Cambridge A Level Mathematics 9709 — 2011 Oct/Nov Paper 2 · Variant 1
9709/21/O/N/11 · 8 questions · 50 marks · ≈56 min
The question paper and its mark scheme, free to read here and free to download. This is Cambridge’s own paper, exactly as it was sat.
Question paper4 pages




Mark scheme5 pages
Answers below. Sit the paper first if you are practising.





Questions as text
Q1 · Solve the inequality |4 - 5x| < 3
1 Solve the inequality |4 - 5x| < 3. [3]
Mark scheme: 1 EITHER State or imply non-modular inequality (4 – 5x)2 < 32, or corresponding equation or pair of linear equations M1 1 7 Obtain critical values and A1 5 5 1 7 State correct answer < x < A1 5 5 1 OR State one critical value, e.g. x = , by solving a linear equation (or inequality) 5 or from a graphical method or by inspection B1 State the other critical value correctly B1 1 7 State correct answer < x < B1 [3] 5 5
Q2 · 2 5 2 Show that dx ln 3
6 2 5 2 Show that dx ln 3. [5] 4x 1 = ä 2 +
Mark scheme: 2 Integrate and obtain term of the form kln(4x + 1) M1 1 State correct term ln( 4 x + )1 A1 2 Substitute limits correctly M1 Use law for the logarithm of a quotient or a power M1 Obtain given answer correctly A1 [5] 1 2
Q3 · Y 1 1 x O 4 p 2 p The diagram shows the part of the curve y 1 tan 2x for 0 Find the…
3 y 1 1 x O 4 p 2 p The diagram shows the part of the curve y 1 tan 2x for 0 Find the x-coordinates of the 2 2π. = ≤x ≤1 points on this part of the curve at which the gradient is 4. [5]
Mark scheme: 1 3 Obtain derivative of the form k sec2 2x, where k = 1 or k = M1 2 Obtain correct derivative sec2 2x A1 Use correct method for solving sec2 2x = 4 M1 1 Obtain answer x = π (or 0.524 radians) A1 6 1 Obtain answer x = π (or 1.05 radians) and no others in range A1 [5] 3
Q4 · Solve the equation 32x 10 0, giving your answers correct to 3 significant figures
4 Solve the equation 32x 10 0, giving your answers correct to 3 significant figures. [5] −7(3x) + =
Mark scheme: 4 Carry out recognizable solution method for quadratic in 3x M1 Obtain 3x = 5 and 3x = 2 A1 Use logarithmic method to solve an equation of the form 3x = k, where k > 0 M1 State answer 1.46 A1 State answer 0.631 A1 [5] 1
Q5 · The polynomial 4x3 ax2 9x 9, where a is a constant, is denoted by It is given that when…
5 The polynomial 4x3 ax2 9x 9, where a is a constant, is denoted by It is given that when is divided by + +the remainder+ is 10. p(x). p(x) (2x −1) (i) Find the value of a and hence verify that is a factor of [3] (x −3) p(x). (ii) When a has this value, solve the equation 0. [4] p(x) =
Mark scheme: 1 5 (i) Substitute x = and equate to 10 M1 2 Obtain answer a = –16 A1 Either show that f(3) = 0 or divide by (x – 3) obtaining a remainder of zero B1 [3] (ii) At any stage state that x = 3 is a solution B1 Attempt division by (x – 3) reaching a partial quotient of 4x2 + kx M1 Obtain quadratic factor 4x2 – 4x – 3 A1 3 1 Obtain solutions x = and x = – A1 2 2 S.C. M1A1√ if value of ‘a’ incorrect [4] GCE AS/A LEVEL – October/November 2011 9709 21 3 2
Q6 · Verify by calculation that the cubic equation x3 5x 0 −2x2 + −3 = has a root that lies…
6 (i) Verify by calculation that the cubic equation x3 5x 0 −2x2 + −3 = has a root that lies between x 0.7 and x 0.8. [2] = = (ii) Show that this root also satisfies an equation of the form ax2 3 x , + = x2 b + where the values of a and b are to be found. [2] (iii) With these values of a and b, use the iterative formula ax2n 3 + xn+1 = x2n b + to determine the root correct to 2 decimal places. Give the result of each iteration to 4 decimal places. [3]
Mark scheme: 6 (i) Consider sign of x3 – 2x2 + 5x – 3 at x = 0.7 and x = 0.8 M1 Complete the argument correctly with appropriate calculations A1 [2] (ii) Rearrange equation to given equation or vice versa B1 State a = 2 and b = 5 B1 [2] (iii) Use the iterative formula correctly at least once M1 Obtain final answer 0.74 A1 Show sufficient iterations to justify its accuracy to 2 d.p. or show there is a sign change in the interval (0.735, 0.745) B1 [3]
Q7 · The parametric equations of a curve are x e3t, y t2et 3
7 The parametric equations of a curve are x e3t, y t2et 3. = = + dy (i) Show that . [4] t(t + 2) dx = 3e2t (ii) Show that the tangent to the curve at the point is parallel to the x-axis. [2] (1, 3) (iii) Find the exact coordinates of the other point on the curve at which the tangent is parallel to the x-axis. [2]
Mark scheme: 7 (i) Use product rule to differentiate y M1 Obtain correct derivative in any form in t for y A1 dy dy dx Use = ÷ M1 dx dt dt Obtain given answer correctly A1 [4] (ii) State t = 0 M1 dy State that = 0 and make correct conclusion A1 [2] dx (iii) Substitute t = –2 into equation for x or y M1 Obtain (e–6, 4e–2 + 3) A1 [2]
Q8 · By first expanding show that cos(2x + x), cos 3x cos3x cos x
8 (i) By first expanding show that cos(2x + x), cos 3x cos3x cos x. ≡4 −3 [5] (ii) Hence show that 16π cos3x dx 12.5 ã 0 (2 −cos x) = [5]
Mark scheme: 8 (i) Make relevant use of the cos(A + B) formula M1* Make relevant use of the cos 2A and sin 2A formulae M1* Obtain a correct expression in terms of cos x and sin x A1 Use sin2 x = 1 – cos2 x to obtain an expression in terms of cos x M1(dep*) Obtain given answer correctly A1 [5] 1 1 (ii) Replace integrand by cos 3 x + cos x , or equivalent B1 2 2 1 1 Integrate, obtaining sin 3 x + sin x , or equivalent B1 + B1√ 6 2 Use limits correctly M1 Obtain given answer A1 [5]
What was in this paper
The subtopics covered by these 8 questions, and how many questions each got. Open one in a new tab to see every Cambridge question on it.
What you needed in this session
Cambridge’s own grade thresholds for 2011 Oct/Nov, Paper 2 · Variant 1. A higher threshold means an easier paper — the bar moves with how the cohort did.