabus Paper IGCSE Examinations — November 2002 0580; 0581 4 1(a)(i) 1444 Bl (0) 2002 Dar <the:) ov Pigs: 12, Mi 18.2(kav/h) wun} Al | Accept 18,18.,, 18%. Units are, www2 (iii) (Mark Fina Aes) 32 min 8.8 sec Bl, ‘y Rece¢t 32.1 iin o 1428-Boe UNITS ESSENTIAL % ee 1430 sec (b) 80 x 0.95 M1 32 -mbenin, 76 Al www2 iC) (©) Division by 110 ee tl. M1 5.60. or S-6 Alp] www2 Aeeeeh Seog 2(a)(i) +35° seen 1 (ii) V61 oe. Bl | Accegr 7-81 ov 1-8 ii) 84S seen Bl DA=AF o.e. Pha Indep 4) . Scare Denuwg => MO (b) 89=100+61-2.10V6lcosB oe | M1 |(Jieir wi) = tooo. 62° b3 => MO cos B= 100+ 61 — 89 M1 | Implies first M1 2.10.V61 = ied " 62° t263° aclusive. =0.46.,... Al lempli ea he) Soria Sate gras. ZB = 62.5° to 62.6° Al, .|Implies previous Al www4 iC) (2) 4.10. V61. sin 62.6° M2 |Oralternative complete method V\ their 2B and /61 34.6 - 34.7 Al @ www3 (4) Two of 24 cm?, 15 cm? , 20 cm? Ml Adds 4 A areas together (theirs) M1 independauk ee 93.6 - 93.7 0) & SKK S.0- + (above) 40 Al ty J* (59 + their (c) ) www3 MI MI defpendsy on first MI Al (3) SSS Saas

Page 2 Mark Scheme Syllabus. Paper IGCSE Examinations — November 2002 0580; 0581 4 3(a) Scales correct Minimum — &<x < 10 and -O<y<8 Generous accuracy. Allow 2mm Heroughoot. EXAM correct we (b)(H (The) E reflected in y-axis Allow Sel for correct reflection in x-axis (-4,2),C2,2),¢2,4).644 Allow Sel for correct sized X , wrong place OF coreck dea Damm ovk (Sem) ka Gi) (th) X correctly enlarged - 0,0), ,0),@,-6),(6,-6) Allow Sel for rotation 90° clockwise iii) (Their) A ectly rotated 90° anticlockwi: eae (iii) (Their) A correctly ro anticlockwise Allow Sei for rotation 90” clockwise G2,6),C4,7),C2,8) Allow Sel for correct sized M, wrong position ce (iv) (Ther) M correctly stretched with S.F.2 buk comech onitubabion (8, 4), (8; 8), (9,6), (10,8) , (10,4) ©@ — (Qas,8) Points, iE labeled, meas have carceak label Gi) o+4 3.61 C.a.0, ww2 Wrong accuracy AO (iii) (Sat (2, 5) (iv) (Rat (-1,7) ee eee = — 4(a)(i) 0.5 of Sow 0.€. Probabilities should be fractions, decimals or (ii) 0.4 ot Woot 2- o.e. | Bl | percentages. Mark i.s.w. all parts for wrong quacelliag. (iii) 0.7 o.e. | Bl | Disallow first answer of 5 in 10 or 5 out of 10 (iv) ¥e0.2 0.€. Bl Ry type. No credit for 5 : 10 type. (by) 0.4%04 — (or[acii)]) M1 tw 0.16 (as) oe. | A) wow (2 (i) 04x06 soi. (%s) M1 | Accept (their 0.4) x (1 — their 0.4) 0.48 (3) (C.ac)Jo.e. Al, a) www2 (iii) Navgh os Noting of 0 or zero or ail. B2_| Allow Sel for “impossible” or O/k for k# 0 e of None or No probability Cee ae , 1) and (1, 2) and (2, 1) only MI |1@ ack seen , alley GD Ev Hoe 0.03 oe. | Al 6 www2 (v)" Conedk Ydea oP prpdocr being square shou Answer in Tage \%aq 4° Le Trelosive MI Jeg 32), WUES).. a7 (Ue) 28)--- or prob. diag. with 25, 36-. the = MBI] Nok possible aPrer ugneng method seen. 0.18 o.e.| Al@} www3 —— SSS ES

Page 3 Mark Scheme Syllabus Paper | IGCSE Examinations — November 2002 0580; 0581 4 o:8 i ns 2 25 3 3g a es 5 SS 6 36.7 BEL 25 12-9 10 pod WT S(a) Bl () (b) Sl ee 12 points correctly plotted pas (J their 7, m ;n) Reasonable correct}curve thro’ 11 points | Cl © (c) Tangent ruled at x = 1.5 MI Uses vert /horiz: and cortechscales (2)! M1 Correct numerical value 7—-~ IS Al Negative answer Bl ie (ai) Line ruled from (0 , 20) to (6, 32) | BL\ (i) yur +20 B2 (1) = LoS4ol.1 inclusive Bl Cigneee%eries ranges intersedin) | BI I Wed 1nS By 26 Bt v vy v - Accuracy for graph is < 2mm Values musk be staked, bul maximum of | mark losk Fae wrong acqurncs. O0<x< 6 and 0<y<40 minimum, Condene reverted owes. Allow P3 for 10 or 11 correct P2 for 8 or 9 correct Pi for 6 or 7 correct /* Daylight rule. Must go from 1 <x <6 Not for chord (daylight) MOM1 possible on hard case MO - Depertenr on M2 (Implios 203 HIF not Seen) Dap. Their line having -¥e gradient . (red) Cakes) Allow B1 for either m =2 or c= 20 or 22420 (no y=) QE greditar. nok eanceited tor Allow Sci if both correct but given as (5.5, 4)and(11, 4) Parallel by eye [:FAMt) corre Hen aby %52'S and wots xsl Ipatwese yoiS a ye20 @® (vy) Gradient ~ 2 vA their d(i) line wrong er same gad ao af) xR y =m + their correct c W\ their y- intercept for this line = — — — fa ares Bi | Allow onsineli Ged Tiaal answers 2x Bl ex (i) xt+2 ,x+7 , x+2 Bly, ¥* (their a(i) + 2) (ii) (e+ 2)(2x 42) =(x+ 5)? M2V) Ifnot scored, allow M1 for either expression seen GAi2 their expressions pewided al Bin avale forms, 00, bo) 2x2+ 6x + 4 or x? + 10x +25 s.oi | 81 No errors to x2 - 4x -21=0 Ely Eerabtiched conedhly , including =O. (iv) (x-7)(x +3) seen M1 | orx=(44V100)/2 Both x= 7 andx=-3 Al www2 (v) 16 years old ¢.a.o,| BL G (OY) h= =8covk B1 | Anykbutall=2, + may jokin + 2 5 82-4.1.(-17) or 132 ‘ Bl Bl Bl KR (ii) Final Ans 1.74(m) e+ Teom BYg to neoresk Cwm . dep. Allow Sel for both correct, wrong accuracy, tresceFed oF (1.7445626 , —9.7445620) er |v Sad ¥en — Must be 2 d.p. V* his positive reasonable h nm mebes or C.eesh$2.s0) is

Tayi) xe (i) apie (iil) Grade B= 28 stents V their 2h. Page 4 Mark Scheme Syllabus Paper IGCSE Examinations — November 2002 0580; 0581 4 108 : 360=36:7 120 students Al | www2 Bly \ (their 7 ) — 36 correct If 0 scored, allow Scl for (their 84) + (their 4 +5 +3) Grade C = 35 students / B1V) soi. gy Sel Grr 120 inte WO, $0, 30. i Grade D = 21 students /* Bly (iv) Angle B = 84° B1 | If0 scored, allow Sel for (360( 108) (their 4 +5 +3) Angle C = 105° Bl 8.0.1. GE Uses mated | perm penn S3° Angle D = 63° Bly ED Wer Bd eoeee? we (vy) 9:7 on 1% of B:1 Bly, * 36 : their B in lowest terms () p=20, q=10, r=15 If not scored, allow either B3 for 2 correct 8(a)(i) A = 97h 0.e. ee (ii) (iii) (iv) )@ qi) ay (ii) Gi) (be). ie wee (ii). Fiqs 3 + their 284 or B2 for 1 correct or Scl when T?US al er leteSpogh B=3ar7h oe Marking FINAL answers C=21nr*h 0.e. 2 reduad tO 9:3:27 J their (a)(i) provides att KEK Ayer. moa Germ: 3:1:9 C.0.0, www2 aes QQ Pot C M1 Because 3r: r=3h:h o.e.| Al Q 9S (cm?) Ww... | B2 | Allow Scl for KS where kis their S.F. @) 4st omarks m.15? + 2.1.15.20 Answer rounds to 2590 cm? Al,.| www2 0.259m? or 300 000 cm? Can ger MOM } Allow Al for 115.7.. or 115.8.. ... or 116 wwwd or3 Pecepr unsimpli Red algebraic wax pressions 115 pots 10: and n Mark =firal ausuers, Conde Consizhant alhuwahive 16 and n+6 Letter, 26 Answer.contains 27” 2n'+6 5(16 —11) 10(26 - 16) B2v‘| J their (a) 10,16,26 nl 2n+6 -(nt+6] B1V‘|V their (a)(i)[(lii) — ({i)] provided Hey inveloe A 2 n Nek Alm) or ann ee