Cambridge IGCSE Mathematics - International 0607 — 2024 Oct/Nov Paper 3 · Variant 1

This document has 16 pages. [Turn over * 0 7 7 2 1 1 7 6 4 0 * Cambridge IGCSE™ CAMBRIDGE INTERNATIONAL MATHEMATICS 0607/31 Paper 3 (Core) October/November 2024 1 hour 45 minutes You must answer on the question paper. You will need: Geometrical instruments INSTRUCTIONS ● Answer all questions. ● Use a black or dark blue pen. You may use an HB pencil for any diagrams or graphs. ● Write your name, centre number and candidate number in the boxes at the top of the page. ● Write your answer to each question in the space provided. ● Do not use an erasable pen or correction fluid. ● Do not write on any bar codes. ● You should use a graphic display calculator where appropriate. ● You may use tracing paper. ● You must show all necessary working clearly and you will be given marks for correct methods, including sketches, even if your answer is incorrect. ● Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless a different level of accuracy is specified in the question. ● For r, use your calculator value. INFORMATION ● The total mark for this paper is 96. ● The number of marks for each question or part question is shown in brackets [ ]. DC (PQ/SG) 337004/3 © UCLES 2024 ,










, * 0000800000001 * ¬OŠ. 4mHuOªEŠ`y6€W ¬eT{[ €R|ƒ‹Zch‘¦‚ ¥ U•5U¥uu 5EE5 5•U

2 0607/31/O/N/24 © UCLES 2024 Formula List Area, A, of triangle, base b, height h. A = bh 2 1 Area, A, of circle, radius r. A = r2 r Circumference, C, of circle, radius r. C = 2rr Curved surface area, A, of cylinder of radius r, height h. A = 2rrh Curved surface area, A, of cone of radius r, sloping edge l. A = rrl Curved surface area, A, of sphere of radius r. A = r 4 2 r Volume, V, of prism, cross-sectional area A, length l. V = Al Volume, V, of pyramid, base area A, height h. V = Ah 3 1 Volume, V, of cylinder of radius r, height h. V = r h 2 r Volume, V, of cone of radius r, height h. V = r h 3 1 2 r Volume, V, of sphere of radius r. V = r 3 4 3 r * 0000800000002 * ,










, ĬÍĊ®Ġ´íÈõÏĪÅĊÝû¸þ× ĬåÒüÚĬĜĪéąõĨĢÙĘéĞĂ ĥÕÅĕõµåĕÅÅĥąÅõĥõµÕ DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN

3 0607/31/O/N/24 © UCLES 2024 [Turn over Answer all the questions. 1 y x 0 – 4 – 3 – 2 – 1 – 1 1 2 3 4 5 – 2 – 3 1 2 3 4 5 6 P A C B (a) Write down the coordinates of the points A, B and C. A = ( … , … ) B = ( … , … ) C = ( … , … ) [3] (b) Point P is the mid-point of the line AC. P is also the mid-point of the line BD. (i) On the grid, plot point D. [1] (ii) Write down the coordinates of point D. D = ( … , … ) [1] (c) Join, with straight lines, A to D and C to D. (i) Write down the number of lines of symmetry of quadrilateral ABCD. … [1] (ii) Write down the order of rotational symmetry of quadrilateral ABCD. … [1] (iii) Write down the mathematical name of quadrilateral ABCD. … [1] * 0000800000003 * ,










, ĬÏĊ®Ġ´íÈõÏĪÅĊÝù¸þ× ĬåÑûÒĞĘĚÐóČá¶áÄéĎĂ ĥÕµÕµÕÅõÕµµąÅĕąµåÕ DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN

4 0607/31/O/N/24 © UCLES 2024 2 A technician repairs 10 computers. He records the time he takes to complete each repair. The times, in minutes, are shown below. 74 25 54 45 60 32 62 59 56 43 (a) Find the mean time taken. … minutes [1] (b) Complete the stem-and-leaf diagram for the times. 2 3 4 5 6 7 Key: …|… means … minutes [3] (c) Find the median time. … minutes [1] * 0000800000004 * ,










, ĬÍĊ®Ġ´íÈõÏĪÅĊßû¸Ā× ĬåÑúÒĨĦďëíăêĘýĢ¹ĦĂ ĥĥĥÕõÕÅÕµĕÅąąĕåµµÕ DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN

5 0607/31/O/N/24 © UCLES 2024 [Turn over (d) One of the times is chosen at random. Find the probability that this time is more than 1 hour. Give your answer as a fraction in its simplest form. … [2] (e) A pie chart is drawn to show the times. Work out the angle for the sector representing less than 30 minutes. … [2] * 0000800000005 * ,










, ĬÏĊ®Ġ´íÈõÏĪÅĊßù¸Ā× ĬåÒùÚĢĪğÎċîğÄõ¶¹ĖĂ ĥĥĕĕµµåµåĥĕąąõÅõåÕ DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN

6 0607/31/O/N/24 © UCLES 2024 3 Nina takes part in a sponsored walk. She walks 29 km. (a) Her mother, grandmother and brother all sponsor her for each kilometre she walks. Complete the table. Sponsor Distance walked (km) Amount for each km walked Amount raised Mother 29 $3 $ Grandmother 29 $1.75 $ Brother 29 50 cents $ Total amount raised $ [4] (b) Nina collects $575 in total from all her sponsors. She divides the money between three charities, A, B and C, in this ratio. 10 8 7 A B C | | | | = Work out how much each charity receives. A $ … B $ … C $ … [3] (c) Nina walked the 29 km in 6 hours 45 minutes. Work out Nina’s average speed in kilometres per hour. Give your answer correct to 2 significant figures. … km/h [3] * 0000800000006 * ,










, ĬÑĊ®Ġ´íÈõÏĪÅĊÞùµþ× ĬåÑùÕĬĂĥÖĀÿĖäý×đĦĂ ĥµµĕµĕåĕĥąµąÅõĥµõÕ DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN

7 0607/31/O/N/24 © UCLES 2024 [Turn over 4 (a) These are the first four terms of a sequence. 2 6 10 14 (i) Work out the next three terms. … … … [2] (ii) Write down the rule for continuing this sequence. … [1] (b) Here is a different sequence with the 1st and the 6th terms missing. … 25 18 11 4 … Find the 1st term and the 6th term of this sequence. 1st term = … 6th term = … [2] (c) The nth term of another sequence is n 2 2 . Find the first three terms of this sequence. … … … [2] (d) These are the first four terms of a different sequence. 8 13 18 23 Find an expression for the nth term. … [2] * 0000800000007 * ,










, ĬÓĊ®Ġ´íÈõÏĪÅĊÞûµþ× ĬåÒúÍĞþĕãúòÓøõăđĖĂ ĥµÅÕõõÅõõõĥąÅĕąõĥÕ DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN

8 0607/31/O/N/24 © UCLES 2024 5 (a) O B Q P A A, B, P and Q lie on a circle, centre O. AOB is a straight line. (i) Write down the mathematical name for the line AB. … [1] (ii) Write down the mathematical name for the line PQ. … [1] (iii) On the diagram, draw a tangent to the circle. [1] (b) q° r° s° p° 52° B C Z T Y X A NOT TO SCALE In the diagram, XAT and YBT are straight lines. ABC is parallel to XYZ. Find the values of p, q, r and s. p = … q = … r = … s = … [4] * 0000800000008 * ,










, ĬÑĊ®Ġ´íÈõÏĪÅĊàùµĀ× ĬåÒûÍĨðĔØøùÜÖÙáāĞĂ ĥąĕÕµõÅÕĕÕĕąąĕåõõÕ DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN

9 0607/31/O/N/24 © UCLES 2024 [Turn over (c) Find the size of one interior angle of a regular polygon with 9 sides. … [3] (d) The diagram shows part of a regular polygon with centre O. NOT TO SCALE x O Show that angle x cannot be 50°. … … [2] * 0000800000009 * ,










, ĬÓĊ®Ġ´íÈõÏĪÅĊàûµĀ× ĬåÑüÕĢôĤáĂĈčĂáõāĎĂ ĥąĥĕõĕåµąåÅąąõŵĥÕ DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN

10 0607/31/O/N/24 © UCLES 2024 6 (a) The price of a printer is $120. In a sale, the price is reduced by $42. (i) Work out the price of the printer in the sale. $ … [1] (ii) Work out $42 as a percentage of $120. … % [1] (b) Sajid sees the same computer advertised in two shops. SHOP A ‘Stella’ computer Was $930 In sale, reduced by 40% SHOP B ‘Stella’ computer Was $930 In sale, reduced by 8 3 Work out which shop is cheaper and by how much. Shop … by $ … [5] * 0000800000010 * ,










, ĬÑĊ®Ġ´íÈõÏĪÅĊÝù·þ× ĬåÓûØĦøĆÚïòòºÛŹĖĂ ĥÕõĕµõĥÕµĥĕÅąµåõÅÕ DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN

11 0607/31/O/N/24 © UCLES 2024 [Turn over 7 (a) Complete this statement using one of 1, = or 2 . 17 … 25 [1] (b) Simplify fully. x x x 5 4 3 - + … [1] (c) A r 6 = Find A when . r 2 5 = . A = … [1] (d) Solve. (i) x 4 8 = x = … [1] (ii) ( ) x 6 2 7 3 - = x = … [3] (e) Rearrange this formula to make t the subject. v t2 20 = + t = … [2] * 0000800000011 * ,









, ĬÓĊ®Ġ´íÈõÏĪÅĊÝû·þ× ĬåÔüÐĤüößĉÿ·Ğãđ¹ĦĂ ĥÕąÕõĕąµåĕÅÅąÕŵÕÕ DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN

12 0607/31/O/N/24 © UCLES 2024 8 y – 5 – 4 – 3 – 2 – 1 1 2 3 4 5 6 7 8 9 – 1 1 2 3 4 5 6 7 – 2 – 3 – 4 – 5 0 x A B (a) Triangle A is drawn on a 1 cm square grid. (i) Work out the area of triangle A. … cm2 [2] (ii) Use Pythagoras’ Theorem to help you work out the perimeter of triangle A. … cm [3] * 0000800000012 * ,









, ĬÑĊ®Ġ´íÈõÏĪÅĊßù·Ā× ĬåÔùÐĪĊóÜćĈ°Àÿ³éĎĂ ĥĥÕÕµĕąĕŵµÅÅÕĥµÅÕ DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN

13 0607/31/O/N/24 © UCLES 2024 [Turn over (b) Describe fully the single transformation which maps triangle A onto triangle B. … … [2] (c) Rotate triangle A by 90° clockwise about (0, 0). Label the image C. [2] (d) Enlarge triangle A by scale factor 2 from centre (0, 0). Label the image D. [2] * 0000800000013 * ,









, ĬÓĊ®Ġ´íÈõÏĪÅĊßû·Ā× ĬåÓúØĠĆăÝñùùĜ÷ħéĞĂ ĥĥåĕõõĥõÕÅĥÅŵąõÕÕ DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN

14 0607/31/O/N/24 © UCLES 2024 9 (a) Uma is paid $35 500 per year. She receives a pay increase of 7%. Work out Uma’s new pay. $ … [2] (b) Uma invests $2500 at a rate of 3% per year simple interest. Work out the value of her investment at the end of 4 years. $ … [3] * 0000800000014 * ,









, ĬÍĊ®Ġ´íÈõÏĪÅĊàü¶Ă× ĬåÔüÕĢùûÏ÷îÖ¸ÞģęĦĂ ĥÅåÕµĕåÕµÕĥąąõåµąÕ DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN

15 0607/31/O/N/24 © UCLES 2024 [Turn over 10 A shop sells computers and printers. The probability that: • a computer breaks down in the first year is 0.10 • a printer breaks down in the first year is 0.15 . (a) The shop sells 420 printers. Work out the number of these printers that are expected to break down in the first year. … [2] (b) Complete the tree diagram. Breaks down Does not break down Breaks down Does not break down Breaks down Does not break down … Computer … … … … Printer … [3] (c) Orla buys a computer and a printer. Find the probability that the computer does not break down but the printer does break down in the first year. … [2] Question 11 is printed on the next page. * 0000800000015 * ,









, ĬÏĊ®Ġ´íÈõÏĪÅĊàú¶Ă× ĬåÓûÍĨõċêāăēĤÖ·ęĖĂ ĥÅÕĕõõŵååµąąĕÅõĕÕ DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN

16 0607/31/O/N/24 © UCLES 2024 Permission to reproduce items where third-party owned material protected by copyright is included has been sought and cleared where possible. Every reasonable effort has been made by the publisher (UCLES) to trace copyright holders, but if any items requiring clearance have unwittingly been included, the publisher will be pleased to make amends at the earliest possible opportunity. To avoid the issue of disclosure of answer-related information to candidates, all copyright acknowledgements are reproduced online in the Cambridge Assessment International Education Copyright Acknowledgements Booklet. This is produced for each series of examinations and is freely available to download at www.cambridgeinternational.org after the live examination series. Cambridge Assessment International Education is part of Cambridge Assessment. Cambridge Assessment is the brand name of the University of Cambridge Local Examinations Syndicate (UCLES), which is a department of the University of Cambridge. 11 y – 3 3 15 – 15 0 x (a) (i) On the diagram, sketch the graph of y x 5 = for values of x from -3 to 3. [2] (ii) Write down the equation of each asymptote of y x 5 = . … and … [2] (b) On the diagram, sketch the graph of y x 3 2 = - for values of x from -3 to 3. [2] (c) Find the coordinates of each point of intersection of y x 3 2 = - and y x 5 = . ( … , … ) ( … , … ) [3] * 0000800000016 * ,









, ĬÍĊ®Ġ´íÈõÏĪÅĊÞü¶Ą× ĬåÓúÍĞćþÍÿČĜÂúĕĉĞĂ ĥõąĕµõÅĕÅąÅąÅĕĥõąÕ DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN DO NOT WRITE IN THIS MARGIN

This document consists of 8 printed pages. © Cambridge University Press & Assessment 2024 [Turn over Cambridge IGCSE™ CAMBRIDGE INTERNATIONAL MATHEMATICS 0607/31 Paper 3 (Core) October/November 2024 MARK SCHEME Maximum Mark: 96 Published This mark scheme is published as an aid to teachers and candidates, to indicate the requirements of the examination. It shows the basis on which Examiners were instructed to award marks. It does not indicate the details of the discussions that took place at an Examiners’ meeting before marking began, which would have considered the acceptability of alternative answers. Mark schemes should be read in conjunction with the question paper and the Principal Examiner Report for Teachers. Cambridge International will not enter into discussions about these mark schemes. Cambridge International is publishing the mark schemes for the October/November 2024 series for most Cambridge IGCSE, Cambridge International A and AS Level components, and some Cambridge O Level components.

0607/31 Cambridge IGCSE – Mark Scheme PUBLISHED October/November 2024 © Cambridge University Press & Assessment 2024 Page 2 of 8 Generic Marking Principles These general marking principles must be applied by all examiners when marking candidate answers. They should be applied alongside the specific content of the mark scheme or generic level descriptions for a question. Each question paper and mark scheme will also comply with these marking principles. GENERIC MARKING PRINCIPLE 1: Marks must be awarded in line with: • the specific content of the mark scheme or the generic level descriptors for the question • the specific skills defined in the mark scheme or in the generic level descriptors for the question • the standard of response required by a candidate as exemplified by the standardisation scripts. GENERIC MARKING PRINCIPLE 2: Marks awarded are always whole marks (not half marks, or other fractions). GENERIC MARKING PRINCIPLE 3: Marks must be awarded positively: • marks are awarded for correct/valid answers, as defined in the mark scheme. However, credit is given for valid answers which go beyond the scope of the syllabus and mark scheme, referring to your Team Leader as appropriate • marks are awarded when candidates clearly demonstrate what they know and can do • marks are not deducted for errors • marks are not deducted for omissions • answers should only be judged on the quality of spelling, punctuation and grammar when these features are specifically assessed by the question as indicated by the mark scheme. The meaning, however, should be unambiguous. GENERIC MARKING PRINCIPLE 4: Rules must be applied consistently, e.g. in situations where candidates have not followed instructions or in the application of generic level descriptors. GENERIC MARKING PRINCIPLE 5: Marks should be awarded using the full range of marks defined in the mark scheme for the question (however; the use of the full mark range may be limited according to the quality of the candidate responses seen). GENERIC MARKING PRINCIPLE 6: Marks awarded are based solely on the requirements as defined in the mark scheme. Marks should not be awarded with grade thresholds or grade descriptors in mind.

0607/31 Cambridge IGCSE – Mark Scheme PUBLISHED October/November 2024 © Cambridge University Press & Assessment 2024 Page 3 of 8 Mathematics-Specific Marking Principles 1 Unless a particular method has been specified in the question, full marks may be awarded for any correct method. However, if a calculation is required then no marks will be awarded for a scale drawing. 2 Unless specified in the question, non-integer answers may be given as fractions, decimals or in standard form. Ignore superfluous zeros, provided that the degree of accuracy is not affected. 3 Allow alternative conventions for notation if used consistently throughout the paper, e.g. commas being used as decimal points. 4 Unless otherwise indicated, marks once gained cannot subsequently be lost, e.g. wrong working following a correct form of answer is ignored (isw). 5 Where a candidate has misread a number or sign in the question and used that value consistently throughout, provided that number does not alter the difficulty or the method required, award all marks earned and deduct just 1 A or B mark for the misread. 6 Recovery within working is allowed, e.g. a notation error in the working where the following line of working makes the candidate’s intent clear.

0607/31 Cambridge IGCSE – Mark Scheme PUBLISHED October/November 2024 © Cambridge University Press & Assessment 2024 Page 4 of 8 MARK SCHEME NOTES The following notes are intended to aid interpretation of mark schemes in general, but individual mark schemes may include marks awarded for specific reasons outside the scope of these notes. Types of mark M Method marks, awarded for a valid method applied to the problem. A Accuracy mark, awarded for a correct answer or intermediate step correctly obtained. For accuracy marks to be given, the associated Method mark must be earned or implied. B Mark for a correct result or statement independent of Method marks. When a part of a question has two or more ‘method’ steps, the M marks are in principle independent unless the scheme specifically says otherwise; and similarly where there are several B marks allocated. The notation ‘dep’ is used to indicate that a particular M or B mark is dependent on an earlier mark in the scheme. Abbreviations awrt answers which round to cao correct answer only dep dependent FT follow through after error isw ignore subsequent working nfww not from wrong working oe or equivalent rot rounded or truncated SC Special Case soi seen or implied Question Answer Marks Partial Marks 1(a) [A=] (5, 3) [B=] (0, 3) [C=] (–3, –1) 3 B1 for each 1(b)(i) D marked at (2, –1) 1 1(b)(ii) (2, –1) 1 FT their D 1(c)(i) 2 1 1(c)(ii) 2 1 1(c)(iii) rhombus 1 2(a) 51 1

0607/31 Cambridge IGCSE – Mark Scheme PUBLISHED October/November 2024 © Cambridge University Press & Assessment 2024 Page 5 of 8 Question Answer Marks Partial Marks 2(b) 5 2 3 5 4 6 9 0 2 4 B2 B1 for correct leaves ordered but with 1 error/omission or for correct leaves but unordered Key e.g. 2 | 5 means 25 B1 2(c) 55 1 2(d) 1 5 2 B1 for 2 10 If 0 scored, SC1 for 20% or 0.2 2(e) 36 2 M1 for 1 10 × 360 oe 3(a) 87 50.75 14.5[0] 152.25 4 B1 for each FT their total 3(b) [A=] 230 [B=] 184 [C=] 161 3 B2 for one correct or M1 for 575 10 8 7 + + soi 3(c) 4.3 3 B2 for 4.296… OR M1 for 29 6.75 their M1 for rounding their more accurate answer correct to 2sf 4(a)(i) 18, 22, 26 2 B1 for 2 correct 4(a)(ii) +4 1 4(b) 32 –3 2 B1for each If 0 scored, SC1 for terms reversed 4(c) 2, 8, 18 2 B1 for 2 correct in correct positions If 0 scored, SC1 for 0, 2, 8 4(d) 5n + 3 oe final answer 2 B1 for 5n + k any k or 3, 0 +  pn p 5(a)(i) Diameter 1 5(a)(ii) Chord 1 5(a)(iii) Ruled tangent drawn to circle 1

0607/31 Cambridge IGCSE – Mark Scheme PUBLISHED October/November 2024 © Cambridge University Press & Assessment 2024 Page 6 of 8 Question Answer Marks Partial Marks 5(b) [p=] 52 [q=] 38 [r=] 38 [s=] 128 4 B1 for each 5(c) 140 3 M1 for 360 9 soi by 40 M1 for 180 – their(exterior angle) OR M2 for ( ) 180 9 2 9 − or M1 for 180(9 – 2) 5(d) 360 50 M1 [7.2 ] is not a whole number oe A1 6(a)(i) 78 1 6(a)(ii) 35 1 6(b) A by 23.25 5 B2 for [A=] 558 or 372 or M1 for 930 × 0.4 or 930 × (1 – 0.4) oe B2 for [B=] 581.25 or 348.75 or M1 for 930 × 3 8 or 930 × (1 – 3 8 ) oe 7(a) < 1 7(b) 4x 1 7(c) 15 1 7(d)(i) 32 1 7(d)(ii) 3.75 or 3¾ or 3 9 12 3 M1 for 12x – 42 = 3 or 2x – 7 = 3 6 oe M1 for 12x = 3 + their42 or 2x = their 3 6 + 7 7(e) [t =] 20 2 − v oe final answer 2 M1 for v – 20 = 2t or 2 v = t + 20 2 oe 8(a)(i) 3 2 M1 for 1 3 2 2  8(a)(ii) 8.61 or 8.605 to 8.606 3 B2 for 3.61 or 3.605 to 3.606 or M1 for 32 + 22

0607/31 Cambridge IGCSE – Mark Scheme PUBLISHED October/November 2024 © Cambridge University Press & Assessment 2024 Page 7 of 8 Question Answer Marks Partial Marks 8(b) Translation 5 3 −       2 B1 for each 8(c) Correct image (1, –1) (1, –4) (3, –1) 2 M1 for correct but anticlockwise or for correct orientation, wrong position 8(d) Correct image (2, 2) (2, 6) (8, 2) 2 M1 for correct size, wrong position 9(a) 37 985 2 M1 for 35 500 × 0.07 oe soi by 2485 9(b) 2800 3 B2 for 300 nfww OR M2 for 2500 + 2500 3 4 100  or M1for  2500 3 4 100  oe 10(a) 63 2 M1 for 420 × 0.15 soi 10(b) Correct complete tree diagram with 0.10, 0.90, 0.15, 0.85 correctly placed 3 B1 for 0.10 and 0.15 correctly placed once each B1 for 0.90 or 0.85 correctly placed once each 10(c) 0.135 2 FT their tree diagram M1 for 0.90 × 0.15 11(a)(i) Correct hyperbola sketch 2 B1 for one branch correct 11(a)(ii) x = 0, y = 0 2 B1 for each

0607/31 Cambridge IGCSE – Mark Scheme PUBLISHED October/November 2024 © Cambridge University Press & Assessment 2024 Page 8 of 8 Question Answer Marks Partial Marks 11(b) Correct straight line sketch 2 B1 for line with positive gradient or for line with negative y intercept 11(c) (–1, –5) (1.67, 3) 3 B1 for (–1, –5) B2 for (1.67, 3) or B1 for (1.7, 3) If 0 scored, SC2 for –1 and 1.67 soi or SC1 for –1 or 1.67 soi