Cambridge IGCSE Mathematics 0580 — 2021 Oct/Nov Paper 2 · Variant 3

0580/23/O/N/21 · 26 questions · 70 marks · ≈79 min

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Cambridge IGCSE Mathematics 0580 2021 Oct/Nov Paper 2 · Variant 3 question paper, page 1 of 12
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Mark scheme6 pages

Answers below. Sit the paper first if you are practising.

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Questions as text

Q1 · Write 26 g as a percentage of 208 g

1 Write 26 g as a percentage of 208 g. ............................................. % [1]

Mark scheme: Question Answer Marks Partial Marks 1 12.5 1

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Q2 · X° NOT TO SCALE 132° The diagram shows two parallel lines intersecting a straight line

2 x° NOT TO SCALE 132° The diagram shows two parallel lines intersecting a straight line. Find the value of x. x = ................................................ [2]

Mark scheme: 2 48 2 B1 for 132 or 48 in the correct position on the diagram or M1 for 180 – 132

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Q3 · 11 13 15 17 19 From this list, write down the number that is both a prime number and a…

3 11 13 15 17 19 From this list, write down the number that is both a prime number and a factor of 195. ................................................. [1]

Mark scheme: 3 13 1

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Question 4

4 (a) = ! 2 1 Put a ring around each of the symbols that make this statement correct. 0.5 .................... 5% [1] (b) Insert one pair of brackets to make this statement correct. 7 - 3 - 1 + 2 = 7 [1]

Mark scheme: 4(a) ≠and > indicated 1 4(b) 7 – (3 – 1) + 2 = 7 cao 1

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Q5 · Nina changes 153 euros into dollars when the exchange rate is $1 = 0.9 euros

5 Nina changes 153 euros into dollars when the exchange rate is $1 = 0.9 euros. Calculate the amount Nina receives. $ ................................................ [1]

Mark scheme: 5 170 1

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Q6 · Marek buys a computer for $420

6 Marek buys a computer for $420. He sells it at a loss of 15%. Calculate the selling price of this computer. $ ................................................ [2]

Mark scheme: 6 357 2  15  M1 for  1 −  × 420 oe  100  or B1 for 63

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Question 7

7 Simplify. 32g 32 ' 4 g 4 ................................................. [2]

Mark scheme: 7 8g 28 final answer 2 B1 for kg 28 or 8 g k as final answer or correct answer seen and spoilt

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Q8 · Beatrice walks 1 km at a speed of 4 km/h and then 2 km at a speed of 4.5 km/h

8 Beatrice walks 1 km at a speed of 4 km/h and then 2 km at a speed of 4.5 km/h. Work out Beatrice’s average speed for the whole journey. ........................................ km/h [3]

Mark scheme: 8 4.32 3 1 2 B1 for oe or oe seen 4 4.5 1 + 2 M1 dep on B1 for oe their 14 + their 4.52

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Q9 · Write the recurring decimal .027o o as a fraction

9 Write the recurring decimal .027o o as a fraction. ................................................. [1]

Mark scheme: 9 3 1 oe fraction 11

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Q10 · These are the first four terms of a sequence

10 These are the first four terms of a sequence. 3 -1 -5 -9 (a) Find the next term in this sequence. ................................................. [1] (b) Find the nth term. ................................................. [2]

Mark scheme: 10(a) –13 1 10(b) –4n + 7 oe final answer 2 B1 for – 4n + k or jn + 7 (j ≠ 0) or for a correct answer spoilt

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Q11 · P = M ( g 2 + h 2 ) (a) Find the value of P when M = 100, g = 3 and h = 4.5

11 P = M ( g 2 + h 2 ) (a) Find the value of P when M = 100, g = 3 and h = 4.5 . P = ................................................ [2] (b) Rearrange the formula to write g in terms of P, M and h. g = ................................................ [3]

Mark scheme: 11(a) 2925 2 M1 for 100(32 + 4.52) or B1 for 29.25 seen 11(b) P 2 3 M1 for correct division by M [±] − h M1 for correct re-arrangement to isolate g M or g2 P − Mh 2 M1 for correct square root of two term or [±] final answer M expression Max 2 marks for an incorrect answer

More questions on Algebraic manipulation

Q12 · 312 Without using a calculator, work out +

11 312 Without using a calculator, work out + . 12 4 You must show all your working and give your answer as a mixed number in its simplest form. ................................................. [3]

Mark scheme: 12 11 9 M1 Allow any correct common denominator + oe 12k 12 12 2 A2 20 13 cao A1 for 12 or equivalent improper fraction or mixed number

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Q13 · Calculate 0.04 2 + 0.03 # 0.28

13 Calculate 0.04 2 + 0.03 # 0.28 . Give your answer in standard form. ................................................. [2]

Mark scheme: 13 1[.0] × 10–2 cao 2 B1 for 0.01 oe

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Q14 · P Q b e d c f a g (a) Complete the statement

14 P Q b e d c f a g (a) Complete the statement. P , Q = { ................................................................................ } [1] (b) Find n(Q). ................................................. [1] (c) Find n ( P l + Q ) . ................................................. [1]

Mark scheme: 14(a) b, c, d, e, f, g 1 14(b) 4 1 14(c) 3 1

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Q15 · The cost of a train journey is increased by 6% to a new cost of $153.70

15 The cost of a train journey is increased by 6% to a new cost of $153.70 . Calculate the original cost of the train journey. $ ................................................ [2]

Mark scheme: 15 145 2 6  M1 for x 1 +  = 153.7 oe or better  100 

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Q16 · Jo and Mo share $26

16 Jo and Mo share $26. Jo receives $5 more than Mo. Find the ratio Jo’s money : Mo’s money. Give your answer in its simplest form. ........................ : ...................... [3]

Mark scheme: 16 31 : 21 3 B2 for equivalents e.g. 15.5 oe and 10.5 oe or for an equivalent ratio e.g. 3.1 : 2.1 or M1 for e.g. x + 5 + x = 26 oe or x – 5 + x = 26 oe

More questions on Ratio and proportion

Q17 · Each interior angle of a regular polygon is 178.5°

17 Each interior angle of a regular polygon is 178.5°. Calculate the number of sides of this polygon. ................................................. [2]

Mark scheme: 17 240 2 M1 for 360 ÷ (180 – 178.5) oe 180( n − 2) or for = 178.5 oe n

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Q18 · Find the equation of the straight line that passes through the points (2, -2) and (3, 10)

18 Find the equation of the straight line that passes through the points (2, -2) and (3, 10). Give your answer in the form y = mx + c . y = ................................................ [3]

Mark scheme: 18 [y =] 12x – 26 final answer 3 10 −−2 M1 for oe 3 − 2 M1 for correct substitution of (2, –2) or (3, 10) into y = (their m)x + c oe

More questions on Equations of linear graphs

Q19 · 12.6 cm NOT TO SCALE 80° O The diagram shows a sector of a circle, centre O, radius 12.6…

19 12.6 cm NOT TO SCALE 80° O The diagram shows a sector of a circle, centre O, radius 12.6 cm. Calculate the perimeter of the shaded segment. ............................................ cm [4]

Mark scheme: 19 33.8 or 33.78 to 33.80 4 M2 for 2 × 12.6 × sin 40 oe ( ... ) or M1 for sin 40 = oe 12.6 80 M1 for × 2 × π × 12.6 oe 360

More questions on Circles, arcs and sectors

Q20 · A lake has an area of 3 km2

20 A lake has an area of 3 km2. On a map the area of the lake is 18.75 cm2. Find the scale of the map in the form 1 : n. 1 : ................................................ [3]

Mark scheme: 20 40 000 3 B2 for 1 cm to 0.4 km or 2.5 cm to 1 km or 1 600 000 000 3 × 10 k or M2 for oe where k > 5 18.75 or M1 for 1 cm2 to 0.16 km2 or 6.25 cm2 to 1 km2 or for 3 × 1010 oe or 1.875 × 10–9 oe or 3 × 106 oe and 1.875 × 10–3 oe

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Question 21

21 Simplify fully. 3 243y 10 5 ` j ................................................. [2]

Mark scheme: 21 27y6 final answer 2 B1 for ky6 or 27yk as final answer or correct answer seen and spoilt

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Q22 · Solve the simultaneous equations

22 Solve the simultaneous equations. You must show all your working. y = x 2 - 3x - 13 y = x - 1 x = .................... , y = .................... x = .................... , y = .................... [5]

Mark scheme: 22 x2 – 4x – 12 [= 0] M2 M1 for x2 – 3x – 13 = x – 1 or or for y = (y + 1)2 – 3(y + 1) – 13 y2 – 2y – 15 [= 0] (x – 6)(x + 2) [= 0] M1 or for correct factors for their quadratic or equation (y – 5)(y + 3) [= 0] or for correct use of quadratic formula or completing the square for their equation [x =] 6, [y =] 5 B2 B1 for one correct pair or two correct [x =] –2, [y =] –3 x values or two correct y values If B0 scored and at least 2 method marks scored SC1 for correct substitution of both of their x values or their y values into y = x2 – 3x – 13 or y = x – 1

More questions on Equations

Q23 · D C 4 cm Q P 5 cm NOT TO SCALE A B 12 cm The diagram shows a triangular prism

23 D C 4 cm Q P 5 cm NOT TO SCALE A B 12 cm The diagram shows a triangular prism. Angle BPC = 90°. (a) Calculate AC. AC = ........................................... cm [3] (b) Calculate the angle between AC and the base ABPQ. ................................................. [3]

Mark scheme: 23(a) 13.6 or 13.60… 3 M2 for 12 2 + 5 2 + 4 2 or M1 for 5 2 + 4 2 or 12 2 + 4 2 or 12 2 + 5 2 23(b) 17.1 or 17.08 to 17.10… 3 4 M2 for sin = oe or their (a) 4 their AP tan = or cos = their AP their (a) or M1 for recognising angle CAP.

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Q24 · Tanx = 3 and 0° G x G 360°

24 tanx = 3 and 0° G x G 360° . Find all the possible values of x. ................................................. [2]

Mark scheme: 24 60 2 B1 for 60 or 240 and 240 If 0 scored SC1 for two answers with a difference of 180°

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Question 25

25 Simplify. 3x 2 - 18x ax - 6a + 2cx - 12c ................................................. [4]

Mark scheme: 25 3 x 4 B1 for 3x(x – 6) final answer B2 for ( x − 6)( a + 2c ) a + 2c or B1 for a ( x − 6) + 2c ( x − 6) or x ( a + 2c ) − 6( a + 2 c )

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Q26 · T NOT TO t X SCALE O R r ORT is a triangle

26 T NOT TO t X SCALE O R r ORT is a triangle. X is a point on TR so that TX : XR = 3 : 2. O is the origin, OR = r and OT = t . Find the position vector of X. Give your answer in terms of r and t in its simplest form. ................................................. [3]

Mark scheme: 26 3 2 1 3 2 3 r + t or (3r + 2t) M2 for r + (–r + t) oe or t + (r – t) 5 5 5 5 5 oe or  M1 for RT = –r + t oe or TR = r − t     M1 for OR + RX or OT + TX any other correct route.

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What was in this paper

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Cambridge’s own grade thresholds for 2021 Oct/Nov, Paper 2 · Variant 3. A higher threshold means an easier paper — the bar moves with how the cohort did.

A46/70
B36/70
C26/70
D18/70
E11/70