Cambridge A Level Mathematics 9709 — 2015 May/June Paper 3 · Variant 2
9709/32/M/J/15 · 6 questions · 75 marks · ≈84 min
The question paper and its mark scheme, free to read here and free to download. This is Cambridge’s own paper, exactly as it was sat.
Question paper4 pages




Mark scheme7 pages
Answers below. Sit the paper first if you are practising.







Questions as text
Q2 · Using the substitution giving your answer correct to 4x, solve the equation 4x 42 u = + =…
2 Using the substitution giving your answer correct to 4x, solve the equation 4x 42 u = + = 4x+2, 3 significant figures. [4]
Mark scheme: 2 Use laws of indices correctly and solve for u M1 16 Obtain u in any correct form, e.g. u = A1 16 − 1 Use correct method for solving an equation of the form 4 x = a , where a > 0 M1 Obtain answer x = 0.0466 A1 [4]
Q3 · A curve has equation y cos x cos 2x
3 A curve has equation y cos x cos 2x. Find the x-coordinate of the stationary point on the curve in the interval 0 x 1 giving= your answer correct to 3 significant figures. [6] < < 20,
Mark scheme: 3 EITHER: Use correct product rule M1 Obtain correct derivative in any form, e.g. − sin x cos 2 x − 2 cos x sin 2 x A1 Use the correct double angle formulae to express derivative in cos x and sin x, or cos 2x and sin x M1 OR1: Use correct double angle formula to express y in terms of cos x and attempt differentiation M1 Use chain rule correctly M1 Obtain correct derivative in any form, e.g. − 6 cos 2 x sin x + sin x A1 OR2: Use correct factor formula and attempt differentiation M1 3 1 Obtain correct derivative in any form, e.g. − sin3x − sin x A1 2 2 Use correct trig formulae to express derivative in terms of cos x and sin x, or sin x M1 Equate derivative to zero and obtain an equation in one trig function M1 Obtain 6 cos 2 x = 1 , 6 sin 2 x = 5 , tan 2 x = 5 or 3 cos 2 x = − 2 A1 Obtain answer x = 1.15 (or 65.9°) and no other in the given interval A1 [6] [Ignore answers outside the given interval.] [SR: Solution attempts following the EITHER scheme for the first two marks can earn the second and third method marks as follows: Equate derivative to zero and obtain an equation in tan 2x and tan x M1 Use correct double angle formula to obtain an equation in tan x M1]
Q6 · X 6 Let I dx
1 x 6 Let I dx. 2 x = Ô 0 − 2 2 2 2 (i) Using the substitution u 2 x, show that I du. [4] −u u = − = Ô 1 (ii) Hence show that I 8 ln 2 [4] = −5.
Mark scheme: 1 6 (i) State or imply d u = − d x , or equivalent B1 2 x Substitute for x and dx throughout M1 ± 2 ( 2 − u 2) Obtain integrand , or equivalent A1 u Show correct working to justify the change in limits and obtain the given answer with no errors seen A1 [4] (ii) Integrate and obtain at least two terms of the form a ln u , bu , and cu 2 M1* Obtain indefinite integral 8 ln u − 8u + u 2 , or equivalent A1 Substitute limits correctly M1(dep*) Obtain the given answer correctly having shown sufficient working A1 [4]
Q7 · The complex number u is given by u i
7 The complex number u is given by u i. = −1 + 4ï3 (i) Without using a calculator and showing all your working, find the two square roots of u. Give your answers in the form a ib, where the real numbers a and b are exact. [5] + (ii) On an Argand diagram, sketch the locus of points representing complex numbers satisfying the relation 1. Determine the greatest value of arg for points on this locus.Ï [4] Ï −u = Ï
Mark scheme: 7 (i) Square x + iy and equate real and imaginary parts to −1 and 4 3 M1 Obtain x 2 −y 2 = −1 and 2 xy = 4 3 A1 Eliminate one unknown and find an equation in the other M1 Obtain x 4 + x 2 − 12 = 0 or y 4 −y 2 − 12 = 0 , or three term equivalent A1 Obtain answers ± ( 3 + )i2 A1 [5] [If the equations are solved by inspection, give B2 for the answers and B1 for justifying them] (ii) Show a circle with centre − 1+ 4 3 in a relatively correct position B1 Show a circle with radius 1 and centre not at the origin B1 Carry out a complete method for calculating the greatest value of arg z M1 Obtain answer 1.86 or 106.4° A1 [4] A Bx + C
Q9 · The number of organisms in a population at time t is denoted by x
9 The number of organisms in a population at time t is denoted by x. Treating x as a continuous variable, the differential equation satisfied by x and t is dx xe−t , dt = k + e−t where k is a positive constant. (i) Given that x 10 when t 0, solve the differential equation, obtaining a relation between x, k and t. = = [6] (ii) Given also that x 20 when t 1, show that k 1 . [2] e = = = −2 (iii) Show that the number of organisms never reaches 48, however large t becomes. [2]
Mark scheme: 9 (i) Separate variables correctly and attempt integration of one side B1 Obtain term ln x B1 Obtain term of the form a ln( k + e − t ) M1 Obtain term − ln( k + e − t ) A1 Evaluate a constant or use limits x = 10, t = 0 in a solution containing terms a ln( k + e − t ) and bln x M1* Obtain correct solution in any form, e.g. ln x − ln 10 = − ln( k + e − t ) + ln( k + )1 A1 [6] (ii) Substitute x = 20, t = 1 and solve for k M1(dep*) Obtain the given answer A1 [2] (iii) Using e −t → 0 and the given value of k, find the limiting value of x M1 Justify the given answer A1 [2]
Q10 · The points A and B have position vectors given by OA 2i 3k and OB i j 5k
10 The points A and B have position vectors given by OA 2i 3k and OB i j 5k. The line l −−→ −−→ has equation r i j 2k 3i j . = −j + = + + = + + + - + −k (i) Show that l does not intersect the line passing through A and B. [5] (ii) Find the equation of the plane containing the line l and the point A. Give your answer in the form ax by d. [6] + + cÏ =
Mark scheme: 10 (i) Carry out a correct method for finding a vector equation for AB M1 Obtain r = 2 i − j + 3k + λ ( − i + 2 j + 2k ) , or equivalent A1 Equate at least two pairs of components of general points on AB and l and solve for λ or for µ M1 4 3 Obtain correct answer for λ or µ, e.g. λ = 1 or µ = 0; λ = − or µ = ; 5 5 1 3 or λ = or µ = − A1 4 2 Verify that not all three pairs of equations are satisfied and that the lines fail to intersect A1 [5] (ii) EITHER: Obtain a vector parallel to the plane and not parallel to l, e.g. i −2 j + k B1 Use scalar product to obtain an equation in a, b and c, e.g. 3a + b − c = 0 B1 Form a second relevant equation, e.g. a – 2b + c = 0 and solve for one ratio, e.g. a : b M1 Obtain final answer a : b : c = 1 : 4 : 7 A1 Use coordinates of a relevant point and values of a, b and c in general equation and find d M1 Obtain answer x + 4y + 7z = 19, or equivalent A1 OR1: Obtain a vector parallel to the plane and not parallel to l, e.g. i −2 j + k B1 Obtain a second relevant vector parallel to the plane and attempt to calculate their vector product, e.g. ( i − 2 j + k ) × (3i + j − k ) M1 Obtain two correct components A1 Obtain correct answer, e.g. i + 4 j + 7 k A1 Substitute coordinates of a relevant point in x + 4y + 7z = d, or equivalent, and find d M1 Obtain answer x + 4y + 7z = 19, or equivalent A1 OR2: Obtain a vector parallel to the plane and not parallel to l, e.g. i −2 j + k B1 Using a relevant point and second relevant vector, form a 2-parameter equation for the plane M1 State a correct equation, e.g. r = 2i − j + 3k + s ( i − 2 j + k ) + t (3i + j − k ) A1 State 3 correct equations in x, y, z, s and t A1 Eliminate s and t M1 Obtain answer x + 4y + 7z = 19, or equivalent A1 OR3: Using the coordinates of A and two points on l, state three simultaneous equations in a, b, c and d, e.g. a + b + 2c = d, 2a − b + 3c = d and 4a + 2b + c = d B1 Solve and find one ratio, e.g. a : b M1 State one correct ratio A1 Obtain a correct ratio of three of the unknowns, e.g. a : b : c = 1 : 4 : 7, or equivalent A1 Either use coordinates of a relevant point and the found ratio to find the fourth unknown, e.g. d, or find the ratio a : b : c : d M1 Obtain answer x + 4y + 7z = 19, or equivalent A1 OR4: Obtain a vector parallel to the plane and not parallel to l, e.g. i −2 j + k B1 Using a relevant point and second relevant vector, form a determinant equation for the plane M1 x − 2 y + 1 z − 3 State a correct equation, e.g. 1 − 2 1 = 0 A1 3 1 − 1 Attempt to expand the determinant M1 Obtain or imply two correct cofactors A1 Obtain answer x + 4y +7z =19, or equivalent A1 [6]
What was in this paper
The subtopics covered by these 6 questions, and how many questions each got. Open one in a new tab to see every Cambridge question on it.
What you needed in this session
Cambridge’s own grade thresholds for 2015 May/June, Paper 3 · Variant 2. A higher threshold means an easier paper — the bar moves with how the cohort did.