Cambridge IGCSE Mathematics (US) 0444 — 2023 Oct/Nov Paper 2 · Variant 3
0444/23/O/N/23 · 22 questions · 70 marks · ≈79 min
The question paper and its mark scheme, free to read here and free to download. This is Cambridge’s own paper, exactly as it was sat.
Question paper12 pages












Mark scheme6 pages
Answers below. Sit the paper first if you are practising.






Questions as text
Q1 · Tara goes on a journey by train
1 Tara goes on a journey by train. The train leaves at 06 48. The journey takes 12 hours and 35 minutes. Find the time when Tara arrives. ................................................. [1]
Mark scheme: Question Answer Marks Partial Marks 1 19 23 or 7 23 pm 1
Q2 · 61 63 64 66 68 69 From this list, write down (a) a square number…
2 61 63 64 66 68 69 From this list, write down (a) a square number ................................................. [1] (b) a prime number. ................................................. [1]
Mark scheme: 2(a) 64 1 2(b) 61 1
Q3 · A builder charges a fixed amount of $40 plus $25 per hour
3 A builder charges a fixed amount of $40 plus $25 per hour. (a) Find the number of hours the builder works when the total charge is $165. ........................................ hours [1] (b) Write down a formula for the total charge, $C, when the builder works for h hours. C = ................................................ [1]
Mark scheme: 3(a) 5 1 3(b) C = 40 + 25h 1
Q4 · The table shows the homework marks of a group of students
4 The table shows the homework marks of a group of students. Homework mark 5 6 7 8 Frequency 1 3 1 5 Find (a) the range ................................................. [1] (b) the mode ................................................. [1] (c) the median ................................................. [1] (d) the mean. ................................................. [3]
Mark scheme: 4(a) 3 1 4(b) 8 1 4(c) 7.5 1 4(d) 7 3 M2 for (1× 5 + 3 × 6 + 1 × 7 + 5 × 8) ÷ ( 1+ 3 + 1 + 5) or M1 for 1 × 5 + 3 × 6 + 1 × 7 + 5 × 8
Q5 · Shubhu invests $750 in a savings account for 5 years
5 Shubhu invests $750 in a savings account for 5 years. The account pays simple interest at a rate of 2% per year. Work out the total interest she earns during the 5 years. $ ................................................ [2]
Mark scheme: 5 75 2 750 2 5 M1 for oe 100
Q6 · B NOT TO 112° SCALE 44° C M A The diagram shows triangle ABC
6 B NOT TO 112° SCALE 44° C M A The diagram shows triangle ABC. M is the midpoint of AC. Triangle ABC is rotated 180° about center M. The image and the original triangle together form a quadrilateral ABCD. (a) Write down the mathematical name of the quadrilateral ABCD. ................................................. [1] (b) Find angle BAD. Angle BAD = ................................................ [2]
Mark scheme: 6(a) Parallelogram 1 6(b) 68 2 M1 for 180 – 112 oe or for 180 − 112 − 44
Q7 · Work out 1 '
7 Work out 1 ' . 6 15 Give your answer as a mixed number in its simplest form.
Mark scheme: 7 1 3 11 15 2 cao M2 for 2 6 11 55k 22 k or oe with common denominator 30 k 30 k 11 or B1 for oe 6 11 15 or M1 for their 6 11
Q8 · Rama asks a group of students how they travel to school
8 Rama asks a group of students how they travel to school. The table shows the probability of how a student, chosen at random, travels to school. Bus Walk Car Other Probability 0.4 0.2 0.1 (a) Complete the table. [2] (b) There are 1000 students at the school. Find the expected number of students that walk to school. ................................................. [1]
Mark scheme: 8(a) 0.3 oe 2 M1 for 1 – (0.4 + 0.2 + 0.1) oe 8(b) 200 1
Q9 · Find the greatest common factor (GCF) of 48 and 80
9 Find the greatest common factor (GCF) of 48 and 80. ................................................. [2] 2
Mark scheme: 9 16 2 B1 for answer 2 or 4 or 8 or M1 for 2 × 2 × 2 × 2 oe as final answer or [48 =] 2 × 2 × 2 × 2 × 3 and [80 =] 2 × 2 × 2 × 2 × 5 or for 2 correct factor trees or tables
Q10 · P = 3 Find the positive value of y when P = 108 and w = 2
10 P = 3 Find the positive value of y when P = 108 and w = 2 . y = ................................................ [3]
Mark scheme: 10 9 3 2 3P 2 3 108 M2 for y = or y = or better 2 w 2 2 2 2 y 2 or M1 for 108 = or better 3
Q11 · AB = - 3 (a) Find 3AB
11 AB = - 3 (a) Find 3AB . [1] f p (b) Find AB , leaving your answer in radical form. AB = ................................................ [2]
Mark scheme: 11(a) 21 1 −9 11(b) 58 2 M1 for (7)2 + ( – 3)2 oe If 0 scored SC1 for 522 or 3 58
Q12 · A solid cube of side 20 cm is made of pine
12 A solid cube of side 20 cm is made of pine. The density of pine is 0.5 g/cm3. Work out the mass of the cube. Give your answer in kilograms. [Density = mass ' volume] ............................................. kg [3]
Mark scheme: 12 4 3 M1 for 203 × 0.5 M1 for ÷ 1000
Q13 · Oliver sent 40% more messages in June than in May
13 Oliver sent 40% more messages in June than in May. He sent 280 messages in June. Find how many more messages he sent in June than in May. ................................................. [3]
Mark scheme: 13 80 3 B2 for 200 or M2 for ( 280 140 ) 40 oe or better 40 or M1 for 1 + m = 280 oe 100
Q14 · The graph of y = 2x + 1 is drawn on the grid
14 The graph of y = 2x + 1 is drawn on the grid. y 5 4 3 2 1 -5 -4 -3 -2 -1 0 1 2 3 4 5 x -1 -2 -3 -4 By shading the unwanted regions of the grid, find and label the region R which satisfies these inequalities. y H 2x + 1 y H 1 4x + 3y 1 12 [4]
Mark scheme: 14 Correct region indicated 4 B1 for 4x + 3y = 12 dashed line B1 for y = 1 solid line B2 for region identified satisfying all 3 inequalities or B1 for region satisfying only 2 of these inequalities with 4x + 3y = 12 and y = 1 both drawn
Q15 · T = 3d - e Solve for d
15 T = 3d - e Solve for d. d = ................................................ [3]
Mark scheme: 15 T 2 + e 3 M1 for T 2 = 3d – e [d =] oe final answer M1 for isolating term in d 3 M1 for dividing by 3 Max 2 marks if answer incorrect
Q16 · A cylinder with height 20 cm has a curved surface area of 120r cm2
16 A cylinder with height 20 cm has a curved surface area of 120r cm2 . Work out the volume of the cylinder. Give your answer in terms of r. ......................................... cm3 [4]
Mark scheme: 16 180 4 B2 for r = 3 120 or M2 for oe 2 20 or M1 for 2 r × 20 = 120 or better M1 for (their r)2 × 20
Question 17
17 (a) Simplify. 2 64y 27 3 ` j ................................................. [2] (b) Simplify. x - 5 x 2 - 25 ................................................. [2]
Mark scheme: 17(a) 16y18 final answer 2 B1 for 16yk or ky18 as final answer or correct answer spoiled 17(b) 1 2 B1 for (x + 5)(x – 5) final answer x + 5
Q18 · F varies as the product of m and a
18 F varies as the product of m and a. Work out the percentage change in F when m is increased by 20% and a is decreased by 10%. ............................................. % [3]
Mark scheme: 18 8 3 20 10 M2 for 1 + 1 − [ma] oe 100 100 or M1 for F = kma or better or 20 10 1 + and 1 − seen 100 100
Q19 · 300 + k = 13 3 Find the value of k
19 (a) 300 + k = 13 3 Find the value of k. k = ................................................ [2] 2 (b) 7 + 3 = a + 2 b ` j Find the value of a and the value of b. a = ................................................ b = ................................................ [2]
Mark scheme: 19(a) 27 2 B1 for 10 3 seen 19(b) [a = ] 10 2 B1 for each [b = ] 21 or M1 for 7 + 21 + 21 + 3 or better
Q20 · The following probabilities are given for events A and B
20 The following probabilities are given for events A and B. P ( A ) = 0.2 P ( B ) = 0.1 P ( A and B) = 0.05 (a) Find P ( A or B ) . ................................................. [2] (b) Show that A and B are not independent. [1]
Mark scheme: 20(a) 0.25 2 M1 for 0.2 + 0.1 – 0.05 20(b) P(A) × P(B) = 0.02 P(A and B) oe 1
Q21 · 1 (a) Evaluate 64 5
621 (a) Evaluate 64 5. ................................................. [1] (b) Solve the equation 2 + 3 y = 7 . y = ................................................ [2]
Mark scheme: 21(a) 32 1 21(b) 125 2 M1 for 3 y = 7 − 2 or better
Q22 · F ( )x = 3 x - 4 (a) When the domain of f ( )x is {0, 5, 7}, find the range of f ( )x
22 f ( )x = 3 x - 4 (a) When the domain of f ( )x is {0, 5, 7}, find the range of f ( )x . ................................................. [2] (b) f ( x) f ( x) - f ( f ( x)) = ax 2 + bx + c Find the value of each of a, b, and c. a = ................................................ b = ................................................ c = ................................................ [4]
Mark scheme: 22(a) –4, 11, 17 2 B1 for 2 correct 22(b) a = 9 4 B2 for 9 x 2 − 12 x − 12 x + 16 or better b = -33 or B1 for three terms correct c = 32 B1 for 3(3x – 4) – 4 oe
What you needed in this session
Cambridge’s own grade thresholds for 2023 Oct/Nov, Paper 2 · Variant 3. A higher threshold means an easier paper — the bar moves with how the cohort did.