Cambridge A Level Mathematics 9709 — 2019 Oct/Nov Paper 2 · Variant 1

9709/21/O/N/19 · 2 questions · 50 marks · ≈56 min

The question paper and its mark scheme, free to read here and free to download. This is Cambridge’s own paper, exactly as it was sat.

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Question paper12 pages

Cambridge A Level Mathematics 9709 2019 Oct/Nov Paper 2 · Variant 1 question paper, page 1 of 12
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Mark scheme10 pages

Answers below. Sit the paper first if you are practising.

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Questions as text

Q1 · Solve the inequality 2x 2x

1 (i) Solve the inequality 2x 2x . [3] −7 < −9 ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ (ii) Hence find the largest integer n satisfying the inequality 2 ln n 2 ln n . [2] −7 < −9 ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................

Mark scheme: 1(i) State or imply non-modular inequality 2 2 (2 7) (2 9) x x − < − or corresponding equation or linear equation (with signs of 2x different) M1 Obtain critical value 4 A1 State 4 x < only A1 3 1(ii) Attempt to find n from lnn = their critical value from part (i) M1 Obtain or imply 4 e n < and hence 54 A1 2

More questions on Quadratics

Q3 · 2 ln x3 A curve has equation y +

3 2 ln x3 A curve has equation y + . Find the exact gradient of the curve at the point for which y 4. = 1 ln x = + [5] ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................ ................................................................................................................................................................

Mark scheme: 3 Use quotient rule (or product rule) to find first derivative *M1 Must have correct u and v Obtain 2 1 (1 ln ) x x − + or (unsimplified) equivalent A1 Use 4 y = to obtain 1 2 ln x = − or exact equivalent for x B1 Substitute for x in their first derivative DM1 Obtain 1 2 4e − or exact equivalent A1 Must be simplified to contain a single exponential term 5

More questions on Functions

What was in this paper

The subtopics covered by these 2 questions, and how many questions each got. Open one in a new tab to see every Cambridge question on it.

What you needed in this session

Cambridge’s own grade thresholds for 2019 Oct/Nov, Paper 2 · Variant 1. A higher threshold means an easier paper — the bar moves with how the cohort did.

A40/50
B35/50
C28/50
D22/50
E15/50