Cambridge IGCSE Mathematics - International 0607 — 2019 May/June Paper 2 · Variant 1
0607/21/M/J/19 · 14 questions · 40 marks · ≈45 min
The question paper and its mark scheme, free to read here and free to download. This is Cambridge’s own paper, exactly as it was sat.
Question paper8 pages
Mark scheme5 pages
Answers below. Sit the paper first if you are practising.
Questions as text
Question 1
1 Work out. (a) (0.3)2 .................................................... [1] 4 1 (b) - 9 6 .................................................... [2]
Mark scheme: Question Answer Marks Partial Marks 1(a) 0.09 1 1(b) 5 2 8 3 or equiv fraction M1 for or oe 18 18 18
Q2 · Divide 360 in the ratio 7 : 2
2 Divide 360 in the ratio 7 : 2. ......................... , ......................... [2]
Mark scheme: 2 280, 80 2 B1 for each or M1 for 360 ÷ (7 + 2) soi by 40
Q3 · A NOT TO 64° SCALE F 33° E 55° B C D ABC is a triangle
3 A NOT TO 64° SCALE F 33° E 55° B C D ABC is a triangle. FED and BCD are straight lines. Work out angle EDC. Angle EDC = .................................................... [2]
Mark scheme: 3 28 2 B1 for CED = 33 or ECD = 119 or ECB = 61 or BFD = 97
Question 4
4 Expand and simplify. 4(3x + y) - 3(x - 2y) .................................................... [2]
Mark scheme: 4 9x + 10y final answer 2 B1 for 12x + 4y – 3x + 6y or ax + 10y, a ≠ 0 or 9x + by, b ≠ 0
Q5 · Sacha drove 425 km from home at an average speed of 100 km/h
5 Sacha drove 425 km from home at an average speed of 100 km/h. (a) Calculate the time for the journey giving your answer in hours and minutes. ....................... h ................... min [2] (b) The return journey took 3 hours and 55 minutes. She started at 21 56. At what time did she arrive home? .................................................... [2]
Mark scheme: 5(a) 4 [h] 15 [min] 2 M1 for 425 ÷ 100 soi by 4.25 oe 5(b) [0]1 51 oe 2 B1 for 25 51
Q6 · Write down the integer solutions to this inequality
6 (a) Write down the integer solutions to this inequality. - 2 G 2x 1 8 .................................................... [2] (b) Solve 2 + 2x 2 5x + 14 . .................................................... [2]
Mark scheme: 6(a) –1, 0, 1, 2, 3 2 B1 for 5 correct and 1 extra or 3 or 4 correct with no errors or M1 for −1 - x < 4 6(b) x < –4 final answer 2 M1 for 2 – 14 > 5x – 2x oe If 0 scored, SC1 for x = – 4 or x > –4 or x ⩽ – 4 or x ⩾ –4
Q7 · Work out (5.2 # 1018) - (2.4 # 1017)
7 Work out (5.2 # 1018) - (2.4 # 1017). Give your answer in standard form. .................................................... [2]
Mark scheme: 7 4.96 × 1018 2 B1 for 52 × 1017 or 0.24 × 1018 or figs 496
Q8 · A map is drawn to a scale of 1 cm to 5 km
8 A map is drawn to a scale of 1 cm to 5 km. (a) On the map, the distance between two towns is 4.8 cm. Find the actual distance between the towns. ...............................................km [1] (b) An island has an area of 75 km2. Find the area of the island on the map. ..............................................cm2 [2]
Mark scheme: 8(a) 24 1 8(b) 3 2 B1 for 52 soi
Question 9
9 Factorise completely. 2x2 - 18 .................................................... [2]
Mark scheme: 9 2(x + 3)(x – 3) final answer 2 B1 for 2(x2 – 9) or (2x + 6)(x – 3) or (x + 3)(2x – 6) in working or answer space
Q10 · U = {integers from 1 to 12} A = {1, 2, 4, 5, 12} B = {2, 3, 4, 6, 10} C = {1, 2, 8, 9…
10 U = {integers from 1 to 12} A = {1, 2, 4, 5, 12} B = {2, 3, 4, 6, 10} C = {1, 2, 8, 9, 10} (a) Complete the Venn Diagram. U A B C [2] (b) Find n (A + (B , C ) )l . .................................................... [1]
Mark scheme: 10(a) 2 B1 for 1, 2 or 3 numbers misplaced A B 5 4 3 6 12 2 1 10 8 9 C 7 11 10(b) 2 1 FT their diagram
Q11 · The point A has co-ordinates (3, 8)
11 The point A has co-ordinates (3, 8). The point B has co-ordinates (7, 0). (a) Find the co-ordinates of the midpoint of AB. ( ....................... , ........................) [1] (b) Find the equation of the perpendicular bisector of AB. Write your answer in the form y = mx + c. y = .................................................... [3]
Mark scheme: 11(a) (5, 4) 1 11(b) 1 1 3 8 − 0 [y =] x + 1 oe M1 for oe or gradient = −2 2 2 3 − 7 M1 for gradient of perpendicular −1 = their gradient
Q12 · 60° NOT TO SCALE 12 cm r cm The sector and the circle have the same area
12 60° NOT TO SCALE 12 cm r cm The sector and the circle have the same area. The angle of the sector is 60°. The radius of the sector is 12 cm and the radius of the circle is r cm. Work out the value of r. Give your answer as a surd in its simplest form. r = .................................................... [3]
Mark scheme: 12 2 6 3 60 M1 for × π × 122 = πr2 oe 360 A1 for r2 = 24 or better
Q13 · Rearrange this formula to make b the subject
13 Rearrange this formula to make b the subject. (a + b) A = h 2 b = .................................................... [3] Question 14 is printed on the next page.
Mark scheme: 13 2A 2 A − ah 3 2A [b =] – a or [b =] oe M2 for 2A – ah = bh or = a + b h h h Final answer A a + b or M1 for 2A = (a + b)h or = h 2
Q14 · Find the value of log 25 5
14 (a) Find the value of log 25 5 . .................................................... [1] (b) Simplify log 63 - 2 log 3 . .................................................... [2]
Mark scheme: 14(a) 1 1 or 0.5 2 14(b) log 7 2 M1 for correct use of logan = nloga or log(a ÷ b) = loga – logb
What was in this paper
The subtopics covered by these 14 questions, and how many questions each got. Open one in a new tab to see every Cambridge question on it.
What you needed in this session
Cambridge’s own grade thresholds for 2019 May/June, Paper 2 · Variant 1. A higher threshold means an easier paper — the bar moves with how the cohort did.