Cambridge IGCSE Mathematics 0580 — 2015 Oct/Nov Paper 2 · Variant 1

0580/21/O/N/15 · 18 questions · 70 marks · ≈79 min

The question paper and its mark scheme, free to read here and free to download. This is Cambridge’s own paper, exactly as it was sat.

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Question paper12 pages

Cambridge IGCSE Mathematics 0580 2015 Oct/Nov Paper 2 · Variant 1 question paper, page 1 of 12
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Mark scheme5 pages

Answers below. Sit the paper first if you are practising.

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Questions as text

Q1 · At midnight the temperature in Newtown was –8 °C

1 At midnight the temperature in Newtown was –8 °C. At noon the next day the temperature in Newtown was 9 °C. Work out the rise in temperature from midnight to noon. Answer ........................................... °C [1] __________________________________________________________________________________________

Mark scheme: Question Answer Mark Part Marks 1 [+]17 1

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Q2 · A B In the Venn diagram shade the region A B'

2 A B In the Venn diagram shade the region A B'. [1] __________________________________________________________________________________________

Mark scheme: 2 1

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Q3 · Y 4 3 2 A 1 x –4 –3 –2 –1 0 1 2 3 4 5 –1 –2 –3 2 Draw the image of shape A after a…

3 y 4 3 2 A 1 x –4 –3 –2 –1 0 1 2 3 4 5 –1 –2 –3 2 Draw the image of shape A after a translation by the vector [2] e - 3 o.__________________________________________________________________________________________

Mark scheme: 3 Triangle (3, –2), (4, –2), 2 B1 for movement 2 right or 3 down (4, –1) 785 [ ]

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Q4 · Pip and Ali share $785 in the ratio Pip : Ali = 4 : 1

4 Pip and Ali share $785 in the ratio Pip : Ali = 4 : 1. Work out Pip’s share. Answer $ ................................................ [2] __________________________________________________________________________________________

Mark scheme: 785 4 628 2 M1 for [× 4 ] 1 + 4

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Q5 · Jim scores the following marks in 8 tests

5 Jim scores the following marks in 8 tests. 7 8 8 y 6 9 10 5 His mean mark is 7.5 . Calculate the value of y. Answer y = ................................................ [2] __________________________________________________________________________________________

Mark scheme: 5 7 nfww 2 M1 for 5.7 × 8 or for ( 7 + 8 + 8 + y + 6 + 9 + 10 + 5) ÷ 8 = 5.7 or better oe 4 × 30

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Q6 · 9 # 29.36 By writing each number correct to 1 significant figure, estimate the value of

3.9 # 29.36 By writing each number correct to 1 significant figure, estimate the value of . 8.9 - 2.7 Show all your working. Answer ................................................ [2] __________________________________________________________________________________________

Mark scheme: 4 × 30 6 M1 Allow one error and 2 for 4 and 6 for 9 – 3 9 − 3 10 nfww A1

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Q7 · Work out the highest common factor (HCF) of 36 and 90

7 Work out the highest common factor (HCF) of 36 and 90. Answer ................................................ [2] __________________________________________________________________________________________

Mark scheme: 7 18 2 M1 for 36 = 2 × 2 × 3 × 3 soi or 90 = 2 × 3 × 3 × 5 soi or listing the correct factors of 36 and 90 showing a minimum of 2, 3, 6, 9 and 18

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Q8 · P 11 cm NOT TO SCALE 37° A O In the diagram, AP is a tangent to the circle at P

8 P 11 cm NOT TO SCALE 37° A O In the diagram, AP is a tangent to the circle at P. O is the centre of the circle, angle PAO = 37° and AP = 11 cm. (a) Write down the size of angle OPA. Answer(a) Angle OPA = ................................................ [1] (b) Work out the radius of the circle. Answer(b) .......................................... cm [2] __________________________________________________________________________________________

Mark scheme: 8 (a) 90 1 OP o (b) 8.29 or 8.289… to 8.29 2 M1 for = tan 37 oe 11

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Question 9

9 Factorise completely. (a) ax + ay + 3cx + 3cy Answer(a) ................................................ [2] (b) 3a2 – 12b2 Answer(b) ................................................ [3] __________________________________________________________________________________________

Mark scheme: 9 (a) ( a + 3c )( x + y ) final answer 2 B1 for a ( x + y ) + 3c ( x + y ) or x ( a + 3c ) + y ( a + 3c ) (b) (3 a − 2b )( a + 2b ) final answer 3 B2 for (3 a − 2b )( a + 2b ) seen and then spoiled or (3a − 6b )( a + 2b ) or ( a − 2b )(3a + 6b ) or ( a − 2b )( a + 2b ) or B1 for 3( a 2 − 4b 2 )

More questions on Algebraic manipulation

Q10 · Write the recurring decimal .015o as a fraction

10 Write the recurring decimal .015o as a fraction. [ .015o means 0.1555...] Answer ................................................ [2] __________________________________________________________________________________________

Mark scheme: 14 10 oe must be fraction 2 M1 for 155. − 5.1 oe 90 or k B1 for 90  2 

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Q11 · NOT TO SCALE 6.1 cm A protractor is a semi-circle of radius 6.1 cm

11 NOT TO SCALE 6.1 cm A protractor is a semi-circle of radius 6.1 cm. Calculate the perimeter of the protractor. Answer .......................................... cm [3] __________________________________________________________________________________________

Mark scheme:  2  11 31.4 or 31.36 to 31.37 3 M2 for × 1.6 × π + 2 × 1.6 oe  2  or B2 for 19.16 to 19.17 or 19.2 or M1 for 1.6 × π or for 12 2. × π 3

More questions on Circles, arcs and sectors

Q14 · A car travels at 56 km/h

14 A car travels at 56 km/h. Find the time it takes to travel 300 metres. Give your answer in seconds correct to the nearest second. Answer .............................................. s [4] __________________________________________________________________________________________

Mark scheme: 14 & &

More questions on Rates

Question 15

15 Simplify. 2 x - 16 x 2 - 3x - 4 Answer ................................................ [4] __________________________________________________________________________________________

Mark scheme: x + 4 15 final answer 4 B1 for ( x − 4)( x + 4) and x + 1 B2 for ( x − 4)( x + )1 or SC1 for ( x + a )( x + b ) where a + b = − 3 or ab = − 4

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Q16 · Hazel invests $1800 for 7 years at a rate of 1.5% per year compound interest

16 Hazel invests $1800 for 7 years at a rate of 1.5% per year compound interest. Calculate how much interest she will receive after the 7 years. Give your answer correct to the nearest dollar. Answer $ ................................................ [4] __________________________________________________________________________________________

Mark scheme: 16 198 4 B3 for 197.7…. or answer 198.00 or 7 5.1  M2 for 1800 × + 1  – 1800  100  or B2 for answer 1998 or 7 5.1  M1 for 1800 × + 1   100  If B0 then B1 for seeing their answer in decimal form correctly written to the nearest integer

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Q17 · Y 6 5 4 3 S 2 T 1 x 0 1 2 3 4 5 6 7 8 9 (a) Describe fully the single transformation that…

17 y 6 5 4 3 S 2 T 1 x 0 1 2 3 4 5 6 7 8 9 (a) Describe fully the single transformation that maps triangle S onto triangle T. Answer(a) ........................................................................................................................................... ............................................................................................................................................................. [3] (b) Find the matrix which represents the transformation that maps triangle S onto triangle T. Answer(b) [2] f p __________________________________________________________________________________________

Mark scheme: 17 (a) Enlargement 1 1 1 2 origin oe 1  12 0   k 0  (b) oe 2FT correct or FT their (a) allow for 2 marks      0 k  0 12   where k = their scale factor in (a)  k 0  B1 for one correct row or correct column or    0 k  ( k ≠ 0 or )1  − 9 − 5 

More questions on Transformations

Q19 · 25° 5 cm NOT TO SCALE 15 cm The diagram shows a wooden prism of height 5 cm

19 25° 5 cm NOT TO SCALE 15 cm The diagram shows a wooden prism of height 5 cm. The cross section of the prism is a sector of a circle with sector angle 25°. The radius of the sector is 15 cm. Calculate the total surface area of the prism. Answer ......................................... cm2 [5] __________________________________________________________________________________________

Mark scheme: 14 19 nfww 4 B3 19.3 or 19.28 to 19.29 or 300 × 60 2 M2 for oe 56 × 1000 or M1 for distance divided by speed 56× 1000 e.g. their 300 ÷ their 56 or 60 2 If B0 then B1 for seeing their answer in decimal form correctly written to the nearest integer x + 4

More questions on Area and perimeter

Q20 · The table shows the probability that a person has blue, brown or green eyes

20 The table shows the probability that a person has blue, brown or green eyes. Eye colour Blue Brown Green Probability 0.4 0.5 0.1 Use the table to work out the probability that two people, chosen at random, (a) have blue eyes, Answer(a) ................................................ [2] (b) have different coloured eyes. Answer(b) ................................................ [4] __________________________________________________________________________________________

Mark scheme: 20 (a) 0.16 oe 2 M1 for 4.0 × 4.0 If zero scored SC1 for fully correct evaluated method involving a without replacement method (b) 0.58 oe 4 M3 for 1 − ( 4.0 2 + 5.0 2 + 1.02 ) oe or M2 for 4.0 2 + 5.0 2 + 1.0 2 ALT method M3 for 4.0 × ( 5.0 + )1.0 + 5.0 × ( 4.0 + )1.0 + 1.0 × ( 4.0 + 5.0) oe or M2 for addition of any three of: 4.0 × ,5.0 4.0 × ,1.0 5.0 × ,4.0 0.5 × 0.1, 1.0 × 4.0 and 1.0 × 5.0 or M1 for addition of any two of: 4.0 × ,5.0 4.0 × ,1.0 5.0 × ,4.0 5.0 × ,1.0 1.0 × 4.0 and 1.0 × 5.0 If zero scored SC2 for fully correct evaluated method involving a without replacement method [ ]

More questions on Probability of combined events

Q21 · F(x) = x3 g(x) = 3x – 5 h(x) = 2x + 1 Work out (a) ff(2), Answer(a)…

21 f(x) = x3 g(x) = 3x – 5 h(x) = 2x + 1 Work out (a) ff(2), Answer(a) ................................................ [2] (b) gh(x) and simplify your answer, Answer(b) ................................................ [2] (c) h–1(x), the inverse of h(x). Answer(c) h–1(x) = ................................................ [2] __________________________________________________________________________________________

Mark scheme: 21 (a) 512 2 B1 for [f ( 2 ) = ]8 or M1 for (x 3) 3 or better (b) 6 x − 2 or 2(3 x − )1 final answer 2 B1 for (3 2 x + )1 − 5 or better (c) 1 M1 for correct first step ( x − )1 oe 2 2 y 1 eg y − 1 = 2 x or = x + 2 2 or x = 2 y + 1 or better

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What was in this paper

The subtopics covered by these 18 questions, and how many questions each got. Open one in a new tab to see every Cambridge question on it.

What you needed in this session

Cambridge’s own grade thresholds for 2015 Oct/Nov, Paper 2 · Variant 1. A higher threshold means an easier paper — the bar moves with how the cohort did.

A57/70
B46/70
C36/70
D29/70
E23/70